0 Find the sample variance and the standard deviation for the following sample. Round the answers to at least two decimal places as needed. 17 40 22 15 12 Send data to Excel The sample variance is 123

Hence, x in terms of y is x = log(y) / log(5) found using the  common logarithms.

To solve the given problem with common logarithms and find x in terms of y, let's start with the provided information that is to use common logarithms.

Let us begin with a common logarithm defined as a logarithm to the base 10.

Therefore, we use the common logarithmic function of both sides of the given equation,

y = 5^x.

As a result, we get:log(y) = log(5^x)

We know that the power property of logarithms states that logb (a^c) = c * logb (a), where b is the base, a is a positive number, and c is a real number.

Using this property, we can rewrite the right-hand side of the above equation as:x log(5)

Now, we have:log(y) = x log(5)

To get the value of x in terms of y, divide both sides of the above equation by log(5).

We obtain the following:log(y) / log(5) = x

Therefore, x = log(y) / log(5).

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The electric force experienced by a charge Q1 due to the presence of another charge Q2 located at a distance r from Q1 is given by the Coulomb’s Law as:

F = (1/4πε0) (Q1Q2/r²)

where ε0 is the permittivity of free space and is equal to 8.854 x 10⁻¹² C²/Nm²

Given : Charge Q1 = 4 uCCharge Q2 = 8 uC - (-8 uC) = 16 uC

Distance between Q1 and Q2 = (6² + 2²)¹/²

= (40)¹/² cm

= 6.3246 cm

Substituting the given values in the Coulomb’s Law equation : F = (1/4πε0) (Q1Q2/r²)

F = (1/4π x 8.98755 x 10⁹ Nm²/C²) (4 x 10⁻⁶ C x 16 x 10⁻⁶ C)/(6.3246 x 10⁻² m)²

F = 6.21 x 10⁻⁵ N

Answer: The force experienced by a charge of 4 uC on the x-axis at x = 6 cm is 6.21 x 10⁻⁵ N.

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The number of plastic tubing needed to fit around the edge of the pool is 423.3 ft².

The number of plastic tubing needed to fit around the area is calculated from the difference between the area of the rectangle and area of the circular pool.

Area of the circular pool is calculated as;

A = πr²

where;

A = π (15 ft / 2)²

A = 176.7 ft²

The area of the rectangle is calculated as follows;

A = length x breadth

A = 20 ft x 30 ft

A = 600 ft²

The number of plastic tubing needed to fit around the edge of the pool is calculated as;

The difference in the area = 600 ft² - 176.7 ft² = 423.3 ft²

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Answer:

2.05m

Step-by-step explanation:

The sample proportion p should be between 0.3574 and 0.4426

Given a population proportion of 0.40, a random sample of size 300 will be taken and the sample proportion p will be used to estimate the population proportion.

We need to find the z-value for a sample proportion p.

Using the z-table, we get that the z-value for a sample proportion p is:

z = (p - P) / √[P(1 - P) / n]

where p = sample proportion

          P = population proportion

          n = sample size

Substituting the given values, we get

z = (p - P) / √[P(1 - P) / n]

  = (p - 0.40) / √[0.40(1 - 0.40) / 300]

  = (p - 0.40) / √[0.24 / 300]

  = (p - 0.40) / 0.0277

We need to find the values of p for which the z-score is less than -1.65 and greater than 1.65.

The z-score less than -1.65 is obtained when

p - 0.40 < -1.65 * 0.0277p < 0.3574

The z-score greater than 1.65 is obtained when

p - 0.40 > 1.65 * 0.0277p > 0.4426

Therefore, the sample proportion p should be between 0.3574 and 0.4426 to satisfy the given conditions.

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The mean, μ, for the binomial distribution which has the stated values of n and p is 7.6. Hence, option D is the correct answer.

Binomial distribution is calculated by multiplying the probability of success raised to the power of the number of successes and the probability of failure raised to the power of the difference between the number of successes and the number of trials.

Given the values, n = 38 and p = 0.2Find the mean, μ, for the binomial distribution.The formula to find the mean for binomial distribution is:μ = npwhere,μ = meann = total number of trialsp = probability of successIn the given problem,

n = 38 and p = 0.2.μ = npμ = 38 × 0.2μ = 7.6

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Based on triangle DEF, the missing side lengths include the following:

10. d = 5.1423 units, e = 6.1284 units.

11. e = 17.2516 units, f = 21.6013 units.

12. d = 24.7365 units, f = 26.8727 units.

In order to determine the missing side lengths, we would apply cosine ratio because the given side lengths represent the adjacent side and hypotenuse of a right-angled triangle.

cos(θ) = Adj/Hyp

Where:

Part 10.

By substituting the given side lengths cosine ratio formula, we have the following;

cos(40) = e/8

e = 8cos40

e = 6.1284 units.

d² = f² - e²

d² = 8² - 6.1284²

d = 5.1423 units.

Part 11.

E = 53°, d = 13.

cos(53) = 13/f

f = 13/cos(53)

f = 21.6013 units.

e² = f² - d²

e² = 21.6013² - 13²

e = 17.2516 units.

Part 12.

D = 67°, E = 10.5.

cos(67) = 10.5/f

f = 10.5/cos(67)

f = 26.8727 units.

d² = f² - e²

d² = 26.8727² - 10.5²

d = 24.7365 units.

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The common ratio of the geometric sequence is: 2/3.

Common ratio, r = a term divided by the consecutive term in the series.

Given the geometric sequence, 54, 36, 24, 16 ...

common ratio (r) = [tex]\frac{16}{24}[/tex] = [tex]\frac{2}{3}[/tex].

[tex]\frac{24}{36}[/tex] = [tex]\frac{2}{3}[/tex].

[tex]\frac{36}{54}[/tex] = [tex]\frac{2}{3}[/tex].

Therefore, the common ratio of the geometric sequence is: 2/3.

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the quotient is a constant value of 2/3. Therefore, the common ratio for the given geometric sequence is 2/3.

The given sequence is a decreasing geometric sequence, and the common ratio can be found by dividing any term of the sequence by its previous term.Let's divide 36 by 54,24 by 36, and 16 by 24 to determine the common ratio:$$\begin{aligned} \frac{36}{54} &=\frac{2}{3} \\ \frac{24}{36} &= \frac{2}{3} \\ \frac{16}{24} &=\frac{2}{3} \end{aligned}$$As seen above, the quotient is a constant value of 2/3. Therefore, the common ratio for the given geometric sequence is 2/3.

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The probability that 130 or fewer individuals will pay their monthly bills on time is approximately 0. The probability that 105 or fewer individuals will pay their monthly bills on time is also approximately 0.

The standard error of the proportion is calculated as the square root of (p*(1-p))/n, where p is the proportion (0.59) and n is the sample size (210). Plugging in these values, we get SE = sqrt((0.59*(1-0.59))/210) ≈ 0.0300 (rounded to four decimal places).

b. To find the probability that 130 or fewer individuals will pay their monthly bills on time, we use the normal distribution. We calculate the z-score as (130 - µ)/σ, where µ is the mean (p*n) and σ is the standard deviation. The probability can be found by evaluating the cumulative distribution function (CDF) at the z-score. For P(X ≤ 130), we have Φ((-0.38 - 0)/(0.0300)) ≈ Φ(-12.67) ≈ 0 (rounded).

c. Similarly, we calculate P(X ≤ 105) by finding the z-score and evaluating the CDF. P(X ≤ 105) ≈ Φ((-4.67 - 0)/(0.0300)) ≈ Φ(-155.67) ≈ 0 (rounded).

d. To find the probability that 129 or more individuals will pay their monthly bills on time, we calculate P(X ≥ 129) as 1 - P(X ≤ 128). P(X ≥ 129) ≈ 1 - Φ((128 - 0)/(0.0300)) ≈ 1 - Φ(4266.67) ≈ 0 (rounded).

e. To find the probability that between 116 and 128 individuals will pay their monthly bills on time, we calculate P(116 ≤ X ≤ 128) as P(X ≤ 128) - P(X ≤ 115). P(116 ≤ X ≤ 128) ≈ Φ((128 - 0)/(0.0300)) - Φ((115 - 0)/(0.0300)) ≈ Φ(4266.67) - Φ(3833.33) ≈ 0 (rounded).

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Therefore, the values of k for which the function y cos(kt) satisfies the differential equation 49y" - 100y = 0 are k = 10/7 and k = -10/7. Therefore, for every value of A and B, the family of functions y = A sin(kt) + B cos(kt) is also a solution to the given differential equation.

(a) To find the values of k for which the function y cos(kt) satisfies the differential equation 49y" - 100y = 0, we substitute y = cos(kt) into the differential equation and solve for k:

[tex]49y" - 100y = 49(cos(kt))" - 100(cos(kt)) = -49k^2 cos(kt) - 100cos(kt)[/tex]

For this expression to equal zero, we need[tex]-49k^2 cos(kt) - 100cos(kt) =[/tex]0.

Factoring out cos(kt), we have cos(kt)[tex](-49k^2 - 100) = 0.[/tex]

Since cos(kt) cannot be zero for all values of t, we focus on the second factor: [tex]-49k^2 - 100 = 0.[/tex]

Solving this quadratic equation, we get:

[tex]k^2 = -100/49[/tex]

Taking the square root of both sides (considering both positive and negative roots), we have:

k = ±10/7

(b) To verify that every member of the family of functions y = A sin(kt) + B cos(kt) is also a solution to the differential equation, we substitute y = A sin(kt) + B cos(kt) into the differential equation and simplify:

y = A sin(kt) + B cos(kt)

y' = Ak cos(kt) - Bk sin(kt)

[tex]y" = -Ak^2 sin(kt) - Bk^2 cos(kt)[/tex]

Substituting these expressions into the differential equation 49y" - 100y, we have:

=[tex]49(-Ak^2 sin(kt) - Bk^2 cos(kt)) - 100(A sin(kt) + B cos(kt))\\ -49Ak^2 sin(kt) - 49Bk^2 cos(kt) - 100A sin(kt) - 100B cos(kt)[/tex]

Rearranging the terms, we get:

[tex](-49Ak^2 - 100A)sin(kt) + (-49Bk^2 - 100B)cos(kt)[/tex]

Comparing this expression with the right-hand side of the differential equation, we find:

A solution for the differential equation is given by:

[tex]49y" - 100y = (-49Ak^2 - 100A)sin(kt) + (-49Bk^2 - 100B)cos(kt) = 0[/tex]

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Answer:

y = 4x + 7

Step-by-step explanation:

The slope-intercept form is y = mx + b

-8x + 2y = 14

Add 8x on both sides

2y = 8x + 14

Divided by 2 both sides

y = 4x + 7

So, the slope-intercept form of this equation is y = 4x + 7

The equation is:

Work/explanation:

We should write [tex]-8x+2y=14[/tex] in slope intercept form, which is [tex]\boldsymbol{\pmb{y=mx+b}}[/tex].

Let's rearrange the terms first:

[tex]\boldsymbol{-8x+2y=14}[/tex]

[tex]\boldsymbol{2y=14+8x}[/tex]

[tex]\boldsymbol{2y=8x+14}[/tex]

Divide each side by 2.

[tex]\boldsymbol{y=4x+7}[/tex]

The 98% confidence interval for B₁ is (38.037, 41.963), and the 95% confidence interval for B₁ is (38.586, 41.414).

To construct a confidence interval for B₁, we need the standard error of B₁, denoted SE(B₁). Using the information, B₁ = 40, s = 5.4, SSzz = 53, and n = 16, we can calculate SE(B₁) as SE(B₁) = s / sqrt(SSzz) = 5.4 / sqrt(53) ≈ 0.741.

For a 98% confidence interval, we use a t-distribution with (n - 2) degrees of freedom. With n = 16, the degrees of freedom is (16 - 2) = 14. Consulting the t-table, the critical value for a 98% confidence level with 14 degrees of freedom is approximately 2.650.

Using the formula for the confidence interval, the 98% confidence interval for B₁ is given by B₁ ± t * SE(B₁) = 40 ± 2.650 * 0.741 = (38.037, 41.963).

For a 95% confidence interval, we use the same SE(B₁) value but a different critical value. The critical value for a 95% confidence level with 14 degrees of freedom is approximately 2.145.

The 95% confidence interval for B₁ is given by B₁ ± t * SE(B₁) = 40 ± 2.145 * 0.741 = (38.586, 41.414).

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The obtained values are where (f – g)(x) is above the x-axis, i.e., (f – g)(x) is positive.The interval where this occurs is (–2, [infinity]). The correct option is (–2, [infinity]).

Given the linear functions f (x) and g(x) in the tables, the solution to the expression (f – g)(x) is positive where x is in the interval (–2, [infinity]).

The table has the following values:

x -8 -5 -2 1 4

f(x) -4 -6 -8 -10 -12

g(x) -14 -11 -8 -5 -2

To find (f – g)(x), we have to subtract each element of g(x) from its corresponding element in f(x) and substitute the values of x.

Therefore, we have:(f – g)(x) = f(x) - g(x)

Now, we can complete the table for (f – g)(x):

x -8 -5 -2 1 4

f(x) -4 -6 -8 -10 -12

g(x) -14 -11 -8 -5 -2

(f – g)(x) 10 5 0 -5 -10

To find where (f – g)(x) is positive, we only need to look at the values of x such that (f – g)(x) > 0.

These values are where (f – g)(x) is above the x-axis, i.e., (f – g)(x) is positive.

The interval where this occurs is (–2, [infinity]).

Therefore, the correct option is (–2, [infinity]).

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Answer:

9/5 * 2/3 = 6/5 units^3  

Step-by-step explanation:

the volume is the area multiplied by the new side:
9/5 units^2  *  2/3  = 18/15 units^3

By simplifying the fraction by 3 we have

(18/15) /  (3/3)= 6/5 units^3

The Vertices should be placed at (0, 1) and (0, -1) to maximize the area of the rectangle.

To maximize the area of a rectangle, we need to find the dimensions that will yield the largest possible product of length and width. In this case, the rectangle has one side on the x-axis, so the length of the rectangle will be determined by the x-coordinate of the upper vertices.

Given that the upper two vertices of the rectangle lie on the graph of y = e^(-3x^2), we can find the coordinates of these vertices by finding the x-values that maximize the function e^(-3x^2).

To find the maximum value of e^(-3x^2), we can take the derivative with respect to x and set it equal to zero. Let's denote the function as f(x) = e^(-3x^2):

f'(x) = -6x * e^(-3x^2)

Setting f'(x) = 0, we have:

-6x * e^(-3x^2) = 0

Since e^(-3x^2) is always positive, the only solution to this equation is x = 0. Therefore, the function f(x) has a maximum at x = 0.

Now, let's find the y-coordinate at x = 0 by evaluating y = e^(-3(0)^2):

y = e^0 = 1

Therefore, the coordinates of one of the upper vertices of the rectangle are (0, 1).

Since the rectangle has one side on the x-axis, the other upper vertex will have the same y-coordinate as the first vertex. So, the coordinates of the second upper vertex are (-x, 1), where x is the distance between the two vertices along the x-axis.

By symmetry, the rectangle formed will be a square. The side length of the square will be twice the x-coordinate of one of the upper vertices, which is 2x.

Therefore, to maximize the area of the rectangle (which is the square's area), we need to maximize the side length, which occurs when x is maximized.

Since x = 0 is the maximum value for x, the vertices of the rectangle should be placed at (0, 1) and (0, -1) to maximize the area of the rectangle.

Thus, the vertices should be placed at (0, 1) and (0, -1) to maximize the area of the rectangle.

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a. The confidence interval has a lower limit of 0.0836 and an upper limit of 0.1624.

b. The margin of error is 0.0394.

c. Since the confidence interval does not include the population proportion from 2016 (0.138).

a. Construct a 95% confidence interval to estimate the actual proportion of people who smoked in the country in 2018.

Since the population proportion is known, it is a case of estimating a population proportion based on a sample statistic.

We will use a normal distribution for the sample proportion with a mean of 0.138 (given) and a standard deviation of [tex]\sqrt{ (0.138 * 0.862 / 526) }[/tex]

= 0.0201.

The margin of error at a 95 percent confidence level will be 1.96 times the standard error.

Therefore, the margin of error is 1.96(0.0201) = 0.0394

We can calculate the 95% confidence interval as follows:

Confidence interval = Sample statistic ± Margin of error Sample statistic

= p = 65/526

= 0.123
There is a 95% probability that the actual proportion of people who smoked in the country in 2018 is between 0.123 - 0.0394 and 0.123 + 0.0394, or between 0.0836 and 0.1624.

Therefore, the confidence interval has a lower limit of 0.0836 and an upper limit of 0.1624.

b. The margin of error is 0.0394.

c. This sample provides evidence that this proportion has changed since 2016, since the confidence interval does not include the population proportion from 2016 (0.138).

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The polynomial P(a) = [tex]a^17[/tex]+ 16 has two terms. The first term is [tex]a^17[/tex], and the second term is the constant term 16.

Polynomials are algebraic expressions that may comprise of exponents which are added, subtracted or multiplied. Polynomials are of different types. Namely, Monomial, Binomial, and Trinomial.

Polynomials can be classified by the number of terms with nonzero coefficients, so that a one-term polynomial is called a monomial, a two-term polynomial is called a binomial, and a three-term polynomial is called a trinomial. The term "quadrinomial" is occasionally used for a four-term polynomial.

In mathematics, a polynomial is an expression consisting of variables (also called indeterminates) and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables. An example of a polynomial of a single indeterminate x is x2 − 4x + 7

The polynomial P(a) = [tex]a^17[/tex]+ 16 has two terms. The first term is [tex]a^17[/tex], and the second term is the constant term 16.

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The probability density function (PDF) of XI, the lifetime of a certain type of device, is defined as follows:

f(x) = 0, if x ≤ 21

f(x) = 1/21, if x > 21

This means that for any value of x less than or equal to 21, the PDF is zero, indicating that the device cannot have a lifetime less than or equal to 21 months.

For values of x greater than 21, the PDF is 1/21, indicating that the device has a constant probability of 1/21 per month of surviving beyond 21 months.

In other words, the device has a deterministic lifetime of 21 months or less, and after 21 months, it has a constant probability per month of continuing to operate.

It's important to note that this PDF represents a simplified model and may not accurately reflect the actual behavior of the device in real-world scenarios.

It assumes that the device either fails before or exactly at 21 months, or it continues to operate indefinitely with a constant probability of failure per month.

To calculate probabilities or expected values related to the lifetime of the device, additional information or assumptions would be needed, such as the desired time interval or specific events of interest.

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A boy has five coins of different denomination. So, the different types of denomination are as follows:Coin 1Coin 2Coin 3Coin 4Coin 5Therefore, the possible sum of money that the boy can form using these coins is as follows:Coin 1Coin 2Coin 3Coin 4Coin 5Coin 1 + Coin 2Coin 1 + Coin 3Coin 1 + Coin 4Coin 1 + Coin 5Coin 2 + Coin 3Coin 2 + Coin 4Coin 2 + Coin 5Coin 3 + Coin 4Coin 3 + Coin 5Coin 4 + Coin 5.

The total number of possible sums of money that can be formed is equal to the number of subsets of a set consisting of five elements. The formula to calculate the total number of subsets of a set of n elements is 2ⁿ, where n is the number of elements in the set.Therefore, in this case, the number of possible sums of money that can be formed is 2⁵ = 32. Hence, the boy can form 32 different sums of money using five coins of different denominations.Out of 5 Statisticians and 4 Psychologists, a committee consisting of 2 Statisticians and 3 members in total can be formed using the combination formula. The formula to calculate the number of combinations of n objects taken r at a time is given by nCr = (n!)/(r!*(n-r)!).In this case, the number of Statisticians (n) = 5 and the number of Psychologists = 4. We need to form a committee consisting of 2 Statisticians and 3 members. Therefore, r = 2 and n - r = 3.So, the number of ways to form such a committee is given by:5C2 * 4C3= (5!)/(2!*(5-2)!) * (4!)/(3!*(4-3)!)= (5*4)/(2*1) * 4= 40.Hence, there are 40 ways to form a committee consisting of 2 Statisticians and 3 members from a group of 5 Statisticians and 4 Psychologists.

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(a).The conditional probability P(A|B) ≈ 66.7%

(b). The conditional probability P(B|A) ≈ 80%

(a) To find P(A|B), we use the formula for conditional probability:

P(A|B) = P(A ∩ B) / P(B)

Given that P(A ∩ B) = 0.40 and P(B) = 0.60, we can substitute these values into the formula:

P(A|B) = 0.40 / 0.60 = 0.67

Converting this to a percentage and rounding to 1 decimal place, we get:

P(A|B) ≈ 66.7%

(b) Similarly, to find P(B|A), we use the formula:

P(B|A) = P(A ∩ B) / P(A)

Given that P(A ∩ B) = 0.40 and P(A) = 0.50, we substitute these values:

P(B|A) = 0.40 / 0.50 = 0.80

Converting this to a percentage and rounding to 0 decimal places, we get:

P(B|A) ≈ 80%

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Here's the LaTeX representation of the explanation:

The equation [tex]$r^2 = 7$[/tex] represents a circle in polar coordinates with a radius of [tex]$\sqrt{7}$.[/tex] To convert it into Cartesian coordinates, we can use the relationship between polar and Cartesian coordinates:

[tex]\[r^2 = x^2 + y^2\][/tex]

Substituting [tex]$r^2 = 7$[/tex] , we have:

[tex]\[7 = x^2 + y^2\][/tex]

This is the equation of a circle in Cartesian coordinates centered at the origin [tex]$(0, 0)$[/tex] with a radius of [tex]$\sqrt{7}$.[/tex]

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If Suppose that we have conducted a hypothesis test for one proportion, and the p-value of the test is 0.13. At \alphaα=0.05, then the type oferror is b) Fail to reject the null hypothesis. We might have committed the type II error.

When the p-value of a hypothesis test is greater than the chosen significance level (α), we fail to reject the null hypothesis. In this case, the p-value is 0.13, which is greater than α = 0.05.

Therefore, we fail to reject the null hypothesis. If we fail to reject the null hypothesis when it is actually false, it means we might have committed a type II error.

Type II error occurs when we fail to reject the null hypothesis even though the alternative hypothesis is true. It implies that we failed to detect a significant difference or effect that truly exists.

In this situation, there is a possibility that we made an incorrect conclusion by accepting the null hypothesis when it should have been rejected. The probability of committing a type II error is denoted as β (beta). The higher the β value, the higher the chance of making a type II error.

Therefore, the correct answer is b) Fail to reject the null hypothesis. We might have committed the type II error.

Therefore the correct answer is b).

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The probability distribution function of Y is given as:

Y          P(Y)

0         0.0115

1          0.0836

2         0.2330

3         0.3343

4         0.2733

5         0.1458

6         0.0563

7         0.0165

8          0.0037

9          0.0006

10         0.0001

11          0.0000

-                 -

20        0.0000

The random variable Y represents the number of questions a student guesses correctly out of 20.

Each question has 5 choices, so the probability of guessing a question correctly by chance is 1/5, and the probability of guessing incorrectly is 4/5.

Y follows a binomial distribution since each question is an independent trial with two possible outcomes (correct or incorrect), and the probability of success (guessing correctly) remains constant.

To find the probability distribution function (pdf) of Y, we can use the binomial distribution formula:

[tex]P(Y = k) = C(n, k)\times p^k (1 - p)^(^n ^- ^k^)[/tex]

Where:

n is the number of trials (number of questions), which is 20 in this case.

k is the number of successful trials (number of correct guesses).

p is the probability of success (probability of guessing a question correctly), which is 1/5 in this case.

C(n, k) represents the binomial coefficient, which is the number of ways to choose k successes from n trials, given by C(n, k) = n! / (k!(n-k)!)

Let's calculate the probabilities for each possible value of Y:

Y = 0: The student guesses none of the questions correctly.

P(Y = 0) = C(20, 0)×(1/5)⁰×(4/5)²⁰

= 1 × 1 × (4/5)²⁰ = 0.0115

Y = 1: The student guesses exactly one question correctly.

P(Y = 1) = C(20, 1) × (1/5)¹ × (4/5)²⁰⁻¹

= 20 × (1/5) × (4/5)¹⁹ = 0.0836

Continuing this process for all possible values of Y up to 20, we can create the table.

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A philosophy professor decides to give a 20 question multiple-choice quiz to determine who has read an assignment. Each question has 5 choices. Let Y be the random variable that counts the number of questions that a student guesses correctly. You can assume that questions and answers are independent. a. Find the probability distribution function of Y by making a table of the possible values of Y and their corresponding probabilities.

The optimal solution is (19, 25.3)

The optimal objective function value is 202.5

From the question, we have the following parameters that can be used in our computation:

Objective function, Max: 4X₁ + 5X₂

Subject to

2X₁ + 3X₂ ≤ 114

4X₁ + 3X₂ ≤ 152

X₁ + X₂ ≤ 85

X₁, X₂ ≥ 0

Next, we plot the graph (see attachment)

The coordinates of the feasible region is (19, 25.3)

Substitute these coordinates in the above equation, so, we have the following representation

Max = 4 * (19) + 5 * (25.3)

Max = 202.5

The maximum value above is 202.5 at (19, 25.3)

Hence, the maximum value of the objective function is 202.5

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We can conclude that the given series diverges.

determine whether the series converges or diverges. [infinity] 3 n2 9 n = 1

The series can be represented as below:[infinity]3n² / (9n)where n = 1, 2, 3, .....On simplifying the given series, we get:3n² / (9n) = n / 3

As the given series can be reduced to a harmonic series by simplifying it,

therefore, it is a divergent series.

The general formula for a p-series is as follows:∑ n^(-p)The given series cannot be considered as a p-series as it doesn't satisfy the condition, p > 1. Instead, the given series is a harmonic series. Since the harmonic series is a divergent series, therefore, the given series is also a divergent series.

Thus, we can conclude that the given series diverges.

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The y-intercept of the quadratic function f(x) = (x – 8)(x + 3) is (0, –24).

The quadratic function f(x) = (x – 8)(x + 3) is given. In the general form, a quadratic equation can be represented as f(x) = ax² + bx + c, where x is the variable, and a, b, and c are constants. We can rewrite the given quadratic function into this form: f(x) = x² - 5x - 24Here, the coefficient of x² is 1, so a = 1. The coefficient of x is -5, so b = -5. And the constant term is -24, so c = -24. Hence, the quadratic function is f(x) = x² - 5x - 24. Now, to find the y-intercept of this function, we can substitute x = 0. Therefore, f(0) = 0² - 5(0) - 24 = -24. So, the y-intercept of the quadratic function f(x) = (x – 8)(x + 3) is (0,-24).The y-intercept of the quadratic function f(x) = (x – 8)(x + 3) is (0, -24).

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Each level curve represents the points where the function is equal to a particular constant.

A contour map is a graphical representation of an equation that shows how the value of the equation changes over a two-dimensional plane.

The contours are used to visualize where the equation is equal to a particular constant.

In order to draw the contour map of f(x, y) = (x2 -y2), we first need to set it equal to different constants and solve for y.

That is f(x,y)= (x^2 - y^2) = c (where c is a constant)

Then, we solve for y:y = sqrt(x^2 - c) and y = -sqrt(x^2 - c)

We can now plot the values of x and y on a graph and connect the points to form the level curves.

Each level curve represents the points where the function is equal to a particular constant.

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Given the curve C parametrized by r(t), where C is defined by the equation x² + y² = 9, we need to evaluate the line integral ∮C F · dr directly, by hand.

To evaluate the line integral ∮C F · dr, we first need to express the curve C in terms of its parametrization r(t).

Since C is defined by x² + y² = 9, we can choose a parametrization such as r(t) = (3cos(t), 3sin(t)), where t is the parameter.

Next, we need to evaluate the dot product F · dr along the curve C. However, the vector field F is not given in the question.

In order to compute F · dr, we need to know the vector field F explicitly.

Once we have the vector field F, we substitute the parametrization r(t) into F and evaluate the dot product F · dr.

The result will depend on the specific form of the vector field F and the parametrization r(t).

Without the explicit form of the vector field F, it is not possible to compute the line integral ∮C F · dr directly by hand.

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A pair of dice is rolled. The 36 different possible pair of dice results are illustrated, on the 2-dimensional grid alongside are as follows :

a) Probability of getting two 3s:

[tex]\(\frac{{1}}{{36}}\)[/tex]

b) Probability of getting a 5 and a 6:

[tex]\(\frac{{2}}{{36}} = \frac{{1}}{{18}}\)[/tex]

c) Probability of getting a 5 or a 6:

[tex]\(\frac{{11}}{{36}}\)[/tex]

d) Probability of getting at least one 6:

[tex]\(\frac{{11}}{{36}}\)[/tex]

e) Probability of getting exactly one 6:

[tex]\(\frac{{10}}{{36}} = \frac{{5}}{{18}}\)[/tex]

f) Probability of getting no sixes:

[tex]\(\frac{{25}}{{36}}\)[/tex]

g) Probability of getting a sum of 7:

[tex]\(\frac{{6}}{{36}} = \frac{{1}}{{6}}\)[/tex]

h) Probability of getting a sum of 7 or 11:

[tex]\(\frac{{8}}{{36}} = \frac{{2}}{{9}}\)[/tex]

i) Probability of getting a sum greater than 8:

[tex]\(\frac{{20}}{{36}} = \frac{{5}}{{9}}\)[/tex]

j) Probability of getting a sum of no more than 8:

[tex]\(\frac{{16}}{{36}} = \frac{{4}}{{9}}\)[/tex]

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Yes, the interaction effect is significant. The appropriate statistical test for the interaction effect is reported as F(1.99, 194.78) = 129.32, p < .001. The partial eta squared value is .57, indicating a large effect size.

The interaction effect refers to the combined effect of two or more independent variables on the dependent variable. In this case, the interaction between the variables "Year Level" and "Gender" is being examined. The output provides the results of the tests for the interaction effect.

The F-value is given as F(1.99, 194.78) = 129.32. The degrees of freedom (df) for the interaction effect are 2 and 196. The p-value is reported as p < .001.

Based on the statistical test, the interaction effect between "Year Level" and "Gender" is significant (p < .001). Additionally, the partial eta squared value of .57 suggests a large effect size, indicating that the interaction between the two variables has a substantial impact on the dependent variable, "Anxiety."

It's important to note that the assumption of sphericity has been met in this analysis.

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