(08.05 MC)The following box plot shows the number of books sold each day at a bookstore for 40 days. How many days did the bookstore sell 2 to 12 books?


A box plot is drawn with end points at 0 and 16. The box extends from 2 to 12 and a vertical line is drawn inside the box at 7


2

4

10

20

Answer:

Yes

Step-by-step explanation:

First we need to determine how much money Allen has

2 dollars = 2.00

5 quarters = 5 * .25 = 1.25

2 dimes = 2 * .10 = .20

7 pennies = 7 * .01 = .07

Add this together

2.00 + 1.25+.20+.07 =3.52

3.52 > 3.50

This is more than 3.50 so he has enough money to buy the pencils

The amount of interest that Bertha Wooten's deposit will earn in 31 days is $38.59, which is the difference between the future value and the present value.

The future value represents the amount that will be in the account after the present value investment is compounded at an interest rate periodically.

The future value of an investment can be calculated using the future value formula, A = P (1 + i)^n.

Where:

A = future value

P = Present value of investment

i = interest rate

n = number of periods.

The future value of the investment can also be determined using an online finance calculator, as follows.

Then the interest is the difference between the future value and the present value.

Initial deposit = $8,241.78

Interest rate = 5.5% compounded daily

Investment period = 31 days

N (# of periods) = 31 days

I/Y (Interest per year) = 5.5%

PV (Present Value) = $8,241.78

PMT (Periodic Payment) = $0

Results:

FV = $8,280.37

Total Interest $38.59 ($8,280.37 - $8,241.78)

Thus, the amount of interest that Bertha Wooten's deposit will earn in 31 days is $38.59.

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the unit price is $3 per pound, the correct option is the second one.

The unit price for the oranges is just the price for one pound of oranges.

Here we know that the price of 4 lb of oranges is $12, with that we want to get the cost of a single lb of oranges, so we can write:

4lb = $12

If we divide both sides by 4, then we get:

4lb/4 = $12/4

1lb = $3

This means that the price of 1 pound of oranges is $3, then the unit price is $3 per pound, the correct option is the second one.

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Thus, 2028 needs to be multiplied by 3 to become a perfect square. Therefore, the number 6084 has 3 pairs of equal prime factors . Hence, the smallest number by which 2028 must be multiplied so that the product is a perfect square is 7

The roots of the given polynomials exist  [tex]$x=8+\sqrt{10}$[/tex], and [tex]$x=8-\sqrt{10}$[/tex].

For a quadratic equation of the form [tex]$a x^{2}+b x+c=0$[/tex] the solutions are

[tex]$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$[/tex]

Therefore by using the formula we have

[tex]$x^{2}-16 x+54=0$$[/tex]

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

[tex]$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$[/tex]

simplifying the equation, we get

[tex]$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\[/tex]

[tex]$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\[/tex]

[tex]$&x=8+\sqrt{10}, x=8-\sqrt{10}[/tex]

Therefore, the roots of the given polynomials are [tex]$x=8+\sqrt{10}$[/tex], and

[tex]$x=8-\sqrt{10}$[/tex].

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Answer:

x=8-[tex]\sqrt{10}[/tex] and x=8+[tex]\sqrt{10}[/tex]

Step-by-step explanation:

It was right for me

The Five number summary for the given data:

Minimum: 24

Lower quartile: Q1 = 29

Median: 43

Upper quartile: Q3 = 50

Maximum: 56

Interquartile range: IQR = 21

The interquartile range is calculated by

IQR = Q3 - Q1

Where Q3 - upper quartile and Q1 - lower quartile

Q3 = 3/4(n + 1) th term

Q1 = 1/4(n + 1) th term

The given data points are

24, 27, 29, 29, 35, 39, 43, 45, 46, 49, 51, 51, 56

where n = 13

Maximum data value = 56

Minimum data value = 24

Calculating Median:

Median = (n+1)/2 th term

⇒ Median = (13 + 1)/2 = 7th term

∴ Median = 43

Calculating the quartiles:

Upper quartile Q3 = 3/4(n + 1)th term

⇒ Q3 = 3/4(13 + 1) = 10.5

⇒ Q3 = 10th term + 1/2(11th term - 10th term)

⇒ Q3 = 49 + 1/2(51 - 49)

⇒ Q3 = 49 + 1

∴ Q = 50

Lower quartile Q1 = 1/4(n + 1)th term

⇒ Q1 = 1/4(13 + 1) = 3.5

⇒ Q1 = 3rd term + 1/2(4th term - 3rd term)

⇒ Q1 = 29 + 1/2(29 - 29)

∴ Q1 = 29

Calculating the IQR:

IQR = Q3 - Q1

      = 50 - 29

      = 21

Thus, the interquartile range is 21.

Therefore, the five-number summary for the given data:

Minimum: 24

Lower quartile: Q1 = 29

Median: 43

Upper quartile: Q3 = 50

Maximum: 56

Interquartile range: IQR = 21

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[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]

Average speed (v) :

[tex]\qquad❖ \: \sf \:v = \cfrac{total \: \: distance \: \: covered}{total \: \: time \: \: taken} [/tex]

[tex]\qquad❖ \: \sf \:v = \dfrac{16.4}{1.5} [/tex]

[tex] \qquad \large \sf {Conclusion} : [/tex]

[tex]\qquad❖ \: \sf \:v = 11 \: \: kmph[/tex]

Answer:

Option 2

Step-by-step explanation:

Using the quadrstic formula,

[tex]\tan \theta=\frac{-2 \pm \sqrt{2^2 - 4(\sqrt{3})(-\sqrt{3})}}{2\sqrt{3}} \\ \\ =\frac{-2 \pm 4}{2\sqrt{3}} \\ \\ =\frac{-1 \pm 2}{\sqrt{3}} \\ \\ = -\sqrt{3}, \frac{1}{\sqrt{3}}[/tex]

Case 1

[tex]\tan \theta=-\sqrt{3} \implies \theta=\frac{2\pi}{3}, \frac{5\pi}{3}[/tex]

Case 2

[tex]\tan \theta=\frac{1}{\sqrt{3}} \implies \theta=\frac{\pi}{6}, \frac{7\pi}{6}[/tex]

Two regular octagons and eight congruent rectangles are perfect for the creation of 3-D figures.

According to the statement

we have to tell and explain about the types of shapes which are required for the creations of 3-D figure.

For this purpose, Firstly we have to know about the 3-D figures.

So,

A shape is a graphical representation of an object or its external boundary and outline, as opposed to other properties such as color, texture, or material type.

A plane shape is constrained to lie on a plane, in contrast to solid 3-D shapes.

After that we know that the

When the all dimensions of a given shape can be observed at the same time, then its is said to be in a 3-D. However, polygons are shapes which has 3 or mores sides. Examples are: trigon, hexagon, octagon etc.

Thus, since the in the 3-D figure have 8 sides connected which is greater than their width.

This confirms that the sides of the figure made up of eight congruent rectangles, because the 3-D figure has eight regular sides. Then, the height of the figure would be the length of the rectangles.

After that all this condition, Two regular octagons and eight congruent rectangles are perfect for the creation of 3-D figures.

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[tex]5(1.5)=\boxed{7.5 \text{ yd}}[/tex]

The length of the curved border or arc is 7.5 yards.

the length of the arc = [tex]\theta \times r[/tex]

given that [tex]\theta[/tex] = 1.5 radian

radius = 5 yards

then the length of arc from the above formula

[tex]l = \theta \times r\\l = 1.5 \times 5 = 7.5[/tex] yards

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area is 1/2 times base times height

triangle A

1/2 times 7 times 9

answer 31.5

Triangle B

1/2 times 7 times 5

answer 17.5

Step-by-step explanation:

8x+6y=24

6y=24-8x

y=24/6 - 8/6x

y=4-4/3x

Answer:

Step-by-step explanation:

If 12 men are needed to run 4 machines. How many men are needed to run 20

we can solve with an equation

12 : 4 = x : 20

x = 12 * 20 : 4

x = 240 : 4

x = 60

----------------------------

check

12 : 4 = 60 : 20

3 = 3

the answer is good

Answer:

y = -5/3 - 8

Step-by-step explanation:

We want to write this in the form y = mx + b.  We need to find the m (slope) and the b (y-intercept) ,  Whew, they already gave us the slope, so we are have way there.  I will plug in the x and y that we are given from the point (-6, 8) to solve for b.

y = mx + b

8 = -5/3(-6) + b  Multiply the fraction by -6

8 = 30/3 + b  I can make 6 a fraction by writing it 6/1 and then just multiply straight across.  A negative times a negative is a positive.

8 = 10 + b   30/3 is equal to 10.  Now subtract 10 from both sides to get b

-8 = b

I can now write the equations since I now know m and b.

y = -5/3 + (-8) which is the same as y = -5/3 - 8.  Adding a negative is the same as subtracting a positive.

Answer:

15

Step-by-step explanation:

Note: Take note , absolute value will give the magnitude of the value. (Which means ignoring the + / - signs.)

Eg. | - 19 | = 19

Therefore,

[tex] \frac{12(30 - (9 + {4}^{2})) }{10 - | - 6| } \\ = \frac{12(30 - (9 + 16))}{10 - 6} \\ = \frac{12(30 - 25)}{4} \\ = \frac{12(5)}{4} \\ = \frac{60}{4} \\ = 15[/tex]

Answer:

A = 20%

B = 33.33%

C = 46.67%

Step-by-step explanation:

Ok we need to add up 3, 5, and 7

3+5+7 = 15

405/15 = 27.

27*3 = A

27*5 = B

27*7 = C

A = 81 / 20%

B = 135 / 33.33%

C = 189 / 46.67%

Answer:

Smallest number: 5555789

Largest number: 9999875

Step-by-step explanation:

Since each digit must be used at least once, the smallest number that can be formed with the digits 5, 7, 8 and 9 is 5555789 (ascending order of digits with smallest digit used four times

The largest number is 9999875 (descending order of digits with largest digit used four times)

Answer:

1 + x  meters.

Step-by-step explanation:

A square has 4 equal sides so each side will have a length equal to the square root of the area.

Side length = √(1 + 2x + x^2)

                   = √(1 + x)(1 + x)

                   = 1 + x.

Answer:

C. 206 unit^2.

Step-by-step explanation:

Area = 2*11*5 + 2*11*3 + 2*3*5

         = 110 + 66 + 30

         =  206.

Answer:

y = - 2x + 8

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = [tex]\frac{1}{2}[/tex] x - 9 ← is in slope- intercept form

with m = [tex]\frac{1}{2}[/tex]

given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{\frac{1}{2} }[/tex] = - 2

y = - 2x + c ← is the partial equation

to find c substitute (3, 2 ) into the partial equation

2 = - 6 + c ⇒ c = 2 + 6 = 8

y = - 2x + 8 ← equation of perpendicular line

Answer:

1. Transversal y intersects lines m and n; <1 ~= <2 (Given)

2. <1 ~= <3 (Vertical Angles Theorem)

3. <2 ~= <3 (Transitive Property of Congruence)

4. m || n (Converse of Alternate Interior Angles Theorem)

The perimeter of the triangle can be express as follows:

12b + 11d + 2c

The perimeter of a figure is the sum of the whole sides of the figure.

A triangle has three sides. Therefore, the perimeter of a triangle is the sum of the three sides.

Therefore, the sides of the triangle are of lengths (2b + 5c) centimetres, (10b + 7d) centimetres, and (4d-3c) centimetres.

Hence, the perimeter of the triangle can be represented as follows:

Perimeter of the triangle = 2b + 5c + 10b + 7d + 4d - 3c

Perimeter of the triangle = 2b + 10b + 7d + 4d + 5c - 3c

Perimeter of the triangle = 12b + 11d + 2c

Therefore, the perimeter of the triangle can be express as follows:

12b + 11d + 2c

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Answer:

Bottom left

Step-by-step explanation:

Since the slope has to be positive it can't be the ones on the right side since both of them are negative. And the bottom left one is rising 3 and running 4. (formula = rise/run). See image.

The munimum value is, at x = 3/10, y = 5 and 10x+3y/5 = 6.

To find the minimum value of 10x (3y/5):

Given - y = 3/(2x)

So, we want the bare minimum of,

Take the derivative to obtain:

When you set it to zero, you get:

So, at x = 3/10, y = 5 and 10x + 3y/5 = 3 + 3 = 6.

Therefore, the munimum value is, at x = 3/10, y = 5 and 10x+3y/5 = 6.

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City B had the highest noon temperature, Interquartile Range, Larger Median temperature while City A had smaller range of temperature.

A box and whisker plot, also known as a box plot, shows a five-number summary of a set of data. The minimum, first quartile, median, third quartile, and maximum are the five-number summary. A box plot is created by drawing a box from the first to third quartiles. At the median, a vertical line runs through the box. The whiskers move from the lowest to the highest quartile.

From the figure:-

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Answer:

(a) B

(b) B

(c) B

(d) B

Step-by-step explanation:

The points of intersection for the two functions and round to the nearest tenth exists (0.5, 1.4) and (4.85, -0.3).

Given:

f(x) = -0.5x+2

g(x) = x³ - 5x² + 3

The point of intersection exists the point where f(x) = g(x)

x³ - 5x² + 3 = - 0.5x + 2

x³ - 5x² + 3 + 0.5x - 2 = 0

x³ - 5x² + 0.5x + 1 = 0

Factorize and estimate the value of x

Let x = 0.53 and 4.85

substitute the value of x = 0.53

f(0.53) = -0.5(0.53) + 2

f(0.53) = -0.265 + 2

f(0.53) = 1.375

If x = 4.85

f(4.85) = -0.5(4.85) + 2

f(4.85) = -2.425 + 2

f(4.85) = -0.245

Therefore, the points of intersection for the two functions and round to the nearest tenth exists (0.5, 1.4) and (4.85, -0.3).

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1st quartile: 11

median: 38.50000

3rd quartile: 45

Measure descriptive statistics

1st quartile: 11

median: 38.50000

3rd quartile: 45

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I understand that the question you are looking for is :

2 Drag the tiles to the boxes to form correct pairs. Match the values associated with this data set to their correct descriptions.  {6, 47, 49, 15, 43, 41, 7, 36} first quartile 38.5  median 11  third quartile 10.5 the difference of the largest value and the median 45