1) (20 pts) Let T be the Turing machine defined by the following 5-tuples: (So, 0, So, 1, R), (So, 1, $1, 0, R), (S1, 1, $2, 1, R), (S1, B, So, 0, R). For the following tape, determine the intermediate tapes, states, and head positions, and final tape, state, and head position when Thalts. Assume T begins in the initial position. state SO BB0001B0BB

The general solution of the differential equation y ′ + (x+4)y = 0 is  equal to y(x) = 0.

To find the power series expansion for the general solution of the differential equation,

Assume a power series of the form,

y(x) = a₀ + a₁x + a₂x²+ a₃x³ + ...

Differentiating y(x) term by term, we have,

y'(x) = a₁ + 2a₂x + 3a₃x² + ...

Substituting these into the differential equation, we get,

(a₁ + 2a₂x + 3a₃x² + ...) + (x + 4)(a₀ + a₁x + a₂x² + a₃x³ + ...) = 0

Expanding the equation and collecting like terms, we have,

a₁ + (a₀ + 4a₁)x + (2a₂ + a₁)x² + (3a₃ + a₂)x³ + ... = 0

Equating coefficients of like powers of x to zero, we can find the values of a₁, a₂, a₃,....

For the first term, equating the coefficient of x⁰ to zero gives,

a₁ + a₀ = 0 → a₁ = -a₀

For the second term, equating the coefficient of x¹ to zero gives,

a₀ + 4a₁ = 0

Substituting the value of a₁ from the first term, we get,

a₀ + 4(-a₀) = 0

⇒-3a₀ = 0

⇒a₀= 0

Since a₀ = 0, the second equation becomes,

0 + 4a₁ = 0

⇒4a₁ = 0

⇒a₁= 0

Continuing in this manner, we can find the values of a₂, a₃, and so on.

For the third term, equating the coefficient of x² to zero gives,

2a₂ + a₁ = 0

⇒2a₂+ 0 = 0

⇒a₂ = 0

For the fourth term, equating the coefficient of x³ to zero gives,

3a₃ + a₂= 0

⇒3a₃ + 0 = 0

⇒a₃ = 0

The first four nonzero terms in the power series expansion are,

y(x) = a₀ + a₁x + a₂x² + a₃x³ + ...

= 0 + 0x + 0x² + 0x³+ ...

= 0

Therefore, the general solution to the given differential equation is

y(x) = 0.

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The result of the whole-number exponent expressions are

a.  16

b.  -27

c.  16

d.  25

e.  -243

f. 64

Using the definition of whole-number exponent, we can multiply the base integer by itself as many times as the exponent indicates.

For positive exponents, the result is a repeated multiplication of the base. For negative exponents, the result is the reciprocal of the repeated multiplication.

a. 2⁴ = 2 * 2 * 2 * 2 = 16

b. (-3)³ = (-3) * (-3) * (-3) = -27

c. (-2)⁴ = (-2) * (-2) * (-2) * (-2) = 16

d. (-5)² = (-5) * (-5) = 25

e. (-3)⁵ = (-3) * (-3) * (-3) * (-3) * (-3) = -243

f. (-2)⁶ = (-2) * (-2) * (-2) * (-2) * (-2) * (-2) = 64

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The values are 16, -27, 26, 25, -243, 64

Using the extended definition of a whole-number exponent, we can find the values as follows:

a. 2^4 = 2 × 2 × 2 × 2 = 16

b. (-3)^3 = (-3) × (-3) × (-3) = -27

c. (-2)^4 = (-2) × (-2) × (-2) × (-2) = 16

d. (-5)^2 = (-5) × (-5) = 25

e. (-3)^5 = (-3) × (-3) × (-3) × (-3) × (-3) = -243

f. (-2)^6 = (-2) × (-2) × (-2) × (-2) × (-2) × (-2) = 64

So the values are:

a. 2^4 = 16

b. (-3)^3 = -27

c. (-2)^4 = 16

d. (-5)^2 = 25

e. (-3)^5 = -243

f. (-2)^6 = 64

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Two vertices of a graph are adjacent when there is an edge that connects them. This is true for option (d).

Definition of vertices:

Vertices refer to the points or nodes on a graph that are connected by edges.

Definition of adjacent:Two vertices are adjacent when they are directly connected by an edge on the graph.

Definition of graph:Graph refers to a collection of vertices connected by edges. Graphs are used to represent networks, relationships, or connections between objects. Graph theory is a branch of mathematics that studies graphs and their properties.

Therefore, option d is the correct answer i.e. There is an edge that between them.

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Ryan obtained a loan of $12,500 at an interest rate of 5.9% compounded quarterly. He wants to know how long it would take to settle the loan by making payments of $2,810 at the end of every quarter.

To find the time it takes to settle the loan, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:
A = the future value of the loan (the amount to be settled)
P = the initial principal (the loan amount)
r = the annual interest rate (5.9%)
n = the number of compounding periods per year (4, since it's compounded quarterly)
t = the time in years

In this case, we need to find the value of t, so let's rearrange the formula:

t = (log(A/P) / log(1 + r/n)) / n

Now let's substitute the given values into the formula:

A = $12,500 + ($2,810 * x), where x is the number of quarters it takes to settle the loan
P = $12,500
r = 0.059 (converted from 5.9%)
n = 4

We want to find the value of x, so let's plug in the values and solve for x:

x = (log(A/P) / log(1 + r/n)) / n

x = (log($12,500 + ($2,810 * x)) / log(1 + 0.059/4)) / 4

Now, we need to solve this equation to find the value of x.

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$x = 5.8333.$Bonus: Solve $2x - 3 = 5x.$$$2x - 3 = 5x$$$$2x - 5x = 3$$$$-3x = 3$$$$x = \frac{3}{-3} = -1.$$Therefore, $x = -1.$

Let's solve the logarithmic equation by using the following logarithmic rule: $\log_a{b^n} = n\log_a{b}$ with the given equation, $\log_7{x} - \log_7{(x-5)} = 1.$We know that when the subtraction sign is in between two logarithmic terms, we can simplify by using the quotient property of logarithms as follows:$$\log_a\frac{b}{c} = \log_ab - \log_ac.$$Using this rule with the equation above, we can simplify as follows:$$\log_7\frac{x}{x-5} = 1.$$This is the same as saying that $\frac{x}{x-5} = 7^1 = 7.$Let's now solve for $x$ as follows:$$x = 7(x-5)$$$$x = 7x - 35$$$$35 = 6x$$$$x = \frac{35}{6} = 5.8333.$$Therefore, $x = 5.8333.$Bonus: Solve $2x - 3 = 5x.$$$2x - 3 = 5x$$$$2x - 5x = 3$$$$-3x = 3$$$$x = \frac{3}{-3} = -1.$$Therefore, $x = -1.$

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a. To define all subsets of the set {a,b,c,d} using a decision tree, we can start by considering whether or not each element is included in each subset.

Let's create a decision tree:
1. Start with an empty set: {}
2. Choose to include or exclude 'a':
  - Include 'a': {a}
  - Exclude 'a': {}
3. For each resulting subset, consider whether or not to include 'b':
  - Include 'b' in the subsets containing 'a': {a, b}
  - Exclude 'b' in the subsets containing 'a': {a}
  - Include 'b' in the subsets without 'a': {b}
  - Exclude 'b' in the subsets without 'a': {}
4. Repeat this process for 'c' and 'd' as well:
  - Include 'c' in the subsets containing 'a' and 'b': {a, b, c}
  - Exclude 'c' in the subsets containing 'a' and 'b': {a, b}
  - Include 'c' in the subsets containing 'a' but not 'b': {a, c}
  - Exclude 'c' in the subsets containing 'a' but not 'b': {a}
  - Include 'c' in the subsets without 'a' or 'b': {c}
  - Exclude 'c' in the subsets without 'a' or 'b': {}
  - Include 'd' in the subsets containing 'a', 'b', and 'c': {a, b, c, d}
  - Exclude 'd' in the subsets containing 'a', 'b', and 'c': {a, b, c}
  - Include 'd' in the subsets containing 'a', 'b', but not 'c': {a, b, d}
  - Exclude 'd' in the subsets containing 'a', 'b', but not 'c': {a, b}
  - Include 'd' in the subsets containing 'a', but not 'b' or 'c': {a, d}
  - Exclude 'd' in the subsets containing 'a', but not 'b' or 'c': {a}
  - Include 'd' in the subsets without 'a', 'b', or 'c': {d}
  - Exclude 'd' in the subsets without 'a', 'b', or 'c': {}

b. To write the binary representation of each subset, we can assign a binary digit to each element in the set. Let's use '1' to indicate the presence of an element and '0' to indicate its absence.
Here are the binary representations of the subsets we found:
- {}: 0000
- {a}: 1000
- {b}: 0100
- {a, b}: 1100
- {c}: 0010
- {a, c}: 1010
- {b, c}: 0110
- {a, b, c}: 1110
- {d}: 0001
- {a, d}: 1001
- {b, d}: 0101
- {a, b, d}: 1101
- {c, d}: 0011
- {a, c, d}: 1011
- {b, c, d}: 0111
- {a, b, c, d}: 1111

c. The binary representation 1011 corresponds to the subset {a, c, d}.

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The standard form equation that equals the combination of the two given equations, \(07x-y=-5\) and \(7x+y=5\), is \(14x = 0\).

To find the combination of these two equations, we can add them together. When we add the left sides of the equations, we get \(07x + 7x = 14x\). Similarly, when we add the right sides, we get \(-y + y = 0\), and \(5 + (-5) = 0\).

Therefore, the combined equation in standard form is \(14x = 0\).

Regarding the second set of equations provided, \(0x-y=14\) and \(7x + 3 = 5\) and \(y-1=6\) and \(2- 4y = -14\), none of these equations can be combined to form a standard form equation. The first equation is already in standard form, but it does not relate to the other equations given. The remaining equations do not involve both \(x\) and \(y\), and therefore cannot be combined into a single standard form equation.

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The percentage of Americans predicted to wear glasses is given as follows:

63.8%.

Two parameters are used to calculate a percentage, as follows:

The proportion is given by the number of desired outcomes divided by the number of total outcomes, while the percentage is the proportion multiplied by 100%.

Hence the equation is given as follows:

P = a/b x 100%.

638 out of 1000 people sampled wear glasses, and the estimate of the percentage can be obtained as follows:

638/1000 x 100% = 63.8%.

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The SAS congruence theorem proves the similarity of triangles ABX and ABY.

The Side-Angle-Side (SAS) congruence theorem states that if two sides of two similar triangles form a proportional relationship, and the angle measure between these two triangles is the same, then the two triangles are congruent.

In this problem, we have that the angle B is equals for both triangles, and the two sides between the angle B, which are BA and BX = BY, in each triangle, form a proportional relationship.

Hence the SAS theorem holds true for the triangle in this problem.

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Answer:

As the cost of a gym membership goes up, the number of new gym memberships sold goes down.

The solutions to the given system of equations simultaneously are (x, y) = (-4, -7) and (2, 5).

Given the equation, we have:(x - 1)² + y² = 32 ---(1)x² + y = 9 ---(2)

Multiplying equation (2) by 4, we get :

4x² + 4y = 36 ---(3)

Multiplying equation (1) by 4, we get:4(x - 1)² + 4y² = 128 ------(4)

Expanding equation (4)

4[x² - 2x + 1] + 4y²

= 1284x² - 8x + 4 + 4y²

= 128

Dividing by 4 on both sides:  x² - 2x + y² = 31 ---(5)

Now we can write equations (3) and (5) as a system of equations:

4x² + 4y = 36 ---(6)

x² - 2x + y² = 31 ---(7)

To solve these equations simultaneously, we can solve one equation in terms of one variable and substitute it into the other equation to solve for the other variable.

Let's solve equation (6) for y:

y = (36 - 4x²)/4 = 9 - x² ------(8)

Substituting equation (8) into equation (7), we get:

x² - 2x + (9 - x²)

= 31-x² - 2 x + 9

= 31-x² - 2x - 22

= 0-x² - 2x + 22 = 0

Multiplying by -1 on both sides:x² + 2x - 22 = 0

Factoring the quadratic expression, we get:(x + 4)(x - 2) = 0

Equating each factor to zero gives:x + 4 = 0 or x - 2 = 0

x = -4 or x = 2

Substituting the value of x = -4 in equation (8) gives:

y = 9 - (-4)² =

-7

Substituting the value of x = 2 in equation (8) gives:

y = 9 - 2²

= 5

Therefore, the solutions to the given system of equations are (x, y) = (-4, -7) and (2, 5).

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Answer:

a) ∠BAD  = 67.4

b)  ∠BDC = 22.6

c) BC = 4.6

Step-by-step explanation:

a) tan θ = opposite/adjacent

In Δ ABD,

tan ∠BAD = DB/AD

tan ∠BAD =  12/5

∠BAD = tan⁻¹(12/5)

∠BAD  = 67.4

b) In  In Δ ABD,

∠BAD + ∠ABD + ∠ADB = 180°

⇒ ∠ABD = 180 - ∠BAD - ∠ADB

= 180 - 67.4 - 90

∠ABD = 22.6

In trapezium, since AB and DC are parallel,

∠BDC = ∠ABD (alternate interior angles)

⇒ ∠BDC = 22.6

c) In  In Δ ABD,

AB² = AD² + DB²

= 5² + 12²

= 25 + 144

= 169

= 13²

AB² = 13²

⇒ AB = 13

In Δ ABD and Δ BDC,

∠ADB = ∠BCD

∠ABD = ∠BDC

Since two angles are equal, the thrid angle must also be equal

∠BAD = ∠BDC

∴ Δ ABD and Δ BDC are similar

∴ the ratio of the corresponding sides should be equal

⇒ [tex]\frac{BD}{AB} = \frac{BC}{AD}= \frac{DC}{BD} \\[/tex]

[tex]\implies \frac{12}{13} = \frac{BC}{5}= \frac{DC}{12} \\\\\\\implies \frac{12}{13} = \frac{BC}{5}\\\\\implies BC = \frac{12*5}{13}\\\\\implies BC = \frac{60}{13}[/tex]

⇒ BC = 4.6

The surface area of a triangular prism is determined by the areas of its two triangular bases and its three rectangular faces. Let's denote the edge lengths of the first prism as 2x and the edge lengths of the second prism as 3x, where x is a common factor.

The surface area of the first prism (A1) is given by:

A1 = 2(base area) + 3(lateral area)

The base area of the first prism is proportional to the square of its edge length:

base area = (2x)^2 = 4x^2

The lateral area of the first prism is proportional to the product of its edge length and its height:

lateral area = 3(2x)(h) = 6xh

Therefore, the surface area of the first prism can be expressed as:

A1 = 4x^2 + 6xh

Similarly, for the second prism, the surface area (A2) can be expressed as:

A2 = 9x^2 + 9xh

To find the ratio of the surface areas, we can divide A2 by A1:

A2/A1 = (9x^2 + 9xh)/(4x^2 + 6xh)

Simplifying this expression is not possible without knowing the specific value or relationship between x and h. Therefore, the ratio of the surface areas of the two prisms cannot be determined solely based on the given information of the edge lengths in a 2:3 ratio.

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Answer: 5

Step-by-step explanation:

So, first we want to find what number times -3 is -15, and what number times -4 is -20 because its a dialation.

-3 times 5 is -15, and -4 times 5 is -20. Therefor the answer is 5.

The Horizontal Dilution of Precision (HDOP) for the given geometry is 1.25.

The HDOP is a measure of the accuracy of a navigation solution, particularly in terms of horizontal position. It is influenced by the geometric arrangement of satellites or reference points. In this case, we have two DME (Distance Measuring Equipment) stations with their respective bearings and ranges.

To calculate HDOP, we need to determine the position dilution of precision (PDOP) and then isolate the horizontal component. PDOP is the combination of dilutions of precision in the three-dimensional space.

(i) To calculate PDOP, we consider the two DME stations. The PDOP formula is given by PDOP = sqrt(HDOP^2 + VDOP^2), where HDOP is the horizontal dilution of precision and VDOP is the vertical dilution of precision. Since we are only concerned with HDOP, we can assume VDOP to be zero in this case. So PDOP = HDOP.

PDOP = sqrt((50/60)^2 + (60/60)^2) = sqrt(25/36 + 1) ≈ 1.25

(ii) If the bearing to the first DME changes to 060° (M), the geometry of the system is altered. This change will affect the PDOP and subsequently the HDOP. However, without additional information about the new range, we cannot determine the exact impact on HDOP.

(iii) If a third DME is acquired at a bearing of 180° (M), the geometry of the system becomes more favorable. The additional reference point allows for better triangulation and redundancy, which can improve the accuracy of the navigation solution. Consequently, the HDOP is likely to decrease, indicating a higher level of precision.

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There is approximately $41,916 in the account after 8 years if no withdrawals or additional deposits are made.

To calculate the amount of money in the account after 8 years with continuous compounding, we can use the formula [tex]A = P * e^{(rt)}[/tex], where A is the final amount, P is the principal amount (initial deposit), e is Euler's number (approximately 2.71828), r is the interest rate, and t is the time in years.

In this case, the principal amount is $30,000 and the interest rate is 4.5% (or 0.045 in decimal form).

We need to convert the interest rate to a decimal by dividing it by 100.

Therefore, r = 0.045.

Plugging these values into the formula, we get[tex]A = 30000 * e^{(0.045 * 8)}[/tex]

Calculating the exponential part, we have

[tex]e^{(0.045 * 8)} \approx 1.3972[/tex].

Multiplying this value by the principal amount, we get A ≈ 30000 * 1.3972.

Evaluating this expression, we find that the amount of money in the account after 8 years with continuous compounding is approximately $41,916.

Therefore, the answer to the question is that there is approximately $41,916 in the account after 8 years if no withdrawals or additional deposits are made.

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Answer:

36 m

Step-by-step explanation:

Perimeter = 2L + 2w = 99

2(L + w) = 99

L = length = 8x

w = width = 3x

2(8x + 3x) = 99

16x + 6x = 99

22x = 99

x = 99/22 = 4.5

L = 8x = 8(4.5) = 36

Answer: A

Step-by-step explanation: I would say A because the angle is greater than 90 degrees

Answer:

We have supplementary angles.

76 + 3x + 2 = 180

3x + 78 = 180

3x = 102

x = 34

The number of machines that must be made to minimize the unit cost is 240.

The given function is $C(x) = 0.6x^2 - 288x + 51,365$ and we are required to find the value of x that minimizes the unit cost. Since it is given that the function is a quadratic function, we know that the minimum value of the function occurs at the vertex of the parabola. We know that the x-coordinate of the vertex of the parabola $ax^2+bx+c$ is given by the formula: $$x=-\frac{b}{2a}$$Here, $a=0.6$ and $b=-288$. Plugging these values in the formula, we get:$$x=-\frac{-288}{2(0.6)} = 240$$ Therefore, the number of machines that must be made to minimize the unit cost is 240.Long answer:We are given a function $$C(x) = 0.6x^2 - 288x + 51,365$$ which gives the cost of manufacturing $x$ copy machines. The cost of manufacturing each machine depends on the number of machines being made. We are to find the number of machines that must be made to minimize the unit cost.

To find the number of machines that minimize the unit cost, we need to find the value of $x$ that minimizes the function $C(x)$.Since the given function is a quadratic function, the graph of this function is a parabola. Quadratic functions are symmetric about their vertex, so the minimum value of the function occurs at the vertex of the parabola. Therefore, to find the value of $x$ that minimizes the function $C(x)$, we need to find the $x$-coordinate of the vertex of the parabola.To find the $x$-coordinate of the vertex of the parabola, we can use the formula $$x=-\frac{b}{2a}$$where $a$ and $b$ are the coefficients of the quadratic function.

Here, $a=0.6$ and $b=-288$. Plugging these values into the formula, we get:$$x=-\frac{-288}{2(0.6)} = 240$$

Therefore, the number of machines that must be made to minimize the unit cost is 240.

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18: The new ratio of the sibling share of sweets is 19:28:25, which is not among the given options. Therefore, none of the options A, B, C, or D is correct.

19: we have m = -3/5, c = 4/5. None of the options is correct.

20: Elaine receives R31,000, means the correct option is D. R31,000.

18:  The original ratio of chocolate sweets for Trust, Hardlife, and Innocent is 3:6:5.

Total parts = 3 + 6 + 5 = 14

Trust's share = (3/14) * 42 = 9

Hardlife's share = (6/14) * 42 = 18

Innocent's share = (5/14) * 42 = 15

After the father buys 30 more chocolate sweets and gives 10 to each sibling:

Trust's new share = 9 + 10 = 19

Hardlife's new share = 18 + 10 = 28

Innocent's new share = 15 + 10 = 25

The new sibling share of sweets ratio is 19:28:25, which is not one of the possibilities provided. As a result, none of the options A, B, C, or D are correct.

19: The linear equation 5y - 3x - 4 = 0 can be written in the form y = mx + c.

Comparing the equation with y = mx + c, we have:

m = -3/5

c = 4/5

Therefore, the values of m and c are not among the given options A, B, C, or D. None of the options is correct.

20: Let Elaine's share be x.

Shericka's share = 2 * Elaine's share = 2x

Shelly-Ann's share = R57,000

Total share = Shelly-Ann's share + Shericka's share + Elaine's share

R150,000 = R57,000 + 2x + x

R150,000 = 3x + R57,000

3x = R150,000 - R57,000

3x = R93,000

x = R93,000 / 3

x = R31,000

Elaine receives R31,000.

Therefore, the correct answer is option D. R31,000.

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No, 1,1,1, , , is not an arithmetic sequence because there is no common difference between the terms.

The given sequence is 1,1,1, , ,. If it is arithmetic, then we need to identify the common difference. Let's try to find out the common difference between the terms of the sequence 1,1,1, , ,There is no clear common difference between the terms of the sequence given. There is no pattern to determine the next term or terms in the sequence.

Therefore, we can say that the sequence is not arithmetic. So, the answer to this question is: No, the sequence is not arithmetic because there is no common difference between the terms.

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the only correct option is that the equation is linear. The correct option is 2.

The given first-order ODE is `xdy/dx = 3xe^x - 2y + 5x^2`. Let's analyze each option:

- The equation is not exact because it cannot be written in the form `M(x,y)dx + N(x,y)dy = 0`.

- The equation is linear because it can be written in the form

`dy/dx + P(x)y = Q(x)`.

- `y=0` is not a solution to the given ODE.

- The equation is not separable because it cannot be written in the form `g(y)dy = f(x)dx`.

- The equation is not homogeneous because it cannot be written in the form `dy/dx = F(y/x)`.

So, the only correct option is that the equation is linear.

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To find the determinant of matrix B, we can use the formula for a 3x3 matrix: det(B) = (2 * (0 * 1 - 1 * 1)) - (2 * (1 * 1 - 0 * 1)) + (0 * (1 * 1 - 0 * 1))

Simplifying this expression, we get:

det(B) = (2 * (-1)) - (2 * (1)) + (0 * (1))

det(B) = -2 - 2 + 0

det(B) = -4

The determinant of matrix B is -4.

Since the determinant is non-zero, B is invertible.

To find the inverse of B, we can use the matrix equation B * X = I, where X is the inverse of B and I is the identity matrix.

B * X = I

Using the given values of B, we have:

|2 2 0| * |x y z| = |1 0 0|

|1 0 1| |a b c| |0 1 0|

|0 1 1| |p q r| |0 0 1|

Solving this system of equations, we can find the values of x, y, z, a, b, c, p, q, and r, which will give us the inverse matrix B^-1.

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To write an equation for an elliptic curve over a finite field Fp or Fq, we can use the Weierstrass equation in the form: [tex]y^2 = x^3 + ax + b[/tex]

where a and b are constants in the field Fp or Fq.

the elliptic curve [tex]y^2 = x^3 + 2x + 3 (mod 17)[/tex] has points (2, 9) and (5, 1) on the curve, which are not additive inverses. The sum of these points can be determined using the elliptic curve point addition algorithm.

Suppose we have an elliptic curve over Fp with the equation:[tex]y^2 = x^3 + ax + b[/tex]

For simplicity, let's assume p = 17, a = 2, and b = 3.

The equation becomes:[tex]y^2 = x^3 + 2x + 3 (mod 17)[/tex]

To find points on the curve, we can substitute different values of x and calculate the corresponding y values.

Let's choose x = 2: [tex]y^2 = 2^3 + 2(2) + 3 = 8 + 4 + 3 = 15 (mod 17)[/tex]

Taking the square root of [tex]15 (mod 17)[/tex], we find y = 9.[tex]y^2 = x^3 + 2x + 3 (mod 17)[/tex]

So, the point (2, 9) lies on the curve. Similarly, we can choose another value of x, let's say x = 5: [tex]y^2 = 5^3 + 2(5) + 3 = 125 + 10 + 3 = 138 (mod 17)[/tex]

Taking the square root of [tex]138 (mod 17)[/tex], we find y = 1. So, the point (5, 1) also lies on the curve. To find the sum of these points, we can use the elliptic curve point addition algorithm.

Note that in this case, the points (2, 9) and (5, 1) are not additive inverses of each other, as their y-coordinates are not negations of each other.

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Hiya, hope these help! :)

Formula for a triangle: A=1/2(base of triangle x height of triangle)

Triangle a: 120cm²
A= 1/2(b x h)
A= 1/2(20 x 12)
A= 1/2 (240)
A= 120

Triangle b: 72cm²
A= 1/2(b x h)
A= 1/2(12 x 12)
A= 1/2 (144)
A= 72

Triangle c: 154cm²
A= 1/2 (b x h)
A= 1/2 (28 x 11)
A= 1/2 (308)
A= 154

Triangle d: 49cm²
A= 1/2 (b x h)
A= 1/2 (14 x 7)
A= 1/2 (98)
A= 49

Triangle e: 105cm²
A= 1/2 (b x h)
A= 1/2 (14 x 15)
A= 1/2 (210)
A= 105

Triangle f: 160cm²
A= 1/2 (b x h)
A= 1/2 (20 x 16)
A= 1/2 (320)
A= 160

Triangle g is missing the base number! It's not shown fully in the screenshot, therefore it will just be whatever answer is leftover! :)

Triangle h: 288cm²
A= 1/2 (b x h)
A= 1/2 (36 x 16)
A= 1/2 (576)
A= 288

Let me know if you have any more questions!

Answer:

Y-intercept: (0,-9)

Step-by-step explanation:

to find the y-intercept, subsitute in 0 for x and solve for y.

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Answer:

Step-by-step explanation:

y=6(x-1/2) (x+3)

y=6(0-1/2) (0+3)

y=6(-1/2)(3)

y=-9

y-intercept is -9

The determinant of the given matrix is 15.

By observing the matrix [4 6 -1 2 3 2 1 -1 1], we get the value of the determinant to be 15.

To verify this result, we can compute the determinant as follows:`Δ = [4(3(-1) - (-1)(2)) - 6(2(-1) - 1(2)) + (-1)(2(2) - 3(1))]

`Expanding the equation, we get: `Δ = [4(-5) - 6(-6) + (-1)(-1)]`

Δ = [-20 + 36 - 1]

`Δ = 15`

Therefore, the determinant of the given matrix is 15.

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Answer:  they need 28 songs for their show, which corresponds to option D.

Step-by-step explanation:

The expression for the number of songs they need for their show is (11-4) + 3×(11-4) - 5, which corresponds to option B.

To find how many songs they need for their show, we can evaluate the expression:

(11-4) + 3×(11-4) - 5 = 7 + 3×7 - 5 = 7 + 21 - 5 = 28.