1)The current flowing when:
(A) 75 m C pass a point in I min will be 1.25 * [tex]10^{-3}[/tex] A
B) 0.5 GC pass a point in 2 hours will be 0.5 * [tex]10^{9}[/tex] C
C) 2.0 MC pass a point in 1000 hours will be 2 * [tex]10^{6}[/tex] C
The charge flow when the current flow is:
(A) 6.0 A for 5 min will be 1800 C
B) 250 mA for 4 hours will be 3600 C
C) 2.5 KA for 50 s will be 125 * [tex]10^{3}[/tex] C
3A) [tex]10^{9}[/tex] seconds will it take for pass 25 MC at a current of 25 mA
B) 4 seconds will it take for pass 48 C at a current of 12 A
C) 90 seconds will it take for pass 360 C at a current of 4.0 A
4) A) Potential difference across the resistor will be 0.4 V
B) Total charge flow in 3 minutes will be 18 C
1 )
current = charge / time
A) 75 m C = 75 * [tex]10^{-3}[/tex] C
current = 75 * [tex]10^{-3}[/tex] C / 60 = 1.25 * [tex]10^{-3}[/tex] A
B ) 0.5 GC = 0.5 * [tex]10^{9}[/tex] C
current = 0.5 * [tex]10^{9}[/tex] C / 216000 = 0.0023 * [tex]10^{5}[/tex] =2.3 * [tex]10^{2}[/tex] A
C) 2.0 MC = 2 * [tex]10^{6}[/tex] C
current = 2 * [tex]10^{6}[/tex] / 36 * [tex]10^{5}[/tex] = 0.0556 * 10 A
2) charge = current * time
A) Q 1 = 6 * 300 = 1800 C
B) Q2 = 250 * [tex]10^{-3}[/tex] * 14400 = 3600 C
C) Q3 = 2.5 * [tex]10^{3}[/tex] C * 50 = 125 * [tex]10^{3}[/tex] C
3 )
time = charge / current
A) T1 = 25 * [tex]10^{6}[/tex] / 25 * [tex]10^{-3}[/tex] = [tex]10^{9}[/tex] seconds
B) T2 = 48 / 12 = 4 seconds
C) T3 = 360 / 4 = 90 seconds
4)
a) V = IR ( using ohm's law )
= 0.1 * 4 = 0.4 V
b) charge = current * time
= 0.1 * 180 = 18 C
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an airplane weighing 5500 lb is flying straight and level at msl with a velocity of 220 mi/h. at this velocity the l/d ratio is a maximum. the wing area and aspect ratio are 200 ft2 and 8.5, respectively. the oswald efficiency factor is 0.93. calculate the total drag on the airplane.
The total drag on the airplane is 97.28
define velocity?
Velocity is the rate of change in position of an object in motion as measured by a certain time standard (e.g., 60 km/h northbound). Velocity is a key notion in kinematics, the branch of classical mechanics that studies body motion.
weight of plane=5500lb
velocity=220m/h
=200x88/60
=292
wing area= 200 ft^2
aspect ratio=8.5
oswald efficiency (E)=0.93
density of air = 1.225Kg/m^3
=0.002377
Drag= 0.5xpxvxAxcd
lift coefficient=0.245
drag coefficient= 0.0024
cd=0.0024+0.0024=0.0048
drag= 0.5x0.002377x(292x292)x200x0.0048
=0.0011885x(85264)x200x0.0048
=97.28 lb
therefore the total drag on the airplane was 97.28 lb
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What is the correct order of the planets in the solar system, starting closest to the sun?.
Answer:
Mercury
Venus
Earth
Mars
Jupiter
Saturn
Uranus
Neptune
and then drawf planets
The equalizing temperature changes in response to changes in external forces of the boundary conditions of climate. What is this about?.
Answer:
It's climate sensitivity.
Two forces are applied to a car in an effort to accelerate it, as shown below. The first force, F1 = 310 N, is applied at an angle = 32° to the forward dashed line. The second force, F2 = 464 N, is applied at an angle = 13° to the forward dashed line.
(a) What is the resultant of these two forces?
______N at _____ ° to the _____
(b) If the car has a mass of 2850 kg, what acceleration does it have? (Disregard friction.)
_____m/s2 at ______ ° to the _____
a ) The resultant of these two forces is 715.92 N at 4.4° to the right of the forward dashed line
b ) If the car has a mass of 2850 kg, its acceleration is 0.25 m / s²
Resolving F1 into its vertical and horizontal component,
F1y = F1 cos θ
F1y = 310 * cos 32°
F1y = 263.5 N
F1x = F1 sin θ
F1x = 310 * sin 32°
F1x = 164.3 N
Resolving F2 into its vertical and horizontal component,
F2y = F2 cos θ
F2y = 464 * cos 13°
F2y = 450.1 N
F2x = F2 sin θ
F2x = 464 * sin 13°
F2x = 106.72 N
∑ Fx = F1x - F2x
∑ Fx = 164.3 - 106.72
∑ Fx = 57.58 N
∑ Fy = F1y + F2y
∑ Fy = 263.5 + 450.1
∑ Fy = 713.6 N
R² = ( ∑ Fx )² + ( ∑ Fy )²
R² = ( 57.58 )² + ( 713.6 )²
R² = 3315.46 + 509224.96
R = 715.92 N
tan θ = ∑ Fy / ∑ Fx
tan θ = 713.6 / 57.58
tan θ = 12.39
θ = 85.6° ( With the horizontal )
With the forward dashed line,
θ = 90 - 85.6
θ = 4.4° ( To the right of the forward dashed line )
F = m a
F = Force
m = Mass
a = Acceleration
m = 2850 Kg
a = F / m
a = 715.92 / 2850
a = 0.25 m / s²
Therefore,
a ) The resultant of these two forces is 715.92 N at 4.4° to the right of the forward dashed line
b ) If the car has a mass of 2850 kg, its acceleration is 0.25 m / s²
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what is the total number of electrons transported from the positive electrode to the negative electrode by the charge escalator from the time the battery is first used until it is completely dead?
The number of electrons transported is 8.1 x 10²² electrons.
The variety of electrons in a neutral atom is identical to the number of protons. The mass wide variety of the atom is the same as the sum of the range of protons and neutrons inside the nucleus. The number of neutrons is equal to the difference between the mass number of the atom and the atomic wide variety. The reduction half-response includes a -electron gain.
The LCM is consequently 6. The net equation is a six-electron transfer. The wide variety of electrons in an atom is identical to the atomic quantity of an element for neutrally charged species. this means the number of electrons and the number of protons in an element are identical. consequently, the variety of electrons in oxygen is 8. Ionic bonds are shaped among or extra atoms by using the switch of one or extra electrons among atoms.
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If a car, with an initial velocity of 15 m/s, accelerates at a rate of 5 m/s^2 for 4 seconds, what will its final velocity be?
Answer:
35 m/s
Explanation:
vf = vo + at
vf = 15 + 5(4) = 35 m/s
world-class sprinters can accelerate out of the starting blocks with an acceleration that is nearly horizontal and has magnitude 15 m/s^2. how much horizontal force f must a sprinter of mass 60 kg exert on the starting blocks to produce this acceleration?
The force exerted by the sprinter who is having a mass of 60 kg and accelerating at 15 m/s² is 900 N
The acceleration of the sprinter is 15 m/s²
The mass of the sprinter is 60 kg
The force exerted by the printer can be found using the formula,
F = ma
where F is the force exerted by the sprinter
m is the mass of the sprinter
a is the acceleration of the sprinter
Let us substitute the known values in the above equation, we get
F = 60 x 15
= 900 N
Therefore, the force exerted is 900 N
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The xylem tube which transports sap to the top of a tree can be considered as uniform cylinders if the transport of sap is entirely due to capillarity determine the diameter of the tube which will move the sap up a tree which is 25m tall.take the surface tension of sap to be 5*10^-2 s.g is 1 g is 9.8 an
The wide wood pores that link to the tree's roots allow sap to be drawn up into the maple tree when it starts to freeze. The tree is really replenishing itself with fluids at this time from its roots.
As long as the temperature is below freezing and the sap is increasing, the process continues.
How does the xylem sap of tall trees go from the roots to the top?Water is drawn up from the roots to the top of the plant according to the cohesion-tension hypothesis of sap ascent. Water and minerals travel upward from the roots through the xylem due to a negative water potential gradient created by the evaporation of mesophyll cells in the leaves.
The water potential gets increasingly negative as you climb the tree, and these variations provide a pull or tension that causes the water to ascend the tree. The loss of water from the leaves through a process called transpiration is a crucial element in the draw of water up the tree.
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two polarizers are oriented to each other by an angle of 75 degrees. polarized light with a polarization angle 25 degrees from the axis of the polarizer is incident on the first polarizer. how much of the light incident on the first polarizer (what percentage) makes it through the second?
82% of incoming polarized light with a polarization angle 25 degrees from the axis of the first polarizer will make it through the second polarizer.
We can use Snell's law to find out how much of the light makes it through the second polarizer.
Snell's law gives us:
sin(θ1)×sin(θ2)=n1×n2
Solving for n1, we get:
n1=(sinθ1cosθ2)/(sinθ1sinθ2)
We know that θ1 and θ2 are each 75 degrees, so we can put this into our equation:
n1=(0.5)(0.5)/(0.25)(0.75)=0.8333
This means that 82% of incoming polarized light with a polarization angle 25 degrees from the axis of the first polarizer will make it through the second polarizer.
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as a meteor moves from a distance of 16 earth radii to a distance of 2 earth radii from the center of earth, the magnitude of the gravitational force between the meteor and earth becomes a) 1/8 as great b) 8 times as great c) 64 times as great d) 4 times as great
The magnitude of the gravitational force between the meteor and earth becomes 64 times as great when meteor moves from 16 to 2 radii.
What is gravitational force and how it becomes 64 times as great when meteor moves from 16 to 2 earth radii?Gravitational force is the force due to gravity that we experience all through living , the attraction of earth to all the universal substances.Here a meteor moves from a distance of 16 radii to distance 2 earth radii and the magnitude of gravitational force is asked .We will use newton's gravitational force formula : F = Gm1m2/r^2 , where m1 and m2 are the masses of objects and G is gravitational constant and F is gravitational force.Here the F1 would be calculated as : F₁ = F/16² = F/256. And F2 will be calculated as :F₂ = F/2² = F/f.Knowing the value of F1 and F2 , we will take a ratio F2/F1, which equals F2/F1 = 256/4 = 64 times.To know more about gravitational force visit:
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how far from the lens should you hold the print to see a final virtual image 30 cm from the lens (at the eye's near point)?
m= near point/ s.
s=4.28 cm ( the distance of the contract from the magnifying glasses)
Near point = 30cm
so m= 30/4.28= 7
Thus, far from the lens should you hold the print to see a final virtual image 30 cm from the lens (at the eye's near point) is 7
a force of 1 newton will cause a mass of 1 kg to have an acceleration of 1 m/s2. if a force of 6 newtons is applied to a mass of 1 kg, what will be its acceleration?
Answer:
6 m/sec square
Explanation:
consider a cube with a mass of 500 kg and sides of 50 cm. calculate the pressure on the floor from such a cube.
The pressure applied by the cube of mass 500 kg and side 50 cm on the floor is 200000 Pascal
The mass of the cube is 500 kg and the side of the cube is 50 cm.
Converting the side of the cube from cm to m.
The side of the cube is 0.5 m.
The pressure applied by any body is given by the force applied by the body divided by the area on which the force is applied.
Pressure = force/area
The force applied by the cube will be equal to the weight of the cube,
The weight of the cube is 5000 Newton.
The area of only one side of the cube is in contact with the floor so the area is,
Area = 0.025 m
Putting values,
P = 5000/0.025
P = 200000 Pascal.
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the product of a force and the perpendicular distance from the force's line of action to the axis of rotation is known as
The product of a force and the perpendicular distance from the force's line of action to the axis of rotation is known as Torque.
Torque or moment of the force is the term used to describe a force's ability to turn.
The moment arm is the length that separates the line of action perpendicular to the axis of rotation. Torque is a mathematical combination of force F and moment arm L. Torque is equal to F times L. The moment arm affects torque. The torque will create more of an increase the longer the moment arm.
The line of action of a force is the path it travels when exerting its power.
The moment arm of the force is the length that separates the force's path of action from its axis of rotation perpendicularly.
The newton meter is the torque SI unit (Nm). A force of 1 N operating perpendicular to the moment arm's length of 1 m produces a torque of 1 N m.
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other than 120 and 240 volts, what is another common voltage used inside a building? i. 208 ii. 277 iii. 480
Other than 120 and 240 volts, what is another common voltage used inside a building is 208,277and 480volts.
What is the standard input voltage?When the same signal is applied to the IN(+) and IN(-) terminals of an op-amp, it must operate satisfactorily within a range of input voltages known as the common-mode input voltage (CMVIN), which is described in the datasheet of the device. You may think of it as never applying common-mode signals to an op-amp.
The voltage shared by an electrical device's two input terminals is known as a common-mode signal. The common-mode signal on a transmission line in telecommunications is also referred to as longitudinal voltage. The signal is typically transmitted between two conductors using a differential voltage in electrical circuits.
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What is the density of a liquid if a volume of 0.025 L has a mass of 0.034 Kg? Express the result in g/cm3?
Answer: density = 1.36g/cm3
Explanation: 0.025L = 25cm3 and 0.034kg = 34 grams
Density= mass/volume
= 34/25
= 1.36g/cm3
Answer:
Explanation:
Given:
V = 0.025 l; or V = 25 cm³
m = 0.034 kg = 34 g
______________
ρ - ?
ρ = m / V
ρ = 34 / 25 = 1.36 g/cm³
What is the Inertia prasent in a stretched rubber
Answer:
inertia of motion ..........
A large block of stone is held at a height of 15meters having gained 4500 j of gpe. how much does it weigh?
The weight of the large block of stone is 300 Newton. The result is obtained by dividing the gravitational potential energy by the height.
What is gravitational potential energy (GPE)?Gravitational potential energy is the energy stored in an object due to its position in a gravitational field. GPE can be expressed as
PE = mgh
Where
PE = gravitational potential energym = mass of an objectg = acceleration of gravityh = height of an objectGiven
h = 15 mPE = 4500 JHow much does it weight?
The weight of an object is the mass times the acceleration of gravity.
W = mg
So, with the GPE equation, the weight is
PE = mgh
PE = W × h
4500 = W × 15
W = 4500 ÷ 15
W = 300 Newton
Hence, the weight of the large block of stone is 300 Newton.
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A hair dryer uses the energy from the plug in order to power a small fan that blows air. When a hair dryer is being used, which is one of the energy transformations that takes place?.
Energy transformation takes place when using a hair dryer, electrical energy into kinetic energy and thermal energy.
Energy can be converted according to the law of conservation of energy. Every object transforms the original form of energy into another form called a converter. Every electrical device works to convert electrical energy into other forms.
A microwave converts electrical energy into thermal energy.A lightbulb converts electric energy into light energy.A mixer converts electric energy into kinetic energy.When we use a hairdryer
The temperature of small wires inside it will be raised because the electrical energy transforms into thermal energy.The motion of a small fan happens because the electrical energy transforms into kinetic energy.The small fan gonna blows the air between hot wires and creates hot air that comes out from it.Learn more about Energy Convertion here: https://brainly.com/question/961052
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my solar system has two types of planets: terrestrials and jovians. the solar nebula hypothesis offers what explanation for the different compositions of these two types of planets?
According to the nebular hypothesis, small terrestrial planets are formed through the process of accretion, in which dense solid particles condensed and collided with one another as a result of their mutual gravitational pull.
As opposed to this, all heavier elements condensed near the sun and formed terrestrial planets, while lighter elements moved away from the sun and formed jovian planets due to the high temperature near the sun, which only allowed heavier particles to condense there.
The solar nebular hypothesis is the explanation put forth and accepted by most scientists as to how the earth came to be. It claims that a nebular, or huge clump of dust, is where the solar system originated. The heavier materials that could resist higher temperatures formed closer to the sun as the condensation of the nebular continued. Because these minerals weren't abundant, the planets they generated weren't very big.
The Jovian planets, on the other hand, formed above the frost line and could support icy compounds. These planets' larger sizes can be attributed to the abundance of ices that formed them. The lighter hydrogen and helium elements were stripped away by solar winds, which caused their accumulation far from the sun.
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1) a magnetic field is not produced by a) stationary electric charge b) moving electric charge c) electric current d) an electromagnet e) current-carrying solenoid g
The magnetic field will not be produced by a) stationary electric charge
Any stationary charge in the system will not produce any magnetic field because it will not affect both the magnetic and electric fields. Thus it will not be able to produce any effect on the magnet. whereas in all other options like moving electric charge, electric current, electromagnet, current carrying solenoid, there will be the movement of the charges, which will produce the magnetic field because it will affect both the magnetic and electric field in the system and It will able to produce an effect on the magnet
Thus, the magnetic field is not produced in stationary electric charges.
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You are skiing and you push off from the top of the hill, giving yourself an initial velocity of 1 m/s. You accelerate down the hill at a rate of 2 m/s/s. What will your speed be after 10 seconds? How far will you have traveled after 10 seconds?
Using Equations of motion, speed after 10 seconds will be 21 m/s and the distance travelled after 10 seconds will be 110 m.
What are Equations of motion?
Equations of motion are thought of as the relationships that assist us in relating the physical quantities, such as distance traveled, time spent traveling there, acceleration, and initial and final velocities.
First equation of motion
The velocity-time relation is the name given to the fundamental equation of motion, v = u + at.Second equation of motion
The position-time relation can be defined as s = ut + 1 / 2at2 in the second equation of motion.Third equation of motion
v2 = u2+ 2as, the position-velocity relation, is the third equation of motion.Given, initial velocity, u = 1 m/s
acceleration, a = 2 m/s/s
time = 10 s
Using First equation of motion, we find the speed after 10 seconds.
v = u + at
v = 1 + 2 x10
v = 1 + 20
v = 21 m/s
Using Second equation of motion, we find the distance travelled after 10 seconds,
s = ut + 1 / 2at2
s = 1 x 10 + ( 2 x 10 x 10)/2
s = 10 + 100
s = 110 m.
Hence, after 10 seconds speed will be 21 m/s and distance will be 110 m.
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a bowling ball of mass 4.5 kg moves in a straight line at 3.98 m/s. how fast must a ping-pong ball of mass 1.322 g move in a straight line so that the two balls have the same momentum? answer in units of m/s.
It should travel at a speed of [tex]13.55[/tex] × [tex]10^{-3}[/tex] [tex]\frac{m}{s}[/tex] so that the two balls have the same momentum.
M = mass of the bowling ball = [tex]4.5 kg[/tex]
V = speed of bowling ball = [tex]3.98 \frac{m}{s}[/tex]
P = magnitude of momentum of bowling ball = ?
magnitude of momentum of bowling ball is given as
[tex]P = MV[/tex]
inserting the values
P = [tex]4.5 * 3.98[/tex]
P = [tex]17.91[/tex] [tex]\frac{kgm}{s}[/tex]
m = mass of ping-pong ball = [tex]1.322[/tex] [tex]g[/tex]= [tex]1.322[/tex] x [tex]10^{-3}[/tex] [tex]Kg[/tex]
v = speed of the ping-pong ball = ?
p = magnitude of momentum of ping-pong ball
Given that :
Magnitude of momentum of ping-pong ball = magnitude of momentum of bowling ball
[tex]p = P[/tex]
[tex]m v = 17.91[/tex]
([tex]1.322[/tex] x [tex]10^{-3}[/tex]) [tex]v[/tex] = [tex]17.91[/tex]
v = [tex]13.55[/tex] x [tex]10^{-3}[/tex] [tex]\frac{m}{s}[/tex]
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a horizontal force is applied to a glider moving along a horizontal air track bringing it to a stop in t seconds. if the same force is applied to a second glider with half the mass and four times the initial velocity, how long does it take for the glider to come to a stop?
The second glider will stop after it travels the distance of 8 times the distance of the first glider.
Let subscript 1 and 2 represent parameters related to glider 1 and glider 2.
According to the Newton's law:
F = m . a
Where:
F = force
m = mass
a = acceleration
Since both gliders received the same forces,
F₁ = F₂
m₁ . a₁ = m₂ . a₂
m₁ . a₁ = 1/2m₁ . a₂
a₂ = 2a₁
Hence, the acceleration of the 2nd glider is twice of that of the 1st glider.
Velocity formula for decelerated move
v² = u² - 2.a.s
Where:
v = final velocity
u = initial velocity
s = distance.
Since the gliders stop, v = 0
Hence,
u₁² = 2.a₁.s₁
u₂² = 2.a₂ . s₂
Substitute u₂ = 4u₁, a₂ = 2a₁
(4u₁)² = 2.(2a₁) . s₂
16 u₁² = 4 a₁ . s₂
16. (2.a₁.s₁) = 4 a₁ . s₂
s₂ = 8 s₁
Hence, the distance of glider 2 is 8 times the distance of glider 1
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Joe is using a crowbar to remove a tree stump. He applies 2066 J of work to the crowbar. The output work of the crowbar is 1240 J. What is the efficiency of the crowbar?
Joe is using crowbar to remove tree stump. When output and input work is given then the efficiency can be calculated as 60%.
How is efficiency defined ?Efficiency can be defined as how good a device is at transferring input energy to useful output energy . The efficiency of a device is the proportion of the energy supplied that is transferred for useful work. The efficiency is calculated as a decimal or a percentage.
Given output work as 1240 J
input work as 2066 J
Then efficiency can be calculated by using the formula :
Efficiency= (output work/ input work) * 100%
=( 1240/2066) * 100%
Efficiency = 60%
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a stealth bomber flying horizontally at a speed of 150 m/s drops a bomb from a height of 2500.0 m. how far in front of the target must the bomb be released
The bomb must be released 3375 m before the target when dropped from the height of 2500.0 m
What are equations of motion?An equation of motion is an equation that describes the behavior of a physical system in terms of motion as a function of time. More specifically, the equations of motion describe the behavior of a physical system as a set of mathematical functions related to dynamic variables.
Following are the equations of motion:
v = u + at
s = ut + 1/2 at²
v² = u² + 2as
Before calculating the horizontal distance let's calculate the time taken by the bomb to reach the ground by using following equation:
s = ut + 1/2 gt²
u = initial velocity in the vertical direction (0)
s = vertical displacement from the ground (−2500.0 m)
g = acceleration due to gravity (-9.8 m/s²)
Now substitute the the value in the above reaction:
-2500 = 0 × t + 1/2 × -9.8 t²
-2500 = -4.9 t²
t = 22.5 s
Now the distance covered by the bomb in horizontal direction by the time it reaches the ground is:
D = v × t
Where, D = distance covered by bomb horizontally
v = velocity of bomber (150 m/s )
t = time taken to reach the ground (22.5 s)
D = 150 × 22.5
D = 3375 m
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a uniform meter stick is suspended from the ceiling by a string attached to the 60. cm mark. a 0.050 kg mass placed at 90. cm mark causes the meter stick to balance in the horizontal position. find the mass of the meter stick.
The mass of the meter stick is 0.15 kg.
The parameter
Meter Stick length = 100 cmA string attached to the 60 cmMass = m = 0.05 kgA mass placed at 90 cmAcceleration due to gravity = 10 m/s²Calculate the weight of the mass.
w = mg
w = [tex]0.05 \times 10[/tex]
w = 0,5 N
Look at the picture. The weight of the stick is in the middle of its length at 50 cm. The meter stick is balanced in the horizontal position. At point A
Distance between mass and string = 90-60 = 30 cmDistance between weight of the stick and string = 60-50 = 10 cmΣ τ = 0
(ws × 10) - (w × 30) = 0
ws × 10 = w × 30
ws × 10 = 0.5 × 30
ws × 10 = 15
[tex]w_s = \frac{15}{10}[/tex]
ws = 1.5 N
ms × 10 = 1.5
[tex]m_s = \frac{1.5}{10}[/tex]
ms = 0.15 kg
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what is one major difference between federal and unitary governments
Explanation:
While the unitarios fought for a centralized government, located in the city of Buenos Aires, the federales sought political decentralization so that the autonomy of the provinces within the nation would be respected.
what is vertical wind shear? change in the wind speed and/or direction with height change in the vertical wind with distance north or south change in wind speed with direction north or south change in wind direction with horizontal distance
The correct answer is option D.
Vertical wind shear changes in wind direction with horizontal distance.
Generally, atmospheric wind is referred to as vertical or horizontal wind shear. It is also called wind gradient.
Simply put, win shear is defined as the change in wind speed over a particular distance.
More specifically, vertical wind shear refers to the alter in wind speed along altitude while the horizontal change refers to the change in wind speed that occurs along lateral side or position of the atmosphere in a given altitude.
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how much tension must a rope withstand if it is used to accelerate a 1054 kg car horizontally along a frictionless surface at 1.23 m/s2?
The tension must a rope withstand is 1296.42N
Given- Mass m=1054 kg
acceleration= 1.23 m/s²
To find Tension generated .
Principle -Tension is the reaction of the action applied that means due to application of mass along with acceleration there is a urge towards earth and to substantiate it or to form a couple the reaction occurred is tension that equalises the role of force,
Mathematically , Force = ma ⇒Tension
F=T
T=ma
Calculations & Answer - T= 1054 x 1.23
= 1296.42N
Since T=F so unit of force and tension will be same.
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