Chemistry High School

1. Explain why you can’t accurately determine the molarity of sodium hydroxide using thenumber of grams dissolved in the total amount of solution? What method does a chemistuse to determine the molarity of sodium hydroxide?

Answers

Answer 1

The reason you can't accurately determine the molarity of sodium hydroxide just by knowing the number of grams dissolved in the total amount of solution is that it doesn't take into account the exact volume of the solution.

To accurately determine the molarity of sodium hydroxide, a chemist would use a technique called titration. In titration, a known concentration of an acid is slowly added to the sodium hydroxide solution until the reaction between the two is complete. By measuring the volume of acid required to neutralize the sodium hydroxide solution, the chemist can calculate the exact molarity of the sodium hydroxide. This method takes into account the exact volume of the solution and the exact amount of acid needed to neutralize it, allowing for a more accurate determination of the molarity of sodium hydroxide.

You cannot accurately determine the molarity of sodium hydroxide by simply using the number of grams dissolved in the total amount of solution because molarity is defined as the number of moles of solute per liter of solution. To calculate molarity, you need to know both the moles of sodium hydroxide and the volume of the solution in liters.
A chemist typically uses a method called titration to determine the molarity of sodium hydroxide. In this process, a known volume of a solution with a known molarity of an acid (usually a strong acid like hydrochloric acid) is gradually added to the sodium hydroxide solution until the reaction reaches the endpoint, which is when the acid and base have neutralized each other. By monitoring the volume of the acid solution required to reach the endpoint, the chemist can then calculate the molarity of the sodium hydroxide solution using the balanced chemical equation and the relationship between the moles of the reactants.

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