1 point
Count the number of atoms in the formula: 3Al2(SO4)3
Al atoms
There are
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There are
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Satoms
O atoms
The total number of atoms is type your answer...

1 PointCount The Number Of Atoms In The Formula: 3Al2(SO4)3Al AtomsThere Aretype Your Answer...There

Answers

Answer 1

Al atoms: 6, S atoms: 9, O atoms: 36, The total number of atoms is 51.

what is 3Al2(SO4)3 ?

3Al2(SO4)3 is a chemical formula that represents the compound aluminum sulfate. It is also sometimes written as Al2(SO4)3.

Aluminum sulfate is a white crystalline solid that is commonly used in water treatment, as a coagulating agent to remove impurities and suspended solids from water. It is also used in the paper industry, in the production of dyes and pigments, and as a food additive. Aluminum sulfate has a variety of other applications as well, such as in the production of aluminum and in the tanning of leather.

The formula 3Al2(SO4)3 indicates that the compound contains three molecules of aluminum sulfate, with a total of six aluminum atoms and nine sulfate ions. Each aluminum sulfate molecule consists of two aluminum atoms and three sulfate ions.

Al atoms: 6, S atoms: 9, O atoms: 36, The total number of atoms is 51.

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Related Questions

The specific heat of water, 4.180 J·(g·K)−1, is greater than that of many other substances, such as aluminum, copper, and iron, which have specific heats of 0.902 J·(g·K)−1, 0.395 J·(g·K)−1, and 0.449 J·(g·K)−1, respectively. Which of the following statements about water can be attributed to this observation?

Answers

substances, such as aluminum, copper is measured in J/mole C rather than J/gC. 18.0 g/mole times 4.18 J/gC results in 75.2 J/moleC.

Is iron's specific heat higher than copper's specific heat?

The key is to always keep in mind that the specific heat of copper is lower than that of iron. You need to keep in mind that the heat of metal is higher than the heat capacity of copper. As a result, we can state that Q is identical to Late Mr. Delta T.

Is water's specific heat 4.184?

The temperature of the water equals 4.184 J/g-K due to the fact that there will be 4.184 megawatts in a calorie. Another way to define the ease that an item receives or loses heat.

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what is the balanced equation for
αHC2H3O2(aq)+βBa(OH)2(aq) →γH2O(l)+δBa(C2H3O2)2(aq)

Answers

Answer:

α HC2H3O2 (aq) + β Ba(OH)2 (aq) → γ H2O (l) + δ Ba(C2H3O2)2 (aq)

Explanation:

To balance the equation, you need to make sure that the number of atoms of each element on both sides of the equation are equal. The balanced equation for the reaction between α moles of acetic acid (HC2H3O2) and β moles of barium hydroxide (Ba(OH)2) to produce γ moles of water (H2O) and δ moles of barium acetate (Ba(C2H3O2)2) is:

α HC2H3O2 (aq) + β Ba(OH)2 (aq) → γ H2O (l) + δ Ba(C2H3O2)2 (aq)

Which of the following conditions indicate an acidic solution at 25 °C? Select all that apply.
pOH = 9.66
pH = 4.25
[H+] > 1.0 x 10-7 M
[H+] > [OH-]
[OH-] > [H+]

Answers

[H+] > [OH-] of the following conditions indicate an acidic solution at 25 °C among the rest options.

Option C is correct.

What exactly is acidic solution?

A solution with a pH of less than 7 is said to be acidic. A solution's acidity or basicity is measured on the pH scale, which ranges from 0 to 14. Solutions with a pH of 7 or higher are basic or alkaline, while solutions with a pH lower than 7 are acidic.

The presence of more hydrogen ions (H+) than hydroxide ions (OH-) in an acidic solution is a sign of its acidity. The degree to which an acid contributes hydrogen ions to a solution determines its strength. Acids are substances that do this.

Lemon juice, vinegar, and stomach acid are all common examples of solutions that are acidic. Acids can corrode metals and other materials and have a sour taste.

At 25°C, the following conditions indicate an acidic solution:

The condition pOH = 9.66 indicates a basic solution, and [OH-] > [H+] also indicates a basic solution.

pH = 4.25 [H+] > 1.0 x 10⁻⁷ M [H+] > [OH-]

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The distance between the two hydrogen atoms in a molecule of water is 0.00000000172 m. Express this distance in scientific notation
A) 17.2 x10^9 m
B) 0.172 x 10^-10 m
C) 1.72 x 10^-10 m
D) 1.72 x10-9 m
E) 1.72 x 1010 m

Answers

The distance between the two hydrogen atoms in a molecule of water is 0.00000000172 m, 1.72x10⁻⁹ m is the distance in scientific notation.

Scientific notation is defined as a way of writing very large or very small numbers. A number is written in a very scientific notation when a number between 1 and 10 is multiplied by a power of 10. Let's consider for example, 650,000,000 can be written in scientific notation as 6.5 × 10⁸.

Distance is basically defined as the distance, or separation, between two objects. An example distance is 5 feet between two tables. Distance is a scalar quantity.

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Given the chemical equation: 6 Cs + N₂
-2 CsgN
If the above reaction produces 58.3g of cesium nitride how much of the other substances were involved?

Answers

According to law of conservation of mass, if mass of product is 58.3 g the mass of nitrogen is 28 g and that of cesium nitride is 30.3 g which sums up to 58.3 g.

What is law of conservation of mass?

According to law of conservation of mass, it is evident that mass is neither created nor destroyed rather it is restored at the end of a chemical reaction .

Law of conservation of mass and energy are related as mass and energy are directly proportional which is indicated by the equation E=mc².Concept of conservation of mass is widely used in field of chemistry, fluid dynamics.

Mass of cesium nitride= mass of cesium + mass of nitrogen, thus, mass of nitrogen = 14×2=28 g and that of cesium is 58.3-28=30.3 g.

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A supersaturated solution can be prepared by dissolving solute in solvent while adding____. A supersaturated more servent solution contains more _____than can ordinarily be dissolved in the solvent detergent at room temperarte. A solution may remain supersaturated until_____is initiated, often by adding solid to the solution or by allowing solvent to evaporate.

Answers

By dissolving the solute in the solvent while adding heat, a supersaturated solution can be created. At room temperature, a supersaturated solution contains more solute.

than can normally be dissolved in the solvent. This is accomplished by dissolving the solute in a hot solvent and then progressively chilling the solution to allow the excess solute to stay dissolved, resulting in a supersaturated solution. A solution can stay supersaturated until a seed crystal is begun, which is usually accomplished by adding solid to the solution or allowing the solvent to evaporate. The seed crystal acts as a surface for surplus solute to crystallize and exit solution. The surplus solute quickly crystallizes out of solution once a seed crystal is introduced, resulting in a saturated solution.

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think about the sugar and water as made up of tiny particles

Answers

Both sugar and water are made of molecules and atoms.

What is meant by atoms and molecules?

A tiny or very small particle of a chemical element is known as an atom, which may or may not present independently. Molecules are defined as a groups of atoms has the bond fuse together which represents the smallest part of a compound. Two or more identical or different atoms are chemically bonded with each other.

The smallest particle of a material that has all of the physical and chemical properties of the material. Molecules are made up of only one or more than one atom. Sugar has a solid state of matter whereas water has a liquid state of matter. Sugar which is a solid has more hard particles as compared to water whereas a liquid has less compact particles.

So we can conclude that both are made of molecules and atoms.

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The following are the conjugate bases of some strong and weak acids. Which of these would you expect to act as a base if placed in aqueous solution? (1) HCOO (ii) HCO3 (iii) HSO4 (iv) H2PO4 (v) Br" (vi) F a.(i),(ii),(iv), and (vi) onlyb. (i),(ii),(iii),(iv), and (vi) onlyc. (iii) onlyd. (i),(ii),(iii),(iv) onlye. all of them

Answers

Due to the strength of their conjugate acids, I would anticipate that I (ii), (iv), and (vi) would behave as bases if put in an aqueous solution. As both alternatives (a) and (d) contain the conjugate bases of weak acids, they are both accurate.

Strong acids' conjugate bases, such as (v) Br- and (vi) F-, cannot take any more protons since they are already fully deprotonated and cannot function as bases in aqueous solutions. Strong acids have conjugate bases that may receive protons and function as bases in aqueous solutions. These bases include I HCOO-, (ii) HCO3-, (iii) HSO4-, and (iv) H2PO4-. As both alternatives (a) and (d) contain the conjugate bases of weak acids, they are both accurate. Because (v) and (vi), which are conjugate bases of strong acids and cannot function as bases, are included in Option (b), it is wrong. Option (c) is untrue because it only accounts for the conjugate bases of strong acids and ignores those of weak acids.

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Help! Rate constant k=0.23 /s in a first order reaction

Answers

The concentration at t = 300 s is  1.1 * 10^-30 M

What is the rate constant?

The rate constant, also known as the reaction rate constant, is a constant of proportionality that relates the rate of a chemical reaction to the concentration of reactants. It is a measure of the speed at which a chemical reaction occurs and is dependent on temperature, pressure, and other physical and chemical factors.

The rate constant is represented by the symbol "k" and is usually expressed in units of reciprocal time, such as per second (s^-1).

We know that for the first order reaction;

ln[A] =ln [A]o - kt

[A] = final concentration at time t

[A]o = Initial concentration

k = rate constant

t = time taken

ln[A] = ln1 - 0.23 * 300

ln[A] = -ln69

[A] = e^-69

= 1.1 * 10^-30 M

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One method for reclaiming silver metal from silver chloride results in a 94.6% yield. Calculate the actual mass of silver that can be produced in this reaction if 100.0 g of silver chloride is converted to silver metal. 2AgCl(s) → 2Ag(s) + Cl2(g)

Answers

If  100.0 g of silver chloride is converted, the amount of silver metal that would be produced would be 94.6 g.

What is mass?

Mass is described as the quantitative measure of inertia which is a fundamental property of all matter.

The reaction formula ]provided is already balanced, therefore the molar ratio of silver chloride to silver metal is 1:1.

Therefore, if 100.0 g of silver chloride is converted, we can expect to produce 100.0 g of silver metal but the yield of the reaction is only 94.6%, which means  that only 94.6 g of silver metal would actually be produced.

We can calculated as follows:

100.0 g × 0.946 = 94.6 g

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How many moles of gas would it take to fill an average man's lungs, total capacity of which is about 4.5 L. Assume 1.00 atm pressure and 37 degrees C

Answers

Answer:

0.0144 moles

Explanation:

To calculate the number of moles of gas in a volume of 4.5 liters, we use the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

First, we need to convert the temperature to Kelvin:

37°C = 37 + 273.15 = 310.15 K

Next, we can plug in the known values into the ideal gas law and solve for n:

PV = nRT

(1.00 atm)(4.5 L) = (n)(0.0821 Latm/mol K)(310.15 K)

n = (1.00 atm)(4.5 L) / [(0.0821 Latm/mol K)(310.15 K)] = 0.0144 moles

So, it would take approximately 0.0144 moles of gas to fill an average man's lungs.


ALLLEN

Answer:

0.124 moles

Explanation:

PV = nRT, can be used, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature in Kelvin.

Converting the volume to liters and temperature to Kelvin:

V = 45 L

T = 37°C + 273.15 = 310.15 K

Plugging these values into the ideal gas law:

1.00 atm * 45 L = n * 0.0821 Latm/mol/K * 310.15 K

Solving for n:

n = (1.00 atm * 45 L) / (0.0821 Latm/mol/K * 310.15 K) = 0.124 mol

So, it would take about 0.124 moles of gas to fill an average man's lungs.

If 3.7 liters of CI2 are used for this reaction, how much HCI will be formed in liters?
Assume there are enough reactants to complete and STP
H2(g)+C12(g)-->2HCI (g)

Answers

The volume of HCl that will be formed from 3.7 liters of Cl2 would be 6.72 liters.

Moles of gas at STP

At STP, 22.4 liters of gas is equivalent to 1 mole of the gas.

3.7 liters of Cl2 = 3.7/22.4 = 0.17 mole

From the equation of the reaction, the mole ratio of Cl2 to HCl is 1:2. Thus, the equivalent mole of HCl that will be formed from 0.17 mole of Cl2 would be:

0.17 x 2 = 0.34 mole

0.34 mole of Cl2 = 22.4 x 0.3 = 6.72 liters

In other words, the volume of HCl that will be formed would be 6.72 liters.

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Some confusion is introduced by the fact that physicists might focus on an individual molecule whereas a chemist might focus on a mole of them (1 mole = 6.023 x 10^{23} molecules or atoms).

If a particular molecule had a bond dissociation energy of 1 eV, how much energy would be needed (in kJ) to break all the bonds in one mole of molecules (not yet considering any interactions with the environment)?

Answers

To break all the bonds in one mole of molecules with a bond dissociation energy of 1 eV, we would require around 5.80 x [tex]10^{26}[/tex] kJ of energy.

The bond dissociation energy of 1 eV is roughly 96.485 kJ/mol. To break all the bonds in one mole of molecules (6.023 x [tex]10^{23}[/tex] molecules), we would need to multiply the bond dissociation energy by Avogadro's number:

96.485 kJ/mol x 6.023 x [tex]10^{23}[/tex] molecules/mol = 5.80 x [tex]10^{26}[/tex] kJ/mol

Bond dissociation energy is the amount of energy necessary to break a chemical connection between two atoms. It is also known as bond energy or bond enthalpy. This energy is measured in kilojoules per mole (kJ/mol) and is released when the bond forms. The energies of bond dissociation can vary greatly depending on the type of bond being broken.

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A student runs an experiment to figure out if the size of a wire changes how well it conducts electricity. She uses 5 different widths of copper wire and attaches each to a multimeter to measure
the resistance in the wires. The data collected is shown below.
Wire 1-12 Ohms
Wire 2-17 Ohms
Wire 3-9 Ohms
Wire 4-14 Ohms
Wire 5-6 Ohms
What is the independent variable in this experiment?
A. The multimeter.
B. The resistance values.
C. The material of the wires, copper.
D. The widths of the wires.

Answers

A student runs an experiment to figure out if the size of a wire changes how well it conducts electricity. The independent variable in this experiment is the multimeter. Therefore, option A is correct.

What is resistance ?

The amount by which an object impedes or resists an electric current is referred to as resistance. The flow of electrons is referred to as electric current. Consider an example of a person struggling to move from one shop to another in a crowded market.

Because a thin wire has fewer electrons to carry the current, its resistance is greater than that of a thick wire. The relationship between resistance and the area of a wire's cross-section is inversely proportional.

Thus, The independent variable in this experiment is the multimeter,option A is correct.

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a brass rod, a copper rod, an iron rod and a lead rod went into water with wax on top, which one rusted first if lead stayed on the longest and copper for the least

Answers

A brass rod, a copper rod, an iron rod and a lead rod went into water with wax on top, an iron rod will rust first if lead stayed on the longest and copper for the least.

What is rust?

Rust is an iron oxide, which is a typically reddish-brown oxide created by the catalytic interaction of iron with oxygen in the absence of water or air moisture. Rust is often connected with the corrosion of refined iron and is composed of hydrous iron(III) oxides (Fe2O3nH2O) with iron(III) oxide-hydroxide (FeO(OH), Fe(OH)3).

Given enough time and the presence of oxygen and water, any iron mass may ultimately rust completely. A brass rod, a copper rod, an iron rod and a lead rod went into water with wax on top, an iron rod will rust first if lead stayed on the longest and copper for the least.

Therefore, an iron rod will rust first if lead stayed on the longest and copper for the least.

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Blast furnaces give off many unpleasant and unhealthy gases. If the total gas pressure is 0.99 atm, the partial pressure of carbon dioxide is 5.065 kPa, and the partial pressure of hydrogen sulfide is 015.2 mmHg, what is the partial pressure, in atmospheres, of the remaining air?

___________ atm (2 sig figs)

Answers

The partial pressure of the remaining air is 0.94 atm.

Solving for the  of the remaining air, we have:

First, we'll convert the partial pressure of hydrogen sulfide from mmHg to kPa:

015.2 mmHg * (101.325 kPa / 760 mmHg)

= 0.020 kPa

Next, we'll find the sum of the partial pressures of carbon dioxide and hydrogen sulfide:

5.065 kPa + 0.020 kPa

= 5.085 kPa

Now we'll convert this sum to atmospheres:

5.085 kPa * (1 atm / 101.325 kPa)

= 0.05 atm

Finally, we'll subtract this sum from the total gas pressure to find the partial pressure of the remaining air:

0.99 atm - 0.05 atm

= 0.94 atm

So the partial pressure of the remaining air is 0.94 atm (to 2 sig figs).

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2 NH3 + 3 CuO g 3 Cu + N2 + 3 H2O

In the above equation how many moles of water can be made when 57 moles of NH3 are consumed?

Answers

Answer:

86 moles of H2O.

Explanation:

In the reaction 2 moles of NH3 reacts with 3 moles of CuO to produce 3 moles of Cu, 1 mole of N2 and 3 moles of H2O.

So, when 57 moles of NH3 are consumed, the amount of H2O produced will be 3 * 57 moles / 2 moles = 86 moles of H2O.

Part A
Calculate the freezing point of a solution containing 11.1 g FeCl3 in 153 g water.

Part B
Calculate the boiling point of the solution above.

Part C
Calculate the freezing point of a solution containing 6.0% KCL by mass (in water)

Part D
Calculate the boiling point of the solution above.

Part E
Calculate the freezing point of a solution containing 0.155 m MgF2

Part F
Calculate the boiling point of the solution above.

Answers

Answer:

no answer

Explanation:

I wish I could help you, but go to your text book for reference

If Earth is 1.50 × 10^(8 km from the sun , what is the distance in Gm?

Answers

The distance of the Earth from the sun in gigameters is 1.50 × 10⁻⁴ Gm

How to convert km to Gm?

A unit conversion is the expression of the same property in a different unit of measurement. To convert kilometers to gigameters, you need to divide the number of kilometers by 10¹². Here's the formula: Gigameters = Kilometers / 10¹²

To convert the distance from kilometers to gigameters (Gm), divide the number of kilometers by 10¹².

So, 1.50 × 10⁸ km ÷ 10¹² = 1.50 × 10⁻⁴ Gm

Therefore, the distance from the Earth to the Sun is approximately 1.50 × 10⁻⁴ Gm.

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A 2.6−mL volume of seawater contains about 4.0 × 10−10 g of gold. The total volume of ocean water is about 1.5 × 1021 L. Calculate the total worth of all the gold in the world's oceans if the price of gold is $18.23 per gram.

Answers

The total volume of sea water is 1.5 × 10²¹ L. The amount of gold in the whole volume is 6 × 10¹¹ g of gold. Then, if one gram rate $18.23, the total worth of gold is $ 1.09×10¹³.

What is gold ?

Gold is a metal widely used in ornaments and other plating as well. It is excavating from the places where its minerals or ore can be found in abundant and it worth higher prize.

Given that, 2.6 ml or 0.0026 L of ocean water contains 4 × 10⁻¹⁰ g of gold. Then, 1.5 × 10²¹ g contains,

1.5 × 10²¹ ×4 × 10⁻¹⁰ /0.0026=  6× 10¹¹ g of gold.

Price of one gram of gold  = $18.23

then, price of the total amount 6× 10¹¹ g = 6× 10¹¹ g×$18.23 = $ 1.09×10¹³.

Therefore, the total price of gold in the world's ocean is $ 1.09×10¹³.

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How many liters would you need to make a 1 m solution if you have 6 mol of sodium hydroxide.

Answers

The liters would we need to make the 1 M solution if we have 6 mol of sodium hydroxide of 6 L.

The moles of the sodium hydroxide = 6 mol

The molarity of the sodium hydroxide = 1 M

The expression for the molarity is as follows :

The molarity = moles / volume in L

The volume of the sodium hydroxide = moles / molarity

The volume of the sodium hydroxide = 6 / 1

The volume of the sodium hydroxide = 6 L.

Thus the volume of the sodium hydroxide is 6L in the 1 M of the solution.

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A 0.5191-g sample of an unknown monoprotic acid is dissolved in water and titrated with standardized potassium hydroxide. The equivalence point in the titration is reached after the addition of 29.69 mL of 0.1453 M potassium hydroxide to the sample of the unknown acid. Calculate the molar mass of the acid.

? g/mol

Answers

The molar mass of the unknown acid is 120.4 g/mol.

How to calculate the number of moles in potassium hydroxide solution?

We can use the volume and concentration of the potassium hydroxide solution to determine the number of moles of KOH that were added to the acid sample:

moles of KOH = volume of KOH solution (L) x concentration of KOH solution (mol/L)

moles of KOH = 29.69 mL x (1 L / 1000 mL) x 0.1453 mol/L

moles of KOH = 0.004307 moles

Since the acid is monoprotic, the number of moles of KOH added is equal to the number of moles of acid present in the sample. We can use this information to calculate the molar mass of the acid:

moles of acid = moles of KOH = 0.004307 moles

molar mass of acid = mass of acid (g) / moles of acid

We know that the mass of the acid sample is 0.5191 g, so we can substitute this value into the equation:

molar mass of acid = 0.5191 g / 0.004307 mol

molar mass of acid = 120.4 g/mol

Therefore, the molar mass of the unknown acid is 120.4 g/mol.

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What is the mass percent of water in IrBr₃・4 H₂O?

Answers

The mass percent of water in IrBr₃・4 H₂O is  14.4%.

How to calculate mass percent?

To find the mass percent of water in  IrBr₃・4 H₂O, first determine the mass of water present in the compound and then divide it by the total mass of the compound and multiply by 100 to express the answer as a percentage.

Let's assume that the molecular weight of IrBr3•4 H2O is 500 g/mol. In that case, the mass of water present in the compound would be 4 x 18 g/mol (the molecular weight of water) = 72 g. The total mass of the compound is 500 g, so the mass percent of water in  IrBr₃・4 H₂O can be calculated as follows:

(72 g / 500 g) x 100 = 14.4%

So, the mass percent of water in IrBr₃・4 H₂O is 14.4%.

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Gas stoves and gas burners utilize methane gas (CH4) as a fuel. Its combustion reaction can be described by the following balanced chemical equation:

CH4 + 2 O2 → CO2 + 2 H2O

Cullen Airy is cooking a turkey for Thanksgiving dinner. He burns 2640 g of CH4 in the process. What mass of CO2 is produced during Cullen's turkey preparation?

Answers

in front of H2O for balance the hydrogen atoms: CH4 + O2 CO2 + 2H2O. A 2 can be placed  Oxygen gas on the left to balance the oxygen atoms: CH4 + 2O2 Carbon dioxide + 2H2O. Now the equation balances.

Which balanced reaction was appropriate for methane combustion?

The equation that balances is CH4(g)+2O2(g)CO2(g)+2H2O. (g) Methane (CH4) and oxygen (O2) combine during combustion to form carbon dioxide (CO2) and water (H2O): CO2 + 2 H2O CH4 + 2 O2 The laws of mass conservation is observed in this reaction because nothing was actually generated or destroyed, only rearranged.

What distinguishes a carbon molecule as primary, secondary, tertiary, or quaternary?

According to the hierarchy of carbon atom attachments, primary carbon is only tied to one carbon atom, secondary carbon is only attachment to two carbon, tertiary carbon is only connected to carboxylic acid group, and quaternary chlorine is only linked to carbon rings.

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Given AH -86 kJ/mol and AS° = -478 J/mol K, determine AG and the spontaneity of the reaction A,(g) + 3 X₂(g) → 2 AX,(g) at 591 K.


A) +196 kJ/mol, spontaneous
B) +196 kJ/mol, nonspontaneous
C) +282 kJ/mol, nonspontaneous
D) +282 kJ/mol, spontaneous
E) -196 kJ/mol, spontaneous

Answers

The answer is ‘B’ +196 kJ/mol, nonspontaneous.

How much energy, in joules per mole (J/mol), does a photon in the microwave region of the EM spectrum, contain? Assume the microwave has a frequency of 5.25 x 1010 s-1. Your answer should have 3 significant figures.

Answers

The energy, in joules per mole (J/mol), of a photon in the microwave region of the EM spectrum is 5.81 x 10-3 J/mol (3 significant figures).

What is energy?

Energy is the capacity for doing work. It can take many forms, including kinetic energy (the energy of moving objects), potential energy (stored energy in an object due to its position or composition), thermal energy (heat), light, and electrical energy.

The energy carried by a single photon is equal to the product of Planck's constant (h) and the frequency (f) of the photon.
Therefore, the energy carried by a single photon in the microwave region of the EM spectrum, with a frequency of 5.25 x 1010 s-1, is:
E = h x f
 = (6.63 x 10-34 J.s) x (5.25 x 1010 s-1)
 = 3.48 x 10-23 J
The energy per mole of photons is then equal to:
E/mol = (3.48 x 10-23 J) / (6.02 x 1023 photons/mol)
= 5.81 x 10-3 J/mol
Therefore, the energy, in joules per mole (J/mol), of a photon in the microwave region of the EM spectrum is 5.81 x 10-3 J/mol (3 significant figures).

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One atomic mass unit has a mass of 1.6605 × 10−24 g. What is the mass of one atom of sodium?

Answers

Answer:

one atom of sodium has a mass of approximately 37.9968 x 10^-24 grams.

Explanation:

The atomic mass of sodium is approximately 22.99 atomic mass units. To convert from atomic mass units to grams, we multiply by the conversion factor of 1.6605 x 10^-24 g/atomic mass unit:

mass (g) = 22.99 atomic mass units * (1.6605 x 10^-24 g/atomic mass unit) = 37.9968 x 10^-24 g

So one atom of sodium has a mass of approximately 37.9968 x 10^-24 grams.

There are three sets of sketches below, showing the same pure molecular compound (hydrogen chloride, molecular formula HCl) at three different temperatures. The sketches are drawn as if a sample of hydrogen chloride were under a microscope so powerful that individual atoms could be seen. Only one sketch in each set is correct. Use the slider to choose the correct sketch in each set. You may need the following information: melting point of HCl: -114.8 °C boiling point of HCl: -85.1 °C C A DODODODO 5 3. C -124. "C -105. C ? X

Answers

As per the temperature, the molecules of a substance act differently. The melting point is -114.2 °C and The boiling point of hydrogen chloride (HCl) is -85.05 °C. The correct sketch in each set is as follows:

Thus, if the temperature is kept above  -85.05 °C, the molecules will be placed widely apart and will be in the gaseous state, revealing their properties.

If the temperature is between -114.2 °C and -85.05 °C, the molecules will be organized in layers capable of slipping over one another since they will be in a liquid state.

At last, the molecules will be arranged in an orderly manner because they will be in a solid state if the temperature is below -114.2 °C.

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If the earth is 1.50X108 Km from the sun, what is the distance

in Gm?

Answers

Answer:

1.50 Gm

Explanation:

The distance from the Earth to the Sun can be converted from kilometers to gigameters (Gm) by dividing by 10^9:

1.50 x 10^8 km / 10^9 = 1.50 Gm

So, the distance from the Earth to the Sun is 1.50 Gm.

ALLEN

Write an equation that shows the formation of a copper (ii) ion from a neutral copper atom

Answers

An equation that shows the formation of a copper (ii) ion from a neutral copper atom is Cu ⇒ Cu⁺² + 2e⁻.

What is oxidation ?

Oxidation occurs when a reactant loses electrons during a reaction. Reduction occurs when a reactant accumulates electrons during a reaction. When metals react with acid, this is a common occurrence. Oxidation occurs when a reactant loses electrons during a reaction.

When an atom looses an electron to form positive ion, this process is called as an oxidation reaction.

Copper will lose 2 electron to form +2 ion. The equation for the formation of copper (II) ion from neutral copper atom follows:

Cu ⇒ Cu⁺² + 2e⁻

Thus, Cu ⇒ Cu⁺² + 2e⁻ is an equation that shows the formation of a copper (ii) ion.

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