1. What are the horizontal rows of the periodic table called?
2. Which sublevel is being filled in period 1?
3. Which sublevel is being filled in period 7?
4. How does the electron configuration of an element give information about the period it is in?
5. What block of elements has the d sublevels being filled?

Answers

Answer 1
1. Period
2. 1S sublevel
3. 7s 5f 6d 7p
Answer 2
I got you.

1. The horizontal rows of the periodic table are called periods.
2. In period 1, the 1s sublevel is being filled.
3. In period 7, the 7p sublevel is being filled.
4. The electron configuration of an element gives information about the period it is in by showing which energy level the valence electrons are in, and how many electrons it has in each energy level.
5. The block of elements that has the d sublevels being filled is the transition metals.

Related Questions

Describe the trend of the reactivity of the elements in group VII

Answers

The non-metal elements in Group 7 – known as the halogens – get less reactive as you go down the group

Answer & Explanation:

The reactivity of elements in Group VII, also known as Group 17, decreases with increasing atomic radius. This is because halogens have high electronegativities and a proclivity to gain electrons in noble gas configurations. Myths are traditional stories or beliefs that explain cultural or societal beliefs, customs, or natural phenomena. They can be passed down through generations and can be based on true or fictitious events. Mythology, on the other hand, is the collection of myths associated with a specific culture or religion. Mythology can be amplified through retelling, incorporation into religious practices; association with significant events or figures, and adaptation into other media forms such as literature, film, or art.

Explain why the following picture illustrates the relationships between voltage, current and resistance. (hint: start with Ohm's Law)

Answers

Answer:

Explanation:

We can see that this picture can be used to show Ohm's Law graphically so it illustrates Ohm's  Law.

According to Ohm's Law electric current is directly proportional to voltage and inversely proportional to resistance.

Mathematically, V ∝ I,

or                       V=IR,

where,       V  ⇒ voltage difference between two points,

                 I  ⇒ current flowing through the resistance,

                 R ⇒ proportionality constant or resistance.

According to the picture voltage ( SI unit Volt ) is supporting the current  ( SI unit Ampier ) to move out from the barrier while the resistor ( SI unit Ohm )is acting as a barrier to its way . As it is satisfying the Ohm's Law it illustrates the relationship between voltage, current, and resistance.

3.3 a liquid with a boiling point of 160 c and a flash point of 45 c would be assigned to

Answers

A liquid with a boiling point of 160°C and a flash point of 45°C would be assigned to the category of flammable liquids.

A liquid with a boiling point of 160°C and a flash point of 45°C would be assigned to the category of flammable liquids. Flammable liquids are substances that can ignite easily and sustain combustion when exposed to a source of ignition, such as an open flame or spark. The flash point of a liquid refers to the lowest temperature at which its vapors can ignite when exposed to an ignition source.

In this case, the liquid's flash point of 45°C indicates that it has a relatively low temperature requirement for vapor ignition. This means that even at relatively lower temperatures, the liquid's vapors can ignite if there is an ignition source present. On the other hand, the boiling point of 160°C suggests that the liquid has a relatively high boiling temperature, indicating that it requires significant heat to vaporize.

Given these properties, the liquid would be classified as a flammable substance, which means it presents a fire hazard and should be handled with caution. Safety precautions, such as appropriate storage, handling, and transportation procedures, should be followed to minimize the risk of accidents or fires.

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CuI2 (light brown solid) name copper compounds

Answers

CuI2 is not a known compound. Copper compounds typically have different oxidation states for copper, resulting in various compound names.

Copper(II) oxide (CuO): It is a black solid compound where copper is in the +2 oxidation state. It is commonly used as a pigment and in catalytic reactions.

Copper(II) sulfate (CuSO4): It is a blue crystalline compound in which copper is in the +2 oxidation state. It is used in various applications such as agriculture, electroplating, and as a laboratory reagent.

Copper(I) oxide (Cu2O): It is a red crystalline compound in which copper is in the +1 oxidation state. It is used as a pigment, in solar cells, and as a catalyst.

Copper(II) chloride (CuCl2): It is a greenish-brown solid compound in which copper is in the +2 oxidation state. It is utilized in various chemical processes, including etching and catalyst synthesis.

Copper(II) nitrate (Cu(NO3)2): It is a blue crystalline compound where copper is in the +2 oxidation state. It is commonly used in the production of catalysts, as a coloring agent, and in electroplating.

These are just a few examples of copper compounds with different oxidation states and properties. It's important to note that the compound CuI2 mentioned in the question, if it exists, would be an exception to the typical nomenclature for copper compounds.

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4- The standard potential of cell: Sn/Sn²+||Cr³+/Cr is −0.60V.what is the standard
reduction potential of the Cr³+/Crelectrode? Es = -0.14V
Sn²+
(b) +0.74V
(c) -0.88V
(d) -0.74V
(a) +0.88V

Answers

The standard reduction potential of the Cr³+/Cr electrode is -0.46V. None of the option is correct.

To determine the standard reduction potential of the Cr³+/Cr electrode, we can use the Nernst equation, which relates the standard reduction potential to the cell potential under non-standard conditions. The Nernst equation is given by:

E = E° - (0.0592/n) * log(Q)

where E is the cell potential, E° is the standard reduction potential, n is the number of electrons transferred in the half-reaction, and Q is the reaction quotient.

In this case, we have the standard potential of the cell as −0.60V. We know that the standard reduction potential of the Sn/Sn²+ electrode is -0.14V. Therefore, the reduction potential of the Cr³+/Cr electrode can be calculated as:

E = -0.60V - (-0.14V)

E = -0.60V + 0.14V

E = -0.46V

Therefore, the standard reduction potential of the Cr³+/Cr electrode is -0.46V.

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A 25 ml solution of 0.5 M NaOH is titrated until neutralized into a 50 ml sample of HCl?

Answers

The concentration of the acid is [tex]0.25 M[/tex].

Titration is a laboratory technique used to determine the concentration of a substance in a solution by reacting it with a standardized solution of known concentration.

The titration formula can be given by,

(Volume of the Base) [tex]\times[/tex] (Normality of the Base) = (Volume of the Acid) [tex]\times[/tex] (Normality of the Acid)

[tex]\Rightarrow V_1N_1=V_2N_2[/tex]

Given, the volume of the base ([tex]NaOH[/tex]), [tex]V_1 =25 ml[/tex].

The concentration of the base ([tex]NaOH[/tex]), [tex]M_1=0.5 M[/tex].

The equivalence of the base ([tex]NaOH[/tex]) is [tex]1[/tex].

Hence, the normality of the base ([tex]NaOH[/tex]), [tex]N_1=\frac{0.5}{1}N=0.5N[/tex].

Given, the volume of the acid ([tex]HCl[/tex]), [tex]V_2 =50 ml[/tex].

Let us assume that the normality of the acid ([tex]HCl[/tex]) [tex]N_2[/tex].

Substitute the values in the given formula of titration.

[tex](25\times0.5)=(50 \times N_2)\\\Rightarrow 12.5=50N_2\\\Rightarrow N_2=\frac{12.5}{50} N\\\Rightarrow N_2=0.25 N[/tex]

Hence, the normality of the acid ([tex]HCl[/tex]), [tex]N_2=0.25 N[/tex].

The equivalence of the acid ([tex]HCl[/tex]) is [tex]1[/tex].

Therefore, the concentration of the acid, [tex]M_1=\frac{0.25}{1}=0.25 M[/tex].

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Stamples of heterogeneous equilibria. FeO(s) + CO(g) = Fe(s) + CO₂(g) II. H₂(g) L₂(g) = 2HI(g) III. CO₂(g) + C(s) = 2CO(g) IV. N₂(g) 3H₂(g) + 2NH3(g) Identify I.​

Answers

An example of heterogeneous equilibrium is:

I. FeO(s) + CO(g) ⇌ Fe(s) + CO₂(g)

What is heterogeneous equilibrium?

Heterogeneous equilibrium refers to an equilibrium state in a chemical reaction where the reactants and products exist in different physical states or phases. It occurs when substances in different phases, such as solids, liquids, and gases, are involved in a chemical reaction.

Considering the given equations:

The equation I: FeO(s) + CO(g) ⇌ Fe(s) + CO₂(g) represents a heterogeneous equilibrium.

This is because the reactants and products involve different phases (solid and gas). FeO is a solid (s), CO is a gas (g), Fe is a solid (s), and CO₂ is a gas (g). The reaction involves the conversion of a solid and a gas to another solid and a gas, and the equilibrium is established between these different phases.

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how do one get this solution
-log10 (2* 10^-2)​

Answers

The result of the computation when you follow the steps is 1.699.

What is logarithm?

A logarithm is a mathematical function that represents the exponent or power to which a specific base must be raised to obtain a given number. In simpler terms, it answers the question: "To what power must we raise a base number to obtain a certain value?"

What you should do is that on your calculator, you could press the logarithm key and then put in the value that has been shown and then the result would be displayed on your calculator.

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Club soda is an aqueous solution of carbon dioxide. A sample of club soda is titrated with 0.04202M NaOH(aq) according to the reaction equation below:
CO2(aq)+2NaOH(aq)→Na2CO3(aq)
If it takes 32.14 mL of 0.04202M NaOH(aq) to react with a 25.00 mL sample of club soda, what is the concentration of CO2 in club soda (in g/L )?

Answers

The concentration of CO2 in club soda is approximately 1.1964 g/L.

To find the concentration of CO2 in club soda, we need to use the stoichiometry of the reaction and the volume and concentration of the NaOH solution used.

The balanced equation for the reaction is:

CO2(aq) + 2NaOH(aq) → Na2CO3(aq)

From the stoichiometry of the equation, we can see that 1 mole of CO2 reacts with 2 moles of NaOH. Therefore, the moles of CO2 can be calculated using the volume and concentration of NaOH solution used.

Given that 32.14 mL of 0.04202 M NaOH solution was used, we can calculate the moles of NaOH:

moles of NaOH = volume (L) × concentration (M)

moles of NaOH = 32.14 mL × 0.04202 mol/L

moles of NaOH = 0.001351 mol

According to the stoichiometry of the equation, 1 mole of CO2 reacts with 2 moles of NaOH. Therefore, the moles of CO2 can be calculated as:

moles of CO2 = (moles of NaOH) / 2

moles of CO2 = 0.001351 mol / 2

moles of CO2 = 0.0006755 mol

Now, we need to convert the moles of CO2 to grams. The molar mass of CO2 is approximately 44.01 g/mol.

mass of CO2 = moles of CO2 × molar mass of CO2

mass of CO2 = 0.0006755 mol × 44.01 g/mol

mass of CO2 = 0.02979 g

Finally, we need to express the concentration of CO2 in club soda in g/L. We are given that the sample of club soda used is 25.00 mL.

concentration of CO2 = (mass of CO2) / (volume of club soda in L)

concentration of CO2 = 0.02979 g / (25.00 mL × 0.001 L/mL)

concentration of CO2 = 1.1964 g/L

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The pOH of a solution is 6.0. Which statement is correct?
Use pOH = -log[OH-] and PH+pOH = 14.
The pH of the solution is 20.0.
O The concentration of OH ions is 1.0 x 108 M.
The concentration of OH ions is 1.0 x 106 M.
O The pH of the solution is 8.0.
A

Answers

At pOH value  of 6.0 the pH value of the following solution is 8.0 and the concentration of [[tex]H^{+}[/tex] ] ion is [tex]10^{-8}[/tex]

In this question we will apply the formula

      pH +pOH = 14 . . . . . . . . . . . . .(1)

where pH = concentration of [[tex]H^{+}[/tex] ] ion

pOH = concentration of [[tex]OH^{-}[/tex] ] ion

As per the question

pOH =6.0

Putting the value of pOH in equation (1) we get the value of pH

              pH + 6.0 =14

             pH = 14 -6.0

             pH  = 8.0

 The value of pH if the pOH value is 6.0 is 8.0

To find the concentration of [tex]H^{+}[/tex] ion we will use the following formula

This is calculated by the formula

                                 [[tex]H^{+}[/tex]} = [tex]10^{-pH}[/tex]

where we will write the values of pH

Hence the concentration of [[tex]H^{+}[/tex]} ion is [tex]10^{-8}[/tex]

Therefore at  pOH of 6.0 the pH value of the following solution is 8.0 and the concentration of [[tex]H^{+}[/tex] ] ion is [tex]10^{-8}[/tex]

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The complete question is -

What is the pH value and concentration of [[tex]H^{+}[/tex] ] ion of the following if the pOH value of the solution is 6.0 ?

Hello How do you do?
What is logic bomb and time bomb?​

Answers

Answer:

A logic bomb and a time bomb are both types of malicious software or code that are designed to cause harm to a computer system or network. Here's a brief explanation of each:

Logic Bomb:

A logic bomb is a piece of code or software that is intentionally inserted into a system to execute a malicious action when specific conditions are met. It remains dormant until triggered by a predefined event or circumstance, such as a specific date, time, or user action. Once triggered, the logic bomb may perform various harmful actions, such as deleting files, corrupting data, or disrupting system functionality. The purpose of a logic bomb is often to cause damage or to gain unauthorized access to a system.

Time Bomb:

A time bomb is similar to a logic bomb, but it is specifically designed to activate or execute its malicious payload at a certain date or time. It is usually programmed to remain undetected until the predetermined time arrives. The time bomb can be set to trigger after a specific time period or on a particular date, at which point it may carry out destructive actions. Time bombs can be used by attackers to target specific events or to coordinate an attack to occur simultaneously across multiple systems.

Both logic bombs and time bombs are considered forms of malicious code or malware and are used with malicious intent to disrupt, damage, or compromise computer systems or networks. They can be extremely harmful, and it is important to have strong security measures, such as antivirus software and regular system updates, to protect against such threats.

Explanation:

the answer choices could be more than one. Kindly help me provide the right choice(s).

Answers

The correct categorization of the solutions is:a. KCl - Neutral

b. ZnCl2 - Acidic

c. Ba(C2H3O2)2 - Basic

d. NH4I - Acidic

e. NaNO3 - Neutral

To determine whether a 0.5M solution of each salt is acidic, basic, or neutral, we need to analyze the nature of the ions present in the solution.

a. KCl: When KCl is dissolved in water, it dissociates into K+ and Cl- ions. Both K+ and Cl- are spectator ions and do not contribute to the acidity or basicity of the solution. Therefore, the solution is neutral.

b. ZnCl2: When ZnCl2 is dissolved in water, it dissociates into Zn2+ and 2Cl- ions. The presence of Zn2+ ions in the solution can hydrolyze water molecules, resulting in the formation of H+ ions. Therefore, the solution is acidic.

c. Ba(C2H3O2)2: When Ba(C2H3O2)2 is dissolved in water, it dissociates into Ba2+ and 2C2H3O2- ions. The acetate ions (C2H3O2-) can hydrolyze water, leading to the formation of OH- ions. Therefore, the solution is basic.

d. NH4I: When NH4I is dissolved in water, it dissociates into NH4+ and I- ions. The presence of NH4+ ions in the solution can undergo a weak hydrolysis, resulting in the formation of H+ ions. Therefore, the solution is acidic.

e. NaNO3: When NaNO3 is dissolved in water, it dissociates into Na+ and NO3- ions. Both Na+ and NO3- ions are spectator ions and do not contribute to the acidity or basicity of the solution. Therefore, the solution is neutral.

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30 example of redox reaction

Answers

Sure! Here are 30 examples of redox reactions:
1. Combustion of gasoline in a car engine
2. Rusting of iron
3. Photosynthesis in plants
4. Respiration in animals
5. Corrosion of metals
6. Bleaching of hair with hydrogen peroxide
7. Formation of ozone in the atmosphere
8. Electroplating of metals
9. Burning of wood
10. Reaction between bleach and ammonia
11. Reaction between copper and nitric acid
12. Reaction between iron and hydrochloric acid
13. Reaction between zinc and sulfuric acid
14. Reaction between magnesium and hydrochloric acid
15. Reaction between aluminum and hydrochloric acid
16. Reaction between sodium and water
17. Reaction between potassium and water
18. Reaction between lithium and water
19. Reaction between calcium and water
20. Reaction between barium and water
21. Reaction between copper and silver nitrate
22. Reaction between lead and silver nitrate
23. Reaction between zinc and copper sulfate
24. Reaction between iron and copper sulfate
25. Reaction between magnesium and copper sulfate
26. Reaction between aluminum and copper sulfate
27. Reaction between sodium and chlorine
28. Reaction between magnesium and chlorine
29. Reaction between aluminum and chlorine
30. Reaction between zinc and hydrochloric acid.
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