1. What theorem allows you to prove line f is parallel to line g? For what value of x is line f parallel to line g? I NEED FULL DETAIL
Answers
The value of x that will make the line f parallel to line g is 6.
The theorem that allows you to prove line f is parallel to line g is corresponding line theorem.
How to find angles when parallel lines is cut by transversal?When parallel lines are cut by a transversal line, angle relationships are formed such as corresponding angles, alternate angles, vertically opposite angles etc.
The theorem that prove the line f is parallel to line g will make the two angles equal.
15x + 9 = 21x - 27
f and g will be parallel and cut by the transversal line h when
15x + 9 = 21x - 27
15x - 21x = -27 - 9
- 6x = -36
x = -36 / -6
x = 6
Therefore, corresponding angle theorem prove line f is parallel to line g and the value of x is 6 to make line f and g parallel.
learn more on parallel lines here: brainly.com/question/28722306
#SPJ1
Related Questions
A student has 30 dimes and nickels. Their total value is $2.70. If d = number of dimes and n = number of nickels, this system of equations represents the situation:
d + n = 30
0.10d + 0.05n = 2.70
How many of each type of coin are there? Solve the system to answer the question.
A.
24 dimes and 6 nickels
B.
20 dimes and 10 nickels
C.
10 dimes and 20 nickels
D.
6 dimes and 24 nickels
Answers
Taking into account the definition of a system of linear equations, a student has 24 dimes and 6 nickels.
System of linear equationsA system of equations is a set of equations in which there are two or more variables, the goal of which is to find all ordered pairs (x, y) that satisfy the equation, where x and y are real numbers.
In other words, a system of linear equations is a set of two or more first degree equations that relate two or more unknowns, in which it is desired to find the value of each unknown so that all the equations of the system are satisfied.
This caseIn this case, a system of linear equations must be proposed taking into account that:
d = number of dimes.n = number of nickels.You know that:
A student has 30 dimes and nickels. The total value is $2.70.The system of equations to be solved is
d + n = 30
0.10d + 0.05n = 2.70
It is decided to solve it using the substitution method. This method consists of isolate one of the variables in one of the equations of the system and substituting its value in the other equation.
In this case, isolating the variable "d" from the first equation:
d= 30 -n
Replacing the expression in the second equation:
0.10×(30 - n) + 0.05n = 2.70
Solving:
0.10×30 - 0.10n + 0.05n = 2.70
3- 0.10n + 0.05n = 2.70
- 0.10n + 0.05n = 2.70 -3
-0.05n= -0.3
n= (-0.3)÷ (-0.05)
n= 6
Remembering that d=30 -n you get:
d= 30 - 6
d= 24
There are 24 dimes and 6 nickels.
Learn more about system of equations:
brainly.com/question/2172700
brainly.com/question/14323743
brainly.com/question/1365672
brainly.com/question/20533585
#SPJ1
Sam takes 4 hours to peel 32 potatoes, while Josh takes 5 hours to peel 30 potatoes. How mnay potatoes will they peel together in 12 hours
Answers
To determine the amount of potato peeled in 12 hours:
Sam takes 4 hours to peel 32 potatoes
Sam take 1 hour to peel 32 / 4 potato
[tex]\begin{gathered} 4\text{ hour }\Rightarrow\text{ 32 potato} \\ 1\text{ hour }\Rightarrow\text{ }\frac{32}{4} \\ 1\text{ hour }\Rightarrow\text{ 8 potato} \\ \end{gathered}[/tex]Josh takes 5 hours to peel 30 potatoes
Josh takes 1 hour to peel 30 / 5 potato
[tex]\begin{gathered} 5\text{ hour }\Rightarrow\text{ 30 potato} \\ 1\text{ hour }\Rightarrow\text{ }\frac{30}{5} \\ 1\text{ hour }\Rightarrow\text{ 6 potato} \end{gathered}[/tex]Sam peels 8 potato
They will peel hepotatoeel together in 12 hours
Answer:
168
Step-by-step explanation:
A 17 m guy wire attached to the top of a tower (the height of the tower is not yet known) is anchored on the ground, 8 m away from the base of the tower. A second guy wire needs to be attached to the centre of the tower and then anchored to the same ground-anchor as the first wire.Draw and label a diagram.How long does the second guy wire need to be?Determine the measure of the angle formed between the two wires.
Answers
Solution
Step 1:
Draw the diagram to illustrate the information.
Step 2:
Use the Pythagoras theorem to find the height of the pole.
[tex]\begin{gathered} 17^2\text{ = h}^2\text{ + 8}^2 \\ 289\text{ = h}^2\text{ + 64} \\ h^2\text{ = 289 - 64} \\ h^2\text{ = 225} \\ h\text{ = }\sqrt{225} \\ \text{h = 15m} \end{gathered}[/tex]Step 3
b) The height of the second guy wire = d
[tex]\begin{gathered} \text{Apply the pythagoras theorem} \\ d^2=\text{ \lparen}\frac{15}{2}\text{\rparen}^2+\text{ 8}^2 \\ d^2\text{ = 56.25 + 64} \\ d^2\text{ = 120.25} \\ \text{d = }\sqrt{120.25} \\ \text{d = 10.97m} \end{gathered}[/tex]c)
[tex]\begin{gathered} sin(\theta\text{ + }\alpha)\text{ = }\frac{Opposite}{Hypotenuse} \\ sin(\theta\text{ + }\alpha)\text{ = }\frac{15}{17} \\ \theta\text{ + }\alpha\text{ = sin}^{-1}(\frac{15}{17}) \\ \theta\text{ + }\alpha\text{ = 61.9}^o \end{gathered}[/tex][tex]\begin{gathered} sin\alpha\text{ = }\frac{7.5}{10.97} \\ \alpha=\text{ sin}^{-1}(\frac{7.5}{10.97}) \\ \alpha\text{ = 43.1} \end{gathered}[/tex]The angle between the two guys' wires = 61.9 - 43.1
Measure of the angle formed between the two wires = 18.8
The measures of 6 interior angles of a heptagon are: 111, 110, 121, 135, 139 and 92.Find the measure of the seventh interior angle. show work please:)
Answers
The sum of the interior angles of a heptagon 900º, if you know 6 of the 7 interior angles of the heptagon, you can determine the measure of the seventh angle as follows:
[tex]\begin{gathered} 900=111+110+121+135+139+92+x \\ 900=708+x \end{gathered}[/tex]Subtract 708 from both sides of the equal sign to reach the measure of the seventh angle:
[tex]\begin{gathered} 900-708=708-708+x \\ 192=x \end{gathered}[/tex]The seventh interior angle has a measure of 192º
Two rows of fluorescent lamps are installed in an office on the same branch circuit, with each row drawing 12.5 amperes. The source voltage is 277 volts, and the line resistance is 0.5 Ω. The wire used has a constant (k) of 12.6. The voltage drop will be within the recommendation of the NEC.
Answers
Explanation:
12.5/227 + 0.5
=
What is the volume of a cone with height of 80 km and diameter 21 km?
Answers
The volume of a cone with height of 80 km and diameter 21 km is 9240km³.
How to determine the volume of a cone?Volume of a cone=R^2H/3
Diameter=21
To get the radius is half of diameter,:
Radius(R)= Diameter/2= 21/2=10.5kM
Height=80km
Volume=22/7×10.5^2×80/3
The volume of the Cone= 9240km^3
Read more about Cone
https://brainly.com/question/29224025
#SPJ1
Stores on the verbal Graduate Record Exam (GRE) have a mean of 462 and a standard deviation of 119. Scores on the quantitative GRE have a mean of 584 and a standard deviation of 151. Assuming the scores are normally distributed, what quantitative scores are required for an applicant to score at or above the 90th percentile
Answers
We need Z-score here.
The formula is:
[tex]z=\frac{x-\mu}{\sigma}[/tex]A normal curve (with 90th percentile), looks like the one below:
We need a standard normal table to move further.
When we go to the table, we find that the value 0.90 is not there exactly, however, the values 0.8997 and 0.9015 are there and correspond to Z values of 1.28 and 1.29, respectively
(i.e., 89.97% of the area under the standard normal curve is below 1.28).
The exact Z value holding 90% of the values below it is 1.282.
--------------- Now, we work backwords and find the value of x:
Verbal GRE:
[tex]\begin{gathered} \mu=462 \\ \sigma=119 \\ z=\frac{x-\mu}{\sigma} \\ 1.282=\frac{x-462}{119} \\ x-462=1.282(119) \\ x=614.558 \end{gathered}[/tex]So, a 90th percentile on Verbal GRE is a score above 614.56
Quantitative GRE:
[tex]\begin{gathered} z=\frac{x-\mu}{\sigma} \\ 1.282=\frac{x-584}{151} \\ x=777.582 \end{gathered}[/tex]So, a 90th percentile on Quantitative GRE is a scoer above 777.58
Solve the quadratic equation by completing the square.x^2-14x+46=0First choose the appropriate form and fill in the blanks with the correct numbers. Then solve the equation. If there’s more than one solution, separate them with commas.
Answers
x² - 14x + 46 = 0
subtract 46 from both-side
x² - 14x = -46
Add the square of the half of the co-efficient of x
x² - 14x + (-7)² = -46 + 7²
(x-7)² = -46 + 49
(x-7)² =3
Take the square root of both-side
x-7 = ±√3
x-7= ±1.732
Add 7 to both-side of the equation.
x= 7 ± 1.732
Eithe x= 7 + 1.732 or x= 7 - 1.732
x=8.732 or x=5.268
Therefore x = 8.732 , 5.268
Show where the expression in number 8 would be on a unit circle
Answers
Solution
Step 1:
Write the expression
[tex]cos270\text{ }[/tex]Step 2
[tex]\begin{gathered} cos270\text{ = 0} \\ sin270\text{ = -1} \\ (0,\text{ -1\rparen} \end{gathered}[/tex]Question 8 Second part
[tex]\begin{gathered} sin(\frac{16\pi}{3})\text{ = sin960 = sin\lparen960 - 2}\times360)\text{ = sin240} \\ sin(\frac{16\pi}{3})\text{ = }\frac{-\sqrt{3}}{2} \\ cos(\frac{16\pi}{3})\text{ = }\frac{-1}{2} \end{gathered}[/tex][tex](\frac{-1}{2},\text{ }\frac{-\sqrt{3}}{2})[/tex]Solve using the quadratic formula
Answers
Suppose you choose four booksto read from a summer readinglist of 12 books. How manydifferent combinations of booksare possible?Note: nCrn!r!(n-r)!
Answers
Answer
495 different combinations of books are possible.
Explanation
The different combinations of books possible can be known using the given formula
[tex]_nC_r=\frac{n!}{r!(n-r)!}[/tex]Choosing four books to read from a list of 12 books means r = 4 and n = 12
Therefore
[tex]\begin{gathered} _nC_r=\frac{n!}{r!(n-r)!}=\frac{12!}{4!(12-4)!}=\frac{12!}{4!\times8!}=\frac{12\times11\times10\times9\times8!}{4\times3\times2\times8!}=495 \\ \\ \end{gathered}[/tex]Hence, there are 495 different combinations of books are possible
After filling the ketchup dispenser at the snack bar where she works, Kelley measures the level of ketchup during the day at different hourly intervals.
Complete parts a to c.
Question content area bottom
Part 1
a. Assuming the ketchup is used at a constant rate, write a linear equation that can be used to determine the level of ketchup in the dispenser after x hours. Let y represent the level of ketchup in inches.
y equals negative five eighths x plus 15
(Type an equation.)
Part 2
b. How can the equation from part a be used to find the level of ketchup when the dispenser is full?
A.
Identify the slope of the line represented by the equation.
B.
Find the difference between the slope and the y-intercept of the line represented by the equation.
C.
Substitute 0 for x in the equation and solve for y. Equivalently, find the y-intercept.
D.
Substitute 0 for y in the equation and solve for x. Equivalently, find the x-intercept.
Part 3
c. If Kelley fills the ketchup dispenser just before the snack bar opens and the snack bar is open for 18 hours, will the dispenser need to be refilled before closing time? Explain.
If the ketchup is used at a constant rate, then the equation from part a indicates the dispenser will become empty
enter your response here hours after the snack bar opens. This means that the dispenser
▼
will become empty before closing time,
will become empty exactly at closing time,
still has ketchup in it at closing time,
and so it
▼
will not
will
need to be refilled before closing time.
Answers
Answer:
Answers
Step-by-step explanation:
Got it from SAVVAS
A professional football prospect runs a 40 yard dash in 5 seconds.What is the player's average speed over this distance?a.) 8 yards per secondb.) 0.625 yards per secondc.) 0.125 yards per secondd.) 5 yards per second
Answers
Which set of expressions are not equivalent?(4 1\2 a + 2) + 3 and 5 + 4 a18 a + 14 and 6 a + 12 + 2 + 1 2a0.5 a + 3.5 + 4 a and 3.5 + 4.5 a3 a + 7 +2 a and 7 a + 5
Answers
Solution:
Solution:
To find which of given expressions are equivalent
For the first expressions
[tex](4\frac{1}{2}a+2)+3\text{ and 5}+4\frac{1}{2}a[/tex]Solving the expression
[tex]\begin{gathered} 4\frac{1}{2}a+2+3=5+4\frac{1}{2}a \\ 5+4\frac{1}{2}a=5+4\frac{1}{2}a \end{gathered}[/tex]The expressions are equivalent
For the second expression
[tex]18a+14\text{ and 6a}+12+2+12a[/tex]Solving the expression
[tex]\begin{gathered} 18a+14=6a+12a+12+2 \\ 18a+14=18a+14 \end{gathered}[/tex]The expressions are equivalent
For the third expression
[tex]0.5a+3.5+4a\text{ and 3.5}+4.5a[/tex]Solving the expression
[tex]\begin{gathered} 3.5+0.5a+4a=3.5+4.5a \\ 3.5+4.5a=3.5+4.5a \end{gathered}[/tex]The expressions are equivalent
For the fourth expression
[tex]3a+7+2a\text{ and 7a}+5[/tex]Solving the expression
[tex]\begin{gathered} 3a+2a+7=7a+5 \\ 5a+7\ne7a+5 \end{gathered}[/tex]The expressions are not equivalent.
Hence, the set of expressions that are not equivalent is
[tex]3a+7+2a\text{ and 7a}+5[/tex]the cost price of 24 articles is the selling price of 15 articles find the gain percentage
Answers
Let cost price of one article be x.
So cost price of 15 articles will be 15*x=15x.
Cost price of 24 articles=selling price of 15 articles.
So selling price of 15 articles= 24*x=24x.
Cost price of 15 articles=15x.
Gain= 24x-15x= 9x.
So gain%= gain/CP ×100.
= 9x/15x *100 .
= 3/5 ×100 .
= 3×20=60%
Answer:
Step-By step explanation:
The prism below is made of cubes which measure 3 of a centimeter on one side. What is the volume? NORSKEREN OA. LICO cubic cm OB. 8 cubic cm oc. i cubic cm 8 OD cubic cm 27
Answers
Recall that for a cube of this form
where the side is of length a, then the volume is calculated by the expression
[tex]a^3[/tex]So, to define the volume of the given cube, we should calculate the side's length of the bigger cube, based on the small cube
If we take a look at the front side of the cube we would look something like this
So, we want to determine the length's side of this square. We can see that in this case the length side corresponds to adding twice the length of one of the small cube. So the side's length of the new cube is
[tex]\frac{1}{3}+\frac{1}{3}=\frac{2}{3}[/tex]So, the volume of the bigger cube is
[tex](\frac{2}{3})^3^{}=\frac{2^3}{3^3}=\frac{8}{27}[/tex]So the volume of the bigger cube is 8/27 cubic centimeters
Helena is watching a movie on television she notices that there are 9 1/4 min of commercial for every 1/2 hour of the movie
Answers
If Helena watches a movie that shows a commercial for 9 1/4 mins of every 30 minutes (half hour), then the unit rate of commercials per hour is derived as;
[tex]\begin{gathered} \text{Com /30 mins=9}\frac{1}{4} \\ \text{Com /60 mins=9}\frac{1}{4}\times2 \\ \text{Com /hour=}\frac{37}{4}\times2 \\ \text{Com /hour=}\frac{37}{2} \\ Com\text{ /hour=18}\frac{1}{2} \end{gathered}[/tex]The unit rate of commercials per hour is 18 1/2 minutes (eighteen and half minutes)
how to write the standard equation for the hyperbola that is on the graph
Answers
The standard form of the hyperbola:
[tex]\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}\text{ = }1[/tex]The center of the hyperbola is at (h, k) = The point where the lines intersect
(h, k) = (0, 0)
For hyperbola:
c² = a² + b²
b is gotten by tracing the value of a to the intersecting line. Trace 3 down to the x axis. you get 5.
[tex]\begin{gathered} a\text{ = distance from center to vertex} \\ \text{the hyperbola coordinate = (0, a) = }(0,\text{ 3)} \\ \text{the other one = (0, -a) = (0, -3)} \\ \text{Hence, a = 3} \end{gathered}[/tex][tex]\begin{gathered} c\text{ = distance from the center to the focus point} \\ b\text{ = 5 and -b = 5} \\ c^2=3^2+5^2 \end{gathered}[/tex][tex]\begin{gathered} c^2\text{ = 9+25 = 34} \\ c\text{ = }\sqrt[]{34} \\ c\text{ = 5.83} \end{gathered}[/tex]The equation becomes:
[tex]\begin{gathered} \frac{(y-k)^2}{5^2}-\frac{(x-h)^2}{3^2}=\text{ }\frac{(y-0)^2}{5^2}-\frac{(x-0)^2}{3^2} \\ =\text{ }\frac{y^2}{25}-\frac{x^2}{9} \end{gathered}[/tex]if you can't read it, it says : Add -7d-3 and 10d-6. Show all steps
Answers
-7 d - 3 + 10d - 6
First step
Group in parenthesis and
Add both letter terms
(-7d + 10d)= -3d
Second step
Group and add numbers only
(-3 - 6) = -9
Now add both results
=-3d - 9
Answer is -3d - 9
The math class is selling raffle tickets to raise money for the fall ball the raffle tickets cost them $0.08 each at the office supply store and they spent $55 making T-shirts for the club members to wear. they are selling the raffle tickets for two dollars each if X represents the number of raffle tickets they sell ,the following functions can be used to present the situation where c(x) is the clubs cost and r(x) is the amount of money they make selling the tickets
Answers
We have the next information
x is the number of raffle tickets
the Profit function is R(x) function minus C(x)
C(x)=0.08x+55
R(x)=2x
P(x)=R(x)-C(x)=2x-(0.08x+55)=2x-0.08x-55
We sum similar terms
P(x)=1.92x-55
What is type of angle is it vertical complementary supplementary or none of the above I will reward you greatly if you answer
Answers
In the given figure,
∠a and ∠b are complementary angles.
This is because ∠CXB + ∠a + ∠b = 180° .........(as they form linear pairs)
∠CXB = 90° ..........(given)
Hence,
∠a + ∠b = 90°
What are Complementary Angles?Two angles whose total is 90 degrees are referred to as complementary angles in geometry. To put it another way, complimentary angles are two angles whose sums equal 90 degrees. 60° and 30°, for illustration. By adding up the two angles' measurements, one can determine the complement and supplement of the two angles. Complementary angles are those where the sum of the two angles equals the measurement of a right angle. They are referred to as adjacent complementary angles if they share a vertex and an arm. It is referred to as non-adjacent complementary angles when two complementary angles are NOT contiguous.To learn more about Complementary angles, refer to:
https://brainly.com/question/5708372
#SPJ13
A jellybean company produces 1,680 jellybeans per second. One box of jellybeans contains 50 jellybeans. What is this company’s production rate, in boxes of jellybeans per minute?
Answers
Answer:
2016
Step-by-step explanation:
1680:50=33.6
33.6x60=2016
Find two points on the line.4y + 2x = 7
Answers
Given the equation of a line:
4y +2x = 7
It's required to find two points on the line.
Solving for y:
[tex]y=\frac{7-2x}{4}[/tex]We give x any value and calculate the corresponding value of y.
For example, for x = 1:
[tex]y=\frac{7-2(1)}{4}=\frac{5}{4}[/tex]The point is (1, 5/4)
Now for x = -4:
[tex]y=\frac{7-2(-4)}{4}=\frac{15}{4}[/tex]The point is (-4, 15/4)
Farmer Anders' pumpkin patch is shown below.
19 yards ,
11 yards ,
48 yards and
22 yards.
He purchases fertilizer that costs $2.68 per square foot of coverage, but he has a coupon for half off.
How much will he spent to apply fertilizer to the entire patch.
Please help me answer!
Answers
If the cost of fertilizer is $2.68 per square foot of coverage then the farmer need to spend an amount of $5085.3 to apply fertilizer to the entire patch.
Given that the farmer Anders' pumpkin patches are such that they are in rectangle and the lengths are 19 yards and 48 yards and the breadths are 11 yards and 22 yards.
We are required to find the amount of money that the farmer need to spend to apply the fertilizer to the entire patch.
Area which is covering the entire patch=11*19+22*48
=209+1056
=1265 square yards
We know that 1 yard=3 foot
Area in foot=1265*3
=3795 square foot
Amount for fertilizer=3795*3
=$10170.6
Since 1/2 is off so it will be $5085.3 ($10170.6/2).
Hence if the cost of fertilizer is $2.68 per square foot of coverage then the farmer need to spend $5085.3 to apply fertilizer to the entire patch.
Learn more about area at https://brainly.com/question/25292087
#SPJ1
Which relation is a function? 4 15 O -6- 7 C fy 0 -H O O O -2 -4
Answers
The most appropriate choice for functions will be given by -
Third option is correct
Third relation is a function.
What is a function?
A function from A to B is a rule that assigns to each element of A a unique element of B. A is called the domain of the function and B is called the codomain of the function.
There are different operations on functions like addition, subtraction, multiplication, division and composition of functions.
Here,
For a function a point in the domain has a unique image.
Here values of x axis represents domain and values of y axis represents the range
For the first option,
x = -1 has two images, y = -1 and y = 3
so x = -1 do not have a unique image
So the first relation is not a function
For the second option,
x = 0 has two images, y = -1 and y = 2
so x = 0 do not have a unique image
So the second relation is not a function
For the third option,
Every point of the domain has a unique image
So the third relation is a function
For the fourth option,
x = -2 has two images, y = 1 and y = -2
so x = -2 do not have a unique image
So the fourth relation is not a function
so, Third option is correct
To learn more about function, refer to the link:
https://brainly.com/question/22340031
#SPJ13
I don’t know how to do 4 - 6mod6
Answers
Modulus (mod) symbol is a symbol that is used to find the remainder of the quotient of two integers
6mod6 means we need to find the result of the remainder if 6 is divided by 6.
Take the ratio of the integers
6/6 = 1.0
Multiply the result by the denominator
1.0 * 6 = 6
Take the difference of the result and the denominator
Remainder = 6 - 6
Remainder = 0
This shows that 6mod6 = 0
Substitute into the original expression
[tex]4-6mod6=4-0=4[/tex](x*y)a=xa*ya illustrates which property of exponents
Answers
Consider the given equation,
[tex](x\cdot y)^a=x^a\cdot y^a[/tex]This equation represents the Product Rule of the exponents.
The properties of exponents are the general rules and laws, followed by the exponents. These are used very frequently, so it is better to memorize these standard properties.
the circumference of the circle is 76 cm. what is the area? using 3.14 for pi round to the nearest square cm
Answers
The circumference of a circle is gotten using the formula below;
[tex]\begin{gathered} C=2\pi r \\ \text{Where r is the radius of the circle} \end{gathered}[/tex]Step 1: Let's find the value of the radius;
[tex]\begin{gathered} C=2\pi r \\ r=\frac{C}{2\pi} \\ r=\frac{76}{2\times3.14} \\ r=\frac{76}{6.28} \\ r=12.10\operatorname{cm} \end{gathered}[/tex]Step 2: The area of the circle is given as;
[tex]\begin{gathered} A=\pi r^2 \\ \text{Where r is the radius of the circle} \\ A=3.14\times(12.10)^2 \\ A=459.73 \\ A=460\operatorname{cm}^2 \end{gathered}[/tex]Hence, the area of the circle is 460 square centimeters.
Mimstoon started with at most 2 boondins (y). Every day (x), he
bought at most 1/2 more of them.
Write an inequality to model this relationship.
Answers
Step-by-step explanation:
y <= x/2 + 2
the maximum is to have 2 boondins and add 1/2 boondin every day.
but every time Mimstoon did not use the max. possible, the resulting total sum of boodins stays smaller that the maximum, and is therefore a valid data point.
(6, 7) is not in the inequality relationship.
because the max. boondins after 6 days is 2 (from the beginning) and 1/2 every day = 2 + 1/2 × 6 = 2 + 3 = 5.
but the data point shows 7 as y value (which is larger than the allowed max. of 5).
therefore the inequality is false for this data point, and therefore the data point is not in the inequality relationship.
Susan works as a Hostess where she makes $8.75 per hour she also babysitting earns $10 per hour last week she made $165 if she works 6 hours more as a Hostess than she did babysitting how many hours did she babysit last week?
Answers
6 hours as babysitter last week
1) Gathering the data
Hostess
8.75h
Babysitting
10h
2) Based on that, we can write out the following equation, considering that Susan worked 6 hours more:
8.75(h+6) +10h= 165 Distribute the factor 8.75
8.75h +52.5 +10h = 165 Combine like terms
18.75h = 165 -52.5 Subtract from both sides 52.5
18.75h = 112.5 Divide both sides by 18.75
h =6
3) Hence, we can conclude that Susan worked as a hostess for 12 hours and as a baby sitter 6 hours last week
