Answer:
a
Explanation:
The correct answer is a. quark. Quarks are elementary particles that are the building blocks of protons and neutrons, which are composite particles made up of quarks and other particles. Protons, neutrons, and atoms are not elementary particles, as they are made up of smaller particles. Protons and neutrons are composed of quarks and other particles, while atoms are composed of protons, neutrons, and electrons.
A beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy. What is the beaver’s mass?
A beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy, then the mass is approximately 1.74 kg, and this can be calculated by using the kinetic energy (KE) of an object that is KE = (1/2) ×m × [tex]v^2[/tex].
KE = (1/2) ×m × [tex]v^2[/tex].
where m= mass of the object, v=its velocity.
The beaver runs at a speed of 2.0 m/s with 45 J of kinetic energy. Substituting these values into the above equation
45 J = (1/2) ×m × [tex](2.0 m/s)^2[/tex]
Simplifying this equation:
45 J = (1/2) × m × 4.0[tex]m^2/s^2[/tex]
45 J = 2 m × 2 [tex]m^2/s^2[/tex]
45 J = 4 [tex]m^3/s^2[/tex]
[tex]m^3[/tex] = 45 J / 4 [tex]s^2[/tex]
[tex]m^3[/tex] = 11.25 kg×[tex]m^2/s^2[/tex]
Taking the cube root of both sides to solve for mass,
m = (11.25 kg×[tex]m^2/s^2)^(^1^/^3^)[/tex]
m = 1.74 kg (rounded to two decimal places)
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There are two resistors connected in parallel: R1-43 Ohms and R2-43 Ohms.
Determine the equivalent resistance. Round your answer to 2 significant digits only. For example, if the answer is 65.4 Ohms write 65.
If There are two resistors connected in parallel: R1-43 Ohms and R2-43 Ohms, then the equivalent resistance is 21.5Ω.
A resistor is a passive two-terminal electrical component used in circuits to implement electrical resistance. Resistors have a variety of purposes in electronic circuits, including lowering current flow, adjusting signal levels, dividing voltages, biassing active components, and terminating transmission lines. High-power resistors that can generate many watts of heat instead of electrical energy can be utilised as test loads for generators, power distribution systems, and motor controls. With temperature, time, or operating voltage changes, fixed resistors' resistances only slightly fluctuate. Variable resistors can be utilised as force sensors, heat sensors, light sensors, volume controls, lamp dimmers, humidity sensors, and chemical activity sensors.
The equivalent resistance in parallel combination is
R(p) = R₁R₂÷R₁+R₂
putting all values,
R(p) = 43×43÷(43+43)
R(p) = 21.5Ω
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In the figure four particles are fixed along an x axis, separated by distances d = 4.80 cm. The charges are 41 = +4e, q2=-e, 93 = +e, and q4 = +12e, with e = 1.60 × 10-19 C. What is the value of the net electrostatic force on (a) particle 1 and (b) particle 2 due to the other particles?
(a) Because the particles are all separated by the same distance, the distances for F13 and F14 are the same as for F12.
(b) Because particle 4 is three spacings distant from particle 2, the distance for F24 is 3d.
How to determine net electrostatic force?To calculate the net electrostatic force on a given particle, calculate the electrostatic force due to each of the other particles and then add them vectorially.
(a) The electrostatic force between two particles with charges q₁ and q₂ separated by a distance r is given by Coulomb's law as:
F = (1/4πε₀) × |q₁q₂| / r²
where ε₀ is the electric constant.
Using this formula, calculate the electrostatic force on particle 1 due to particle 2, which is:
F12 = (1/4πε₀) × |q₁q₂| / d² = (1/4πε₀) × 4e × e / (0.048 m)²
Similarly, calculate the electrostatic force on particle 1 due to particle 3 and particle 4:
F13 = (1/4πε₀) × |q₁q₃| / d² = (1/4πε₀) × 4e × e / (0.048 m)²
F14 = (1/4πε₀) × |q₁q₄| / (2d)² = (1/4πε₀) × 4e × 12e / (0.096 m)²
The distances for F13 and F14 are the same as for F12 because the particles are all separated by the same distance.
Add the forces vectorially:
F1net = F12 + F13 + F14
The direction of the net force will depend on the signs of the charges and their relative positions.
(b) To find the net electrostatic force on particle 2 due to the other particles, use the same method.
F21 = F12 (since the force is equal and opposite)
F23 = (1/4πε₀) × |q₂q₃| / d² = (1/4πε₀) × e × e / (0.048 m)²
F24 = (1/4πε₀) × |q₂q₄| / (3d)² = (1/4πε₀) × e × 12e / (0.144 m)²
The distance for F24 is 3d because particle 4 is three spacings away from particle 2.
Add the forces vectorially:
F2net = F21 + F23 + F24
The direction of the net force will depend on the signs of the charges and their relative positions.
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2) Let the angle 8 be the angle that the vector à makes with the I, the x-direction. Find the angle
for the vectors with the following components:
a) Ax=2.00 m and Ay--1.00 m
b) Ax=2.00 m and Ay= 1.00 m
c) Ax= -2.00 m and Ay 1.00
d) Ax= -2.00 m and Ay-1.00 m
(a) Ax=2.00 m and Ay--1.00 m, the angle of the vector is 153.4⁰.
(b) Ax=2.00 m and Ay= 1.00 m, the angle of the vector is 26.6⁰.
(c) Ax= -2.00 m and Ay 1.00 m, the angle of the vector is 333.43⁰.
(d) Ax= -2.00 m and Ay = -1.00 m, the angle of the vector is 206.6⁰.
What is the angle of the vectors?The angle of the vectors is known as the direction of the vectors and it is calculated as follows
(a) Ax=2.00 m and Ay--1.00 m, the angle of the vector;
tan θ = Ay/Ax
tan θ = (-1/2)
θ = arc tan (-1/2)
θ = -26.6⁰ = (180 - 26.6⁰) = 153.4⁰ (2nd quadrant).
(b) Ax=2.00 m and Ay= 1.00 m, the angle of the vector;
tan θ = Ay/Ax
tan θ = (1/2)
θ = arc tan (1/2)
θ = 26.6⁰ (1st quadrant).
(c) Ax= -2.00 m and Ay 1.00 m, the angle of the vector;
tan θ = Ay/Ax
tan θ = (-1/2)
θ = arc tan (-1/2)
θ = -26.6⁰ = (360 - 26.6⁰) = 333.43⁰ (4th quadrant).
(d) Ax= -2.00 m and Ay = -1.00 m, the angle of the vector;
tan θ = Ay/Ax
tan θ = (1/2)
θ = arc tan (1/2)
θ = 26.6⁰ = (180 + 26.6⁰) = 206.6⁰ (3rd quadrant).
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Question 1
2. Can 120 g of KNO3 (potassium nitrate) dissolve in 100 mL of water at 60°C?
Provide evidence from the graph to support your answer.
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12pt
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BI U A
✓ T²V
4
1 pts
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We can now see that 120 g of KNO3 (potassium nitrate) can not dissolve in 100 mL of water at 60°C.
What is the solubility?Solubility is the ability of a substance, called the solute, to dissolve in a solvent to form a hom--ogeneous mixture called a solution.
The saturated solution of potassium nitrate will hold about 110 g of dissolved salt per 100 mL of water at 60∘C . Thus we can say that the solubility of the KNO3 at 60°C is 110g of the salt per 100 g of water.
Solubility is an important concept in chemistry and is used in various applications such as in the preparation of solutions.
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Jason's heartbeat is measured to be 65 beats per minute.
What is the frequency of heartbeats in hertz?
What is the period for each heartbeat in seconds?
Answer:
To find the frequency of heartbeats in hertz, we need to convert the beats per minute (BPM) to beats per second (BPS), since frequency is measured in hertz (Hz) which is equivalent to cycles per second.
Frequency = BPM / 60
Frequency = 65 / 60
Frequency ≈ 1.083 Hz
To find the period for each heartbeat in seconds, we need to find the reciprocal of the frequency, which gives the time duration for one complete cycle.
Period = 1 / Frequency
Period = 1 / 1.083
Period ≈ 0.922 seconds per beat
A voltage of 65 V happen to a 2.53 nC. Calculate the work done.
How do i solve E=MC^2
Answer:
Calculating E = mc^2 for any object tells you how much energy would result if the entire object disappeared. Weigh the object you will perform the calculation for with a mass balance scale. Record its mass. Convert the mass to kg, if necessary. To convert from g to kg, for example, divide by 1,000. Square the speed of light.
Explanation:
Determine the magnitude of current in the 6 Ω resistor shown in Figure 3 if emf 1 has
an internal resistance of 1 Ω and emf 2 has an internal resistance of 0.2 Ω.
The magnitude of current in the 6Ω resistor is 0.72A.
EMF stands for electromotive force, which is the energy supplied by a source (such as a battery or generator) per unit of charge that passes through it, measured in volts. It represents the potential difference between the two terminals of the source when it is not connected to any circuit.
From the circuit diagram, we can see that the current flowing through the 6Ω resistor can be found by using Ohm's Law:
V = IR
where V is the voltage across the 6Ω resistor, I is the current flowing through it, and R is the resistance of the resistor.
To find V, we need to use Kirchhoff's Voltage Law (KVL) to determine the total voltage drop across the circuit. Starting from the top left corner and moving clockwise, we have:
V1 (emf) = IR1 + V2 (emf)
V2 (emf) - IR2 - IR1 = 0
Substituting V2 = -IR2 - 0.2I (since emf 2 has an internal resistance of 0.2Ω) into the first equation, we get:
V1 = I(R1 + R2 + 1) + 0.2I
Simplifying, we get:
V1 = I(7Ω) + 0.2I
Now we can solve for I:
I = V1 / (7Ω + 0.2Ω)
I = V1 / 7.2Ω
To find V1, we can use KVL again, starting from the bottom left corner and moving clockwise:
V1 - IR1 - V2 = 0
V1 - IR1 - (IR2 + 0.2I) = 0
Substituting V2 = -IR2 - 0.2I, we get:
V1 = I(R1 + R2 + 0.2) = I(7.2Ω)
Now we can substitute this expression for V1 into the equation for I:
I = (I(7.2Ω)) / (7Ω + 0.2Ω)
Simplifying, we get:
I = 0.72A
Therefore, the magnitude of current in the 6Ω resistor is 0.72A.
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A work done of 25 J happen to a charge that is 8.33 μC. Calculate the voltage.
A woman lifts a barbell 2.0 m in 5.0 s. If she lifts it the same distance in 10 s, the work done by her is:
The work done by the woman is independent of the time taken to lift the barbell, as long as the distance lifted remains constant.
The work done by the woman lifting the barbell can be calculated using the formula:
work = force x distance
Assuming the force required to lift the barbell remains constant, the work done is directly proportional to the distance lifted.
Therefore, if the woman lifts the barbell 2.0 m in 5.0 s, the work done is:
work1 = force x distance1 = force x 2.0 m
If she lifts it the same distance in 10 s, the work done is:
work2 = force x distance2 = force x 2.0 m
Since the distance lifted is the same in both cases, the work done by the woman is the same, and can be expressed as:
work1 = work2 = force x 2.0 m
Therefore, the work done by the woman is independent of the time taken to lift the barbell, as long as the distance lifted remains constant.
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Over which of the following time intervals is the net force on the object.
it seems that the rest of the question is missing. Could you please provide the full question and any relevant context so that I can better understand and provide an accurate answer. I can provide the definition of net force and how to calculate it.
The net force is the total force acting on an object, taking into account the magnitude and direction of all the individual forces acting on it. It is also referred to as the resultant force.
The net force on an object can be calculated using Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Mathematically, this can be expressed as:
Net force = mass x acceleration
or
Fnet = ma
where Fnet is the net force, m is the mass of the object, and a is its acceleration.
To calculate the net force on an object, you first need to identify all the individual forces acting on it, including their magnitudes and directions. Then, you can use vector addition to find the net force, taking into account the direction of each force.
Hence, If the forces are acting in the same direction, you can simply add their magnitudes to find the net force. If they are acting in opposite directions, you subtract the smaller force from the larger force, and the direction of the net force is in the direction of the larger force. If the forces are acting at right angles to each other, you can use the Pythagorean theorem to find the magnitude of the net force, and trigonometry to determine its direction.
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How do I measure luminous intensity? Are there specific devices that measure it in candelas? Is there a possibility to measure Luminous intensity using an analogue system like radiant intensity?
explanation of the 3 newtons laws? at least 2 paragraphs please
100 points & Brainliest
A ball of mass m = 0.275 kg swings in a vertical circular path tied to a string of L = 0.850 m long. (a) What are the forces acting on the ball at any point on the path? (b) Draw force diagrams for the ball when it is at the bottom of the circle and when it is at the top. (c) If its speed is 5.20 m/s at the top of the circle, what is the tension in the string there? (d) If the string breaks when its tension exceeds 22.5 N, what is the maximum speed the ball can have at the bottom before that happens?
At any point on the circular path, there are two forces acting on the ball: the tension force T from the string and the gravitational force mg acting downward. Additionally, at the top of the circle, there is a normal force N acting upward to balance the weight of the ball.
At the top of the circle, the tension force T and the weight of the ball mg are both acting on the ball in the same direction, so the net force is:
F_net = T - mg
Since the ball is moving in a circle at a constant speed, the net force must be equal to the centripetal force:
F_c = mv^2 / r
where m is the mass of the ball, v is its speed, and r is the radius of the circle, which is equal to the length of the string L. Therefore:
T - mg = [tex]mv^2[/tex] / L
Solving for T, we get:
T = mg + [tex]mv^2[/tex] / L
Substituting the given values, we get:
T = (0.275 kg)(9.81 m/s^2) + (0.275 kg)(5.20 m/s)^2 / 0.850 m = 3.06 N
Therefore, the tension in the string at the top of the circle is 3.06 N.
At the bottom of the circle, the tension force T is pointing upward, opposing the gravitational force mg, which is pointing downward. The net force is:
F_net = T - mg
To find the maximum speed the ball can have at the bottom before the string breaks, we need to find the maximum tension that the string can withstand. From the given information, the maximum tension is 22.5 N.
Setting F_net equal to the maximum tension, we get:
T - mg = 22.5 N
Solving for v, we get:
v = sqrt[(T - 22.5 N) L / m]
Substituting the given values and solving for v, we get:
v = sqrt[(3.06 N - 22.5 N) (0.850 m) / 0.275 kg] = 3.89 m/s
Therefore, the maximum speed the ball can have at the bottom before the string breaks is 3.89 m/s.
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5. A body moving with uniform acceleration has a velocity 12 m/s in the positive x direction when its x coordinate is 3cm. If its x coordinate 2 s later is -5 cm, what is the magnitude of its acceleration?
How would the pollution from 2 coal plants compare if the first plant were twice as energy efficient as the second one?
The pollution from the first plant would be half that of the second plant for the same amount of energy produced.
The energy efficiency of a coal plant refers to the amount of energy produced per unit of fuel consumed. If the first plant is twice as energy efficient as the second plant, it means that it can produce the same amount of energy using half the amount of fuel.
Since pollution from coal plants is directly proportional to the amount of fuel consumed, the first plant would produce half the pollution of the second plant for the same amount of energy produced. This assumes that the two plants have the same level of emissions per unit of fuel consumed, which may not necessarily be the case.
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2. A bus travels 280 km south along a straight path with an average velocity of 88 km/h to the south. The bus stops for 24 min. Then, it travels 210 km south with an average velocity of 75 km/h to the south. a. How long does the total trip last? b. What is the average velocity for the total trip?
Answer:76.78 km/h To calculate the average velocity for the total trip, you need to first determine the total distance travelled and the total time taken. First, let's calculate the total distance travelled. The trip consists of 2 legs. The 1st leg is 280 km and the 2nd leg is 210 km. So the total distance is 280 km + 210 km = 490 km. Now you need to calculate the total time taken. For this problem, there are 3 intervals that need to be accounted for. The travel time for the 1st leg, the duration of the rest stop in the middle, and the travel time for the 2nd leg. The travel time for both legs is calculated by dividing the distance travelled by the average speed. So for the first leg we have 280 km / (88 km / h) = 3.181818 h The 2nd leg is 210 km / (75 km/h) = 2.8 h The rest stop in hours is 24 min / (60 min/h) = 0.4 h The total time is 3.181818 h + 2.8 h + 0.4 h = 6.381818 h The average velocity is the distance divided by the time, giving: 490 km / (6.381818 h) = 76.78 km/h
Explanation: I am middle school genius and I spell diff bc I am british-english
Can someone help me with my physics sheet? I don’t understand it.. thank you
Acceleration of the skydiver during the free fall is 4.13 m/s².
1) Mass of the skydiver, m = 83 kg
Weight, W = mg = 83 x 9.8
W = 813.4 N
Free fall acceleration is the acceleration that a body travelling in free fall experiences due to only the gravitational pull of the earth. This is the acceleration brought on by gravity.
Since there is no air resistance, the acceleration of the skydiver during the free fall is the acceleration due to gravity, g.
Freebody diagram is given in Fig.1.
2) Mass of the skydiver, m = 78 kg
Air resistance acting on him, F' = 470 N
mg - 470 = ma
813.4 - 470 = ma
a = 343.4/83
a = 4.13 m/s²
Freebody diagram is given in fig.2.
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What is the process where light bounces back from an object at the same angle and intensity as it. is received by the object?
Answer: It is Reflection
Explanation: Reflection occurs when incoming solar radiation bounces back from an object or surface that it strikes in the atmosphere, on land, or water, and is not transformed into heat.
. Describe the five adjustments you made to the Rube Goldberg device in order to keep the flow of energy going.
The five changes I made to the Rube Goldberg apparatus to keep the energy flowing is 1) Reduced the height of the first ball platform 2) Attached the weight that has to be lifted. 3) The sling shot was attached to the pin. 4) Took a shot, I lowered the seesaw gadget. 5) A water-filled balloon. this is basically a machine.
A Rube Goldberg machine, named after American cartoonist Rube Goldberg, is a machine or device that is purposely constructed to do a basic task in an indirect and (impractically) too convoluted manner. Typically, these machines are made up of a sequence of basic unconnected devices; the action of one initiates the next, finally culminating in the achievement of a specified purpose. A similar device is known as a "Heath Robinson contraption" in the United Kingdom, after the cartoonist W. Heath Robinson.
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WILL GIVE BRAINLIEST HELPPP FASTER PLEASE l ONLY RIGHT ANSWER!!!!! l
How can spectroscopy and infrared technology be useful in space?
They can enhance speed by making spacecraft fuel more efficient.
They can measure magnetic fields produced by astronomical bodies.
They can provide an emergency escape to the astronaut from a space center.
They can determine the elements that make up the surface of astronomical bodies.
Answer: D. They can determine the elements that make up the surface of astronomical bodies.
Explanation: Spectroscopy and infrared technology are useful in space because they allow scientists to determine the elements that make up the surface of astronomical bodies, such as planets, moons, and asteroids.
Spectroscopy involves the analysis of light or radiation emitted or absorbed by these bodies. When light interacts with matter, it gets absorbed or emitted in specific wavelengths that correspond to the energy levels of atoms and molecules. By studying the pattern of these wavelengths, scientists can identify the unique "fingerprint" or spectral lines of elements and compounds.
Infrared technology, on the other hand, detects and measures the infrared radiation emitted by objects. This radiation is produced due to the thermal energy or heat emitted by celestial bodies. By analyzing the specific wavelengths of infrared radiation, scientists can gain insights into the composition and temperature of these bodies.
By combining spectroscopy and infrared technology, scientists can gather valuable data about the chemical composition of astronomical bodies. This information helps in understanding the geological processes, formation, and evolution of these bodies. It also provides insights into the presence of specific elements or compounds that may be important for studying habitability, potential resources, or even the origins of life in the universe.
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A long jumper leaves the ground with an initial speed of 9.5m/s at an angle of 22degrees from the ground. Determine the time it takes for the long jumper to reach her maximum height of her jump.
The time it takes for the long jumper to reach her maximum height will be approximately 0.372 seconds .
To determine the time it takes for the long jumper to reach her maximum height, the vertical motion of the jumper separately.
The initial vertical velocity, v₀y, can be calculated by multiplying the initial speed, v₀, by the sine of the launch angle, θ:
v₀y = v₀sin(θ)
Plugging in the given values:
v₀ = 9.5 m/s (initial speed)
θ = 22° (launch angle)
We can convert the launch angle from degrees to radians, as the trigonometric functions in most programming languages (including Python, which we'll use later) take input in radians:
θ = 22° * (π/180) ≈ 0.384 radians
Substituting the values:
v₀y = 9.5 m/s * sin(0.384) ≈ 3.65 m/s
The maximum height of the jump occurs when the vertical velocity, vy, becomes zero. At that moment, the jumper is at the highest point of the jump before descending.
vy = v₀y + at
where a is the acceleration due to gravity, which is approximately 9.8 m/s² (assuming no air resistance).
Setting vy to zero and solving for t:
0 = v₀y + at
t = -v₀y / a
Substituting the values:
t = -3.65 m/s / 9.8 m/s² ≈ -0.372 seconds
Since time cannot be negative in this context, we discard the negative value and take the absolute value. Therefore, the time it takes for the long jumper to reach her maximum height is approximately 0.372 seconds .
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A pool noodle has a density of 145 kg/m3, a length of 1.65 m and a radius of 2.5 cm. How many pool noodles would be needed to make a raft that would support the weight of a person with a mass of 65.0kg?
The number of pool noodles that would be needed to support the weight is 20.
What is the volume of single pool noodle?
The volume of a single pool noodle is calculated as follows;
V = πr²h
V = π (0.025)² x 1.65
V = 0.00324 m³
The weight of the water displaced is calculated as follows;
W = ρVg
where;
ρ is the density of waterV is the volumeg is gravityW = 1000 x 0.00324 x 9.8
W = 31.75 N
The number of pool noodles needed to support a person is calculated as follows;
= (65 x 9.8 ) / (31.75)
= 20
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What is the velocity of a sound wave that travels 2500 m in 8.2 s.
Explanation:
V=lander f. where,
v is the velocity of the sound wave
f is the frequency of sound wave(Hz)
L is the wavelength
so we simply just divide 2500 by 8.2 that gives us 304.88ms-¹
hopefully I get this right!
A 2.02-kg particle has a velocity (2.03 î − 2.96 ĵ) m/s, and a 2.94-kg particle has a velocity (0.91 î + 5.94 ĵ) m/s.
(a) Find the velocity of the center of mass.
î +
ĵ
m/s
(b) Find the total momentum of the system.
î +
ĵ
kg · m/s
(a)The velocity of the center of mass is (0.829 î + 2.261 ĵ) m/s. and (b) the total momentum of the system is (6.79 î + 8.66 ĵ) kg · m/s.
Momentum is a measure of an object's motion and is the product of its mass and velocity. It is a vector quantity, meaning it has both magnitude and direction.
(a) The velocity of the center of mass can be found using the formula:
v_cm = (m1v1 + m2v2) / (m1 + m2)
where m1 and v1 are the mass and velocity of the first particle, and m2 and v2 are the mass and velocity of the second particle. Substituting the given values:
v_cm = (2.02 kg)(2.03 î − 2.96 ĵ) m/s + (2.94 kg)(0.91 î + 5.94 ĵ) m/s / (2.02 kg + 2.94 kg)
v_cm = (4.115 î + 11.242 ĵ) / 4.96
v_cm = 0.829 î + 2.261 ĵ m/s
So, the velocity of the center of mass is (0.829 î + 2.261 ĵ) m/s.
(b) The total momentum of the system can be found by adding the momentum of the two particles:
p_total = m1v1 + m2v2
Substituting the given values:
p_total = (2.02 kg)(2.03 î − 2.96 ĵ) m/s + (2.94 kg)(0.91 î + 5.94 ĵ) m/s
p_total = (4.115 î − 8.798 ĵ) kg · m/s + (2.67494 î + 17.4636 ĵ) kg · m/s
p_total = 6.78994 î + 8.6646 ĵ kg · m/s
So, the total momentum of the system is (6.79 î + 8.66 ĵ) kg · m/s.
Therefore,(a)The velocity of the center of mass is (0.829 î + 2.261 ĵ) m/s. and (b) the total momentum of the system is (6.79 î + 8.66 ĵ) kg · m/s.
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The highness or lowness of a sound is perceived as
a.
compression.
c.
ultrasound.
b.
wavelength.
d.
pitch.
Answer:
i think its D
Explanation:
Answer:
The highness or lowness of a sound is perceived as pitch. Pitch is a perceptual property of sound that allows us to distinguish between sounds that have the same loudness and duration, but differ in their frequency content. The pitch of a sound is determined by the frequency of the sound wave, with higher frequencies producing higher pitches and lower frequencies producing lower pitches. The pitch is what makes a sound distinguishable and is important in music, language, and communication.
A/An breaks down a complicated goal into daily action to make it more manageable?
A routine breaks down a complicated goal into daily action to make it more manageable.
What is a routine?A routine can be described as the sequence of actions regularly followed which do help individuals as well as the organization so they can acheive their goals.
It should be noted that a routine is neccessary in an organization because it will help help them to breakdown the task as well as the activities and this will help to achive the goals as well as the neccessary things on time because allcomplicated goals woud have been included as well as how it will be carried out.
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An object has a mass of 25 kilograms: to. How much is the potential energy if the height is 30 m. b. How much is the kinetic energy at a height of 30 m. If the object is in repose?
The potential energy of the object is 7,350 J.
The kinetic energy is zero.
What is the potential energy of the object?The potential energy of an object at the given position is calculated by applying the following formula.
P,.E = mgh
Where;
g is the acceleration due to gravityh is height m is massP.E = 25 x 9.8 x 30
P.E = 7,350 J
If the object is at rest (not moving), then its kinetic energy is zero, sice kinetic energy of a nergy of a body in motion.
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The same collision as in Question 5 takes place, only this time the car and the truck bounce off each other completely elastically What are the final velocities of the car and truck just after the collision?
The final velocities of the car and truck just after the collision will be as per the conservation of momentum.
Momentum is defined as product of mass and velocity of the body. It is denoted by letter p and it is expressed in kg.m/s. Mathematically p = mv. it discuss the moment of the body. body having zero mass or velocity has zero momentum. The dimensions of the momentum is [M¹ L¹ T⁻¹].
According to conservation of momentum, Initial momentum will be equal to the final momentum. In the elastic collision there is no loss of energy, both energy and momentum is conserved.
if the the car is coming with velocity equal to the mass of the truck and truck is coming with mass of the car, then they have same momentum in opposite direction when they collide each other the final velocity of both car and truck becomes zero.
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