10. Given: ABED, AD = EBProve: AABD AEDBLook at the proof. Name the postulate you would use to prove the two triangles are congruent.Given: AB ED, AD EBProve: AABD = AEDBAB EDGivenAD EBGivenBD BDReflexive Propertyof CongruenceAABD AEDB?BDE
Answers
In the problem, we are already given 2 pairs of sides that are congruent: AB and ED, and AD and BE.
Using the reflexive property of congruence, we also know that segment BD is congruent to itself.
We have therefore used three pairs of sides that are congruent to prove that △ABD ≅ △EDB.
This means that we used the SSS Postulate to prove the congruence of the two triangles.
Related Questions
Solve the equation using the quadratic formula. 2y^2 + 4y + 1 = 0
Answers
Answer:
The solution to the quadratic equation is;
[tex]\begin{gathered} y=-1+\frac{\sqrt[]{2}}{2} \\ \text{and} \\ y=-1-\frac{\sqrt[]{2}}{2} \\ y=-1+\frac{\sqrt[]{2}}{2},-1-\frac{\sqrt[]{2}}{2} \end{gathered}[/tex]Explanation:
Given the quadratic equation;
[tex]2y^2+4y+1=0[/tex]Applying quadratic formula;
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]Substituting the coefficients of the quadratic equation;
[tex]\begin{gathered} y=\frac{-4\pm\sqrt[]{4^2-4(2)(1)}}{2(2)} \\ y=\frac{-4\pm\sqrt[]{16^{}-8}}{4} \\ y=\frac{-4\pm\sqrt[]{8}}{4} \\ y=\frac{-4\pm2\sqrt[]{2}}{4} \\ y=\frac{-2\pm\sqrt[]{2}}{2} \end{gathered}[/tex]Therefore, the solution to the quadratic equation is;
[tex]\begin{gathered} y=-1+\frac{\sqrt[]{2}}{2} \\ \text{and} \\ y=-1-\frac{\sqrt[]{2}}{2} \\ y=-1+\frac{\sqrt[]{2}}{2},-1-\frac{\sqrt[]{2}}{2} \end{gathered}[/tex]Solve for x using the "Quadratic Formula". You MUST show every level of work (like you saw in the lesson) in order to receive full credit.
3x^2-5x+1
Answers
The solution to the quadratic equation 3x² - 5x + 1 using quadratic formula is; x = (5 + √13)/6 or (5 - √13)/6
How to use the quadratic formula?
The general form of a quadratic equation is given as;
ax² + bx + c = 0
The quadratic formula that is used to solve this is given by;
x = [-b ± √(b² - 4ac)]/(2a)
Now, we are given the quadratic equation as;
3x² - 5x + 1
Thus, using quadratic formula we have;
x = [-(-5) ± √((-5)² - (4 * 3 * 1))]/(2 * 3)
x = [5 ± √(25 - 12)]/6
x = (5 ± √13)/6
x = (5 + √13)/6 or (5 - √13)/6
Read more about quadratic formula at; https://brainly.com/question/8649555
#SPJ1
A brick has dimensions of110. cm x 655 cm x 1330 cm.What is the volume of the brick in cubic meters?
Answers
Answer: We have to find the volume of the brick, the formula for the volume is as follows:
[tex]V=l\times w\times h\Rightarrow(1)[/tex]Identifying the known variables and plugging in the equation (1) gives the following answer:
[tex]\begin{gathered} l=110cm \\ w=655cm \\ h=1330cm \end{gathered}[/tex]The volume therefore is:
[tex]\begin{gathered} V=(110cm)\times(655cm)\times(1330cm) \\ V=95,826,500cm^3 \end{gathered}[/tex]Hi can someone please explain this?
Image is attached
Answers
Answer:
B
Step-by-step explanation:
Since triangles BCD and PQR are similar, we can find BD through the three proportional sides. Line BD is to PR and option B is the only answer where BD and PR are both numerators/denominators in this case the denominators of the two fractions. Hope this helps!
given the function. calculate the following values.
Answers
Answer:
[tex]5, \sqrt{2}, 10[/tex]
Step-by-step explanation:
[tex]x=-7 \implies x<0 \implies f(-7)=5 \\ \\ x=0 \implies x \geq 0 \implies f(0)=\sqrt{2(0)^2+2}=\sqrt{2} \\ \\ x=7 \implies x \geq 0 \implies f(7)=\sqrt{2(7)^2+2}=10[/tex]
Write an equation in slope-intercept form of the line that passes through the point (-6,-5) with slope 6.A. y = -5 + 6(2 + 6)B.y=6x + 31c. y - 5 = 6(x+6)D. 6x – y + 31 =0
Answers
Using the Point-Slope Formula :
[tex]y-y_1=m(x-x_1)[/tex]where m is the slope and (x1, y1) is the point on the line
From the given problem, m = 6 and the point is (-6, -5)
Subsitute the given to the formula :
[tex]\begin{gathered} y-(-5)=6\lbrack x-(-6)\rbrack \\ y+5=6(x+6) \\ y+5=6x+36 \\ y=6x+36-5 \\ y=6x+31 \end{gathered}[/tex]The answer is Choice B. y = 6x + 31
help meeeeeeeeeeeeeeeeeeeeeee
thank you
Answers
The height of the object based on the information is 1963 feet.
How to calculate the height?It should be noted that a function is important to show the relationship between the variables given in the data.
In this case, the function given for the height of the object is given as:
h = 16t² + 1899
where t = time
When the time is 2 seconds, the height will be:
h = 16t² + 1899
h = 16(2)² + 1899
h = 64 + 1899
h = 1963
The height is 1963 feet.
Learn more about height on:
brainly.com/question/983412
#SPJ1
he two-way table shows the number of students in a school who have rabbits and/or birds as pets:Have RabbitsDo Not Have RabbitsTotalHave Birds182240Do Not Have Birds253560Total4357100How many more students have rabbits than birds? (4 points)372225
Answers
The numbers we want to compare are ther number of students that have rabbits and the number of students that have birds.
The number of students that have rabbits is in the column "Have Rabbits" and, since we want all of them, we get the value from the row "Total", so the number is 43.
Similarly, the number of students that have birds is in the row "Have Birds" and, since we want all of them, we pick the number in column "Total", which is 40.
So, the number of students that have rabbits is 43 and the number of students that have birds is 40. Since 43 is 3 more than 40, there are 3 more students that have rabbits that students that have birds.
a hotel manager has 12 diferent promotional events,plans to run 4 weeks, how many events can she run
Answers
Answer: 3 per week.
Step-by-step explanation: 3 x 4 = 12.
Simplify: ✓- 72 O A - 6iva O B. 6iv 2 O c. 5i/3 OD. – 517 3
Answers
We want to simplify the following expression
[tex]\sqrt[]{\text{ -72}}[/tex]To do so we will use the following properties
[tex]\sqrt[]{a\cdot b}=\sqrt[]{a}\cdot\sqrt[]{b}[/tex]and
[tex]\sqrt[]{\text{ -1}}=i[/tex]So we have that
[tex]\sqrt[]{\text{ -72}}=\sqrt[]{\text{ -1}\cdot72}=\sqrt[]{\text{ -1}}\cdot\sqrt[]{72}=\sqrt[]{72}i=\sqrt[]{8\cdot9}i=\sqrt[]{8}\cdot\sqrt[]{9}i=\pm3\cdot\sqrt[]{8}i=\pm3\cdot\sqrt[]{4\cdot2}i=\pm3\sqrt[]{4}\sqrt[]{2}i[/tex]which is equal to
[tex]\pm3\cdot2\sqrt[]{2}i=\pm6\sqrt[]{2}i[/tex]so options A and B are correct
Is this the right answer to the question. Not 100% sure.
Answers
Answer:
Yes, you are correct. Lines l and m are parallel, so corresponding angles are congruent. It does follow that x = 60.
sketch one cycle of y= -3 sin θ
Answers
Answer:
Explanation:
One cycle of the function runs from 0 to 2 pi.
To sketch one cycle one -3 sin θ, we first plot find some points that lie on it and then plot them to sketch the graph.
We evaluate the function at 0, pi/2, and 2pi.
[tex]\begin{gathered} y(0)=-3\sin 0=0 \\ y(\frac{\pi}{2})=-3\sin \frac{\pi}{2}=-3 \\ y(2\pi)=-3\sin 2\pi=0 \end{gathered}[/tex]We now sketch the three points we found above.
Hence, we get the graph of the function for one cycle.
If a car will go 108 miles on a 6 gallon of gasoline in city driving. What is the rate in miles per gallon.
Answers
To find the rate in miles per gallon, divide the number of miles by the number of gallons of gasoline:
[tex]\frac{108\; \text{miles}}{6\; \text{gallons}}[/tex]Reduce the fraction by 6:
[tex]\frac{108}{6}=18\text{ miles per gallon}[/tex]The rate in miles per gallon is 18.
A store has clearance items that have been marked down by 40%. They are having a sale, advertising an additional 60% off clearance items. What percent of the original price do you end up paying?
Answers
Answer:
24 percent
Step-by-step explanation:
Let's say that there is a 100-dollar item. Mark that by 40 and you get 60. Marking that by 60 again gives you 24 dollars. 24 dollars is 24 percent of 100, so you only pay 24 percent of the original price.
Translate "the sum of m and 2.33 multiplied by s is 52.25" into an algebraic equation. Do not solve the equation.
Answers
Answer:
[tex](m + 2.33) \times s = 52.25[/tex]
:)
for each pair of equations decide whether the given value of x is a solution to one or both equations
Answers
Answers:
1. x = 2 is solution of both equations.
2. x = 3 is a solution of equation b.
3. x = -2 is solution of both equations.
4. x = -1 is solution of both equations.
5. x = -5 is solution of both equations.
Explanation:
To know if the value of x is a solution, we need to replace x with the given value. So:
1. Repalcing x by 2, we get:
a. x ( 2 + 3) = 10
2 ( 5) = 10
10 = 10
b. 2x + 3x = 10
2(2) + 3(2) = 10
4 + 6 = 10
10 = 10
The equality is true in both cases, so x = 2 is solution of both equations.
2. Replacing x by 3, we get:
a. x - 4 = 1
3 - 4 = 1
- 1 = 1
b. 4 - x = 1
4 - 3 = 1
1 = 1
Since -1 and 1 are distintc, x = 3 is a solution of equation b.
3. Replacing x by -2, we get:
a. 7x = -14
7(-2) = -14
- 14 = - 14
b. x(14) = - 28
(-2)(14) = - 28
- 28 = - 28
So, x = -2 is solution of both equations.
4. Replacing x by -1, we get:
a. x + 3 = 2
-1 + 3 = 2
2 = 2
b. 3 + x = 2
3 + (-1) = 2
2 = 2
So, x = -1 is solution of both equations.
5. Replacing x by -5, we get:
a. 3 - x = 8
3 - ( - 5) = 8
3 + 5 = 8
8 = 8
b. 5 - x = 10
5 - ( - 5) = 10
5 + 5 = 10
10 = 10
So, x = -5 is solution of both equations.
3 The table shows the average mass, in kilograms, of different sizes of cars and trucks. Size Small Car Large Car Large Truck Average Mass (kilograms) 1,354 1,985 2,460 Parta
Answers
The average mass of the large truck is 2460 kg and the average mass of the small car is 1354 kg.
Based on the given data, the mass of the large truck is 1106 kg.
Now, rounding off to the nearest hundred, the average mass of the larger truck is 2500 kg and the average mass of the small car is 1400 kg.
So, the larger truck is 1100 kg heavier than than the smaller car.
(1 point)
Use the complete the square method to find the vertex of the following parabola:
y = x² + 16x +67
Step 1: Separate non-x-terms from x-terms
Manipulate the equation until all terms containing x are on one side of the equation, and all terms not containing x are
on the opposite side:
Step 2: Identify the value that completes the square
Step 3: Complete the Square
Step 4: Factor and solve for y
Step 5: Identify the vertex
= x² + 16x
Answers
Answer:
32
Step-by-step explanation:
Consider the following inequality:2(3z - 4) > - 2z + 16Step 1 of 2: Solve the linear inequality for the given variable. Simplify and express your answer in algebraic notation.
Answers
Let's solve the inequality:
[tex]\begin{gathered} 2(3z-4)\ge-2z+16 \\ 6z-8\ge-2z+16 \\ 6z+2z\ge16+8 \\ 8z\ge24 \\ z\ge\frac{24}{8} \\ z\ge3 \end{gathered}[/tex]Therefore the solution of the inequality is:
[tex]z\ge3[/tex]The function g is defined as follows.
g(x)=x² +1
If the graph of g is translated vertically upward by 4 units, it becomes the graph of a function h.
Find the expression for h (x).
Answers
Answer:
Use that steps to find your answer
Answer:
h(x) = g(x) + 5 = x² + 5
Step-by-step explanation:
Since the graph is translated vertically upward by 4 units, there is no change in the x values; for the same x value the new y value is +4 times the old y value
solve 8,961 ÷ 29 in standard algorithm.
500 points
Answers
The value of the quotient expression 8,961 ÷ 29 = 309
How to determine the quotient of the numbers?The numbers are given as
8961 and 29
So, we have
8,961 ÷ 29
By using the standard algorithm i.e. the partial quotient method, we have the following equation
8,961 ÷ 29 = (8700 + 261)/29
Open the bracket
So, we have the following equation
8,961 ÷ 29 = 8700/19 + 261/29
Evaluate the quotients
So, we have the following equation
8,961 ÷ 29 = 8700/19 + 261/29
Next, we evaluate
So, we have the following equation
8,961 ÷ 29 = 309
This means that the quotient is 309
Read more about quotient at
https://brainly.com/question/629998
#SPJ1
Answer:
Step-by-step explanation:
309
As a first step in solving the system shown, Yumiko multiplies both sides of the equation 2x – 3y = 12 by 6. By what factor should she multiply both sides of the other equation so that she can add the equations and eliminate a variable?5x + 6y = 182x – 3y = 12factor:
Answers
Given the equations
[tex]\begin{cases}5x+6y=18 \\ 2x-3y=12\end{cases}[/tex]First, she multiplied the second equation by 6:
[tex]\begin{gathered} 6\cdot(2x-3y)=6\cdot12 \\ 6\cdot2x-6\cdot3y=6\cdot12 \\ 12x-18y=72 \end{gathered}[/tex]You have to determine the factor to multiply the equation 5x+6y=18 to be able to add both equations and eliminate one of the variables.
To do so, compare the coefficients of the like terms:
5x and 12x, "12" is not a multiple of 5, so there is no factor that when multiplied by 5x will give 12x as a product.
6y and 18y, 18 is a multiple of 6, if you multiply 6y by 3 the product will be 18y.
So, the factor you have to use to multiply the equation and eliminate one variable is 3.
Solve each inequality.
1/2-2p>2/3
Answers
Answer:
our house and the only way I can see the only way I can see the only u new friends at the only way I can see the 77
What’s the correct answer answer asap for brainlist
Answers
Answer: its protein channels
Step-by-step explanation:
what is the answer too 14:10=:55
Answers
Answer: Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.
Step-by-step explanation:
Find the 29th term of an arithmetic sequence with a1 = 2 and d =5
Answers
Arithmetic Sequence is a sequence of numbers such that the difference between each number is constant. The formula for the arithmetic sequence is given by;
[tex]a_n=a_1+(n-1)d[/tex]where An is the last term
A₁ is the first term
n is the number of terms (or number in the sequence)
d is the common difference
In our problem we are given the first term (a₁) = 2, a common difference of 5 (d = 5), and the number of terms which is 29 (n = 29).
Now in order to find the 29th term of the sequence (a₂₉), we just need to follow the formula;
[tex]\begin{gathered} a_{29}=a_1+(n-1)d_{} \\ a_{29}=2_{}+(29-1)5 \\ a_{29}=2_{}+(28)5 \\ a_{29}=2_{}+140 \\ a_{29}=142 \end{gathered}[/tex]Therefore the 29th term of the arithmetic sequence is 142.
Formula: an=a1 + (n-1) x d
a1=2
d=5
n=29
plug in the values: an= 2 + (29-1) x 5 = 142
SO THE ANSWER IS : 142
what percent of 51 is 127.5?20.67 is 42.5% of what?
Answers
a) We have to find what percent of 51 is 127.5.
As 127.5 is larger than 51, we expect a percentage larger than 100%.
We can find the percentage by dividing the part, 127.5, by the total, 51, and multiplying by 100%:
[tex]\frac{127.5}{51}\cdot100\%=2.5\cdot100\%=250\%[/tex]b) We have to find the value x of which 42.5% is equal to 20.67.
We can write this as:
[tex]\begin{gathered} x\cdot\frac{42.5}{100}=20.67 \\ x\cdot0.425=20.67 \\ x=\frac{20.67}{0.425} \\ x\approx48.63 \end{gathered}[/tex]Answer:
a) 127.5 is 250% of 51.
b) 20.67 is 42.5% of 48.63.
y=5x+50 in standard form
Answers
Answer:
-5x + y = 50
Step-by-step explanation:
to formula for standard form is Ax + By = C
the formula (y=5x+50) is in slope-intercept form, which is y=mx+b
to write (y=5x+50) in standard form, move the 'mx' (which in this case is 5x) to the other side of the '=' or also known as the equation:
y = 5x + 50
y - 5x = 5x - 5x + 50
y - 5x = 50
(here, we subtracted 5x on both sides of the equation to 'move it')
Ax = -5x
By = 1y = y
C = 50
so, to write it in the standard form:
-5x + y = 50
Angela purchase a shirt for $14.65 a pair of jeans for $21.99 and she was charged $2.93 tax how much change should she receive if she paid with a $50 bill
Answers
The cost of the shirt = $14.65
The cost of the pair of jeans = $21.99
Tax = $2.93
Amount paid = $50
Change = Amount paid - (Cost of shirt + Cost of jeans + tax)
Change = 50 - (14.65 + 21.99 + 2.93)
Change = 50 - 39.57
Change = $10.43
Determine all solutions to the equation radical 2 times cosine 2 times x equals sine squared x plus cosine squared x on the interval [0, 2π).
Answers
Given
The equation,
[tex]\sqrt{2}\cos2x=\sin^2x+\cos^2x[/tex]To determine all the solutions in the interval [0, 2π).
Explanation:
It is given that,
[tex]\sqrt{2}\cos2x=\sin^2x+\cos^2x[/tex]Since
[tex]\sin^2x+\cos^2x=1[/tex]Then,
[tex]\begin{gathered} \sqrt{2}\cos2x=\sin^2x+\cos^2x \\ \Rightarrow\cos2x=\frac{1}{\sqrt{2}} \\ \Rightarrow2x=\cos^{-1}(\frac{1}{\sqrt{2}}) \\ \Rightarrow2x=\frac{\pi}{4} \\ \Rightarrow x=\frac{\pi}{8} \end{gathered}[/tex]Hence, the solutions of the given equation in [0, 2π) is,
[tex]a)\text{ }x=\frac{\pi}{8},\frac{7\pi}{8},\frac{9\pi}{8},\frac{15\pi}{8}[/tex]
