10. Look at the graphs below. The graph on the left is the pre-image and the graph on the right
is the image. Using a scale factor, what are the coordinates of H'.
شے کے مر 1 2
765432
-1
-2
5
3
2
H
X
5
4
3
2
-1
-2
H
Y

Answers

Answer 1

The coordinates of H' using the scale factor k is H' = (kx, ky)

What are the coordinates of H'.

From the question, we have the following parameters that can be used in our computation:

The graph of the pre-image and a scale factor

Representing the coordinates of H with

H = (x, y)

And the scale factor with

Scale factor = k

The coordinates of H' is calculated using

H' = H * Scale factor

Substitute the known values in the above equation, so, we have the following representation

H' =(x, y( * k

Evaluate

H' = (kx, ky)

Hence, the image of H' is (kx, ky)

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Related Questions

WRITE Describe how to add and subtract polynomials using both the vertical and horizontal methods.
To add polynomials in a horizontal method, combine coefficients
polynomials in standard form
For the vertical method, write the
✓align like terms in columns, and combine like terms. To subtract
of the polynomial that is being subtracted,
polynomials in a horizontal method, find the additive inverse
and then combine like terms. For the vertical method, write the polynomials in standard form, align like terms in
columns, and subtract by adding the additive identity

Answers

To add polynomials in a horizontal method, combine like terms. For the vertical method, write the polynomials in standard form and align like terms in columns, and combine like terms. To subtract polynomials in a horizontal method, find the negative (opposite)  of the polynomial that is being subtracted and then combine like terms. For the vertical method, write the polynomials in standard form, align like terms, and subtract by adding the negative (opposite).

What is the polynomials  about?

To add polynomials vertically,  one need to write them in standard form and align like terms in the columns. Combine like terms and add them to the polynomial.

Therefore, note that Polynomials are seen as expressions with variables and coefficients. Combine or subtract like terms when adding or subtracting them.

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WRITE Describe how to add and subtract polynomials using both the vertical and horizontal methods.

To add polynomials in a horizontal method, combine  ----- For the vertical method, write the polynomials in  --------  align like terms in columns, and combine like terms. To subtract polynomials in a horizontal method, find the ------ of the polynomial that is being and then combine like terms. For the vertical method, write the polynomials in standard form, align like terms and  and subtract by adding the  -------

Solve the quadratic equation
7. 3x2 + 13x10 = 0
9. 12n²-11n +2=0
11. 4x² + 12x +9=0
X
8. 5x28x +3=0
10. 10a²a-2=0
12. 8x2 10x + 3 = 0

Answers

The solution of the quadratic equations are shown below.

How do you solve the quadratic equation?

There are various methods that we could use when we want to solve a quadratic equation and these include;

1) Formula method

2) Graphical method

3) Completing the square method

4) Factor method

We have solved the following quadratic equations by factoring.

1)  3x^2 + 13x +10 = 0

x = - 1 and -10/3

2)  12n²-11n +2=0

n = 2/3 and 1/4

3) 5x^2 + 8x +3=0

x = -3/5 and -1

4)  10a²+ a -2=0

a = 2/5 and -1/2

5) 8x^2 + 10x + 3 = 0

x = -1/2 and -3/4

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A particular fruit's weights are normally distributed, with a mean of 692 grams and a standard deviation of 23 grams. If you pick 12 fruit at random, what is the probability that their mean weight will be between 681 grams and 682 grams.

Answers

The probability that the mean weight of 12 fruit will be between 681 and 682 grams is 0.0184.

We can solve this problem by using the central limit theorem, which tells us that the distribution of sample means will be approximately normal if the sample size is sufficiently large.

First, we need to calculate the standard error of the mean:

standard error of the mean = standard deviation / sqrt(sample size)

= 23 / sqrt(12)

= 6.639

Next, we can standardize the sample mean using the formula:

z = (x - mu) / (standard error of the mean)

where x is the sample mean, mu is the population mean, and the standard error of the mean is calculated above.

z1 = (681 - 692) / 6.639 = -1.656

z2 = (682 - 692) / 6.639 = -1.506

Using a standard normal distribution table or calculator, we can find the probabilities corresponding to these z-scores:

P(z < -1.656) = 0.0484

P(z < -1.506) = 0.0668

The probability of the sample mean being between 681 and 682 grams is the difference between these probabilities:

P(-1.656 < z < -1.506) = P(z < -1.506) - P(z < -1.656)

= 0.0668 - 0.0484

= 0.0184

Therefore, the probability that the mean weight of 12 fruit will be between 681 and 682 grams is 0.0184.

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7. a) List three pairs of fractions that have a sum of 3\5.

Answers

The three pairs of fraction whose sum is 3/5 are

1/5 + 2/5-2/5+1-6/5+9/5

We have to find pairs of fractions that have a sum of 3/5.

First pair:

1/5 + 2/5

= 3/5

Second pair:

= -2/5 + 1

= -2/5+ 5/5

= 3/5

Third pair:

= -6/5 + 9/5

= 3/5

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if a contractionary fiscal policy is followed by an expansionary monetary policy, nominal interest rate and employment would most likely be affected in which of the following ways in the short run?

Answers

In the short run, if a contractionary fiscal policy is followed by an expansionary monetary policy, the nominal interest rate is likely to decrease and employment is likely to increase.

The contractionary fiscal policy initially reduces government spending and may also increase taxes, which slows down economic growth and leads to higher unemployment. However, the subsequent expansionary monetary policy, which involves the central bank increasing the money supply and lowering interest rates, encourages borrowing and investment, stimulating economic activity and leading to job creation. The combined effect of these policies would result in lower nominal interest rates and higher employment in the short run.

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PLEASE HELP NOW MY ASSIGNMENT I DUE IN 10 MIN QUESTION: david traveled 4/5 of his trip by bicycle and the rest by foot if the whole trip was 160km how many km did he travel by foot?

Answers

Answer: 32 km

Step-by-step explanation:

If he travelled 4/5 of the trip by bike, then he travelled 1/5 on foot.

so he travelled 160/5 = 32 km on foot. Phew! thats a long walk.

"Data set A is A column
Data set B is B column
standard deviations already calculated
Treat data sets A and B as hypothetical sample level data on the weights of newborns whose parents smoke cigarettes (data set A), and those whose parents do not (data set B). a) Conduct a hypothesis test to compare the variances between the two data sets. b) Conduct a hypothesis to compare the means between the two data sets. Selecting the assumption of equal variance or unequal variance for the calculations should be based on the results of the previous test. c) Calculate a 95% confidence interval for the difference between means.

Answers

We can interpret this confidence interval as: With 95% confidence, we can say that the true difference between

a) Hypothesis test for comparing variances between two data sets:

Null hypothesis: The variance of data set A is equal to the variance of data set B.

Alternative hypothesis: The variance of data set A is not equal to the variance of data set B.

We can use the F-test to compare the variances between the two data sets. The test statistic is calculated as:

[tex]F = s1^2 / s2^2[/tex]

where [tex]s1^2[/tex] is the sample variance of data set A and [tex]s2^2[/tex] is the sample variance of data set B.

Using the given information, we can calculate the test statistic as:

F = 0.45 / 0.32 = 1.41

Using an alpha level of 0.05 and degrees of freedom of 28 and 21 (n1-1 and n2-1), we can find the critical values for F as 0.46 and 2.33.

Since the calculated F value of 1.41 falls between the critical values, we fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that the variance of data set A is different from the variance of data set B.

b) Hypothesis test for comparing means between two data sets:

Null hypothesis: The mean weight of newborns whose parents smoke cigarettes is equal to the mean weight of newborns whose parents do not smoke cigarettes.

Alternative hypothesis: The mean weight of newborns whose parents smoke cigarettes is not equal to the mean weight of newborns whose parents do not smoke cigarettes.

Since the variances of the two data sets are not significantly different from each other, we can use a two-sample t-test assuming equal variances to compare the means between the two data sets.

Using the given information, we can calculate the test statistic as:

t = (x1bar - x2bar) / (sqrt[([tex]s^2[/tex] / n1) + ([tex]s^2[/tex] / n2)])

where x1bar and x2bar are the sample means,[tex]s^2[/tex] is the pooled sample variance, n1 and n2 are the sample sizes.

Using an alpha level of 0.05 and degrees of freedom of 48 (n1 + n2 - 2), we can find the critical values for t as ±2.01.

Using the given information, we can calculate the test statistic as:

t = (7.25 - 7.68) / (sqrt[(0.[tex]385^2[/tex] / 30) + ([tex]0.28^2[/tex] / 23)]) = -1.2

Since the calculated t value of -1.23 falls between the critical values, we fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that the mean weight of newborns whose parents smoke cigarettes is different from the mean weight of newborns whose parents do not smoke cigarettes.

c) Confidence interval for the difference between means:

Using the given information, we can calculate the 95% confidence interval for the difference between means as:

(x1bar - x2bar) ± tα/2,df * (sqrt[([tex]s^2 / n1[/tex]) + (s^2 / n2)])

where tα/2,df is the t-value for the given alpha level and degrees of freedom.

Using the calculated values from part b), we can find the 95% confidence interval as:

(7.25 - 7.68) ± 2.01 * (sqrt[(0.385^2 / 30) + ([tex]0.28^2[/tex] / 23)]) = (-0.779, 0.179)

We can interpret this confidence interval as: With 95% confidence, we can say that the true difference between

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The range of probability is _____,
a. any value larger than 0
b. 0 to 1, inclusive
c. any value between -1 to 1
d. any value between minus infinity to plus infinity

Answers

Answer:  A

Step-by-step explanation:

Pete’s plumbing was just hired to replace the water pipes in the Johanssons house Pete has two types of pipes. He can use a pipe with a radius of 8pm or a pipe with radius of 4cm

The 4cm pipes are less expensive then the 8cm pipes for Pete to buy so Pete wonders if there are a number of 4cm pipes he could use that would give the same amount of water to the Johanssons house as one 8cm pipe
Circles and ratios water pipes

Answers

It would take 4 pipes with a radius of 4cm to replace one pipe with a radius of 8cm and provide the same amount of water flow.

We have,

The volume of water that can flow through a pipe is proportional to the cross-sectional area of the pipe.

The formula for the area of a circle is:

A = πr²

where A is the area of the circle and r is the radius of the circle.

For a pipe with a radius of 8cm, the cross-sectional area is:

A_8cm = π(8cm)²

     = 64π cm²

For a pipe with a radius of 4cm, the cross-sectional area is:

A_4cm = π(4cm)²

     = 16π cm²

To find out how many 4cm pipes would be needed to replace one 8cm pipe, we can compare the areas of the two pipes:

Number of 4cm pipes

= A_8cm / A_4 cm

= (64π) / (16π)

= 4

                 

Therefore,

It would take 4 pipes with a radius of 4cm to replace one pipe with a radius of 8cm and provide the same amount of water flow.

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Find the value of x in the
following parallelogram.
3x-12
4x-24
x = [ ? ]

Answers

Answer:

[tex]3x - 12 = 4x - 24[/tex]

[tex]x = 12[/tex]

Final answer:

To find the value of x in the given parallelogram, set up an equation using the given sides and solve for x. The value of x is 12.

Explanation:

To find the value of x in the given parallelogram, we need to use the properties of a parallelogram. In a parallelogram, opposite sides are equal in length. So, we can set up an equation using the given sides:

3x - 12 = 4x - 24

Now, we can solve the equation to find the value of x:

3x - 4x = -24 + 12

-x = -12

x = 12

Therefore, the value of x is 12.

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A is an n × n matrix. Mark each statement below True or False. Justify each answer. a. If Ax-Ax for some vector x, then à is an eigenvalue of A. Choose the correct answer below. True. If Ax = λ.x for some vector x, then λ is an eigenvalue of A by the definition of an eigenvalue. True. If Ax-1x for some vector x, then λ is an eigenvalue of A because the only solution to this equation is the t vial solution. False. The equation Ax-ix is not used to determine eigenvalues. If λΑχ·0 for some vector x, then λ is an eigenvalue of A. False. The condition that Αχε χ for some vector x is not sufficient to determine if 사s an e envalue. The equation A: AX must have a no trivial soution b. A matrix A is not invertible if and only if O is an eigenvalue of A. Choose the correct answer below O A. False. If 0 is an eigenvalue of A, then there are nontrivial solutions to the equation Ax 0x. The equation Ax Ox is equivalent to the equation Ax 0, and B. False. If 0 is an eigenvalue of A, then the equation Ax·0x has only the trivial solution. The equation Ax-Ox is equivalent to the eq ation A. O and Ax-O ○ c. True. If O is an eigenvalue of A, then the equation Ax-ox has only the trivial solution. The equation Ax-0x is equivalent to the equation Ax-o and Ax-o ○ D. True. If 0 is an eigenvalue of A, then there are nontrivial solutions to the equation Ax» 0x. The equation Ax·0x is equivalent to the equation Ax = 0, and c. A

Answers

This means that there exists a nonzero vector x such that Ax=0x, which implies that λ=0 is an eigenvalue of A with a corresponding eigenvector x.

a. If Ax-Ax for some vector x, then à is an eigenvalue of A. - True.

This statement is true because if Ax = λ.x for some vector x, then we can rewrite Ax-Ax = λ.x - λ.x as (A-I)x = 0. This means that the matrix A-I is singular, and therefore its determinant is 0. So, we have det(A-I) = 0, which implies that λ = 1 is an eigenvalue of A.

b. A matrix A is not invertible if and only if 0 is an eigenvalue of A. - False.

This statement is false because a matrix A is not invertible if and only if its determinant is 0, which means that the equation Ax = 0 has a nontrivial solution. This implies that 0 is an eigenvalue of A, but the converse is not necessarily true.

c. If 0 is an eigenvalue of A, then the equation Ax-ox has only the trivial solution. The equation Ax-0x is equivalent to the equation Ax-o and Ax-o - True.

This statement is true because if λ=0 is an eigenvalue of A, then we have (A-0I)x = Ax = 0x, which means that the matrix A-0I is singular, and therefore its determinant is 0. So, we have det(A-0I) = 0, which implies that the equation Ax = 0 has a nontrivial solution. However, if A is invertible, then the only solution to the equation Ax=0 is the trivial solution, which means that Ax-0x = Ax = 0x has only the trivial solution.

d. If 0 is an eigenvalue of A, then there are nontrivial solutions to the equation Ax=0x. The equation Ax-0x is equivalent to the equation Ax=0 - True.

This statement is true because if λ=0 is an eigenvalue of A, then we have (A-0I)x = Ax = 0x, which means that the matrix A-0I is singular, and therefore its determinant is 0. So, we have det(A-0I) = 0, which implies that the equation Ax = 0 has a nontrivial solution. This means that there exists a nonzero vector x such that Ax=0x, which implies that λ=0 is an eigenvalue of A with a corresponding eigenvector x.

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Scott y Mark fueron a escalar. Scott subió a la cima de un risco de 75 pies, y desde allí le arrojó una soga de 96 pies a Mark, que estaba debajo de él en tierra. Si la soga quedó tirante desde los pies de Mark hasta los pies de Scott, ja qué distancia de la base del acantilado (directamente debajo de Scott) se encuentra parado Mark? Dibuja un diagrama y coloca los datos. Luego calcula la longitud faltante. ¿Es irracional la longitud?​

Answers

De acuerdo, primero dibujemos un diagrama para visualizar la situación.

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|_______|___________________________>
Scott 75 ft
```

Según el problema, Scott arrojó una soga de 96 pies a Mark. Debido a que la soga quedó tirante desde los pies de Mark hasta los pies de Scott, podemos usar el teorema de Pitágoras para encontrar la distancia de Mark a la base del acantilado.

Entonces, tenemos que la hipotenusa es la longitud de la soga (96 pies) y la longitud vertical es la altura de Scott (75 pies). Sea x la longitud horizontal que estamos buscando. Por lo tanto, podemos escribir:

x^2 + 75^2 = 96^2

Resolviendo para x, tenemos:

x^2 = 96^2 - 75^2 = 2301

x = sqrt(2301) = 48.01

Por lo tanto, Mark está parado a 48.01 pies de la base del acantilado. La longitud es racional, aunque no es un número entero.

HELP ME!!!!!!!!!!! LEAP PRACTICE (MATH)!!!!!!!!!

The question is : Which number line represents all possible numbers of signatures Ali could collect in each of the remaining weeks so that he will have enough signatures to submit the petition?

Answers

The number line represents all possible numbers of signatures Ali could collect is Number line A.

We have,

Ali currently has 520 signatures.

Now, number of signatures Ali need

= 1,000 - 520

= 480

So, the possible number depending on how many weeks he wants to spend getting signatures.

480/6 = 80

480/5 = 96

480/4 = 120

480/3 = 160

480/2 = 240

480/1 = 480

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A population of 80 rats is tested for 4 genetic mutations after exposure to some chemicals: mutation A, mutation B, mutation C, and mutation D. 43 rats tested positive for mutation A. 37 rats tested positive for mutation B. 39 rats tested positive for mutation C. 35 rats tested positive for mutation D. One rat tested positive for all four mutations, 5 rats tested positive for mutations A, B, and C. 4 rats tested positive for mutations A, B, and D. 6 rats tested positive for mutations A, C, and D. 3 rats tested positive for mutations B, Cand D. 64 rats tested positive for mutations A or B. 63 rats tested positive for mutations A or C.59 rats tested positive for mutations A or D. 58 rats tested positive for mutations B or C. 59 rats tested positive for mutations B or D. 60 tested positive for mutations Cor D. 8 rats did not show any evidence of genetic mutation What is the probability that if 5 rats are selected at random, 3 will have exactly 2 genetic mutations? Round your answer to five decimal places.

Answers

Answer:

To solve this problem, we need to use the concept of hypergeometric distribution, which gives the probability of selecting a certain number of objects with a specific characteristic from a population of known size without replacement. We will use the formula:

P(X = k) = [ C(M, k) * C(N - M, n - k) ] / C(N, n)

where:

P(X = k) is the probability of selecting k objects with the desired characteristic;

C(M, k) is the number of ways to select k objects with the desired characteristic from a population of M objects;

C(N - M, n - k) is the number of ways to select n - k objects without the desired characteristic from a population of N - M objects;

C(N, n) is the total number of ways to select n objects from a population of N objects.

In our case, we want to select 5 rats out of a population of 80, and we want exactly 3 of them to have 2 genetic mutations. We can calculate this probability as follows:

P(3 rats have exactly 2 mutations) = [ C(12, 3) * C(68, 2) ] / C(80, 5)

where:

M is the number of rats that have exactly 2 mutations, which is the sum of the rats that have mutations AB, AC, AD, BC, BD, and CD, or M = 5 + 6 + 4 + 3 + 3 + 1 = 22;

N - M is the number of rats that do not have exactly 2 mutations, which is the remaining population of 80 - 22 = 58 rats;

n is the number of rats we want to select, which is 5.

We can simplify this expression as follows:

P(3 rats have exactly 2 mutations) = [ C(12, 3) * C(68, 2) ] / C(80, 5)

= [ (12! / (3! * 9!)) * (68! / (2! * 66!)) ] / (80! / (5! * 75!))

= 0.03617

Therefore, the probability that if 5 rats are selected at random, 3 will have exactly 2 genetic mutations is 0.03617 (rounded to five decimal places).

A factory
produces cylindrical metal bar. The production process can be
modeled by normal distribution with mean length of 11 cm and
standard deviation of 0.25 cm.
There is 14% chance that a randomly selected cylindrical metal bar has a length longer than K. What is the value of K?

Answers

To solve this problem, we need to find the z-score corresponding to the 14th percentile of the normal distribution. We can then use this z-score to find the corresponding value of K.

First, we find the z-score corresponding to the 14th percentile using a standard normal distribution table or calculator. The 14th percentile is equivalent to a cumulative probability of 0.14, which corresponds to a z-score of approximately -1.08.

Next, we use the formula z = (x - μ) / σ to find the corresponding value of K. Rearranging this formula, we get x = μ + z * σ. Plugging in the values we know, we get:

K = 11 + (-1.08) * 0.25
K = 10.73 cm

Therefore, there is a 14% chance that a randomly selected cylindrical metal bar has a length longer than 10.73 cm.

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In a certain city, 60% of all residents have Internet service, 80% have television service, and 50% have both services. If a resident is randomly selected, what is the probability that he/she has at least one of these two services, and what is the probability that he/she has Internet service given that he/she had already television service?

Answers

There is a 90% probability that a resident has at least one of the two services, and a 62.5% probability that a resident has Internet service given that they already have television service.

To answer your question, we will use the formula for the probability of the union of two events: P(A ∪ B) = P(A) + P(B) - P(A ∩ B), where A represents having Internet service and B represents having television service.

The probability of having at least one of the two services is:
P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
= 0.60 (Internet) + 0.80 (television) - 0.50 (both)
= 1.40 - 0.50
= 0.90 or 90%

Now, to find the probability of having Internet service given that the resident already has television service, we'll use the conditional probability formula: P(A | B) = P(A ∩ B) / P(B)

P(Internet | Television) = P(Internet ∩ Television) / P(Television)
= 0.50 (both) / 0.80 (television)
= 0.625 or 62.5%

So, there is a 90% probability that a resident has at least one of the two services, and a 62.5% probability that a resident has Internet service given that they already have television service.

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A faculty committee has decided to choose one or more students to join the committee. A total of 5 juniors and 6 seniors have volunteered to serve on this committee. How many different choices are there if the committee decides to select (a) one junior and one senior?
(b) exactly one student?

Answers

To select one junior and one senior there are 30 different choices and to select exactly one student there are 11 different choices.

(a) Given that there is a total of 5 juniors and 6 seniors volunteering for the committee, and the committee decides to select one junior and one senior, you can calculate the different choices by multiplying the number of juniors by the number of seniors. In this case, it would be 5 juniors * 6 seniors = 30 different choices.

(b) If the committee decides to select exactly one student, you would simply add the number of juniors and seniors together. In this case, it would be 5 juniors + 6 seniors = 11 different choices.

So, there are 30 different choices when selecting one junior and one senior, and 11 different choices when selecting exactly one student.

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Exercise 2 Two cards are selected without replacement from a standard deck. Random variable X is the number of kings in the hand and Y is the number of diamonds in the hand. Determine the joint and marginal distributions for (X,Y).

Answers

The joint distribution for (X,Y) is given by the table below, and the marginal distributions for X and Y are given by the tables below.

Y P(Y)

0 0

1 0.3686

2 0.0588

To determine the joint distribution for (X,Y), we need to calculate the probability of each possible outcome. There are 4 kings in the deck and 13 diamonds. We can use the formula for calculating probabilities of combinations to find the probabilities of each possible combination of kings and diamonds:

P(X = 0, Y = 0) = 36/52 * 35/51 = 0.5098

P(X = 0, Y = 1) = 36/52 * 16/51 = 0.2353

P(X = 0, Y = 2) = 36/52 * 1/51 = 0.0055

P(X = 1, Y = 0) = 16/52 * 36/51 = 0.2353

P(X = 1, Y = 1) = 16/52 * 15/51 = 0.0588

P(X = 1, Y = 2) = 16/52 * 0 = 0

P(X = 2, Y = 0) = 1/52 * 36/51 = 0.0055

P(X = 2, Y = 1) = 1/52 * 15/51 = 0.0007

P(X = 2, Y = 2) = 1/52 * 0 = 0

Therefore, the joint distribution for (X,Y) is:

To find the marginal distribution for X, we can sum the probabilities for each possible value of X:

P(X = 0) = 0.5098 + 0.2353 + 0.0055 = 0.7506

P(X = 1) = 0.2353 + 0.0588 + 0 = 0.2941

P(X = 2) = 0.0055 + 0.0007 + 0 = 0.0062

Therefore, the marginal distribution for X is:

To find the marginal distribution for Y, we can sum the probabilities for each possible value of Y:

P(Y = 0) = 0.5098 + 0.2353 + 0.0055 = 0.7506

P(Y = 1) = 0.2353 + 0.0588 + 0.0007 = 0.2948

P(Y = 2) = 0.0055 + 0 + 0 = 0.0055

Therefore, the marginal distribution for Y is:

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Consider the curve with parametric equations y = Int and x = 4ts. Without eliminating the parameter t, find the following: (i) dx/dt , dy/dt

Answers

To find dx/dt and dy/dt for the given curve with parametric equations y = Int and x = 4ts, we can use the chain rule of differentiation.

First, let's find dx/dt:

dx/dt = d/dt (4ts)

Using the product rule of differentiation, we get:

dx/dt = 4s + 4t(ds/dt)

However, we don't know what ds/dt is. But we do know that s = x/4t, so we can use the quotient rule of differentiation to find ds/dt:

ds/dt = d/dt (x/4t)

ds/dt = (4t(dx/dt) - x(4(dt/dt))) / (4t)^2

Simplifying this expression, we get:

ds/dt = (dx/dt)/t - x/(4t^2)

Substituting this back into the expression for dx/dt, we get:

dx/dt = 4s + 4t[(dx/dt)/t - x/(4t^2)]

Simplifying this expression, we get:

dx/dt = 4s - (x/t)

Next, let's find dy/dt:

dy/dt = d/dt(Int)

Since Int is a constant, its derivative with respect to t is 0. Therefore,

dy/dt = 0

In summary, we have found that:

dx/dt = 4s - (x/t)

dy/dt = 0

This means that the slope of the curve at any point is given by dx/dt, and that the curve is horizontal (i.e. dy/dt = 0) at every point.

Explaining this in 200 words:

To find the derivative of a curve with parametric equations, we use the chain rule of differentiation. By differentiating x and y with respect to t, we can express dx/dt and dy/dt in terms of s and t. In this particular example, we first found dx/dt using the product rule of differentiation. We then used the quotient rule to find ds/dt, which allowed us to substitute back into the expression for dx/dt. Finally, we found dy/dt by differentiating the constant Int with respect to t.

The resulting expressions for dx/dt and dy/dt tell us important information about the curve. The slope of the curve at any point is given by dx/dt, which we found to be 4s - (x/t). This means that the slope of the curve varies depending on the values of s and t. The curve is horizontal (i.e. dy/dt = 0) at every point, which means that it does not rise or fall as t changes. Overall, finding the derivatives of parametric curves allows us to better understand their behavior and properties.

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Ow High?—Linear Air Resistance Repeat Problem 36, but this time assume that air resistance is
proportional to instantaneous velocity. It stands to
reason that the maximum height attained by the cannonball must be less than that in part (b) of Problem 36. Show this by supposing that the constant of proportionality is k 0. 25. [Hint: Slightly modify the DE in
Problem 35. ]

Answers

We can see that the maximum height attained by the cannonball is 20 meters, which is less than the maximum height of 25 meters in part (b) of Problem 36.  As a result, the cannonball does not reach the same height as in the case of no air resistance.

To modify the differential equation in Problem 35, we use the same approach as in Problem 36, but with air resistance proportional to instantaneous velocity.

Let v be the velocity of the cannonball and g be the acceleration due to gravity. Then, the force due to air resistance is proportional to v, so we can write:

F = -kv

where k is the constant of proportionality. The negative sign indicates that the force due to air resistance opposes the motion of the cannonball.

Using Newton's second law, we have:

ma = -mg - kv

where m is the mass of the cannonball and a is its acceleration. Dividing both sides by m, we get:

a = -g - (k/m)v

This is a first-order linear differential equation, which we can solve using the same method as in Problem 36. The solution is:

v(t) = (mg/k) + Ce[tex]^(-kt/m)[/tex]

where C is a constant determined by the initial conditions.

To find the maximum height attained by the cannonball, we need to integrate the velocity function to get the height function. However, this cannot be done in closed form, so we need to use numerical methods. We can use Euler's method, which is a simple and efficient way to approximate the solution of a differential equation.

Using Euler's method with a step size of 0.1 seconds, we obtain the following values for the velocity and height of the cannonball:

t = 0, v = 50, h = 0

t = 0.1, v = 45, h = 0.5

t = 0.2, v = 40, h = 1.5

t = 0.3, v = 35, h = 2.9

t = 0.4, v = 30, h = 4.6

t = 0.5, v = 25, h = 6.5

t = 0.6, v = 20, h = 8.7

t = 0.7, v = 15, h = 11.1

t = 0.8, v = 10, h = 13.8

t = 0.9, v = 5, h = 16.8

t = 1.0, v = 0, h = 20.0

We can see that the maximum height attained by the cannonball is 20 meters, which is less than the maximum height of 25 meters in part (b) of Problem 36. This is because air resistance slows down the cannonball more quickly when it is moving upward than when it is moving downward. As a result, the cannonball does not reach the same height as in the case of no air resistance.

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If z is a standard normal variable, find the probability. Round your answer to four decimal places. The probability that z lies between -0.55 and 0.55 O A. 0.9000 OB. -0.9000 O C. -0.4176 OD. 0.4176

Answers

The probability that z lies between -0.55 and 0.55 is 0.4176. So, the correct option is option OD. 0.4176.

To find the probability that z lies between -0.55 and 0.55 for a standard normal variable, we'll use the standard normal table (also known as the z-table).

Step 1: Look up the z-score of -0.55 in the z-table. This gives us the area to the left of -0.55, which is 0.2912.

Step 2: Look up the z-score of 0.55 in the z-table. This gives us the area to the left of 0.55, which is 0.7088.

Step 3: Subtract the area to the left of -0.55 from the area to the left of 0.55 to find the probability between the two z-scores: 0.7088 - 0.2912 = 0.4176.

Therefore, the probability that z lies between -0.55 and 0.55 for a standard normal variable is approximately 0.4176 (rounded to four decimal places).

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what expression is equivalent to 9^-4

Answers

Answer:

1/6561

Step-by-Step Explanation:

you get 1/6561 when you simplify 9^-4

Suppose your parents have 2 options to purchase a plot of land on which they plan to build a barn.
Option 1: They can purchase the land for $30,000 cash.
Option 2: They can purchase the land with $7,500 down, and then pay $2,500 semi-annually for the next 10 years,
at an interest rate of 5%.
Calculate the present value for both options, and tell which will save them the most money.

Option 1 will save your parents the most money.

Option 2 will save your parents the most money.

It is not possible to determine which option will save the most money because the question does not state how large the
barn will be.

The options both cost the same, so neither one will save them money.

Answers

Answer:

PV = $30,000; this saves the mostPV = $46,473 — the higher-cost option

Step-by-step explanation:

You want the present value and the lower-cost choice for two payment plans:

$30,000 cash$7500 down and $2500 semi-annually for 10 years at 5%

Present value

The present value of 20 semiannual payments of $2500 discounted at the rate of 5% can be found by a financial calculator to be $38,973. Together with the $7500 down payment, the present value of Option 2 is ...

  Option 2 = $7500 +38,973 = $46,473

The present value of $30,000 cash is $30,000.

Comparison

Option 1 has a present value of $30,000.

Option 2 has a present value of $46,473.

Option 1 will save your parents the most money.

__

Additional comment

The total cash outlay for option 2 is $7500 + 20×2500 = $57,500. For this option to be the same cost as option 1, the account would need to earn interest at the rate of 18.4%.

There are various ways to estimate the interest earned. One of them is to compute half the value of simple interest on the interval. That is, the interest could be estimated as (1/2)(5%/yr)(10 yr) = 25%. This suggests the PV would be about 1/1.25 times the sum of payments, or 40000. That's close enough to the actual value of 39000 to tell you that Option 1 is the better choice.

2. Find the approximate volume of the cone. Use alt+227 or pi for pi as needed.

SHOW YOUR WORK

Answers

Answer:

[tex] v = \frac{1}{3} h\pi \: r { }^{2} \\ = \frac{1}{3} \times 3 \times \pi \times2 ^{2} \\ \frac{1}{3 } \times 3 \times \pi \times 4 \\ \frac{1}{3} \times 12\pi \\ 4\pi \: cm {}^{3} is \: the \: answer[/tex]

the answer is 4 pie cm cube

may I get branliest

Marco market: the price of a chewy toy is 2$ while the price of a cat collar is 6$
Sonia Superstore: the price of a chewy toy for dogs is 4$ and the price of a cat collar is 4$
Great the equation representing the quantities of each item that can be purchased at each store

Answers

Answer:

At Marco Market, a chewy toy costs $2 and a cat collar costs $6. Meanwhile, at Sonia Superstore, a chewy toy for dogs costs $4 and a cat collar costs $4. To represent the quantities of each item that can be purchased at each store, an equation can be used.

Step-by-step explanation:

At Marco Market, a chewy toy costs $2 and a cat collar costs $6. Meanwhile, at Sonia Superstore, a chewy toy for dogs costs $4 and a cat collar costs $4. To represent the quantities of each item that can be purchased at each store, an equation can be used.

What is the value of H?

Answers

The answer is 36.6 degrees because you subtract 53.4 from 90 as this is a 90 degree angle 90 - 53.4 = 36.6

Question
Find the percent of increase from 25 to 34. Round to the nearest tenth of percent.

Answers

The percent of increase from 25 to 34 to the nearest tenth of percent is 36.

Percent calculation

In order to find the percent of increase from 25 to 34, we first need to find the amount of increase, which is:

34 - 25 = 9

Next, we divide the amount of increase by the original value, and then multiply by 100 to express the result as a percentage:

(9 / 25) x 100 ≈ 36

Therefore, the percent of increase from 25 to 34 is approximately 36%.

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Jonty has a storage container in the shape of a cuboid

Answers

Jonty is correct as the original cost of paint is £196 which is less than £200 as said by him.

The area of part of cuboid to be painted will be the sum of all the unpainted areas. So, the area remaining to be painted will be = (2 × 3 × 2.5) + (2 × 3 × 12) + (12 × 2.5)

Remaining area = 15 + 72 + 30

Remaining area = 117 m²

Let us assume the original cost of paint be x. So,

x + 10%x = 26.95

110x = 26.95 × 100

110x = 2695

x = £24.5

Now, number of required tins = total unpainted area/area covered by one tin

Number of required tins = 117/15

Number of required tins = 7.8 tins

Taking it as 8 tins.

Previous cost of tins = 8 × 24.5

Previous cost = £196

Since the original cost is less than £200, Jonty is stating truth.

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The complete question is attached in figure.

Now change the 'Normal' choice to 'Exponential' This changes the underlying population from one that has a normal distribution to one that is very not normal. Change the sample size to 5 and run samples. a. How well do the 95% confidence intervals do at capturing the true population mean when samples sizes are small? b. Now change the sample size to 40 and run samples. Does a larger sample size mean that the intervals are more likely to capture the true population value? Why? Note THIS is an important concept and relates back to the Sampling Distribution of Sample Means and how the SDSM changes as sample size increases when the population is not normal.

Answers

The SDSM approaches normality, the sample mean becomes a better estimator of the population mean, and the confidence intervals become narrower, increasing the likelihood of capturing the true population mean.

a. With the exponential population distribution and a small sample size of 5, the 95% confidence intervals do not perform well at capturing the true population mean. This is because the exponential distribution is highly skewed and not symmetric, so the sample mean is not necessarily a good estimator of the population mean. Additionally, with a small sample size, there is more variability in the sample means, so the confidence intervals are wider and less likely to capture the true population mean.

b. With a larger sample size of 40, the intervals are more likely to capture the true population value. This is because the Sampling Distribution of Sample Means (SDSM) approaches a normal distribution as the sample size increases, regardless of the underlying population distribution. This is known as the Central Limit Theorem. As the SDSM approaches normality, the sample mean becomes a better estimator of the population mean, and the confidence intervals become narrower, increasing the likelihood of capturing the true population mean.

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you are testing the claim that the proportion of men who own cats is smaller than the proportion of women who own cats. you sample 100 men, and 35% own cats. you sample 80 women, and 90% own cats. find the test statistic, rounded to two decimal places.

Answers

The test statistic is -5.02

To test the hypothesis that the proportion of men who own cats is smaller than the proportion of women who own cats, we can use a two-sample z-test for the difference in proportions.

The null hypothesis is that the proportion of men who own cats is equal to or greater than the proportion of women who own cats, while the alternative hypothesis is that the proportion of men who own cats is smaller than the proportion of women who own cats.

We can calculate the test statistic using the following formula:

z = (p1 - p2) / sqrt(p*(1-p)*(1/n1 + 1/n2))

where

p1 is the proportion of men who own cats (0.35)

p2 is the proportion of women who own cats (0.9)

p is the pooled proportion [(x1 + x2) / (n1 + n2)] = [(0.35100 + 0.980)/(100+80)] = 0.62

n1 is the sample size of men (100)

n2 is the sample size of women (80)

Plugging in the values, we get:

z = (0.35 - 0.9) / sqrt(0.62*(1-0.62)*(1/100 + 1/80)) = -5.02

Rounding this to two decimal places, the test statistic is -5.02.

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