Answer:
Scalar quantity Vector quantity
Pressure Force
Energy Momentum
Speed Weight
Explanation:
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what most influenced transcendentalism way of thinking
Answer:
Transcendentalism was greatly influenced by various philosophical and religious ideas, including:
German Idealism: Transcendentalism was heavily influenced by the works of German philosophers such as Immanuel Kant and Friedrich Schelling, who stressed the importance of the individual and the power of the human mind to comprehend the world.
Romanticism: Transcendentalists also drew on the ideas of the Romantic movement, which emphasized the importance of emotion, intuition, and imagination in the human experience.
American Romanticism: Transcendentalism was a product of the American Romantic movement, which rejected the materialism and commercialism of American society in the 19th century and sought to elevate the individual, nature, and spiritual experience.
Eastern philosophy and religion: Transcendentalists were influenced by the teachings of Hinduism and Buddhism, particularly the concept of transcendence, which emphasizes the individual's ability to transcend the limitations of the material world and connect with a higher spiritual reality.
Overall, transcendentalism was shaped by a diverse range of ideas and thinkers, reflecting its emphasis on individualism, intuition, and spiritual experience.
How much energy is required to change a 42 g ice cube from ice at −13◦C to steam at 114◦C? The specific heat of ice is 2090 J/kg · ◦ C, the specific heat of water is 4186 J/kg · ◦ C, the specific heat of stream is 2010 J/kg · ◦ C, the heat of fusion is 3.33 × 105 J/kg, and the heat of vaporization is 2.26 × 106 J/kg. Answer in units of J.
The energy required to change a 42 g ice cube from ice at −13°C to steam at 114°C will be 129964.96 J.
To calculate the energy required to change a 42 g ice cube from ice at −13°C to steam at 114°C, we need to consider the following processes:
Heating the ice from −13°C to 0°C
Melting the ice at 0°C
Heating the water from 0°C to 100°C
Boiling the water at 100°C
Heating the steam from 100°C to 114°C
calculate the energy required for each step:
Heating the ice from −13°C to 0°C:
The specific heat of ice is 2090 J/kg · ◦C. We have 42 g of ice, which is 0.042 kg. The temperature difference is 0◦C - (-13◦C) = 13◦C.
The energy required to heat the ice is:
Q₁ = (0.042 kg) x (2090 J/kg°C) x (13°C) = 1151.04 J
Melting the ice at 0°C:
The heat of fusion of ice is 3.33 × 105 J/kg. The energy required to melt the ice is:
Q₂ = (0.042 kg) x (3.33 × 105 J/kg) = 14046 J
Heating the water from 0°C to 100°C:
The specific heat of water is 4186 J/kg°C. The mass of water is still 42 g. The temperature difference is 100°C - 0°C = 100°C.
The energy required to heat the water is:
Q3 = (0.042 kg) x (4186 J/kg°C) x (100°C) = 17607.72 J
Boiling the water at 100°C:
The heat of vaporization of water is 2.26 × 10 J/kg. The energy required to boil the water is:
Q₄ = (0.042 kg) x (2.26 × 106 J/kg) = 94920 J
Heating the steam from 100°C to 114°C:
The specific heat of steam is 2010 J/kg°C. The mass of steam is the same as the mass of water, which is 0.042 kg. The temperature difference is 114°C - 100°C = 14°C.
The energy required to heat the steam is:
Q₅ = (0.042 kg) x (2010 J/kg°C) x (14°C) = 1239.24 J
The total energy required is the sum of all the energies:
Qtotal = Q₁ + Q₂ + Q₃ + Q₄ + Q₅ = 129964.96 J
Therefore, the energy required to change a 42 g ice cube from ice at −13°C to steam at 114°C is 129964.96 J.
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A rock is thrown straight up with an initial speed of 22 m/s.
A. Graph the vertical position, velocity, and acceleration of the rock on the axes provided.
B. Draw a motion map for the trip.
C. How long will it be in the air before it returns to the thrower?
The rock will be in the air for 4.48s before it returns to the thrower.
Initial velocity of the rock, u = 22 m/s
Vertical acceleration of the rock, a(y) = -9.8 m/s²
Vertical displacement, Sy = 0
Applying equations of motion,
Sy = ut + 1/2 a(y)t²
0 = 22t - 4.9t²
Time,
t = 22/4.9
t = 4.48 s
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Attaching the image file here.
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C. If the speed of the wave is 25 m/s, what is the wavelength of the wave? Show data
listing, equation, substitution leading to the answer for full credit.
We are given:
Frequency of the wave = 10 Hz
Speed of the wave = 25 m/s
We can use the formula:
speed = frequency x wavelength
Rearranging the formula, we get:
wavelength = speed / frequency
Substituting the given values, we get:
wavelength = 25 m/s / 10 Hz
wavelength = 2.5 m
Therefore, the wavelength of the wave is 2.5 m.
A car starts 200 m west and moved with constant velocity of 15 m/s toward the east where will the car be 10 minutes later
An ostrich left its nest 77 seconds after a rainstorm and is now running at 3.2meterspersecond to the west. At this velocity, how much time will it take the ostrich to run 240meters?
Answer:
75 seconds
Explanation:
distance = speed x time
Rearranging the formula to solve for time:
time = distance / speed
time = 240 m / 3.2 m/s
time = 75 s
Which factors directly affect the magnetic force produced by an electromagnet?
Answer:
The number of turns of wire wound around the coil, and. The amount of current flowing through the wire
7. What do the following scientists study:
a. Geologists -
b. Zoologists -
c. Anthropologists -
d. Botanists -
e. Chemists -
f. Physicists -
on line papper
These scientists are known to study different aspects of science. The study they engage are;
What do scientists studya. Geologists - study the physical structure and composition of the Earth, including rocks, minerals, and natural resources.
b. Zoologists - study animals, their behavior, physiology, evolution, and distribution.
c. Anthropologists - study human societies, cultures, and behavior across time and space.
d. Botanists - study plants, their physiology, structure, ecology, and evolution.
e. Chemists - study the composition, properties, and behavior of matter and the chemical changes it undergoes.
f. Physicists - study the fundamental principles that govern the behavior of matter and energy in the universe, including mechanics, thermodynamics, electromagnetism, quantum mechanics, and relativity.
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18. A European sports car dealer claims that his car will accelerate at a constant rate from rest to 100 km/hr in 8.00 s. If so, what is the acceleration?
a. 3.47 m/s²
b. 6.82 m/s²
c. 11.4 m/s²
d. 17.4 m/s²
The acceleration of a sports car is (a) 3.47 m/s² when it goes from 0 to 100 km/hr in 8.00 s.
Define acceleration ?
Acceleration is the rate of change of velocity with respect to time. It is a vector quantity, which means that it has both magnitude (a numerical value) and direction (either positive or negative).
First, we need to convert the final velocity from km/hr to m/s, since the SI unit of acceleration is m/s²:
100 km/hr * (1000 m/km) / (60 s/hr) ≈ 27.78 m/s
Using the formula for acceleration, which relates acceleration, final velocity, initial velocity, and time:
acceleration = (final velocity - initial velocity) / time
where initial velocity is 0 since the car starts from rest, we can plug in the values given in the problem:
acceleration = (27.78 m/s - 0 m/s) / 8.00 s ≈ 3.47 m/s²
Therefore, the answer is (a) 3.47 m/s².
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The drag force on a sphere of radius 2 cm that falls through a fluid with speed 10 cm/s is 8 N. What is the drag force on a sphere of radius 4 cm that falls through the same fluid with a speed of 5 cm/s?
Answer:
0.10 N
Explanation:
The drag force can be expressed using the following formula:
F = 1/2 * rho * A * Cd * v^2
Let's calculate the cross-sectional area of the sphere:
A1 = pi * r1^2
A1 = pi * (0.02 m)^2
A1 = 0.00126 m^2
Converting the speed to meters per second:
v1 = 0.1 m/s
Now we can use the formula to solve for the density times the drag coefficient:
rho * Cd = 2 * F / (A1 * v1^2)
rho * Cd = 2 * 8 N / (0.00126 m^2 * (0.1 m/s)^2)
rho * Cd ≈ 1.592 kg/m
For the second sphere with a radius of 4 cm and a speed of 5 cm/s, we can calculate the cross-sectional area and the speed in the same way:
A2 = pi * r2^2
A2 = pi * (0.04 m)^2
A2 = 0.00502 m^2
v2 = 0.05 m/s
Using the same value of the density times the drag coefficient:
F2 = 1/2 * rho * Cd * A2 * v2^2
F2 = 1/2 * (1.592 kg/m) * 0.00502 m^2 * (0.05 m/s)^2
F2 ≈ 0.10 N
A mass is attached to the end of a spring and set into oscillation on a horizontal frictionless surface by releasing it from a stretched position. The position of the mass at any time is described by x = (7.8 cm)cos[2t/(3.98 s)]. Determine the following.
(c) first time the mass is at the position
x = 0
(d) first time the mass is at the site of maximum compression of the spring
Answer:
The frequency of the wave is 4.65 Hz.
The period of the motion is 0.22 s.
The amplitude of the wave is 3.9 cm.
The time when the object reaches 2.6 cm is 0.025 s.
The given parameters;
wave equation,
The frequency of the wave is calculated as follows;
The period of the motion is calculated as follows;
The amplitude of the wave is obtained by comparing the given equation with general wave equation;
Amplitude, A = 3.9 cm
The time when the object reaches 2.6 cm is calculated as follows;
Explanation:
By comparing the preceding equation with the general wave equation, the wave's amplitude is determined to be A = 3.9 cm when the mass is at the location of the spring's greatest compression. 1.2s
What is the straightforward meaning of mass?The quantity of matter of a particle or object is represented by the dimensionless quantity mass (symbolised m). The kilogramme (kg) is the accepted unit of mass on the International System (SI).
How is mass determined?The quantity of matter on an item is its mass. Scientists frequently use balances to quantify mass. Using an electronic balance or a beam balance, one may directly determine the mass of solids.
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Which example represents a class 2 lever? (1 point)
O salad tongs picking up salad
O tweezers plucking hairs
O a car door being opened and shut
a screwdriver opening a paint can
The example that represents a class 2 lever is: D. a screwdriver opening a paint can.
Which example represents a class 2 lever?The load is situated in a class 2 lever halfway between the fulcrum and the effort. The screwdriver's resting place against the paint can's rim serves as the fulcrum in this scenario.
The paint can's lid serves as the load, and the force exerted by the hand on the screwdriver's handle serves as the effort. A class 2 lever can be identified by the load being situated between the fulcrum and the effort.
Tweezers, salad tongs, and opening and closing a car door are not examples of class 2 levers. Class 1 levers include things like tweezers and salad tongs, whereas class 3 levers include things like car doors that open and close.
Therefore the correct option is D.
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A block of mass M=5.0 kg is hanging at equilibrium from an ideal spring with spring constant k=250 N/m
a) on the dot below, which represents the block, draw and label the forces (not components) that act on the block. Each force must be represented by distinct arrow, starting on, and pointing away from, the dot.
The block is pulled 0.15 m below is equilibrium position and released from rest.
b) determine the maximum displacement of the mass from equilibrium
c) calculate the elastic potential energy of the spring, just as the block is being released
d) calculate the maximum speed, the block will have during its motion
e) calculate the displacement of the block from equilibrium when the kinetic energy of the block is equal to the elastic potential energy of the spring
The block is brought to rest at equilibrium. The block is then pulled down half the original distance.
f) will the new period for the motion of the block, be greater than, less than, or equal to the original period for the motion of the block?
The maximum displacement of the mass from equilibrium is 0.4 times the square root of the maximum height the block reaches.
What is Displacement?
In physics, displacement is the distance and direction of an object's change in position from its starting point to its end point. It is a vector quantity and is represented by a vector pointing from the object's initial position to its final position. Displacement is different from distance, which is the total path length traveled by an object and is a scalar quantity.
The elastic potential energy of the spring is given by:
U = 1/2 k[tex]x^{2}[/tex]
where U is the elastic potential energy, k is the spring constant, and x is the displacement from equilibrium.
At the instant the block is released, it is pulled 0.15 m below its equilibrium position. Therefore, the initial displacement of the block is x = 0.15 m.
Substituting the given values, we get:
U = 1/2 * 250 N/m * [tex](0.15 m)^{2}[/tex] = 1.875 J
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If a student were to measure the ball's speed at each position above, at which position would
the ball be traveling the fastest?
A
B
C
D
Answer:
The ball would be traveling fastest at point (C).
Point (D) appears to be the same height as point (C) but the ball would probably have lost some speed on rebounding,
If a student were to measure the ball's speed at each position above, at which position would
the ball be traveling the fastest?
A
B
C
D
Effects of Mobile Phones Radiation On Bio System. Biosystem.
Answer:
The potential effects of mobile phone radiation on the biosystem, including the human body, have been a topic of research and debate for many years. Mobile phones emit non-ionizing radiation, which is different from ionizing radiation (such as X-rays) that is known to cause cellular damage and increase the risk of cancer. However, there is still concern about the effects of prolonged exposure to mobile phone radiation, especially on the brain and other sensitive organs.
Studies have shown that the radiation emitted by mobile phones can cause a slight increase in temperature in the brain and other tissues near the ear. This increase in temperature can potentially cause damage to cells and tissues, although the amount of radiation emitted by mobile phones is generally considered to be too low to cause significant harm.
There is also some evidence to suggest that mobile phone radiation can affect sleep patterns, as the radiation emitted by mobile phones can interfere with the body's natural circadian rhythm. This can potentially lead to sleep disturbances and other health problems.
Other potential effects of mobile phone radiation on the biosystem include changes in blood pressure, heart rate, and brain activity. Some studies have also suggested that mobile phone radiation may affect fertility in men by reducing sperm motility and increasing DNA damage.
While there is still much debate about the potential effects of mobile phone radiation on the biosystem, most experts agree that the risk of harm is generally low. However, it is still recommended that people take precautions to limit their exposure to mobile phone radiation, such as using hands-free devices or texting instead of making phone calls.
Explanation:
Answer:
As stated by the National Cancer Institute, "there is currently no consistent evidence that non-ionizing radiation increases cancer risk in humans. The only consistently recognized biological effect of radiofrequency radiation in humans is heating."
Explanation:
good afternoon
The brick wall (of thermal conductivity 1.12 W/m · ◦ C) of a building has dimensions of 6.1 m by 13 m and is 14 cm thick. How much heat flows through the wall in a 14.3 h period when the average inside and outside temperatures are, respectively, 12◦C and 7◦C?
Answer in units of MJ.
The heat flow through the wall in a 14.3 h period would be approximately 0.491 MJ.
To calculate the heat flow through the wall, we need to use the formula:
Q = (kA×ΔT)t / d
Where Q is the heat flow, k is the thermal conductivity of the wall, A is the area of the wall, ΔT is the temperature difference across the wall, t is the time period, and d is the thickness of the wall.
First, let's calculate the area of the wall:
A = l × h = 6.1 m × 13 m = 79.3 m²
Next, let's calculate the temperature difference across the wall:
ΔT = Ti - To = 12◦C - 7◦C = 5◦C
Now, we can substitute the values into the formula:
Q = (1.12 W/m °C × 79.3 m² × 5°C × 14.3 h) / (0.14 m)
= 491,007.14 J
= 491.00714 kJ
= 0.49100714 MJ
Therefore, the heat flow through the wall in a 14.3 h period is approximately 0.491 MJ.
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in the figure below, wire AX is folded at back at P such that /AP/ is 40cm and is in parallel with PX which is 60cm long to form a parallel combination. Calculate effective resistance of the parallel combination, if the resistance per unit length of the material if the wire is 2ohms per metre.
The effective resistance of the parallel combination is 80 ohms.
What is resistance ?Resistance is the ability to oppose or reject something or someone. It is often used to describe the opposition of a force or entity such as an electrical current or a political ideology. In physics, resistance is the measure of an object's opposition to a flow of electric current. Resistance is measured in ohms and is determined by the material, geometry, and temperature of the object in question.
The effective resistance of the parallel combination can be calculated using the following formula: 1/R = 1/R1 + 1/R2Where R1, R2 are the individual resistances.In this case, R1 = 2 ohms/m x 40 cm = 80 ohms, and R2 = 2 ohms/m x 60 cm = 120 ohms.Therefore, 1/R = 1/80 + 1/120 = 0.0125,R = 1/0.0125 = 80 ohms.
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A kettle of water gets boiled. It takes 3 minutes to boil 1.0 kg of water. A student empties it
and puts in 2.0 kg of water. How long will it take to boil?
It will take 6 minutes to boil 2 kg of water in the kettle.
The given information states that the kettle takes 3 minutes to boil 1 kg of water. Therefore, to boil 2 kg of water, we can multiply the boiling time of 1 kg water by 2. So, it will take 3 x 2 = 6 minutes to boil 2 kg of water in the kettle.
The reason it takes longer to boil 2 kg of water instead of 1 kg is that more water means more energy is required to raise the temperature to the boiling point. This means that the kettle needs more time to heat up the water to the required temperature.
Therefore, after the student empties the kettle and fills it with 2 kg of water, the boiling process will take 6 minutes.
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The sum of two point charges is -15µC. They attract each other with a force of 9 x 10-2 N when kept 5m apart. Find their charges.
According to the question the two charges are -7.5 µC and -7.5 µC.
What is charges?Charges are fees or payments for services or goods. Charges can be one-time payments, recurring payments, or fees associated with using a product or service. Charges can be for products, services, or activities. Examples of charges include fees for using a credit card, fees for using a bank account, fees for renting a car, fees for using a mobile phone plan, fees for using a subscription service, fees for using a streaming service, and fees for using a gym membership.
Let the two charges be x and ( -15 - x ) µC.
According to Coulomb's law,
F = (k × x × ( -15 - x ))/r2
Where k is the Coulomb's constant,
k = 9 × 109 N × m2/C2
Given, F = 9 × 10-2 N
r = 5 m
Substituting these values in the equation,
9 × 10-2 = (9 × 109 × x × ( -15 - x ))/252
⇒ x2+ 15x - 4.5 × 10-4 = 0
Solving this equation,
x = -7.5 µC and ( -15 - x ) = -7.5 µC
Therefore, the two charges are -7.5 µC and -7.5 µC.
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a body of mass 0.5kg is taken up an inclined plane the length 10m and height 8m and then allowed to slide down to the bottom again the coefficient of friction between the body and the plane is 0.12. what is work done by gravitational force over the ground trip?,work done by applied force over the up work trip?, work done by frictional force over the round trip? and kinetic energy of the body at the end of the trip?
According to the question Work done by gravitational force over the ground trip: Gravitational force does not do any work over the ground trip since the body is not moving.
What is gravitational force?Gravitational force is the attractive force between two masses. This force is the result of the curvature of spacetime caused by the presence of mass. Gravitational force is what keeps the planets in orbits around the sun, and what keeps the moon orbiting the Earth.
Work done by applied force over the up work trip: The work done by the applied force over the up work trip is given by,
W = F * d * cosθ
= (0.5 kg * 9.81 m/s2) * 10 m * cos(45°)
= 71.4 J
Work done by frictional force over the round trip: The work done by the frictional force over the round trip is given by,
W_f = F_f * d
= (0.5 kg * 9.81 m/s2 * 0.12) * 10 m
= 5.88 J
Kinetic energy of the body at the end of the trip: The kinetic energy of the body at the end of the trip is given by,
KE = 0.5 mv2
= 0.5 * 0.5 kg * (2 * 9.81 m/s2 * 8 m)2
= 611.52 J
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Children's behavior is marked by egocentrism during the concrete-operational stage.
O True
False
Answer:
false because this is not possible that children behaviour is marked over by egocentrism children are also the tender creation of God
Question 8 (5 points)
What is indicated by the slope of an acceleration vs. time graph?
The maximum speed of the object
The total displacement of the object
The change in position of the object
The velocity of an object
The velocity of an object is indicated by the slope of an acceleration vs. time graph
What is velocity of an object?Acceleration is how much velocity changes,from the definition here, the slope of the graph tells us how quickly the object's velocity is changing over time.
To dtermine object's velocity from an acceleration vs. time graph, you would have to carry out the integration of the acceleration to get the object's velocity as a function of time.
Hence the last option is the corrcet answer here
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Answer:The velocity of an object
Use the graph to answer the following questions
1.) About how long is one half-life for Element 1? (Hint: how long does it take for half of it to decay?)
2.) A scientist finds a bone that has about 15% Element 1 left. About how old is the bone?
3.) A scientist finds a rock with about 75% of its Element 1 left. About how old is the rock?
4.) A scientist drops all his samples and is trying to figure out where to classify them. He thinks a sample is from about 9,000,000 years ago. If he tests the sample, how much of element 1 should be left in it?
5.)A paleontologist finds a skeleton that he thinks is about 1,000,000 years old. How much Element 1 should she expect to find in the sample if her guess is correct?
1. The half-life for element 1 is 3000000 years
2. The age of the bone is 8220000 years
3. The age of the rock is 1230000 years
4. The amount of element 1 remaining is 12.5%
5. The amount of element 1 she would find is 79.55%
1. How do i determine the half-life?The half-life of a substance is the time taken for half the substance to decay.
From the above diagram, we can see that the original amount of element 1 is 100 g. Thus, half of 100 is 50.
Looking at the diagram, the time for 50 g is 3000000 years.
Therefore, we can conclude that the half-life of element 1 is 3000000 years
2. How do i determine the age of the bone?First, we shall determine the number of half lives that has elapsed. This is obtained as follow:
Original amount (N₀) = 100%Amount remaining (N) = 15%Number of half-lives (n) =?2ⁿ = N₀ / N
2ⁿ = 100 / 15
2ⁿ = 6.67
Take the log of both sides
Log 2ⁿ = Log 6.67
nLog 2 = Log 6.67
Take the log of both sides
n = Log 6.67 / Log 2
n = 2.74
Finally, we shall determine the age of the bone. Details below
Half-life of element 1 (t½) = 3000000 yearsNumber of half-lives (n) = 2.74 Age of bone (t) =?t = n × t½
t = 2.74 × 3000000
t = 8220000 years
Thus, the age of the bone is 8220000 years
3. How do i determine the age of the rock?First, we shall determine the number of half lives that has elapsed. This is obtained as follow:
Original amount (N₀) = 100%Amount remaining (N) = 75%Number of half-lives (n) =?2ⁿ = N₀ / N
2ⁿ = 100 / 75
2ⁿ = 1.33
Take the log of both sides
Log 2ⁿ = Log 1.33
nLog 2 = Log 6.67
Take the log of both sides
n = Log 1.33 / Log 2
n = 0.41
Finally, we shall determine the age of the rock. Details below
Half-life of element 1 (t½) = 3000000 yearsNumber of half-lives (n) = 0.41 Age of bone (t) =?t = n × t½
t = 0.41 × 3000000
t = 1230000 years
Thus, the age of the rock is 1230000 years
4. How do i determine the amount remaining?We shall first obtain the number of half lives that will elaspe during the time. Details below:
Half-life of element 1 (t½) = 3000000 yearsTime (t) = 9000000 yearsNumber of half-lives (n) =?n = t / t½
n = 9000000 / 3000000
n = 3
Finally, we shall determine the amount remaining. Details below:
Original amount (N₀) = 100Number of half-lives (n) = 3Amount remaining (N) = ?N = N₀ / 2ⁿ
N = 100 / 2³
N = 100 / 8
N = 12.5%
Thus, we can conclude that the amount remaining is 12.5%
5. How do i know how much of the element she would find?We shall first obtain the number of half lives that will elaspe during the time. Details below:
Half-life of element 1 (t½) = 3000000 yearsTime (t) = 1000000 yearsNumber of half-lives (n) =?n = t / t½
n = 1000000 / 3000000
n = 0.33
Finally, we shall determine the amount she would find. Details below:
Original amount (N₀) = 100Number of half-lives (n) = 0.33Amount found (N) = ?N = N₀ / 2ⁿ
N = 100 / 2^0.33
N = 79.55%
Thus, the amount she would find is 79.55%
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A group of students were given a balloon, two aluminum soda cans, two Styrofoam cups, and some scotch tape and were told to design an investigation that would demonstrate the distribution of charge by induction. The students charged the balloon positively by rubbing it against a wool sweater. The balloon was then brought into contact with the first soda can (P).
After the cans P and Q are separated, will the balloon be attracted to or repelled by can Q? Why?
A
The balloon will not be attracted to or repelled by can Q because can Q will have no net charge after the cans are separated.
B
The balloon will be repelled by the soda can labelled Q after they are separated because the can labelled Q will be positively charged.
C
The balloon will be attracted to the soda can labelled Q after they are separated because both soda cans will be negatively charged.
D
The balloon will not be attracted to or repelled by can Q because when the balloon is placed in contact with either can no charge is induced on the surface of the cans.
After the cans P and Q are separated, The balloon will be repelled by the soda can labeled Q after they are separated because the can labeled Q will be positively charged.
How to get the situation of the balloonLets assume that the soda cans (P and Q) are initially neutral and in contact.
When the +ve is brough close to there would be the distribution of charge. The -ve charges that are in P would then be attracted to the area that is closer to ballon. The positives would be repeled. They would be farther
P will then have the net negative on area that faces balloon and Q with the net positive on area facing P
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what is speed sound travelling in the soil ?
The speed of sound traveling in the soil depends on the type of soil.
Speed of sound in the soilThe speed of sound traveling through soil can vary depending on the composition and density of the soil.
In general, sound travels slower through soil than through air, with typical speeds ranging from around 1000 to 4000 meters per second.
The speed of sound in the soil has been researched to have important implications for seismic surveys, which use sound waves to map underground geological structures and identify potential sources of natural resources like oil and gas.
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20. An x vs. t graph is drawn for a ball moving in one direction. The graph starts at the origin and at t = 5 s the velocity of the ball is zero. We can be positive that at t = 5 s,
a. the slope of the curve is non-zero.
b. the ball has stopped.
c. the acceleration is constant.
d. the curve is at x = 0, 1 = 0.
We can be positive that at t = 5 s, a. the slope of the curve is non-zero.
How to explain the graphIt should be noted that the graph does not indicate that the ball has stopped, as it only tells us that the velocity of the ball is zero at t=5s. Moreover, the curve is not at x=0,1=0 as this statement is not meaningful.
Therefore, the slope of the curve is non-zero. Since the velocity of the ball is zero at t=5s, the slope of the x vs. t graph must be horizontal at this point. However, it is non-zero because the slope was changing up until t=5s.
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Using a social marketing strategy, design a persuasive message to promote any health behavior of your choice
1 a Explain the difference between a transverse wave and a longitudinal
wave.
b Give one example of each.
c Draw a diagram of a transverse wave. On your diagram, mark the
wavelength and amplitude of the wave.
The difference between transverse and longitudinal waves is direction of wave motion in relative to direction of the particle motion.
Transverse vs Longitudinal Waves: What's the Difference?The particle motion in a transverse wave is only perpendicular to the wave motion but in longitudinal wave, the particle motion is parallel to the wave motion.
An example of transverse wave is a wave on a guitar string which when plucked, it vibrates back and forth in a direction perpendicular to the direction of the wave traveling along the string.
An example of a longitudinal wave is sound waves which are created when a source like speaker or a musical instrument vibrates back and forth in the same direction as the wave is traveling through the air.
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what is hookies law of elasticity
Hooke's law of elasticity is a principle in physics that states that the force required to extend or compress a spring by some distance is proportional to that distance. It is named after the English physicist Robert Hooke, who first stated the law in 1678. Hooke's law is often written as F = -kx, where F is the force applied to the spring, x is the distance it is stretched or compressed, and k is the spring constant, a measure of the stiffness of the spring.
