15.18. Find the area of the region bounded by
TC
the curve y = cosx, x=0, x= pi/
2 and x-axis.

Answer:

I think the answer is 100 because nothing greater than 200 if its rounded hope this helped if not sorry

Answer:

The answer is true

Step-by-step explanation:

[tex]\\\\\\[/tex]

Therefore

[tex]\sf{ }[/tex]

[tex]\sf{ }[/tex]

[tex]\sf{ }[/tex]

[tex]\sf{ }[/tex] [tex]\sf{ }[/tex] [tex]\sf{ }[/tex] [tex]\sf{ }[/tex] [tex]\sf{ }[/tex]

Answer:

-8x² -6x + 35

Step-by-step explanation:

A expression is given to us and we need to find out the quadratic equation . For that Multiply the two terms of the quadratic equation. The given expression is ,

Given expression :-

[tex]\rm\implies ( 2x +5)( 7 - 4x ) [/tex]

Multiply the terms :-

[tex]\rm\implies 2x ( 7 - 4x )+5(7-4x) [/tex]

Simplifying the brackets :-

[tex]\rm\implies 14x - 8x^2 + 35 - 20x [/tex]

Rearrange and simplify :-

[tex]\rm\implies -8x^2 -6x + 35 [/tex]

Therefore :-

[tex]\rm\implies\boxed{ \rm Quadratic\ Equation \ = -8x^2 -6x + 35} [/tex]

Answer:

0.2917 = 29.17% probability that a randomly selected female student on campus will have served a mission.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question:

1200 female students, out of them, 350 have served a mission. So

[tex]p = \frac{350}{1200} = 0.2917[/tex]

0.2917 = 29.17% probability that a randomly selected female student on campus will have served a mission.

Answer:

Step-by-step explanation:

[tex]4(x+y)^{2} - 9(x-y)^{2}=4[x^{2}+2xy+y^{2}]-9[x^{2}-2xy+y^{2}]\\\\=4x^{2}+4*2xy + 4y^{2}-9x^{2}-2xy*(-9)+y^{2}*(-9)\\\\= 4x^{2}+8xy+4y^{2}-9x^{2}+18xy-9y^{2}\\\\= 4x^{2}-9x^{2} + 8xy + 18xy +4y^{2} - 9y^{2}\\\\= -5x^{2} + 26xy - 5y^{2}[/tex]

= -5x² + 25xy + xy - 5y²

= 5x(-x + 5y) - y(-x +5y)

= (-x + 5y)(5x - y)

Answer:

21.4 m

Step-by-step explanation:

Let x represent the sum of the tall metal, medium metal and short metal heights. Since the tall metal has a length of 1.44 m, and the ratio is in 9:8:7, hence:

(9/24) * x = 1.44

x = 3.84 m

For the medium metal pieces:

(8/24) * 3.84 = medium metal height

medium metal height = 1.28 m

For the short metal pieces:

(7/24) * 3.84 = short metal height

short metal height = 1.12 m

Total horizontal metal piece length  = 3 * 1.8 m = 5.4 m

Total tall metal piece length  = 2 * 1.44 m = 2.88 m

Total medium metal piece length  = 5 * 1.28 m = 6.4 m

Total short metal piece length  = 6 * 1.12 m = 6.72 m

Total length of metal = 5.4 + 2.88 + 6.4 + 6.72 = 21.4 m

9514 1404 393

Answer:

  1240 in³

Step-by-step explanation:

The overall dimensions of the block are ...

  10 in by 11 in by 17 in

The volume of that space is ...

  V = LWH = (10 in)(11 in)(17 in) = 1870 in³

The volume of each of the three identical holes is similarly found:

  V = (10 in)(3 in)(7 in) = 210 in³

Then the volume of the block is the overall volume less the volume of the three holes:

  = 1870 in³ - 3(210 in³) = 1240 in³

Answer:

108801

Step-by-step explanation:

Well, you should first add 99 to 99999 which is 10098. And since it's not a palindrome you need to keep adding 99 to the sum until you reach one.

----------------------------------

This is with a calculator

Btw, I used calculator soup.com for it.

100089, 100188, 100287, 100386, 100485, 100584, 100683, 100782, 100881, 100980, 101079, 101178, 101277, 101376, 101475, 101574, 101673, 101772, 101871, 101970, 102069, 102168, 102267, 102366, 102465, 102564, 102663, 102762, 102861, 102960, 103059, 103158, 103257, 103356, 103455, 103554, 103653, 103752, 103851, 103950, 104049, 104148, 104247, 104346, 104445, 104544, 104643, 104742, 104841, 104940, 105039, 105138, 105237, 105336, 105435, 105534, 105633, 105732, 105831, 105930, 106029, 106128, 106227, 106326, 106425, 106524, 106623, 106722, 106821, 106920, 107019, 107118, 107217, 107316, 107415, 107514, 107613, 107712, 107811, 107910, 108009, 108108, 108207, 108306, 108405, 108504, 108603, 108702, 108801, 108900, 108999, 109098, 109197, 109296, 109395, 109494, 109593, 109692, 109791, 109890

[tex]\frac{13}{28}[/tex]

Given:

Blue marbles: 3

Reb marbles: 5

Total marbles: 8

Two marbles are selected at random, one after the other with replacement.

Getting the same colour of marbles from the selection means the two marbles are both red or both blue.

(a) Probability of getting 2 marbles being red in colour

i. Probability of picking a red at the first selection:

Number of red marbles ÷ Total number of marbles

=> 5 ÷ 8 = [tex]\frac{5}{8}[/tex]

ii. Probability of picking a red at the second selection:

Number of remaining red marbles ÷ Total number of remaining marbles

Since after the first pick, the marble is not replaced, the remaining red marbles is 4 while the total number of remaining marbles is 7

=> 4 ÷ 7 = [tex]\frac{4}{7}[/tex]

iii. The probability of getting both marbles being red is the product of i and ii above. i.e

[tex]\frac{5}{8}[/tex] x [tex]\frac{4}{7}[/tex] = [tex]\frac{5}{14}[/tex]

(b) Probability of getting 2 marbles being blue in colour

i. Probability of picking a blue at the first selection:

Number of blue marbles ÷ Total number of marbles

=> 3 ÷ 8 = [tex]\frac{3}{8}[/tex]

ii. Probability of picking a blue at the second selection:

Number of remaining blue marbles ÷ Total number of remaining marbles

Since after the first pick, the marble is not replaced, the remaining blue marbles is 2 while the total number of remaining marbles is 7

=> 2 ÷ 7 = [tex]\frac{2}{7}[/tex]

iii. The probability of getting both marbles being blue is the product of i and ii above. i.e

[tex]\frac{3}{8}[/tex] x [tex]\frac{2}{7}[/tex] = [tex]\frac{3}{28}[/tex]

(c) Probability of getting 2 marbles of the same colour.

The probability of getting 2 marbles of same colour is the sum of the probability of getting both marbles of red colour and the probability of getting both marbles as blue colour. i.e The sum of a(iii) and b(iii)

[tex]\frac{5}{14}[/tex] + [tex]\frac{3}{28}[/tex] = [tex]\frac{13}{28}[/tex]

The probability of getting 2 of the same colour is [tex]\frac{13}{28}[/tex]

Answer:

[tex] - \frac{ \sqrt{3} }{2} [/tex]

Step-by-step explanation:

Unit circle

Answer:

1. Tyler

2. 8.33

3. 8.5

4. Tyler

Step-by-step explanation:

this is just playing with the numbers. no complex math concepts.

Tyler's graph shows she reached 1 mile after 8 1/3 minutes (8 minutes and 20 seconds). that is 25/3 minutes.

according to Elena's equation she reached 1 mile (x=1) after 8.5 minutes. that is 8 1/2 minutes or 8 minutes and 30 seconds.

so, we see that Elena took more time (10 seconds longer) to run 1 mile, so Tyler was faster.

to generally compare the 2 we can write also Tyler's graph as function (like for Elena) :

8 1/3 = 8.333333....

y = 8.33x

but that is just FYI (not asked for here).

since Tyler was faster (and her graph also showed a straight line of time and distance up to 10 minutes and beyond, so, she did not slow down after the first mile), she also ran further after 10 minutes. that is the definition of "being faster" - to go further in the same amount of time.

Tyler needed 8.33 minutes per mile.

Elena needed 8.5 minutes per mile.

and so, Tyler was faster.

points 1 and 4 are directly coupled. they both express the same thing.

Answer:

2x(4x-4+1)

Step-by-step explanation:

i hope it will help you

Answer:

x=1/2

Step-by-step explanation:

press the calculator

8x²-8x+2=0

x=1/2

min,x=1/2

min,y=0

Answer:

it's and equilateral triangle because

all sides are equal

Answer:

equilateral triangle i have a math proffesor helping me

Step-by-step explanation:

I have a math proffesor helping me

Answer:

x = 16

Step-by-step explanation:

The product of the lengths theorem is a property that can be sued to describe the relationships of the sides between the tangents and secants in a circle. One of these products states the following;

The distance between the point of tangency and its intersection point with the exterior secant squared is equal to the product of the exterior secant times the interior secant.

This essentially means the following equation can be formed;

[tex](AB)^2=(DC)(CB)[/tex]

Substitute,

[tex]12^2=x*9[/tex]

Simplify,

[tex]144=9x[/tex]

Inverse operations,

[tex]\frac{144}{9}=x\\\\16=x[/tex]

Answer:

[tex]\boxed{\sf x=7}[/tex]

Step-by-step explanation:

By Targent-secant theorem...

[tex]\sf 9(x + 9) = {12}^{2} [/tex]

Use the distributive property to multiply 9 by x+9.

[tex]\sf 9x+81= {12}^{2} [/tex]

Now, let calculate 12 to the power of 2 and get 144.

[tex]\sf 9x+81=144[/tex]

Subtract 81 from both sides.

[tex]\sf 9x=63[/tex]

Divide both sides by 9.

[tex] \sf \cfrac{ 9x}{9} = \cfrac{63}{9} [/tex]

[tex]\sf x=7[/tex]

9514 1404 393

Answer:

  y = 2

Step-by-step explanation:

The figure must be flipped top-to-bottom, so the line of reflection must be a horizontal line. Point B must be reflected to itself, so it is on the line of reflection. That means the line of reflection is y = 2.

__

You can draw the line of reflection using any two points that have y-coordinates of 2, for example, (0, 2) and (2, 2).

Answer:

[tex]{ \tt{rate \: of \: change \: in \: A = 9}}[/tex]

Rate of change in function A is two times than that in function B

Answer:

(5) c

(6) c

(7) b

(8) a

Step-by-step explanation:

(5) The multiplicative inverse of a number n, is the number which when multiplied by n will give a result of 1 which is a multiplicative identity. The multiplicative inverse of a number is actually the reciprocal of that number. For example, the multiplicative inverse of n is 1/n. The multiplicative inverse of 5 is 1/5. The multiplicative inverse of 5/6 is 6/5.

Therefore, the multiplicative inverse of [tex]\frac{-11}{15}[/tex] is [tex]\frac{-15}{11}[/tex]

(6) To solve 7m + 12 = -4m + 78, follow these steps;

i. Collect like terms by putting terms with m on the left hand side and the terms without m on the right hand side as follows;

7m + 4m = 78 - 12

ii. Now solve both sides;

11m = 66

iii. Divide both sides by 11;

[tex]\frac{11m}{11} = \frac{66}{11}[/tex]

m = 6

(7) Let the number be x;

10 more than twice number is 22 implies that

10 + 2x = 22

Now solve the equation;

2x = 22 - 10

2x = 12

x = 6

(8) The interior angles of a given polygon are the angles of its vertices that are within or inside of the polygon.

The sum of the interior angles of a polygon is given by;

(n-2) x 180°

where;

n = number of sides of the polygon.

For example;

For a triangle, which has n = 3 sides, the sum of these interior angles is (3 - 2) x 180° = 180°

For a rectangle/square, which has n = 4 sides, the sum of these interior angles is (4 - 2) x 180° = 360°.

For a pentagon, which has n = 5 sides, the sum of these interior angles is (5 - 2) x 180° = 540°

Therefore, depending on the number of sides n, the sum of the interior angles of a given polygon is given by;

(n-2) x 180°

Answer:

a) 8:3, b) no formula is there, c) 30

Step-by-step explanation:

because 200/75=8:3

because there formula being obtained

because 300/24=12.5

375/12.5=30

Answer:

1024

Step-by-step explanation:

Given :-

Value of -2x²y³

Answer:

254

Step-by-step explanation:

^ <- this is the square sign

-2x^y^3

x=2

y=4

put x values in to x place and y value in to y place.

-2(2)^2(4)^3

Find the squares and - it with 2

-2(4)(64)

2-256=254

:. the value of -2x^2y^3 =254

That the answer.

Hope this is what you asked.

Answer:

306 square meters.

Step-by-step explanation:

Divide the shape into 2 rectangles.

Lets do the one that is sticking to the top first.

The area is 6 * 15, which is 90.

Lets do the second rectangle. The area is:

27 * 8, which is 216.

Add them all up (90 + 216), which is 306.

Answer:

306m²

Step-by-step explanation:

Split the shape into two rectangles with the accureate lengths

The top-most of the two rectangles with length 6m and width 15m:

6 x 15 = 90 m² (area of rectangle A)

The bottom rectangle:

27(full length) x 8m(full width) = 216m²

Add the two areas together for the full shape

216 + 90 = 306m²

What are you trying to solve for?

[tex]824381 + 1654 = - 121[/tex]

Parameterize the surface (I'll call it S) by

r(u, v) = (1 - u) (1 - v) i + u (1 - v) j + v k

with 0 ≤ u ≤ 1 and 0 ≤ v ≤ 1.

Take the normal vector to this surface to be

n = ∂r/∂u × ∂r/∂v = ((v - 1) i + (1 - v) j) × ((u - 1) i - u j + k) = (1 - v) (i + j + k)

with magnitude

||n|| = √3 (1 - v)

Then in the integral, we have

[tex]\displaystyle\iint_SG(x,y,z)\,\mathrm ds = \int_0^1\int_0^1 G((1-u)(1-v),u(1-v),v) \|\mathbf n\| \,\mathrm du\,\mathrm dv \\\\= \sqrt3 \int_0^1\int_0^1uv(1-v)^2\,\mathrm du\,\mathrm dv \\\\= \boxed{\frac1{8\sqrt3}}[/tex]

Alternatively, if you're not familiar with parameterizing surfaces, you can use the "projection" formula:

[tex]\displaystyle\iint_S G(x,y,z)\,\mathrm ds = \int_{S_{xy}}G(x,y,z)\sqrt{1+\left(\frac{\partial f}{\partial x}\right)^2+\left(\frac{\partial f}{\partial y}\right)^2}\,\mathrm dx\,\mathrm dy[/tex]

where I write [tex]S_{xy}[/tex] to mean the projection of the surface onto the (x, y)-plane, and z = f(x, y). We would then use

x + y + z = 1   ==>   z = f(x, y) = 1 - x - y

and [tex]S_{xy}[/tex] is the triangle,

{(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1 - x}

Then the integral becomes

[tex]\displaystyle\int_0^1\int_0^{1-x}y(1-x-y)\sqrt{1+(-1)^2+(-1)^2}\,\mathrm dy\,\mathrm dx \\\\= \sqrt3\int_0^1\int_0^{1-x} y(1-x-y)\,\mathrm dy\,\mathrm dx \\\\= \frac{\sqrt3}{24} \\\\= \boxed{\frac1{8\sqrt3}}[/tex]

This question is incomplete, the complete question is;

A student bought a smart-watch that tracks the number of steps she walks throughout the day. The table shows the number of steps recorded (t) minutes after 3:00 pm on the first day she wore the watch.

t (min)       0          10          20         30         40

Steps   3,288    4,659    5,522    6,686    7,128

a) Find the slopes of the secant lines corresponding to the given intervals of t.

1) [ 0, 40 ]

11) [ 10, 20 ]

111) [ 20, 30 ]

b) Estimate the student's walking pace, in steps per minute, at 3:20 pm by averaging the slopes of two secant lines from part (a). (Round your answer to the nearest integer.)

Answer:

a)

1) for [ 0, 40 ], slope is 96

11) for [ 10, 20 ],  slope is 86.3

111) for  [ 20, 30 ], slope is 116.4

b) the student's walking pace is 101 per min

Step-by-step explanation:

Given the data in the question;

t (min)       0          10          20         30         40

Steps   3,288    4,659    5,522    6,686    7,128

SLOPE OF SECANT LINES

1) [ 0, 40 ]

slope =  ( 7,128 - 3,288 ) / ( 40 - 0

= 3840 / 40 = 96

Hence slope is 96

11)  [ 10, 20 ]

slope = ( 5,522 - 4,659 ) / ( 20 - 10 )

= 863 / 10 = 86.3

Hence slope is 86.3

111)  [ 20, 30 ]

slope = ( 6,686 - 5,522 ) / ( 30 - 20 )

= 1164 / 10 = 116.4

Hence slope is 116.4

b)

Estimate the student's walking pace, in steps per minute, at 3:20 pm by averaging the slopes of two secant lines from part .

Since this is recorded after 3:00 pm

{ 3:20 - 3:00 = 20 }

so t = 20 min

so by average;

we have ( [ 10, 20 ] + [ 20, 30 ] ) /2

⇒ ( 86.3 + 116.4 ) / 2

= 202.7 /2

= 101.35 ≈ 101

Therefore, the student's walking pace is 101 per minutes

Answer:

Test statistic = - 2.71

Step-by-step explanation:

Table of the sample data is attached below :

Using a dependent sample t test :

H0 : μd = 0

H0 : μd ≠ 0

The difference in the 6th and 13th date data is :

Difference, d = -4, -6, -3, -1, 1, -7

The sample size, n = 6

The mean of d ; μd = Σd/ n = - 3.667

Standard deviation of difference, Sd = 3.011

The test statistic : μd/(Sd/√n)

Test statistic = - 3.33 / (3.011/√6)

Test statistic = - 3.33 / 1.2292356

Test statistic = - 2.709

Test statistic = - 2.71