After solving simple arithmetic we have found that, Professor V teaches physics as Professor P = English, Professor Q =Chemistry, Professor R = Maths, Professor S = Biology, Professor T= Geography, Professor U = history.
What is arithmetic?Arithmetic is the branch of mathematics concerned with the study of numbers through various operations on them. The basic operations of math are addition, subtraction, multiplication, and division.
It is said that Each professor teaches a different subject and not more than two subjects are taught on any one which means
1 teacher = 1 subject
1 day = 2 subjects
We have given that
Chemistry is taught by professor Q on Tuesday
Professor Q is Chemistry teacher
Professor S teaches on Friday but neither Geography nor Physics
Professor U teaches History but neither on Thursday nor on Friday
Professor U is History teacher
Professor P teaches English on the day on which History is taught
Professor P is English teacher
Professor R teaches Maths on Monday
Professor R is Maths teacher
Geography and Chemistry are taught on the same day
Which means geography is taught on Tuesday
Tuesday = geography and Chemistry (1 day = 2 subjects)
Professor U and Professor P teaches history and English on the same day and it is either Monday or Wednesday as Tuesday already filled and they don't teach on Thursday or Friday.
But it couldn't be Monday as Professor R teaches Maths on Monday and there could only be two subjects
So,
Wednesday = history and English (1 day = 2 subjects)
Professor S teaches on Friday but neither Geography nor Physics and other teachers are taken for Chemistry, math, English and history, so Professor S is Biology teacher
There are seven subjects and 5 days which means three subjects are learned twice at the end of the week
Mondays = Maths and 1 other subject
Tuesday = geography and Chemistry
Wednesday = history and English
Thursday = Professor V(subject) and any of the repeated subject
Friday = Biology and any of the repeated subject
As Biology is a repeated subject we can assume that it is also learned on Monday, We have found that Professor U and Professor P teaches history and English on the same day and Geography and Chemistry are taught on the same day, so the repeated subjects are neither history, English, Geography, nor chemistry.
Which means repeated subject could only be Maths, Physics and biology
But for Friday it could only be maths or physics
As Geography could only be taught on same days with chemistry it means professor T teaches geography as Chemistry is taught by professor Q on Tuesday and Geography and Chemistry are taught on the same day so Professor V wont be teaching on that Tuesday.
Thus, we have
Professor P = English
Professor Q =Chemistry
Professor R = Maths
Professor S = Biology
Professor T= Geography
Professor U = history
Professor V = ?
Only subject left is Physics
So, professor V teaches physics
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Full question
Which of the following subjects is taught by professor V?
If p and q vary inversely and p is 19 when q is 16, determine q when p is equal to 8.
The value of q solving with variation method is 38
How to calculate the value of q ?Variation van be described as the relationship between a set of variable. We will be applying inverse variation to solve the question
The value of q can be calculated by using variation method
p= k/q
The first step is to calculate the constant k
19= k/16
cross multiply both sides
k= 19 × 16
k= 304
Since the value of k is 304, then the value of q can be calculated as follows
p = k/q
8= 304/q
cross multiply both sides
8q= 304
q= 304/8
q= 38
Hence the value of q when the value of p is 8 is 38
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Murray has tossed a coin 120 times. The coin landed on heads 54 times. What is the experimental probability that the coin will land on heads on the next toss?
Answer:
Explanation:
Experimental probability = number of favorable outcomes/number of total outcomes
From the information given,
number of favorable outcomes = 54
number of total outcomes = 120
The experimental probability that the coin will land on heads on the next toss = 54/120
Dividing the numerator and denominator by 6,
The experimental probability that the coin will land on heads on the next toss = 9/20
Given the image below, identify the value of x. 9 2x - 19 M
You have the the length of segment NK is 23.
Furthermore, you have that segment NK is the sum of the following segments:
NK = NM + ML + LK
Each of the previous segments are given by the following algebraic expressions:
NM = x - 6
ML = 9
LK = 2x - 19
You sum the previous expression, by taking into account that the result is 23. Then you solve for x, just as follow:
NM + ML + LK = NK
(x - 6) + (9) + (2x - 19) = 23 eliminate parenthesis
x - 6 + 9 + 2x - 19 = 23 simplify similar terms
x + 2x - 6 - 19 + 9 = 23
3x - 16 = 23 add 16 both sides
3x = 23 + 16
3x = 39 divide by 3 both sides
x = 39/3
x = 13
Hence, the solution for x is x = 13
A T-shirt company has determined that the profit it makes from a new T-shirt design can be modeled by the quadratic equation below:y = -100(x - 9)(x - 17)Where x represents the price of a T-shirt in dollars and y represents the company profit in dollars.According to this model, how much should the T-shirt company charge if they want to maximize their profit.Round your answer to the nearest penny.
Given data:
The expression for the profit function is y=-100(x-9)(x-17).
Differentiate teh above expressionn and equate to zero, in order to maimize the profit function.
[tex]\begin{gathered} \frac{dy}{dx}=0 \\ -100\frac{d}{dx}(x-9)(x-17)=0 \\ -100(x-9)\frac{d(x-17)_{}}{dx}-100(x-17)\frac{d(x-9)}{dx}=0 \\ -100(x-9)-100(x-7)=0 \\ -100(x-9+x-7)=0 \\ 2x=16 \\ x=8 \end{gathered}[/tex]Thus, 8 T-shirts must be sold in order to maximmize tthe profit.
A gardener has a bag of flower seeds. Half of the seeds are roses, one fourth are gardenias,
and one fourth are irises.
a. P(gardenias)
b. P(not gardenias)
the ratio of the measures of three angles of a triangle is 3:6:1. Find the measurements of each angle
Gabe, you are doing great. Now you need to solve for x:
3x + 6x + x = 180
10x = 180
dividing by 10 at both sides:
10x/10 = 180/10
x = 18 That is the answer you have.
Finally, you need to multiply the ratio for the value of x, you just calculated:
Side 1 = 3 * 18
Side 2 = 6 * 18
Side 3 = 1 * 18
Prove that the following four points will form a rectangle when connected in orderby showing the diagonals are congruent. Show all work.AIO. -3). B(-4.0). C(2. 8). D(6. 5)
SOLUTION
For the four points to form a rectangle, the length of the diagonals will be equal.
This means that we have to find the distance between the point BD and AC. If
BD = AC, then the four points would form a rectangle.
[tex]\begin{gathered} Dis\tan ce\text{ betw}ee\text{n points B and D, that is BD} \\ \text{Distance betw}ee\text{n two points = }\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ BD=\text{ }\sqrt[]{(6-(-4)^2+(5-0)^2} \\ BD=\sqrt[]{10^2+5^2} \\ BD=\sqrt[]{125} \\ BD=\text{ 5}\sqrt[]{5} \end{gathered}[/tex]Now let's find AC
[tex]\begin{gathered} AC=\text{ }\sqrt[]{(2-0)^2+(8-(-3)^2} \\ AC=\sqrt[]{2^2+11^2} \\ AC=\sqrt[]{4+121} \\ AC=\sqrt[]{125} \\ AC=5\sqrt[]{5} \end{gathered}[/tex]So, since BD = AC, the four points A, B, C and D would form a rectangle.
can i get some help on this one?
Answer:
[tex](x+9)^2=-4[/tex]Step by step explanation:
Completing the square is where we take a quadratic equation like this:
[tex]\begin{gathered} ax^2+bx+c=0 \\ \text{ and turn it into this:} \\ a(x+d)^2+e=0 \end{gathered}[/tex]Where d and e can be represented by the following expressions:
[tex]\begin{gathered} d=\frac{b}{2a} \\ e=c-\frac{b^2}{4a} \end{gathered}[/tex]Since we have the following equation:
[tex]\begin{gathered} x^2+18x+74=-11 \\ x^2+18x+85=0 \end{gathered}[/tex]So, for a=1, b=18 and c=85.
Find d and e:
[tex]\begin{gathered} d=\frac{18}{2}=9 \\ e=85-\frac{18^2}{4}=4 \end{gathered}[/tex]Then, the result for completing the square would be:
[tex]\begin{gathered} (x+9)^2+4=0 \\ (x+9)^2=-4 \end{gathered}[/tex]Please helpp..Use the simple interest formula to determine the missing value.
p=$951.63, r= 6.5%, t= ?, i = $123.71
t=years
Using the simple interest formula, the value of time (t) is 103 years.
What is simple interest?Simple interest is a quick and simple formula for figuring out how much interest will be charged on a loan. The daily interest rate, the principal, and the number of days between payments are multiplied to calculate simple interest. Ordinary simple interest and exact simple interest are the two types of simple interest. In order to calculate interest, a year is divided into 360 days for ordinary simple interest and 365 days (or 366 days for leap years) for exact simple interest. The simple interest calculation formula is the same for both approaches.So, the simple interest rate formula:
A = P (1 + rt)We need to find the value of time (t), then the formula will become:
t = (1/r)(A/P - 1)Insert the values as follows:
t = (1/6.5)(951.63/123.71) - 1)t = 102.96Rounding off: t = 103 years
Therefore, using the simple interest formula, the value of time (t) is 103 years.
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A new road is being constructed parallelto the train tracks through point V. An equation of the line representing thetrain tracks is y = 2x.Find an equation of the linerepresenting the new road.
the equation of the line representing the new road will be 2 x - y + 7 = 0.
The line is:
y = 2 x.
The slope of the line is:
m = 2
Now, the point V is:
V = (- 2, 3)
Since the train track is parallel to the line, its slope will be:
m' = 2 ( slope of parallel lines are equal)
So, the equation of the new road line will be:
y - y₁ = m (x - x₁)
y - 3 = 2 ( x + 2)
y - 3 = 2 x + 4
2x - y + 7 = 0
Therefore, the equation of the line representing the new road will be 2 x - y + 7 = 0.
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The numbers of students in the 9 schools in a district are given below. (NOTE THAT THESE ARE ALL ALREADY IN ORDER FROM LEST TO GREATEST)
Given:
The data is:
240,256, 307, 310, 325, 333, 359, 363, 378
Required:
If the number 378 changes to 261 then
(a) What happens to the median
(b) What happens to the mean
Explanation:
(a)The number of terms = 9
Median = 5th term
Median = 325
if the term 378 changed to 261 then the data will be:
240,256, 261 307, 310, 325, 333, 359, 363
Median = 310
Thus the median is decreasing.
Decreased value = 325 - 310 = 15
(b) Mean is given by the formula:
[tex]mean=\frac{sum\text{ of observation}}{Total\text{ number of observation}}[/tex][tex]\begin{gathered} mean\text{ = }\frac{240+256+307+310+325+333+359+363+378}{9} \\ mean\text{ =}\frac{2871}{9} \\ mean\text{ =319} \end{gathered}[/tex]if the term 378 changed to 261 then
[tex]\begin{gathered} mean=\text{ }\frac{240+256+307+310+325+333+359+363+261}{9} \\ mean=\text{ }\frac{2754}{9} \\ mean=\text{ 306} \end{gathered}[/tex]Thus the mean is decreasing.
Decreased value = 319 - 306 = 13
Final answer:
(a) median is decreased by 15
(b) mean is decreased by 13
ahmed want to make a triangle, he has rods that measure 9 inch and 15 inches. the rods cannot be cut. which is the length of a rod he could use to complete the triangle?
The length of the rod that he could use to complete the triangle is 12 inches. This is solved based on the principle of Pythagorean Triples.
What are the Principles of Pythagorean Triples?Pythagorean triples are a collection of three positive numbers that fit into the Pythagorean theorem formula, which is written as a² + b² = c², where a, b, and c are positive integers. In this case, 'c' is the 'hypotenuse,' or the triangle's longest side, while 'a' and 'b' are the other two legs of the right-angled triangle.
Pythagorean triples are denoted as (a,b, c). The most well-known Pythagorean triple example is (3, 4, 5). We can see that the numbers 3, 4, and 5 meet the equation a² + b² = c².
To prove that the length of the rod that should be used to complete the triangle is 12. Let's subject the values to the Principles of Pythagorean Triples.
Given:
9,
let's assume that 15 is the longest side.
Thus,
If we are correct,
9² + 12² should equal 15²
9² = 81
12² = 144
15² = 225
81 + 144 =225
Hence the length of the rod that must be used to complete the triangle is 12 inches.
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Can you someone solve for x
-2x + -3 = 1x
Answer: x = -3/2
Step-by-step explanation:
Equation:
x -2x + -3 = 1x
Combine Like Terms:
x - 2x + -3 = 1x
-x - 3 = 1x
+x +x
[tex]-3 = 2x[/tex]
[tex]\frac{-3}{2} = \frac{2x}{2}[/tex]
-3/2 = x
which integer could represent the fact that the water level of a pool decreases by 4 feet
-4
1) In this question, there's not much information so let's think of a rule
2) We can sketch this out:
We could even write a function that describes this, which "W" stands for Water Level and "t":
3) So if the level of water is decreasing by 4 feet each and every water level from now on is negative.
(6x+31-9=0
3X+34-320
Answer:
X= - 154/3
Step-by-step explanation:
solve P=2M+2M for G
G=?
G=P-2M/2
Step-by-step explanation:
P=2G+2M
p - 2M = 2G
G=P - 2M/2
3. Use the slope and y-intercept to complete thetable of values with solutions that includeonly integers. (1 point total)y=2x-3=xу
given the equation:
y = 5/4x - 3
to complete the table for the values of x and y using intergers
fristly,
when x = -4
y = 5/4(-4) - 3
y = -5 - 3
y = -8
when x = 0
y = 5/4(0) - 3
y = 0 - 3
y = -3
when = 4
y = 5/4(4) - 3
y = 5 - 3
y = 2
when x = 8
y = 5/4(8) - 3
y = 5(2) - 3
y = 10 - 3
y = 7
so completing the table:
y = 5/4x - 3
x y
-4 -8
0 -3
4 2
8 7
Find the equation of the line that passes through the two points (2, -1) and (5, 5). Write your answer in standard form.
Explanation
Given the points two points (2, -1) and (5, 5) we can find the equation of a line using the point-slope formula.
[tex]\begin{gathered} y_-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1) \\ Where\text{ x}_1,y_1=2,-1 \\ x_2,y_2=5,5 \end{gathered}[/tex]Therefore, we will have;
[tex]\begin{gathered} y-(-1)=\frac{5-(-1)}{5-2}(x-2) \\ y+1=\frac{6}{3}(x-2) \\ y+1=2(x-2) \\ y+1=2x-4 \\ 2x-y=1+4 \\ 2x-y=5 \\ \end{gathered}[/tex]Answer: 2x-y=5
Use the diagram below to find x x = 34x = 32x = 30x = 28
Given the following question:
find the volume of a conebase diameter of 10 ydheight 6 ydsuse the value 3.14 for pie
Given
The formula
[tex]\begin{gathered} \text{The volume of a cone =}\frac{1}{3}\pi r^2h \\ \\ \pi=3.14 \\ r=5 \\ h=6 \end{gathered}[/tex][tex]\begin{gathered} \text{The volume of a cone =}\frac{1}{3}\pi r^2h \\ \text{The volume of a cone =}\frac{1}{3}\times3.14\times5^2\times6 \\ \\ \text{The volume of a cone =}\frac{1}{3}\times3.14\times25^{}\times6 \\ \\ \text{The volume of a cone =}\frac{1}{3}\times3.14\times150 \\ \\ \text{The volume of a cone =}3.14\times50 \\ \\ \text{The volume of a cone =}157yd^3 \end{gathered}[/tex]The final answer
[tex]\text{The volume of a cone =}157yd^3[/tex]can you check to see if my work is correct?
The Solution.
[tex]P=-\frac{1}{250}T^2+2.8T-394[/tex]To obtain the maximum value of T, we differentiate with respect to x and equate to zero.
[tex]\begin{gathered} \frac{dP}{dT}=2(-\frac{1}{250}T)+2.8\text{ =0} \\ \\ -\frac{1}{125}T+2.8=0 \\ \\ -\frac{T}{125}=-2.8 \\ \text{Cross multiplying, we get} \\ T=125\times2.8=350^oF \end{gathered}[/tex]To get the maximum value of P, we shall substitute 350 for T in the given function.
[tex]\begin{gathered} P=-\frac{1}{250}(350^2)+2.8(350)-394 \\ \\ P=-490+980-394 \\ P=96\text{ percent} \end{gathered}[/tex]The correct answer is T = 350 degrees Fahrenheit , and P = 96 percent.
find the surface area of the triangular prism 7 6 7 9
The surface area of the triangular prism will be 217.95 cm²
What is a triangular prism?When a triangle is, stretch it out to produce a stack of triangles, one on top of the other. A triangular prism is a name given to this novel 3D object.
It is given that,
Base side, a = 7 sm
Base side, b = 6 cm
Base side, c = 7 cm
Height, h = 9 cm
The surface area of a triangle prism: The formula for a triangular prism's surface area is,
A=bh+(b₁+b₂+b₃) units²
where b is the base of a triangular face, h is the height of a triangular face, b₁ is the side of the triangular base, b₂ is the side of the triangular base, and l is the prism's length.
The surface area of the triangular prism will be,
[tex]\rm A = ah + bh + ch + \dfrca{1}{2} \sqrt{-a^4 +2(ab)^2 +2(ac)^2 -b^4+2(bc)^2 -c^4}[/tex]
Substitute the given values,
[tex]\rm A = 7 \times 9 + 6 \times 9 + 7 \times 9 + \dfrac{1}{2} \times \sqrt{-7^4 + 2(7 \times 6)^2 +2 (7\times 7)^2 -6^4 + 2(6 \times 7)^2 - 7^4} \\\\ A = 217.94 \ cm^2[/tex]
Thus, the surface area of the triangular prism will be 217.95 cm².
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What is the first point you would graph the function 3x+1/2y=2
First, let's clear y to get the slope-intercept form:
[tex]\begin{gathered} 3x+\frac{1}{2}y=2 \\ \\ \rightarrow6x+y=4 \\ \Rightarrow y=-6x+4 \end{gathered}[/tex]This way, we can conclude that the y-intercept is 4. This is the first point we have to graph:
[tex](0,4)[/tex]The weight of 8 eggs is 496 grams. Identify the constant of proportionality of total weight to number of eggs.
Group of answer choices
60
56
62
58
Gravel is being dumped from a conveyor belt at a rate of 40 ft/min, and its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal. How fast (in ft/min) is the height of the pile increasing when the pile is 5 ft high?
(Round your answer to two decimal places.)
The radius of a sphere is increasing at a rate of 2 mm/s. How fast is the volume increasing (in mm/s) when the diameter is 40 mm? (Round your answer to two decimal places.)
The formula Wh = Rs + Q, where Q stands for total energy losses experienced upon impact, can be used to represent any of the five fundamental types of dynamic pile drive formulas now in use.
Calculate dynamic pile ?
Fixed Formula
Maximum load a pile or set of piles (group pile) can support (Qu)
Depending on the soil's properties
Qu=Qp+Qs
Maximum failure load
Qp is the pile's point resistance.
Qs is the shaft resistance caused by rubbing between the pile and the dirt.
Load (Q) (Q)
Qp
QsQs.
Given diameter
height = h = ft(say)
radius = r =h/2
volume =v =1/3πr²h =1/3π(h/2)²h
=1/3π(h²/4)(h)
=1/12πh³
dv/dt = 1/12π(3h²dh/dt)
dv/dt = π/4 h² dh/dt
here dv/df =40ft³ and h =5ft
40 = π/4 (5² dh/dl
=40*4/100π
= 160/100π
=8/5π
So, the height is increasing at the rate of (8/5π) ft/min.
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The graph of y=√x is reflected over the y-axis and then translated down 2 units to form f(x). Which is the graph off(x)?$ 10-10-88 10 x
We must apply some transformations to the function:
[tex]y=g(x)=\sqrt[3]{x}.[/tex](1) A reflection across the y-axis is given by the transformation:
[tex]g(x)\rightarrow h(x)=g(-x)=\sqrt[3]{-x}=-\sqrt[3]{x}.[/tex](2) A translation down 2 units is given by the transformation:
[tex]h(x)\rightarrow f(x)=h(x)-2=-\sqrt[3]{x}-2.[/tex]Plotting the function f(x), we get the following graph:
AnswerRound to the nearest tenths 62.32
Answer:62.3
Step-by-step explanation:
A car rental company charges $15 per day and $0.55 per kilometer to rent a car. What is the total bill if a car is rented for 4 days and is driven 146 kilometers?
The ages of the people on the bus are 24, 38, 47, 29, 51, 44, 40, 31, 36, and 43. If a bus passenger is selected at random, what is the probability that he or she is younger than 30?
We want to know the probability of a passenger to be younger than 30.
There are 10 persons on the bus and out of those, just 2 are younger than 30.
Denote by E the event: "obtaining a person younger than 30 when its selected at random from the bus". Then,
[tex]P(E)=\frac{\text{number of persons younger than 30}}{\text{total persons on the bus}}=\frac{2}{10}=\frac{1}{5}=0.2[/tex]This means that the probability of a passenger to be younger than 30 is 0.2.
I need some help on number 4...Also, was my answer right for number 5, I believe it is..
In order to find the solution of this system of equations, we need to find the ordered pair that is a solution to both equations.
To do so, let's use the value of x from every option and calculate the corresponding value of the functions:
[tex]\begin{gathered} x=0\colon \\ f(0)=\sqrt[]{0+4}=2 \\ g(0)=0-4=-4 \\ \\ x=1.6\colon \\ f(1.6)=\sqrt[]{3.2+4}=2.68 \\ g(1.6)=1.6^3-4=0 \\ \\ x=-1.3\colon \\ f(-1.3)=\sqrt[]{-2.6+4}=1.18 \\ g(-1.3)=(-1.3)^3-4=-6.2 \\ \\ x=1.9\colon \\ f(1.9)=\sqrt[]{3.8+4}=2.8 \\ g(1.9)=(1.9)^3-4=2.8 \end{gathered}[/tex]So the correct option is the fourth one.
