18 - (-f) = 91
Subtracting a negative value changes to addition:
18 + f = 91
Subtract 18 from both sides:
F = 73
Answer:
f = 73
Step-by-step explanation:
Solve for f
18 - ( - f ) = 91
Remove the parantheses and change their sign.18 + f = 91
subtract each side by 1818 - 18 + f = 91 - 18
calculatef = 73
Find the lenght of x
Answer:Answer in on Attached photo.
[tex]\color{red}{==========================}[/tex]
✍︎ꕥᴍᴀᴛʜᴅᴇᴍᴏɴǫᴜᴇᴇɴꕥ
✍︎ꕥᴄᴀʀʀʏᴏɴʟᴇᴀʀɴɪɴɢꕥ
what s the equation of the line through the origin and (-2, 3)
Answer:
y=[tex]\frac{-3x}{2}[/tex]
Step-by-step explanation:
Hi there!
We need to find the equation of the line that passes through the origin (the point (0,0)) and (-2,3)
There are 3 ways to write the equation of the line, although the most common way is slope-intercept form.
Slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept
So we need to find the slope of the line first
The formula for the slope (m) calculated from two points [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex] where ([tex]x_{1}[/tex],[tex]y_{1}[/tex]) and ([tex]x_{2}[/tex], [tex]y_{2}[/tex]) are points
We have the needed information to calculate the slope, but let's label the values of the points to avoid any confusion
[tex]x_{1}[/tex]=0
[tex]y_{1}[/tex]=0
[tex]x_{2}[/tex]=-2
[tex]y_{2}[/tex]=3
Now substitute their values into the equation and find m
m=[tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
m=[tex]\frac{3-0}{-2-0}[/tex]
subtract
m=[tex]\frac{3}{-2}[/tex]
so the slope of the line is [tex]\frac{3}{-2}[/tex]. It can also be rewritten as [tex]\frac{-3}{2}[/tex]
Here is the equation of the line so far:
y=[tex]\frac{-3x}{2}[/tex]+b
we need to find b
As the equation passes through both (0,0) and (-2,3), we can use either one of them to solve for b
Let's take (0,0) for this case
Substitute 0 as x and 0 as y
0=-[tex]\frac{3}{2}[/tex](0)+b
multiply
0=0+b
add 0 to both sides
0=b
So b is 0
The equation of the line therefore is y=[tex]\frac{-3x}{2}[/tex]
Hope this helps!
685 gym members were asked if they use the elliptical machine or treadmill as their primary cardiovascular exercise. 257 said they use the treadmill, 157 said they use the elliptical, and 85 said they use both.
a.) Organize this using a venn diagram (2 marks)
b.) A gym member is chosen from this group. What is the probability that this member uses the treadmill only? (1 mark)
Given:
Total number of gym members = 685
257 said they use the treadmill, 157 said they use the elliptical, and 85 said they use both.
To find:
a. The venn diagram.
b. The probability that a member uses the treadmill only?
Solution:
(a)
We have,
Total number of gym members = 685
Treadmill user = 257
Elliptical user = 157
Who use both = 85
Only treadmill user is:
[tex]257-85=172[/tex]
Only Elliptical used
[tex]157-85=72[/tex]
Therefore, the venn diagram for the given situation is shown below.
(b)
The member who use treadmill only = 172
Total user = 685
The probability that a member uses the treadmill only is:
[tex]P(\text{Only treadmill})=\dfrac{\text{Only treadmill users}}{\text{Total users}}[/tex]
[tex]P(\text{Only treadmill})=\dfrac{172}{685}[/tex]
Therefore, the probability that a member uses the treadmill only is [tex]\dfrac{172}{685}[/tex].
The nth term for the question
Answer:
Step-by-step explanation:
1) nth therm = dn + (a - d)
-10n + (11+10)
-10n + 21
t11 = -110 + 21 = -89
2) nth therm = 3n + (-66 - 3)
3n - 69
t16 = 48 - 69 = -21
Solve for x. Round to the nearest tenth, if necessary.
Answer:
x = 10.7
Step-by-step explanation:
We have:
[tex]\frac{x}{sin 90}[/tex] = [tex]\frac{9.2}{sin59}[/tex]
=> x × sin59 = 9.2 × sin90
=> x × sin59 = 9.2
=> x = 9.2 ÷ sin59
=> x = 10.733027...
=> x = 10.7 (Round to the nearest tenth)
<3 Have a nice day!!
I have like no clue what this means, please help! :)
Answer:
1/9
You are being asked to "complete the square"
you need to find a value to make the quadratic a "perfect square:
the focus is -2/3 you need to "add" one half of -2/3 squared to the
equation (1/2 * -2/3)^2 .... (-2/6)^2 .... 4/36 .... 1/9
Step-by-step explanation:
find the point(s) in which f(x)=e^5-2x and y=6 intercept
Answer:
(1.6, 6)
Step-by-step explanation:
[tex] ln({e}^{5 - 2x} = 6)[/tex]
[tex]5 - 2x = ln(6) [/tex]
[tex]2x = 5 - ln(6) [/tex]
[tex]x = \frac{5 - ln(6) }{2} [/tex]
y = 6
Score for Question 2: ___ of 5 points) 2. Write the equation of the circle in general form. Show your work.
Answer:
[tex]x^2 + y^2 + 2x - 2y - 7 = 0[/tex]
Step-by-step explanation:
Given
See attachment for circle
Required
The circle equation
First, we get the radius of the circle.
From the attachment, we have:
[tex]r = 3[/tex]
Next, the center of the circle
[tex](h,k) = (-1,1)[/tex]
The equation of the circle is:
[tex](x - h)^2 + (y - k)^2 = r^2[/tex]
This gives:
[tex](x - -1)^2 + (y - 1)^2 = 3^2[/tex]
[tex](x +1)^2 + (y - 1)^2 = 3^2[/tex]
Expand
[tex]x^2 + 2x + 1 + y^2 - 2y + 1 = 9[/tex]
Collect like terms
[tex]x^2 + y^2 + 2x - 2y + 1 + 1 - 9 = 0[/tex]
[tex]x^2 + y^2 + 2x - 2y - 7 = 0[/tex]
Hence, the equation in general form is:
[tex]x^2 + y^2 + 2x - 2y - 7 = 0[/tex]
Question is in the photo*
Answer:
3x - y +5=0
Step-by-step explanation:
Slope:-
=> m = 2-8/-1-1 = -6/-2
=> m = 3
Using point slope form :-
=> y - 2 = 3 ( x - (-1))
=> y - 2 = 3x + 3
=> 3x - y +5 = 0
Answer:
y=3x+5
Step-by-step explanation:
first find the gradient
m=y2-y1/x2-x1
from the coordinates you are given x one is -1,x two is1,y one is 2,y two is 8
8-2/1-(-1)
=3
therefore the gradient is 3
after finding the gradient use the equation
y-y1=m(x-x1)
substitute x1,y1 and the gradient..y and x are constant
y-2=3(x-(-1))
y-2=3x+3
y=3x+3+2
y=3x+5
Solve for x. Round to the nearest tenth of a degree, if necessary.
Answer:
[tex]x\approx 49.6^{\circ}[/tex]
Step-by-step explanation:
In any right triangle, the tangent of an angle is equal to its opposite side divided by its adjacent side.
For angle [tex]x[/tex]:
Opposite side is 40Adjacent side is 34Therefore, we have:
[tex]\tan x^{\circ}=\frac{40}{34}[/tex]
Take the inverse tangent of both sides to solve for [tex]x[/tex]:
[tex]\tan^{-1}(\tan x)=\tan^{-1}(\frac{40}{34}),\\x=\tan^{-1}(\frac{40}{34}),\\x=49.63546343\approx \boxed{49.6^{\circ}}[/tex]
*Recall [tex]\tan^{-1}(\tan x)=x\text{ for } x\in (-90^{\circ}, 90^{\circ})[/tex]
If f(x) = -3 3 and g(x)= 4x2 + 2x - 4, find (f +g)(x).
Answer:
A. 4x² + 9x/4 - 7
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Terms/CoefficientsFunctionsFunction NotationStep-by-step explanation:
Step 1: Define
Identify
f(x) = x/4 - 3
g(x) = 4x² + 2x - 4
(f + g)(x) is f(x) + g(x)
Step 2: Find
Substitute in functions: (f + g)(x) = x/4 - 3 + 4x² + 2x - 4Combine like terms: (f + g)(x) = 4x² + 9x/4 - 7Find the area of the figure below
Answer:
35.2 cm²Step-by-step explanation:
The area is:
A = 2(3.5*2) + 7*2 + 2(1.8*2) = 35.2 cm²We can find the area,
→ 2(3.5 × 2)+ (7 × 2) + 2(1.8 × 2)
→ 14 + 14 + 7.2
→ 35.2 cm²
Thus, the area is 35.2 cm².
Find the area of a circle with radius, r = 5.72m.
Give your answer rounded to 2 DP.
r
The diagram is not drawn to scale.
Answer:
A≈102.79
Step-by-step explanation:
The formula for area of a circle is πr² so we need to substitute the r by 5.72.
π×5.7² = 102.79 m²
Answer:
Approximately 102.79 meters squared
Step-by-step explanation:
pi times 5.72 meters squared
Hope this helps!
In London today, four times the high temperature was more than twice the high temperature plus
sixty-six. In interval form, what are the possible temperatures
Answer:
Let's define the high temperature as T.
We know that:
"four times T, was more than 2*T plus 66°C"
(i assume that the temperature is in °C)
We can write this inequality as:
4*T > 2*T + 66°C
Now we just need to solve this for T.
subtracting 2*T in both sides, we get:
4*T - 2*T > 2*T + 66°C - 2*T
2*T > 66°C
Now we can divide both sides by 2:
2*T/2 > 66°C/2
T > 33°C
So T was larger than 33°C
Notice that T = 33°C is not a solution of the inequality, then we should use the symbol ( for the set notation.
Then the range of possible temperatures is:
(33°C, ...)
Where we do not have an upper limit, so we could write this as:
(33°C, ∞°C)
(ignoring the fact that ∞°C is something impossible because it means infinite energy, but for the given problem it works)
Someone please help, this is the last question on my assignment, and I really need to get it right! I'll mark brainliest for the best answer ^-^
Answer:
x + 2
Step-by-step explanation:
im sure its the right answe
Find the integral of x(4x² + 1) from 0 to 2. a. 18 c. 22 b. 16 d. 20
Answer:
a. 18
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightDistributive Property
Algebra I
Terms/CoefficientsCalculus
Integrals
Definite IntegralsIntegration Rule [Reverse Power Rule]: [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]
Integration Rule [Fundamental Theorem of Calculus 1]: [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]
Integration Property [Multiplied Constant]: [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]
Integration Property [Addition/Subtraction]: [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle \int\limits^2_0 {x(4x^2 + 1)} \, dx[/tex]
Step 2: Integrate
[Integrand] Distribute x [Distributive Property]: [tex]\displaystyle \int\limits^2_0 {(4x^3 + x)} \, dx[/tex]Rewrite Integral [Integration Property - Addition/Subtraction]: [tex]\displaystyle \int\limits^2_0 {4x^3} \, dx + \int\limits^2_0 {x} \, dx[/tex]Rewrite 1st Integral [Integration Property - Multiplied Constant]: [tex]\displaystyle 4\int\limits^2_0 {x^3} \, dx + \int\limits^2_0 {x} \, dx[/tex][Integrals] Reverse Power Rule: [tex]\displaystyle 4(\frac{x^4}{4}) \bigg| \limits^2_0 + (\frac{x^2}{2}) \bigg| \limits^2_0[/tex]Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: [tex]\displaystyle 4(4) + 2[/tex]Evaluate: [tex]\displaystyle 18[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
Book: College Calculus 10e
0.54,0.45,0.405,0.054 in order smallest first
Answer:
0.054, 0.405, 0.45, 0.54
Answer:
0.054, 0.405, 0.45, 0.54
Step-by-step explanation:
1. The 0 after the decimal point makes it the smallest
2. 405/1000 < 45/100
3. 45/100 < 54/100
Tommy went to the shop where there was a 20% off sale taking place
The shirt he wanted to buy was originally £20
How much money does he save in the sale?
Answer:
4 pounds
Step-by-step explanation:
take 20% off the original price. 20(0.20)= 4
So that's a discount of 4 pounds and the sale price is 16 pounds.
The savings is 4 pounds on 1 shirt.
Use the distributive property to write the next step in simplifying the numerical expression. Use the asterisk symbol (*) to represent multiplication. Do not multiply factors fully and do not use spaces. 4(x + 9)
Answer:
This is the expression:
4*x+4*9
HELPPPPPP i will give brainliest!!!!!
Answer:
10-5=5 answer is 8^5
Step-by-step explanation:
Answer:
[tex]8^{5}[/tex]
Step-by-step explanation:
[tex]\frac{8^{10} }{8^{5} }[/tex]
Where are there more 8's ?
top
How many more?
5
Then they stay on top of fraction.
Another way :
[tex]x^{a}[/tex] ÷ [tex]x^{b}[/tex] = [tex]x^{a-b}[/tex]
[tex]8^{10}[/tex] ÷ [tex]8^{5}[/tex] = [tex]8^{10-5}[/tex] = [tex]8^{5}[/tex]
Additional Mathematics
Answer:
a = 1000, p = 10
Step-by-step explanation:
Given
y = - 3lg x + lg a
in the form y = mx + c ( m is the slope and c the y- intercept )
From the graph
(a)
c = 3 , then
lg a = 3 , that is
a = 10³ = 1000
(b)
Replace x by p and y = 0 in the equation
0 = - 3lg p + 3 ( subtract 3 from both sides )
- 3 = - 3lg p ( divide both sides by - 3 )
1 = lg p
p = 10 [ [tex]log_{10}[/tex] 10 = 1 ]
How do I complete the table?
Answer:
From left to right, fill in 3.5 and 6.5
Step-by-step explanation:
Use the given formula to calculate y for the given values of x.
When x = 0.5, y = 3(0.5) + 1/0.5
y = 1.5 + 2
y = 3.5 if x = 0.5
When x = 2, y = 3(2) + 1/2
y = 6 + 0.5
y = 6.5 if x = 2
Find the measure of the indicated angle to the nearest degree using trig functions. (if you can also give me step by step on how to get the answer that would be great)
A) 21°
C) 20°
B) 70°
D) 9°
Answer:
A ; 21
Step-by-step explanation:
Here, the side facing the right angle is the hypotenuse and it has a measure of length 42
The side facing the missing angle is the opposite and it has a length of 15
The trigonometric ratio that connects the hypotenuse and the opposite is the sine
The sine of an angle is the ratio of the opposite to the hypotenuse
Thus;
sine ? = 15/42
sine ? = 0.357
? = arc•sim 0.357
? = 21 degrees
Rewrite the equation by completing the square.
Answer:
4(x - [tex]\frac{1}{2}[/tex] )² = 0
Step-by-step explanation:
Given
4x² - 4x + 1 = 0 ( factor out 4 from the first 2 terms )
4(x² - x) + 1 = 0
To complete the square
add/subtract ( half the coefficient of the x- term)² to x² - x
4(x² + 2(- [tex]\frac{1}{2}[/tex] )x + [tex]\frac{1}{4}[/tex] - [tex]\frac{1}{4}[/tex] ) + 1 = 0
4(x - [tex]\frac{1}{2}[/tex] )² - 1 + 1 = 0
4(x - [tex]\frac{1}{2}[/tex] )² = 0
Can someone help me with this math homework please!
Answfirst one
Step-by-step explanation:
hope it helps thank u
Answer:
first one
Step-by-step explanation:
2 students have the same age but different heights.
since age is the input and height is the output. in order to be a function one must have exact one output for one input.
since the heights of students in Tessa 's class are not a function of their ages (one input must have two outputs) two students of same age must have different heights.
FOR EASY BRAINLIEST ANSWER QUESTION BELOW!
1. Solve each word problem .twice a number added three times the sum of the number and 2 is more than 17. Find the numbers that satisfy condition
Answer:
x > 23/5
Step-by-step explanation:
2x+ 3(x+2)>17
2x + 3x + 6 >17
5x >23
x > 23/5
factories ((x+2)+3x+6. 2a(a-1)-a+1
Answer:1. = 4x+8
2. 2a²-a+1
Step-by-step explanation:
1. ((x+2)+3x+6. 2. 2a(a-1)-a+1
((x+2)+3x+6
= x+2+3x+6
= 4x+8
2a(a-1)-a+1
2a²-2a-a+1
2a²-a+1
WILL MARK AS BRAINLIEST. PLS HLP MEEE
A claim is reviewed for MOHS surgery on the foot that was performed in 1 stage with 6 tissue blocks. The claim was reported with 17311, 17312-51, 17312-51. Is this correct
Answer:
17311, 17315
Step-by-step explanation:
Explanation,
Mohs surgery, also known as chemosurgery, created by a general surgeon, Dr. Frederic E. Mohs, is performed to remove complex or ill-defined cutaneous malignancy.List Of CPT Codes For Mohs Surgery
CPT Code 17311 and CPT Code 17313 are the base codes for the range of this surgery. CPT Code 17312, CPT Code 17314, and CPT Code 17315 are the add-on codes for this range.
Description Of CPT Code 17311
Moh’s micrographic technique, including removal of all gross tumor, surgical excision to tissue specimens, mapping, color coding of specimens, microscopic examination of specimens by the surgeon, and histopathologic preparation including routine stain(s) (eg. Hematoxylin and eosin, toluidine blue), head, neck, hands, feet genitalia, or any location with surgery directly involving muscle, cartilage, bone, tendon, major nerves, or vessels; first stage, up to 5 tissue blocksDescription Of CPT Code 17315 (addon)
CPT Code 17315 may be used to report each block after the first 5 blocks for any single-stage.
Moh’s micrographic technique, including removal of all gross tumor, surgical excision of tissue specimens, mapping color coding of specimens, microscopic examination of specimens by the surgeon, and histopathologic preparation including routine stains(s) (eg. Hematoxylin and eosin, toluidine blue), each additional block after the first 5 tissue blocks, any stage (List separately in addition to code for primary procedure)Extras
Description Of CPT Code 17312 (addon)
Each additional stage after the first stage, up to 5 tissue blocks (List separately in addition to code for primary procedure)
Description of CPT Code 17313
Moh’s micrographic technique, including removal of all gross tumor, surgical excision of tissue specimens, mapping, color coding of specimens, microscopic examination of specimens by the surgeon, and histopathologic preparation including routine stains(s) (eg. Hematoxylin and eosin, toluidine blue), of the trunk, arms, or legs; first stage, up to 5 tissue blocks
Description Of CPT Code 17314 (addon)
Each additional stage after the first stage, up to 5 tissue blocks (List separately in addition to code for primary procedure).
Solve for x. Round to the nearest tenth of a degree, if necessary
Answer is x=50.1
Step 1
Tanx=opposite/adjacent
Step2
Tanx=6.1/5.1
x=arctan(6.1/5.1)
x=50.1
Answer in degrees as required
