1)Determine the hydroxide concentration in a 0.5M of hydrochloric acid? 0.5M of potassium hydroxide.

2)What is the hydroxide ion concentration of a solution if the pH is 5.36?

3)what is the concentration of a hydrochloric acid solution if 3.5mL are needed to neutralize 7.6mL of 0.25M sodium hydroxide?

4) write the bronsted- Lowry reaction between ammonia and sulfuric acid. Label the acid, base, and their conjuagtes.

Answer:

2.7

Explanation:

The equation of the reaction is

3 BaCl2 + Al2(SO4)3 = 3 BaSO4 + 2 AlCl3

So, frok the coefficients of the equation, the answer is 2.7

2.67 moles of  aluminum chloride can be produce if we have 4.0 moles of aqueous barium chloride, and we mix this with aluminum sulfate solution.

The balanced chemical reaction is :

3BaCl₂ + Al₂(SO₄)₃ ---> 3BaSO₄ + 2AlCl₃

When aqueous barium chloride is mixed with aluminum sulfate solution, a double displacement reaction occurs. The barium ions from barium chloride react with the sulfate ions from aluminum sulfate to form insoluble barium sulfate  precipitate. At the same time, the aluminum ions  from aluminum sulfate react with the chloride ions  from barium chloride to form aluminum chloride.

Given :

Number of Moles of BaCl₂ = 4.0 moles

From the balanced chemical reaction,moles of AlCl₃:

= (4.0 moles BaCl₂) (2 moles AlCl₃/3 moles BaCl₂)

= 2.67 moles AlCl₃

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Answer:

d

Explanation:

d

Answer:

B.) 1.3 atm

Explanation:

To find the new pressure, you need to use Gay-Lussac's Law:

P₁ / T₁ = P₂ / T₂

In this equation, "P₁" and "T₁" represent the initial pressure and temperature. "P₂" and "T₂" represent the final pressure and temperature. After converting the temperatures from Celsius to Kelvin, you can plug the given values into the equation and simplify to find P₂.

P₁ = 1.2 atm                                    P₂ = ? atm

T₁ = 20 °C + 273 = 293 K              T₂ = 35 °C + 273 = 308 K

P₁ / T₁ = P₂ / T₂                                             <----- Gay-Lussac's Law

(1.2 atm) / (293 K) = P₂ / (308 K)                  <----- Insert values

0.0041 = P₂ / (308 K)                                   <----- Simplify left side

1.3 = P₂                                                         <----- Multiply both sides by 308

The identity of a metal that has a mass of 27.0g and a volume of 10.0cm is Aluminium. That is option B.

Molar mass is defined as the mass in grams of one mole of an element. This is measured in grams/mole of that substance.

The metal that is 27.0 g and a volume of 10.0 cm3 is aluminium because aluminium is 27 times heavier than 1/12th of the mass of carbon-12 atom.

Therefore, the identity of a metal that has a mass of 27.0g and a volume of 10.0cm is Aluminium.

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Answer:

BeCO3 will hydrolyze in an aqueous medium, yielding a basic solution.

Explanation:

In accord with the rules of salt hydrolysis, the cation [tex]Be^{2+}[/tex] can hydrolyze. The anion [tex]CO_{3} ^{2-}[/tex] can also hydrolyze, given that the resulting conjugate acid is weak.

Given that both ions hydrolyze, the Ka (acid ionization constant) and Kb (Base ionization constant) of each reactant (or product [that is, the conjugate acid and base for each ion]) must be compared.

Using the web (hopefully some sort of reference table has been provided to you):

Ka (for Be^2+) = [tex]3 * 10^{-7}[/tex]

Kb (for CO3^2-) = [tex]\frac{Kw (water)}{Ka (HCO3)}[/tex]

= [tex]\frac{1*10^{-14}}{4.7*10^{-11}}[/tex]

= [tex]2.1 * 10^{-4}[/tex]

The Kb > Ka, so the solution will be basic.

Hope this helps! My apologies if this answer is incorrect, I have not done this type of problem in a while.

Answer:

copper - 52 (or Cu - 52)

⁵²Cu

Explanation:

Isotopes are different atoms of the same element that differ in the number of neutrons. Therefore, you can determine which element this is by examining the number of protons. All atoms with 29 protons are copper (Cu).

The mass number is the total number of protons and neutrons in an atom. Therefore, the mass number of this isotope is 52 (29 + 23 = 53). When writing an elemental symbol, the mass number is found on the top left.

As such, the name of this isotope is copper - 52 (or Cu - 52) and the symbol is ⁵²Cu.

0.5376 g is the minimum mass of sodium sulfite that we should add.

Molarity (M) is defined as the number of moles of solute dissolved in 1L of solution. Molarity is also known as Molar concentration. The S.I unit of Molarity is molar (M) or mol/L.

The conversion sequence is

mL solution → L solution →  mol → g

[tex]80\ mL \times \frac{1\ L}{1000\ mL} \times \frac{0.04\ \text{mol Calcium nitrate solution}}{L} \times \frac{168\ \text{Calcium nitrate solution}}{\text{mol Calcium nitrate solution}}[/tex]

= 0.5376 g

Thus from the above conclusion we can say that 0.5376 g is the minimum mass of sodium sulfite that we should add.

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Answer:

to launch aerials and also causes the explosions necessary for special effects like noise or colored light.

Explanation:

Answer:

3.) 51.7 L

Explanation:

To find the volume, you need to use the Ideal Gas Law:

PV = nRT

In the equation,

-----> P = pressure (kPa)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas constant (8.314 kPa*L/mol*K)

-----> T = temperature (K)

First, you need to convert the temperature from Celsius to Kelvin. Then, you can plug the given values into the equation and simplify to find "V".

P = 68.0 kPa                          R = 8.314 kPa*L/mol*K

V = ? L                                    T = 27.00 °C + 273 = 300 K

n = 1.41 moles

PV = nRT                                                              <----- Ideal Gas Law

(68.0 kPa)V = (1.41 moles)(8.314 kPa*L/mol*K)(300 K)      <----- Insert values

(68.0 kPa)V = 3516.822                                      <----- Multiply right side

V = 51.7                                                                <----- Divide both sides by 68.0

Taking into account the definition of dilution, the answer is "The volume of stock solution used is less than 3 Liters."

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

In this case, you know:

Replacing in the definition of dilution:

10 M× Vi= 1 M× 3 L

Solving:

Vi= (1 M× 3 L)÷ 10 M

Vi= 0.3 L

In summary, to prepare 3 Liters of 1 M solution, you need 0.3 L of the 10 M concentration stock solution and dilute to 3 L. Therefore, the answer is "The volume of stock solution used is less than 3 Liters."

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Answer:

D.) 2.5 moles

Explanation:

To find the moles of H₂, you need to multiply the given value by the mole-to-mole ratio. This ratio consists of the coefficients in front of the relevant molecules. It is important to arrange the ratio in a way that allows for the cancellation of units.

1 Mg + 2 HCl -----> MgCl₂ + 1 H₂
^                                            ^

2.5 moles Mg            1 moles H₂
-----------------------  x  ---------------------  =  2.5 moles H₂
                                   1 mole Mg

Answer:

B.) The reaction will shift to the right to produce more product.

Explanation:

When the pressure of a reaction is increased, the equilibrium shifts to the side with less moles of gas.

You can determine the moles of gas by adding the coefficients on each side of the reaction. The reactants have 4 moles of gas (1 + 3 = 4) and the products have 2 moles of gas. Since there are less moles of gas on the product side, the equilibrium will shift to that side. As such, more product will be produced.

Answer:

You can never have above 100% yield under any circumstance

To solve such this we must know the concept of chemical reaction. Therefore, the correct option is option D that is  you can never have above 100% yield under any circumstance.

Chemical reaction is a process in which two or more than two molecules collide in right orientation and energy to form a new chemical compound. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, double displacement reaction.

You can never have above 100% yield under any circumstance for any chemical reactions. Option D is the correct options among all the given options.

Therefore, the correct option is option D that is  you can never have above 100% yield under any circumstance.

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Answer:

[OH⁻] = 2.2 x 10⁻¹²

Explanation:

(Step 1)

Calculate the pH.

pH = -log[H⁺]

pH = -log[4.6 x 10⁻³]

pH = 2.34

(Step 2)

Find the pOH.

pH + pOH = 14

2.34 + pOH = 14

pOH = 11.66

(Step 3)

Calculate the [OH⁻].

[OH⁻] = 10^(-pOH)

[OH-] = 10^(-11.66)

[OH⁻] = 2.2 x 10⁻¹²

Answer:

131 atm

Explanation:

To find the new pressure, you need to use Boyle's Law:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new pressure (P₂) by plugging the given values into equation and simplifying.

P₁ = 3.88 atm                       P₂ = ? atm

V₁ = 7.74 L                           V₂ = 0.23 L

P₁V₁ = P₂V₂                                                      <----- Boyle's Law

(3.88 atm)(7.74 L) = P₂(0.23 L)                       <----- Insert values

30.0312 = P₂(0.23 L)                                      <----- Simplify left side

131 = P₂                                                          <----- Divide both sides by 0.23

Answer:

Sulfur

Explanation:

In general, elements are more reactive the more electronegative they are. The most electronegative elements are at the top-right of the periodic table. Since sulfur (S) is one unit up and one unit to the right of arsenic (As), it is considered more electronegative, and therefore more reactive, than arsenic.

The edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.

The cubic unit cell is the smallest repeating unit when all angles are 90 degrees and all lengths are equal.

The volume of the molybdenum is calculated from mass and density of the molybdenum as shown below;

V = (zm/ρN)

where;

V = (2 x 95.96) / (10.28 x 6.02 x 10²³)

V = 3.10 x 10⁻²³ cm³

a³ = V

a = (V)^¹/₃

a = ( 3.10 x 10⁻²³)^¹/₃

a = 3.142 x 10⁻⁸ cm

a = 3.142 x 10⁻¹⁰ m

a = 314.2 x 10⁻¹² m

a = 314.2 pm

Thus, the edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.

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Answer:

Correct answer is option C

70.0 g HNO3 and 30.0 g water

See the attached image.

The vapor pressure is obtained as 23.47 torr.

Given that; p = x1p°

p = vapor pressure of the solution

x1 = mole fraction of the solvent

p° = vapor pressure of the pure solvent

Δp = p°(1 - x1)

Δp =x2p°

Δp =  vapor pressure lowering

x2 = mole fraction of the  of the solute

Number of moles of  glycerol =  32.5 g/92 g/mol = 0.35 moles

Number of moles  of water = 500.0 g/18 g/mol = 27.8 moles

Total number of moles = 0.35 moles + 27.8 moles = 28.15 moles

Mole fraction of glycerol = 0.35 moles/28.15 moles = 0.012

Mole fraction of water = 27.8 moles/28.15 moles =0.99

Δp =  0.012 * 23.76 torr

Δp =  0.285 torr

p1 = p° - Δp

p1 = 23.76 torr -  0.285 torr

p1 = 23.47 torr

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Answer:

46 359 J

Explanation:

You need heat of fusion of water:   334 J/g

 and specific heat of ice : 2.093 j/g-C

120 * 334    = 40 080 J to make ice

+   120 * 2.093 * 25  = 6279 J   to chill the ice to -25 C

Total = = 46359 J

Answer:

.900 J / g-C°

Explanation:

I assume you are looking for the specific heat of the metal

Specific heat =  J / g-C

                      = 6640 J / 348 g[ (43.6 - 22.4) ] = .900 J / g-C

The specific heat of the unknown metal is approximately [tex]\rm \( 0.90 \, \text{kJ/kg\°C} \)[/tex].

To find the specific heat of the unknown metal, we can use the formula:

[tex]\rm \[ q = m \cdot c \cdot \Delta T \][/tex]

where:

[tex]\rm \( q \)[/tex] = heat absorbed by the metal (in kJ)

[tex]\rm \( m \)[/tex] = mass of the metal (in g)

[tex]\rm \( c \)[/tex] = specific heat of the metal (in kJ/kg·°C)

[tex]\rm \( \Delta T \)[/tex] = change in temperature (in °C)

Given data:

[tex]\( m = 348 \, \text{g} \)\\\( \Delta T = 43.6°C \\\\- 22.4°C = 21.2°C \)\\\( q = 6.64 \, \text{kJ} \)[/tex]

Now, let's rearrange the formula to solve for [tex]\rm \( c \)[/tex]:

[tex]\rm \[ c = \frac{q}{m \cdot \Delta T} \][/tex]

Substitute the values:

[tex]\rm \[ c = \frac{6.64 \, \text{kJ}}{348 \, \text{g} \times 21.2°C} \][/tex]

Convert the mass to kg and temperature to °C:

[tex]\rm \[ c = \frac{6.64 \, \text{kJ}}{0.348 \, \text{kg} \times 21.2\°C} \]\\\\\ c \approx 0.90 \, \text{kJ/kg\°C} \][/tex]

The specific heat of the unknown metal is approximately [tex]\rm \( 0.90 \, \text{kJ/kg\°C} \)[/tex].

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Your question is incomplete, but most probably your full question was,

A piece of unknown metal weighs 348 g. When the metal piece absorbs 6.64 kJ of heat its temperature increases from 22.4°C to 43.6°C. Determine the specific heat of this metal. What is your unknown metal?

The pH of the solution when no base is added is 0.424.

An aqueous solution's acidity or basicity can be determined using the pH scale. The pH values of acidic solutions are typically lower than those of basic or alkaline solutions.

The chemical formula of hypochlorous acid is HClO.

1 mole of HClO produces 1 mole of hydrogen ions and 1 mole of fluoride ions.

KOH (aq) + HClO (aq) → KClO (l) + H2O (l)

To calculate the pH of the solution when no base is added, we use the equation:

[tex]p_{H} = - log {H}^{+}[/tex]

We are given:

[tex]H^{+} = 0.376 M[/tex]

Putting values in the above equation, we get:

[tex]p_{H} = - log (0.376)[/tex]

[tex]p_{H}[/tex] = 0.424

Hence, the pH of the solution when no base is added is 0.424

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Answer:

C.) 42 grams NaOH

Explanation:

To find the mass of NaOH, you need to (1) find the moles (using the molarity equation) and then (2) convert moles to grams (using the molar mass).

(Step 1)

250.0 mL / 1,000 = 0.2500 L

Molarity = moles / volume (L)

4.2 M = moles / 0.2500 L

1.05 = moles

(Step 2)

Molar Mass (NaOH): 22.990 g/mol + 15.998 g/mol + 1.008 g/mol

Molar Mass (NaOH): 39.996 g/mol

1.05 moles NaOH           39.996 g
-----------------------------  x  ------------------  =  42 grams NaOH
                                           1 mole

Answer:D. In order to restore equilibrium, the reaction shifts right, towards products

Explanation:

The equilibrium shift if the HCl concentration is increased to the product.

Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)

If the concentration of a substance is changed, then the equilibrium will shift in such a way that it minimise the effect of change which occur. If we increase the concentration of a reactant, then the equilibrium will shift to minimize the changes in the direction of the reaction which uses the reactants, so that the reactant concentration decreases.

Thus, we concluded that with increase in the concentration of reactant equilibrium shift forward.

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Answer:

uestion

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I think we make a mistake when we consider that data are qualitative if they come from applying qualitative methods and techniques or if they are collected in qualitative researches. I think we make the same mistake when we consider quantitative all data collected through, for example, questionnaires.

I think we have to consider the qualitative or quantitative character of data looking exclusively at data. Are they numeric? Are they textual or visual?

I think (as Traian Rotariu argues) that quantitative data are numeric and that qualitative data are textual or visual and that we could gather quantitative and qualitative data with each and every method and technique being it qualitative or quantitative.

For example most of the data gathered with questionnaires are qualitative in their primary form: opinions, gender, preferences etc. and just a few are quantitative in their primary form: income, age, children's number And more

Here, Iodine is going under oxidation and Sulphur  reduction.

8[tex]NaI[/tex](aq) + 5  (aq) ---> 4(aq) +  (g) + 4 [tex]Na_{2} SO_{4}[/tex] (aq) + 4[tex]H_{2} O[/tex](l)

the oxidation state of I in NaI is -1 whereas, it is 0 in [tex]I_{2}[/tex] .

in the same way , the oxidation state of S in [tex]H_{2} SO_{4}[/tex] is +6  whereas it is -2 in [tex]H_{2} S[/tex].

what is oxidation?

oxidation is when the element loses its electron ( I went from -1 to 0, losing an electron ).

what is reduction ?

reduction is when the element gains its electron ( S went from +6 to -2, gaining 8 electron ).

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a)λ = 1.43 x 10⁻⁷ m, b)λ =5 x 10⁻¹⁹ and, c)λ = 1.99 x 10⁻⁷ m.

a) The wavelength of the photon needed to excite an electron from E1 to E4:

ΔE = hc/λ

(-1 + 15) x 10⁻¹⁹ = 6.63 x 10⁻³⁴ x 3 x 10⁸ / λ

λ = 1.43 x 10⁻⁷ m

b) The energy (in joules) a photon must have in order to excite an electron from E2:

= (-5 + 10) x 10⁻¹⁹

λ = 5 x 10⁻¹⁹

c) An electron drops the E3 level to the E1 level, and the atom is said to undergo emission:

Change in energy = 10 x 10⁻¹⁹ J

10 x 10⁻¹⁹ = 6.63 x 10⁻³⁴ x 3 x 10⁸ / λ

λ = 1.99 x 10⁻⁷ m

The wavelength of the photon needed to excite an electron from E1 to E4 is 1.43 x 10⁻⁷ m.

The energy (in joules) a photon must have in order to excite an electron from E2 is 5 x 10⁻¹⁹.

An electron drops the E3 level to the E1 level, and the atom is said to undergo emission is 1.99 x 10⁻⁷ m.

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B. Heating up the reaction will increase the entropy of a reaction.

Entropy is the measure of the degree of disorderliness of a system.

Entropy is also the measure of a system's thermal energy per unit temperature that is unavailable for doing useful work.

S = ΔH/T

where;

Entropy increases in reactions in which the total number of product molecules is greater than the total number of reactant molecules.

However, entropy increases as temperature increases. Thus, heating up the reaction will increase the entropy of a reaction.

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