Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration.
1. Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration. The valence electrons are the outermost electrons in an atom's electron shell, and they are crucial in determining the chemical properties and reactivity of elements.
2. Evidence from data tables can be shown by examining the electron configuration and the group and period numbers of various elements on the periodic table. Here is a simplified example:
Element | Electron Configuration | Group | Period |
--------------------------------------------
Hydrogen | 1s^1 | 1 | 1 |
Lithium | [He] 2s^1 | 1 | 2 |
Carbon | [He] 2s^2 2p^2 | 14 | 2 |
Oxygen | [He] 2s^2 2p^4 | 16 | 2 |
Neon | [He] 2s^2 2p^6 | 18 | 2 |
--------------------------------------------
3. The evidence from the data table supports the claim that the arrangement of elements on the periodic table is based on valence electrons.
- Group Trend: Elements within the same group (vertical columns) share the same number of valence electrons. In the example table, Hydrogen, Lithium, and Neon are all in Group 1, indicating they have 1 valence electron.
- Period Trend: Elements within the same period (horizontal rows) have the same number of electron shells. In the example table, Hydrogen and Lithium are in Period 1, indicating they have their valence electron in the first energy level. Carbon, Oxygen, and Neon are in Period 2, indicating they have their valence electrons in the second energy level.
By examining the electron configurations, group numbers, and period numbers, we can clearly see the trends and patterns in the number of valence electrons for both groups and periods on the periodic table. This evidence supports the claim that the arrangement of elements on the periodic table is based on their valence electrons, which play a crucial role in determining their chemical behavior and properties.
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Traveler A takes the train from New York to Boston. Traveler B flies from Boston to New York.
Describe how the size and direction of displacement of Traveler A is different from the size and
direction of displacement of Traveler B.
If two forces act at right angles to each other, the magnitude of the vector sum of the forces can be found by
Answer:
The formula for the hypotenuse via the Pythagorean Theorem
Explanation:
Notice that if the forces are perpendicular, since they add via the "parallelogram rule", the length of the diagonal of the rectangle they make as one constructs the parallelogram, carries the actual quantity we are looking for.
The diagonal divides the rectangle formed by the two adding forces, in two right angle triangles, for which the hypotenuse is the diagonal of the rectangle. As such, the magnitude of it can be derived via the Pythagorean Theorem, looking for the length of the hypotenuse.
Arthur made a labeling the diagram of the three stages of the cell cycle.
What is the error in the diagram
answer;aExplanation:
An unhealthy diet is to cardiovascular disease as______
is to cancer.
1. obesity
2. smoking
3. poor hygiene
Answer:
2- smoking
because smoking caused lung cancer.
Answer:
Obesity
Explanation:
Obesity the condition of being grossly fat or overweight mostly causes cardiovascular diseases such as coronary heart disease (CHD)
wo cars are moving in the same velocity.Car A has a mass of 95 kilograms while car B has a mass of 110 kilograms.How much internia does the car b have compared to car a
Explanation:
Intertia of an object is defined as its tendency to remain in the state or rest or in state of uniform motion. It is basically the measure of mass of an object. The greater the mass of an object, greater will be its tendency to change its state of motion or state or rest. Also, lesser the mass of the object, lesser will be its tendency to change its state of motion or state of rest.
In this problem, car A has a mass of 95 kg and car B has a mass of 110 kg. Car B has more mass than car A, it will have more inertia than car A.
Hence, inertia of car B is 15 more than the inertia of car A.
Jordan wants to know the difference between using a 60-W and 100-W lightbulb in her lamp. She calculates the energy it would take to use each bulb for 30 s by using this equation:
Power = Energy transferred (J)/time (s)
What is the difference in the amount of energy transferred by the two bulbs during this time?
A. 40 J
B. 1200 J
C. 1800 J
D. 3000 J
Answer:
B. 1200 J
Explanation:
Hello.
In this case, given the powers, we compute the energy transferred as shown below:
[tex]E=P*t\\\\E_1=60J/s*30s=1800J\\\\E_2=100J/s*30s=3000J\\\\Difference=3000J-1800J\\\\Difference=1200J[/tex]
Therefore, answer is B. 1200 J .
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A car accelerates from rest to 31.8 m/s in 6 sec. What is the
acceleration?
See this solution.
Click on the picture to view full solution.
Hope it helps
A car is traveling at a speed of 70 km/hr for 2 hours
Answer:
the answer is 140
Explanation:
70 × 2 = 140km 2hr
the car will travel 140 km in 2 hours.
Question 2
If a rocket travels 9,684 km in 2.4 hours, what is its speed in km/hr?
Answer:
4,035 km/hr.Explanation:
velocity = distance / time
where distance = 9684 km
time = 2.4 hours
plugin values into the formula:
distance = 9,684 km
2.4 hours
= 4,035 km/hr.
Answer:
4,035/kmph
Explanation:
I just found the unit rate by dividing 9684 by 2.4
You conduct an experiment to see how different colors of light affect the growth of sunflowers. At the end of each week, you measure the height of each flower and record the data in your journal.
What is the independent variable in the above example?
The independent variable in the given question will be colors of light.
What is Mathematical function ?
Mathematical function is the representation of relation between independent variables and dependent variables. Generally used to make equations which further can be used to represents in graphical form.
Here, the change in height of tree dependents upon the color of light according to the different wavelength produced by different color of light. A Mathematical function can also be formed between color of light and height of trees.
Therefore, the colors of light is the independent variable and height of tree is the dependent variable.
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Gravity causes objects to be attracted to one another. This attraction keeps our feet firmly planted on the ground and causes the moon to orbit the earth. The force of gravitational attraction is represented by the equation
F=Gm1m2r2
where F is the magnitude of the gravitational attraction on either body, m1 and m2 are the masses of the bodies, rrr is the distance between them, and GGG is the gravitational constant. In SI units, the units of force are kg⋅m/s^2, the units of mass are kg, and the units of distance are m. For this equation to have consistent units, the units of G must be which of the following?
a. kg3m⋅s^2
b. kg⋅s2m^3
c. m3kg⋅s^2
d. mkg⋅s^2
Answer:
C. the units of G is m³/kg.s²
Explanation:
Given;
magnitude of gravitational force, [tex]F = \frac{Gm_1m_2}{r^2}[/tex]
From the equation above, gravitational constant G is given as;
[tex]F = \frac{Gm_1m_2}{r^2} \\\\G = \frac{Fr^2}{m_1m_2}\\\\G = (F)(\frac{1}{m_1m_2})(r^2) \\\\G = (\frac{kg.m}{s^2})(\frac{1}{kg^2} )(m^2)\\\\G = \frac{m^3}{kg.s^2}[/tex]
Thus, the correct option is "C" G = m³/kg.s²
How are temperature and average kinetic energy related? Explain.
Answer: When a substance is heated, some of the absorbed energy is stored within the particles, while some of the energy increases the motion of the particles.
Explanation: Increase in temperature means an increase in Kinetic energy.
Einstein’s theory of general relativity was published in 1916 it became fully accepted by scientists in the 1960s and is currently the best explanation of gravity, ignore c filled in
Answer:
It is C
Explanation:
i just answered it on apex
Answer:
C. More evidence needed to be gathered to validate the ideas in the theory.
Explanation:
A P E X
a balloon brusts when more air is filled
Answer:
It expands due to the elasticity of the rubber. but wen , the rubber is expanded to its maximum point and cannot be stretched further, it will burst because there will be no space for the rubber to accommodate the air.
Explanation:
A block of mass m = 4.80 kg is suspended as shown in the diagram below. Assume the pulley to be frictionless and the mass of the strings to be negligible. If the system is in equilibrium, what will be the reading of the spring scale in newtons?
Answer:
W = 47.04 N
Explanation:
It is given that,
A block of mass 4.8 kg is suspended by the pulley and it is assumed that it is frictionless and the mass of the strings to be negligible.
We need to find the reading of the spring scale if the system is in equilibrium.
At this position, the scale reading is equal to the weight of the block such that,
W = mg, where g is the acceleration due to gravity
W = 4.8 kg × 9.8 m/s²
W = 47.04 N
So, the reading of the spring scale is 47.04 N.
A car of mass M
= 1200 kg
traveling at 65.0 km/hour
enters a banked turn covered with ice. The road is banked at an angle θ
, and there is no friction between the road and the car's tires as shown in image. Use g
= 9.80 m/s2
throughout this problem.
What is the radius r
of the turn if θ
= 20.0 ∘
(assuming the car continues in uniform circular motion around the turn)?
A car with a mass of 1200 kg enters a banked turn covered with ice at a velocity of 65.0 km/h. The road is banked at an angle of 20°. The radius of the turn is found to be 91.9 m using the equation r = v²/gtanθ.
The banked turn covered with ice A banked turn is a turn or curve in which the vehicle follows a circular path. The car of mass M=1200kg traveling at 65.0 km/h enters a banked turn covered with ice. There is no friction between the road and the car's tires. Use g=9.80m/s² throughout this problem. The road is banked at an angle of θ=20°. We have to find the radius r of the turn. Assuming the car continues in uniform circular motion around the turn, the centripetal force required to keep the car moving in a circle is given by the equation:Centripetal force, Fc = mv²/r, where, m is the mass of the car, v is the velocity of the carand,r is the radius of the turn. Since the car is moving in uniform circular motion, we can equate the centripetal force to the gravitational force. This is because the gravitational force is acting downwards, towards the centre of the circle, which is also the direction in which the centripetal force is acting. Hence we can say that Fc = mg, where,m is the mass of the car and, g is the acceleration due to gravity.Substituting the above equations for Fc and mg, we getmv²/r = mgtanθMultiplying both sides by rm, we getv² = grtanθTherefore,r = v²/gtanθwhere,v is the velocity of the car and, g is the acceleration due to gravity.Substituting the given values, we getv = 65.0 km/hour = 18.1 m/sθ = 20.0°g = 9.80 m/s²Therefore,r = (18.1 m/s)² / (9.80 m/s² × tan 20.0°) = 91.9 mSummary: The banked turn is a turn or curve in which the vehicle follows a circular path. A car of mass M = 1200 kg traveling at 65.0 km/hour enters a banked turn covered with ice. The road is banked at an angle θ = 20.0 ∘. We have to find the radius r of the turn. Assuming the car continues in uniform circular motion around the turn, the radius r can be found by using the equation r = v²/gtanθ. Substituting the given values, the radius r is 91.9m.For more questions on velocity
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what is kinetic friction in a easy way to understand?
Answer:
Let's say when you are in a car and the is moving but that stands for potential energy but when it stops it's called KINETIC ENERGY. i hope that help......
Explanation:
If an object can make 10 revolutions in two minutes what’s it’s period
Answer:
12[tex]s^{-1}[/tex]
Explanation:
Period= how long for each revolution
Since we have 10 revolutions in 120 seconds.
120/10=12s
At the lowest point in the jump when the student is stationary, the extension of the bungee
cord is 35 metres.
The bungee cord behaves like a spring with a spring constant of 40 N / m.
Calculate the energy stored in the stretched bungee cord.
Given parameters:
Extension of the cord = 35m
Spring constant (K ) = 40N/m
Unknown:
The energy stored in the string = ?
Elastic potential energy is a mechanical energy form usually stored in strings.It accrues when an elastic body is stretched or undergoes extension.
mathematically, we can solve for it using the expression below;
Elastic potential energy = 0.5 x K x e²
where K is the spring constant
e is the extension
To solve this problem simply input the parameters;
Elastic Potential energy = 0.5 x 40 x 35²
= 24500J
The energy stored in the stretched bungee cord is 24500J .
If a car travels 500 m in 10 seconds how fast is it going?
O 50 m/s
O 5 m/s
O 5,000 m/s
O 5 Km/s
Answer:
50m/s
Explanation:
Divide 500 by 10 and keep same variables m/s. Hope this helps!
The center of the Hubble space telescope is 6940 km from Earth’s center. If the gravitational force between Earth and the telescope is 9.21 × 104 N, and the mass of Earth is 5.98 × 1024 kg, what is the mass of the telescope? Round the answer to the nearest whole number.
Answer:
11121.19 kg
Explanation:
Given that,
the gravitational force between Earth and the telescope is [tex]9.21\times 10^4\ N[/tex]
Mass of the Earth is [tex]5.98\times 10^{24}\ kg[/tex]
The center of the Hubble space telescope is 6940 km from Earth’s center.
We know that, the force of gravity is given by the formula as follows :
[tex]F=\dfrac{GmM}{r^2}[/tex]
m is mass of telescope and M is mass of Earth
So,
[tex]m=\dfrac{Fr^2}{GM}\\\\m=\dfrac{9.21\times 10^4\times (6940\times 10^3)^2}{6.67\times 10^{-11}\times 5.98\times 10^{24}}\\\\m=11121.19\ kg[/tex]
So, the mass off the telescope is 11121.19 kg
If a radioactive substance has a half-life of 262 years, and I have 2 grams of that substance initially, how much would I have left after 262 years? I
A horizontal spring is attached to a wall at one end and a mass at the other. The mass rests on a frictionless surface. You pull the mass, stretching the spring beyond the equilibrium position a distance A, and release it from rest. The mass then begins to oscillate in simple harmonic motion with amplitude A. During one period, the mass spends part of the time in regions where the magnitude of its displacement from equilibrium is greater than (0.66)A— that is, when its position is between −A and(−0.66)A, and when its position is between (0.66)A and A. What total percentage of the period does the mass lie in these regions?
Answer:
54%
Explanation:
So, we have that the "magnitude of its displacement from equilibrium is greater than (0.66)A—''. Thus, the first step to take in answering this question is to write out the equation showing the displacement in simple harmonic motion which is = A cos w×t.
Therefore, we will have two instances t the displacement that is to say at a point 2π/w - a2 and the second point at a = a2.
Let us say that 2π/w = A, then, we have that a = A cos ^-1 (0.66)/2π. Also, we have that a2 = A/2 - A cos^- (0.66) / 2π.
The next thing to do is to calculate or determine the total length of of the required time. Thus, the total length is given as:
2a1 + ( A - 2a2) = 2A{ cos^-1 (0.66)}/ π.
Therefore, the total percentage of the period does the mass lie in these regions = 100 × {2a1 + ( A - 2a2) }/A = 2 { cos^-1 (0.66)}/ π × 100 = 54%.
Thus, the total percentage of the period does the mass lie in these regions = 54%.
A person travels by car from one city to another with different constant speeds between pairs of cities. She drives for 35.0 min at 100.0 km/h, 10.0 min at 55.0 km/h, and 45.0 min at 35.0 km/h and spends 35.0 min eating lunch and buying gas.
(a) Determine the average speed for the trip. km/h
(b) Determine the distance between the initial and final cities along the route. km
Explanation:
Solution:
Let the time be
t1=35min = 0.58min
t2=10min=0.166min
t3=45min= 0.75min
t4=35min= 0.58min
let the velocities be
v1=100km/h
v2=55km/h
v3=35km/h
a. Determine the average speed for the trip. km/h
first we have to solve for the distance
S=s1+s2+s3
S= v1t1+v2t2+v3t3
S= 100*0.58+55*0.166+35*0.75
S=58+9.13+26.25
S=93.38km
V=S/t1+t2+t3+t4
V=93.38/0.58+0.166+0.75+0.58
V=93.38/2.076
V=44.98km/h
b. the distance is 93.38km
Geckos can walk on walls and ceilings—at least some of the adhesion is due to static electricity. Gecko feet are covered with microscopic hairs. When these hairs rub against a surface, charges separate, with the hair developing a positive charge and negative charge forming below the surface. There is an attractive force between the separated charges. This is an effective means of adhering to a surface, but it would not be without cost; two planes of charge are like two charged plates of a capacitor, which takes energy to charge. Doubling the amount of charge on each surface will increase the at- tractive force, but will also increase the energy required to separate the charge. By what factor will this energy increase?
Answer:
U = 4 U₀
we see that the gecko must use 4 times more energy to double the force
Explanation:
For this exercise they indicate that we can approximate the situation to a charged capacitor, so the stored energy is
U = Q² / 2C
where C is the capacitance that does not change since it is the same gecko and Q is the stored charge. In the initial state
U₀ = Q₀² /2C
They tell us that the load is doubled
Q = 2Q₀
where Qo is the initial charge; the new energy is
U = (2Q₀)² / 2C
U = 4 Q₀² / 2C
U = 4 U₀
where U₀ is the initial energy
Therefore we see that the gecko must use 4 times more energy to double the force
1. How are each of Newton’s Laws of motion demonstrated
in the flight of an airplane?
Newton’s Law of Inertia:
Newton’s Law of Acceleration:
Newton’s Law of Action / Reaction:
Answer:
Newton's law of inertia - His first law states that every object remains at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. ... This is the first part cited in Newton's first law; "there is no net force on the airplane and it travels at a constant velocity in a straight line."
Newton's law of acceleration - "a net external force changes the velocity of the object. The drag of the aircraft depends on the square of the velocity. So the drag increases with increased velocity."
Newton's law of Action/Reaction - "As a plane flies, the force of the air hitting the plane is always equal and opposite to the force of the plane pushing against the air. The force generated by the engine pushes against air while the air pushes back with an equal and opposite force."
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The force of air resistance acts to oppose the motion of an object moving through the air. A ball is thrown upward and eventually returns to the ground.
a. As the ball moves upward, is the net force that acts on the ball greater than, less than, or equal to its weight?
1. The net force will be greater than the weight of the ball.
2. The net force will be lesser than the weight of the ball.
3. The net force will be equal to the weight of the ball.
b. Repeat part (a) for the downward motion of the ball.
1. net force will be greater than the weight of the ball
2. net force will be lesser than the weight of the ball
3. net force will be equal to the weight of the ball
Answer:
a. As the ball moves upward, is the net force that acts on the ball greater than, less than, or equal to its weight?
1. The net force will be greater than the weight of the ball.
b. Repeat part (a) for the downward motion of the ball.
3. net force will be equal to the weight of the ball
Explanation:
True or false. ciliary muscles are responsible for accommodation of the eye.
Answer:
true
Explanation:
The ciliary muscle is a smooth muscle ring that controls accommodation by altering the shape of the lens
As shown in the figure below, a seal and the penguin are playing a fun game of tag. The penguin first swims rightward
6 m then dodges leftwards another
10
Answer:
Explanation:
Average velocity = Displacement/Time
ΔS = -10+6
ΔS = -4m
Given tme = 30s
Average velocity = -4/30
Average velocity = -0.13m/s
Average speed = Distance/Time
Total distance covered = 10m+6m
Total distance covered = 16m
Average speed = 16/30
Average speed = 0.53m/s
Two point charges, with charge magnitudes q and ????, are placed a distance r apart. In this arrangement, each point charge experiences a force of magnitude F. In the three scenarios, q, ????, and r are changed to some multiple of their original values. In each case, fill in the missing value on one of the variables that will result in a force between the point charges that is equal in magnitude to the original F.
Original q Q r
Scenario 1 2q ...Q 4r
Scenario 2 ...q 2Q (1/2)r
Scenario 3 (3/2)q (3/8)Q ...r
Answer:
1) Q ’= 8 Q , 2) q ’= 16 q , 3) r ’= ¾ r
Explanation:
For this exercise we will use Coulomb's law
F = k q Q / r²
It asks us to calculate the change of any of the parameters so that the force is always F
Original values
q, Q, r
Scenario 1
q ’= 2q
r ’= 4r
F = k q ’Q’ / r’²
we substitute
F = k 2q Q ’/ (4r)²
F = k 2q Q '/ 16r²
we substitute the value of F
k q Q / r² = k q Q '/ 8r²
Q ’= 8 Q
Scenario 2
Q ’= Q
r ’= 4r
we substitute
F = k q ’Q / 16r²
k q Q / r² = k q’ Q / 16 r²
q ’= 16 q
Scenario 3
q ’= 3/2 q
Q ’= ⅜ Q
we substitute
k q Q r² = k (3/2 q) (⅜ Q) / r’²
r’² = 9/16 r²
r ’= ¾ r
