The spacing is given as 22.5
How to solve for the spacingBurden distance = [2 x 0.9 / 2.65 + 1.5] x 4
= Burden distance is given as 9 ft
The stiffness ratio is 27 / 9
= 3
T depth = 6 ft
J depth = 3 ft
Spacing S = 27 + 2 x9 / 3
= 15 ft
Actual spacing =
15 ± 1.15
= 13.85 , 16.25
c olumn length = 27 + 3 - 6
= 24
explosive per blast hole
= 24 x 4.9
= 117 . 6
(2 x 1/4)² / 28
= 0.180
27 x 0.18 + 3 x 0.18
= 5.4
Spacing = 10 x 2.25
= 22.5
Read more on blast plan here https://brainly.com/question/29345048
#SPJ4