Answer:
Explanation:
By the speed addition theorem:
V = 20 - 5 = 15 km/h
Suppose you need average speed of 100 km/h to arrive at a certain destination on time. However, trafficlimits your average speed to only 60 km/h during the first half of the trip's distance. What must youraverage speed be in the second half of the trip to be on time?
Answer:
140 km/h
Explanation:
If you have a speed of v1 the first half of the trip and a speed of v2, the second half of the speed, the average speed will be
[tex]v_{\text{avg}}=\frac{v_1+v_2}{2}[/tex]Solving for v2, we get:
[tex]\begin{gathered} 2v_{\text{avg}}=v_1+v_2 \\ 2v_{\text{avg}}-v_1=v_2 \\ v_2=2v_{\text{avg}}-v_1 \end{gathered}[/tex]Then, we can replace the average speed Vavg = 100 km/h and the speed of the first half v by 60 km/h
[tex]\begin{gathered} v_2=2(100\operatorname{km}/h)-60\operatorname{km}/h \\ v_2=200\operatorname{km}/h-60\operatorname{km}/h \\ v_2=140\operatorname{km}/h \end{gathered}[/tex]Therefore, the speed in the second half of the trip must be 140 km/h
A book of mass 0.5 kg is dropped from a height of 2.8 m. How much mechanical energy does it have right before it hits the ground? (Assume there is no air resistance.) Acceleration due to gravity is g = 9.8 m/s2.
The mechanical energy the book has right before it hits the ground is equal to 13.72 J.
What is mechanical energy?Mechanical energy can be described as the sum of potential energy and kinetic energy. The law of conservation of mechanical energy states that for an isolated system is only subjected to the conservative forces then its mechanical energy is constant.
The mechanical energy of the object is conserved during the fall in absence of air resistance. When the book is just about to hit the ground, the initial gravitational potential energy at the beginning of the fall will be completely converted into kinetic energy.
Therefore, the mechanical energy at the beginning of the fall will be equal to the mechanical energy just before the book hits the ground.
The mechanical energy in starting is all gravitational potential energy:
U = mgh
where m = 0.5 kg is the mass of the book, g = 9.8 m/s² is the acceleration of gravity, h = 2.8 m is the height above the ground.
U = 0.5× 9.8×2.8
U = 13.72 J
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12) A bus makes three displacements in the following order:
1) 38 mi, 48° east of north
2) 79 mi, 46 west of north; and
3) 55 mi, south-east
a. Find the X and Y components of displacement D₁.
b. Find the X and Y components of displacement D2.
Find the X and Y components of displacement D3.
d. Find the magnitude and direction of the resultant vector
The values of the displacement and direction of the bus, calculated using vectors are:
a. The X component of D₁ is [tex]\overset{ \rightharpoonup}{D_{1x}}}[/tex] ≈ 28.24·i
The Y component of D₁ is [tex]\overset{ \rightharpoonup}{D_{1y}}}[/tex] ≈ 25.43·j
b. X component: [tex]\overset{ \rightharpoonup}{D_{2x}}}[/tex] ≈ -56.83·i
Y component: [tex]\overset{ \rightharpoonup}{D_{2y}}}[/tex] ≈ 57.88·j
c. X component: [tex]\overset{ \rightharpoonup}{D_{3x}}}[/tex] ≈ 38.89·i
Y component: [tex]\overset{ \rightharpoonup}{D_{3y}}}[/tex] ≈ -38.89·j
d. The magnitude of the resultant force is approximately 45.6 miles
The direction is approximately 13.1° east of north
What is the magnitude of a vector?The magnitude of a vector indicates the length of the vector.
12) Whereby the indicated direction of the bus are as follows and taking the direction of north and east as positive, we have:
1) D₁ = 38 mi, 48° east of north
2) D₂ = 79 mi, 46° west of north
3) D₃ = 55 mi, south–east
a. The X and Y components of D₁ are:
The X component of D₁ is D₁ₓ = 38 mi × sin(48°) = 38 mi × cos(90° - 48°) ≈ 28.24 mi
Vectorially, [tex]\overset{ \rightharpoonup}{D_{1x}}}[/tex] ≈ 28.24·iThe Y component is: [tex]D_{iy}[/tex] = 38 mi × cos(48°) = 38 mi × sin(90° - 48°) ≈ 25.43 mi
Vectorially, [tex]\overset{ \rightharpoonup}{D_{1y}}}[/tex] ≈ 25.43·jb. The X and Y components of D₂ are found as follows:
D₂ₓ = 79 mi × sin(46°) = 79 mi × cos(90° - 46°) ≈ 56.83 mi
[tex]\overset{ \rightharpoonup}{D_{2x}}}[/tex] ≈ -56.83·iThe Y component is: [tex]D_{2y}[/tex] = 79 mi × cos(46°) = 79 mi × sin(90° - 48°) ≈ 57.88 mi
[tex]\overset{ \rightharpoonup}{D_{2y}}}[/tex] ≈ 57.88·jc. Given that the direction of D₃ is the south west direction, which is south 45° west, the X and Y components of D₃ are:
D₃ₓ = 55 mi × sin(45°) = 55 mi × cos(90° - 45°) ≈ 38.89 mi
[tex]\overset{ \rightharpoonup}{D_{3x}}}[/tex] ≈ 38.89·iThe Y component is: [tex]D_{3y}[/tex] = 55 mi × cos(45°) = 55 mi × sin(90° - 45°) ≈ 38.89 mi
[tex]\overset{ \rightharpoonup}{D_{3y}}}[/tex] ≈ -38.89·jd. The resultant vector is therefore: (28.24-56.83+38.89)·i + (25.43+57.88-38.89)·j = 10.3·i + 44.42·j
The resultant vector, [tex]\overset{ \rightharpoonup}{D}}[/tex] ≈ 10.3·i + 44.42·jThe magnitude of the resultant vector, [tex]|\overset{ \rightharpoonup}{D}}|[/tex] ≈ [tex]\sqrt{10.3^2 +44.42^2}[/tex] ≈ 45.6
The resultant vector is approximately 45.6 milesThe direction, θ is therefore:
[tex]\theta = arctan\left(\dfrac{44.42}{10.3} \right)\approx 76.9^{\circ}[/tex]The direction of the resultant is 76.9° north of east which is (90° - 76.9°) ≈ 13.1° east of north
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What exactly is the second law of thermodynamics? What does entropy mean in it?
The second law of thermodynamics state that the entropy of the universe always increases.
The entropy is the measure of the disorderness of a system. The entropy can be described as a measure of the thermal energy that can not be utilized to do work.
Thus the second law of thermodynamics means that as the energy is transferred more and more energy is wasted.
Can somone please explain difference between potential and potential energy?
Answer:
Potential basically tells us the ability of an object to do some work . And Potential energy is the amount of energy it acquires due to that Potential difference.
Explanation:
I hope it will be helpful ror you.
Calculate the net force.
A) A pipe of length 150 cm is open at both ends and a standing wave is set up with only one node between the ends. If the speed of sound is 343 m/s, find the frequency of this standing wave.
B) Take the same pipe as in the previous problem (same speed of sound), and close one of the ends. Now find the fundamental frequency.
The fundamental frequency of the standing wave when the pipe is open at both ends is 114.3 Hz.
The fundamental frequency of the standing wave when the pipe is closed at one end is 57.2 Hz.
What is the frequency of the standing wave?The fundamental frequency of the standing wave when the pipe is open at both ends is calculated as follows;
L = λ/2
where;
L is the length of the pipeλ is the wavelength of the standing waveλ = 2L
λ = 2(150 cm)
λ = 300 cm
λ = 3 m
f = v/λ
where;
f is the frequency of the standing wavev is the speed of soundλ is the wavelengthf = (343 m/s) / (3 m)
f = 114.3 Hz
The fundamental frequency of the standing wave when the pipe is closed at one end is calculated as follows;
L = λ/4
λ = 4L
λ = 4(150 cm)
λ = 600 cm = 6 m
f = v/λ
f = (343) / (6)
f = 57.2 Hz
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If the limits of human hearing are 20 Hz to 20,000 Hz, what are the sound wavelengths thatare associated with both of these two extremes, assuming the speed of sound is 345 m/s.Frequency = 20 Hz: Wavelength = 1.725 10 m
Given data:
* The value of the frequency of wave is 20,000 Hz.
* The value of wavelength of sound wave is,
[tex]undefined[/tex]A person stands at a point 245 m in front of the face of a sheer cliff. 1f the person shouts, how much time will elapse before an echo is heard? (Assume the speed of sound is 344 m/s.)
Answer: time = 1.42 seconds
Explanation:
The formula for calculating time is expressed as
time = distance/speed
From the information given,
distance of person from cliff = 245
total distance travelled by echo in returning = 245 x 2 = 490
speed of sound = 344 m/s
Thus,
time = 490/344
time = 1.42 seconds
A ball is projected horizontally from the edge of a
table that is 1.00 m high, and it strikes the floor at a
point 1.20 m from the base of the table.
a. How high is the ball above the floor when its
velocity vector makes a 45.0° angle with the
ad horizontal?
The height of the ball at the given angle is 0.18 m.
What is the time of motion of the ball?
The time of motion of the ball from the given height is calculated as follows;
h = ut + ¹/₂gt²
where;
u is the initial vertical velocity of the ball = 0t is time of motionh = ¹/₂gt²
t = √(2h/g)
t = √(2 x 1 / 9.8)
t = 0.45 s
The horizontal speed of the ball is calculated as follows;
X = vt
where;
X is the horizontal distancev = X/t
v = (1.2 m) / (0.45 s)
v = 2.67 m/s
The height of the ball at the given angle is calculated as follows;
(vsinθ)² = (usinθ) + 2gh
where;
u is the initial vertical velocity = 0(vsinθ)² = (0) + 2gh
(vsinθ)² = 2gh
h = (vsinθ)²/2g
h = (2.67 sin45)²/(2 x 9.8)
h = 0.18 m
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The height achieved by the ball will be 0.18 m above the floor when its velocity vector makes a 45° angle with the horizontal.
What is Velocity?The velocity of a vector represents the rate and direction of motion. Anything's velocity is the rate at which it moves in a single direction.
The SI unit is meter per second (m/s) and the dimension formula is M⁰L¹T⁻¹.
According to the question,
The given values are :
Initial Speed, u = 0 m/s
Height, h = 1.00 m
The horizontal distance, X = 1.2 m.
Use the equation of time of motion,
h = ut + 1/2gt²
put the values in the equation,
1 = 0 + 1/2(9.8)t²
t² = [tex]\sqrt{2/9.8}[/tex]
t = 0.45 seconds.
The ball will move horizontally at a speed of :
X = v × t
v = X/t
v = 1.2 / 0.45
v =2.67 m/s.
Now, calculate the height of the ball at a given angle,
(v sinθ)² = (u sinθ) + 2gh
(v sinθ)² = 0 + 2gh
h = (v sinθ)²/2g
h = (2.56 sin 45°)² / (2 × 9.8)
h = 0.18 m.
Hence, the height of the ball above the floor is 0.18 meters.
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Logan pushes a box with a 400n of force with a direction angle of 30 degrees, while Andrew pushes the same box with a force of 250N with a direction angle of 290 degrees.Which of the following represents the component vectors of the force applied by Andrew?
Given:
The force applied by the logan is
[tex]F=400\text{ N}[/tex]The force applied by the Andrew is
[tex]F=250\text{ N}[/tex]Required: component of force applied by the andrew.
Explanation:
first, draw the free body diagram,
from the free body diagram we can write resolve the force into two components
one along the y axis and one along the x axis
Along x axis
[tex]F\sin(290^{\circ})[/tex]Plugging the values, we get
[tex]\begin{gathered} =250\times\sin(290) \\ =250\times-0.939 \\ =-234.92\text{ N} \end{gathered}[/tex]Along y axis
[tex]\begin{gathered} F\cos(290^{\circ}) \\ =250\times\cos(290^{\circ}) \\ =250\times0.342 \\ =85.50\text{ N} \end{gathered}[/tex]Thus, the component of forces are
[tex]85.50\text{ N, }-234.92\text{ N}[/tex]and option first is correct.
pls help i’ll give brainliest!the land area of adeline's house is 235 square meters. what is this in square feet? explain and answer with solution.
Given area of the adeline's house is,
[tex]A=235m^2[/tex]As the one meter in terms of foot is,
[tex]1\text{ m =3.}2808\text{ foot}[/tex]Thus, the area can be written as,
[tex]\begin{gathered} A=235\times3.2808\times3.2808 \\ A=2529.52ft^2 \end{gathered}[/tex]Hence, the area in square feet is 2529.52 square feet.
Please select the word from the list that best fits the definition
Situation in which a mother holds most of the authority.
family
nuclear family
patriarchy
matriarchy
Answer:
Explanation:
Situation in which a mother holds most of the authority:
Matriarchy
An air traffic controller observes two airplanes approaching the airport. The displacement from the control tower to plane 1 is given by the vector A which has a magnitude of 220km and points in a direction 32 degree north of west. The displacement from the control tower to plane 2 is given by the vector B, which has a magnitude of 140km and points 65 degree east of North. (a) sketch the vectors A, B and D = A -B. Notice that D is the displacement from plane 2 to plane 1. (b) Find the magnitude and direction of the vector D
Given,
The magnitude of vector A, A=220 km
The direction of vector A, θ₁=32° north of west
The magnitude of vector B, B=140 Km
The direction of vector B, θ₂=65° east of north
(a)
(b)
The vector A is given by,
[tex]\vec{A}=Acos\theta_1(-\hat{i})+A\sin \theta_1\hat{j}[/tex]That is,
[tex]\begin{gathered} \vec{A}=-220\cos 32^{\circ}\hat{i}+220\sin 32^{\circ}\hat{j} \\ =-186.57\hat{i}+116.52\hat{j} \end{gathered}[/tex]And vector B is given by,
[tex]\begin{gathered} \vec{B}=B\sin \theta_2\hat{i}+B\cos \theta_2\hat{j} \\ =140\sin 65^{\circ}\hat{i}+140\cos 65^{\circ}\hat{j}_{} \\ =126.88\hat{i}+59.17\hat{j} \end{gathered}[/tex]Thus, vector D is given as
[tex]\begin{gathered} \vec{D}=\vec{A}-\vec{B} \\ =(-186.75-126.88)\hat{i}+(116.52-59.17)\hat{j} \\ =-313.63\hat{i}+57.35\hat{j} \end{gathered}[/tex]The magnitude of the vector D is given by,
[tex]\begin{gathered} D=\sqrt[]{(-313.63)^2+57.65^2} \\ =318.88\text{ km} \end{gathered}[/tex]The direction of vector D is given by,
[tex]\begin{gathered} \theta=\tan ^{-1}(\frac{57.65}{313.63}) \\ =10.41^{\circ} \end{gathered}[/tex]Therefore the magnitude of vector D is 318.88 km and the direction of the vector D is 10.41° north of the west.
The direction of the vector D is represented as,
1) An object located 33.9 cm in front of a lens
forms an image on a screen 8.57 cm behind
the lens.
Find the focal length of the lens.
Answer in units of cm
2) What is the magnification of the object?
Answer:
Explanation:
Given:
d = 33.9 cm
f = 8.57
___________
F - ?
G - ?
The focal length of the lens:
F = d*f / (d + f) = 33.9*8.57 / (33.9 + 8.57) ≈ 6.84 cm
The magnification of the object:
M = f / d = 8.57 / 33.9 ≈ 0.25
Select the correct answer. When a substance changes from one phase to another, which of the following events occurs? A. The substance loses or gains heat. B. The average kinetic energy of the substance changes. C. The temperature of the substance changes. D. The molecular motion of the substance changes.
When a substance changes from one phase to another, which of the following events occurs (A) The substances loses or gains heat.
A Phase change is reversible physical change that happens when a substance changes from one state of matter to the another state of matter. when substances changes from solid , liquid or gas state to different state called as phase change. Temperature can change the substance from one phase to another. for example . we can freeze the water by putting it to freezer to change it into ice and when we put it on heat it changes to liquid.
Thus, When a substance changes from one phase to another, which of the following events occurs (A) The substances loses or gains heat.
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Answer:
The substance loses or gains heat.
Explanation:
Substances can be made to change phases by fluctuating the temperature, the pressure, or both
can you just sketch or draw in coordinate plane or graph about statement as A hockey player skates at full speed then comes to a sudden stop with time and velocity.
Answer:
See below
Explanation:
See the image attached:
120 volts is run through a primary coil containing 200 turns. If the secondary coil has 610 turns, what will the new output voltage be?
We are asked to determine the output voltage of a coil with 610 turns given the number of turns and the voltage of the primary coil. To do that we will use the following formula:
[tex]\frac{V_2}{V_1}=\frac{n_2}{n_1}[/tex]Where:
[tex]\begin{gathered} n_1,n_2=\text{ number of turns of the primary and secondary coil} \\ V_1,V_2=\text{ voltage of the primary and secondary coil. } \end{gathered}[/tex]Now, we solve for V2 by multiplying both sides by V1:
[tex]V_2=\frac{n_2}{n_1}V_1[/tex]Now, we substitute the values:
[tex]V_2=\frac{610}{200}(120V)[/tex]Solving the operations:
[tex]V_2=366V[/tex]Therefore, the voltage of the secondary coil is 366V.
Not yet answered Marked out of 1.00
Which of the following statements about gravitational force, Fe, is not
correct?
Oa. The gravitational force between two objects depends on their separation.
Ob. Gravitational force is the strongest of the fundamental forces.
Oc. Gravitational forces always exist in pairs of equal magnitude.
Od. Gravitational force is an attractive force only; it is never repulsive.
a. The distance between two objects affects the gravitational force between them.
All physical things with mass are drawn to the gravitational force, which can be thought of as an attracting force. It is by far the most insignificant natural force.
The gravitational attraction, an attractive force whose magnitude is directly proportional to the masses of the two objects and inversely proportional to the square of their distance from one another, attracts all objects with mass toward one another.
According to Newtonian mechanics, the "pull" of gravity is caused by mass. There is only a pull between any two masses and every other mass. However, the fact that the magma is so hot is what causes the gravitational pull, not the magma itself.
The gravitational pull between two objects is proportional to their masses and becomes weaker as their distance from one another grows. Both things are attracted to one another equally; for example, a falling object is attracted to the Earth with a force equal to that of the Earth's attraction.
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Why does this graph have a positive slope through the first 4.5 seconds or so and then approximately zero slope till roughly 11.5 seconds?
The slope of the graphical curve in terms of change in variable along y-axis and the change in the variable along the x-axis is,
[tex]\text{slope=}\frac{Change\text{ in force of tension}}{\text{Time}}[/tex]The change in force of tension in terms of final and its initial value is,
[tex]\text{Change in force= Final value of force - Initial value of force}[/tex]As the value of force is increasing for the first 4.5 seconds.
Thus, the final value of force of is more than the initial value of force.
The change in force for the first 4.5 seconds is,
[tex]\text{change in force > 0}[/tex]Thus, the slope of the curve for the first 4.5 seconds is,
[tex]\text{Slope > 0}[/tex]Hence, the slope is positive for first 4.5 seconds.
For the further time till 11.5 seconds,
There is no change in the value of force which means the final value of force is equal to the initial value of force.
The change in force is,
[tex]\text{change in force = 0}[/tex]Hence, the slope of the c
Which option best describes light from the sun?
The sun produces only visible light.
It travels in waves with different wavelengths.
The sun only produces yellow and red light.
All light from the sun is of the same wavelength.
The option that best describes light from the sun is it travels in waves with different wavelengths.
The light from the sun travels to Earth and other parts of the solar system as waves. These waves have different wavelengths with all frequencies of Electromagnetic waves. The light is transmitted as Electromagnetic waves such as radio waves, microwaves, infrared waves, visible light, ultraviolet waves, and X-rays.
Option 1 is incorrect because the sun produces waves other than visible light. Option 3 is incorrect because the sun produces all the wavelengths of visible light from purple to red. Option 4 is incorrect because different Electromagnetic waves have different wavelengths.
Therefore, the option that best describes light from the sun is it travels in waves with different wavelengths.
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Speed (m/s) vs. Time (s) Graph
30
*K
8
10
E-F
A-B
30
43
Car's Speed vs Time
E
50
Teets
LL
70
In the speed vs Time Graph, which time interval(s) show pricitive (+) acceleration?
Calculate the car's acceleration between the following points
(Acceleration (Speed-Speed,
F-G
In the speed vs Time Graph, which time interval(s) show negative (-) acouleration?
30
In the speed vs Time Graph, which lime interval(s) show constant speed?
92
100
Time, Time,) or Acceleration Aspeed/ Alime
B-C
C-D
G-H
D-E
H-I
Considering the acceleration concept and the speed vs time graph, it is found that:
The acceleration is positive in intervals CD and EF.The acceleration is negative in intervals BC, GH and HI.The acceleration is constant in intervals AB and FG.For each interval, the acceleration is given as follows:
AB: 0 m/s².BC: -1 m/s².CD: 1 m/s².DE: -1 m/s².EF: 3 m/s².FG: 0 m/s².GH: -3 m/s².HI: -1 m/s².How to calculate acceleration?Acceleration is given by the change in velocity divided by the change in time, according to the following formula:
[tex]a = \frac{\Delta v}{\Delta t}[/tex]
Considering a graph of velocity x time, the acceleration is:
Positive when the graph is increasing, hence in intervals CD and EF.Negative when the graph is decreasing, hence in intervals BC, GH and HI.Constant when the graph is constant, hence in intervals AB and FG.Considering that each point has a time interval of 10s, and the numeric values of the velocity, the acceleration for the intervals is found as follows:
AB: 0 m/s². (constant velocity).BC: (10 - 20)/20 = -1 m/s².CD: (20 - 10)/10 = 1 m/s².DE: (10 - 20)/10 = -1 m/s².EF: (40 - 10)/10 = 3 m/s².FG: 0 m/s². (constant velocity).GH: (10 - 40)/10 = -3 m/s².HI: (0 - 10)/10 = -1 m/s².More can be learned about acceleration at https://brainly.com/question/14344386
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Calculate the horizontal component Fx of the supporting force on point B for the configuration given in the Figure. The mass of the weight W is m-3.0kgr. Provide your answer in Newtons (Nt).
The horizontal component of the force Fx of the supporting force on point B is 19.715 N
What is horizontal component of force?When a force is not in the vertical (y direction) or in the horizontal (x direction), the force will be in the diagonal and can be resolved in to the horizontal or vertical component
The horizontal component of force refers to the part of he diagonal force resolved to be acting on the x direction
Considering the figure, the force, W acting is given by the product of mass, m and acceleration due to gravity, g
m = 3.0 kg
g = 9.81 m/s
W = mg = 3 * 9.81 = 29.43 N
The force is supported by the string at B
Fx = W cos 60
= 29.43 * 0.5
= 19.715 N
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You place a box weighing 242.4 N on an in- clined plane that makes a 37.2° angle with the horizontal. Compute the component of the gravita- tional force acting down the inclined plane. Answer in units of N
The unit of N is 238.8
What is unit ?
an individual thing or person regarded as single and complete but which can be a also form the an be individual component of a larger or more complex the whole.
Sol-On an inclined plane, component of the weight i.e. gravitational force acting in opposite direction to normal force is mgcos\thetamgcosθ and the component acting down the inclined plane is mgsin\theta.mgsinθ.
It is given that the weight of the block is, mg= 242.N
The angle made with the inclined plane is 37.2°
\Rightarrow mgsin\theta = 242.N N sin 37.2°/^o =238 N⇒mgsinθ=242.N?Nsin42.9
o
=238.8N
Hence, the component of the gravitational force acting down the inclined plane is 238.8 N.
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22
Carly mentions to her friends that her new scented oils have been helping heal her headaches. With no scientific evidence that this "aromatherapy"
actually works, her friends should caution her and tell her to be careful. What do Carly's friends think she may be diving into?
O A. astrology
OB. phrenology
OC. pseudoscience
O D. astronomy
(c) Friends think she may be diving into pseudoscience.
Friends of Carly speculate that she may be engaging in pseudoscience.
A claim, discovery, or explanatory framework lacks the objectivity required for scientific investigation when it is presented as pseudoscience. Pseudoscience can also result from research that is based on dubious theories, poor experimental layouts, or incorrect data.
A single assertion or claim that is purported to be supported by facts or science but breaks down when subjected to the test of reason is referred to as pseudoscience.
Another illustration of a pseudoscience is a complex system, such as astrology, that purports to explain how astronomical events influence and are affected by global events. Numerous bogus sciences, such as astrology, are largely risk-free.
The correct option is (c).
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What planet is more similar in size to earth
Answer: Venus
Explanation:
At a baseball game, a ball of m = 0.15 Kg moving at a speed of v = 30m/s is caught by a fan.
a. Show that the impulse supplied to bring the ball to rest is 4.5 N x s. Remember to use the correct units (0.25pts)
b. Show that if the ball is stopped in 0.02 s, then the average force of the ball on the catcher’s hand is 225 N. Remember to use the correct units. (0.25pts)
A. The impulse supplied to bring the ball to rest 4.5 Ns. Details below
B The average force of the ball is 225 N. Details below
What is impulse?This is defined as the change in momentum of an object.
Impulse = change in momentum
Impulse = final momentum – Initial momentum
Impule = m(v - u)
Where
m is the massu is the initial velocityv is the final velocityAlso,
Impulse = force × time
Therefore
Force × time = final moment – Initial momentum
A. How to determine the impulse
The impulse can be obtainedas illustrated below
Mass (m) = 0.15 KgInitial velocity = 30 m/sFinal velocity = 0 m/sImpulse =?Impulse = m(v + u) since the came to rest
Impulse = 0.15 × (0 + 30)
Impulse = 0.15 × 30
Impulse = 4.5 Ns
Thus, the impulse is 4.5 Ns
B. How to determine the average force
The average force can be obtained as follow:
Impulse = 4.5 NsTime = 0.02Average force = ?Impulse = force × time
4.5 = average force × 0.02
Divide both sides by 0.02
Average force = 4.5 / 0.02
Average force = 225 N
Thus, the average force is 225 N
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Song
Using a popular song (like Twinkle
Twinkle or Row, Row, Row Your Boat),
change the lyrics to create a song on
chemical reactions. How do they happen?
Include key vocabulary words, important
things to remember, and real world
examples. Help Needed
Answer:
in twinkle and row row your boat is education in childrens
Find the answer to the problem
Acceleration of box is 2.82m/s.
How does acceleration work?acceleration is the rate of change in both speed and direction of velocity over time. When anything moves faster or slower in a straight line, it is said to have been accelerated. Because the direction is constantly changing, even motion on a circle accelerates at a constant pace.
Acceleration is measured in what ways?Meters per second per second (m/s2) is a unit of measurement for acceleration.
Formula,
F_NET = ∑ F1 + F2 , and F_NET = m . a
F_NET = 18N + 6N = 24N
Then,
F_NET = m . a , a = F_NET/m
a = 24N / 8.5kg
a = 2.82m/s.
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An object has a mass 60 kg on the Earth's surface. The object is taken to a point 4 times the Earth's radius from the Earth's center. What is the object's mass at this point?
Given that the mass of the object, m = 60 kg, and the distance from the earth's surface is, h = 4R.
We have to find mass at this height.
The mass of the object is 60 kg as mass is constant irrespective of height.
