2. Let A and B be invertible 5 x 5 matrices with det. A = -3 and det B = 8. B8 Calculate: (a) det(A? B-) (b) det(2. A)

In the context of the Mumbai study, the residual is the difference between the observed value (the child's height or arm span) and the predicted value (based on a statistical model or an average value). Therefore, the residual for this child is -3.1 cm.

To calculate the residual, we need to first determine the predicted arm span for a child with a height of 59 cm using the regression equation from the Mumbai study. Let's assume the regression equation is:

Arm span = 0.9*Height + 10

Plugging in the height of 59 cm, we get:

Arm span = 0.9*59 + 10 = 63.1 cm

The predicted arm span for this child is 63.1 cm.

Now, to calculate the residual, we simply subtract the predicted arm span from the actual arm span:

Residual = Actual arm span - Predicted arm span
Residual = 60 - 63.1
Residual = -3.1 cm

Therefore, the residual for this child is -3.1 cm.

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The cost per pound of the soup is $4.06 per pound (rounded to the nearest cent).

To find the cost per pound of the soup, we need to calculate the total cost of all the ingredients and divide it by the total weight of the soup.

The total cost of potatoes is 3 pounds × $3.62 per pound = $10.86.

The total cost of cod is 5 pounds × $4.56 per pound = $22.80.

The total cost of fish broth is 3 pounds × $3.66 per pound = $10.98.

So, the total cost of all the ingredients is:

$10.86 + $22.80 + $10.98 = $44.64

The total weight of the soup is 3 + 5 + 3 = 11 pounds.

Thus, the cost per pound of soup is:

$44.64 / 11 pounds = $4.06 per pound

Therefore, the cost per pound of the soup is $4.06 per pound (rounded to the nearest cent).

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Answer:

89

Step-by-step explanation:

it is a straight line mean 180 degrees.

180 subtract 91 is 89

Answer:The measure of angle b is 89 degrees.

Step-by-step explanation:

Types of angles:

• Angles between 0 and 90 degrees (0°< θ <90°) are called acute angles.

• Angles between 90 and 180 degrees (90°< θ <180°) are known as obtuse angles.

• Angles that are 90 degrees (θ = 90°) are right angles.

• Angles that are 180 degrees (θ = 180°) are known as straight angles.

• Angles between 180 and 360 degrees (180°< θ < 360°) are called reflex angles.

• Angles that are 360 degrees (θ = 360°) are full turn.

We know that,

 Angles that are 180 degrees (θ = 180°) are known as straight angles.

In this question ,let

a= 91 and we have to find b=?

here,by straight angle

a+b=180

91+b=180

b=180-91

b=89

this is the required answer.

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Answer:

Step-by-step explanation:

You want the common ratio and first 3 terms of a decreasing geometric progression with the sum of the first three terms being 7, and their product being 8.

Let the first term be represented by x, and let r represent the common ratio. Then the first three terms are ...

  x, xr, xr²

Their sum is ...

  7 = x +xr +xr²

Their product is ...

  8 = (x)(xr)(xr²) = (xr)³

Taking the cube root of the product equation, we have ...

  2 = xr

Substituting this into the first equation, we have ...

  7 = x +2 + 2r

  5 = x +2r   ⇒   x = 5 -2r

And substituting back into the above, we get ...

  2 = (5 -2r)(r)

  2r² -5r +2 = 0

  (2r -1)(r -2) = 0

  r = 2 or 1/2

We want r < 1, so r = 1/2.

  x = 5 -2(1/2) = 4

For x = 4, r = 1/2, the first three terms are ...

  x, xr, xr² = 4, 2, 1

__

Additional comment

The equations are nicely solved by a graphing calculator. In the attached, we used y instead of r. We want the solution with y<1.

The two solutions give rise to terms 4, 2, 1 (decreasing) or 1, 2, 4 (increasing).

The closest answer is B. None of these

To find the present value of an income of Rs. 3 lakhs to be received after 1 year at a 5% rate of interest, you can use the present value formula:

Present Value (PV) = Future Value (FV) / (1 + Interest Rate) ^ Number of Years

1. Repeat the question in your answer: The present value of an income of Rs. 3 lakhs to be received after 1 year at a 5% rate of interest is:

2. Step-by-step explanation:

Step 1: Identify the values for the formula.
- Future Value (FV) = Rs. 3 lakhs
- Interest Rate = 5% or 0.05
- Number of Years = 1

Step 2: Plug the values into the formula.
PV = Rs. 3,00,000 / (1 + 0.05) ^ 1

Step 3: Calculate the present value.
PV = Rs. 3,00,000 / 1.05

PV ≈ Rs. 2,85,714.29

Based on the given options, the closest answer is B. None of these, as the calculated present value is approximately Rs. 2,85,714.29, which does not match any of the provided options.

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Answer: $13.39

Step-by-step explanation:

first, you take 25% off 21, by multiplying 21*.25 which is 5.25

next, subtract 5.25 from 21, which gets you 15.75

next, add the 15% off coupon, by multiplying 15.75*.15 which is 2.3625

last, subtract 2.3625 from 15.75, which gets you 13.3875, or $13.39 rounded

As per the given values, the area of the hemisphere is 45065.41 m³

Volume = 450000 m³

Calculating the volume of the hemisphere -

Volume = 2/3 πr³

Substituting the values -

450,000 =2/3 x 3.14 x r³

Solving for r³

r³ = 450000 x 3/(2 x 3.14)

r³ = 214968.1

r = √214968.1

r = 59.9

Calculating the area of the hemisphere -

Area = 4πr²

Substituting the values -

Area = 4 x 3.14 x (59.9)²

= 12.56 x (59.9)²

= 45065.41

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Answer:

-----------------------

There are two sectors that are factors of 3:

So out of the 10 sectors, there is a 2/10 probability that the randomly selected point lies in one of these three sectors.

Therefore, the probability is 0.2 or 20%.

Answer:

20%

Step-by-step explanation:

For this question, we must find the numbers from 1-10 that are factors of 3. A factor is a number that, when multiplied by a specific number, gives a specific whole. For instance, in 2*4=8, 2 and 4 would be factors. The number 3 only has two factors: one and itself. Since two of the ten numbers are factors of 3, that is a rate of 2/10, 0.2, or 20%.

The magnitude of the error is less than [tex]$\$ 0.015 \$$[/tex], which is our final exact answer.

We can use the Mean Value Theorem to estimate the error in approximating [tex]$(128.012)^{\frac{6}{7}}$[/tex] by [tex]$128^{\frac{6}{7}}$[/tex]. Let [tex]$f(x) = x^{\frac{6}{7}}$[/tex] and [tex]$a = 128.012$[/tex]. Then, by the Mean Value Theorem, there exists some [tex]$c$[/tex] between [tex]$a$[/tex] and [tex]$128$[/tex] such that:

[tex]$$\frac{f(a)-f(128)}{a-128}=f^{\prime}(c)$$[/tex]

Taking the absolute value of both sides and rearranging, we get:

[tex]$$|f(a)-f(128)|=|a-128| \cdot\left|f^{\prime}(c)\right|$$[/tex]

Now, we can find [tex]$\$ f^{\prime}(x) \$$[/tex] :

[tex]$$f(x)=x^{\frac{6}{7}}=e^{\frac{6}{7} \ln x}$$[/tex]

Using the chain rule, we get:

[tex]$$f^{\prime}(x)=\frac{6}{7} x^{-\frac{1}{7}} e^{\frac{6}{7} \ln x}=\frac{6}{7} x^{-\frac{1}{7}} f(x)$$[/tex]

Plugging in [tex]$\$ \mathrm{c} \$$[/tex] and simplifying, we get:

[tex]$$|f(a)-f(128)|=|128.012-128| \cdot\left|\frac{6}{7} c^{-\frac{1}{7}}\left(\frac{128.012}{c}\right)^{\frac{6}{7}}\right|$$[/tex]

We want to find an upper bound for this expression, so we will use the fact that [tex]$\$ c \$$[/tex] is between [tex]$\$ 128 \$$[/tex] and [tex]$\$ 128.012 \$$[/tex]. Therefore, we have:

[tex]$$|f(a)-f(128)| < 0.012 \cdot \frac{6}{7} 128^{-\frac{1}{7}}(128.012)^{\frac{6}{7}}$$[/tex]

Plugging in the values, we get:

[tex]$$|f(a)-f(128)| < 0.012 \cdot \frac{6}{7} \cdot 128^{-\frac{1}{7}}(128.012)^{\frac{6}{7}} \approx 0.015$$[/tex]

Therefore, the magnitude of the error is less than [tex]$\$ 0.015 \$$[/tex], which is our final exact answer.

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The first two approximations of the root of f(a) using Newton's method starting at x=0 are: X₁ = 1/3 X₂= 19/54

Newton's Method Algorithm: (1) Choose a beginning value x0 (ideally near to a root of f). (2) Create a new estimate xn+1=xnf(xn)f′(xn) for each estimate xn. (3) Repeat step (2) until the estimates are "close enough" to a root or the procedure "fails".

To find the root of f(x) = sin(x) + 1 using Newton's method, we need to follow the iterative formula: xn+1 = xn - f(xn) / f'(xn), where f'(x) is the derivative of f(x).

First, find the derivative of f(x): f'(x) = cos(x)

Now, compute x₁ and x₂ using the formula:

x₁ = x0 - f(x0) / f'(x0) = 0 - (sin(0) + 1) / cos(0) = 0 - 1/1 = -1

x₂ = x1 - f(x1) / f'(x1) = -1 - (sin(-1) + 1) / cos(-1)

The first two approximations of the root of f(a) using Newton's method starting at x=0 are:

X1 = 1/3

X2 = 19/54

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For a cost function, C(x) = 36100 + 800x + x²

a) The cost at the production level 1250 is equal to 2,598,600.

b) The average cost at the production level 1250 is equal to 2,078.88.

c) The marginal cost at the production level 1250 is equal to 3300 $/unit.

d) The production level, x = 60 that will minimize the average cost.

e) The minimal average cost is equals the 1,461.67.

Let consider C(x) be a total cost function where x is quantity of the product, then,

We have a cost function is written as C(x) = 36100 + 800x + x²

a) The cost at production level 1250, that is x = 1250 is equals to

=> C( 1250) = 36100 + 800× 1250 + 1250²

= 2,598,600

b) The average cost at the production level 1250, that is AC(x) [tex]= \frac{36100 + 800x + x²}{x}[/tex]

[tex]= \frac{36100}{x} + 800 + x[/tex]

Plug the value x = 1250

[tex]= \frac{36100}{1250} + 800 + 1250[/tex]

= 2,078.88

c) The marginal cost at the production level 1250 is equal to the derivative of

[tex]\frac{dC(x)}{dx }[/tex], evaluated for x = 1250,

[tex]\frac{dC(x)}{dx }[/tex] = C'(x)

= 800 + 2x

C'(1250) = 800 + 2× 1250 = 3300$/unit

d) As we know the average cost of the total cost function is,

[tex] A C(x) = \frac{36100}{x} + 800 + x[/tex]

Compute the critical point for minimizing the average cost, differentating the above equation, [tex]AC′(x)= \frac{ d(\frac{36100}{x} + 800 + x)}{dx}[/tex]

[tex]= \frac{- 36100}{x²} + 1[/tex]

For critical value plug AC'(x) = 0

[tex]\frac{- 36100}{x²} + 1 = 0[/tex]

=> x² - 3600 = 0

=> x = ± 60

As the quantity must be positive so x = 60.

e) Now we will compute the minimum average value at x = 60,

[tex] A C(60) = \frac{36100}{60} + 800 + 60[/tex]

= 1,461.67

Hence, required value is 1,461.67.

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Answer:

[tex].12 \times 360 \: degrees = 43.2 \: degrees[/tex]

The 2-D shape used here is a right triangle. When rotated about the axis, this becomes a cone which is 3-D. See the attached.

In mathematics, rotation is a notion that originated in geometry. Any rotation is a movement of a specific space that retains at least one point.

A rotation differs from the following motions: translations, which have no fixed points, and (hyperplane) reflections, which each have a full (n 1)-dimensional flat of fixed points in an n-dimensional space.

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Both statements are true. When events A and B are mutually exclusive, meaning they cannot occur simultaneously, you can use the special rule of addition.

If events A and B are not mutually exclusive, meaning they can occur together, you should use the general rule of addition. The specific rule of addition can only be used when dealing with mutually exclusive events, while the general rule of addition can be used for any two events, whether they are mutually exclusive or not. The specific rule of addition states that the probability of either event A or event B occurring is equal to the sum of their individual probabilities, while the general rule of addition states that the probability of event A or event B occurring is equal to the sum of their individual probabilities minus the probability of their intersection (if they are not mutually exclusive).

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The probability that the experiment ends before the 6th toss and an even number of tosses are required is 5/16.

The given experiment involves tossing a coin until the first time the same result appears twice in succession. This means that the experiment could end after two tosses if both tosses yield the same result (e.g., heads-heads or tails-tails) or it could continue for many more tosses until this condition is met.

The sample space for this experiment can be represented as a binary tree where the root node represents the first toss and the two branches from the root represent the two possible outcomes (heads or tails). The next level of the tree represents the second toss, with two branches emanating from each branch of the root (one for heads and one for tails). This process continues until the experiment ends with two successive outcomes being the same.

The probability of each outcome in the sample space can be computed by multiplying the probabilities of each individual toss. Since each toss has a probability of 1/2 of resulting in heads or tails, the probability of any particular outcome requiring n tosses is 1/2^n.

(a) A = The experiment ends before the 6th toss.

To calculate the probability of this event, we need to sum the probabilities of all outcomes that end before the 6th toss. This includes outcomes that end after the second, third, fourth, or fifth toss. Thus, we have:

P(A) = P(outcome ends after 2 tosses) + P(outcome ends after 3 tosses) + P(outcome ends after 4 tosses) + P(outcome ends after 5 tosses)

= (1/2^2) + (1/2^3) + (1/2^4) + (1/2^5)

= 15/32

Therefore, the probability that the experiment ends before the 6th toss is 15/32.

(b) B = An even number of tosses are required.

An even number of tosses are required if the experiment ends after the second, fourth, sixth, etc. toss. The probability of this event can be calculated as follows:

P(B) = P(outcome ends after 2 tosses) + P(outcome ends after 4 tosses) + P(outcome ends after 6 tosses) + ...

= (1/2^2) + (1/2^4) + (1/2^6) + ...

This is a geometric series with first term a = 1/4 and common ratio r = 1/16. Using the formula for the sum of an infinite geometric series, we have:

P(B) = a/(1-r) = (1/4)/(1-1/16) = 4/15

Therefore, the probability that an even number of tosses are required is 4/15.

(c) A∩B = The experiment ends before the 6th toss and an even number of tosses are required.

To calculate the probability of this event, we need to consider only the outcomes that satisfy both conditions. These include outcomes that end after the second or fourth toss. Thus, we have:

P(A∩B) = P(outcome ends after 2 tosses) + P(outcome ends after 4 tosses)

= (1/2^2) + (1/2^4)

= 5/16

Therefore, the probability that the experiment ends before the 6th toss and an even number of tosses are required is 5/16.

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As given below find the suitable option which gives you the answer for the question. "There are 11 questions in 5 pages. No credit will be given without sufficient work 1. Let Z be a standard normally distributed random variable."

1. Let Z be a standard, normally distributed random variable.
a. P(Z ≤ 2.32)
To find this probability, you need to use the standard normal distribution table (also known as the Z-table) to look up the value corresponding to Z = 2.32. The value you find in the table is the probability P(Z ≤ 2.32).
b. P(Z ≥ -1.56)
To find this probability, first look up the value corresponding to Z = -1.56 in the standard normal distribution table. This value represents P(Z ≤ -1.56). Since we want P(Z ≥ -1.56), we need to find the complement, which is 1 - P(Z ≤ -1.56).
c. P(-1.43 ≤ Z ≤ 2.47)
To find this probability, look up the values corresponding to Z = -1.43 and Z = 2.47 in the standard normal distribution table. The difference between these two values will give you the probability P(-1.43 ≤ Z ≤ 2.47).
d. Find z* so that P(-z* ≤ Z ≤ z*) = 0.99
To find the z* value, you need to look up the value in the standard normal distribution table that corresponds to the area of 0.995 (since 0.99 is the area between -z* and z*, and each tail contains 0.005). Once you find the value in the table, look at the corresponding Z value. This value will be your z*.

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This is because the function f(t) is a constant function, which is an even function and has no odd component.

The half-range Fourier series is a representation of a periodic function over a finite interval, where the function is assumed to be even or odd. In the case of the function f(t) = 0, the function is even and the interval is from 0 to π.

(a) The half-range cosine series:

To find the half-range cosine series, we first need to find the Fourier coefficients:

[tex]a_0 &= \frac{2}{\pi} \int_0^{\pi} f(t) dt = \frac{2}{\pi} \int_0^{\pi} 0 dt = 0 \a_n &= \frac{2}{\pi} \int_0^{\pi} f(t) \cos(nt) dt = \frac{2}{\pi} \int_0^{\pi} 0 \cos(nt) dt = 0 \\[/tex]

Since all the Fourier coefficients are zero, the half-range cosine series for f(t) is:

[tex]$\begin{align*}f(t) &= \frac{a_0}{2} + \sum_{n=1}^{\infty} a_n \cos(nt) \&= 0\end{align*}$[/tex]

b) The half-range sine series:

To find the half-range sine series, we need to find the Fourier coefficients:

[tex]b_n &= \frac{2}{\pi} \int_0^{\pi} f(t) \sin(nt) dt = \frac{2}{\pi} \int_0^{\pi} 0 \sin(nt) dt = 0 \\[/tex]

Since all the Fourier coefficients are zero, the half-range sine series for f(t) is:

[tex]$\begin{align*}f(t) &= \sum_{n=1}^{\infty} b_n \sin(nt) \&= 0\end{align*}$[/tex]

Therefore, both the half-range cosine series and the half-range sine series for f(t) are zero. This is because the function f(t) is a constant function, which is an even function and has no odd component.

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The large drain can empty the tank on its own in 10 hours, while the small drain can empty the tank on its own in 16 hours.

Let's assume that the large drain can empty the tank in x hours. Then, according to the problem statement, the small drain can empty the same tank in x + 6 hours.

When both the large and small drains are opened together, they can empty the tank in 4 hours. This means that their combined rate of emptying the tank is 1/4 tank per hour.

We can set up two equations based on the rates of the individual drains and their combined rate:

1/x + 1/(x+6) = 1/4

Solving for x, we get x = 10 hours, which is the time it takes for the large drain to empty the tank on its own.

To find the time it takes for the small drain to empty the tank on its own, we substitute x = 10 in x+6, which gives us 16 hours.

Therefore, the large drain can empty the tank on its own in 10 hours, while the small drain can empty the tank on its own in 16 hours.

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To prove that at least one participant is lying when they say they are taller than the average height of all participants in the survey, we can follow these steps:

1. Calculate the average height of all participants in the survey. To do this, sum the heights of all participants and divide by the total number of participants.

2. Compare each participant's height to the calculated average height.

3. If everyone answered that they are taller than the average height, it means that they all believe their height is greater than the calculated average height.

4. However, since the average height is a calculated value based on the sum of all heights divided by the number of participants, it is impossible for all participants to be taller than the average height. The average height must always include some participants who are shorter and some who are taller.

5. Therefore, at least one participant must be lying when they claim to be taller than the average height of all participants in the survey.

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The printer that has a better rate of cost per page would be = printer B.

For printer A:

The number of pages printed = 100

The cost for the printed pages = $26.99

Cost per page = 26.99/100 = $0.27/page

For printer B:

The number of pages printed = 275

The cost for the printed pages = $67.99

Cost per page =67.99/275

= 0.25

Therefore the printer that has a better rate of cost per page would be = printer B

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Answer:

Step-by-step explanation:

from the angles we understand that they are similar, therefore in proportion, we solve, in fact, with a proportion between the corresponding sides

24 : x = 32 : 38

x = 24 x 38 : 32

x = 912 : 32

x = 28.5 units

-------------------------

check

24 : 28.5 = 32 : 38

0.84 = 0.84

The answer is good

Answer:

dark blue

Step-by-step explanation:

The probability that the randomly selected point is in the bullseye is 0.75, or 75%.

The area of the bullseye is the difference between the areas of the larger and smaller circles:

[tex]A = \pi r_1^2 - \pi r_2^2[/tex]

where [tex]r_1[/tex] is the radius of the larger circle (8 cm) and [tex]r_2[/tex] is the radius of the smaller circle (4 cm).

[tex]A = \pi(8^2 - 4^2)A = \pi(64 - 16)A = 48\pi[/tex]

The area of the entire target (both circles) is:

[tex]A = \pi r_1^2[/tex]

A = 64π

Therefore, the probability of selecting a point in the bullseye is:

P(bullseye) = A(bullseye) / A(target)

P(bullseye) = (48π) / (64π)

P(bullseye) = 3/4 or 0.75

So the probability that the randomly selected point is in the bullseye is 0.75, or 75%.

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The probability of 3 dying of SIDS in this situation is approximately 0.000227. The number of SIDS cases in this hospital is significantly higher than the expected rate.

a. The probability of 3 infants dying of SIDS in this situation can be calculated using the binomial probability formula:
P(X=k) = C(n,k) * p^k * (1-p)^(n-k)
Where:
P(X=k) is the probability of k successes (SIDS cases) in n trials (infants),
C(n,k) is the number of combinations of n items taken k at a time,
p is the probability of SIDS (0.0001),
n = 100 infants,
k = 3 SIDS cases.
P(3 SIDS cases in 100 infants) = C(100,3) * (0.0001)^3 * (1-0.0001)^(100-3)
After calculating, the probability is approximately 0.000227.

b. In this situation, it is alarming that many infants died of SIDS, as the probability of 3 deaths in 100 infants is very low (0.000227), much lower than the prevalence of 0.01%. This indicates that the number of SIDS cases in this hospital is significantly higher than the expected rate.

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Answer:

11.4583 = 114583 / 10000

Step-by-step explanation:

The height of the second cylinder should be 56.25% greater than the height of the first cylinder. (Option 1)

Let's assume the radius of the first cylinder to be 'r' and its height to be 'h'. So, its volume can be represented as V1 = πr^2h.

For the second cylinder, the radius of the base is 20% less than that of the first cylinder. So, the radius of the second cylinder can be represented as 0.8r. Let the height of the second cylinder be represented as 'H'. So, its volume can be represented as V2 = π(0.8r)²H.

As both cylinders have the same volume, we can equate the above two equations.

πr²h = π(0.8r)²H

h = (0.8)²H

H = (1/(0.8)²)h

H = (1.5625)h

Therefore, the height of the second cylinder should be 56.25% greater than the height of the first cylinder.

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Complete Question:

Two cylinders have the same volume, but the radius of the base of the second cylinder is 20% less than the radius of the base of the first. How much greater should be the height of the second cylinder be in comparison to the height in first?

Options:

Step-by-step explanation:

the main triangle is an isoceles triangle (both legs are equally long). that means that the height y bergen the 2 legs splits the baseline in half.

therefore,

x = 10/2 = 5

Pythagoras gives us y.

c² = a² + b²

c being the Hypotenuse (the side opposite of the 90° angle). in our case 10.

a and b are the legs. in our case x and y.

10² = 5² + y²

100 = 25 + y²

75 = y²

y = sqrt(75) = 8.660254038...

The number is -4. We can solve for it using algebraic equations and multiplication.

The problem states that when we multiply our number by four and add twenty, we get 4. We can represent this relationship using an algebraic equation with the variable x representing our unknown number:

4x + 20 = 4

To solve for x, we need to isolate it on one side of the equation. We start by subtracting 20 from both sides of the equation:

4x = -16

Now, we divide both sides by 4:

x = -4

Therefore, our number is -4. We can check this answer by plugging it back into the original equation:

Simplifying the left side of the equation, we get:

-16 + 20 = 4

4 = 4

This confirms that our answer, x = -4, is correct.

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The set statement that is NOT true is option B) If A is an event such that Pr(A)=1, then A'=Ø.

In terms of option A, one can have Pr(A)=1, Pr(B)=0, and Pr(A u B)=1. This outcome is true in cases where A and B are not mutually exclusive occurrences, telling us that they have the potential to happen concurrently.

Therefore, If Pr(A) is equal to Pr(B) and both are greater than zero, then Pr(A/B) is one that is equivalent to Pr(B|A). Bayes' theorem, which establishes a connection between conditional probabilities, is an accurate hold to this.

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The equivalent distance travelled by Mia is 2.3333... and 2[tex]\frac{1}{3}[/tex] miles.

The distance run by Mia is equivalent to 7/3 miles. We can express the fraction as -

7/3 = 2.3333

7/3 = (3 x 2 + 1)/3 = 2[tex]\frac{1}{3}[/tex]

So, the equivalent distance travelled by Mia is 2.3333... and 2[tex]\frac{1}{3}[/tex] miles.

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Answer: 2.33 and 2 1/3

Step-by-step explanation: