2 units down
2) reflection across the x-axis
1).
)
A) J\(-2,-4), K (2, -1), L (2,-5)
B) K(5,0), L(5, 4), J'(1,3)
C) K (5,-2), L'(5,2), J'(1, 1)
D) J'(-1,3), K (-5,0), L'(-5, 4)

D

Answer:

A and C are the right statements

The largest subset S on which the vector-valued function F is continuous is the interval (-3, ∞).

To find the largest subset S on which the given vector-valued function is continuous, we need to examine the individual component functions and identify any restrictions or conditions that could cause discontinuities.

Component 1: f1(t) = t/(9 + t^4)

This function is a rational function. It will be continuous for all real values of t except where the denominator equals zero: 9 + t^4 = 0. However, there are no real values of t that satisfy this equation, so f1(t) is continuous for all real values of t.

Component 2: f2(t) = 7t^2 - 7t + 1

This function is a polynomial function, and polynomial functions are continuous for all real values of t. Therefore, f2(t) is continuous for all real values of t.

Component 3: f3(t) = ln(t + 3)

The natural logarithm function is defined for the positive values of its argument. Therefore, t + 3 > 0, which implies t > -3. Hence, the function f3(t) is continuous for t > -3.

Taking all these considerations into account.The function is continuous for all values of t greater than -3.

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Answer:

The width is 10 meters and the length is 18 meters

Step-by-step explanation:

P = 2( l+w)

56 = 2(l+w)

w = l-8

Substitute for w in the perimeter equation

56 = 2( l+l-8)

Combine like terms

56 = 2 ( 2l-8)

Divide each side by 2

56/2 = 2/2( 2l-8)

28 = 2l-8

Add 8 to each side

28+8 = 2l-8+8

36 = 2l

Divide by 2

36/2 = 2l/2

18 = l

Now find w

w = l-8

w = 18-8

w = 10

Answer: 47 mins

Step-by-step explanation:

Based on the context of the problem, the range of the exponential function y = [tex]45,529(0.78)^x[/tex] is y > 0.

The exponential function for depreciation given in the problem is:

y = 45,529(0.78)^x

This function gives us the value of Sharlene's truck in dollars after x months of ownership, assuming that the depreciation follows a constant rate and is modeled by an exponential function.

To find the range of the function, we need to consider the minimum value that y can take. Since depreciation leads to a decrease in value over time, y should always be greater than zero. In other words, the range of the function is:

y > 0

In practical terms, this means that Sharlene's truck will always have some positive value, even if its market value has decreased due to depreciation. In other words, a truck is never worth zero or less than zero (unless it has additional debts associated with it), and Sharlene's truck will always have some resale or scrap value even if it has depreciated significantly.

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(a) FIFO (First-In-First-Out): In the FIFO policy, the page that entered the memory first is the first to be replaced when a page fault occurs. In the given string of page references, the frame allocation for FIFO would depend on the order in which the pages were brought into memory.

(b) LRU (Least Recently Used): The LRU policy replaces the page that has not been accessed for the longest period of time. It requires maintaining a history of page accesses to determine the least recently used page. c) Clock (Single Hit Version): The Clock policy uses a circular list of frames and a clock hand that points to the current position in the list. When a page fault occurs, the clock hand advances and checks if the page in the current position has been recently used. If it has not been used, it is replaced. Otherwise, it is marked as not recently used.

(d) Optimal: The optimal policy is an idealized policy that replaces the page that will not be used for the longest duration in the future. It requires knowledge of the entire future sequence of page references, which is not practical in real-world scenarios. The total number of page faults and the miss rate for each policy would depend on the specific sequence of page references and the initial frame allocation. Without the specific sequence provided, it is not possible to calculate the exact numbers of page faults and miss rates for each policy.

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Answer:

y= (1/2)x-1

Step-by-step explanation:

X-2y-2=0

-2y=-x+2

y= (1/2)x-1

Given data: Principal amount (P) = $3,500Number of years (t) = 70 - 26 = 44 years. Rate of Interest (R) = 7%Total amount that client will have after 44 years can be calculated as follows: Total Amount (A) = P[(1 + R/100)^t - 1]/(R/100)Putting the values:

Therefore, Total Amount (A) = $3,500[(1 + 7/100)^44 - 1]/(7/100)Total Amount (A) = $680,471.44Therefore, client will have $680,471.44 at the age of 70 years.

If the client saves $3,500 per year and invests in securities that provide an average annual return of 7 percent, she will have $680,471.44 by the time she reaches the age of 70. Since the first payment will be made one year from now, the amount of money that will accumulate will be for 44 years (70-26). The formula for calculating the total amount that the client will have after 44 years can be derived as follows:

Total Amount (A) = P[(1 + R/100)^t - 1]/(R/100)Where P is the principal amount, R is the rate of interest, and t is the number of years. The value of P is given as $3,500, and the rate of interest is 7 percent. Putting these values in the above equation, we get:

Total Amount (A) = $3,500[(1 + 7/100)^44 - 1]/(7/100)The total amount that the client will have after 44 years is $680,471.44. Therefore, it is advisable for the client to save $3,500 per year and invest it in securities that provide an average annual return of 7 percent. This investment plan will help the client to accumulate a substantial amount of money for her retirement.

Thus, the client can have $680,471.44 by the time she reaches the age of 70 if she saves $3,500 per year and invests it in securities that provide an average annual return of 7 percent. This investment plan will help the client to accumulate a substantial amount of money for her retirement.

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Answer:

lesser x =-4

greater x =1/2

The mode of the given data values is N/A (not applicable).Hence, the mean, median, and mode of the given data values are:Mean = 54.36Median = 55.5Mode = N/A (not applicable)

Given data values are 55, 56, 70, 61, 53, 57, 50, 73, 52, 69, and 2. We need to calculate the mean, median, and mode of this sample.So, let's first arrange the data values in ascending order:2, 50, 52, 53, 55, 56, 57, 61, 69, 70, 73

Mean:The mean is the sum of all the data values divided by the total number of data values. So, we can use the following formula to calculate the mean:

Mean = (sum of all the data values) / (total number of data values)Sum of all the data values = 55 + 56 + 70 + 61 + 53 + 57 + 50 + 73 + 52 + 69 + 2 = 598Total number of data values = 11

Therefore,Mean = (sum of all the data values) / (total number of data values) = 598 / 11 = 54.36 (rounded to two decimal places)Therefore, the mean of the given data values is 54.36.

Median:The median is the middle value of a sorted data set. Since the data set has 11 data values, the median is the average of the 6th and 7th values (counting from smallest to largest).

Therefore, the median is :Median = (55 + 56) / 2 = 55.5Therefore, the median of the given data values is 55.5.

Mode:The mode is the data value that appears most frequently in the data set. In this case, there is no data value that appears more than once. So, there is no mode.

Therefore, the mode of the given data values is N/A (not applicable).Hence, the mean, median, and mode of the given data values are:Mean = 54.36Median = 55.5Mode = N/A (not applicable)

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Answer:

marvel - c

dc - d

Answer:

marvel c dc c

Step-by-step explanation:

The matrix A has two eigenvalues, 1 and -1. To find the bases for the eigenspaces of A, we need to solve the eigenvector equations for each eigenvalue.

Let's start with the eigenvalue 1. We need to find a vector x such that Ax = 1x. Using the equation (A - λI)x = 0, where λ is the eigenvalue and I is the identity matrix, we have:

(A - I)x = 0

[1 - 1 0] [x1] = 0

[4 - 1 0] [x2]

This gives us the following system of equations:

x1 - x2 = 0

4x1 - x2 = 0

Solving these equations, we find that x1 = x2, which means the eigenvector corresponding to the eigenvalue 1 is [1, 1]. Therefore, the basis for the eigenspace corresponding to the eigenvalue 1 is { [1, 1] }.

Next, let's consider the eigenvalue -1. Using the same equation, (A - λI)x = 0, we have:

(A + I)x = 0

[1 1] [x1] = 0

[4 - 1] [x2]

This gives us the following system of equations:

x1 + x2 = 0

4x1 - x2 = 0

Solving these equations, we find that x1 = -x2, which means the eigenvector corresponding to the eigenvalue -1 is [-1, 1]. Therefore, the basis for the eigenspace corresponding to the eigenvalue -1 is { [-1, 1] }.

In summary, the basis for the eigenspace corresponding to the eigenvalue 1 is { [1, 1] }, and the basis for the eigenspace corresponding to the eigenvalue -1 is { [-1, 1] }.

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Answer:

1/20

Step-by-step explanation:

x(whatever the amount was) -3/4= 1/4

1/4 - 1/5 = 1/20

THE PART

Answer:

4/20

Step-by-step explanation:

Since 3/4 & 1/5 don't have the same denominator you would multiply their denominators by each other top and bottom. You would get 3/4=15/20 & 1/5=4/20. Since you spent 15/20 of your money you would have 5/20 left. Now 1/5 of 5/20 is 1/20. So you would take 5/20 - 1/20 and you would have 4/20 of your money left.

I hope this helps:)

Answer:

C

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

I took the test on edgen 2020

The equation to find the volume of the water Sheila is putting in the tank is V = 3000 cubic inches.

To find the volume of the water Sheila is putting in the fish tank, we need to calculate the volume of a rectangular prism with the given dimensions.

The formula to calculate the volume of a rectangular prism is:

V = length × width × height

In this case, the dimensions of the fish tank are given as 15 inches, 20 inches, and 10 inches.

Let's use V as the variable to represent the volume of the water in the tank. Plugging in the given values, the equation becomes:

V = 15 inches × 20 inches × 10 inches

Simplifying the equation, we get:

V = 3000 cubic inches

It's important to note that the volume is measured in cubic units, such as cubic inches in this case, as we are dealing with three-dimensional space. The equation calculates the total volume of the fish tank, assuming it is being filled one-third of the way full with water.

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Answer:

-44

Step-by-step explanation:

Answer:

15w - 15y - 36

Step-by-step explanation:

Combine like terms

In this case the only two terms would be numbers without variable and numbers with the variable w

First lets combine the numbers with no variable which are -16 and -20. you subtract these two -16 - 20 = -36 and get -36

Now lets combine like terms for w, it doesn't matter which order you go in exactly but in the case I will do

1. combine 8w and 7w, since these are both positive you will add the together

8w + 7w = 15w

2. Now combine -11y and -4y, since these are both negative you will subtract them and get -15y

Answer:

42

Step-by-step explanation:

6*(-3) = (-18)

24-(-18) = 42

Answer:42

Step-by-step explanation:

Answer:

33

Step-by-step explanation:

3 plus 5 = 8

8 plus 9 = 17

17 plus 7 = 24

24 plus 9 = 33

this is just a multistep problem,

Hope this helps!

Step-by-step explanation:

Answer: x=7

              y=5

im not 100% sure so pls b careful

Answer:

your answer is x = 3

Answer:

x = 3

Step-by-step explanation:

2x/3 + 1 = 3

Subtract 1 from both sides

2x/3 = 2

Multiply both sides by 3

2x = 6

Divide both sides by 2

x = 3

Answer:

See image below.

Step-by-step explanation:

Answer:

3,000

Step-by-step explanation:

Create 2 expressions to represent the cost and the revenue, where x is the number of newspapers:

2x + 15,000 will represent the cost

5x + 6,000 will represent the revenue

Set the expressions equal to each other and solve for x:

2x + 15,000 = 5x + 6,000

15,000 = 3x + 6,000

9,000 = 3x

3,000 = x

So, 3,000 newspaper copies have to be sold to break even

Answer:

False

3, 6, 9, 12, 15...

6, 12, 18, 24...

The fields [tex]$\mathbb{Q}[\sqrt[4]{3}]$ and $\mathbb{Q}[\sqrt[4]{3}i]$[/tex] are isomorphic but not equal.

To prove that the fields are isomorphic, we need to find a bijective ring homomorphism between them. Consider the map [tex]$\phi: \mathbb{Q}[\sqrt[4]{3}] \to \mathbb{Q}[\sqrt[4]{3}i]$[/tex] defined by [tex]$\phi(a + b\sqrt[4]{3}) = a + bi\sqrt[4]{3}$ for any $a, b \in \mathbb{Q}$[/tex].

To show that [tex]$\phi$[/tex] is a ring homomorphism, we need to verify that it preserves addition and multiplication. This can be easily verified by applying the properties of complex numbers and the fact that [tex]$\sqrt[4]{3}$[/tex] is a real number.

To show that [tex]$\phi$[/tex] is bijective, we need to show that it is injective and surjective. Injectivity follows from the fact that if [tex]$\phi(a + b\sqrt[4]{3}) = \phi(c + d\sqrt[4]{3})$[/tex]. then [tex]$a + bi\sqrt[4]{3} = c + di\sqrt[4]{3}$[/tex], which implies a = c and b = d.

Surjectivity follows from the fact that for any i[tex]$a + bi\sqrt[4]{3}$[/tex] in [tex]$\mathbb{Q}[\sqrt[4]{3}i]$[/tex], we can find [tex]$a + b\sqrt[4]{3}$[/tex] in [tex]$\mathbb{Q}[\sqrt[4]{3}]$[/tex] such that [tex]$\phi(a + b\sqrt[4]{3}) = a + bi\sqrt[4]{3}$[/tex].

Since we have found a bijective ring homomorphism between the two fields, they are isomorphic. However, they are not equal because [tex]$\sqrt[4]{3}$[/tex] is a real number in [tex]$\mathbb{Q}[\sqrt[4]{3}]$\\[/tex] while [tex]$\sqrt[4]{3}i$[/tex] is an imaginary number in [tex]$\mathbb{Q}[\sqrt[4]{3}i]$[/tex] .

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Answer:

Option (3)

Step-by-step explanation:

There are two parallel line m and n.

A transverse 'p' is intersection these parallel lines.

Pair of corresponding angles between these parallel lines are,

Angle 3 and angle 7

Angle 2 and angle 6.

Similarly, angle 4 and angle 9 are also a pair of corresponding angles.

Therefore, from the given options, Option (3) is the correct option.

Answer:

D.

Step-by-step explanation:

I took the test.

Answer:

answer d or chose 4

Step-by-step explanation:

i did unit test on edg.

true i think i hope its correct dont want you to get it incorrect brainliest plz