Answer:
x<-3
Step-by-step explanation:
-2(x+3)>9+3x - Distribute
-2x-6 > 9+3x - Subtract 3x to both sides
-5x-6 > 9 - Add 6 to both side
-5x > 15 - Divide -5 to both sides
Integer switches: x < -3 - Answer
Source: MathPapa
x=2y-z/4 solve for z
idk how to solve it even though I'm in algebra 1 lol :/
Answer:
z = − 4 x + 2 y
Step-by-step explanation:
Given J(1,4) and the midpoint is M(2, 1), find the other endpoint K.
Which way is better?
Answer:
the best way is to follow the law, sales tax is not subject to discount by the seller.
Step-by-step explanation:
both ways result in the same outcome:
improper way, discount after tax
$50+$5(tax)=$55, after discount $55-$11(20%)=$44
proper way, discount before tax
$50-$10(20%)=$40+$4(tax)=$44
Please help!————————
Answer:
°F =(K − 273.15) × 9/5 + 32
Step-by-step explanation:
-3.3x + 1x + 8 = -10x
Answer:
x= -80/77
Step-by-step explanation:
-33x+x+8=-10x
-2.3x+8=-10x
-2.3x=-10-8
-2.3x+10x=-8
7.7x=-8
x=-80/77
if f(x, y) = xy, find the gradient vector ∇f(2, 7) and use it to find the tangent line to the level curve f(x, y) = 14 at the point (2, 7).
Equation of tangent line curve: 7x - y = 7
The function f(x, y) = xy . To find the gradient vector ∇f(2, 7) and use it to find the tangent line to the level curve f(x, y) = 14 at the point (2, 7).Gradient vector ∇f(2, 7)We need to find the partial derivative of the function with respect to x and y. Therefore, ∂f/∂x = y and ∂f/∂y = x∴ ∇f = (y)i + (x)j ∴ ∇f(2, 7) = (7)i + (2)j. Hence the gradient vector ∇f(2, 7) = (7)i + (2).j. Tangent line to the level curve f(x, y) = 14 at the point (2, 7)Level curve f(x, y) = 14 is f(x, y) = xy = 14. Therefore, y = 14/x. Then, ∂y/∂x = -14/x²We know that the slope of the tangent line to the level curve is the value of the gradient vector ∇f at the point (2, 7).Therefore, slope = ∇f(2, 7) = 7So, the slope of the tangent line is 7 and it passes through the point (2, 7).Therefore, the equation of the tangent line is given by y-7 = 7(x-2) or y = 7x - 7.
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Will give brainiest.
1. At the store, I purchased 3.25 lb of honey crisp apples. The apples cost $15.60. How much does it cost per pound
2. Mr. Santora got 4.3 gallons of gas at Wawa. His bill was $12.47. How much was each gallon of gas?
3. A grocery store sells fruit snacks that come in two different sizes. Box A has 8 snacks for $2.48. Box B has 12 snacks for $3.48. How much does it cost per snack in Box A? How much does it cost per snack in Box B? How much more does Box A cost than Box B?
4. Ashton works at a drop in day care center. She earned $68.25 for working 6 hours and 30 minutes. How much does Ashton make per hour? How many hours would it take Ashton to earn $126
5. The small poster in the gift shop has a width of 12 inches and a height of 15 inches. The largest poster has a width of 32 inches. What is the height of the largest poster?
6. Lauren took 12 hours to read a 360 page book. At this rate, how long will it take her to read a 400 page book? It will take Lauren _____ hours and ____ minutes.
Answer:
(Hope I got them correct I may have some mistakes)
1. $4.80 per pound
2. $2.90 per gallon
3. 31 cents or $0.31, 29 cents or $0.29, 2 cents
4. $10.50, 12 hours
5. 40 inches
6. 13 hours and 20 min
Step-by-step explanation:
1. $15.60/3.25=
$4.80 per pound
2. $12.47/4.3=
$2.90 per gallon
3. $2.48/8=
31 cents or $0.31
$3.48/12=
29 cents or $0.29
31 cents- 29 cents= 2 cents
4. $68.25/6hr 30 min=
$68.25/6.5=
$10.50
$126/10.5= 12 hours
5. Hope you are doing a ratio problem
12/32=15/x
15*32= 480
480/12=
40 inches
6. 360/12=
30
400/30=
13 1/3=
13 hours and 20 min
A coin is tossed three times. Find the probability of the following events:
(1) A: getting at least two heads
(2) B: getting exactly two heads
(3) C: getting at most one head
Given, the coin is tossed three times.
Sample space: {HHH, HTH, THH, TTH, HHT, HTT, THT, TTT}
Number of positive outcomes = 8
Probability of
(1) A: Getting at least two heads
P(A) = P(Getting 3 heads) + P(Getting 2 heads)
= [tex]\frac{3}{8} +\frac{1}{8}[/tex] Since, P(event) = [tex]\frac{No. of favourable outcomes}{Total no. of possible outcomes}[/tex]
P(A) = [tex]\frac{1}{2}[/tex]
(2) B: Getting exactly two heads
P(B) = [tex]\frac{3}{8}[/tex]
(3) C: Getting at most one head
P(C) = P(Getting zero head) + P(Getting 1 head)
= [tex]\frac{1}{8} + \frac{3}{8}[/tex]
= [tex]\frac{4}{8}[/tex]
P(C) = [tex]\frac{1}{2}[/tex]
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A pelt of 3104 people reveaved that of the respendents that were registered Republicans, 125 aporoved of their representative's job performance, 405 did not, and 733 tad no opinion. of the registered Democrats, 239 approved of their representative's job performance, 433 did not, and 74 had no opinion. of those registered as tindepensents, 117 approved, 107 cd not apprave, and 20 had no opinion, Of the remaining respondents, whe were not registered, 74 approved, 46 did not approve, and 26 had no cpinion. Represent these data in a 3×4 matrix.
Given that a pelt of 3104 people revealed that of the respondents that were registered Republicans, 125 approved of their representative's job performance, 405 did not, and 733 had no opinion. Also, of the registered Democrats, 239 approved of their representative's job performance, 433 did not, and 74 had no opinion.
Moreover, of those registered as independents, 117 approved, 107 did not approve, and 20 had no opinion. Lastly, of the remaining respondents, who were not registered, 74 approved, 46 did not approve, and 26 had no opinion.The required matrix can be obtained as follows:Republicans Democrats Independents Not registered Approved12523911774.Did not approve40543310746No opinion7337420Total126910031004
From the given information, we can observe that the pelt of 3104 people is divided into four categories. These categories are registered Republicans, registered Democrats, registered Independents, and the remaining respondents, who are not registered. Further, the data is given in terms of approval, disapproval, and no opinion.Let us tabulate the data for each of these categories. For registered Republicans, 125 people approved, 405 did not approve, and 733 had no opinion. Similarly, for registered Democrats, 239 people approved, 433 did not approve, and 74 had no opinion. Moreover, for registered Independents, 117 people approved, 107 did not approve, and 20 had no opinion. Lastly, for the remaining respondents who were not registered, 74 people approved, 46 did not approve, and 26 had no opinion.Using the above information, we can represent the data in the form of a matrix. The required matrix has four rows and three columns. The first column represents the category, and the remaining three columns represent approval, disapproval, and no opinion for that category. The final matrix is as follows:
RepublicansDemocratsIndependentsNot registeredApproved12523911774Did not approve40543310746No opinion7337420Total126910031004
Thus, we can conclude that a pelt of 3104 people was divided into four categories, and the data was given in terms of approval, disapproval, and no opinion. Using this information, we represented the data in the form of a 3 × 4 matrix, where the first column represents the category, and the remaining three columns represent approval, disapproval, and no opinion for that category.
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If m<1 = 88 , find the m<3.
Answer:
use symbolab
Step-by-step explanation:
Rhonda decided to invest 15,000 of her retirement fund conservatively . She invested part of this money into one account that pays 4% simple interest and part into another account that pays 2% simple interest . Last year she earned 360$ in intrest . How much did she invest in each type of account ?
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
Total Planned amount to invest = 15,000
Investment A:
Rate = 4% = 0.04
Principal = a
Investment B:
Rate = 2% = 0.02
Principal = b
Total interest earned = $360
Simple interest = principal * rate * time
Simple interest on A + simple interest on B = $360
a + b = 15,000 - - - (1)
(a * 0.04) + (b * 0.02) = 360
0.04a + 0.02b = 360 - - - (2)
a = 15000 - b
0.04(15000 - b) + 0.02b = 360
600 - 0.04b + 0.02b = 360
-0.02b = 360 - 600
-0.02b = - 240
b = 240 / 0.02
b = $12000
a = 15000 - b
a = 15000 - 12000
a = $3000
SHOW WORK PLEASE!!!!!!!!!!!
Answer:
(3x)/2+14=15-x
2*(3x/2+14)=2*(15-x)
3x+14*2=15*2-x*2
3x-2x=30-28
x=2
7. Find two consecutive even integers such that twice the smaller is
26 less than 3 times the larger.
Answer:
20 and 22Step-by-step explanation:
The difference between two consecutive even integers is 2
and even integer is always twice some integer
So:
2x ← smaller of numbers
2x+2 ← larger of numbers
2×2x ← twice the smaller of numbers
3(2x+2) ← three times the larger
3(2x+2)-26 ← 26 less than 3 times the larger
twice the smaller is 26 less than 3 times the larger:
3(2x+2) - 26 = 2×2x
6x + 6 - 26 = 4x
+20 +20
6x - 4x = 20
2x = 20
2x+2 = 20 + 2 = 22
Check: 2×20=40; 40+26 = 66; 66÷3=22
A popular radio station, NPR, transmits a signal that is has a wavelength of 3.38 m. What is the frequency of this signal? Remember that the speed of light is 299,792,458 m.
Answer:
88,695,993.49HertzStep-by-step explanation:
The formula for calculating the velocity of wave is expressed as;
v = fλ
f is the frequency
λ is the wavelength
f = v/λ
Given
v = 299,792,458 m/s
λ = 3.38m
Substitute and get the frequency f
f = 299,792,458 /3.38
f = 88,695,993.49Hertz
Hence the frequency of the signal is 88,695,993.49Hertz
Answer plz and do y’all wanan start a chat
Answer:
Sorry, no thanks
Step-by-step explanation:
The answer for the equation is A and B... I think
Answer:
A B that is what I think the answer is
Help me solve this ASAP worth 25 points
202· 87/100 –100· 87/100 –2· 87/100
Answer:
87
Step-by-step explanation:
Answer:
87
Step-by-step explanation:
V= 1/2bhw
solve for b
Answer:
uhmmm try to search on google ♂️
In a class of 17 students, 3 are math majors. A group of four students is chosen at random.
(a) What is the probability that the group has no math majors?
(b) What is the probability that the group has at least one math major?
(c) What is the probability that the group has exactly two math majors?
Answer:
Step-by-step explanation:
Step1
Definition permutation (order is important):
P(n,r)= n!/(n−r)!
Definition combination (order is not important):
C(n,r) =( n/r )= n!/r!(n−r)!
Step2
a) The order of the students does not matter, because a different order results in the same students being selected, and thus we should use the definition of combination.
We are selecting 3 of the 17 students in the class (of which 3 are math majors and 14 are not math majors).
# of possible outcomes=(17,3)=17!/3!(17−3)!=17!/3!14!=680
There areC(14,3) ways to select 3 of the 14 no math majors.
# of favorable outcomes=C(14,3)= 14!/3!(14−3)! = 14!/3!11! =364
The probability is the number of favorable outcomes divided by the number of possible outcome.
P(no math majors)= # of favorable outcomes/# of possible outcomes
= 364/680= 91/170
≈0.5353=53.53%
Step 3
(b) By part (a):
P(no math majors)=91/170≈0.5353=53.53%
Use the Complement rule
Complement rule:
P(E’)=1−P(E)
P(at least one math major)=1−P(no math majors)=1−91/170
=79/170≈0.4647=46.47%
Step 4
(c) The order of the students does not matter, because a different order results in the same students being selected, and thus we should use the definition of combination.
We are selecting 3 of the 17 students in the class (of which 3 are math majors and 14 are not math majors).
# of possible outcomes=C(17,3)= 17!/3!(17−3)!=17! /3!14!=680
There areC(14,1) ways to select 1 of the 14 no math majors and there are
C(3,2) ways to select 2 of the 3 major majors.
# of favorable outcomes=C(14,1)⋅C(3,2)=14⋅3=42
P(2 math majors)= # of favorable outcomes/# of possible outcomes
= 42/680= 21/340=approx0.0618=6.18%
Question
Show that a language A is Turing recognizable if and only if there is a decider V such that for all x∈Σ∗, x∈A if and only if ∃y∈Σ∗ such that V accepts (x,y).
By proving both directions, we have established the equivalence between a language A being Turing recognizable and the existence of a decider V such that for all x ∈ Σ∗, x ∈ A if and only if ∃y ∈ Σ∗ such that V accepts (x, y).
To prove the statement, we need to show both directions of the "if and only if" statement.
First, let's assume that language A is Turing recognizable. This means that there exists a Turing machine M that recognizes A. We will construct a decider V based on M as follows:
V = "On input (x, y):
Simulate M on input x and y.
If M accepts, accept."
Now, let's analyze the behavior of V. If there exists y such that V accepts (x, y), it means that M accepts both x and y as inputs. Since M recognizes language A, this implies that x ∈ A. Therefore, if V accepts (x, y), then x ∈ A.
On the other hand, if x ∈ A, we know that there exists some string y such that M accepts (x, y). In this case, V will also accept (x, y) because it simulates M and accepts when M accepts. Therefore, if x ∈ A, there exists y such that V accepts (x, y).
We have shown that for all x ∈ Σ∗, x ∈ A if and only if ∃y ∈ Σ∗ such that V accepts (x, y). Hence, the existence of the decider V satisfies the condition for language A to be Turing recognizable.
Next, let's assume that there is a decider V such that for all x ∈ Σ∗, x ∈ A if and only if ∃y ∈ Σ∗ such that V accepts (x, y). We will construct a Turing machine M that recognizes A based on V as follows:
M = "On input x:
For each y in Σ∗, do the following:
Simulate V on input (x, y).
If V accepts, accept."
Now, let's analyze the behavior of M. If x ∈ A, then there exists some y such that V accepts (x, y) according to the assumption. In this case, M will eventually simulate V on input (x, y) and accept. Therefore, if x ∈ A, M will accept.
On the other hand, if x ∉ A, it means that for every y in Σ∗, V rejects (x, y). In this case, M will simulate V on all possible pairs (x, y) and reject for each of them. Therefore, if x ∉ A, M will reject.
We have shown that M recognizes language A based on the existence of the decider V.
By proving both directions, we have established the equivalence between a language A being Turing recognizable and the existence of a decider V such that for all x ∈ Σ∗, x ∈ A if and only if ∃y ∈ Σ∗ such that V accepts (x, y).
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Work out the product of
work out the product of 3 1/3 and 2 1/6
Give your answer as a mixed number.
Answer:
3⅓×2 1/6
10/3×13/6
5/3×13/3
65/3
21 2/3
If f(x) = 3x + 2
Find f(x + 1)
Answer:
use symbolab
Step-by-step explanation:
The area of a rectangular painting is 6348 cm
cm.
If the length of the painting is 92 cm, what is its width?
Width of the painting: cn
cm
David's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs David $4.10 per pound, and type B coffee costs $5.25 per pound. This month's blend used twice as many pounds of type B coffee as type A, for a total cost of $423.40. How many pounds of type A coffee were used?
Answer:
29 pounds of type A coffee was used
Step-by-step explanation:
David's shop makes a blend that is a mixture of 2 coffee
Type A costs $4.10
Type B costs $5.25
Let a represent the number of pounds of type A coffee used
Since this month's blend used twice as many pound of type B coffee as type A
a + 2a
The total cost is $423.40
Therefore the amount of pounds of type A coffee used can be calculated as follows
4.10a + 5.25(2a)= 423.40
4.10a + 10.5a= 423.40
14.6a= 423.40
a= 423.40/14.6
a= 29
Hence 29 pounds of type A coffee was used
2.1 = -0.6m
What is the solution to m?
Answer:
m=-3.5
Good Luck!!!
Answer:
Your answer to this is M=-3.5
What is the length of segment AB with point A and B located at (-4, 1) and (2, 9)
Answer:
The answer is 10 unitsStep-by-step explanation:
The distance between two points or a line segment can be found by using the formula
[tex]d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\[/tex]
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
(-4, 1) and (2, 9)
The length of segment AB is
[tex] |AB| = \sqrt{ ({ - 4 - 2})^{2} + ({1 - 9})^{2} } \\ = \sqrt{( { - 6})^{2} + ({ - 8})^{2} } \\ = \sqrt{36 + 64} \\ = \sqrt{100} \: \: \: \: \: \: \: \: \\ = 10 \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
We have the final answer as
10 unitsHope this helps you
Answer:
The length of segment AB is 10
Step-by-step explanation:
The distance formula is d=[tex]\sqrt{ (x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}[/tex]
With the points (-4,1) and (2,9) you know that [tex]-4=x_{1}, 2=x_{2}, 1=y_{1} ,9=y_{2}[/tex]
Now you put the numbers into the distance formula
d=[tex]\sqrt{(2-(-4))^{2}+(9-1)^2[/tex]
(2-(-4) turns into (2+4) because two negatives equal a positive.
After adding and subtracting you get d=[tex]\sqrt{6^2+8^2[/tex]
You then square [tex]6^2[/tex] and [tex]8^2[/tex] to get [tex]\sqrt{36+64[/tex]
After adding 34+64 you get [tex]\sqrt{100[/tex], which is 10
So the length of segment AB is 10
Kenny is making a small quilt for his new niece. His pattern calls for 4.5 yards of fabric, and he picks out a plaid fabric that costs $3.90 per yard. How much money does Kenny spend on the fabric?
Answer:
He spends $17.55 on the new fabric.
Step-by-step explanation:
First multiply 3.9 (cost of fabric per yard) by 4 (number of yards) to get 15.6. Then divide 3.9 by 2 (since we need half a yard) to get 1.95. Lastly add 15.6 plus 1.95 to get your answer, $17.55.
Answer:
Kenny spent $17.55 on the fabric.
Step-by-step explanation:
Since it costs $3.90 per yard, we need to multiply 3.90 and 4. The product is 15.60, but we still have half a yard left. Simply divide $3.90 by 2 to get the price of half a yard ($1.95). Now, add them together to get $17.55
Please answer correctly !!!!!!!! Will mark brainliest !!!!!!!!!!!
Answer:
D
Step-by-step explanation:
Just simply plus 3 of the equation then you can get the answer.
Hope my answer can help you
Please mark as brainliest!!
A jeweler had a piece of silver that weighed 196.54 grams. she used 98.6 grams to make some jewelry. How many grams of silver did she have left?
Answer:
97.94
Step-by-step explanation:
The number of hits per day on the Web site of a tool company is normally distributed with a mean of 510 and a standard deviation of 100 . a. What proportion of days have more than 650 hits? b. What proportion of days have between 580 and 650 hits? c. Find the number of hits such that only 15% of the days will have the number of hits below this number. Click the icon to view the standard normal table of the cumulative distribution function. a. The proportion of days with more than 650 hits is (Round to four decimal places as needed.) b. The proportion of days with between 580 and 650 hits is (Round to four decimal places as needed.) c. Only 15% of the days will have loss than hits
a. The proportion of days with more than 650 hits is approximately 0.0808.
b. The proportion of days with between 580 and 650 hits is approximately 0.6772.
c. The number of hits such that only 15% of the days will have fewer hits is approximately 406.36.
To solve these questions, we will use the standard normal distribution and the z-score.
a. To find the proportion of days with more than 650 hits, we need to calculate the z-score for 650 and find the area under the standard normal curve to the right of that z-score.
First, calculate the z-score:
z = (x - μ) / σ
z = (650 - 510) / 100
z = 1.4
Using the standard normal table or a calculator, we find the area to the right of the z-score 1.4 is approximately 0.0808.
Therefore, the proportion of days with more than 650 hits is 0.0808 (rounded to four decimal places).
b. To find the proportion of days with between 580 and 650 hits, we need to calculate the z-scores for 580 and 650 and find the area between these two z-scores under the standard normal curve.
First, calculate the z-score for 580:
z1 = (580 - 510) / 100
z1 = 0.7
Next, calculate the z-score for 650:
z2 = (650 - 510) / 100
z2 = 1.4
Using the standard normal table or a calculator, we find the area to the right of z1 (0.7) is approximately 0.7580, and the area to the right of z2 (1.4) is approximately 0.0808. To find the area between these two z-scores, we subtract the smaller area from the larger area:
0.7580 - 0.0808 = 0.6772
Therefore, the proportion of days with between 580 and 650 hits is 0.6772 (rounded to four decimal places).
c. To find the number of hits such that only 15% of the days will have fewer hits, we need to find the z-score that corresponds to the cumulative probability of 0.15 (15%).
Using the standard normal table or a calculator, we find that the z-score corresponding to a cumulative probability of 0.15 is approximately -1.0364.
Now, we can use the z-score formula to find the number of hits:
z = (x - μ) / σ
-1.0364 = (x - 510) / 100
Solving for x:
x - 510 = -1.0364 * 100
x - 510 = -103.64
x = 510 - 103.64
x ≈ 406.36
Therefore, the number of hits such that only 15% of the days will have fewer hits is approximately 406.36.
In summary:
a. The proportion of days with more than 650 hits is approximately 0.0808.
b. The proportion of days with between 580 and 650 hits is approximately 0.6772.
c. The number of hits such that only 15% of the days will have fewer hits is approximately 406.36.
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t/f) when calculating the standard error for p-hat, we use the p-hat not the p under h null. true false
The given statement when calculating the standard error for p-hat, we use the p-hat not the p under h null is false.
When calculating the standard error for p-hat (the sample proportion), we use the value of p under the null hypothesis (p₀) rather than the observed sample proportion (p-hat). This is because the standard error is an estimate of the variability or uncertainty in the sample proportion compared to the population proportion assumed under the null hypothesis.
The standard error formula for p-hat is:
SE(p-hat) = sqrt[(p₀ * (1 - p₀)) / n]
Here, p₀ represents the hypothesized population proportion under the null hypothesis, and n is the sample size. We use p₀ because it represents the proportion assumed to be true in the population when there is no evidence to reject the null hypothesis.
Using p-hat (the observed sample proportion) instead of p₀ would not accurately reflect the assumptions made under the null hypothesis and could lead to incorrect inference and conclusions.
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