23.780 g of acetaldehyde (CH3CHO) reacts completely with oxygen to produce acetic acid (HC2H3O2) using manganese (II) acaetate catalyst according to the equation shown below: 2CH3CHO + O2 → 2HC2H3O2 What mass of oxygen reacted with acetaldehyde ? (Atomic mass: C-12.011 g/mol; 0-15.999 g/mol; H- 1.008 g/mol). Show answer choices 34.558 g 34.494 g 8.623 g 17.247 g​

Assertion and the reason both are correct and it is the correct explanation of the given assertion.AgBr is used in the photographic and X-ray film.

Assertion (A): AgBr is used on photographic and X-ray film.Reason (R): AgBr is photosensitive and changes to Ag and bromine in the presence of sunlight and undergoes a decomposition reaction.It is well known that AgBr is photosensitive and changes to Ag and bromine in the presence of sunlight and undergoes a decomposition reaction.What is AgBr-AgBr is the chemical formula of Silver Bromide which is an ionic compound of silver and bromine. It is insoluble in water, but is soluble in ammonia and solutions of alkali cyanides. It is used in photographic films and papers as the light-sensitive component. During photographic development, silver ions are reduced by the developer to metallic silver which forms a visible image on the film or paper.A more technical approachAgBr, being photosensitive, undergoes decomposition on exposure to light. The AgBr molecules absorb light photons, which excite the electrons present in the molecules. These excited electrons then jump from their ground state to the conduction band, leaving behind holes in the valence band. These holes then react with bromide ions present in the AgBr lattice to form Br2. AgBr → Ag + Br This decomposition of AgBr is responsible for the formation of an image on the photographic film.

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The incorrect part of the chemical equation is the coefficient for the oxygen gas reactant.

        2 C2H6 + 7 O2 → 4 CO2 + 6 H2O

        2 C2H10 (should be C2H6) + 10 O2 → 8 CO2 + 10 H2O

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The oxidation state of nitrogen (N) in NaNO3 is +5. option B

To determine the oxidation state of nitrogen (N) in sodium nitrate (NaNO3), we need to assign oxidation numbers to each element in the compound.

In NaNO3, we know that the sodium ion (Na+) has a +1 oxidation state because it is an alkali metal. Oxygen (O) typically has an oxidation state of -2 in compounds, and there are three oxygen atoms in NaNO3. Since the compound is neutral, the sum of the oxidation states must be zero.

Let's assume that the oxidation state of nitrogen is x. Therefore, we can set up the equation:

(+1) + x + (-2) * 3 = 0

Simplifying the equation:

+1 + x - 6 = 0

x - 5 = 0

x = +5

Therefore, the oxidation state of nitrogen (N) in NaNO3 is +5.

The oxidation state of an element indicates the number of electrons it has gained or lost in a compound. In this case, the nitrogen atom in NaNO3 has gained five electrons to achieve a stable oxidation state of +5.

It is important to note that oxidation states are formal charges and do not necessarily represent the actual distribution of electrons in a compound. They are assigned based on a set of rules and can be useful in understanding the reactivity and behavior of elements in chemical reactions.

Option B

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Answer:

The correct description of a mixture is:

The particles do not retain their individual chemical properties, and they can only be separated by physical means.

In a mixture, different substances are combined physically, but they do not undergo any chemical bonding or reaction. The components of a mixture retain their individual physical and chemical properties. This means that the particles in a mixture can be separated by physical methods such as filtration, distillation, or evaporation, without undergoing any chemical changes.

Answer:

I think it's B. The particles are not chemically bonded, and they can only combine in certain set ratios. AI approved.

Hope this helps :)

The balanced ionic equation shows that the reaction is balanced on both sides and that the number of atoms of each element remains the same.

When ammonium bromide and copper(I) chromate are mixed, an ionic reaction occurs that produces precipitates of copper(I) bromide and ammonium chromate. These precipitates are insoluble in water, which causes them to separate from the solution. Therefore, the balanced ionic equation for the reaction is as follows:3Cu2+ (aq) + 2CrO42- (aq) + 12NH4+ (aq) + 12Br- (aq) → Cu3Br2 (s) + (NH4)2CrO4 (s)Ionic reactions are chemical reactions in which ions in aqueous solutions interact with one another. In this reaction, ammonium bromide and copper(I) chromate dissociate into their respective ions when they come into contact with one another. Ammonium bromide dissociates into ammonium ions (NH4+) and bromide ions (Br-), while copper(I) chromate dissociates into copper ions (Cu2+) and chromate ions (CrO42-).Upon mixing, the ions combine to form copper(I) bromide (Cu3Br2) and ammonium chromate ((NH4)2CrO4), which precipitate out of solution as solid products.

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Answer:

Within smokestacks and tailpipes

Explanation:

this is where manmade ozone is usually produced

The statement "increasing the force will increase the moment" is true.

This is because the moment is a measure of the turning effect of a force on an object about a pivot point. It is defined as the product of the force and the perpendicular distance between the force and the pivot point. The unit of moment is the newton-meter (Nm) or the joule (J).When a force is applied to an object, it will produce a moment about the pivot point if the force is not acting along the same line as the pivot point. The magnitude of the moment depends on the force applied and the distance of the force from the pivot point. As the force increases, the moment also increases, provided that the distance from the pivot point remains constant. Conversely, if the force remains constant, but the distance from the pivot point increases, the moment also increases. This is because the perpendicular distance is directly proportional to the moment, meaning that a longer distance results in a larger moment.Therefore, it can be concluded that increasing the force applied to an object will increase the moment produced about a pivot point.

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The volume of gold in cubic meters is approximately 0.00003529 m3.

To find the volume of gold in cubic meters, we need to first convert the given mass of gold from pounds to grams and the density of gold from grams per cubic centimeter to kilograms per cubic meter. Once we have the mass and density in SI units, we can use the formula for density to calculate the volume of gold.
Step-by-step solution:
Given: Mass of gold = 1.5 lbs; Density of gold = 19.3 g/cm3.
We know that 1 lb = 0.453592 kg, so the mass of gold in grams is:
1.5 lbs × 0.453592 kg/lb × 1000 g/kg = 680.388 g
We also know that 1 cm3 = 10-6 m3, so the density of gold in kg/m3 is:
19.3 g/cm3 × 1000 kg/g × (10-6 m3/cm3) = 19300 kg/m3
Now we can use the formula for density:
Density = Mass/Volume
to find the volume of gold in cubic meters:
Volume = Mass/Density
Volume = 680.388 g/19300 kg/m3
Volume = 0.00003529 m3
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mass = 1.306 grams of Nickel Sulfate (NiSO₄)

The mass of a compound (with symbol m ) can be determined by multiplying the number of moles of compound (with symbol n ), by its molar mass. (in grams per mole; with symbol M ) Considering their units, this can be represented as:

[tex]\Large \text{$\rm mol\times g/mol = g$}[/tex]

Therefore, mass = moles × molar mass:

[tex]\boxed{\begin{tabular}{c}\Large\text{$\large \text{$\rm mass = moles\times molar\ mass$}$} \\\\ \huge\textsf{$\implies\rm m = n \times M$ }\\\end{tabular}}\\[/tex]

Plugging in the following values:

[tex]\boxed{\boxed{\begin{tabular}{c}\Large\text{$\Large \text{$\rm m = 0.00844\times 154.76$}$} \\\\ \Large\textsf{$\therefore \rm mass = 1.306\ grams$ }\\\end{tabular}}}\\[/tex]

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Answer:

Explanation:

Hess’s law derives directly from the law of conservation of energy, as well as its expression in the first law of thermodynamics. By Hess’s law, the net change in enthalpy of the overall reaction is equal to the sum of the changes in enthalpy for each intermediate transformation: ΔH = ΔH1+ΔH2+ΔH3.

A redox reaction is a reaction in oxidation or the loss of electrons occurs simultaneously with reduction involving a gain of electrons.

The balanced equation of the redox reaction by the oxidation number method is as follows: Zn + 2HNO₃ ----> Zn(NO₃)₂ + 2NO₂ + H₂O

The complete equation of the redox reaction is given below as follows:

To balance the chemical reaction by oxidation number, we need to ensure that the total change in oxidation numbers for each element is zero on both sides of the equation.

Let's assign the oxidation numbers to the elements:

In Zn(NO₃)₂, the oxidation number of Zn is +2, and the oxidation number of each NO₃ group is -1.

In HNO₃, the oxidation number of H is +1, the oxidation number of N is +5, and the oxidation number of each O in NO₃ is -2.

On the product side, the oxidation number of Zn is +2, and the oxidation number of each NO₃ group is -1. The oxidation number of N in NO₂ is +4, and the oxidation number of each O is -2. The oxidation number of H in H₂O is +1, and the oxidation number of O is -2.

Now, let's balance the reaction by considering the changes in oxidation numbers:

Zn: 0 → +2

H: +1 → 0

N: +5 → +4

O: -2 → -2

To balance the oxidation numbers, we need two NO₂ molecules on the product side. The balanced equation is:

Zn + 2HNO₃ ----> Zn(NO₃)₂ + 2NO₂ + H₂O

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The percent by mass of diluted solution, given that the hydrochloric acid is diluted by adding 500 g of water is 17.5%

First, we shall determine the mass of the HCl in the solution. Details below:

Mass of HCl = Percentage × mass of solution

= 0.35 × 0.5

= 0.175 Kg

Finally, we shall obtain the percent by mass of diluted solution

Percentage = (mass of HCl / mass of diluted solution) × 100

= (0.175 / 1) × 100

= 17.5%

Thus, we can conclude that the percent by mass of diluted solution is 17.5%

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Answer:

Explanation:

i) in keeping industrial machine cool

ii) in textile inustries for dying clothes

The endothermic reaction PE diagram is characterized by higher energy products and lower energy reactants.

The Potential Energy (PE) diagram represents the potential energy of the reactants and products. The change in potential energy during a reaction is often an indicator of whether the reaction is endothermic or exothermic.Endothermic reactions are those that absorb energy from their surroundings, while exothermic reactions release energy into their surroundings. The potential energy diagram for an endothermic reaction is characterized by a higher energy of products than that of the reactants.In other words, the energy required to break the bonds in the reactants is less than the energy required to form bonds in the products. The reactants are at a lower energy level than the products on the potential energy curve. The graph of PE diagram for an endothermic reaction is as follows: Image depicting a PE diagram for an endothermic reaction. As a result, Option B represents a PE Diagram for an endothermic reaction.

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Answer: 2.48 L of water is required.

Explanation:

We will use the formula relating concentration and volume:

[tex]M_1V_1 = M_2V_2[/tex]

From the given information, we have:

[tex](18.0 \text{ M})(x) = (0.125 \text{ M})(2.50 \text{ L})[/tex]

then, [tex]x = 0.0174 \text{ L}[/tex]. This represents the amount of stock solution required.

To find the amount of water, we simply subtract the amount of stock solution from the total volume of 2.50 L:

[tex]V_\text{H2O} = 2.50 \text{ L} - 0.0174 \text{ L} = 2.48 \text{ L}[/tex]

The Tc and Pc values of water are very high compared to the room temperature and common atmospheric pressure. As a result, water exists in liquid state under ordinary condition of temperature and pressure.

Water exists in the liquid state under ordinary conditions because its critical temperature (Tc = 647.1 K) and critical pressure (Pc = 220.6 bar) are significantly higher than room temperature and common atmospheric pressure.

The critical temperature is the temperature above which a substance cannot exist in the liquid state regardless of the pressure applied and the critical pressure is the pressure required to convert a substance into a liquid at its critical temperature.

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Approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

To determine the number of molecules of HCl required to form 34.52 g of MgCl₂, we need to use the molar mass and stoichiometry of the balanced equation:

Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)

The molar mass of MgCl₂ is 95.21 g/mol.

First, we need to calculate the number of moles of MgCl₂ formed:

Moles of MgCl₂ = mass of MgCl₂ / molar mass of MgCl₂

Moles of MgCl₂ = 34.52 g / 95.21 g/mol

Moles of MgCl₂ = 0.363 mol

According to the balanced equation, the stoichiometric ratio between HCl and MgCl₂ is 2:1. Therefore, the moles of HCl required can be calculated as follows:

Moles of HCl = 2 * Moles of MgCl₂

Moles of HCl = 2 * 0.363 mol

Moles of HCl = 0.726 mol

To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules of HCl = Moles of HCl * Avogadro's number

Number of molecules of HCl = 0.726 mol * 6.022 x 10^23 molecules/mol

Number of molecules of HCl = 4.37 x 10^23 molecules

Therefore, approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

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The size of the reactor for maximum yield is 4.4 m3 for a mixed-flow reactor, 1.47 m3 for three equal-sized mixed-flow reactors in series, and 4.26 m3 for a plug-flow reactor.

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6.4875 moles of nitrogen gas would be produced if 8.65 moles of copper(II) oxide were reacted with excess ammonia.

Given the following balanced equation, 2 NH₃(g) + 3 CuO (s) → 3 Cu(s) + N₂(g) + 3 H₂O(g). We are required to determine the number of moles of nitrogen gas that would be produced if 8.65 moles of copper(II) oxide were reacted with excess ammonia. We can use stoichiometry to solve this problem. Stoichiometry is the quantitative relationship between the reactants and products in a chemical reaction. It allows us to make predictions about the amount of product produced or reactant required in a chemical reaction. Stoichiometry relies on the balanced chemical equation for the reaction. In this case, the balanced chemical equation is 2 NH₃(g) + 3 CuO (s) → 3 Cu(s) + N₂(g) + 3 H₂O(g).

The balanced chemical equation shows that 2 moles of ammonia react with 3 moles of copper(II) oxide to produce 1 mole of nitrogen gas and 3 moles of water. This means that the mole ratio of ammonia to nitrogen gas is 2:1. We can use this mole ratio to determine the number of moles of nitrogen gas produced in the reaction. We know that 8.65 moles of copper(II) oxide is reacted with excess ammonia. Since copper(II) oxide is the limiting reagent, we can use it to calculate the number of moles of ammonia used in the reaction. The molar ratio of copper(II) oxide to ammonia is 3:2. Therefore, we can calculate the number of moles of ammonia used in the reaction as follows:Number of moles of ammonia = (3/2) × number of moles of copper(II) oxideNumber of moles of ammonia = (3/2) × 8.65Number of moles of ammonia = 12.975 molesWe know that the mole ratio of ammonia to nitrogen gas is 2:1. Therefore, the number of moles of nitrogen gas produced in the reaction is half the number of moles of ammonia used.Number of moles of nitrogen gas produced = (1/2) × number of moles of ammoniaNumber of moles of nitrogen gas produced = (1/2) × 12.975Number of moles of nitrogen gas produced = 6.4875 moles.

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A mixture can be defined as a physical blend of two or more substances that are not chemically combined.

They retain their own properties and can be separated by physical means like filtration, distillation, evaporation, or magnetism. The various types of mixtures include homogeneous mixtures, heterogeneous mixtures, and colloids.Homogeneous mixtures, also known as solutions, are uniform mixtures where the composition is the same throughout. They are not visibly different and consist of a solute (the substance being dissolved) and a solvent (the substance doing the dissolving). For example, salt water is a homogeneous mixture because the salt is dissolved uniformly throughout the water.Heterogeneous mixtures are non-uniform mixtures that consist of two or more phases, each with its own distinct properties. They can be seen with the eye, and the different components can be separated using physical means. An example of a heterogeneous mixture is oil and water. They can be mixed together, but they will eventually separate.Colloids are mixtures where the particle size is intermediate between that of a solution and a suspension. The particles are small enough to not be visible to the eye, but they are large enough to scatter light. Milk is an example of a colloid because it appears homogeneous but is actually made up of small particles of fat and protein dispersed throughout the liquid.In conclusion, a mixture is a physical blend of two or more substances that are not chemically combined. They can be separated by physical means and consist of homogeneous mixtures, heterogeneous mixtures, and colloids.

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The description of the potential energy diagram created by the student aligns with the characteristics of an endothermic reaction, illustrating the energy changes and activation energies involved.

The curve line starting at a higher level and ending at a slightly lower level indicates the change in potential energy during the course of the reaction. In an endothermic reaction, the products have higher potential energy than the reactants.

The curve correctly depicts this energy change, as the reaction progresses from higher potential energy (reactants) to a slightly lower potential energy (products).

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The concentration of the H2SO4 solution is 0.080 M.

The concentration of 50.0 ml of a solution of H2SO4 can be found by titrating the acid with a standardized solution of Ba(OH)2. This can be achieved by first preparing a 0.20M solution of Ba(OH)2 by dissolving a known mass of the reagent in distilled water and diluting to the mark. The end point is reached when all the H2SO4 has reacted with Ba(OH)2 and no more acid is left to react with the reagent.When 40.0 ml of 0.20M Ba(OH)2 titrant was added, we can calculate the amount of moles of Ba(OH)2 that reacted with the H2SO4 and use this value to find the concentration of H2SO4. To do this, we can use the following balanced equation:H2SO4 + 2Ba(OH)2 → BaSO4 + 2H2OFrom the balanced equation, we can see that one mole of H2SO4 reacts with two moles of Ba(OH)2. Thus, the number of moles of Ba(OH)2 used in the titration is given by:(40.0/1000) L × (0.20 mol/L) = 0.008 molWe can use the number of moles of Ba(OH)2 used to calculate the number of moles of H2SO4 present in the original solution. Since one mole of H2SO4 reacts with two moles of Ba(OH)2, the number of moles of H2SO4 in the solution is given by:0.008 mol Ba(OH)2 × (1 mol H2SO4 / 2 mol Ba(OH)2) = 0.004 mol H2SO4.The concentration of H2SO4 is then given by dividing the number of moles of H2SO4 by the volume of the solution in liters:0.004 mol / (50.0/1000) L = 0.080 M.

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