-2(8x-5) + 2x =4(x+5)

[tex]\sqrt{64}[/tex] in terms of [tex]\sqrt[8]{2}[/tex] can be expressed as  [tex](\sqrt[8]{2})^{24}[/tex].

A root is a value in mathematics that, when multiplied by itself a particular number of times, generates a given value.The most commonly used roots are the square root (√), cube root (∛), and nth root (√n), where "n" represents a positive integer. For example, the cube root of 1331 is 11, because 11*11*11=1331.

Roots are important in a variety of mathematical operations, such as solving equations, simplifying expressions, and determining the sides of geometric forms like squares, cubes, and rectangles.

In the given problem,

[tex]\sqrt{64} =\sqrt{2*2*2*2*2*2} =\sqrt{2^{6} } =2^{\frac{6}{2} }=2^3[/tex]      (∵ [tex]\sqrt{a} =a^{\frac{1}{2} }[/tex] and [tex](a^m)^n = a^{mn}[/tex] )

Now, [tex]\sqrt[8]{2} =(2)^\frac{1}{8}[/tex]

Also,  [tex]2=2^\frac{8}{8}[/tex]

∴ [tex]\sqrt{64} =2^3=(2^\frac{8}{8} )^3 = (2^\frac{1}{8} )^{8*3} =(2^\frac{1}{8} )^{24}[/tex]

Hence, [tex]\sqrt{64} =(\sqrt[8]{2})^{24}[/tex]

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Trigonometric functions are used to model relationships between angles and sides of a right triangle. They are particularly useful in solving problems that involve angles, distances, heights, and lengths that are difficult to measure directly.

For example, consider a problem that involves finding the height of a building. By measuring the length of the shadow cast by the building at a particular time of day, the angle of the sun's rays can be calculated using trigonometry. Once the angle is known, the height of the building can be determined using the tangent function.

In contrast, a non-trigonometric function may not be able to model the relationship between the given quantities in such problems, and may not provide an accurate solution. Therefore, when a problem involves angles or distances that are not directly measurable, trigonometric functions are typically the best tool for setting up and solving the problem.

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The chance that a randomly selected individual will buy a car that charges at the least $30,000 is 0.9772, or approximately 97.72%.

To clear up this problem, we need to discover the probability that a randomly selected person will purchase a vehicle that prices as a minimum $30,000, given that the starting income rate of a new automobile on the Monticello vehicle lot is usually dispensed with a mean of $forty,000 and a preferred deviation of $5,000.

We can use the same Standard normal distribution to solve this problem with the aid of changing the beginning sales price of $30,000 to a z-score, and then using a standard normal distribution table or calculator to discover the corresponding opportunity.

The z-rating for a starting sales rate of $30,000 is:

z = (30,000 - 40,000) / 5,000 = -2

Using a standard normal distribution table or calculator, we will locate that the opportunity of a z-score less than or identical to -2 is approximately zero.0228.

But, we need to find the possibility that the starting sales price is at the least $30,000, so we want to subtract this chance from 1:

P(X ≥ 30,000) = 1 - P(X < 30,000)

P(X ≥ 30,000) = 1 - 0.0228

P(X ≥ 30,000) = 0.9772

Therefore, the chance that a randomly selected individual will buy a car that charges at the least $30,000 is 0.9772, or approximately 97.72%.

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Answer:

The area of Jack's rhombus is four times the area of Soshi's rhombus.

Step-by-step explanation:

First, calculate the area of Soshi's rhombus. Use the formula for the area of a rhombus:

[tex]A = bh=\\A=(12)(10)=\\A=120[/tex]

Now, we have the Soshi's rhombus is 120 [tex]in^2[/tex].

Jack's rhombus' base and height are double those of Soshi's; multiply each value by two.

[tex]12*2=24\\\\10*2=20[/tex]

Now, substitute the values in the formula for the area of a rhombus:

[tex]A = bh=\\A=(24)(20)=\\A=480[/tex]

Notice that 480 is 4 times 120.

This is because area is a two-dimensional measure (measured in units squared, like [tex]in^2[/tex]) while length is a one-dimensional measure (measured in regular units, like cm and in), The one-dimensional measures of Jack's rhombus are double those of Soshi's, and to translate this to the two-dimensional measure of area, square 2 (2 squared is 2 times 2).

2 squared is 4, so:

the area of Jack's rhombus is four times that of Soshi's.

Yes, this classic puzzle can be solved by drawing 4 straight lines that cross through all 9 dots without lifting your pencil off the paper or retracing backwards over lines.

To do this, you must extend your lines beyond the boundaries of the 3x3 grid. Start by drawing a line that connects the top left dot to the bottom right dot, then draw a line from the top right dot to the bottom left dot. Next, draw a line from the top middle dot to the bottom middle dot, and finally, draw a line from the left middle dot to the right middle dot. This solution requires thinking outside the box and extending the lines beyond what may seem like the obvious solution.

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Answer:

I would say convenience sampling. It's hard to tell. Sampling every other person is like systematic sampling, BUT convenience sampling would be to sample people that are easy to reach.

We can conclude that cosh2x−sinh2x=1.

An equation is a mathematical statement that states that two expressions are equal. It is typically written as a comparison between two expressions and consists of an equal sign (=). Equations are used to solve mathematical problems, to understand the relationships between different quantities, and to describe the behavior of a physical system. In addition, equations are used to calculate various quantities, such as the area of a circle or the speed of an object.

To show that cosh2x−sinh2x=1, we can use the identities for cosh2x and sinh2x. The identity for cosh2x is cosh2x=2cosh2x−1 and the identity for sinh2x is sinh2x=2sinh2x−1.

Substituting these identities into the equation cosh2x−sinh2x=1 yields 2cosh2x−1−2sinh2x−1=1. Simplifying this equation yields cosh2x−sinh2x=1, as required. Thus, we can conclude that cosh2x−sinh2x=1.

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Simplifying this equation yields [tex]\cosh^2x-sinh^2x=1[/tex], as required. Thus, we can conclude that [tex]\cosh^2x-sinh^2x=1[/tex].

An equation is a mathematical statement that states that two expressions are equal. It is typically written as a comparison between two expressions and consists of an equal sign (=). Equations are used to solve mathematical problems, to understand the relationships between different quantities, and to describe the behavior of a physical system. In addition, equations are used to calculate various quantities, such as the area of a circle or the speed of an object.

We will show that [tex]\cosh^2x-sinh^2x=1[/tex].

Let us consider the expression [tex]\cosh^2x-sinh^2x.[/tex]

Then, [tex]\cosh^2x=(e^2x+e^{-2}x)/2[/tex] and [tex]sinh^2x=(e^2x+e^{-2}x)/2[/tex]

Substituting, we get [tex]\cosh^2x -\sinh^2x=(e^2x+e^{-2}x)/2\ -(e^2x+e^{-2}x)/2[/tex]

Simplifying, we have [tex]\cosh^2x -\sinh^2x=e^2x+e^{-2}x-e^2x+e^{-2}x[/tex]

[tex]=2e^{-2}x\\\\=2(e^{-2}x)\\\\=2[/tex]

Hence, [tex]cosh^2x-sinh^2x=1[/tex]

Therefore, we have shown that [tex]cosh^2x-sinh^2x=1[/tex]

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The correct form of question is Show that cosh2x−sinh2x=1 .

In the given problem, using  the concept of graph theory  the number of paths that satisfy the given conditions is 3.

To solve this problem, we can use the concept of graph theory, where each room is a vertex, and each doorway is an edge connecting two vertices. Since we cannot pass through the same doorway more than once or revisit a room, this problem can be solved by finding all possible paths in the graph that do not contain cycles.

To find the number of such paths from room A to room F, we can use the depth-first search (DFS) algorithm. We start from room A and explore all possible paths until we reach room F, making sure not to visit the same room or pass through the same doorway more than once.

Using DFS, we can generate all possible paths from room A to room F, and count the number of paths that do not contain cycles. The total number of such paths is the answer to the problem.

Here's the list of all possible paths from room A to room F:

Out of these paths, the following paths contain cycles or revisit a room:

Therefore, the number of paths that satisfy the given conditions is 3.

Note: We can also solve this problem using other algorithms such as Breadth-first search (BFS) or dynamic programming, but DFS is a simple and efficient approach for small graphs like this one.

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Answer: If Amanda runs two miles the first week and then adds two miles each subsequent week, we can create a sequence using arithmetic progression. The common difference between each term in the sequence is two, and the first term is two.

Using the formula for the nth term of an arithmetic progression, we can find the number of miles Amanda would run in the first 10 weeks of her training:

an = a1 + (n-1)d

where:

an = the nth term of the sequence

a1 = the first term of the sequence (2 miles in the first week)

n = the number of terms (up to 10 weeks)

d = the common difference between each term (2 miles per week)

So for n = 1 to 10, we have:

a1 = 2

d = 2

n = 1: a1 + (n-1)d = 2 + (1-1)2 = 2

n = 2: a1 + (n-1)d = 2 + (2-1)2 = 4

n = 3: a1 + (n-1)d = 2 + (3-1)2 = 6

n = 4: a1 + (n-1)d = 2 + (4-1)2 = 8

n = 5: a1 + (n-1)d = 2 + (5-1)2 = 10

n = 6: a1 + (n-1)d = 2 + (6-1)2 = 12

n = 7: a1 + (n-1)d = 2 + (7-1)2 = 14

n = 8: a1 + (n-1)d = 2 + (8-1)2 = 16

n = 9: a1 + (n-1)d = 2 + (9-1)2 = 18

n = 10: a1 + (n-1)d = 2 + (10-1)2 = 20

Therefore, Amanda would run 2, 4, 6, 8, 10, 12, 14, 16, 18, and 20 miles in the first 10 weeks of her training if she followed the new regimen.

Step-by-step explanation:

Answer: To solve -x²-2x=0 by factoring, we can factor out x from the left-hand side:

x(-x-2) = 0

This equation is true if either x = 0 or -x-2 = 0. Solving for x in the second equation:

-x-2 = 0

-x = 2

x = -2

Therefore, the solutions to the equation -x²-2x=0 are x = 0 and x = -2.

To solve x²-4x-8--6x by factoring, we can simplify it first by combining like terms:

x²-10x-8 = 0

To factor this quadratic, we need to find two numbers that multiply to -8 and add to -10. These numbers are -2 and -8, so we can write:

x²-2x-8x-8 = 0

(x²-2x) - (8x+8) = 0

x(x-2) - 8(x+1) = 0

(x-8)(x-2) = 0

Therefore, the solutions to the equation x²-4x-8--6x are x = 8 and x = 2.

To solve 3x² +12=-21x-24 by completing the square, we first need to move all the terms to one side:

3x² + 21x + 36 = 0

Next, we divide both sides by 3 to simplify the coefficient of x²:

x² + 7x + 12 = 0

To complete the square, we need to add and subtract (7/2)² = 49/4 inside the parentheses:

x² + 7x + 49/4 - 49/4 + 12 = 0

(x + 7/2)² = 1/4

Taking the square root of both sides and solving for x, we get:

x + 7/2 = ±1/2

x = -7/2 ± 1/2

Therefore, the solutions to the equation 3x² +12=-21x-24 by completing the square are x = -4 and x = -3.

To solve -x²-3x-13 = -2x² by using the quadratic formula, we first need to move all the terms to one side:

-x² + x - 13 = 0

Next, we identify the coefficients a, b, and c:

a = -1, b = 1, c = -13

Substituting these values into the quadratic formula:

x = (-b ± sqrt(b² - 4ac)) / 2a

x = (-1 ± sqrt(1² - 4(-1)(-13))) / 2(-1)

x = (-1 ± sqrt(1 + 52)) / (-2)

x = (-1 ± sqrt(53)) / (-2)

Therefore, the solutions to the equation -x²-3x-13 = -2x² by using the quadratic formula are approximately x = -3.25 and x = 4.25.

Step-by-step explanation:

The distance between building B and C is 10√2 meters, or 9.38 meters, rounded to two decimal places.

Triangle is a three-sided geometric shape. It has three vertices which join together to form three sides. The sum of the three angles in a triangle is always equal to 180°. It can be classified into three types, namely equilateral, isosceles, and scalene based on the length of the sides. Triangles can also be classified as right, obtuse, or acute depending on the angles. Triangles are one of the most basic shapes in geometry and are used in many real-world applications such as architecture and engineering.

To answer this question, we need to use the Pythagorean theorem, which states that the sum of the squares of the two sides of a right triangle is equal to the square of the hypotenuse.

Using the given information, we can set up the equation:

10² + x² = (x√2)²

Where x is the distance between building B and C.

We can solve this equation with algebra to find x:

100 + x² = 2x²

x² = 100

x = 10√2

Therefore, the distance between building B and C is 10√2 meters, or 9.38 meters, rounded to two decimal places.

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The major flaw of the linear probability model is, Option d, which allows predicted values to range from above 1 to below 0

The binary dependent variable, which accepts values of 0 and 1, and the independent variables are assumed to have a linear relationship under the linear probability model.

The anticipated values from the linear probability model, however, can range from 0 to 1, and in some circumstances, they can be either above or below 0. This goes against the dependent variable's probabilistic character and can produce inaccurate forecasts.

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The formula for the confidence interval standard error would be:

CI SE = 1.96 * sqrt[(p1 * (1 - p1) / n1) + (p2 * (1 - p2) / n2)]

To calculate the standard error for the difference in sample proportions, we use the following formula:

SE = sqrt[(p1 * (1 - p1) / n1) + (p2 * (1 - p2) / n2)]

Where p1 and p2 are the sample proportions, n1 and n2 are the sample sizes.

To calculate the confidence interval standard error, we need to multiply the standard error by the appropriate critical value from the t-distribution.

Assuming a 95% confidence interval with degrees of freedom equal to (n1 - 1) + (n2 - 1), we can use a t-distribution table or calculator to find the critical value, which is typically 1.96.

So, the formula for the confidence interval standard error would be:

CI SE = 1.96 * sqrt[(p1 * (1 - p1) / n1) + (p2 * (1 - p2) / n2)]

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The correct answer is option B. Translate 1 to the left, scale vertically by 1/2, then reflect over the y-axis.

The process of modifying the shape, location, or features of a graph is often referred to as graph transformation. Graphs are visual representations of mathematical functions or data point connections, often represented on a coordinate plane.

Translations, reflections, rotations, dilations, and other changes to the look of a graph are examples of graph transformations.

For the given problem, Transformation to get the desired result can be carried out as:

Hence, to convert the graph of "y = k(x)" to the graph of "y = -k(x + 1)," the correct sequence of transformations is to translate 1 unit to the left, scale vertically by 1/2, and then reflect across the y-axis, which is option B.

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∠A = ∠C in trapezoid ABCD with arcAB = arcCD, can be proven with the property of isosceles triangles.

Since arcAB = arcCD, the lengths of the two arcs are equal. This implies that the lengths of the segments subtended by these arcs, AB and CD, are also equal.

Let E and F be the midpoints of the non-parallel sides AD and BC, respectively. Connect E and F with a line segment EF.

Since E and F are midpoints, DE = EA and BF = FC. In addition, since AB = CD = L, we can say that:

DE + EA = BF + FC

EA = FC

So, by the Hypotenuse-Leg (HL) theorem of congruence, triangles AEF and CFE are congruent:

ΔAEF ≅ ΔCFE

Now, since the triangles are congruent, their corresponding angles are equal:

∠A = ∠C

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Based on the given information about the acf for the gap sales. The statement "there is clear evidence in the acf that there is a strong trend in the data" is correct. so, the correct option is A).

The given statement is correct as the autocorrelation function (ACF) measures the correlation between a time series and its lagged values. If there is a strong trend in the data, it will be reflected in the ACF as a significant correlation at lag 1 and beyond. Therefore, a clear evidence of a strong trend in the data can be observed in the ACF.

However, the other answer choices cannot be determined from the information provided. There is no information provided regarding seasonality or the stationarity of the data, and the information provided is not sufficient to determine whether the data has fallen in the last 12 periods. so, the correct answer is A).

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The Riemann sum that represents the illustration on the graph is the second option as i goes from 1 to 4:

[tex]1∑2 {(xᵢ)}^{2} [/tex]

The Riemann sum is a mathematical concept used to approximate the area under a curve. It is named after the German mathematician Bernhard Riemann.

The idea behind the Riemann sum is to divide the area under the curve into a series of rectangles, where the height of each rectangle is determined by the function being integrated, and the width of each rectangle is determined by the size of the intervals used to divide the domain of the function. The area of each rectangle is then calculated and added together to get an approximation of the total area under the curve.

The Riemann sum is written in the following form:

[tex]∑f(xᵢ)Δxᵢ[/tex]

where f(xᵢ) is the value of the function at the ith point in the interval, Δxᵢ is the width of the ith rectangle, and the sum is taken over all i intervals.

Thus, the Riemann sum that represents the illustration on the graph as i goes from 1 to 4 is:

[tex]1∑2 {(xᵢ)}^{2} [/tex]

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The pair of figures having same volume are:

1. The rectangular prism length is labeled 16 units, width of 6 units, and height of 6 units ; The rectangular prism length is labeled 8 units, width of 8 units, height of 9 units.

2. The cylinder has a radius of 3 units and a height of 8 units ; The cone has a radius of 6 units and a height of 6 units.

3. The cone has a radius of 8 units and a height of 9 units ; The cylinder has a radius of 4 units and a height of 12 units.

What is volume of a figure?

A measurement of three-dimensional space is volume. It is frequently expressed quantitatively using SI-derived units, as well as several imperial or US-standard units. Volume and the notion of length are connected.

1. 3-D shape of a cone is represented. The cone has a radius of 4 units and a height of 12 units.

⇒ Volume = π[tex]r^{2} \frac{h}{3}[/tex]

⇒ Volume = π[tex]4^{2} \frac{12}{3}[/tex]

⇒ Volume = 64 π

⇒ Volume = 201 cubic units

2. 3-D shape of a rectangular prism is represented. The rectangular prism has a length of 18 units, a width of 6 units, a height of 6 units.

⇒ Volume = length * width * height

⇒ Volume = 18 * 6 * 6

⇒ Volume = 648 cubic units

3. 3-D shape of a rectangular prism is represented. The rectangular prism length is labeled 16 units, width of 6 units, and height of 6 units.

⇒ Volume = length * width * height

⇒ Volume = 16 * 6 * 6

⇒ Volume = 576 cubic units

4. 3-D shape of a cylinder is represented. The cylinder has a radius of 3 units and a height of 8 units.

⇒ Volume = π[tex]r^{2}[/tex]h

⇒ Volume = π[tex]3^{2}[/tex] * 8

⇒ Volume = 72 π

⇒ Volume = 226 cubic units

5. 3-D shape of a cone is represented. The cone has a radius of 8 units and a height of 9 units.

⇒ Volume = π[tex]r^{2} \frac{h}{3}[/tex]

⇒ Volume = π[tex]8^{2} \frac{9}{3}[/tex]

⇒ Volume = 192 π

⇒ Volume = 603 cubic units

6. 3-D shape of a rectangular prism is represented. The rectangular prism length is labeled 8 units, width of 8 units, height of 9 units.

⇒ Volume = length * width * height

⇒ Volume = 8 * 8 * 9

⇒ Volume = 576 cubic units

7. 3-D shape of a cylinder is represented. The cylinder has a radius of 4 units and a height of 12 units.

⇒ Volume = π[tex]r^{2}[/tex]h

⇒ Volume = π[tex]4^{2}[/tex] * 12

⇒ Volume = 192 π

⇒ Volume = 603 cubic units

8. 3-D shape of a cone is represented. The cone has a radius of 6 units and a height of 6 units.

⇒ Volume = π[tex]r^{2} \frac{h}{3}[/tex]

⇒ Volume = π[tex]6^{2} \frac{6}{3}[/tex]

⇒ Volume = 72 π

⇒ Volume = 226 cubic units

Hence, the required solution has been obtained. Three pairs have same volume.

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The 95% confidence interval for the standard deviation of the height of students at UH is (1.918, 5.732), which corresponds to option b.

To construct a 95% confidence interval for the standard deviation of the height of students at UH, we will use the Chi-square distribution. Given the sample standard deviation (s) of 3.2 feet, a sample size (n) of 19 students, and assuming normality for the data, we can find the confidence interval as follows:
1. Determine the degrees of freedom: df = n - 1 = 19 - 1 = 18
2. Identify the Chi-square values for the confidence level (95%): χ²_lower = 7.632, χ²_upper = 32.852 (using a Chi-square table or calculator)
3. Calculate the lower and upper bounds of the confidence interval:
Lower bound = sqrt((n - 1) * s² / χ²_upper) = sqrt(18 * (3.2)² / 32.852) ≈ 1.918
Upper bound = sqrt((n - 1) * s² / χ²_lower) = sqrt(18 * (3.2)² / 7.632) ≈ 5.732

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The 95% confidence interval for the standard deviation of the height of students at UH is approximately (1.918, 5.732), Option B.

Construct a 95% confidence interval for the standard deviation of the height of students at UH, we'll use the given data and the Chi-Square distribution.

Here's a step-by-step explanation:
SRS (simple random sample) of 19 students, which means the degrees of freedom (df) = n - 1 = 19 - 1 = 18.
The sample standard deviation (s) is given as 3.2 feet.
Assume normality for the data.
A 95% confidence interval, we'll use the Chi-Square distribution table to find the critical values.

The two tail probabilities are 0.025 and 0.975, so we'll look up the Chi-Square values for 18 degrees of freedom and these probabilities:
[tex]- X^2_{0.025} = 30.191 (upper limit)[/tex]
[tex]- X^2_{0.975} = 8.231 (lower limit)[/tex]
Calculate the confidence interval for the population standard deviation (σ):
[tex][tex](\sqrt((n - 1) \times s^2 / X^2_{upper}), \sqrt((n - 1) \times s^2 / X^2_{lower}))[/tex][/tex]
Plug in the values:
[tex]- n = 19[/tex]
[tex]- s = 3.2[/tex]
[tex]- df = 18[/tex]
[tex][tex]- X^{2} _{upper} = 30.191[/tex][/tex]
[tex][tex]- X^2_{lower} = 8.231[/tex][/tex]
Calculate the confidence interval:
[tex](√((18 \times 3.2^2) / 30.191), \sqrt((18 \times 3.2^2) / 8.231)) \approx (1.918, 5.732)[/tex]

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Answer:

c

Step-by-step explanation:

To compare the price per ounce of peas, we can divide the cost by the number of ounces in each can:15 ounce can: 49 cents / 15 ounces = 3.27 cents per ounce24 ounce can: 98 cents / 24 ounces = 4.08 cents per ounceBased on this calculation, the 15 ounce can of peas for 49 cents is the better buy in terms of price per ounce.b. To compare the price per package of margarine, we can divide the cost by the number of packages:Three packages: 99 cents / 3 packages = 33 cents per packageFive packages: $1.59 / 5 packages = 31.8 cents per packageBased on this calculation, the five packages for $1.59 is the better buy in terms of price per package.c. To compare the price per pound of beans, we can divide the cost by the number of pounds:4 pounds: $2.25 / 4 pounds = 56.25 cents per pound6 pounds: $3.95 / 6 pounds = 65.83 cents per poundBased on this calculation, the 4 pounds of beans for $2.25 is the better buy in terms of price per pound.

Answer:

1. 15 ounce can of peas for 49 cents would be a better buy

2.  five for $1.59 would be a better buy

3. 4 pounds of beans for $2.25 would be a better buy

For the first question, we can use unit price to determine which is the better buy. The unit price of the 15 ounce can of peas is 3.27 cents per ounce, while the unit price of the 24 ounce can is 4.08 cents per ounce. Therefore, the 15 ounce can is the better buy.

For the second question, we can use unit price again. The unit price of three packages of margarine is 33 cents per package, while the unit price of five packages is 31.8 cents per package. Therefore, buying five packages is the better buy.

To determine the better buy, we can use unit price once again. The unit price of 4 pounds of beans is 56.25 cents per pound, while the unit price of 6 pounds of beans is 65.83 cents per pound. Therefore, buying 4 pounds of beans for $2.25 is the better buy.

If the area of a kite is 35cm square, the area of the new kite with all diagonals multiplied by 2 is 70 cm².

If we multiply all the diagonals of a kite by 2, then the area of the new kite will be 4 times the area of the original kite.

The area of a kite is given by the formula:

Area = (diagonal 1 x diagonal 2)/2

Let the diagonals of the original kite be d1 and d2. Then, the area of the original kite can be expressed as:

Area = (d1 x d2)/2 = 35 cm²

If we multiply all the diagonals of the original kite by 2, then the new diagonals will be 2d1 and 2d2. The area of the new kite can be expressed as:

New area = (2d1 x 2d2)/2 = 2d1d2

Substituting the value of d1d2 from the original equation, we get:

New area = 2d1d2 = 2 x (d1 x d2) = 2 x Area = 2 x 35 cm² = 70 cm²

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The equation of g(x) in parabola vertex form is g(x) = (x + 4)^2 + 3. Option (D) is the correct answer.

Since the vertex of the parabola is at (-4, 3), we can write the equation of the parabola in vertex form as:

g(x) = a(x + 4)^2 + 3

where "a" is a constant that determines the shape of the parabola. Since the parabola opens upward, "a" must be positive.

We also know that the parabola passes through the points (-6, 7) and (-2, 7). Substituting these values into the equation above, we get:

7 = a(-6 + 4)^2 + 3

7 = 4a + 3

4a = 4

a = 1

Substituting "a = 1" into the equation above, we get:

g(x) = (x + 4)^2 + 3

Therefore, the equation of g(x) in vertex form is g(x) = (x + 4)^2 + 3. Option (D) is the correct answer.

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the value of the car decreases by 15 percent each year. This means that the value of the car decreases to 85% of its previous year's value every year.

what do you mean by term  decreases  ?

In this context, "decreases" means that the value of the car is getting smaller over time. The term "decrease" is often used in mathematics to describe a decrease in the numerical value of a quantity. In this case, the value of the car is decreasing by 15% each year, which means that its value is getting smaller by 15% of the previous year's value.

In the given question,

The given function for the value of the car is:

v(t) = P(0.85)ⁿ

Here, P is the initial purchase price of the car, and t is the time in years since the car was purchased.

To find the percent that the value of the car decreases by each year, we need to find the ratio of the decrease in value to the initial value, and express it as a percentage.

Let's consider the value of the car after one year, i.e., when t=1. The value of the car after one year is:

v(1) = P(0.85)¹ = 0.85P

The decrease in value from the initial value P is:

P - v(1) = P - 0.85P = 0.15P

Therefore, the ratio of the decrease in value to the initial value is:

(0.15P/P) = 0.15

To express this ratio as a percentage, we multiply by 100, which gives:

0.15 x 100% = 15%

Therefore, the value of the car decreases by 15% each year. This means that the value of the car decreases to 85% of its previous year's value every year.

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The theoretical probability of the spinner not landing on red is 0.875.

The total number of sections on the spinner is 8, out of which only one section is red. Therefore, the probability of the spinner landing on red is:

P(Red) = 1/8

The probability of the spinner not landing on red would be the probability of landing on any other section, which is:

P(Not Red) = 1 - P(Red) = 1 - 1/8 = 7/8

Therefore, the theoretical probability of the spinner not landing on red is 7/8 or 0.875 in decimal form.

So, the correct answer is: 0.875.

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Answer:

D

Step-by-step explanation:

The GCF of 48 and 60 is 12

To find the greatest common factor (GCF) of 48 and 60, we can start by finding the prime factorization of each number

48 = 2^4 × 3

60 = 2^2 × 3 × 5

Next, we can identify the common factors of both numbers by looking at their prime factorization

The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

The common factors of 48 and 60 are: 1, 2, 3, 4, 6, and 12.

The greatest common factor is the largest number that both 48 and 60 can be divided evenly by. In this case, that number is 12. Therefore, the GCF is 12.

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The given question is incomplete, the complete question is:

Find the GCF of 48 and 60.

The composite function h(2) - g(-3) has a value of 9 when evaluated

To find h(2) - g(-3), we need to first evaluate h(2) and g(-3) separately using the given functions:

h(2) = 2^2 - 1 = 4 - 1 = 3

g(-3) = 2(-3) = -6

Now we can substitute these values in the expression h(2) - g(-3) and simplify:

h(2) - g(-3) = 3 - (-6)

Evaluate

h(2) - g(-3) = 9

Hence, the solution is 9

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Answer:

Step-by-step explanation:

Graph #          Matching equation

1                             |-3x|

2                            |-x|

3                           -|2x|

You can tell which one matches by finding the slope and whether the V points up or down

Answer:

Step-by-step explanation:

yeah she is... i think.. this is twisting my mind rn