The specific heat of the glass is 1.58 J/(g°C).
The specific heat of a substance is the amount of energy required to raise the temperature of one unit of mass of the substance by one degree Celsius.
To find the specific heat of the glass, we can use the formula:
Q = mcΔT
where Q is the amount of energy transferred to the glass, m is the mass of the glass, c is the specific heat of the glass, and ΔT is the change in temperature of the glass.
We are given:
m = 385 g
Q = 7032 J
ΔT = 24°C - 12°C = 12°C
Substituting these values into the formula, we get:
7032 J = (385 g) c (12°C)
Solving for c, we get:
c = 7032 J / (385 g * 12°C)
c = 1.58 J/(g°C)
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Which of the following is NOT a function of the skeletal system?
moving blood through your body
protecting soft body parts
supporting your body
providing a place for muscles to attach
Answer:
Moving blood through your body
Explanation:
Thats the job of vascular system IE heart arteries and veins.
How many moles of ammonia are produced when 4. 8 moles of nitrogen react with hydrogen? N2 + 3H2 — 2NH3
9.6 moles of ammonia are produced when 4.8 moles of nitrogen react with hydrogen.
To answer this question, we will use the balanced chemical equation provided: N2 + 3H2 — 2NH3. From this equation, we can see that for every 1 mole of nitrogen that reacts, 2 moles of ammonia are produced.
So, to determine how many moles of ammonia are produced when 4.8 moles of nitrogen react with hydrogen, we will first need to calculate how many moles of nitrogen are present in the reaction.
Since the coefficient for nitrogen is 1 in the balanced equation, we know that the number of moles of nitrogen is equal to 4.8.
Now we can use the mole ratio from the balanced equation to determine the number of moles of ammonia produced.
For every 1 mole of nitrogen, 2 moles of ammonia are produced, so we can set up a ratio:
1 mole of nitrogen : 2 moles of ammonia
Using the number of moles of nitrogen we calculated earlier (4.8 moles), we can multiply it by the ratio to find the number of moles of ammonia produced:
4.8 moles of nitrogen x 2 moles of ammonia / 1 mole of nitrogen = 9.6 moles of ammonia
Therefore, 9.6 moles of ammonia are produced when 4.8 moles of nitrogen react with hydrogen.
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For photosynthesis to occur, 2801 kJ/mole of energy is required. Add the ΔH to the correct side of the equation below:
6 CO2 (g) + H2O (l) --> C6H12O6 (aq) + 6 O2 (g)
The change in heat or enthalpy change in the reaction for photosynthesis to occur has + 2801 kJ of energy on the reactant side.
Which part holds the energy?To show the energy necessary for the reaction to occur, the proper ΔH value should be added to the left side of the equation. As a result, the equation is:
6 CO₂ (g) + 6 H₂O (l) + 2801 kJ → C₆H₁₂O₆ (aq) + 6 O₂ (g)
it is true that the energy value is included as a reactant in the reaction, since it is required for the reaction to take place.
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I NEED HELP ON THIS ASAP!!!
Answer: I believe it's A
Source: Trust me bro
Please help!!! The following thermodynamically favored reaction takes place in an acidified
galvanic cell.
O2(g) + 2 H2S(g) 2 S(s) + 2 H2O(l)
a. What is the half reaction that takes place at the anode?
b. What is the half reaction the takes place at the cathode?
c. Calculate the standard cell potential, Eo
cell.
d. What must the partial pressures of the reactants be in order to produce the
voltage in part c?
a. The anode is where oxidation occurs, so the half reaction taking place at the anode is: O₂(g) + 4 H⁺(aq) + 4 e⁻→ 2 H₂O(l)
b. The cathode is where reduction occurs, so the half reaction taking place at the cathode is: 2 H⁺(aq) + 2 e⁻+ 2 H₂S(g) → 2 S(s) + 2 H₂O(l)
c. To calculate the standard cell potential, Eocell, we need to add the reduction potential of the cathode and the oxidation potential of the anode. The reduction potential of the cathode half reaction is +0.15 V, and the oxidation potential of the anode half reaction is -1.23 V. Therefore, Eocell = +0.15 V + (-1.23 V) = -1.08 V.
d. To produce the voltage of -1.08 V, the reaction must be spontaneous, which means that the Gibbs free energy change, ΔG, must be negative.
The relationship between ΔG, Eocell, and the equilibrium constant, K, is: ΔG = -nFEocell = -RTlnK, where n is the number of electrons transferred, F is Faraday's constant, R is the gas constant, and T is the temperature.
Solving for K, we get: K = e^(-ΔG/RT) = e^(-nFEocell/RT).
Substituting the values, we get: K = e^(-(-2)(96485 C/mol)(-1.08 V)/(8.314 J/mol-K)(298 K)) = 4.5 x 10¹⁸. Since the reaction is in acid, the partial pressure of H⁺ is 1 atm.
Using the equilibrium constant expression for the reaction, K = [S]²/[H₂S]², we can solve for the partial pressure of H₂S: P(H₂S) = [S]/√K. Substituting the values, we get: P(H₂S) = (1 atm)/√(4.5 x 10¹⁸) = 6.7 x 10⁻¹⁰atm.
Therefore, the partial pressure of H₂S must be 6.7 x 10⁻¹⁰ atm, and the partial pressure of O₂ must be 1 atm, to produce the voltage in part c.
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Review this reaction:
H2SO4+NaOH->?.
What are the products?
Dalton's Law and the Ideal Gas Law
At what pressure will 4. 80 moles of fluorine gas have a volume of 60. 0 liters and a temperature of 298 K?
The pressure of the fluorine gas under these conditions is approximately 2.01 atmospheres.
To answer your question, we will use the Ideal Gas Law equation:
PV = nRT
Where:
P = pressure
V = volume (60.0 liters)
n = number of moles (4.80 moles)
R = gas constant (0.0821 L atm / K mol)
T = temperature (298 K)
We need to find the pressure (P). Rearrange the equation for P:
P = nRT / V
Now plug in the given values:
P = (4.80 moles * 0.0821 L atm / K mol * 298 K) / 60.0 liters
P ≈ 2.01 atm
So, the pressure of the fluorine gas under these conditions is approximately 2.01 atmospheres.
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How many joules are required to raise the temperature of 100.0 grams of water from -269 degrees celsius to 1500 degrees celsius
About 739,982.4 Joules energy is required to raise the temperature of 100.0 grams of water from -269 degrees Celsius to 1500 degrees Celsius.
The formula for the change in heat is,
Q = mcΔT, the amount of energy required is Q, m is the mass of water, specific heat capacity of water is c, the change in temperature is ΔT,
ΔT = 1500°C - (-269°C)
ΔT = 1769°C
Next, we can look up the specific heat capacity of water, which is 4.184 J/g°C. Then, we can substitute the values into the formula,
Q = 100.0 g * 4.184 J/g°C * 1769°C
Q = 739,982.4 J
Therefore, it would require 739,982.4 Joules of energy to raise the temperature of 100.0 grams of water from -269 degrees Celsius to 1500 degrees Celsius.
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You are in a car traveling 60 mph. the car stopped suddenly and you are thrown forward but are stopped by the seat belt. why are you thrown forward?
Answer:
when u stop at great speed in a vechial your body is in still in motion
Explanation:
Is the hypothesis that a particular trait evolved by natural selection falsifiable? That is, if you thought a particular trait didn't evolve by natural selection, could you test that our for yourself, given sufficient time, resources, an an organism that isn't too difficult to study?
Group of answer choices
Yes, the hypothesis that a particular trait evolves by natural selection is falsifiable
No, the hypothesis that a particular trait evolved by natural selection is intrinsic to a modern understanding of biology and the *theory* of evolution by Natural Selection. Therefore in order to disprove that a particular trait evolved by natural selection, you would need to accumulate so much evidence that you could overturn that entire theory,.
It's impossible to tell - unlike other scientific theories, the idea that a trait evolved by natural selection is more of a philosophical position - you can't really test it
Yes, but to do that you would be required to show that the trait isn't heritable, and that it doesn't provide a fitness advantage, and that it doesn't vary in your population.
The hypothesis that a particular trait evolved by natural selection is indeed falsifiable. In fact, this is one of the foundational principles of the scientific method.
researchers must also consider alternative hypotheses and rule out alternative explanations before concluding that a trait evolved by natural selection.
The hypothesis that a particular trait evolved by natural selection is indeed falsifiable. In fact, this is one of the foundational principles of the scientific method.
To test whether a particular trait evolved by natural selection, researchers can design experiments or observational studies to investigate the trait's function and potential selective pressures. For example, they could manipulate the trait in question to see how it affects the organism's fitness, or compare the trait's frequency or variation across populations with different environmental conditions.
However, it's important to note that demonstrating that a trait evolved by natural selection does not necessarily mean that it is the only possible explanation for the trait's existence. Other evolutionary mechanisms such as genetic drift, gene flow, or mutation could also play a role in shaping the trait. Therefore, researchers must also consider alternative hypotheses and rule out alternative explanations before concluding that a trait evolved by natural selection.
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Differentiate between tagatose and leloir pathways
Tagatose and Leloir pathways are two different metabolic pathways involved in the breakdown and utilization of dietary sugars, such as galactose.
The Tagatose pathway is a bacterial pathway that allows for the utilization of galactose, a monosaccharide similar to glucose, as an energy source.
In this pathway, galactose is converted into tagatose, another monosaccharide, by the enzyme galactose isomerase.
The tagatose is then broken down into dihydroxyacetone phosphate (DHAP) and glyceraldehyde-3-phosphate (G3P) through a series of reactions, which can enter the glycolysis pathway for further energy production.
The Leloir pathway, on the other hand, is a pathway found in animals and some microorganisms that also converts galactose into glucose-6-phosphate (G6P), a molecule that can enter the glycolysis pathway.
In the Leloir pathway, galactose is converted into galactose-1-phosphate by the enzyme galactokinase, and then into UDP-galactose by the enzyme galactose-1-phosphate uridylyltransferase. UDP-galactose is then converted into UDP-glucose by the enzyme UDP-galactose 4-epimerase.
Finally, UDP-glucose is converted into G6P by the enzyme phosphoglucomutase.
In summary, while both pathways involve the conversion of galactose into glucose derivatives, the Tagatose pathway involves the conversion of galactose into tagatose and then into DHAP and G3P, while the Leloir pathway involves the conversion of galactose into G6P through a series of intermediate steps.
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Three ions that contain the element phosphorus are phosphate (PO43–), hydrogen phosphate (HPO42–), and dihydrogen phosphate (H2PO4–). Compare the formulas of these three ions. Also notice any other instances in which hydrogen is added to a polyatomic ion from the table. Then complete the description of the pattern you see. Select the correct answer from each drop-down menu
The three ions containing phosphorus are phosphate (PO₄³⁻), hydrogen phosphate (HPO₄²⁻), and dihydrogen phosphate (H₂PO₄⁻).
The pattern observed is that adding hydrogen atoms successively reduces the negative charge of the ion by one unit.
1. Observe the formulas of the three ions: PO₄³⁻, HPO₄²⁻, and H₂PO₄⁻.
2. Notice that hydrogen atoms are added successively: 0, 1, and 2.
3. Observe the charges of the ions: -3, -2, and -1.
4. Recognize the pattern: adding hydrogen atoms reduces the negative charge by one unit.
In other instances where hydrogen is added to polyatomic ions, a similar pattern occurs. The negative charge decreases as more hydrogen atoms are added. This pattern is consistent across various polyatomic ions containing hydrogen.
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A 500.0-ml canister holds 0.4650 g of co2 gas at 20.00°c. what is the pressure?
The pressure of [tex]CO_2[/tex] gas in the canister at 20.00°C is 0.611 atm.
To determine the pressure of [tex]CO_2[/tex] gas in the canister, we can use the ideal gas law:
PV = nRT
First, we need to convert the volume of the canister from milliliters (mL) to liters (L):
500.0 mL = 0.5000 L
Next, we need to calculate the number of moles of [tex]CO_2[/tex] gas:
n = m/MW
where m is the mass of [tex]CO_2[/tex] gas and MW is the molar mass of [tex]CO_2[/tex] (44.01 g/mol).
n = 0.4650 g / 44.01 g/mol = 0.01057 mol
Now we can plug in the values and solve for the pressure:
P = nRT/V = (0.01057 mol)(0.0821 L·atm/mol·K)(293.15 K) / 0.5000 L = 0.611 atm
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What does the NaCl + Br₂ represent in the reaction?
NaBr + Cl₂ → NaCl + Br₂
A. Reactants
B. Products
C. Yields Br
D. States of Matter
Determine the amount of heat required to convert 46. 0 g of ethanol at 25°c to the vapor phase at 78°c. Based on the melting and boiling points, ethanol is a liquid at 25°c. Consider the heating curve when organizing your thoughts and answering the question. Use the information about ethanol ch3ch2oh given in the table below.
The amount of heat required to convert 46.0 g of ethanol at 25° C to vapor phase is ≅ 44.2 KJ total heat .
Using the mass , evaluating the moles of ethanol :
46.0 g × [tex]\frac{1 Mol}{46.07 g}[/tex] = 0.998 mol
≅ 1.0 mol
The heat required to convert 46.0 g ethanol from 25° C at 78° C is evaluated :
q₁ = m[tex]C_{liquid }[/tex]ΔT
= 46.0 g × [tex]\frac{2.3 J}{g. K}[/tex] × 78° C - 25°C
= 5607.47J × 1 KJ /1000 J
= 5.607 KJ
So, the heat required in conversion of 1.0 mol of ethanol at 78 ° C to 1.0 mol ethanol vapour is expressed as :
q₂ = moles × Δ[tex]H_{vap}[/tex]
= 1.0 mol × 38.56 KJ /mol
= 38.56 kJ/ mol
The total heat requirement conversion of 46 .0 g of ethanol at 25° C to the vapour state at 78° C :
Total heat = q₁ + q₂
= 5.607 KJ + 38.56 KJ
= 44.167 KJ
≅ 44.2 KJ
Vapour phase :Fume alludes to a gas stage at a temperature where a similar substance can likewise exist in the fluid or strong state, beneath the basic temperature of the substance. As a result of their tendency to be volatile, liquids will enter the vapor phase when the temperature is raised sufficiently. At the specified temperature, a liquid is considered to be volatile if it exhibits a significant vapor pressure.
How does vapour phase transfer work?Transferring a substance from a vapor to a solid by desorbing it using a desorbent or carrier gas and passing the vapor sample through a stationary phase (such as silica particles).
Incomplete question :
Determine the amount of heat required to convert 46. 0 g of ethanol at 25°c to the vapor phase at 78°c. Based on the melting and boiling points, ethanol is a liquid at 25°c. Consider the heating curve when organizing your thoughts and answering the question. Use the information about ethanol CH₃CH₂OH given in the table below.
Use the following information about ethanol CH₃CH₂OH.
Tmelt = –114°C
Tboil = 78°C
∆Hfus = 5.02 kJ/mol
∆Hvap = 38.56 kJ/mol
C solid = 0.97 J/g-K
C liquid = 2.3 J/g-K
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If 3.57 g of barium sulfate is formed, how many grams of sodium sulfate reacted
Answer:2.18 g.
Explanation:To find the mass of sodium sulfate reacted, we use the balanced chemical equation to know that 1 mole of sodium sulfate reacts with 1 mole of barium sulfate. From the given mass of barium sulfate formed, we calculate the number of moles of barium sulfate. Since the stoichiometry of the reaction is 1:1, the number of moles of sodium sulfate reacted is the same as the number of moles of barium sulfate formed. We then use the molar mass of sodium sulfate to calculate the mass of sodium sulfate reacted. The final answer is 2.18 g.
the process in which an atom or ion experiences a decrease in its oxidation state is _____________.
Answer:
Reduction
Explanation:
when an atom or ion decreases in oxidation state
The process in which an atom or ion experiences a decrease in its oxidation state is called reduction.
Reduction is the opposite of oxidation, which is the process in which an atom or ion experiences an increase in its oxidation state. In a redox (reduction-oxidation) reaction, one species undergoes reduction while the other undergoes oxidation.
In the process of reduction, the species gains electrons, resulting in a decrease in its oxidation state. The reducing agent is the species that donates electrons, while the oxidizing agent is the species that accepts electrons.
Reduction reactions are important in many chemical and biological processes, including metabolism, photosynthesis, and corrosion. The study of redox reactions is important in understanding the behavior of chemicals in natural and industrial processes.
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I’m the space provided below, show a correct numerical setup for calculating the total number of moles of ethylene glycol needed to prepare 2.50 liters of a 10.0 M solution?
2.50 litres of a 10.0 M solution require the preparation of 25.0 moles of ethylene glycol.
What is the recommended ratio of ethylene glycol to water?Excellent antifreeze, anti-boil, and anti-corrosive qualities are produced when antifreeze and water are mixed in a 50/50 ratio. The proportion of conventional ethylene glycol to water in severely cold conditions can reach 70% antifreeze, 30% water. The maximum antifreeze to water ratio when using DEX-COOL® is 60/40.
moles = concentration (M) x volume (L)
Given that the desired concentration is 10.0 M and the volume needed is 2.50 L, the setup for calculating the total number of moles of ethylene glycol can be written as:
moles = 10.0 M x 2.50 L
moles = 25.0 mol
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How many ions would form from the dissociation of ammonium dichromate (nh4)2cr2o7?
One formula unit of ammonium dichromate, three ions would form upon dissociation in water.
When ammonium dichromate (NH₄)₂Cr₂O₇ dissociates in water, it breaks down into two ammonium ions (NH₄⁺) and one dichromate ion (Cr₂O₇²⁻). The dissociation is represented by the following chemical equation:
(NH₄)2Cr₂O₇ → 2NH₄⁺ + Cr₂O₇²⁻
Therefore, a total of three ions would be formed from the dissociation of ammonium dichromate in water. The two ammonium ions would have a positive charge, while the dichromate ion would have a negative charge.
These ions can interact with other ions in the solution and participate in various chemical reactions. The dissociation of ammonium dichromate is important in various industrial processes, as well as in chemical education for demonstrating chemical reactions and properties of ions.
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What mass of solid CH2Cl2 can be melted by applying 7. 80 kJ of energy at the melting point?
grams (3 sig figs)
The mass of CH2Cl2 that can be melted by applying 7.80 kJ of energy at the melting point can be calculated using the equation of q = m * c * ΔT, where q is the energy applied, m is the mass, c is the heat capacity, and ΔT is the difference between the final and initial temperatures. In this case, the mass can be calculated as m = q / (c * ΔT). Plugging in the given values yields a mass of 0.126 g, rounded to three significant figures.
Therefore, 7.80 kJ of energy can melt 0.126 g of solid CH2Cl2 at the melting point. The equation used for this calculation assumes that the heat capacity and melting point of CH2Cl2 remain constant throughout the process, and thus the calculated value is only an estimate.
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A solution of lithium carbonate reacts with a solution of potassium iodide to produce solid potassium carbonate and aqueous lithium iodide. You measure 3. 9 moles of potassium carbonate produced by the reaction. How much lithium iodide was produced?
The quantity of lithium iodide produced in the reaction was determined to be 7.8 moles.
The balanced chemical equation for the reaction between lithium carbonate (Li₂CO₃) and potassium iodide (KI) is:
2 Li₂CO₃ + 2 KI → 2 K₂CO₃ + 4 LiI
From the balanced equation, we can see that for every 2 moles of Li₂CO₃ reacted, 4 moles of LiI are produced.
Therefore, if we have 3.9 moles of K₂CO₃, we can calculate the moles of LiI produced as:
3.9 moles K₂CO₃ × (4 moles LiI / 2 moles Li₂CO₃) = 7.8 moles LiI
Therefore, 7.8 moles of lithium iodide were produced in the reaction.
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A cylinder of Krypton has contains 17 L of Ar at 22. 8 atm and 112 degrees celsisus. How many moles are in the
cylinder?
A cylinder of Krypton has contains 17 L of Ar at 22. 8 atm and 112 degrees celsisus. There are 0.824 moles of Ar in the cylinder.
The number of moles of Ar in the cylinder can be calculated using the ideal gas law equation: PV = nRT, where P is the pressure in atm, V is the volume in liters, n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin.
To use this equation, the given temperature of 112 degrees Celsius must be converted to Kelvin by adding 273.15 to get 385.15 K. The pressure of 22.8 atm and volume of 17 L are already in the correct units.
R can be found using the equation R = 0.0821 L atm/(mol K), and plugging in the values for P, V, n, R, and T gives: (22.8 atm)(17 L) = n(0.0821 L atm/(mol K))(385.15 K) n = 0.824 mol
The number of moles of Ar in the cylinder can be found using the ideal gas law equation, which requires the pressure, volume, temperature, and the gas constant. After converting the given temperature to Kelvin, the calculation yields 0.824 moles of Ar.
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What is mean by region of postive slope on the heating curve of water
When we talk about a heating curve of water, we are referring to a graph that shows the temperature of water as it is heated.
The x-axis of the graph represents the amount of heat energy being added to the water, while the y-axis represents the temperature of the water.
The region of positive slope on the heating curve of water refers to the portion of the graph where the temperature of the water is increasing as more heat energy is added. This region starts at the melting point of ice (0°C) and extends all the way to the boiling point of water (100°C) at standard atmospheric pressure.
During this region, the heat energy being added to the water is being used to break the intermolecular bonds between the water molecules and increase their kinetic energy, resulting in an increase in temperature. As the temperature increases, the water transitions from a solid (ice) to a liquid, and finally to a gas (steam).
It is important to note that the slope of the heating curve during the region of positive slope is positive, which means that the temperature is increasing at a steady rate. This region is significant because it represents the phase changes of water, which have important implications for a variety of fields, including chemistry, physics, and engineering.
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Determine the number of moles of c2o4 in a sample with 0.48 moles of mno4 at endpoint
There are 2.4 moles of C2O4^2- in the given sample
To determine the number of moles of C2O4 in the given sample, we need to use the balanced chemical equation of the reaction between MnO4 and C2O4. The equation is:
MnO4- + 5C2O4^2- + 8H+ → Mn2+ + 10CO2 + 4H2O
From the equation, we can see that 1 mole of MnO4- reacts with 5 moles of C2O4^2-. Therefore, if we have 0.48 moles of MnO4- at the endpoint, we can calculate the number of moles of C2O4^2- as follows:
0.48 moles MnO4- x (5 moles C2O4^2-/1 mole MnO4-) = 2.4 moles C2O4^2-
Therefore, there are 2.4 moles of C2O4^2- in the given sample.
It is important to note that moles are a unit of measurement used in chemistry to represent the amount of a substance, and it is equal to the mass of a substance in grams divided by its molar mass. In this case, we were able to determine the number of moles of C2O4^2- in the sample by using the stoichiometry of the balanced chemical equation.
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A 22 -ml sample of 12m h2so4 is diluted to a volume of 1200.0 ml. what is the molarity of the diluted solution?
The molarity of the solution diluted to the 1200.0 ml volume is found to be 0.220M.
The number of moles of H₂SO₄ in the original 22 mL solution can be calculated using the following formula,
moles of H₂SO₄ = Molarity × Volume (in liters)
22 mL = 22/1000 L
= 0.022 L
Substituting the given values, we get,
moles of H₂SO₄ = 12 M × 0.022 L
= 0.264 moles
The number of moles of H₂SO₄ will not change once the solution is diluted to a volume of 1200.0 mL since no H₂SO₄ is added or taken away. Consequently, the following formula can be used to determine the molarity of the diluted solution:
Molarity = moles of H₂SO₄ / Volume (in liters)
Again, we need to convert the volume to liters,
1200.0 mL = 1200.0/1000 L
= 1.200 L
Substituting the values, we get,
Molarity = 0.264 moles / 1.200 L
= 0.220 M
Therefore, the molarity of the diluted solution is 0.220 M.
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if potassium carbonate is used to selectively precipitate one of the cations while leaving the other cation in solution, which cation will precipitate first? what minimum concentration of will trigger the precipitation of the cation that precipitates first?
When potassium carbonate is added to a solution containing two cations, the cation that forms a less soluble compound with carbonate will precipitate first.
This is because the less soluble compound will exceed its solubility product and form a solid precipitate. The solubility product is a constant that indicates the maximum amount of solute that can dissolve in a solution at a given temperature and pressure. In the case of the two cations, calcium ion (Ca2+) forms a more insoluble compound with carbonate ion (CO32-) than strontium ion (Sr2+). Therefore, calcium carbonate (CaCO3) will precipitate first, leaving strontium ion in solution.
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For #12 - #14, write the balanced chemical equation and identify each by type of reaction.
12. copper + chlorine → copper(II) chloride
13. calcium chlorate → calcium chloride + oxygen
14. lithium + water → lithium hydroxide + hydrogen
Answer:
12. Balanced chemical equation: Cu + Cl2 → CuCl2
Type of reaction: Combination or synthesis reaction
13. Balanced chemical equation: 2Ca(ClO3)2 → 2CaCl2 + 3O2
Type of reaction: Decomposition reaction
14. Balanced chemical equation: 2Li + 2H2O → 2LiOH + H2
Type of reaction: Single displacement or substitution reaction
Explanation:
Hope it helps^^
Choosy moms choose JIF! Your mom is making PB & J sandwiches for you and her. When she looks in the cupboard, she realizes she has 3 slices of bread, 1 jar of peanut butter, and 1/2 jar of jelly. What is the limiting reactant?
In this scenario, the limiting reactant is the ingredient that will run out first and limit the number of sandwiches that can be made.
Assuming that each sandwich requires two slices of bread, one serving of peanut butter, and one serving of jelly, we can see that we have enough bread and jelly to make a maximum of 1.5 sandwiches. However, since we only have one serving of peanut butter, we can only make one sandwich.
Therefore, the peanut butter is the limiting reactant. It is important to identify the limiting reactant in chemical reactions to determine the maximum amount of product that can be formed and to avoid wasting resources.
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Pressure is equal to force per unit area. P=F/A therefore F=PA
A brick has the following dimensions, 1. 00 mx 0. 200 m x 0. 500 m. The pressure exerted
by the brick on the floor is different when the brick is placed in different ways. If the
minimum pressure exerted by the brick on the floor is 100. 0 Pa, what is the force
exerted on the floor in newtons (N)?
O 200. N
0 50. 0 N
O 10. 0 N
O 100, N
A brick with dimensions 1.00 m x 0.200 m x 0.500 m exerts different pressures on the floor when placed in different ways. The force exerted on the floor is 20.0 N.
To calculate the force exerted on the floor by the brick, we need to first calculate the area of the face of the brick that is in contact with the floor. The minimum pressure exerted by the brick on the floor is given as 100.0 Pa. Therefore, the force exerted on the floor by the brick can be calculated as:
Force = Pressure x Area
The area of the face of the brick in contact with the floor is given by 1.00 m x 0.200 m = 0.200 m². Therefore, the force exerted on the floor by the brick is:
Force = 100.0 Pa x 0.200 m² = 20.0 N
Since 20.0 N is not listed in the given options, it seems there may be an error or discrepancy in the provided answer choices.
To know more about the force exerted refer here :
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How many atoms are in 8.02 grams of sulfur?
Answer:
1.503 x 10^23
Explanation:
your question was how many atoms, so you have to multiply that number which is how many molecules by 8 atoms per molecule of sulphur. So you get 1.503 x 10^23 atoms in 8 grams of sulfur.
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