(3) Determine If The Statement Below Is True Or False. If It's True, Give A Proof. If It's Not, Give An Example Which Shows It's False. (Such Examples Are Called "Counter-Examples.") "For All X,Y∈R We Have ||X∣−∣Y∣∣≤∣X+Y∣." (4) Find All Subsets Of {{A},{A,B},{Φ}}.

Answers

Answer 1

The statement "||X| - |Y|| ≤ |X + Y|" is false. A counter-example is X = -1 and Y = 2. The subsets of {{A}, {A, B}, Φ} are {}, {A}, {A, B}, {Φ}, {A}, {A, B}, {Φ}, {A}, {A, B}, Φ.



The statement "For all X, Y ∈ R, we have ||X| - |Y|| ≤ |X + Y|" is false. A counter-example can be found by considering X = -1 and Y = 2. Let's evaluate the left-hand side of the inequality first:

||X| - |Y|| = ||-1| - |2|| = |1 - 2| = |-1| = 1.

Now, let's evaluate the right-hand side of the inequality:

|X + Y| = |-1 + 2| = |1| = 1.Therefore, the inequality becomes: 1 ≤ 1, which is true. So the statement holds for this particular example.

In order to find all subsets of {{A}, {A, B}, Φ}, we need to consider all possible combinations of elements. The power set (set of all subsets) can be obtained by including or excluding each element at a time.The given set has three elements: {A}, {A, B}, and Φ (the empty set).The subsets of {{A}, {A, B}, Φ} are as follows:- The empty set: {}

- Sets with one element: {{A}}, {{A, B}}, {Φ}

- Sets with two elements: {{A}, {A, B}}, {{A}, {Φ}}, {{A, B}, {Φ}}

- The original set: {{A}, {A, B}, Φ}

Therefore, the power set of {{A}, {A, B}, Φ} is {{}, {A}, {A, B}, {Φ}, {A}, {A, B}, {Φ}, {A}, {A, B}, Φ}.

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Related Questions

Write the complex number 7−2i in polar form. Give approximate values. Express the angle in degrees. Answer:

Answers

The complex number 7 - 2i can be expressed in polar form as 7.28 ∠ -16.70°. In polar form, a complex number is represented by its magnitude and angle with respect to the positive real axis.

To convert a complex number from rectangular form (a + bi) to polar form (r ∠ θ), we can use the following formulas:

r = √([tex]a^2[/tex] + [tex]b^2[/tex])  (magnitude), θ = atan(b / a)  (angle)

r = √( [tex]7^2[/tex] [tex]+[/tex] [tex](-2)^2[/tex] ) = √(49 + 4) = √53 ≈ 7.28 (rounded to two decimal places)

θ = atan((-2) / 7) ≈ -16.70° (rounded to two decimal places)

Therefore, the polar form of the complex number 7 - 2i is approximately 7.28 ∠ -16.70°. The magnitude 7.28 represents the distance of the number from the origin, and the angle -16.70° indicates its direction with respect to the positive real axis, counterclockwise.

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The following linear programming problem has been solved by The Management Scientist.
Use the output to answer the questions.
LINEAR PROGRAMMING PROBLEM
MAX 25X1+30X2+15X3 S.T.
1) 4X1+5X2+8X3<1200
2) 9X1+15X2+3X3<1500
OPTIMAL SOLUTION
Objective Function Value = 4700.000
Variable Value Reduced Cost
X1 140.000 0.000
X2 0.000 10.000
X3 80.000 0.000
Constraint Slack/Surplus Dual Price
1 0.000 1.000
2 0.000 2.333
OBJECTIVE COEFFICIENT RANGES
Variable Lower Limit Current Value Upper Limit
X1 19.286 25.000 45.000
X2 No Lower Limit 30.000 40.000
X3 8.333 15.000 50.000
RIGHT HAND SIDE RANGES
Constraint Lower Limit Current Value Upper Limit \
1 666.667 1200.000 4000.000
2 450.000 1500.000 2700.000
a. Give the complete optimal solution.
b. Which constraints are binding?
c. What is the dual price for the second constraint? What interpretation does this have?
d. Over what range can the objective function coefficient of x2 vary before a new solution point becomes optimal?

Answers

a. Optimal solution: X1 = 140, X2 = 0, X3 = 80, Objective Function Value = 4700.000.

b. The first constraint (4X1 + 5X2 + 8X3 < 1200) is binding.

c. The dual price for the second constraint is 2.333, indicating that for each unit increase in its right-hand side value, the objective function value increases by 2.333.

d. The objective function coefficient of X2 can vary between 30 and 40 without changing the optimal solution

a. The complete optimal solution is:

X1 = 140

X2 = 0

X3 = 80

Objective Function Value = 4700.000

b. The first constraint (4X1 + 5X2 + 8X3 < 1200) is binding because it has a slack/surplus value of 0.

c. The dual price for the second constraint (9X1 + 15X2 + 3X3 < 1500) is 2.333. This means that for each unit increase in the right-hand side value of the second constraint, the objective function value will increase by 2.333 units, assuming all other variables and constraints remain constant.

d. The objective function coefficient of X2 can vary between 30 and 40 before a new solution point becomes optimal. This means that as long as the coefficient remains within this range, the current solution will still be optimal. However, if the coefficient of X2 goes below 30 or above 40, a new optimal solution may be obtained.

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Determine the range of the function f(x)=∣1+∣x 2 −4∣∣ where x∈[0,6]. Answer: The range of the function f is [a,b], where

Answers

To determine the range of the function f(x) = |1 + |x^2 - 4||, where x ∈ [0,6], we need to find the maximum and minimum values of the function within the given interval.

The function f(x) = |1 + |x^2 - 4|| has two absolute value expressions. To determine the range of this function within the interval x ∈ [0,6], we consider two cases: when x^2 - 4 ≥ 0 and when x^2 - 4 < 0.

When x^2 - 4 ≥ 0, the inner absolute value expression evaluates to x^2 - 4. In this case, the function simplifies to f(x) = |1 + (x^2 - 4)| = |x^2 - 3|.

When x^2 - 4 < 0, the inner absolute value expression evaluates to -(x^2 - 4) = 4 - x^2. In this case, the function simplifies to f(x) = |1 + (4 - x^2)| = |5 - x^2|.

For the interval x ∈ [0,6], we consider the maximum and minimum values of the function within this range. By evaluating the function at the endpoints and critical points, we can determine the maximum and minimum values and hence the range.

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Peyton Manning completes 67% of his passes. What is the probability that it takes more than four throws to complete his pass in a game?

Answers

On the assumption that each throw has a 33% risk of failing to complete, the likelihood that Peyton Manning needs more than four attempts to complete a pass in a game is 0.008192.

The probability that Peyton Manning completes his first pass on any given throw is 0.67. This means that there is a 67% chance that he will complete his pass on the first try, and a 33% chance that he will not complete his pass on the first try.

If he does not complete his first pass, then there is a 33% chance that he will also not complete his second pass. And if he does not complete his second pass, then there is a 33% chance that he will also not complete his third pass. And so on.

So, the probability that it takes more than four throws to complete his pass is the same as the probability that he does not complete his first four throws.

The probability that he does not complete his first four throws is calculated by multiplying the probability that he does not complete each individual throw. The probability that he does not complete any given throw is 0.33, so the probability that he does not complete his first four throws is (0.33)⁴ = 0.008192.

Therefore, the probability that it takes more than four throws to complete his pass in a game is 0.008192.

Here is an explanation of the steps involved in calculating the probability:

1. The probability that Peyton Manning completes his first pass on any given throw is 0.67.

2. The probability that he does not complete his first pass is 1 - 0.67 = 0.33.

3. The probability that he does not complete his first four throws is (0.33)⁴ = 0.008192.

4. Therefore, the probability that it takes more than four throws to complete his pass in a game is 0.008192.

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When I stand 30 feet away from a tree at home, the angle of elevation to the top of the tree is 52∘ and the angle of depression to the base of the tree is 8∘. What is the height of the tree? Round your answer to the nearest foot.

Answers

The height of the tree is approximately 26 feet.

To find the height of the tree, we can use trigonometric relationships involving angles of elevation and depression. Let's denote the height of the tree as h.

From the given information, we have the following information:

Angle of elevation: The angle of elevation from your position to the top of the tree is 52 degrees.

Angle of depression: The angle of depression from your position to the base of the tree is 8 degrees.

Distance: You stand 30 feet away from the tree.

We can use the tangent function to establish a relationship between the height of the tree and the distances involved. The tangent of the angle of elevation is equal to the height of the tree divided by the distance from your position to the tree:

tan(52°) = h / 30

Solving for h, we have:

h = 30 * tan(52°)

Using a calculator, we find:

h ≈ 26 feet

Therefore, the height of the tree is approximately 26 feet

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Let a, b, c, ri, r2 be five positive constants with r+r₂> V(a² + b² + c²), |r₁ - r₂| V(< a²+b²+c²). Let S1 and S2 be the spheres with center (0, 0, 0), (a, b, c) and radius r1,r2 respectively.
(a) Find the equation of the plane containing the intersection of S1 and S2.
(b) Determine the line joining the points (0,0,0) and (a, b, c). Determine its point of intersection with the plane.

Answers

The point where this line intersects the plane is obtained by substituting the values of x, y, and z into the equation of the plane.

The required question mentions that a, b, c, r1, and r2 are five positive constants.

It also mentions that r1 + r2 > √(a² + b² + c²) and |r1 - r2| < √(a² + b² + c²).

S1 and S2 are two spheres with center (0, 0, 0), (a, b, c), and radius r1, r2 respectively. Let's solve both parts of the question below:

(a) Find the equation of the plane containing the intersection of S1 and S2:

The equation of the sphere S1 is given by the following:S1 : x² + y² + z² = r1²

The equation of the sphere S2 is given by the following:S2 : (x - a)² + (y - b)² + (z - c)² = r2²

Now we'll solve for their intersection points by substituting one equation into another:x² + y² + z² = r1²(x - a)² + (y - b)² + (z - c)² = r2²

Expanding the second equation yields:x² - 2ax + a² + y² - 2by + b² + z² - 2cz + c² = r2²

Rearranging the terms gives us:x² + y² + z² - r1² = 2ax - a² + 2by - b² + 2cz - c² + r2²

If we add the two above equations, we get:2ax + 2by + 2cz = r1² + a² + b² + c² - r2²

If we divide both sides by 2, we get the equation of the plane containing the intersection of S1 and S2:x/a + y/b + z/c = (r1² + a² + b² + c² - r2²)/2

The equation of the plane containing the intersection of S1 and S2 is x/a + y/b + z/c = (r1² + a² + b² + c² - r2²)/2.(b)

Determine the line joining the points (0, 0, 0) and (a, b, c). Determine its point of intersection with the plane:

The coordinates of the two points are:(0, 0, 0) and (a, b, c).

The vector joining these two points is given by (a, b, c) - (0, 0, 0) = (a, b, c).

Thus the parametric equation of the line joining the two points is given by the following:x = at, y = bt, z = ct, where t is a real number.

The point where this line intersects the plane is obtained by substituting the values of x, y, and z into the equation of the plane.

We get the following:a²t/a + b²t/b + c²t/c = (r1² + a² + b² + c² - r2²)/2t = (r1² + a² + b² + c² - r2²)/(2(a² + b² + c²))

Substituting the value of t in the parametric equation of the line gives us the point of intersection with the plane:

(a(r1² + a² + b² + c² - r2²)/(2(a² + b² + c²)), b(r1² + a² + b² + c² - r2²)/(2(a² + b² + c²)), c(r1² + a² + b² + c² - r2²)/(2(a² + b² + c²)))

Therefore, the point of intersection of the line joining the two points with the plane is ((ar1² + a³ + ab² + ac² - ar2²)/(2(a² + b² + c²)), (br1² + a²b + b³ + bc² - br2²)/(2(a² + b² + c²)), (cr1² + a²c + b²c + c³ - cr2²)/(2(a² + b² + c²))).

The point of intersection of the line joining the two points with the plane is ((ar1² + a³ + ab² + ac² - ar2²)/(2(a² + b² + c²)), (br1² + a²b + b³ + bc² - br2²)/(2(a² + b² + c²)), (cr1² + a²c + b²c + c³ - cr2²)/(2(a² + b² + c²))).

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A survey of residential college students at a large university revealed the following breakdown of whether their major is in STEM or not and whether the students were living in a single room or not. Find the probability that a randomly selected student from the survey: (a) Has a major in STEM. (b) Has a major in STEM and a single room. (c) Has a major in STEM given that they have a single room. (d) Does not have a single room given they have a major not in STEM. A total of 108 students filled out a survey for a psychology class project. A total of 36 students indicated they were athletes. Of those students, 21 said they preferred to work out in the morning as opposed to the afternoon. For the nonathletes, 25 said they preferred to work out in the morning. Find the following probabilities for a randomly selected student who took the survey: (a) P (Athlete given prefer morning workout). (b) P (Prefer morning workout given nonathlete). (c) P (Nonathlete given prefer nonmorning workout).

Answers

The probability that a randomly selected student from the survey has a major in STEM is 0.59.

The probability that a randomly selected student from the survey has a major in STEM is given by the following formula:

P(major in STEM) = 46/82 = 0.59

This is because there are 46 students in the survey with a major in STEM, and there are a total of 82 students in the survey.

The probability that a randomly selected student from the survey has a major in STEM and a single room is given by the following formula:

P(major in STEM and single room) = 23/82 = 0.28

This is because there are 23 students in the survey with a major in STEM and a single room, and there are a total of 82 students in the survey.

The probability that a randomly selected student from the survey has a major in STEM given that they have a single room is given by the following formula:

P(major in STEM | single room) = 23/46 = 0.5

This is because the probability of having a major in STEM is 0.5 for students with a single room, since there are 23 students with a major in STEM and a single room, and there are a total of 46 students with a single room.

The probability that a randomly selected student from the survey does not have a single room given they have a major not in STEM is given by the following formula:

P(not single room | major not in STEM) = 57/62 = 0.92

This is because the probability of not having a single room is 0.92 for students with a major not in STEM, since there are 57 students without a single room and a major not in STEM, and there are a total of 62 students with a major not in STEM.

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Find the derivative of the following function by first expanding the expression. f(x)=(4x+5)(5x^2+4) f'(x)=3

Answers

The derivative of the function f(x) = (4x + 5)(5x^2 + 4) is 3.

To find the derivative of the given function, we need to expand the expression first using the distributive property.

[tex]f(x)= 4x + 5)(5x^2 + 4)\\\\= 4x(5x^2 + 4) + 5(5x^2 + 4)\\\\= 20x^3 + 16x + 25x^2 + 20[/tex]

Next, we differentiate the expanded expression with respect to x. The derivative of a constant term (20) is zero, and the derivative of each term involving x can be found using the power rule of differentiation.

[tex]f'(x) = d/dx (20x^3 + 16x + 25x^2 + 20)\\= 60x^2 + 16 + 50x\\= 60x^2 + 50x + 16[/tex]

Now, since we were given that f'(x) = 3, we set the derivative equal to 3 and solve for x:

[tex]3 = 60x^2 + 50x + 16[/tex]

Simplifying the equation and solving for x may require using techniques such as factoring, the formula, or approximating the solution using numerical methods. The solution will provide the specific values of x that satisfy the given derivative equation.

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Emily practices the piano 826 minutes in 2 weeks. Assuming she practices the same amount every week, how many minutes would she practice in 3 weeks?

Answers

The number of minutes Emily would practice the piano in three weeks will be 1,239 minutes, if she practices 826 minutes in 2 weeks assuming she practices the same amount every week by solving the function f(x)=2x=826

To determine the total number of minutes Emily would practice in three weeks, you can use the principle of ratio and proportions since Emily practices the same amount every week.

Here's how:

Let x be the number of minutes Emily practices per week.

Then, the number of minutes she practices in 2 weeks will be equal to 2x

Therefore, using the information given in the problem,

2x = 826

We can then solve for x: (solving function f(x))

2x = 826

Divide both sides by 2:

2x/2 = 826/2

x = 413

Now that we know Emily practices for 413 minutes every week, we can find the total number of minutes she would practice in three weeks by multiplying 413 by 3:

413 × 3 = 1239

Therefore, Emily would practice for 1,239 minutes in three weeks.

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The following functions give the populations of four towns with time t in years. (i) P=400(0.10)^{t} (ii) P=900(1.10)^{t} (iii) P=500(1.02)^{t} (iv) P=1000(1.07)^{t} (a)

Answers

Town (ii) has the largest percent growth rate of 110%, and town (iv) has the largest initial population of 1000. No town is decreasing in size.

To determine which town has the largest percent growth rate, we need to compare the growth rates of the given functions.

(a) Percent growth rate can be found by calculating the coefficient of exponential growth in each function. Let's calculate the growth rates for each town:

(i) P = 400(0.10)^t

The growth rate for town (i) is 0.10, or 10%.

(ii) P = 900(1.10)^t

The growth rate for town (ii) is 1.10, or 110%.

(iii) P = 500(1.02)^t

The growth rate for town (iii) is 1.02, or 102%.

(iv) P = 1000(1.07)^t

The growth rate for town (iv) is 1.07, or 107%.

Comparing the growth rates, we can see that town (ii) has the largest percent growth rate of 110%.

To determine which town has the largest initial population, we need to compare the coefficients of the exponential functions.

(b) Let's examine the initial populations for each town:

(i) P = 400(0.10)^t

The initial population for town (i) is 400.

(ii) P = 900(1.10)^t

The initial population for town (ii) is 900.

(iii) P = 500(1.02)^t

The initial population for town (iii) is 500.

(iv) P = 1000(1.07)^t

The initial population for town (iv) is 1000.

Comparing the initial populations, we can see that town (iv) has the largest initial population of 1000.

(c) To determine if any of the towns are decreasing in size, we need to examine the growth rates. If the growth rate is less than 1, it indicates a decrease in size.

From the growth rates calculated earlier, we can see that none of the towns have a growth rate less than 1. Therefore, no town is decreasing in size.

In summary, town (ii) has the largest percent growth rate of 110%, and town (iv) has the largest initial population of 1000. None of the towns are decreasing in size.

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The following functions give the populations of four towns with time t in years. (i) P=400(0.10)^t (ii) P=900(1.10)^t (iii) P=500(1.02)^t (iv) P=1000(1.07)^t

 (a) Which town has the largest percent growth rate? What is the percent growth rate? Town has the largest percent growth rate, at eTextbook and Media (b) Which town has the largest initial population? What is that initial population? Town has the largest initial population, at eTextbook and Media (c) Are any of the towns decreasing in size? If so, which one(s)? Town (i) is decreasing in size. Town (ii) is decreasing in size. Town (iii) is decreasing in size. Town (iv) is decreasing in size. No town is decreasing in size.

A force of 40 Newtons applied horizontally is required to push a 20 kg box at a constant velocity across the floor. Find the acceleration of the box.

Answers

The acceleration of the box is 2 m/s², which is calculated by using Newton's second law of motion, which states that the force applied to an object is equal to the mass of the object multiplied by its acceleration.

To find the acceleration of the box, we can use Newton's second law of motion, which states that the force applied to an object is equal to the mass of the object multiplied by its acceleration. Mathematically, it can be written as F = ma, where F is the force, m is the mass, and a is the acceleration.

In this scenario, a force of 40 Newtons is applied horizontally to a 20 kg box. Since the box is moving at a constant velocity, we know that the net force acting on the box is zero (according to the first law of motion). Therefore, we have: 40 N = 20 kg × a

Dividing both sides by 20 kg, we get: a = 40 N / 20 kg

Simplifying, we find: a = 2 m/s²

Therefore, the acceleration of the box is 2 m/s². This means that for every second the box moves, its velocity will increase by 2 meters per second.

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A survey of students at a film school revealed the following information. 51 like arimated films 49 like comedy films 60 like dramatic films 34 like animated and comedy 32 ike comedy and dramatic 36 like animated and dramatic 24 ike all three types 1 does not like any of the three types (a) Based on the survey above, answer the following questions: i. Draw a Venn diagram to represent the survey. ii. How many like only one of the three types of film? DISCRETE MATHEMATICS 3/7 CONFIDENTIAL iii. How many like animated and comedy but not dramatic? iv. How many like animated and dramatic but not comedy? v. How many like either animated, dramatic or comedy? vi. How many like either dramatic or comedy? vii. How many like dramatic and comedy? viii. How many students were surveyed? ix. How many do not like animated?

Answers

Let's analyze the given information and answer the questions:

a) Venn diagram representation:

        +-------------------+

        |                   |

        |       Drama       |

        |                   |

+--------+---------+---------+---------+

|        |         |         |         |

|        |         |         |         |

|        | Animated | Comedy  | Drama   |

|        |         |         |         |

|        |         |         |         |

|        |         |         |         |

+--------+---------+---------+---------+

        |         |         |

        |         |         |

        |         |         |

        |         |         |

        +-------------------+

b) Number of people who like only one type of film:

To find the number of people who like only one type of film, we can sum the individual regions outside the intersections.

Number of people who like only animated = 51 - 24 - 36 + 1 = 8

Number of people who like only comedy = 49 - 24 - 32 + 1 = 6

Number of people who like only drama = 60 - 32 - 36 + 1 = 25

ii) The total number of people who like only one type of film is 8 + 6 + 25 = 39.

iii) Number of people who like animated and comedy but not drama:

This corresponds to the region only within the intersection of animated and comedy (excluding the drama section).

Number of people = 24 - 1 = 23.

iv) Number of people who like animated and dramatic but not comedy:

This corresponds to the region only within the intersection of animated and drama (excluding the comedy section).

Number of people = 36 - 1 = 35.

v) Number of people who like either animated, dramatic, or comedy:

To find this, we sum the individual regions outside the intersections and include the region where all three types intersect.

Number of people = 8 + 6 + 25 + 24 + 32 + 36 - 24 = 107.

vi) Number of people who like either dramatic or comedy:

This corresponds to the regions within the drama and comedy sections, including the intersection.

Number of people = 60 + 49 - 32 = 77.

vii) Number of people who like both dramatic and comedy:

This corresponds to the intersection region of drama and comedy.

Number of people = 32.

viii) Total number of students surveyed:

To find the total number of students surveyed, we sum all the individual regions and the region where all three types intersect.

Total number of students = 8 + 6 + 25 + 24 + 32 + 36 + 1 = 132.

ix) Number of people who do not like animated:

To find this, we subtract the number of people who like animated from the total number of students surveyed.

Number of people = 132 - 51 = 81.

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Suppose that f is differentiable. If f′(x∗)=0 and f′′(x∗)=2 then f has a local maximum at x∗. true false b) If x∗ is a local minimum then f′′(x∗)≥0. true false c) If x∗ maximizes the function f on the interval [0,2] then f′(x∗)=0. true false d) Suppose that f′(x)=sin(x)+1 for all x. Then f is an increasing function. true false

Answers

a) True. If f′(x∗) = 0 and f′′(x∗) = 2, it indicates that the derivative of f is zero at x∗ and the second derivative is positive at x∗. These conditions suggest that f has a local maximum at x∗.

b) False. The statement is incorrect. If x∗ is a local minimum, it means that the derivative f′(x∗) is zero, but it doesn't provide any information about the second derivative f′′(x∗). The second derivative can be positive, negative, or zero at x∗.

c) False. If x∗ maximizes the function f on the interval [0,2], it implies that f is at its maximum value at x∗. However, this doesn't necessarily mean that the derivative f′(x∗) is zero. The derivative being zero represents a critical point, but not all critical points correspond to maximum values.

d) False. If f′(x) = sin(x) + 1 for all x, the derivative is positive for some values of x and negative for others. This means that f is not strictly increasing but rather fluctuates between increasing and decreasing intervals depending on the value of x. Therefore, f is not an increasing function.

a) If f′(x∗) = 0 and f′′(x∗) = 2, it means that the slope of the function f is zero at x∗, indicating a possible extremum. Additionally, the positive value of f′′(x∗) suggests that the graph of f is concave up at x∗, reinforcing the idea of a local maximum.

b) The statement is false because the second derivative f′′(x∗) can be positive, negative, or zero at a local minimum. The second derivative test can determine the concavity of the function and provide information about whether it is a maximum or minimum, but it does not establish a direct relationship between the sign of f′′(x∗) and the nature of the extremum.

c) The statement is false. If x∗ maximizes the function f on the interval [0,2], it only implies that f achieves its maximum value at x∗. However, the derivative f′(x∗) may or may not be zero. The derivative being zero represents a critical point, but it doesn't guarantee that it corresponds to a maximum.

d) The statement is false. The derivative f′(x) = sin(x) + 1 includes the sine function, which oscillates between positive and negative values. Consequently, f′(x) is not always positive, indicating that f does not strictly increase for all x. The function f exhibits variations in its slope and does not exhibit a consistent increasing trend.

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If 3 people are randomly selected from a population of 3 males and 5 females:
a. What is the probability that all will be males?
b. What is the probability that there will be at least one of each sex?
Hint: Consider all possible scenarios that could result in at least one male and one female.
c. Show that the probability over all k possibilities of males and females sums to 1, i.e. that ∑P(=)=1.

Answers

a. The probability that all will be males is:P(3 males) = (3 choose 3)/(8 choose 3) = 1/56b. The probability that there will be at least one of each sex is:P(at least one male and one female) = 1 - P(3 females) - P(3 males) = 1 - (5 choose 3)/(8 choose 3) - (3 choose 3)/(8 choose 3) = 19/28.

We used the fact that P(at least one male and one female) = 1 - P(no males or all males) and that P(no males or all males) = P(3 females) + P(3 males)c. We know that all the possibilities add up to 1. That is, the sum of the probability of selecting k males and 3 - k females is 1, as k ranges from 0 to 3. Therefore, we can calculate the probability of selecting k males and 3 - k females for each value of k and sum up the results. Since there are 4 values of k to consider, we can write:∑P(=) = P(0 males and 3 females) + P(1 male and 2 females) + P(2 males and 1 female) + P(3 males and 0 females) = [(5 choose 3)/(8 choose 3)] + [(3 choose 1)(5 choose 2)/(8 choose 3)] + [(3 choose 2)(5 choose 1)/(8 choose 3)] + [(3 choose 3)/(8 choose 3)] = 1

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New employees at a company are given a proficiency test. The test scores are approximately normally distributed with a mean of 350 and a standard deviation of 30. A new employee scores 386 on the exam.
What is the employee's z-score?

Answers

It is calculated using the formula: z = (x - μ) / σ

The employee's z-score is approximately 1.2.

The z-score measures how many standard deviations an individual observation is from the mean of a normally distributed population. It is calculated using the formula:

z = (x - μ) / σ

where x is the individual observation, μ is the population mean, and σ is the population standard deviation.

In this case, the employee's score is 386, the population mean is 350, and the population standard deviation is 30. Let's calculate the z-score step by step.

Substituting the given values into the formula:

z = (386 - 350) / 30

Simplifying the expression:

z = 36 / 30

z = 1.2

Therefore, the employee's z-score is approximately 1.2. This indicates that the employee's score is 1.2 standard deviations above the mean of the population.


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Translate to a system of equations but do not solve. One evening 1600 concert tickets were sold for the Fairmont Summer Jazz Festival. Tickets cost $30 for covered pavilion seats and $10 for lawn seats. Total receipts were $36,000. How many of ear type of tickets were sold?

Answers

These equations represent the number of each type of ticket sold and the total revenue generated from ticket sales, respectively.

Let's assume the number of covered pavilion seats sold is represented by the variable 'x' and the number of lawn seats sold is represented by the variable 'y'.

We can set up a system of equations based on the given information:

Equation 1: x + y = 1600 (The total number of tickets sold is 1600)

Equation 2: 30x + 10y = 36000 (The total revenue from ticket sales is $36,000)

In Equation 1, we express the total number of tickets sold by adding the number of covered pavilion seats (x) and the number of lawn seats (y), which must equal 1600.

In Equation 2, we express the total revenue from ticket sales by multiplying the cost of covered pavilion seats ($30) by the number of covered pavilion seats (x) and adding it to the product of the cost of lawn seats ($10) and the number of lawn seats (y), which must equal $36,000.

By solving this system of equations, we can determine the values of x and y, representing the number of each type of ticket sold.

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) Suppose we do 100 tests at the 0.05 significance level. Can we expect 5 of these to be statistically significant, even though there is actually no effect in any of the tests?
b) Can we predict a child's cognitive ability based on the age at which the child begins to speak? Suppose the variable include for the age (months) at which children begin to talk along with results from a later cognitive test during growing up.
Suppose the child who took 42 months to start talking was excluded from the analysis. How would that affect the correlation coefficient? Would we get a value closest to -1, 0 or +1?
Where Y = COGNITIVE ABILITY and X = AGE AT FIRST SPEAK
Note: No explanation needed its general question

Answers

a. It is possible to have a certain number of statistically significant results even when there is no true effect present.

b. The specific impact on the correlation coefficient would depend on the data and the relationship between cognitive ability and age at first speak.

a) In hypothesis testing, the significance level of 0.05 means that we expect, on average, 5 out of 100 tests to result in a statistically significant finding purely by chance, even when there is no actual effect. This is because the significance level represents the probability of obtaining a statistically significant result when the null hypothesis is true. Therefore, it is possible to have a certain number of statistically significant results even when there is no true effect present.

b) Excluding a child who took 42 months to start talking from the analysis would affect the correlation coefficient between cognitive ability (Y) and age at first speak (X). The correlation coefficient measures the strength and direction of the linear relationship between two variables. By excluding the child with a longer delay in starting to talk, the correlation coefficient may shift towards a value closer to zero or become weaker. This is because the excluded child's data point, which might have contributed to a stronger negative or positive correlation, is no longer considered in the analysis. The specific impact on the correlation coefficient would depend on the data and the relationship between cognitive ability and age at first speak.

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The length of human pregnancies from conception to birth approximates a normal distribution with a mean of 266 days and a standard deviation of 16 days. What is the probability of observing a pregnancy that lasts longer than 282 days? Answer: a. 0.1587 b. 0.8413 c. 0.5000 d. 0.6826 e. 0.9500

Answers

The probability of observing a pregnancy that lasts longer than 282 days is 0.8413, which corresponds to option b.

The probability of observing a pregnancy that lasts longer than 282 days can be calculated using the normal distribution. Given a mean of 266 days and a standard deviation of 16 days, we need to find the probability of the observation falling above 282 days.

To calculate this probability, we can standardize the observation using the z-score formula: z = (x - μ) / σ, where x is the value we want to find the probability for, μ is the mean, and σ is the standard deviation.

In this case, we want to find the probability of x being greater than 282 days. So we calculate the z-score as follows: z = (282 - 266) / 16 = 1.

Using a standard normal distribution table or a calculator, we can find the probability corresponding to a z-score of 1, which is 0.8413.

Therefore, the probability of observing a pregnancy that lasts longer than 282 days is 0.8413, which corresponds to option b.

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Let x4= the number of 4 -cylinder connecting rods produced next week x6= the number of 6 -cylinder connecting rods produced next week s4=1 if the production line is set up to produce the 4-cylinder connecting rods; 0 if otherwise s6=1 if the production line is set up to produce the 6 -cylinder connecting rods; 0 if otherwise (a) Using the decision variables x4 and s4, write a constraint that limits next week's production of the 4-cylinder connecting rods to either 0 or 9,000 units. (b) Using the decision variables x6 and s6′, write a constraint that limits next week's production of the 6 -cylinder connecting rods to either 0 or 7,000 units. (c) Write a third constraint that, taken with the constraints from parts (a) and (b), limits the production of connecting rods for next week. (d) Write an objective function for minimizing the cost of production for next week. Min

Answers

The constraints and objective function can be formulated as follows for next week's production of connecting rods:

(a) x4 must be either 0 or 9,000 units when s4 is set to 1,

(b) x6 must be either 0 or 7,000 units when s6 is set to 1, (c) the third constraint is not specified, and (d) the objective function aims to minimize the cost of production.

(a) To limit the production of 4-cylinder connecting rods, we can write the following constraint:

x4 <= 9,000 * s4

This constraint ensures that if s4 is set to 1, x4 can take a value up to 9,000. Otherwise, if s4 is set to 0, x4 must be 0.

(b) Similarly, to limit the production of 6-cylinder connecting rods, we can write the constraint:

x6 <= 7,000 * s6

When s6 is set to 1, x6 can take a value up to 7,000. If s6 is 0, x6 must be 0.

(c) The third constraint is not explicitly mentioned and needs to be defined based on the problem requirements. It could involve a limit on the total production quantity or any other relevant condition that needs to be considered.

(d) The objective function for minimizing the cost of production can be written as:

Minimize Cost = c4 * x4 + c6 * x6

where c4 is the cost per unit of 4-cylinder connecting rods and c6 is the cost per unit of 6-cylinder connecting rods. The objective is to find the values of x4 and x6 that minimize the total cost of production for next week

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Estimate the value as a whole number or as a mixed numeral where the fractional part is (1)/(2). 16(15)/(31)*23(17)/(19)

Answers

The estimated value of the expression 16(15)/(31)*23(17)/(19) is approximately 368 and 249/589 when expressed as a mixed numeral with a fractional part of (1)/(2).



To calculate the value of the expression, we can multiply the whole numbers and the fractions separately, and then add the results together.

Let's start by multiplying the whole numbers:16 * 23 = 368

Now let's multiply the fractions:(15/31) * (17/19) = (255/589)

Next, we add the whole number and fraction results:368 + (255/589).

To add these, we need to find a common denominator:Since 589 is a prime number, the common denominator is 589 itself.Now we can add the fractions:(368 * 589 + 255) / 589 = (216352 + 255) / 589 = 216607 / 589

Therefore, the value of the expression, as a mixed numeral where the fractional part is (1)/(2), is approximately:216607/589 ≈ 368 + (249/589). Hence, the estimated value is 368 (249/589) as a mixed numeral.

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Give the angle(s) α in degrees, α∈[0∘,360∘] whose trigonometric function have the indicated value. Omit the degree symbol. sinα=1 secα=−1 cscα=1

Answers

The angles α that satisfy the given trigonometric function values are α = 90°, 180°, and 270°.

The trigonometric functions with the indicated values are:

sinα = 1: This occurs when α = 90° or α = 270°. In the unit circle, these angles correspond to the points (0, 1) and (0, -1) respectively, where the y-coordinate represents the sine function.

secα = -1: This occurs when α = 180°. In the unit circle, this angle corresponds to the point (-1, 0), where the x-coordinate represents the secant function.

cscα = 1: This occurs when α = 90° or α = 270°. In the unit circle, these angles correspond to the points (0, 1) and (0, -1) respectively, where the y-coordinate represents the cosecant function.

Therefore, the angles α that satisfy the given trigonometric function values are α = 90°, 180°, and 270°.

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Determine if 0.898998999899998999998dots is rational or irrational and give a reason for your answer. The number 0.898998999899998999998dots is because

Answers

The number 0.898998999899998999998... is rational. It can be expressed as the fraction 8099/9000, which means it is a ratio of two integers. The repeating pattern in the decimal representation of the number allows us to express it as a fraction, indicating its rationality.

To determine if the number 0.898998999899998999998... is rational or irrational, we need to examine its decimal representation. The repeating pattern in the decimal representation is "8989". This pattern repeats indefinitely.

To express the number as a fraction, we can assign a variable, say x, to the repeating part "8989". By multiplying x by 10000, we can shift the decimal point and obtain 10000x = 8989.8989...

Next, we subtract x from 10000x to eliminate the repeating part:

10000x - x = 8989.8989... - 0.8989...

9999x = 8989

x = 8989/9999

Simplifying the fraction, we get:

x = 8099/9000

Since the number can be expressed as the ratio of two integers, it is rational. Therefore, 0.898998999899998999998... is a rational number.

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3) (3pts) Give a precise (in words) geometric description of the set of points whose coordinates satisfy the given conditions: y^{2}+z^{2}=2 and x=1

Answers

The set of points whose coordinates satisfy the given conditions, y^{2}+z^{2}=2 and x, can be described as a cylinder with radius square root of 2, centered at the x-axis.

The cylinder extends indefinitely in the positive and negative x directions, and every cross-section of the cylinder perpendicular to the x-axis is a circle with radius square root of 2.

Geometrically, the equation y^{2}+z^{2}=2 represents a circle with radius square root of 2 centered at the origin of the yz-plane. The condition x means that this circle is projected onto the x-axis, resulting in a cylinder with the circle as its base. Since the circle extends indefinitely in the y and z directions, so does the cylinder.

Thus, the set of points whose coordinates satisfy the given conditions is a cylinder with radius square root of 2 centered at the x-axis, extending infinitely in the positive and negative x directions.

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Suppose that the probability of event A is a(i.e.,P(A)=a) and the probability of event B is b( i. e.,P(B)=b). Also, it is given that the two events are independent. Then P(B∣A)
P(A∣B)
​ is: Answer: a. 0 b. (a×b)
a+b
​ C. b
a
​ d. a
b
​ e. (a×b)
1

Answers

The correct answer is c. P(B∣A) = b/a.

When two events A and B are independent, it means that the occurrence of one event does not affect the probability of the other event. In this case, P(B∣A), the probability of event B given event A, is equal to the probability of event B, which is b.

P(A∣B), the probability of event A given event B, would be calculated using Bayes' theorem:

P(A∣B) = P(A) * P(B∣A) / P(B)

Since P(B∣A) = b/a and P(B) = b, substituting these values into Bayes' theorem, we get:

P(A∣B) = a * (b/a) / b = 1

Therefore, P(A∣B) is equal to 1.

The options provided in the question do not include the correct answer for P(A∣B).

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Correlation among the explanatory variables in a multiple regression that makes the estimates uninterpretable is called…
multilinearity.
collinearity.
linearity.
nonlinearity.

Answers

The correlation among the explanatory variables in a multiple regression that makes the estimates uninterpretable is called "collinearity." Collinearity refers to a high degree of correlation or linear relationship among the independent variables in a regression model. When collinearity is present, it becomes difficult to distinguish the individual effects of each independent variable on the dependent variable.

High collinearity can lead to unstable parameter estimates, high standard errors, and unreliable inference. It can also make it challenging to interpret the coefficients of the independent variables accurately. In extreme cases, collinearity can even result in contradictory or counterintuitive coefficient signs.

Therefore, to ensure the interpretability of estimates in a multiple regression, it is essential to address and mitigate the issue of collinearity by taking appropriate measures such as removing highly correlated variables, transforming variables, or using regularization techniques.

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Find all values of θ, if θ is in the interval [0, 360°) and has the given function value..
tan θ = 1
45° and 315°
45° and 225°
225° and 315°
135° and 225°

Answers

The values of θ in the interval [0, 360°) that satisfy tan θ = 1 are:

θ = 45° and θ = 225°

To find all values of θ in the interval [0, 360°) that satisfy the equation tan θ = 1, we need to determine the angles at which the tangent function is equal to 1.

The tangent function is defined as the ratio of the sine function to the cosine function: tan θ = sin θ / cos θ. To solve the equation tan θ = 1, we need to find the angles where the sine and cosine functions have a specific relationship.

First, let's consider the unit circle. The unit circle is a circle with a radius of 1 centered at the origin of a coordinate system. The x-axis and y-axis intersect the unit circle at the points (1, 0) and (0, 1), respectively.

In the unit circle, the sine of an angle θ is the y-coordinate of the point on the unit circle corresponding to that angle, and the cosine of θ is the x-coordinate of the point.

To find the angles where tan θ = 1, we need to look for points on the unit circle where the y-coordinate (sine) is equal to the x-coordinate (cosine). These points are (1/√2, 1/√2) and (-1/√2, -1/√2).

In the first quadrant, the angle that corresponds to the point (1/√2, 1/√2) is 45°. This means that tan 45° = 1.

In the third quadrant, the angle that corresponds to the point (-1/√2, -1/√2) is 45° + 180° = 225°. This means that tan 225° = 1.

Therefore, the values of θ in the interval [0, 360°) that satisfy tan θ = 1 are 45° and 225°.

To summarize:

- θ = 45° satisfies tan θ = 1.

- θ = 225° satisfies tan θ = 1.

The other options you provided, 45° and 315°, 45° and 225°, and 135° and 225°, do not satisfy the equation tan θ = 1.

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1. Manny has a box of marbles. (1)/(4)of the marbles are yellow, are (5)/(12)are green, and the remaining marbles are white. How many marbles are there in the box altogether?

Answers

Manny has 12 marbles in the box altogether.

Manny has a box of marbles, with (1/4) of them being yellow and (5/12) being green. The remaining marbles are white. To find the total number of marbles, we need to determine the common denominator and calculate the number of marbles for each color.

Let's start by finding the common denominator for 4 and 12, which is 12. This means we can express (1/4) as (3/12) and (5/12) as (5/12). So, we know that out of 12 parts, 3 parts are yellow and 5 parts are green. The remaining parts, which are white, can be calculated by subtracting the sum of yellow and green parts from the total of 12 parts.

To find the total number of marbles, we calculate (3/12) + (5/12) = (8/12) parts for yellow and green marbles combined. Subtracting this from the total of 12 parts gives us (12/12) - (8/12) = (4/12), which represents the white marbles.

Since each part represents one marble, we can find the total number of marbles by dividing 4 (the number of parts for white marbles) by (4/12) (the fractional value of one part) to get 12 marbles. Therefore, Manny has 12 marbles in the box altogether.

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Write a slope -intercept equation for a line passing through the point (6,-6) that is parallel to the line x=-4. Then write a second equation for a line passing through the point (6,-6) that is perpendicular to the line x=-4

Answers

The slope-intercept equation of the line passing through the point (6,-6) and parallel to the line x=-4 is y = -6. The slope-intercept equation of the line passing through the point (6,-6) and perpendicular to the line x=-4 is x = 6.



Parallel lines have the same slope, so we first need to find the slope of the line x = -4. Since it is a vertical line, its slope is undefined. So we can't directly apply slope-intercept equation y = mx + b. However, we can still determine the equation of the parallel line passing through (6,-6) since the y-coordinate of the given point is -6. Therefore, the equation of the parallel line is y = -6 (the y-intercept is -6).

Now, to find the equation of the perpendicular line passing through (6,-6), we first need to find the slope of the line x = -4. Since the slope is undefined, the slope of the perpendicular line will be zero. Thus, the equation of the perpendicular line passing through (6,-6) will be x = 6 (the x-intercept is 6).

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Find the values of the six trigonometric functions of θ for the right triangle with the given sides. sinθ= cosθ= tanθ= cscθ= secθ= cotθ=

Answers

The values of the six trigonometric functions are:

sinθ = √2/2

cosθ = √2/2

tanθ = 1

cscθ = 2

secθ = 2

cotθ = 1

Are all six trigonometric functions equal in the given right triangle?

If both sine (sinθ) and cosine (cosθ) of an angle are equal, then the angle must be 45 degrees or π/4 radians in a right triangle. In this case, the opposite side and adjacent side of the angle will be equal in length.

Let's assume the length of both sides is "x". Then, the hypotenuse (the side opposite the right angle) can be found using the Pythagorean theorem:

[tex]hypotenuse^2 = x^2 + x^2\\hypotenuse^2 = 2x^2\\hypotenuse = \sqrt(2x^2) = x\sqrt2\\[/tex]

Now, we can calculate the values of the trigonometric functions:

sine (sinθ) = opposite/hypotenuse = x/x√2 = 1/√2 = √2/2

cosine (cosθ) = adjacent/hypotenuse = x/x√2 = 1/√2 = √2/2

tangent (tanθ) = opposite/adjacent = x/x = 1

cosecant (cscθ) = 1/sinθ = √2/(√2/2) = 2

secant (secθ) = 1/cosθ = √2/(√2/2) = 2

cotangent (cotθ) = 1/tanθ = 1/1 = 1

Therefore, the values of the six trigonometric functions for θ in this right triangle are:

sinθ = √2/2

cosθ = √2/2

tanθ = 1

cscθ = 2

secθ = 2

cotθ = 1

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At Supergrocery, The Price Of A Loaf Of Bread Increased From $1.28 To $1.64. Find The Percent Increase. Using This Information, Match With The Correct Response.

Answers

The percent increase in the price of the loaf of bread is approximately 28.13%.

The percent increase is a measure of the change in a quantity relative to its original value. It is commonly used to compare changes in prices, quantities, or other numerical values. In this case, the percent increase represents how much the price of a loaf of bread has increased from $1.28 to $1.64. By calculating the difference between the new price ($1.64) and the original price ($1.28), we find that the increase is $0.36. Dividing this increase by the original price ($1.28) and multiplying by 100 gives us the percent increase of approximately 28.13%. This means that the price of the loaf of bread has increased by about 28.13% from its original value.

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You require them a minimum down payment of 5%, which they should pay in cash, and for the rest of the loan you offer them a financing plan at the nominal rate of 6% capitalized quarterly, over a period of 20Years.According to your estimates:1. How much will this couple have to pay each month to repay the mortgage?2. What is the amount of interest paid for the duration of the mortgage?3. What is the balance of the mortgage at the end of the 5th year?4. If at the beginning of the 6th year the nominal rate increases to 8% capitalized quarterly, what is the new amount of the monthly payment? Let X be a discrete random variable which can take 3 distinctvalues in [0,1]. Suppose X can take each of those 3 values withnonzero probability. Prove that E[X] > E[X^2]. Fateve Consulting is deciding which of two computer systems to purchase. It can purchase state-of-the-art equipment (System A) for an after-tax cost of $22,000, which weil generate atter-tax cash fows of $9,000 at the end of each of the next 6 years. Alsematively, the company can purchase equipment with an after-tax cost of $14,000 that can be used for 3 years and wili generate after-tax cash fows of 39,000 at the end of each year (System B). If the company's wacC is 5% and both "projects" can be repeated indefinitely, which system should be chosen, and what is its EAA? Do not round intermedate cakulations. Aound your answer to the nearest cent. choose froject , Whose EAA =5 Continue without saving A construction firm purchased 3 tractors from a certain company. At the end of 5th year, let El, E2, and E3 denote, respectively, the vents that tractors no. 1,2 , and 3 are still in good operational condition. Past experience indicates that the chance of a given tractor manufactured by this company having a useful life longer than 5 years is 60% (meaning each tractor has 60% chance to be in good condition after 5 years). If one tractor needs to be replaced (meaning it is not in good condition) at the end of 5th year, the probability of replacement for one of the other 2 tractors is 60%. If 2 tractors need to replaced, the probability of replacement of the remaining one is 80%. Calculate the probabilities of Events A,B, and C. This week you will develop a model to assess the profitability of a strategy.Lets start with1 acquire the daily data on Excel (from Yahoo Finance) for the past year on UVXY2 arrange the data so it runs from oldest to newest (dates).3 create a formula to determine a buy at the close (today) and sell at the open (tomorrow) strategy. (this will be a difference from one time to the next)4 generate a separate row with the information from #35 next, sum the data from your calculation to determine if this strategy is profitable .6 How can this strategy be improved or "optimized An advantage of publicity is its low cost, since the company is not paying for time or space in a mass medium such as TV, radio, or newspapers. True or False Mobile marketing is an online means of communication and interactions among people that are used to create, share, and exchange content such as information, insights, experiences/perspectives, and even media themselves. True or False The clothes washer in your house consumes 351kWh of energy per year. Price of the washer is $397 and the lifetime of the washer is 10yrs. Energy price in your city is 11 cents per kWh. What is the lifecycle cost of the clothes washer? (assumes a maintenance cost of $10 per year) Exam 2 Conversions and Formulae 883.10$ 390.17$ 793.10$ 426.80$ 391.07$ Shares in Growth Corporation are selling for $65 per share. There are 2 million shares outstanding. The company repurchases 300,000 shares. After the repurchase: How many shares will be outstanding? What will be the price per share? Outstanding shares = Price per share = Calculate the target gap using the following date: Product 1 target selling price is $30, target profit is 25% margin and the estimated cost is $25.20. a. $1.80 b. $4.80 c. $2.70 d. $1.20 Dixon \& Company manufactures Part A and uses standard costs to prepare its flexible budget. For the first quarter of the year, direct materials and direct labor standards for Part A were as follows: Direct materials: 3 pounds per unit; $7 per pound Direct labor: 2 hours per unit; $20 per hour During the first quarter, Dixon produced 4,900 units of this product. Actual direct materials and direct labor costs were $68,000 and $270,000, respectively. For the purpose of preparing the flexible budget, calculate the total standard direct labor cost at a production volume of 4,900 units. A. $98,000 B. $9,800 C. $196,000 D. $686,000 On January 1, 2020, Corgan Company acquired 80 percent of the outstanding voting stock of Smashing, Inc., for a total of $1,600,000 in cash and other consideration. At the acquisition date, Smashing had common stock of $910,000, retained earnings of $460,000, and a noncontrolling interest fair value of $400,000. Corgan attributed the excess of fair value over Smashing's book value to various covenants with a 20-year remaining life. Corgan uses the equity method to account for its investment in Smashing.During the next two years, Smashing reported the following:Net Income Dividends Declared Inventory Purchases from Corgan2020 $ 360,000 $ 56,000 $ 310,000 2021 340,000 66,000 330,00Corgan sells inventory to Smashing using a 60 percent markup on cost. At the end of 2020 and 2021, 50 percent of the current year purchases remain in Smashing's inventory. Compute the equity method balance in Corgan's Investment in Smashing, Inc., account as of December 31, 2021. Prepare the worksheet adjustments for the December 31, 2021, consolidation of Corgan and Smashing. Compute the equity method balance in Corgan's Investment in Smashing, Inc., account as of December 31, 2021. Investment balance 12/31/21Prepare the worksheet adjustments for the December 31, 2021, consolidation of Corgan and Smashing. (If no entry is required for a transaction/event, select "No journal entry required" in the first account field.)No Transaction Accounts Debit Credit1 1 Investment in Smashing Cost of goods sold 2 2 Common stock - Smashing Retained earnings - Smashing Investment in Smashing Noncontrolling interest 3 3 Covenants Investment in Smashing Noncontrolling interest 4 4 Equity in earnings of Smashing Investment in Smashing 5 5 Investment in Smashing Dividends declared 6 6 Amortization expense Covenants 7 7 Sales Cost of goods sold 8 8 Cost of goods sold Inventory Wilson Properties just closed a new mortgage loan of $18,000,000 with interest at 5%, 20-year amortization and due in seven years. What it the principal balance of the loan at the end of year seven?(A) $18,000,000 (B) $13,606,404 (C) $12,094,581 (D) $7,470,892All of the following are acquisition period costs of investing in distressed properties except?(A) Renovation, repair, and maintenance costs (B) Market research costs (C) Legal and title costs (D) Property inspection costs