30 points if someone gets it right

You roll a cube what is the probability of rolling a number greater than 2? write you answer as a fractiom

The counterexample is 2/3 x 9 if two positive numbers are multiplied together and the result is bigger than either of the two positive numbers. d is the right answer, thus.

It is defined as the method through which we multiply, divide, add, and subtract numerical quantities. It contains the basic operators +, -,, and.

Multiplication is a useful tool for carrying out many common tasks, such as computing area, sales tax, and other geometric measurements.

The result will be greater than each of the two positive numbers if a two positive numbers when multiplied together.

If a two positive numbers in the stated condition are x and y,

xy > x

xy> y

The two figures are found to be 2/3 and 9.

=2/3 x 9 =6

Therefore, 2/3 x 9 will serve as the example that refutes the assertion "If two positive numbers when multiplied together, then perhaps the product would be greater than either of the two positive numbers

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The complete question is

The correct question is-

Which is a counterexample for the conditional statement?If two positive numbers are multiplied together, then the product will be greater than both of the two positive numbers.

a. 2 x 4

b. 5x(-3)

c. x

d. 2/3x9

Answer: a

Step-by-step explanation:

West Virginia is needed to estimate the true proportion of children living in poverty within 3% with 95% confidence

To estimate the required sample size, we can use the formula:

n = (Z^2 * p * (1-p)) / E^2

where:

Z = the Z-score associated with the desired level of confidence (95% confidence corresponds to a Z-score of 1.96)

p = the estimated proportion of the population with the characteristic of interest (in this case, the estimated proportion of children under age 6 living in poverty in West Virginia, which is 0.3)

E = the desired margin of error (in this case, 0.03)

Substituting the given values, we get:

n = (1.96^2 * 0.3 * (1-0.3)) / 0.03^2

Simplifying:

n = 601.78

Rounding up to the nearest whole number, we get:

n = 602

Therefore, a sample of at least 602 children under age 6 from West Virginia is needed to estimate the true proportion of children living in poverty within 3% with 95% confidence.

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Two angles are co-terminal, meaning they differ by a multiple of 360°.

a) We know that sin A = opposite/hypotenuse = 5/12. Therefore, the adjacent side of angle A must be negative, since it is located in the second quadrant. We can use the Pythagorean theorem to find the hypotenuse:

(5/12)^2 + (adjacent)^2 = hypotenuse^2

25/144 + (adjacent)^2 = hypotenuse^2

(adjacent)^2 = hypotenuse^2 - 25/144

(adjacent)^2 = (hypotenuse^2 * 144 - 25)/144

We also know that cosine is adjacent/hypotenuse and tangent is opposite/adjacent, so:

cos A = adjacent/hypotenuse = sqrt(hypotenuse^2 - 25/144)/hypotenuse

tan A = opposite/adjacent = 5/sqrt(hypotenuse^2 - 25/144)

b) To find angle A, we can use the inverse sine function:

A = sin^-1(5/12)

A ≈ 24.02°

We know that cosecant is the reciprocal of sine, so:

csc A = 1/sin A

We want to find angles that have a cosecant of V3, so:

1/sin A = V3

sin A = 1/V3

We can use the unit circle to find angles whose sine is 1/V3. One such angle is 60°, since sin 60° = V3/2. Another angle is 300°, since sin 300° = -V3/2. These two angles are co-terminal, meaning they differ by a multiple of 360°.

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Solving an exponential equation we can see that it will take 23.86 years.

We know that the population is modeled by the exponential equation:

P= 100,000•10^(0.02t)

The initial population is 100,000, so it will triple when P = 300,000

Then the equation we need to solve is:

300,000 = 100,000•10^(0.02t)

Now we can solve this for t.

300,000/100,000 = 10^(0.02t)

3 = 10^(0.02t)

Apply the natural logarithm in both sides:

ln(3) = 0.02*t*ln(10)

t = ln(3)/(0.02*ln(10)) = 23.86

It will take 23.86 years.

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Complete question.

"The population of a town can be modeled using the formula P=20,000e^0.02t , where t is the number of years after 2012 and P is the town's population. Which of the following equations can be used to find the number of years after 2012 that the population will triple to  300,000?"

The polynomial long division of 6x³+x²+7x+9 by 2x+1 gives a quotient of 3x² - x + 4

From the question, we have the following parameters that can be used in our computation:

6x³+x²+7x+9 by 2x+1

Using the polynomial long division setup, we have

2x + 1   |  6x³ + x² + 7x + 9

Evaluating the division, we have

              3x² - x + 4

2x + 1   |  6x³ + x² + 7x + 9

              6x³ + 3x²

             ---------------------------------------

                     -2x² + 7x + 9

                     -2x² - x

             ---------------------------------------

                           8x + 9

                           8x + 4

                        ---------------------------------------

                                  5

Hence, the quotient is 3x² - x + 4

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The sum of 8 of the interior angles of a regular nonagon is 1120 degrees.

A nonagon is a polygon with 9 sides and 9 interior angles. The sum of the interior angles of any polygon is given by using the method (n-2) × 180 degrees, wherein n is the number of sides.

Therefore, the sum of the interior angles of a nonagon is (9-2) × 180 = 1260 levels.

Because the nonagon is a regular polygon, every of its interior angles has the equal degree. To discover the measure of every attitude, we will divide the sum of the interior angles through the wide variety of angles.

Therefore, the degree of every interior perspective of a ordinary nonagon is 1260/9 = 140 ranges.

To discover the sum of 8 of the interior angles, we are able to simply multiply the measure of each attitude through eight, which gives:

8 × 140 = 1120 degrees

Thus, the sum of 8 of the interior angles of a regular nonagon is 1120 degrees.

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The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is:

0.817 to 0.849.

Statistics is a branch of mathematics that deals with the collection, analysis, interpretation, presentation, and organization of numerical data.

a. To find the number of subjects who used at least one prescription medication, we can simply multiply the total number of subjects by the percentage who used at least one prescription medication:

3234 x 0.833 = 2690.22

Rounding this to the nearest whole number, we get:

b. To construct a 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication, we can use the following formula:

CI = p ± z*√(p(1-p)/n)

where:

p = proportion of adults who use at least one prescription medication = 0.833

n = sample size = 3234

z* = z-score corresponding to the desired level of confidence, which for a 90% confidence interval is 1.645

Substituting these values, we get:

CI = 0.833 ± 1.645√(0.833(1-0.833)/3234)

= 0.833 ± 0.016

Therefore, the 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is:

0.817 to 0.849

This means that we can be 90% confident that the true percentage of adults in this age group who use at least one prescription medication falls between 81.7% and 84.9%.

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The probability of exactly one successes in five trials  is 0.20

From the question, we have the following parameters that can be used in our computation:

The probability is calculated as

P(x) = nCx * p^x * (1 - p)^(n -x)

Where

n = 5

p = 5%

x = 1

Substitute the known values in the above equation, so, we have the following representation

P(1) = 5C1 * (5%)^1 * (1 - 5%)^(5 -1)

Evaluate

P(1) = 0.20

HEnce, the probability value is 0.20

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The parameters of the sinusoidal function, y = -3·cos(π·(π - 2)) - 4, obtained from the equation of the function are;

(a) a) 2

b) 4 units down

c) 2 units left

(b) d) Please find attached the graph of the function showing the period created with MS Excel.

A sinusoidal function is a periodic sine or cosine based function.

The specified sinusoidal function can be presented as follows;

y = -3·cos(π·(x - 2)) - 4

The general form of a sinusoidal function is; y = A·cos(B·(x + C)) + D

(a) a) The period of a sinusoidal function is T = 2·π/|B|

A comparison with the general form of a sinusoidal function indicates;

A = 3, B = π, C = -2, D = -4

B = π

Therefore; T = 2·π/π = 2

The period, T = 2

b) The vertical shift of the function, D = -4

c) The horizontal shift of the function, C = -2

(b) d) Please find attached the graph of the function created with MS Excel

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To plot points along the portion of the firm's short-run supply curve that corresponds to prices where there is positive output, we need to identify the portion of the graph where the firm is producing output.

We can observe from the graph that the firm's short-run supply curve is the component of the marginal cost curve that is higher than the average variable cost curve. The company will shut down and create no production if prices fall below the minimum point of the average variable cost curve. However, as long as the price is above the marginal cost of production, the company will create output at prices above the minimum point of the average variable cost curve.

We may use the orange square symbols to represent the price and matching amount provided at each point where the company is generating output to plot points along this segment of the short-run supply curve. We may advance up the marginal cost curve from the last point of the average variable cost curve until we reach the maximum price at which the company is generating output. The firm's short-run supply curve may then be created by marking each price and quantity combination along this segment of the curve.

It is important to note that the firm's short-run supply curve is a reflection of its marginal cost curve above the average variable cost curve, and will shift as the firm's costs of production change or its technology improve.

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Answer:

We can use the Pythagorean theorem to solve for the width of Dominic's living room. The Pythagorean theorem states that for a right triangle with legs of length a and b and hypotenuse of length c, a² + b² = c².

In this case, we can treat the length of the living room (9 meters) as one leg of the right triangle, and the distance between opposite corners (10 meters) as the hypotenuse. Let w be the width of the living room. Then the other leg of the right triangle has length w.

Applying the Pythagorean theorem, we get:

9² + w² = 10²

81 + w² = 100

w² = 19

w ≈ 4.4

Therefore, the width of Dominic's living room is approximately 4.4 meters.

Step-by-step explanation:

To predict the number of situps a person who watches 13.5 hours of TV can do, we can use the given regression equation y = ax + b, where 'a' and 'b' are the coefficients and 'x' is the hours of TV watched.

Given:
a = -1.077
b = 30.98
x = 13.5

Step 1: Substitute the given values into the regression equation:
y = (-1.077)(13.5) + 30.98

Step 2: Perform the calculations:
y = (-14.5395) + 30.98

Step 3: Add the values:
y = 16.4405

Since we need the result to one decimal place, we can round it off to:
y ≈ 16.4

So, a person who watches 13.5 hours of TV per day can do approximately 16.4 situps.

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a) The light flashes as the circuit leaves the field at a speed of 16 ms.

b) The current flow as the loop exits the field in the clockwise direction.

c) The power dissipated in the bulb during the flash is 0.04 W. 

To reply to these questions, we will utilize Faraday's Law, which states that a changing attractive field actuates an electromotive drive (EMF) in a circuit, and the initiated EMF is rise to the rate of alter of attractive flux through the circuit.

a) The attractive flux through the circle is given by the item of the attractive field, region of the circle, and cosine of the point between the attractive field and the ordinary to the plane of the circle.

As the circle is pulled out of the attractive field, the magnetic flux through the circle diminishes, and thus, an EMF is actuated within the circle. This initiated EMF drives a current through the light bulb, causing it to light up.

The time term of the streak of light can be decided from the time taken by the circle to move out of the attractive field.

The removal voyage by the circle is 40 cm, and the speed is 25 m/s, so the time taken is:

t = d/v = 0.4 m / 25 m/s = 0.016 s = 16 ms

Subsequently, the streak of light endures for 16 ms.

b) Concurring to Lenz's Law, the course of the initiated current is such that it contradicts the alter within the attractive flux that produces it. As the circle is pulled out of the attractive field, the attractive flux through the circle diminishes.

Hence, the actuated current flows in a course that makes a magnetic field that restricts the initial attractive field. This could be accomplished by the induced current streaming clockwise as seen from above. Hence, the reply is clockwise.

c) The control scattered within the light bulb can be calculated utilizing the equation P = V²/R, where V is the voltage over the bulb and R is its resistance.

The voltage over the bulb is break even with to the initiated EMF, which can be calculated from Faraday's Law. The attractive flux through the circle changes at a rate of (40 cm) x (25 m/s) = 1 T.m²/s.

The region of the circle is (40 cm) x (10 cm) = 0.04 m². The cosine of the point between the attractive field and the ordinary plane of the circle is 1 (since the circle is opposite to the field). Subsequently, the induced EMF is:

EMF = -d(phi)/dt = -NA(dB/dt)

= -(1)(0.04 m²)(1 T.m²/s)/0.016 s

= -1 V

The negative sign indicates that the actuated EMF is within the inverse course of the current stream. Subsequently, the voltage over the light bulb is:

V = -EMF = 1 V

The power dissipated within the bulb is:

P = V²/R = (1 V)²/25 ohm = 0.04 W

Subsequently, the control scattered within the bulb during the streak is 0.04 W. 

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The surface area of the pyramid is 179 sq. m.

The surface area of a given shape is the summation of all the area of each figure that forms its sides called surfaces.

The given pyramid has triangular shaped surfaces, so that;

area of a triangle = 1/2 *base*height

To determine the area of one of the surfaces, we have;

area of the triangular surface = 1/2x base x height

base = 8 m, and slant height of the surface = 11.2 m

So that;

the area of one triangular surface = 1/2*8*11.2

                                                    = 44.8 sq. m.

Thus since the pyramid has 4 equal triangular surfaces, then;

the surface area of the pyramid = 4 x 44.8

                                            = 179.2

The surface area of the pyramid is 179 sq. m.

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Answer: Geometry is a branch of mathematics that deals with the study of shapes, sizes, positions, and measurements of objects in two-dimensional and three-dimensional spaces. It involves analyzing and calculating angles, lengths, areas, volumes, and other properties of various figures such as triangles, circles, squares, cubes, and spheres. Geometry is used in many fields including architecture, engineering, physics, and computer graphics.

The coordinates of S' is (-10, 6).

We have,

Dilation is a transformation in which the size of a figure is changed without altering its shape.

In the coordinate plane, a dilation changes the size of a figure by multiplying the distance between each point and the center of dilation by a scale factor.

The center of dilation is a fixed point in the plane about which the figure is dilated. If the scale factor is greater than 1, the figure is enlarged, and if it is less than 1, the figure is reduced. If the scale factor is negative, the figure is also reflected across the center of dilation.

From the figure,

S = (-5, 3)

Now,

Dilated with a scale factor of 2.

This means,

S' = (-5 x 2, 3 x 2) = (-10, 6)

Thus,

The coordinates of S' is (-10, 6).

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The steady-state solutions of y'(t) =

[tex] y^2 - 15y + 56[/tex]

are y = 7 and y = 8, with y = 7 being a stable equilibrium point and y = 8 being an unstable equilibrium point.

The steady-state solutions of a differential equation are the values of the function that remain constant over time. To find the steady-state solutions of the given differential equation, we need to set y'(t) = 0 and solve for y.

[tex]y^2 - 15y + 56 = 0[/tex]

We can factor this quadratic equation as (y-7)(y-8) = 0, so the steady-state solutions are y = 7 and y = 8. These values are called equilibrium points or fixed points because if y(t) starts at one of these values, it will remain there as time goes on.

To understand the behavior of the system around these steady-state solutions, we can use the first derivative test. If y'(t) > 0 for y < 7 or y > 8, then y(t) is increasing and moving away from the steady-state solution. If y'(t) < 0 for 7 < y < 8, then y(t) is decreasing and moving towards the steady-state solution. Hence, y = 7 is a stable equilibrium point, and y = 8 is an unstable equilibrium point.

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We have reduced the given word to the normal form word [tex]$a^2$[/tex], with [tex]$m=1$[/tex].

(a) We can use the following circulation rules to simplify the given word:

Rule 1: [tex]$aa^{-1}$[/tex] and [tex]$a^{-1}a$[/tex] can be replaced with the empty word.

Rule 2: [tex]$aa$[/tex] and [tex]$bb$[/tex] can be replaced with [tex]$a^2$[/tex] and [tex]$b^2$[/tex], respectively.

Rule 3: If a subword [tex]$aba^{-1}$[/tex] or [tex]$bab^{-1}$[/tex] appears, it can be replaced with [tex]$a^{-1}b^{-1}ab$[/tex] or [tex]$b^{-1}a^{-1}ba$[/tex], respectively.

Using these rules, we can simplify the given word as follows:

[tex]$a b c b^{-1} d c^{-1} d^{-1} a^{-1} & =a \cdot b \cdot c \cdot b^{-1} \cdot d \cdot c^{-1} \cdot d^{-1} \cdot a^{-1} \\$ =a \cdot b \cdot b^{-1} \cdot d \cdot c^{-1} \cdot c \cdot d^{-1} \cdot a^{-1} \\$ =a \cdot d \cdot d^{-1} \cdot a^{-1} \\$ =a^2$[/tex]

So we have reduced the given word to the normal form word [tex]$a^2$[/tex], with [tex]$m=1$[/tex].

(b) Using the same circulation rules, we can simplify the given word as follows:

[tex]$a b a^{-1}-c d b^{-1}-c^{-1} d^{-1} & =a \cdot b \cdot a^{-1}-c \cdot d \cdot b^{-1}-c^{-1} \cdot d^{-1} \\$ =a^2-c \cdot d \cdot b^{-1}-c^{-1} \cdot d^{-1} \\$ =a^2-c \cdot d \cdot b^{-1}-c \cdot d^{-1} \cdot c^{-1} \\$ =a^2-\left(c d^{-1}\right) \cdot\left(c^{-1} b\right) \\$ =a^2-\left(c d b^{-1}\right)^{-1} \\$ =a^2-\left(b d c^{-1}\right)^{-1} \\$ =a^2$[/tex]

So we have reduced the given word to the normal form word [tex]$a^2$[/tex], with [tex]$m=1$[/tex].

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The area of rectangle DEFG is 16 square units and its perimeter is 12 units.

To find the area, we can use the formula: Area = length x width We can find the length and width by calculating the distance between the coordinates of opposite sides of the rectangle.

Length = EF =

[tex] \sqrt{} ((2-1)^2 + (1-3)^2)[/tex]

=

[tex] \sqrt{} (2 + 4) = \sqrt{} (6)[/tex]

Width = DG =

[tex] \sqrt{} ((-3+2)^2 + (1+1)^2) = \sqrt{} (2 + 4) = \sqrt{} (6)[/tex]

The area of rectangle DEFG = length x width =

[tex] \sqrt{} (6) x \sqrt{} (6)[/tex]

= 6 x 2 = 16 square units.

To find the perimeter, we can add up the lengths of all four sides: Perimeter = DE + EF + FG + GD

DE =

[tex] \sqrt{} ((1+3)^2 + (-3+(-1))^2) = \sqrt{} (16 + 4) = \sqrt{} (20)[/tex]

EF =

[tex] \sqrt{} ((2-1)^2 + (1-3)^2) = \sqrt{} (2 + 4) = \sqrt{} (6)[/tex]

FG =

[tex] \sqrt{} ((2+2)^2 + (1+1)^2) = \sqrt{} (16 + 4) = \sqrt{} (20)[/tex]

GD =

[tex] \sqrt{} ((-2+3)^2 + (-1-1)^2) = \sqrt{} (1 + 4) = \sqrt{} (5)[/tex]

The perimeter of rectangle DEFG =

[tex] \sqrt{} (20) + \sqrt{} (6) + \sqrt{} (20) + \sqrt{} (5) [/tex]= 12 units.

Hence, The area of the rectangle is 16 square units and the perimeter is 12 units.

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The solution of the system of equations  -10x - 9y = 10 and 8x + 9y = 10 is x = 10 and y = -3.33

From the question, we have the following parameters that can be used in our computation:

-10x9y = 10

8x +9y = 10

Express properly

So, we have

-10x - 9y = 10

8x + 9y = 10

When the above equations are added to one another, we have

2x  = 20

This means that

x = 10

Nexy, we have

-10(2) - 9y = 10

This means that

-9y = 30

S,o we have

y = -3.33

Hence, the soltuion is x = 10 and y = -3.33

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Yes, that is correct. The Gaussian elimination rules are essentially the same as the three basic row operations, which allow you to algebraically manipulate a matrix's rows.

You can interchange two rows, multiply a row by a constant, or add a row to another row. These rules are essential in solving systems of linear equations and finding the reduced row echelon form of a matrix. By applying these rules, you can transform a matrix into an equivalent matrix that is easier to work with and reveals important information about the system of equations or the matrix itself. The Gaussian elimination rules, also known as the three basic row operations, allow you to algebraically manipulate a matrix in order to solve systems of linear equations. These operations include:
1. Interchanging two rows (R2 ↔ R3)
2. Multiplying a row by a nonzero number (R1 → kR1, where k is a constant)
3. Adding a row to another row (R2 → R2 + 3R1)
These rules help simplify the matrix and ultimately obtain the unique solution for the system of equations.

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The derivative of f(x) = log(1 - x) by expanding it into a power series is f'(x) = -(1 + x + x^2 + x^3 + ...).

To find the derivative of f(x) = log(1 - x) by expanding it into a power series, we first need to expand log(1 - x) using a power series and then differentiate term by term.

Here's how to do it:

1. Recall the power series expansion for the natural logarithm of (1 - x):
  ln(1 - x) = -(x + x^2/2 + x^3/3 + x^4/4 + ...)

2. Now we have the power series representation of f(x):
  f(x) = -(x + x^2/2 + x^3/3 + x^4/4 + ...)

3. Differentiate term-by-term with respect to x:
  f'(x) = -[1 + (2x)/2 + (3x^2)/3 + (4x^3)/4 + ...]

4. Simplify the expression:
  f'(x) = -[1 + x + x^2 + x^3 + ...]

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The value of x in the triangle is 21, option B is correct.

The given triangle is right triangle

We know that the sine function is the ratio of opposite side and hypotenuse

Opposite side =19

Hypotenuse =x

We have to find the value of x

Sin 65 = 19/x

0.91 =19/x

x=19/0.91

x=20.8

x=21

Hence, the value of x in the triangle is 21, option B is correct.

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Michael should expect that the quantity of visitors that will buy more than one costume is  23.

In order to calculate the quantity of expected visitors who will buy more than one costume amongst a projected 1800 attendees next week, we can utilize the proportion between the individuals who purchased multiple costumes and the overall number of people who bought at least a single costume.

3 / 230 = 0.013

We can determine the potential number of multiple costume buyers among the anticipated 1800 visitors by utilizing a straightforward calculation: multiplying the quantity of one-costume purchasers by the ratio of those who obtained more than one costume.

0.013 x 1800 = 23.4

= 23 visitors

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The  area of the lateral face of cylinder = 150.79 ft²

The  area of the two bases of the cylinder = 56.55 ft²

The total surface area of the cylinder =  207.34  ft²

We know that the formula for the surface area of cylinder is:

A = 2πrh + 2πr²

where r is the radius of the cylinder

and h is the height of the cylinder

Here, r = 3 ft and h = 8 ft

The area of the lateral face of cylinder would be,

A₁ = 2 × π × r × h

A₁ = 2 × π × 3 × 8

A₁ = 48 × π

A₁ = 150.79 sq. ft.

And the area of two bases is,

A₂ = 2πr²

A₂ = 2 × π × 3²

A₂ = 18 × π

A₂ = 56.55 sq. ft.

The total surface area of cylinder would be,

A = A₁ + A₂

A = 150.79 + 56.55

A = 207.34 sq. ft.

Therefore, the required surface area of cylinder = 207.34 ft²

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A one-tailed t-test is used when the researcher has a specific directional hypothesis.

If you are comparing the difference between two separate populations, such as children who attend two different Elementary schools, you should use an independent-measures design. In an independent-measures design, two separate groups of participants are sampled, and each participant is only tested once. The purpose of this design is to compare the means of two independent populations to determine if there is a statistically significant difference between them. In contrast, a within-groups design would involve testing the same group of participants twice under different conditions, while a repeated-measures design would involve testing the same group of participants under all conditions. A one-tailed t-test is a specific type of statistical test that can be used in either an independent-measures or within-groups design to test a directional hypothesis.

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The ratio of the trigonometric function of the right triangle, cos A is 3/5.

Given that,

In △ABC , ∠C is a right angle.

Then the opposite side to the right angle will be the hypotenuse.

So AB is the hypotenuse.

Sin A = BC / AB [ Since sine of an angle is opposite side / hypotenuse]

BC / AB = 4/5

BC = 4 and AB = 5

Using the Pythagoras theorem,

Third side, AC = √(5² - 4²) = 3

Cos of an angle is the ratio of adjacent side to the hypotenuse.

Cos A = 3/5

Alternatively, we can use the identity,

sin²A + cos²A = 1

to find the value of cos A.

Hence the value of cos A is 3/5.

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The general solution of the y" + 2y + y= 7 +75sin2x is given as:

y =  (c₁+c₂x)[tex]e^{-x}[/tex] + 7 - 12cos2x - 9sin2x

The Greek terms trigonon (triangle) and metron (measure) are the origin of the word trigonometry. The connections between the lengths and angles of triangles' sides are the subject of this area of mathematics. An equation with one or more trigonometric ratios of unknown angles is said to as trigonometric. The ratios of sine, cosine, tangent, cotangent, secant, and cosecant angles are used to express it.

y" + 2y' + y = 7 + 75sin2x

Auxlliary equation are (m²+2m+1) = 0

CF = (c₁+c₂x)[tex]e^{-x}[/tex]

PI = [tex]\frac{1}{D^2+2D+1} (7+75sin2x)[/tex]

Now,

[tex]\frac{7}{D^2+2D+1} +\frac{75}{D^2+2D+1} (sin2x)[/tex]

7 -3(2D+3)sin2x

7 - 6D.sin2x - 9sin2x

7 - 6 x 2cos2x - 9sin2x

7 - 12cos2x - 9sin2x

PI = 7 - 12cos2x - 9sin2x

Finally,

y = C.F + P.I

y =  (c₁+c₂x)[tex]e^{-x}[/tex] + 7 - 12cos2x - 9sin2x.

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We reject the null hypothesis and conclude that the data supports the claim that the mean height of high school students who play basketball on the school team is less than 73 inches.

Null Hypothesis: The mean height of high school students who play basketball on the school team is 73 inches or greater.

Alternative Hypothesis: The mean height of high school students who play basketball on the school team is less than 73 inches.

We are given a sample size of 40 players with a sample mean of 71 inches and a sample standard deviation of 1.5 inches.

To test our hypothesis, we will use a one-sample t-test with a significance level of 0.05.

Using a t-distribution table with 39 degrees of freedom (n-1), we find the critical t-value to be -1.686.

We calculate the test statistic as:

t = (sample mean - hypothesized mean) / (sample standard deviation / sqrt(sample size))

t = (71 - 73) / (1.5 / sqrt(40)) = -4.38

Using a t-distribution table with 39 degrees of freedom, we find the p-value to be almost zero (less than 0.0001).

Since the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that the data supports the claim that the mean height of high school students who play basketball on the school team is less than 73 inches.

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