a) The angle of the banking, is = 32.65° b) Coefficient of static friction is = 0
What is coefficient of static friction?The ratio of the maximum static friction force between the surfaces in contact before movement commences to the normal force is called the coefficient of static friction.
Given radius of the banked curve is, r = 95 m.
Given, v= 88 km/hr
Maximum speed of the car for which road is banked is,
=(88km/1hr) *(1000m/1km) *(1hr/60min)*(1min/60sec)
= 24.44m/s
As we know, tanФ = v² /r*g
= 24.44² /(95 * 9.8)
= 0.641
Ф = tan⁻¹(0.641)
= 32.65°
μ=(v²/r- g tan Ф) / (g + v²/r tanФ)
= (24.44² /95- 9.8 * 0.641)/ (9.8+( 24.44² * 0.641 /95))
= (6.28 - 6.28) / [9.8 + 4.02)]
= 0
Coefficient of static friction is = 0
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an old streetcar rounds a flat corner of radius 8.0 m, at 13 km/h. what angle with the vertical will be made by the loosely hanging hand straps?
Angle with the vertical will be made by the loosely hanging hand straps is 13 degrees.
A string attached to an object can also exert a force but only if the string is pulled taut, and only in the direction of the string. This force is called tension.
We usually make the approximation that the string is massless and unstretchable, so we don’t need to worry about it sagging in the middle or about its length changing, our strings which we consider in questions are also usually unbreakable.
The force transmitted through a string, rope, cable, or wire that is pulled tight. The rope pulls with a tension force on both objects.
For examples, A box hangs from the ceiling by a cable. The cable exerts an upward tension force on the box. A dog is pulled by a dog chain. The chain exerts a force upon the dog.
Given,
V=13km/h = 4.4 m/s
TsinФ = mv^2/R------(1)
TcosФ = mg-------(2)
Divide (1) by (2)
tanФ = v^2/Rg
Ф = tan ^-1(4.4*4.4)/8.50*9.80
Ф = 13 degrees.
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a current of 27.0 ma is maintained in a single circular loop of 3.90 m circumference. a magnetic field of 0.710 t is directed parallel to the plane of the loop.
The magnetic moment of the loop is 8.37 * 10⁻³ Am²
The torque exerted on the loop by the magnetic field is 5.94 * 10⁻³ Nm.
What is the magnetic moment of the loop?The magnetic moment of the loop is calculated as follows:
M = IAwhere;
M is the magnetic momentA is the area of the loop in m²I is the current in amperesThe Area of the loop, A = πr²
where r is the radius
r = Circumference / 2π
r = 3.9 / 2π
Area = π * (3.9/2π)²
A = 0.31 m²
Moment of the loop = 27 * 10⁻³ * 0.31
Moment of the loop = 8.37 * 10⁻³ Am²
The torque exerted on the loop by the magnetic field is given as follows:
T = MB
where;
T is the torque
B is the magnetic field.
T = 8.37 * 10⁻³ * 0.71
T = 5.94 * 10⁻³ Nm
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Complete question:
A current of 27.0 mA is maintained in a single circular loop with a circumference of 3.90 m. A magnetic field of 0.710 T is directed parallel to the plane of the loop. (a) Calculate the magnetic moment of the loop. (b) What is the magnitude of the torque exerted on the loop by the magnetic field?
The direction of the force of sliding friction is always select one to that of velocity of the object and is select one static friction. True or False?
The direction of the force is sliding friction is always select one to that velocity of the object and is Select one Statics friction this statement is false.
What is friction?Friction is the force resisting to the relative motion of the solid surfaces, fluid layers, and material elements and the sliding against each other. There are some several types of friction: Dry friction is a force and that opposes the relative lateral and the motion of two solid surfaces in contact.
Frictional force offers to the resistance to the applied by the force opposing it is the motion. Thus, it always acts like it is in the direction of the opposite to that of the object in the motion
So it will not be in direction of the motion
And static friction also work as the opposite direction of the motion .
Thus, it is false.
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for the circuit diagram below: a. find the voltage vout and the current ix. b. find the current iy. c. how much power is delivered by the 6 v source? d. find the power dissipated in the 8 kw resistor.
A. In the ideal Amp, V⁺ = V⁻
B. [tex]V_{out} = -2v[/tex]
C. [tex]P_{8K} = 4.5 m watts[/tex]
Solution:
[tex]V_{out} = 3-5 = -2v = V_{out} = -2v\\\\I_{y} = \frac{V_{out} }{500} = \frac{-2}{500} = I_{y} = -4ma[/tex]
Power delivered by 6v = P6v = (6)(1) (6)(m) -6mworth = = 6 V Vgk = (8k) (a) = (8k) (0,75 mA)
Power dissipated in the 8k = P₁₁ = (6v) (ia) = (6) (0.75 m) = 4.5 mwatts.
A schematic is a graphical representation of an electrical circuit. Schematics uses simple images of components, and schematics use standardized symbolic representations to show circuit components and connections. A schematic is a simplified representation of the components of an electrical circuit using either pictures of individual parts or standard symbols.
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the longest wavelengths on the electromagnetic spectrum are ________.
Radio waves have the electromagnetic spectrum's longest wavelengths. Radio waves have wavelengths that are longer than one millimeter.
What is wavelength ?A waveform signal that is propagated in space or along a wire has a wavelength, which is the separation between two identical points (adjacent crests) in the adjacent cycles.
What are radio waves ?The electromagnetic spectrum's longest wavelengths, which are found in radio waves, are normally found at frequencies of 300 gigahertz and below. The wavelength for 300 GHz is 1 mm, while the wavelength for 30 Hz is 10,000 kilometers.
So,
Radio waves have the electromagnetic spectrum's longest wavelengths. Radio waves have wavelengths that are longer than one millimeter.
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Who of the following would be included in the Bureau of Labor Statistics' "unemployed" category?
a. Miguel, who is on temporary layoff.
b. Reta, who worked only 15 hours last week.
c. Marisa, who neither has or job or looking for one.
d. None of the above is correct.
The correct option is (d). none of the above is correct .For the "unemployed" category.
According to the Organization for Economic Co-operation and Development (OECD), unemployment is defined as those over a certain age (often 15) who are not now employed or self-employed but are nonetheless currently available for work during the reference period.The number of unemployed people as a percentage of the labour force serves as a proxy for unemployment, which is expressed as the unemployment rate (the total number of people employed added to those unemployed).To know more about unemployed
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rag the appropriate labels to their respective targets. Reset Help Pons Il Midbrain Hypothalamus Spinal cord UM Cerebellum Thalamus Pineal gland Medulla oblongata
Pons, Midbrain, Hypothalamus, Spinal cord ,UM Cerebellum, Thalamus Pineal gland, Medulla oblongata are the parts of brain.
Hypothalamus : Is located at the base of the brain, the release hormones and regulate body temperature.
Pons : is part of the brainstem located Superior To The Medulla and inferior To Midbrain.
Medulla Oblongata : Part Of Brain Stem , located Inferior To Pons, plays an important role in passing messages between spinal cord and brain.
Spinal Cord : Is a Structure made up of nervous tissue, it is Long and Thin.
Cerebellum : Located Near The Brainstem , and Is Major Part Of Hindbrain , primarily involved in coordinating movement and balance.
Midbrain : Is the Uppermost part of the brainstem
There are three main parts of the midbrain - the colliculi, the tegmentum, and the cerebral peduncles.
Pineal Gland : Is a Pea Shaped Gland which produce and secrete the hormone melatonin.
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what is the total momentum of the three pieces immediately after the explosion? express your answer to three significant figures and include the appropriate units.
Conservation of momentum
The total momentum of three pieces immediately after the explosion is
What is Conservation of Momentum?Along with the conservation of energy and the conservation of mass, the conservation of momentum is a fundamental principle of physics. The definition of momentum is the product of an object's mass and velocity. According to the principle of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain. Because momentum is a vector quantity with both a magnitude and a direction, dealing with momentum is more challenging than dealing with mass and energy. At the same time, momentum is conserved in all three physical directions.
Calculation:The total momentum of three pieces immediately after the explosion is
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(a) Consider a cart on a spring which is critically damped. At time t = 0, it is sitting at its equilibrium position and is kicked in the positive direction with velocity
v_o.
Find its position x(t) for all subsequent times and sketch your answer. (b) Do the same for the case that it is released from rest at position
x = x_o.
In this latter case, how far is the cart from equilibrium after a time equal to
τ_o = 2π/ω_o
the period in the absence of any damping?
The required position is: 0.0136π
What is equilibrium?
Equilibrium, in physics, the state of a system when neither its state of motion nor its internal energy state tend to change over time. A simple mechanical body is in equilibrium when it experiences neither linear nor angular acceleration. This state will continue indefinitely unless disturbed by an external force. Equilibrium occurs for a single particle when the vector sum of all forces acting on the particle is zero. A rigid body (which by definition differs from a particle by its properties of extension) is in equilibrium when, in addition to the states listed above for particles, the vector sum of all torques acting on the body is equal to zero, Its state of rotational motion remains constant. An equilibrium is said to be stable when a small externally induced displacement from that state produces a force opposing the displacement tending to bring the body or particle back into equilibrium. Examples include weights suspended from springs or bricks placed on a flat surface.
Therefore, The required position is: 0.0136π
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speed of 0.986 c what would be the momentum of this proton? express your answer with the appropriate units.
The momentum of the proton with speed of 0.986 c is 4.20 × 10⁸ kJ - m/s.
Momentum is defined as the product of the mass of a particle and its velocity. Momentum is a vector quantity, which means it has both magnitude and direction. Isaac Newton's second law of motion says that the time rate of change of momentum is equal to the force acting on the particle.
Calculate the momentum by using the formula:
p = (m₀v)/√(1 - v²/c²)
Substituting the values we get,
⇒ p = (1.67 × 10⁻²⁷ × 0.986 c) / √{1 - (0.986/c)²}
⇒ p = (1.67 × 10⁻²⁷ × 0.986 c) / √{1 - (0.986)²}
⇒ p = 1.404 × 10⁻²⁶ c
⇒ p = 4.20 × 10⁸ kJ - m/s
Hence, the momentum of the proton is 4.20 × 10⁸ kJ - m/s.
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In the definition of weight, W = mg, the mass m refers to an inertial mass.
True or false
For a cart moving along a track with the x-axis parallel to the track, all forces acting on the cart must be along the x-direction.
True or false
If the cart is moving on the positive x axis, the x-component of velocity must be positive.
True or False
The mass m used in the formula for weight, W = mg, refers to passive gravitational mass rather than inertial mass.
Objects accelerate due to imbalanced forces. However, not every item accelerates at the same rate in the presence of the same imbalanced force. A mass quantity called inertial mass determines the body's inertial resistance to acceleration when responding to all types of force.The gravitational force a body experiences while in the gravitational field, or g, is what determines its gravitational mass.
It is untrue that all forces acting on a cart going along a track with the x-axis perpendicular to the track must travel in the x direction. Because they might cancel each other out, the forces in the y direction.It is true that the x-component of velocity must be positive if the cart is travelling along the positive x axis.To learn more about inertial mass click here https://brainly.com/question/27750078
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what is the velocity of a 900-kg car initially moving at 3000 cm/s, just after it hits a 150-kg deer initially running at 12000 mm/s in the same direction? assume the deer remains on the car.
The velocity of car is v= 27.42 m/s.
Given;-the 900 kg car initially moving at 30 m/s and just after it hits a 150 kg deer initially run at 12 m/s in the same direction are:-
m1 = 900kg
m2= 15okg
v1= 30 m/s
v2= 12 m/s
so, velocity is
v=(900*30 + 150*12)/(900+150)
v= 27.42 m/s.
What happens when two things collide in terms of velocity?When two objects collide, they are both subject to forces that are equal in strength and directed in opposite directions. Such forces frequently result in the acceleration of one object and the deceleration of the other object (lose momentum).
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increasing the brightness of a beam of light without changing its color will increase
The photons speed will rise if a light beam is made brighter without altering its hue.
What is the simple definition of light?Light is indeed a form of electromagnetic radiation which makes things visible or enables the human eye to see. It can also be described as radiation that is seen by the human eye. Light reaches photon, which are minuscule energy bundles.
What is light and its types?Light that is visible to the human eye alone. It is an electromagnetic energy type. This sun is the primary source of all visible light. Lamps, flashlights, light bulbs, and other objects can also emit it. Another electromagnetic energy that generates heat is infrared light.
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in a double slit experiment light of wavelength 585.0 nm is used, the separation of the slits is 0.100 mm and the viewing screen is 21.0 cm from the slits. on this screen, what is the separation between the fifth maximum and seventh minimum from the central maximum?
The separation between fifth maximum and seventh minimum from central maximum is calculated to be 2.457mm.
What is the double-slit experiment?The double-slit experiment shows that light and matter can exhibit the properties of classically defined waves and particles. This experiment was first performed by Thomas Young in 1802 to demonstrate the wave behavior of visible light
This experiment belongs to general class of double-path experiments, in which a wave is split into two separate waves. Changes in the path length of both the waves leads to a phase shift that creates interference patterns.
Separation between 5th and 7th minima is,
= 2 * (wavelength)x(Distance of the screen) / (slit separation)
=(2x 585x10^-9 x21x10^-2 )/ 0.1x10^-3
Hence, Separation between 5th and 7th minima is =2.457mm.
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a magnetic field is caused by a _______ electric charge.
Answer: MOVING
Explanation:
A magnetic field is caused by a MOVING electric charge.
Charge can be positive or negative.
what are the two principles of the first law of motion
Answer: The principles are
An object at rest (not moving) will stay at rest unless an unbalanced force acts on it.An object in motion will stay in motion (in a straight line and at a constant speed) unless an unbalanced force acts on it.Explanation: Hope this was helpful
gravity on the surface of the moon is only 1 6 as strong as gravity on the earth. what is the weight of a 31 kg object on the earth? the acceleration of gravity is 10 m/s2 . answer in units of n.
The weight of a 31 kg object on the earth is 304.017 newtons.
Briefly:-Weight equals (mass of the thing) x (acceleration of gravity in that place).
— The acceleration of gravity on Earth is approximately 9.807 m/s2.
31 kilograms of mass has a weight of (31 kg) x (9.807 m/s2) = 304.017 newtons.
— On the Moon, the gravitational acceleration is approximately 1.623 m/s2.
The identical mass of 31 kg has a weight of (31 kg) x (1.623 m/s2) = 5.313 newtons.
Why is lunar gravity only one-sixth that of Earth's?The Moon is significantly lighter in mass than the Earth. The Moon is not just smaller than the Earth, but it is also only around 60% as dense. As a result, a person weighs less on the Moon than they do on Earth due to the significantly lower gravitational attraction there.
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a 50-turn coil has a diameter of '17cm'. the coil is placed in a spatially uniform magnetic field of magnitude so that the face of the coil and the magnetic field are perpendicular. find the magnitude of the emf, , induced in the coil if the magnetic field is reduced to zero uniformly
The magnitude of the emf induced in the coil is - 1.134 dB/dt. If the initial magnitude of the magnetic field 0.5 T in 0.5 s is reduced to zero uniformly the magnitude of the emf induced in the coil is 1.134 Volt.
The formula to calculate the magnitude of the emf induced in the coil when the magnetic field is perpendicular to the face of the coil
ε = - NA dB/dt
[tex]\epsilon \:=\: - NA \frac{dB}{dt}[/tex]
where
N = the number of turns in the coil = 50A = the surface area of the coil (m²)dB = the change in magnetic inductionThe surface area of the coil is a circle A = πr²
d = 17 cmr = 17 ÷ 2 = 8.5 cm = 0.085 mA = 3.14 × 0.085² A = 0.0227 m²ε = - NA dB/dt
ε = - 50 × 0.0227 × dB/dt
ε = - 1.134 dB/dt
The problem is not complete. It should tell the initial magnitude of the magnetic field and the interval time.
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Predict/Calculate A 1100-kg car coasts on a horizontal road with a speed of 19 m/s. After crossing an unpaved, sandy stretch of road 32 m long, its speed decreases to 12 m/s. Was the net work done on the car positive, negative, or zero? Explain, Find the magnitude of the average net force on the car in the sandy section.
The magnitude of average net force on the car in the sandy section = 11395.31 N
What is Force ?An object is pushed or pulled by force. When an item interacts with another object, force can be applied to that object. Force is an external agent that has the power to alter an object's state of motion, causing a body at rest to move and a body in motion to stop.
According to the given information
Work Done = [tex]\Delta K E \\[/tex]
Net work done = [tex]K E_f-K E_i \\[/tex]
Net work done = [tex]\frac{1}{2} m v_f^2-\frac{1}{2} m v_i^2 \\[/tex]
Net work done = \[tex]\frac{1}{2} \times 1100 \times\left[(19)^2-(32)^2\right] \\[/tex]
Net work done = -364650 [tex]\mathrm{~J} \\[/tex]
Net work done = [tex]F_{\text {avg }} \cdot d \\[/tex]
364650 = [tex]\left(F_{\text {avg }}\right)(32) \\[/tex]
[tex]F_{\text {avg }}[/tex] = 11395.31 N
Hence
The magnitude of average net force on the car in the sandy section = 11395.31 N
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A 1,193 kg car moving at 27.6 m/s hits a stationary truck with a mass of 4,302 kg. If the two vehicles become stuck together in the collision, how fast do they move away from the point of impact?
use units and work out
The final momentum will be the sum of the initial momentum of the two vehicles. The final velocity of the combined mass will be 5.9 m/s.
What is collision?Collision is a short range force exerted by an object on other object make them move either to the same side or opposite sides based on their mass.
Momentum of a moving body is the product of its mass and velocity. During a collision, the initial momentum will be equal to the final momentum.
The momentum of the car = mass × velocity
= 1193 Kg × 27.6 m/s
= 32926 kg m/s
The initial momentum of the truck is zero because it was stationary.
The final momentum with the velocity v, of the combined mass is equal to the total initial momentum i.e. 32926 kg m/s.
32926 kg m/s = (1193 Kg + 4302 Kg) v
v = 32926 kg m/s / (1193 Kg + 4302 Kg)
= 5.9 m/s.
Therefore, the final velocity of the vehicles when they stuck together is 5.9 m/s.
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if the mass of a wheel is increased by a factor of 2 and the radius is increased by a factor of 1.5, by what factor is the moment of inertia increased? model the wheel as a solid disc.
The Moment of inertia is increased by the factor of 3.
Rotational inertia, or moment of inertia, is the rotational equivalent of mass; this is the quantity we want to measure to see how much energy is needed to accelerate the wheel. We can measure the weight of a wheel relatively easily, but it is not necessarily true that the lightest wheel will have the smallest moment of inertia or vice versa. If we have a rigid body rotating with an angular velocity Ω about a fixed axis , each particle in it will have a certain amount of kinetic energy. A particle of mass m with radius r from the axis of rotation moves in a circle with radius r with angular velocity Ω around this axis. So it has a linear velocity v = Ωr and its kinetic energy K is ½ mv2 = ½ mΩ2r2. The total kinetic energy is the sum of the kinetic energies of its particles, and each particle in a solid moves with the same angular velocity Ω (it moves the same number of angular degrees per unit time), but the radius r can be different for different particles. So the total kinetic energy isK = ½ (m1r12 + m2r22 + …)Ω2 = ½ (∑miri2)Ω2
The moment of inertia of the wheel is given as
I = MR2
if M' = 2M and R' = 1.5R
then I' = M'R'2 = (2M)(1.5R)2 = 3.0 MR2 = 3I
so the factor is 3
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at the instant a traffic light turns green, a car that has been waiting at the intersection starts ahead with a constant acceleration of 2.00 m/s2. at that moment a truck traveling with a constant velocity of 15.0 m/s overtakes and passes the car. (a.) calculate the time necessary for the car to reach the truck. (b.) calculate the distance beyond the traffic light that the car will pass the truck. (c.) determine the speed of the car when it passes the truck.
a) time, t = 11.407 s, b) distance x = 175.66 m, v = c) speed v = 30.80 m / s
Explanation of question:a) This is kinematics exercise, write the equation of each vehicle car is;-
x = x₀ + v₀ t + ½ a t²
Let's fix our the reference system at a point where the car indicate that the car stops from rest is vo = 0.
x₀ = v₀ = 0
we substitutex = ½ a t²
truck
x₂= v₀ t
v₀ = 15.4 m / s
At the point where they are, positions are equal:-
½ a t² = vo t
t = 2 vo / a
calculate us
t = 2 15.4 / 2.
t = 11.407 s
b) the distance to reach it
x = ½ to t²
x = ½ 20 11.407²
x = 175.66 m
c) the speed of the car is
v = vo + a t
vo = 0
v = at
v = 2.0 11.407
v = 30.80 m / s
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how much tension must a rope withstand if it is used to accelerate a 3074 kg car vertically down at 9.1 m/s^2 .
Tension must a rope withstand is 2.182kN
Tension is described stress transmitted axially by a cord, rope, chain, or similar object, or through the ends of a rod, truss, or similar three-dimensional object. Stresses can also be described as pairs of acting and reaction forces acting at each end of the element. Tension may be the opposite of compression. At the atomic level, a restoring force can create what is called stress when atoms or molecules are pulled apart and gain potential energy while the restoring force is still present. An end of a cord or rod under such tension can pull on the object to which it is attached to return the cord or rod to its relaxed length.
Solution:
Assuming only tension and gravity act on the car,
T+mg=ma
T=m(g+a)
=3074*(9.81 - 9.1) N
=2.182 kN which is the tension the rope must withstand.
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on a violin, a correctly tuned string has a frequency of 460 hz. if the string produces a sound at 510 hz when under a tension of 25.0 n, what should the tension be to produce the correct frequency?
The tension be to produce the correct frequency is 306N
What is the frequency?The frequency of a repeated event is its number of instances per unit of time. It differs from angular frequency and is sometimes referred to as temporal frequency for clarification. One event occurs per second when measuring frequency in hertz.
f= 1/2L[tex]\sqrt[/tex] μT
so
fα[tex]\sqrt[/tex] T
∴ f 1/f 2 = [tex]\sqrt[/tex]T 1/T 2
In our example, f 1 = 460 Hz, and T 1 =?
and for f = 510 Hz, T 2 = 255.
∴
510/460 = [tex]\sqrt[/tex]T 1/255.
∴T 1 =( 510/510 )=306N.
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ocean currents are caused primarily by the gravitational attraction between the earth, moon, and sun. true or false
The statement that ocean tides are caused primarily by the gravitational attraction between the earth, moon, and sun is a true statement.
Tides can be defined as the rise and fall of water level in water bodies such as lakes and oceans due to the gravitational force of attraction exerted by the moon on earth. The side closest to the moon creates a bulge of water known as high tide. Low tides are generally experienced when a sea level is not within the bulge.
Generally, the gravitational pull of the Moon cause visible changes on planet Earth's surface.
This ultimately implies that, the pull of the Moon's gravity causes high and low tides on planet Earth's surface.
Therefore, The statement that ocean tides are caused primarily by the gravitational attraction between the earth, moon, and sun is a true statement.
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what is the closest you can be to speaker b and be at a point of perfectly destructive interference?
The closest you can be to speaker B and be at a point of perfectly destructive interference- 1.008m.
The wavelength of sound emitted by speakers
= velocity / frequency
= 344 / 172
= 2 m
For destructive interference , path difference is equal to odd multiple of half the wavelength .
path difference = 2 / 2 = 1 m
d₂ - d₁ = 1 m
d₂ = d₁ + 1 m
d₂ = .008 m + 1
d₂ = 1.008 m
So, the closest you can be to speaker B and be at a point of perfectly destructive interference- 1.008m.
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The complete question is:
Two loudspeakers, A and B, are driven by the same amplifier and emit sinusoidal waves in phase. The frequency of the waves emitted by each speaker is 172 HzHz. You are 8.00 mm from speaker A. Take the speed of sound in air to be 344 m/sm/s. What is the closest you can be to speaker B and be at a point of perfectly destructive interference?
in a car lift used in a service station, compressed air exerts a force on a small piston of circular cross-section having a radius of 3.17 cm. this pressure is transmitted by a liquid to a second piston of radius 16.2 cm. what force must the compressed air exert in order to lift a car weighing
The compressed air must exert a force of 508.47N on the small piston in order to lift the car weighing 13300 N and the pressure exerted is 16.14x10^4Pa.
Given circular cross-section having a radius (r1) = 3.17cm = 3.17x10-2m
The pressure is transmitted by a liquid to a second piston of radius (r2) = 16.2cm = 16.2x10-2m
Force exerted on car (F2) = 13300N
Here pascals principle is applied.
We know that Pressure (P) = force/area
P1 = P2 then F1/A1 = F2/A2
Area of the circle = π*r²
F1/π*(3.17x10-2)^2 = 13300/π*(16.2x10-2)^2
F1 = 508.47N
(b) The air pressure will produce a force of that magnitude P =F/A
P = F1/A1 = 508.47/ π*(3.17x10-2)^2 = 16.14x10^4Pa
(c) As a result, the work is equal in both pistons. The little piston displaces a small volume of liquid, which is dispersed across the large piston in a thin layer.
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complete question: In a car lift used in a service station, compressed air exerts a force on a small piston of circular cross section having a radius of r1 = 3.17 cm. This pressure is transmitted by an incompressible liquid to a second piston of radius 16.2 cm. (a) What force must the compressed air exert on the small piston in order to lift a car weighing 13,300 N? Neglect the weights of the pistons. (b) What air pressure will produce a force of that magnitude? (c) Show that the work done by the input and output pistons is the same.
An IC with a switching rate of 4GHz4GHz and VDD=6VVDD=6V is dissipating 60W60W. What will be the power dissipation if we change VDDVDD to 5V5V and the switching rate to 3GHz3GHz while keeping the activity factor the same?
The power dissipation after changing voltage and switching rate will be 31.25 Volt.
What is power dissipation?
The greatest power that an integrated circuit (IC) can continuously dissipate under a given thermal environment is known as power dissipation.
For 1st case,
switching rate: f = 4 GHz.
power dissipation: P = 60 W.
voltage drop: [tex]V_{DD}[/tex] = 5 V.
So, load capacitance: [tex]C_L[/tex] = [tex]\frac{P}{V_{DD}^{2} *f}[/tex] = 60/{6^2×4} f = 0.417 f.
Now for 2nd case:
switching rate: f = 4 GHz.
voltage drop: [tex]V_{DD}[/tex] = 6V.
Hence, power dissipation in this case: P = [tex]{C_L*V_{DD}^{2} *f}[/tex]
= 0.417 × 5² × 3 V
= 31.25
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the escape speed for a rocket at earth's surface is ve (a) 2 v . what would be the rocket's escape speed from the surface of a planet with twice earth's mass and the same radius as earth?
The rocket's escape speed from the surface of a planet with twice earth's mass and the same radius as earth is √(2GM/r).
Escape speed with the speed at which the kinetic energy of the satellite is exactly equal to the negative amount of potential energy within the satellite/mass system. That is
1/2mv2 = |-GMm/r| which gives the escape speed ve = √(2GM/r)
The earth's surface escape speed is roughly 11.186 km/s. Accordingly, "an object needs have a starting velocity of at least 11.186 km/s to escape the gravity of the earth and fly to infinity."
The escape velocity vesc is expressed as vesc = Square root of√2GM/r,where G is the gravitational constant, M is the mass of the attracting mass, and r is the distance from the centre of that mass.
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1 pts D.A.V.E." is an acronym that helps you assign function (sensory vs. motor) to various structures in he central nervous system. The function of which of the following structures can not be esolved by thinking of DAVE?
O ventral root of a spinal nerve
O dorsal ramus of a spinal nerve
O posterior (dorsal) gray horns of the spinal cord
O anterior (ventral) gray horns of the spinal cord
option b) dorsal ramus of a spinal nerve, is correct answer.
Describe the spinal nerve.
In order to modulate motor and sensory information from the body's periphery, spinal nerves, which are mixed nerves, directly communicate with the spinal cord. Each nerve is made up of fila radicular, or nerve fibers, that originate from the ventral and dorsal roots of the spinal cord.
What are the functions of spinal nerves?
Between your brain, spinal cord, and the rest of your body, your spinal nerves transmit electrical messages. You may move your body and perceive feelings thanks to these electrical nerve signals (sensory nerve) (motor nerves).
What 31 spinal nerves are there?
There are 31 pairs in humans, including 8 cervical, 12 thoracic, 5 lumbar, 5 sacral, and 1 coccygeal. Each pair joins a certain part of the body to the spinal cord. Each spinal nerve splits into two roots close to the spinal cord.
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