.4.1 Here are the data from Exercise 2.3.10 on the num-ber of virus-resistant bacteria in each of 10 aliquots: 14 14 15 26 13 16 21 20 15 13 (a) Determine the median and the quartiles. (b) Determine the interquartile range. (c) How large would an observati

Answer:

(I) yessssssssssssssssssssssss

Answer:

yes it is.

Step-by-step explanation:

i did this and it was correct

Answer:

a. P)  = 0.25

b.  P) = 0.25

c. P) = 0.5

Step-by-step explanation:

a) 1/4  as 1/2 x 1/2 = 1/4  = 0.25   This becomes reduced as we are multiplying one complete probability journey by another complete probability journey.

b) see above as 1/2 x 1/4 and 1/4 x 1/2 = 2.5 = 1/4 = 0.25

or we can Set to 1 and 1 - 3/4 = 1/4. = 0.25.

c)  1/2 as half of the journeys have traffic jams so its 1 -  1/2 = 1/2 = 0.5

Answer:

22.7 pounds

Step-by-step explanation:

Simply just subtract 42.7 with 37 (5/8) to get the answer. If done correctly, you should get 22.7 pounds.

So, the final answer is 22.7 pounds.

Hope this helped!

Answer:

24

Step-by-step explanation:

3x5=15

15+9=24

Answer:

[tex]\sin(\theta) = \frac{5}{27}[/tex]

Step-by-step explanation:

Given

[tex]\csc(\theta) = \frac{27}{5}[/tex]

Required

Determine [tex]\sin(\theta)[/tex]

In trigonometry identity;

[tex]\sin(\theta) = \frac{1}{\csc(\theta)}[/tex]

So, we have:

[tex]\sin(\theta) = \frac{1}{\frac{27}{5}}[/tex]

Take inverse of the fraction

[tex]\sin(\theta) = \frac{5}{27}[/tex]

Answer:

y = 21

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Step-by-step explanation:

Step 1: Define

Identify

y = -4x + 9

x = -3

Step 2: Evaluate

Answer:

1. C

2. B

3 A

4. A

Step-by-step explanation:

#1

Brady starts off with 12 coins

And buys 6 more coins every year

So add 6 to find number of coins he will have the next year until we've done it five times ( because we want to find how many he will have after 5 years )

12 ( 1st year )

Add 6

12 + 6 = 18 ( 2nd year )

Add 6

18 + 6 = 24 ( 3rd year )

Add 6

24 + 6 = 30 ( 4th year )

Add 6

30 + 6 = 36 ( 5th year )

By the fifth year he will have 36 coins and the sequence would be

12, 18, 24, 30, 36

Which corresponds with answer choice C

2

15, 19, 23, 27, ?

We want to find the next term

To do so we must find the common difference

We can do this by subtracting the last given term by the term before it

27 - 23 = 4

Just to clarify we can do the terms before those

19 - 15 = 4

So the common difference is 4

Now to find the next term we simply add 4 to the last given term

27 + 4 = 31

The next term would be 31

3. Cumulative property of addition states that you can add any 3 numbers in a different order and they will be the same

a + b + 2 = 2 + a + b

Same variables and numbers just different order

Therefore this is an example of cumulative property of addition

4. The GCF ( greatest common factor ) is the greatest number that the two numbers can be divided by

18a and 24ab

Factors of 18

2 , 9 , 6, 3 , 1 and 18

Factors of 24

24, 1, 2, 12, 6, 4, 3 and 8

The greatest factor that both 18 and 24 have is 6

The GCF would be 6a ( not 6 ) because both numbers share a common variable (a) ( 18a , 24ab )

Answer:

(-8,0), (0,-6)

Step-by-step explanation:

Answer:

Top left: not a function

Top right: not a function

Bottom left: function

Bottom right: not a function

Step-by-step explanation:

A function is a relationship where each x value has it's own y value ( note that domain = x values and range = y values)

For the one on the top left.

S and n have more than one y value.

Because s and n have more than one y value the relation is not a function

For the one of the top right.

There x value "c" has multiple y values therefore the relation is not a function

For the one on the bottom left

Each x value has it's own y value therefore it is a function ( note that the y values can repeat. It's only the x values that can't repeat. )

For the one on the bottom right

The x value "-5" has multiple y values therefore the relation is not a function

The solution for set F(x) is -1

Answer:

a) By the Central Limit Theorem, it has an approximately normal shape, with mean(center) 0.9 and standard deviation(spread) 0.035.

b) Average numbers of children between 0.83 and 0.97 are reasonably likely in the sample.

c) 0.0021 = 0.21% probability that the average number of children per family in the sample will be 0.8 or less

d) 0.9958 = 99.58% probability that the average number of children per family in the sample will be between 0.8 and 1.0

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean 0.9 and standard deviation 1.1.

This means that [tex]\mu = 0.9, \sigma = 1.1[/tex]

Suppose a television network selects a random sample of 1000 families in the United States for a survey on TV viewing habits.

This means that [tex]n = 1000, s = \frac{1.1}{\sqrt{1000}} = 0.035[/tex]

a. Describe (as shape, center and spread) the sampling distribution of the possible values of the average number of children per family.

By the Central Limit Theorem, it has an approximately normal shape, with mean(center) 0.9 and standard deviation(spread) 0.035.

b. What average numbers of children are reasonably likely in the sample?

By the Empirical Rule, 95% of the sample is within 2 standard deviations of the mean, so:

0.9 - 2*0.035 = 0.83

0.9 + 2*0.035 =  0.97

Average numbers of children between 0.83 and 0.97 are reasonably likely in the sample.

c. What is the probability that the average number of children per family in the sample will be 0.8 or less?

This is the p-value of Z when X = 0.8. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.8 - 0.9}{0.035}[/tex]

[tex]Z = -2.86[/tex]

[tex]Z = -2.86[/tex] has a p-value of 0.0021

0.0021 = 0.21% probability that the average number of children per family in the sample will be 0.8 or less.

d. What is the probability that the average number of children per family in the sample will be between 0.8 and 1.0?

p-value of Z when X = 1 subtracted by the p-value of Z when X = 0.8.

X = 1

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{1 - 0.9}{0.035}[/tex]

[tex]Z = 2.86[/tex]

[tex]Z = 2.86[/tex] has a p-value of 0.9979

X = 0.8

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.8 - 0.9}{0.035}[/tex]

[tex]Z = -2.86[/tex]

[tex]Z = -2.86[/tex] has a p-value of 0.0021

0.9979 - 0.0021 = 0.9958

0.9958 = 99.58% probability that the average number of children per family in the sample will be between 0.8 and 1.0

Given:

so, total cost fir 200 masks=

200×5

= 1000

therefore, Joe paid Rs. 1000 altogether.

9514 1404 393

Answer:

  x = -5  or  x = -2

Step-by-step explanation:

Factoring, we have ...

  ((x +3 +2)((x +3) -1)) = 0

  (x +5)(x +2) = 0

  x = -5  or  x = -2 . . . . . . . . values that make the factors zero

Answer:

[tex]\mu = 5.2[/tex]

[tex]\sigma = 2.257[/tex]

Step-by-step explanation:

Given

[tex]n = 260[/tex] -- samples

[tex]p = \frac{1}{50}[/tex] --- one in 50

Solving (a): The mean

This is calculated as:

[tex]\mu = np[/tex]

[tex]\mu = 260 * \frac{1}{50}[/tex]

[tex]\mu = 5.2[/tex]

Solving (b): The standard deviation

This is calculated as:

[tex]\sigma = \sqrt{\mu * (1-p)}[/tex]

[tex]\sigma = \sqrt{5.2 * (1-1/50)}[/tex]

[tex]\sigma = \sqrt{5.2 * 0.98}[/tex]

[tex]\sigma = \sqrt{5.096}[/tex]

[tex]\sigma = 2.257[/tex]

Answer:

A = 1/2 b × h

Step-by-step explanation:

hope it helps !!!!

Answer:

The formula for the area of a triangle is 1/2bh.  

Answer:

Slope = 2

Step-by-step explanation:

To find the slope of the line, you need to plot two points

My own two points will be: [tex](1,2)[/tex] and [tex](2,4)[/tex]

Now use the Slope-Formula to identify the slope of the line

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m=\frac{4-2}{2-1}[/tex]

[tex]m=\frac{2}{1}[/tex]

[tex]m=2[/tex]

so the slope of the line in simplest form will be 2.

Answer:

Domain: (-∞, 1]

Range: (-∞, 3]

Step-by-step explanation:

The function starts at point (1, 3) and goes to the left and down forever.

Domain: (-∞, 1]

Range: (-∞, 3]

Answer:

Domain: [tex](-\infty, 1][/tex]

Range: [tex](-\infty, 3][/tex]

Step-by-step explanation:

The domain of a function represents the range of x-values that are part of the function, read left to right. We can see that the function goes forever to the left and stops at [tex]x=1[/tex] when we read left to right. Therefore, the domain of this function is [tex]\boxed{(-\infty, 1]}[/tex].

The point at [tex]x=1[/tex] is a filled-in solid dot so it is included as part of the function. Use square brackets to denote inclusive.

The range of a function represents all y-values that are part of the function, read bottom to top. The function continues down forever and stops at [tex]y=3[/tex] when read bottom to top. Therefore, the range of this function is [tex]\boxed{(-\infty, 3]}[/tex]. Similar to the domain, we use a square bracket on the right to indicate that [tex]y=3[/tex] is included in the function. If the dot was not filled-in, then we would use a parenthesis to indicate that [tex]y=3[/tex] would not be part of the function.

Answer:

[tex]v = \frac{1}{3}bh[/tex]

since base is pi r^2

[tex]v = \frac{1}{3} \pi \: r {}^{2} h[/tex]

it's given that h=4r

[tex]v = \frac{1}{3} \pi \: r^{2} (4r) = \frac{4}{3} \pi \: {r}^{3} [/tex]

now find derivative

[tex] \frac{dv}{dt} = 4\pi \: r {}^{2} [/tex] × dr/dt

r=8 , dv/dt = 3

dv/dt = 4pi (8)^2 ×3 = 768pi

Answer:

768 pi in^3/min

Step-by-step explanation:

Volume of cone=1/3 pi×r^2×h

Differentiating this gives:

dV/dt=1/3×pi×2r dr/dt×h+1/3×pi×r^2×dh/dt

We are given the following:

dr/dt = 3 in./min.

h=4r when r = 8 inches

If h=4r then dh/dt=4dr/dt=4(3 in/min)=12 in/min

If h=4r and r=8 in, then h=4(8)=32 in for that particular time.

Plug in:

dV/dt=1/3×pi×2r dr/dt×h+1/3×pi×r^2×dh/dt

dV/dt=1/3×pi×2(8)(3)×32+1/3×pi×(8)^2×12

dV/dt=pi×2(8)(32)+pi×(8)^2(4)

dV/dt=pi(256×2)+pi(64×4)

dV/dt=pi(512)+pi(256)

dV/dt=pi(768)

dV/dt=768pi

dV/dt=768/pi in^3/min

Step-by-step explanation:

25 minutes=3 miles

1 minute = 3/25 miles

20 minutes = 3/25 * 20 miles

= 2.4 miles

Therefore, the answer is 2.4 miles.

Answer:

[tex]d_2=-8.32ft[/tex]

Step-by-step explanation:

From the question we are told that:

Height of first draw down [tex]h=30[/tex]

Pump Discharge [tex]Q=250gallons/day[/tex]

Well 1 depth [tex]d_1=10ft[/tex]

Transmissivity[tex]\=T 10.0 ft2/day[/tex]

Radius[tex]r=0.5[/tex]

Well 2 depth [tex]d_2=50ft[/tex]

Generally the Thiem's equation for Discharge is mathematically given by

 [tex]Q=\frac{2\piT(h_2-h_1)}{ln(\frac{r_2}{r_1})}[/tex]

 [tex]250=\frac{2*\pi 10 (10-d_2)}{ln(\frac{50}{0.5})}[/tex]

 [tex]1151.293=2*\pi 10 (10-d_2)[/tex]

 [tex]d_2=-8.32ft[/tex]

Answer:

The sales tax on a 320 dollars purchase is of $29.6.

Step-by-step explanation:

State sales tax y is directly proportional to retail price x.

This means that:

[tex]y = cx[/tex]

In which c is the constant of proportionality.

An item that sells for 156 dollars has a sales tax of 14.42 dollars.

This means that [tex]x = 156, y = 14.42[/tex]. We use this to find c. So

[tex]y = cx[/tex]

[tex]14.42 = 156c[/tex]

[tex]c = \frac{14.42}{156}[/tex]

[tex]c = 0.0924[/tex]

Then

[tex]y = 0.0924x[/tex]

What is the sales tax on a 320 dollars purchase?

y when [tex]x = 320[/tex]. So

[tex]y = 0.0924(320) = 29.6[/tex]

The sales tax on a 320 dollars purchase is of $29.6.

Answer:

It's A

Step-by-step explanation:

On Edg

Answer:

1) Parallel lines are "ALWAYS"

coplanar.

2) Perpendicular lines ARE "ALWAYS"

coplanar.

3) Distance around an unmarked circle CAN "NEVER" be measured

Step-by-step explanation:

1) Coplanar means lines that lie in the same plane. Now, for a line to be parallel to another line, it must lie in the same plane as the other line otherwise it is no longer a parallel line. Thus, parallel lines are always Coplanar.

2) similar to point 1 above, perpendicular lines are Coplanar. This is because perpendicular lines intersect each other at right angles and it means they must exist in the same plane for that to happen. Thus, they are always Coplanar.

3) to have the distance, we need to have the circle marked out. Because it is from the marked out circle that we can measure radius, diameter and find other distances around the circle. Thus, distance around an unmarked circle can never be measured.

Answer:

(1) Ordinal

(2) Such data should not be used for calculations such as an average.

Step-by-step explanation:

Given

[tex]1 \to Low[/tex]

[tex]2 \to Medium[/tex]

[tex]3 \to High[/tex]

[tex]Average = 1.3[/tex]

Solving (a): The level of measurement

When observations are presented in ranks such as:

[tex]1 \to Low[/tex]

[tex]2 \to Medium[/tex]

[tex]3 \to High[/tex]

The level of measurement of such observation is ordinal

Solving (b): What is wrong with the computation?

Ordinal level of measurement are not numerical values whose average can be calculated because they are used as ranks.

Hence, (a) is correct

Answer:

$0.60

Step-by-step explanation:

To find the cost of 1 orange, divide the $6 by 10:

6/10 = 0.6

Hope it helps (●'◡'●)

Step-by-step explanation:

x intercept=(-1,0) because the graph is passing this point on the x axis

y intercept=(0,-3)

Answer:

4th option

Step-by-step explanation:

The x- intercept is where the graph crosses the x- axis.

This is at (- 1, 0 )

The y- intercept is where the graph crosses the y- axis.

This is at (0, - 3 )

Answer:

Length of the rectangle:

[tex]x = \frac{4800}{106} = \frac{2400}{53} [/tex]

Breadth of the rectangle:

[tex]60\%(x) = \frac{60}{100} \times \frac{4800}{106} \: \: \: \: \: \: \: \: \: \: \: \\ =60 \times \frac{48}{106} \\ = \frac{2880}{106} [/tex]

Step-by-step explanation:

Longer side of the rectangle(length) = x

Shorter side of the rectangle(breadth) = (60%)x

Perimeter of the rectangle = 2(l+b) = 96 inches

Hence,

[tex]96 = 2(x + 60\%(x))[/tex]

[tex]96 = 2(x + \frac{6}{100 } x)[/tex]

[tex]96 = 2( \frac{100}{1 00} x + \frac{6}{100} x)[/tex]

[tex]96 = 2( \frac{106}{100} x)[/tex]

[tex]96 = \frac{106}{50} x[/tex]

[tex]96 \div \frac{106}{50} = x[/tex]

[tex]96 \times \frac{50}{106} = x[/tex]

[tex] \frac{4800}{106} = x[/tex]

Answer:

Step-by-step explanation:

Given expressions are,

[tex]p=\frac{\sqrt{10}-\sqrt{5}}{\sqrt{10}+\sqrt{5}}[/tex] and [tex]q=\frac{\sqrt{10}+\sqrt{5}}{\sqrt{10}-\sqrt{5}}[/tex]

Remove the radicals from the denominator from both the expressions.

[tex]p=\frac{\sqrt{10}-\sqrt{5}}{\sqrt{10}+\sqrt{5}} \times \frac{\sqrt{10}-\sqrt{5}}{\sqrt{10}-\sqrt{5}}[/tex]

  [tex]=\frac{(\sqrt{10}-\sqrt{5})^2}{(\sqrt{10})^2-(\sqrt{5})^2}[/tex]

  [tex]=\frac{(\sqrt{10}-\sqrt{5})^2}{5}[/tex]

[tex]\sqrt{p}=\sqrt{\frac{(\sqrt{10}-\sqrt{5})^2}{5}}[/tex]

      [tex]=\frac{\sqrt{10}-\sqrt{5}}{\sqrt{5}}[/tex]

[tex]q=\frac{\sqrt{10}+\sqrt{5}}{\sqrt{10}-\sqrt{5}}[/tex]

  [tex]=\frac{\sqrt{10}+\sqrt{5}}{\sqrt{10}-\sqrt{5}}\times \frac{\sqrt{10}+\sqrt{5}}{\sqrt{10}+\sqrt{5}}[/tex]

  [tex]=\frac{(\sqrt{10}+\sqrt{5})^2}{(\sqrt{10})^2-(\sqrt{5})^2}[/tex]

  [tex]=\frac{(\sqrt{10}+\sqrt{5})^2}{5}[/tex]

[tex]\sqrt{q}=\sqrt{\frac{(\sqrt{10}+\sqrt{5})^2}{5}}[/tex]

     [tex]=\frac{(\sqrt{10}+\sqrt{5})}{\sqrt{5}}[/tex]

[tex]\sqrt{q}-\sqrt{p}-2\sqrt{pq}=\frac{(\sqrt{10}+\sqrt{5})}{\sqrt{5}}-\frac{(\sqrt{10}-\sqrt{5})}{\sqrt{5}}-2(\frac{(\sqrt{10}+\sqrt{5})}{\sqrt{5}})(\frac{(\sqrt{10}-\sqrt{5})}{\sqrt{5}})[/tex]

                           [tex]=\frac{1}{\sqrt{5}}(\sqrt{10}+\sqrt{5}-\sqrt{10}+\sqrt{5})-\frac{2}{5}[(\sqrt{10})^2-(\sqrt{5})^2)][/tex]

                           [tex]=\frac{1}{\sqrt{5}}(2\sqrt{5})-\frac{2}{5}(10-5)[/tex]

                           [tex]=2-2[/tex]

                           [tex]=0[/tex]