4fe 3o2 xh2o → 2fe2o3 • xh2o the formation of rust (equation above) is an example of both combustion and

H2o is initially present in a state where its molecules are far apart. during a change of state, its molecules slow down. Gaseous state to liquid state has most likely take place.

In the gaseous state, molecules of water are far away. Hence intermolecular forces are weak.

But when water vapours changes into liquid state molecules start coming closer. And hence intermolecular forces become strong.

Due to this entropy of water molecules decreases.

Thus from above we concluded that when water vapour changes into liquid its molecules is slow down.

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The name of CuO is copper II oxide and its bond type is ionic or electrovalent bond.

An ionic or electrovalent bond is the type of chemical bond where two atoms or molecules are connected to each other by electrostatic attraction.

This electrostatic attraction is as a result of the transfer of electrons from the metallic element to the non-metal.

According to this question, CuO is a chemical compound consisting of two elements namely; copper and oxygen. The compound name is copper II oxide.

Copper as a metal transfers electrons to oxygen atoms, hence, an ionic bond is formed between the molecules.

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Answer:

D

Explain:

Biology because normally everyone just studies under it so that is my answer for you i hope its right.

pH value of a 0. 011 m naf solution is 8.57.

Solution

This problem uses the relationship between Kb and the dissociation constants which is expressed as Kw = KaKb. Calculations are as follows:

Kb = KaKb

1.00 x 10^-14 = 7.2 x 10^-4(x)

x = 1.39 x 10^-11

We now need to calculate the [OH¯] using the Kb expression:

1.39 x 10^-11 = x^2 / (0.30 - x)

The denominator can be neglected. Thus, x is 3.73 x 10^-6.

pOH = -log 3.73 x 10^-6 = 5.43

pH = 14-5.43 = 8.57

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N3- and Mg2 ions have the same ground-state electron configuration.

Understanding molecule bonding, characteristics, and structures begin with understanding ground state electron configurations. The ground state electron configuration provides insight into a wide range of atomic properties, including the electrons in an atom, distinct orbitals, and hybridization.

The ground state of an atom's electrons is the lowest energy state that is feasible for that atom since, throughout the cosmos, a system's natural state is to use the least amount of energy.

Aufbau-Principle: If you have a lot of luggage, you'll probably choose the room that is closest to the ground floor in a hotel without an elevator. The Aufbau principle demonstrates the identical behavior of electrons in the ground state. According to the Aufbau principle, electrons first occupy lower energy orbitals before moving on to higher energy orbitals.

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A monosaccharide that contains 6 carbon atoms, one of which is in an aldehyde group, is classified an Aldohexose.

Monosaccharides of specific sizes may be indicated by names composed of a stem denoting the number of carbon atoms and the suffix -ose.

For example, the terms triose, pentose, and hexose signify monosaccharides with, respectively, three, four, five, and six carbon atoms. Monosaccharides are also classified as aldoses or ketoses.

Those monosaccharides that contain an aldehyde functional group are called aldoses; those containing a ketone functional group on the second carbon atom are ketoses. Combining these classification systems gives general names that indicate both the type of carbonyl group and the number of carbon atoms in a molecule.

. Glucose and fructose are specific examples of an aldohexose and a ketohexose, respectively.

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The concentration of the hydroxide ion given that the concentration of the hydronium ion 1.0 times 10^-14 M. The reverse mathematical method used to determine the pOH can be used to get the hydroxide ion concentration from the pOH. How many hydroxide ions are there in a solution with a pOH of 5.70, for instance.

Calculate 10-5.70, or "inverse" log, on a calculator (- 5.70). It indicates that one hydroxide ion is produced by one part of the NaOH solution. Because of this, the molar concentration of hydroxide ions in the solution is the same as the molar concentration of the NaOH.

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Answer:

Explanation:

1. Write down the balanced equation

2. Use molar mass of O2 (32g/mol) divided by the given mass to derive the amount of mols

3. multiply the answer by 2/3 (divide by 3 then multiply by 2), to ensure the mols are in correct proportion

4. Use given molar mass and multiply it by the amount

5. Make sure to use proper significant digits (3 in this case) and units :)

Taking into account the reaction stoichiometry, 2.8 moles of NaF are formed when 3.0 mol Na reacts with 1.4 mol F₂.

In first place, the balanced reaction is:

2 Na + F₂  → 2 NaF

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 2 moles of Na reacts with 1 mole of F₂, 3 moles of Na reacts with how many moles of F₂?

[tex]amount of moles of F_{2} =\frac{3 moles of Nax 1 moles of F_{2}}{2 moles of Na}[/tex]

amount of moles of F₂= 1.5 moles

But 1.4 moles of F₂ are not available, 1.4 moles are available. Since you have less moles than you need to react with 3 moles of Na, F₂ will be the limiting reagent.

The following rule of three can be applied: if by reaction stoichiometry 1 mole of F₂ form 2 moles of NaF, 1.4 moles of F₂ form how much mass of NaF?

[tex]moles of NaF=\frac{1.4 moles of F_{2}x2 moles of NaF }{1 mole of F_{2} }[/tex]

moles of NaF= 2.8 moles

Then, 2.8 moles of NaF are formed when 3.0 mol Na reacts with 1.4 mol F₂.

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If we takes 11. 2 kj of energy to raise the temperature of 145 g of benzene from 23. 0°c to 68. 0°c, then the specific heat of benzene is

1716.475 J/kg.°C.

Specific Heat capacity is given as

Q = cm(t₂-t₁) ................[tex]equation 1[/tex]

Where Q = quantity of heat, c = specific heat of benzene, m = mass of benzene, t₁  = initial temperature, t₂ = final temperature.

[tex]C[/tex] = [tex]\frac{Q}{m_{(t2-t1)} } ...........equation 2[/tex]

Given:

[tex]Q = 11.2 kJ = 11200 J \\\\m= 145\\\\g = 0.145 kg\\\\t_{2} = 68.0 °C\\\\t_{1} = 23.0 °C[/tex]

Substitute into equation 2.

[tex]C = \frac{11200}{[0.145(68-23)]}\\\\ C= \frac{11200}{6.525}\\\\ C= 1716.475 J/kg °C[/tex]

Hence the specific heat of benzene = [tex]1716.475 J/kg °C[/tex]

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Partial pressure of helium gas in the tank is 162.24 atm.

Partial Pressure:

A partial pressure is the imaginary pressure that a gas would have if it were to occupy the complete volume of the initial mixture by itself at the same temperature. Each gas in a mixture of gases has a partial pressure.

Explanation:

Total pressure in Heloix (P) = 208 atm

The mole fraction of an individual gas component in an ideal gas mixture can be expressed in terms of the component's partial pressure or the moles of the component

Mole fraction of oxygen (X₀) = 0.220

The sum of the mole fractions of all the components present must equal 1.

Mole fraction of helium (Xₐ) = 1-(X₀) = 1- 0.220= 0.78

According to Dalton's law of partial pressure.

Partial pressure of an individual gas component in an ideal gas can be obtained using this expression:

Partial pressure of oxygen gas in Heloix: P*X₀ = 208 * 0.22 = 45.76 atm

Partial pressure of helium gas in Heloix: P*Xₐ = 208 * 0.78 = 162.24 atm

Partial pressure of helium gas is 162.24 atm.

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The complete and balanced molecular equation is-

K₂SO₄(aq) + SrI₂(aq) → KI(aq)+ SrSO₄(s)

Both sides of the reaction must have an equal amount of atoms in each element to balance the equation.

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Balanced molecular equation is :

K₂SO₄(aq) + SrI₂(aq) → KI(aq)+ SrSO₄(s)

What is Balanced equation?

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Answer:

80 m/hr

Explanation:

Changes from 20 to 100 meters in ONE Hour

    changes  80 meters in one hour    = 80 m/hr

The energy required to melt 20 kg of ice at 0°C is 6.68 kJ.

The enthalpy change for melting of an ice is called the enthalpy of fusion. Its value is 6.02 kJ/mol. This means for every mole of ice we must apply  6.02 kJ of heat for melting. The calculation of heat is done by following equation.

q = n×ΔH

in this problem we need to calculate heat needed to melt 20grams of ice at  0°C .

Calculation of moles of water,

Number of moles of water (n) = given mass/ molar mass = 20g/18.02g/mol

Number of moles of water (n) = 1.109 mole

heat or energy required = q = n×ΔH =  1.109 mole× 6.02 kJ/mol = 6.68 kJ

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An endothermic reaction is favored by raising the temperature of a system in dynamic equilibrium. The mechanism absorbs the increased heat to offset the alteration you made. An exothermic reaction is favored by a system's temperature falling while it is in dynamic equilibrium.

Any chemical process that takes heat from its surroundings is said to be endothermic. The reaction's activation energy comes from the energy that was absorbed. This kind of reaction is characterized by its icy sensation.

An exothermic reaction is one in which energy is given off as heat or light. In contrast to an endothermic process, which draws energy from its surroundings, an exothermic reaction transfers energy into the environment.

Materials like hydrocarbons reacting with oxygen to produce combustion products like water and carbon dioxide is an example of an exothermic process.

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The ph of the solution will be acidic. It is because of the higher ka value of ammonia as compared to kb of nitrate

As we know, A salt solution contains ammonium cation (ka = 5.7 × 10^–10) and nitrite anion (kb = 1.4 × 10^–11) in equal proportions but the ka and kb are different.

As we see that the value of ka is higher than the kb that's why the ph level will be acidic.

Acidic solutions are sour in taste as compared to alkaline solutions.

We know that the ph scale basically ranges from 0 to 14. The ph solutions less than 7 are acidic and greater than 7 are basic.

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Buffer is a solution that has been known to have an acid and base dissolved with constant hydrogen concentration. If 5 drops of HCl are added to the buffer then the final pH will be 8.64. Thus, option a is correct.

pH has been the concentration that is made of hydrogen or proton ions. The ions have been known to be released from the acids while the bases release the hydroxide ions.

The given buffer has a pH of 8.78, and hence, it is a basic buffer. If the solution of HCl (strong acid) is added to this buffer then the pH will decrease definitely. As only 5 drops are added there will be not much decrease in the pH.

Therefore, option a. the pH of the buffer after addition to HCl will be 8.64.

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Your question is incomplete, but most probably your full question was, A solution containing a buffer has an initial pH of 8.78. If a student adds 5 drops of HCl(aq) to this solution. What would be a reasonable pH for the resulting solution?

The most likely reaction product in the monobromination of 2-pentanone by bromine in the presence of acid in the dark is known to be 1-Bromo-2-pentanone

The term is known to be the bringing in of one bromine atom into  what we call an organic compound.

Note that the brominating of benzene is known to be a good example of what we know as electrophilic aromatic substitution reaction. In this kind of reaction, the electrophile (which is bromine) is said to forms a kind of sigma bond to that of the benzene ring, bringing in an intermediate. Then, a proton is said to be deleted from the intermediate to create a substituted of benzene ring.

Hence, The most likely reaction product in the monobromination of 2-pentanone by bromine in the presence of acid in the dark is known to be 1-Bromo-2-pentanone

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See full question below

Identify the most likely reaction product(s) in the monobromination of 2-pentanone by bromine in the presence of acid in the dark.

a.) 1-Bromo-2-pentanone and 3-bromo-2-pentanone

b.) 1-Bromo-2-pentanone, 3-bromo-2-pentanone, and 4-bromo-2-pentanone

c.) 1-Bromo-2-pentanone, 3-bromo-2-pentanone, 4-bromo-2-pentanone, and 5-bromo-2-pentanone

d.) 3-Bromo-2-pentanone

e.)1-Bromo-2-pentanone

The bluish color that makes the atmosphere of neptune so beautiful to the human eye is caused by the interaction of sunlight with methane gas.

The compositions of Uranus but also Neptune are fairly similar at high altitudes. The existence of methane in both ice giants' upper atmospheres may be responsible for their blue hue. The majority of the red light that strikes the planets is absorbed by methane, giving the planets their blue appearance.

The blue marble occurrence of the faraway planet is actually a result of methane gas clouds. Methane is a gas that, despite making up a very small fraction of Neptune's atmosphere, absorbing red light's wavelengths while reflecting blue light outward.

Therefore, the bluish color that makes the atmosphere of neptune so beautiful to the human eye is caused by the interaction of sunlight with methane gas.

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Solute s has a distribution constant of 5. 0 between water (phase 1) and hexane (phase 2), then the concentration of solute s in hexane if [s]water is 0. 011 m is 0.055m.

It is defined as the ratio of the concentration of solute in two immiscible ( or slightly miscible liquid) in two solids, when they are in equilibrium across the interface between them.

It is defined as the ratio of number of moles of compound to the volume of compound.

Solute S has a partition coefficient of 5 between water and hexane

Partition coefficient Kd = 5.0

Now we calculate the concentration of S in hexane

[hexane]/[water] = Kd

[Hexane]= 5.0 × (water)

[Hexane] = 5 × (0. 011)

[Hexane] = 0.055 m

Thus, we found that the concentration of solute of hexane if water is 0.011m is 0.055m.

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Gasoline is refined petroleum used in engines as a fuel. It contains octane that can be converted to isooctane by adding catalysts like platinum and palladium.

Catalysts are substances that raise the reaction rate by decreasing the activation energy but do not get consumed themselves in a reaction.

Platinum and palladium metals can be used as a catalyst to convert the octane of the gasoline into isooctane as they are oxidation catalyst that converts the fuel components into water and carbon dioxide.

Therefore, platinum and palladium are used as catalysts in converting octane.

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Suppose protons were emitted rather than electrons then it affects the experiment as the mean velocity of proton will be less then mean velocity electron .

The mass of proton is greater than the mass of electrons but charge of electron is equal to the charge of proton . So , due to difference in the mass of electron and proton there will be some effects.  We can conserve the electric energy which is equal to the qe .

The kinetic energy = 1/2[tex]mv^{2}[/tex]

Now changing the electric potential energy into kinetic energy

v = √2qe/m

The mean velocity of proton will be less then mean velocity electron .

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The temperature of the physics book increasing as the chemistry book slides across it is the difference when motion is faster.

Because the molecules have kinetic energy, molecular motion rises with rising temperature and decreases with falling temperature. At absolute zero, molecular motion comes to a complete standstill.

This is defined as the degree of hotness or coldness of a body and it increases when there is more friction.

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Answer:

The speed of the particles increases for both books, and the temperature of the physics book increases even more.

Explanation:

edmentum

The final answer is 29.8 mL

Molar mass HCl = 36.5 g/mol

Mol HCl in 1.85 g = 1.85 g / 36.5 g/mol = 0.05068 mol

The molarity of the HCl solution is 0.0507 mol /L

Mol HCl in 50 mL = 50 mL / 1000 mL/L * 0.0507 mol /L = 0.002535 mol

This will require 0.002535 mol NaOH

1000 mL contains 0.0850 mol

The volume that contains 0.002535 mol

Volume = 0.002535 mol / 0.0850 mol /L *1000 mL/L = 29.8 mL

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The volume of 0.0850 M NaOH is required to titrate 25.0 ml of 0.0720 M is 21.176 ml.

Normality is defined as the number of equivalents per litre of the solution

It is given by

Normality = number of equivalents / 1 L of solution

Molarity is defined as the number of moles of solute present in one litre of solution

Molarity = moles of solute / 1 litre of solution

Relationship between molarity and normality

Normality = Molarity × Acidity or Basicity of a salt

Here, the Acidity Of NaOH is 1 and the basicity of HBr is also 1.

Thus, Normality = Molarity

We know, N₁V₁ = N₂V₂

We can also write it as M₁V₁ = M₂V₂

V1 = [tex]\frac{M_2V_2}{M_!}[/tex]

Substitute M₁ = 0.0850 M, M₂ = 0.0720 M, V₂= 25 ml

V1 = 21.176 ml

Hence, The volume of 0. 0850 m NaOH are required to titrate 25. 0 ml of 0. 0720 m is 21.176 ml.

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The volume of carbon dioxide that will be produced is 191.4 g.

Calculation:

The following is the balanced equation for the given reaction:

Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g),

It is obvious that when 1.0 mole of Fe2O3 reacts with 3.0 mole of CO, 2.0 mole of Fe and 3.0 mole of CO2 are produced.

Hence by using cross multiplication:

If 2.0 mol of Fe was produced with → 3.0 mol of CO₂, from stoichiometry.

Then how many moles of CO₂ are produced by 2.9 mol of Fe?

To find the answer we have a formula:

∴ The no. of moles of CO₂ produced = (3.0 mol)(2.9 mol)/(2.0 mol) = 4.35 mol.

∴ The mass of CO₂ produced = no. of moles x molar mass = (4.35 mol)(44.0 g/mol) = 191.4 g.

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The concentration of glucose in the new solution will be

30 M mol/liter.

Subtract the solute's mass from the total volume of the solution. Using m as the solute's mass and V as the total volume of the solution, write out the equation C = m/V.

A concentrated solution is referred to as a stock solution since it will be diluted to a lesser concentration before usage. M₁V₁ = M₂V₂ is the dilution equation.

                     A diluted solution = stock solution.

M₁ is the stock solution's molarity.

M₂ stands for the diluted solution's molarity.

V1 is the volume of the starting solution.

V2 is the volume of the final solution.

M₁ = 90M mol/liter

V₁ = 20mL

V₂ = 40mL

Using the formula,

                               M₁V₁ = M₂V₂

                 20mL × 90 M mol/liter = 40mL × M₂

                              M₂ = 30 M mol/liter

Therefore, the concentration of glucose in the new solution will be

30 M mol/liter.

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The number of NH₄⁺ NH₄⁺ and CO₃⁻² CO₃⁻² ions required to form a neutral ionic compound are 2 and 1 respectively.

A Neutral Ionic Compound means a compound that is made by both positively and negatively charged ions i.e. cations and anions respectively.

NH₄⁺ is called as Ammonium ion formed due to addition of H+ (Proton) in Ammonia and CO₃⁻² is called as Carbonate ion formed with a Trigonal Planar structure.

For a compound having NH₄⁺ and CO₃⁻², a neutral compound can be made by keeping the total charge on the compound to be zero.

Hence, Ammonium carbonate (NH₄) ₂CO₃ is a neutral compound formed by taking 2 NH₄⁺ and 1 CO₃⁻² ions.

So, for the formation of the Neutral compound i.e. Ammonium carbonate (NH₄) ₂CO₃ , 2 NH₄⁺ and 1 CO₃⁻² is needed.

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Answer:

Within each group of metals, reactivity increases as you go down the group. The valence electrons are less tightly bound and easier to remove, because they are farther away from the nucleus of the atom. A nonmetal tends to attract additional valence electrons to attain a full valence shell.

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