4m square - 8mn+3n ( resolve into factors)​

Answer:

The answer is "What is important for me to understand?".

Step-by-step explanation:

It is because it is based also on the conclusion that the word in the text read the Jac can draw. Essentially, the particular excerpt read by Jac in his coding book explains that, whether old or new, all older techniques used in the past, compared with the new factorization methods, in truth all shortcuts in mathematics are not feasible and hence all steps have to occur. This implies Jac has to discover what really is important, what he must comprehend, and whether whatever tactics he is using are old and new. The same would be valid of life itself; irrespective of how he chooses to live his life, there are times where shortcuts cannot be used.

Answer:

:

Example Question #1:

Step-by-step explanation:

Which of the following is the equation of a line that is parallel to the line 4x – y = 22 and passes through the origin?

Possible Answers:

4x – y = 0

(1/4)x + y = 0

4x + 8y = 0

4x = 8y

y – 4x = 22

Correct answer:

4x – y = 0

Explanation:

We start by rearranging the equation into the form y = mx + b (where m is the slope and b is the y intercept); y = 4x – 22

Now we know the slope is 4 and so the equation we are looking for must have the m = 4 because the lines are parallel. We are also told that the equation must pass through the origin; this means that b = 0.

In 4x – y = 0 we can rearrange to get y = 4x. This fulfills both requirements.

', .

Answer:

[tex]Height = x - 5[/tex] --- one of the dimension

Step-by-step explanation:

Given

[tex]Volume = 4x^3 - 20x^2 + 3x - 15[/tex]

Required

The side dimension

Factorize the given expression

[tex]Volume = 4x^2 (x- 5) + 3(x - 5)[/tex]

Factor out x - 5

[tex]Volume = (4x^2 + 3)(x - 5)[/tex]

Volume is the product of base area and height'

Hence:

[tex]Area = 4x^2 + 3[/tex]

[tex]Height = x - 5[/tex]

The property of math they are learning is the distributive property

Answer:

B = 34.77°

Step-by-step explanation:

For this problem you are given all three side lengths and asked to find an angle. To do this you can use the law of cosines which is written:

[tex]b^{2} =a^{2} +c^{2} -2ac Cos(B)[/tex]

This can be rearranged to find the angle B:

[tex]b^{2} -a^{2} -c^{2} /-2ac = Cos(B)[/tex]

With lowercase letters being sides and uppercase being angles.

We simply plug in the sides and solve:

[tex]4^{2} -6^{2} -7^{2}/-2*6*7= Cos(B)[/tex]

0.8214 = Cos (B)

Then you use inverse cosine to get angle B alone.

B = 34.77°

Answer:

y= ¼x +1

Step-by-step explanation:

Rewriting the equation into the slope-intercept form (y= mx +c, where m is the gradient and c is the y- intercept):

4y -x= -20

4y= x -20 (+x on both sides)

y= ¼x -5 (÷4 throughout)

Thus, slope of given line is ¼.

Parallel lines have the same gradient.

Gradient of line= ¼

y= ¼x +c

To find the value of c, substitute a pair of coordinates into the equation.

When x= 8, y= 3,

3= ¼(8) +c

3= 2 +c

c= 3 -2

c= 1

Hence the equation of the line is y= ¼x +1.

Answer:

theta = 44.4 degrees

Step-by-step explanation:

Since this is a right triangle, we can use trig formulas

cos theta = opposite/ hypotenuse

cos theta = 15/21

Take the inverse of each side

cos^ -1 (cos theta) = cos ^-1 (15/21)

theta =44.4153086

theta = 44.4 degrees

Step-by-step explanation:

log 25 + log 8 = log (25 × 8) = log 200

log 200 - log 2 = log (200 ÷ 2) = log 100

logarithm base 10 of 100 is 2.

Answer:

D

Step-by-step explanation:

Answer:

[tex]m\angle 2=122^{\circ},\\m\angle 1 = 58^{\circ}[/tex]

Step-by-step explanation:

By definition, tangent lines touch a circle at one point. This one point intersects the circle at a 90 degree angle.

In any circle, the measure of an inscribed angle is exactly half of the arc it forms. Since [tex]\angle 2[/tex] forms an arc labelled 244 degrees, the measure of angle 2 must be [tex]\frac{244}{2}=\boxed{122^{\circ}}[/tex].

Angle 1 and 2 form one side of a line. Since there are 180 degrees on each side of the line, we have:

[tex]\angle 1+\angle 2=180,\\\angle 1 + 122=180,\\\angle 1=180-122=\boxed{58^{\circ}}[/tex]

Given the 22 m. horizontal distance and the angles of elevation of 26°

and 31° gives the height of the building as approximately 2.49 meters.

Horizontal distance from the building = 22 m

Angle of elevation to the top of the roof = 26°

Angle of elevation to the top of the antenna = 31°

Height of his eyes from the ground = 1.53 m

Required:

The height of the antenna.

Solution:

In a right triangle, we have relative to an angle of the triangle, we have;

Opposite side = Adjacent side

Height of the building + Height of antenna = [tex]1.53 + 22 \times tan \left(31^{\circ} \right)[/tex] ≈ 14.75

Which gives;

Height of the building = [tex]1.53 + 22 \times tan \left(26^{\circ} \right)[/tex] ≈ 12.26

Therefore;

Height of the antenna ≈ 14.75 - 12.26 ≈ 2.49

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Answer:

what is the question you are only telling us the fact

Step-by-step explanation:

Answer:

SA = 486

Step-by-step explanation:

Its a cube. s = side length

V = [tex]s^{3}[/tex]

729 = [tex]s^{3}[/tex]

take cube root of each side : [tex]\sqrt[3]{729}[/tex] = 9

so,  s = 9

Surface Area of a cube

SA = 6[tex]s^{2}[/tex]

SA = 6([tex]9^{2}[/tex])

SA = 6(81)

SA = 486

The surface area of the cube is 486 square inches. The correct option is A.

To find the surface area of a cube, we need to use the formula:

Surface Area = 6 x (side length)²

Given that the volume of the cube is 729 cubic inches, we can determine the side length of the cube using the formula for volume:

Volume = (side length)³

729 = (side length)³

Taking the cube root of both sides:

side length = ∛(729) = 9 inches

Now, we can substitute the side length into the surface area formula:

Surface Area = 6 x (9 inches)² = 6 x 81 = 486 square inches

Therefore, the surface area of the cube is 486 square inches.

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Answer:

3m -2

Step-by-step explanation:

(10m – 6) – (7m – 4)

Distribute the minus sign

(10m – 6) – 7m + 4

Combine like terms

3m -2

Answer:

Height of the goalpost is 9.25 m.

Step-by-step explanation:

As per the rule of reflection in physics,

Angle of incidence = Angle of reflection

As we can see in the picture attached, both the angles (θ) are equal.

m∠ACB = m∠ECD = 90° - θ

m∠ABC = m∠ADC = 90°

Therefore, both the triangles ΔABC and ΔEDC will be similar.

And by the property of similar triangles, their corresponding sides will be proportional.

[tex]\frac{AB}{ED}= \frac{CB}{CD}[/tex]

[tex]\frac{1.75}{ED}=\frac{2.6}{13.75}[/tex]

ED = [tex]\frac{1.75\times 13.75}{2.6}[/tex]

ED = 9.25 m

Height of the goalpost is 9.25 m.

Answer:

Step-by-step explanation:

if it is rotated in clockwise direction then C'(-2,-3),D'(2,-5),E'(0,-7)

if rotated in anticlockwise direction C'(2,3),D'(-2,5),E'(0,7)

Answer:

nom nom

Step-by-step explanation:

nom nommy nom nom

Answer:

(a) T = 16√x

Step-by-step explanation:

T is directly proportional to √x, so we can say,

T=k√x (where k is a constant)

now, according to the question,

400=k×√625

400=k×25

k=16

so, putting the value of k in the equation, T=16√x

Answered by GAUTHMATH

Step-by-step explanation:

Given that ,

Mathematically we can write it as ,

[tex]\implies T \propto \sqrt{x}[/tex]

Let k be the constant , therefore ,

[tex]\implies T = kx [/tex]

Now when T = 400 and x = 625 , lets find the value of k , as ,

[tex]\implies 400 = k\times 625 \\\\\implies k =\dfrac{400}{625}\\\\\implies k= 0.64 [/tex]

Therefore the required formula will be ,

[tex]\implies \underline{\underline{ T = 0.64x}} [/tex]

Answer:

The answer is B

Step-by-step explanation:

B

The 22 Australian dollar in USD is 18.33.

Currency is a medium of exchange for goods or services within an economy, usually issued by a government or central bank and generally accepted at its face value.

Given that, we need to determine that there are how many USD in 22 AUD,

So, 1.2 Australian dollars equals 1 US dollar.

Therefore,

22 AUD = 22 x 1 / 1.2 = 18.33

Hence, the 22 Australian dollar in USD is 18.33.

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Answer:

x = 3     y = 5

Step-by-step explanation:

     y=x+2

+    y=-x +8

2y = 10

y = 5

y = -x + 8

5 = -x + 8

x = 3

Answer:

quadratic binomial

[tex]{ \boxed{ \bf{a {x}^{2} + bx + c }}} \\ 2 {g}^{2} + 3g - g[/tex]

Answer:

The temperature at the start is 35F

The temperature of the room is 74F

Step-by-step explanation:

Given

[tex]T(m) = 74 - 39(0.87)^m[/tex]

Solving (a): The temperature at the start.

To do this, we set: [tex]m = 0[/tex]

So, we have:

[tex]T(0) = 74 - 39(0.87)^0[/tex]

[tex]T(0) = 74 - 39*1[/tex]

[tex]T(0) = 74 - 39[/tex]

[tex]T(0) = 35[/tex]

Hence, the temperature at the start is 35F

Solving (b): The room temperature

We have:

[tex]T(m) = 74 - 39(0.87)^m[/tex]

To get the temperature of the room, we simply remove the exponential function.

So, we have:

[tex]Initial = 74[/tex]

Hence, the temperature of the room is 74F

The initial temperature of the liquid is 35 F and the room temperature is 74 F.

The melting point is the temperature at which the solid starts converting into liquid.

Given here,

[tex]T_m = 74- 39(0.87)^m[/tex]

Leat the [tex]m = 0,[/tex]

So,

[tex]T_0 = 74- 39(0.87)^0\\\\T_0 = 35 \rm \ F[/tex]

Thus the initial temperature is 35 F.

Now remove the exponential to get the room temperature,

So,

[tex]T_{RT} = 74[/tex]

Therefore, the initial temperature of the liquid is 35 F and the room temperature is 74 F.

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Step-by-step explanation:

Step 2:

[tex] ({15x}^{2} - 9x) + (5x - 3)[/tex]

Stepc3:

[tex]3x(5x - 3)[/tex]

Evelyn and Meredith were paddling at a rate of [tex]\frac{3+\sqrt{493}}{11}mph[/tex] which is equivalent to 2.29mph approximately.

Step 2: See attached picture

Step 3: In this case we only have different variables, there is the rate at which Evelyn and Meredith were paddling, the rate at which they moved when rowing upstream, the rate at which they moved when rowing downstream, the time it took them to paddle upstream and the time it took them to paddle downstream.

v = rate at which Evelyn and Meredith were paddling.

[tex]v_{up}[/tex]= velocity at which they were moving when paddling upstream.

[tex]v_{down}[/tex]= velocity at which they were moving when paddling downstreamstream.

[tex]t_{up}[/tex]= time it took them paddling upstream.

[tex]t_{down}[/tex]= time it took them paddling downstream

Se attached picture for the table.

Step 4: Building this equation will require us to combine different equations into a single one. Let's start with the equation for the final rate at which they paddled when rowing upstream.

[tex]v-2=v_{up}[/tex]

When rowing upstream, the current will drag the kayak, so we subtract it from the rate at which they were rowing.

Let's find the final rat at which they moved when rowing downstream.

[tex]v+2=v{down}[/tex]

next, the problem tells us it took them 3 hours and 40 minutes to row up and down the channel so we can convert it into just hours like this:

[tex]40min*\frac{1hr}{60min}=\frac{2}{3}hr[/tex]

[tex]3hr+\frac{2}{3}hr=\frac{11}{3}hr[/tex]

so now we can build our equation for time.

[tex]t_{up}+t_{down}=\frac{11}{3}[/tex]

We also know that the rate is built by dividing the distance over the time it took them to travel the distance, so:

[tex]v_{up}=\frac{1}{t_{up}}[/tex]

[tex]v_{down}=\frac{1}{t_{down}}[/tex]

If we solved each of those equations for their respective times, we would end up with the following:

[tex]t_{up}=\frac{1}{v_{up}}[/tex]

[tex]t_{down}=\frac{1}{v_{down}}[/tex]

so we can now combine all the equations together so we get:

[tex]t_{up}+t_{down}=\frac{11}{3}[/tex]

[tex]\frac{1}{v_{up}}+\frac{1}{v_{down}}=\frac{11}{3}[/tex]

[tex]\frac{1}{v-2}+\frac{1}{v+2}=\frac{11}{3}[/tex]

So this equation models the problem.

Step 5: We can solve this equation by multiplying everything by the LCD

In this case the LCD is:

3(v-2)(v+2)

so, when doing the respective multiplications we end up with:

[tex]\frac{3(v-2)(v+2)}{v-2}+\frac{3(v-2)(v+2)}{v+2}=\frac{11(3)(v-2)(v+2)}{3}[/tex]

We can now simplify to get:

3(v+2)+3(v-2)=11(v+2)(v-2)

We can now do the respective multiplications to get:

[tex]3v+6+3v-6=11(v^{2}-4)[/tex]

and we can further simplify:

[tex]6v=11v^{2}-44[/tex]

Step 5: So we can now solve it by using the quadratic formula, first, we need to rewrite the equation in standard form:

[tex]11v^{2}-6v-44=0[/tex]

So we can now use the quadratic formula:

[tex]v=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}[/tex]

we substitute:

[tex]v=\frac{-(-6) \pm \sqrt{(-6)^{2}-4(11)(-44)}}{2(11)}[/tex]

and simplify:

[tex]v=\frac{6 \pm \sqrt{36+1936}}{22}[/tex]

[tex]v=\frac{6 \pm \sqrt{1972}}{22}[/tex]

[tex]v=\frac{6 \pm \sqrt{4(493)}}{22}[/tex]

[tex]v=\frac{6 \pm 2\sqrt{493}}{22}[/tex]

[tex]v=\frac{3 \pm \sqrt{493}}{11}[/tex]

this gives us two possible results:

[tex]v=\frac{3 + \sqrt{493}}{11}[/tex] and [tex]v=\frac{3 - \sqrt{493}}{11}[/tex]

Step 6: We only pick the first result since it's the positive result. We don't take the second one because a negative result represents the kayak moving in the opposite direction which is not how the situation was modeled.

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Answer:

f=x−32

Step-by-step explanation:

Subtract 3232 from both sides.

Answer:

f=32.2m

Step-by-step explanation:

got it right on edge

Answer:

[tex]{ \tt{ \cos(A) = \frac{ \sqrt{700} }{40} }} \\ { \tt{ \cos(A) = 0.66 }}[/tex]

Answer:

Luis’s, because he flipped the inequality sign when he subtracted

Step-by-step explanation:

7.2b + 6.5 > 4.8b – 8.1.

Amelia started by subtracting 7.2b from both sides to get

6.5 > –2.4b – 8.1

Correct

Luis started by subtracting 4.8b from both sides to get

2.4b + 6.5 < – 8.1

Incorrect

Shauna started by subtracting 6.5 from both sides to get

7.2b > 4.8b – 14.6

Correct

Clarence started by adding 8.1 to both sides to get

7.2b + 14.6 > 4.8b

Correct

Luis’s is incorrect because he flipped the inequality sign when he subtracted

Answer:

93600

Step-by-step explanation:

24=3*2*2*2

y=0,8

1) x3600, then x=9,6,3

2)x3608, then x=1,4,7

9 is the largest so the final answer is 93600

Answer:

[tex]\frac{1}{12}[/tex]

Step-by-step explanation:

A full circle consists of 360°, so we can write the fraction of this arc as [tex]\frac{30}{360}[/tex], which can be simplified to [tex]\frac{1}{12}[/tex] by dividing the numerator and denominator by 30.

**This content involves simplifying fractions and knowledge on the angle sum of a circle which you may wish to revise. I'm always happy to help!