The y-intercept of the function is given as (0, -4). This also shows that the value of y missing from the coordinate is -4
How to find the y-intercept of a function?The y-intercept of a function is the point where the value of x is zero. Given the function below;
4x-9y=36
when the value of x is zero, hence;
4(0) - 9y = 36
Simplify to have:
0 - 9y = 36
-9y = 36
Divide both sides by -9 to have:
-9y/-9 = 36/-9
y = -4
Hence the y-intercept of the function is given as (0, -4). This also shows that the value of y missing from the coordinate is -4
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Let g be a one-to-one function and suppose f is the inverse function of g
if g(5)=11 and g(3)=5, find f(5)
Answer:
So g(6) comes out to be 2.
Step-by-step explanation:
So f(6)=5 means when f acts on 6, the result is 5....so the inverse would take 5 back to 6...or g(5)=6
So f(2)=6 means that f reassigns 2 to 6....so the inverse would take 6 back to 2....or g(6)=2
hope this helps :)
Answer: 3
Step-by-step explanation:
If f(x) = y, then invf(y) = x
So, f(5) = invg(5) = 3
If $6,000 principal plus $132.90 of simple interest was withdrawn on August 14, 2011, from an investment earning 5.5% interest, on what day was the money invested?
[tex]~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill & \$132.90\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 5.5\%\to \frac{5.5}{100}\dotfill &0.055\\ t=years \end{cases} \\\\\\ 132.90 = (6000)(0.055)(t)\implies \cfrac{132.90}{(6000)(0.055)}=t\implies \cfrac{443}{1100}=t \\\\\\ \stackrel{\textit{converting that to days}}{\cfrac{443}{1100}\cdot 365} ~~ \approx ~~ 147~days[/tex]
now, if we move back from August 14th by 147 days backwards, that'd put us on March 20th.
MR MARK MARKS HIS CLASS ON A NORMAL CURVE. THOSE WITH z-SCORES ABOVE 1.8 WILL RECEIVE AN A, THOSE
BETWEEN 1.8 AND 1.1 WILL RECEIVE A B, THOSE BETWEEN 1.1 AND -1.2 WILL
RECEIVE A C, THOSE BETWEEN -1.2 AND -1.9 WILL RECEIVE A D, AND THOSE
UNDER -1.9 WILL RECEIVE AN F.
FIND THE PERCENT OF GRADES THAT WILL BE
A, B, C, D, AND F.
Using the normal distribution, it is found that the percentages are given as follows:
3.59% of the grades will be A.9.98% of the grades will be B.74.92% of the grades will be C.8.64% of the grades will be D.2.87% of the grades will be F.Normal Probability DistributionThe z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.The prorportion of students who receive an A is one subtracted by the p-value of Z = 1.8.
Looking at the z-table, Z = 1.8 has a p-value of 0.9641.
1 - 0.9641 = 0.0359.
3.59% of the grades will be A.
For B, it is the p-value of Z = 1.8 subtracted by the p-value of Z = 1.1, hence:
0.9641 - 0.8643 = 0.0998.
9.98% of the grades will be B.
For C, it is the p-value of Z = 1.1 subtracted by the p-value of Z = -1.2, hence:
0.8643 - 0.1151 = 0.7492.
74.92% of the grades will be C.
For D, it is the p-value of Z = -1.2 subtracted by the p-value of Z = -1.9, hence:
0.1151 - 0.0287 = 0.0864.
8.64% of the grades will be D.
For F, it is the p-value of Z = -1.9, hence 2.87% of the grades will be F.
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If a certain train fare costs $5.00 for the first
10 miles of service, $0.25 per mile for the next
40 miles, and $0.10 per mile for each additional
mile, what would the train fare be to travel a
total distance of 100 miles?
Answer:
$20
Step-by-step explanation:
$5.00 = 10miles
$0.25(40) = 40 miles
Remaining miles: 100 - (10 + 40) = 50
0.10(50) = 50 miles
5.00 + 0.25(40) + 0.10(50)
5.00 + 10.00 + 5.00
$20.00 for 100 miles
Question 10 of 25
Which pair of functions are inverses of each other?
[tex]f(x) = \sqrt[3]{11x} \\ y = \sqrt[3]{11x} \\ x = \sqrt[3]{11y} \\ x {}^{3} = 11y \\ y = \frac{x {}^{3} }{11} [/tex]
Option A eliminated[tex]f(x) = \frac{x}{7} + 10 \\ y = \frac{x}{7} + 10 \\ x = \frac{y}{7} + 10 \\ x - 10 = \frac{y}{7} \\ y = \frac{x - 10}{7} [/tex]
Option B eliminated[tex]f(x) = \frac{7}{x} - 2 \\ y = \frac{7}{x} - 2 \\ x = \frac{7}{y} + 2 \\ x - 2 = \frac{7}{y} \\ y = \frac{7}{x - 2} [/tex]
Option C eliminatedBy elimination it's DConfirmation:[tex]f(x) = 9x - 6 \\ y = 9x - 6 \\ x = 9y - 6 \\ x + 6 = 9y \\ y = \frac{x + 6}{9} = g(x)[/tex]
Prove Sin(90-A)=cosA
Step-by-step explanation:
sin(90-A) = sin90cosA-sinAcos90
= cosA*1-0*sinA
= cos90
hence proved
Step-by-step explanation:
sin(90-A)=cosA
sin(90-A)=sin(90-A)
90-A=90-A
-A+A=90-90
=0
1. A foot contains 12 inches. 5 inches is what fraction of a foot?
Answer:
5/12
Step-by-step explanation:
a foot =12 inches
fraction of 5 inches=5/12
What is the answer (X^2)(X)(4)
Answer:
Simplified: 4X^3
Step-by-step explanation:
Simplify the expression.
Which of the following linear equations corresponds to the table above?
OA. y=4x-3
OB. y=¹/4x-3
OC. y=¹/4x+3
OD.
y = 4x + 3
[tex]given \: that \: its \: linear \\ m = \frac{15 - 3}{3 - 0} = \frac{12}{3} = 4 [/tex]
[tex]b = y(0) = 3 \\ y = 4x + 3 \: [/tex]
Option DAnswer:
D) y = 4x + 3
Step-by-step explanation:
Equation of line in slope y-intercept form:[tex]\sf \boxed{\bf y = mx +b}[/tex]
Here, m is the slope and b is y intercept.
At y intercept, x = 0
From the table, y intercept = 3
Choose any two points from the table to find the slope.
(0 ,3) & (3,15)
[tex]\sf \boxed{\bf Slope =\dfrac{y_2-y_1}{x_2-x_1}}[/tex]
[tex]\sf =\dfrac{15-3}{3-0}\\\\=\dfrac{12}{3}\\\\=4[/tex]
m = 4 ; b = 3
Equation of line:
y = 4x + 3
Please help me solve the problem in the image. I found that a=-65 and b=17 and when I plug it in the equation it’s wrong
Answer:
-181 - 79x
Step-by-step explanation:
I am not sure your comment fits the given problem.
I get the following approach and solution :
T(1 + 4x) = 1×a + 4x×b = 2 + 2x
a = 2 + 2x - 4xb
T(4 + 15x) = 4×a + 15x×b = -3 + 3x
4×(2 + 2x - 4xb) + 15xb = -3 + 3x
8 + 8x - 16xb + 15xb = -3 + 3x
11 + 5x - xb = 0
11 + 5x = xb
b = (11 + 5x)/x
a = 2 + 2x - 4x(11 + 5x)/x = 2 + 2x - 44 - 20x = -42 - 18x
T(3 - 5x) = 3×a - 5xb = 3(-42 - 18x) - 5x(11 + 5x)/x =
= -126 - 54x - 55 - 25x = -181 - 79x
control :
T(1 + 4x) = a + 4xb = -42 - 18x + 44 + 20x = 2 + 2x
T(4 + 15x) = 4a + 15xb = -168 - 72x + 165 + 75x = -3 + 3x
A polynomial f (x) has the
given zeros of 6, -1, and -3.
Part A: Using the
Factor Theorem, determine the
polynomial f (x) in expanded form. Show all necessary
calculations.
*
Part B: Divide the polynomial f (x) by (x2 - x - 2) to
create a rational function g(x) in simplest factored form.
Determine g(x) and find its slant asymptote.
Part C: List all locations and types of discontinuities of
the function g(x).
a) The polynomial f(x) in expanded form is f(x) = x³ + 10 · x² - 20 · x - 24.
b) The rational function g(x) in factored form is g(x) = [(x - 6) · (x + 3)] / (x - 2). there is no slant asymptotes.
c) There is one evitable discontinuity at x = - 1, and one definitive discontinuity at x = 2, where there is a vertical asymptote.
How to analyze polynomial and rational functions
a) In the first part of this question we need to determine the equation of a polynomial in expanded form, derived from its factor form defined below:
f(x) = Π (x - rₐ), for a ∈ {1, 2, 3, 4, ..., n} (1)
Where rₐ is the a-th root of the polynomial.
If we know that r₁ = 6, r₂ = - 1 and r₃ = - 3, then the polynomial in factor form is:
f(x) = (x - 6) · (x + 1) · (x + 3)
f(x) = (x - 6) · (x² + 4 · x + 4)
f(x) = (x - 6) · x² + (x - 6) · (4 · x) + (x - 6) · 4
f(x) = x³ - 6 · x² + 4 · x² - 24 · x + 4 · x - 24
f(x) = x³ + 10 · x² - 20 · x - 24
The polynomial f(x) in expanded form is f(x) = x³ + 10 · x² - 20 · x - 24.
b) The rational function is introduced below:
g(x) = (x³ + 10 · x² - 20 · x - 24) / (x² - x - 2)
g(x) = [(x - 6) · (x + 1) · (x + 3)] / [(x - 2) · (x + 1)]
g(x) = [(x - 6) · (x + 3)] / (x - 2)
The slope of the slant asymptote is:
m = lim [g(x) / x] for x → ± ∞
m = [(x - 6) · (x + 3)] / [x · (x - 2)]
m = 1
And the intercept of the slant asymptote is:
n = lim [g(x) - m · x] for x → ± ∞
n = Non-existent
Hence, there is no slant asymptotes.
c) There is vertical asymptote at a x-point if the denominator is equal to zero. There is one evitable discontinuity at x = - 1, and one definitive discontinuity at x = 2, where there is a vertical asymptote.
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Use identities to find the values of the sine and cosine functions for the following angle measure.
θ, given that cos 20 =12/13 and θ terminates in quadrant I. Find sin θ and cos θ. Can you explain how do it and what is the answer?
Using the cosine double angle formula,
[tex]\cos 2\theta=2\cos^2 \theta-1=\frac{12}{13}\\\\2\cos^{2} \theta=\frac{25}{13}\\\\\cos^{2} \theta=\frac{25}{26}\\\\\boxed{\cos \theta=\frac{5}{\sqrt{26}}}[/tex]
(Note I took the positive case since [tex]\theta[/tex] terminates in the first quadrant)
Using the Pythagorean identity,
[tex]\sin^2 \theta+\cos^2 \theta=1\\\\\sin^2 \theta+\frac{25}{26}=1\\\\sin^2 \theta=\frac{1}{26}\\\\\boxed{\sin \theta=\frac{1}{\sqrt{26}}}[/tex]
(Note I took the positive case since [tex]\theta[/tex] terminates in the first quadrant)
if tan theta = 1/√5 then verify the identity sin²theta + cos²theta = 1
The identity of sin²Ф + cos²Ф = 1 is verified below
How to evaluate Trigonometry Ratio ?Trigonometry ratio can be evaluated by following the laid down rules with the the use of table and calculator
Given that tan Ф = 1/√5
Where Tan Ф = Opposite / adjacent
We can calculate the hypotenuse by using Pythagoras theorem
Hyp² = 1² + (√5)²
Hyp² = 1 + 5
Hyp = √6
sin Ф = opp / hyp
sin Ф = 1/√6
sin²Ф = 1/6
cos Ф = adj / hyp
cosФ = √5 / √6
cos²Ф = 5/6
sin²Ф + cos²Ф = 1/6 + 5/6
sin²Ф + cos²Ф = 6/6
sin²Ф + cos²Ф = 1
Therefore, the identity of sin²Ф + cos²Ф = 1 is verified.
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please help!!!
Using long division, what is the quotient of this expression?
3x42x³-x-4
x²+2
OA. 3x²
3x - 4
OB. 3x² + 2x + x² + 2
O C.
3x² 2x
O D.
-
2x
3x² + 2x
- 6 +
-
- 5+
-
3x + 8
x² + 2
-
3x+6
x²+2
5x8
x² + 2
Rese
Check the picture below.
notice, the dividend and divisor must be in descending order, and when one of the variables is "missing", is really not missing, it simply has a coefficient of 0.
Here is the solution process:
3 x² - 2 x - 6
x² + 0x + 2 | 3 x⁴ - 2 x³ + 0 x² - x - 4
3 x⁴ + 0 x³ + 6 x²
- 2 x³ - 6 x² - x - 4
- 2 x³ + 0 x² - 4 x
- 6 x² + 3 x - 4
- 6 x² + 0 x - 12
3 x + 8
Long division:
Standard: [tex]\sf{3x^{2} -2x-6+\dfrac{3x+8}{x^{2} +2} \ \ \to \ \ \ Option \ "A" }[/tex]Quotient: 3x² - 2x - 6Rest: 8 + 3xTherefore, the correct option is "A".
A rectangular table is six times as long as it is wide. If the area is 150 ft2, find the length and the width of the table.
The width of the table is
The length of the table is?
Answer:
Length = 30ft, Width = 5ft
Step-by-step explanation:
Let x be the width.
Area of Rectangle = Length * Width
Given from the information in the question,
Length = 6x ft
Width = x ft
Substitute the values into the formula:
6x * x = 150
[tex]6x^{2}[/tex] = 150
[tex]x^{2} =\frac{150}{6}[/tex]
[tex]x^{2} =25[/tex]
[tex]x=\sqrt{25}[/tex]
x = 5 ft.
Therefore,
Length = 6 * 5 = 30ft
Width = 5 ft.
please help me figure this out
Answer:
-25
Step-by-step explanation:
[tex] \dfrac{(20 - 5^2)(16 + 2^2)}{-2^3 + (3 \times 2^2)} = [/tex]
First, do all exponents.
[tex] = \dfrac{(20 - 25)(16 + 4)}{-8 + (3 \times 4)} [/tex]
Now do each operation in parentheses.
[tex] = \dfrac{(-5)(20)}{-8 + 12} [/tex]
Multiply in the numerator. Add in the denominator.
[tex] = \dfrac{-100}{4} [/tex]
Divide the numerator by the denominator.
[tex] = -25 [/tex]
Answer:
-25
Step-by-step explanation:
PEMDAS
The PEMDAS rule is an acronym representing the order of operations in math:
ParenthesesExponentsMultiplication and Division (from left to right)Addition and Subtraction (from left to right)Given expression:
[tex]\sf \dfrac{(20-5^2)(16+2^2)}{-2^3+(3 \times 2^2)}[/tex]
As the given expression is a fraction, carry out the operations in the numerator and denominator first before finally dividing them.
Following PEMDAS, carry out the calculations inside the parentheses first, then carry out the rest of the calculations following the order of operations:
Parentheses
Calculate the exponents inside the parentheses:
[tex]\implies \sf \dfrac{(20-25)(16+4)}{-2^3+(3 \times 4)}[/tex]
Multiply:
[tex]\implies \sf \dfrac{(20-25)(16+4)}{-2^3+(12)}[/tex]
Add and subtract:
[tex]\implies \sf \dfrac{(-5)(20)}{-2^3+(12)}[/tex]
Exponents
Calculate the exponent:
[tex]\implies \sf \dfrac{(-5)(20)}{-8+(12)}[/tex]
Multiply and Divide
Multiply:
[tex]\implies \sf \dfrac{-100}{-8+(12)}[/tex]
Add and Subtract
Add:
[tex]\implies \sf \dfrac{-100}{4}[/tex]
Finally, divide the numerator by the denominator:
[tex]\implies \sf -25[/tex]
Line passes through the point (8,4) and a slope of 5/4. Write equation in slope-intercept
Answer:
Step-by-step explanation:
y - 4 = 5/4(x - 8)
y - 4 = 5/4x - 10
y = 5/4x - 6
Heyy i just need some help with questions 21and 25 if anyone could help me and show the work that would be amazing thank you!!
Step-by-step explanation:
21) f(x)=1/x-6. g(x)=7/x+6
f(g(x))=f(7/x+6)=1÷7/x+6 - 6=x+6/7 - 6
g(f(x))=g(1/x-6)=7÷1/x-6 - 6 =7(x-6) - 6
simplify forward
25)f(x)=|x| g(x)=5x+1
f(g(x))=f(5x+1)=|5x+1|=5x+1=g(x)
g(f(x))=g(|x|)=5|x|+1=5x+1=g(x)
This graph represents a quadratic function. An upward parabola on a coordinate plane vertex at (minus 2, 2) and passes through (minus 3, 5) and (minus 1, 5). What is the value of a in the function’s equation? A. -2 B. -3 C. 2 D. 3
Answer: 3
Step-by-step explanation:
Substituting into vertex form, the equation is
[tex]y=a(x+2)^2 +2[/tex]
Substituting in the coordinates (-3, 5),
[tex]5=a(-3+2)^2 +2\\\\5=a+2\\\\a=3[/tex]
Is 25x²-40xy+16y²a perfect square number? why?
Answer:
yes
Step-by-step explanation:
25x² - 40xy + 16y² can be factored as
(5x - 4y)² ← a perfect square
Given two independent random samples with the following results:
n1=13
x‾1=141
s1=13
n2=9
x‾2=161
s2=12
Use this data to find the 98% confidence interval for the true difference between the population means. Assume that the population variances are equal and that the two populations are normally distributed.
Step 1 of 3 : Find the point estimate that should be used in constructing the confidence interval.
Step 2 of 3: Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places.
Step 3 of 3: Construct the 98% confidence interval. Round your answers to the nearest whole number.
please explain
The point estimate of difference of the sample his will be -20.
How to illustrate the information?Based on the information given, the. following can be depicted:
n1 = 13
x1 = 141
s1 = 13
n2 = 9
x2 = 161
s2 = 12
The point estimate of difference will be:
= 141 - 161
= -20
The margin of error to be used in constructing the confidence interval will be calculated by multiplying the standard error which is 5.467 and the critical value. This will be:
= 5.467 × 2.528
= 13.822
The margin of error is 13.822.
The confidence interval will now be:
= (-20 + 13.822) and (-20 - 13.822)
= -6.178 and -33.822
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A student purchased 7 binders for a total of $8.61. Write an equation that can be used to find the cost of each binder, n, in dollars.
The equation that can be used to find the cost of each binder n in dollars is 861=7n.
Given that the cost of 7 binders is $8.61.
We are required to form an equation that represents the total cost of each binder n in dollars.
Equation is like a relationship between all the variables that are expressed in equal to form.It may be linear equation or may be more types.
Suppose the cost of 1 binder is n dollar.
We know that the total cost is basically the product of price of 1 unit and number of quantities of units.
Total cost=Price of 1 unit* number of units
8.61=n*7
8.61=7n
Hence the equation that can be used to find the cost of each binder n in dollars is 861=7n.
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X
-5
Probability 17
-3
-2 0
0 2
13 33 16 11
3
.10
Find the probability that x <-3
The value of the probability is 0.30
How to determine the probability?Using the table of values, we have:
P(x <= -3) = P(x = -5) + P(x = -3)
From the table of values, we have:
P(x = -5) = 0.17
P(x = -3) = 0.13
Substitute the known values in the above equation
P(x <= -3) = 0.17 + 0.13
Evaluate the sum
P(x <= -3) = 0.30
Hence, the value of the probability is 0.30
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Which pair of angles are vertical angles? AngleWRU and AngleSRT AngleWRS and AngleVRT AngleVRU and AngleTRS AngleVRT and AngleSRT
Step-by-step explanation:
important of festival in nepali languages for class seven
Answer:
b
Step-by-step explanation:
What is the solution to the system of equations?
y = 2/3 x + 3
X= -2
The solution to the given system of equations is x = -2, y = 5/3. That is (-2, 5/3)
Solving system of equationsFrom the question, we are to determine the solution to the given system of equations
The given system of equation is
y = 2/3 x + 3 ----------- (1)
x= -2 ----------- (2)
The value of x has been given in the second equation of the system of equations.
Now, we will determine the value of y
From the second equation, we have that
x = -2
Substitute the value of x into the first equation,
y = 2/3 x + 3
y = 2/3 (-2) + 3
y = -4/3 + 3
y = 5/3
Hence, the solution to the given system of equations is x = -2, y = 5/3. That is (-2, 5/3)
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(questions in image)
A. Which plane contains line b?
B. Name 3 Collinear Points
C. Name the plane containing point W
D. Name two points not coplanar with points T and Q
E. At which line do the planes M and N intersect
Answer:
1. Plane N
2. Points P, Q, R
3. Plane CRW …
4. Points K and H
5. Line a
The mean of a normally distributed data set is 118, and the standard deviation is 16.
a) Use the standard normal table to find the probability that a randomly-selected data value is greater than 140.
b) Use the standard normal table to find the probability that a randomly-selected data value is less than 90.
Step-by-step explanation:
a)
z = (140 - 118)/16 = 22/16 = 11/8 = 1.375 ≈ 1.38
in the z-table this gives us the p-value : 0.91621
that is the probability of values 140 and below.
for above 140 we need to calculate the value of the other side of the bell-curve :
1 - 0.91621 = 0.08379
b)
z = (90 - 118)/16 = -28/16 = -7/4 = -1.75
in the z-table this gives us the p-value : 0.04006
that is the probability of values of 90 and below.
What is the smallest odd number of using 9,3,6,8,1,9
Answer: well one is
Bc its the smallest besides zero, but zero is neither odd or even
Step-by-step explanation:
Help whats the answer and an explanation to it
Answer:
C
Step-by-step explanation:
the answer is c
Whole page of geometry stuff for 50 points only do 2,3 and 4 ( serious answers only or 1 star and report )
See below for the distance between the points and the lines
How to determine the distance between the lines and the points?Question 2
The line and the points are given as:
x = y
P = (4, -2)
Rewrite the equation as:
y = x
The slope of the above equation is
m = 1
The slope of a line perpendicular to it is
m = -1
A linear equation is represented as:
y = mx + b
Substitute m = -1
y = -x + b
Substitute (4, -2) in y = -x + b
-2 = -4 + b
Solve for b
b = 2
Substitute b = 2 in y = -x + b
y = -x + 2
So, we have:
x = y and y = -x + 2
Substitute x for y
x = -x + 2
Solve for x
x = 1
Substitute x = 1 in y = x
y = 1
So, we have the following points
(1, 1) and (4, -2)
The distance between the above points is
d = √(x2 - x1)² + (y2 - y1)²
So, we have:
d = √(1 - 4)² + (1 + 2)²
Evaluate
d = 3√2
Hence, the distance between x = y and P = (4, -2) is 3√2 units
Question 3
The line and the points are given as:
y = 2x + 1
Q = (2, 10)
The slope of the above equation is
m = 2
The slope of a line perpendicular to it is
m = -1/2
A linear equation is represented as:
y = mx + b
Substitute m = -1/2
y = -1/2x + b
Substitute (2, 10) in y = -1/2x + b
10 = -1/2 * 2 + b
Solve for b
b = 11
Substitute b = 11 in y = -1/2x + b
y = -1/2x + 11
So, we have:
y = 2x + 1 and y = -1/2x + 11
Substitute 2x + 1 for y
2x + 1 = -1/2x + 11
Solve for x
x = 4
Substitute x = 4 in y = 2x + 1
y = 9
So, we have the following points
(4, 9) and (2, 10)
The distance between the above points is
d = √(x2 - x1)² + (y2 - y1)²
So, we have:
d = √(4 - 2)² + (9 - 10)²
Evaluate
d = √5
Hence, the distance between the line and the point is √5 units
Question 4
The line and the points are given as:
y = -x + 3
R = (-5, 0)
The slope of the above equation is
m = -1
The slope of a line perpendicular to it is
m = 1
A linear equation is represented as:
y = mx + b
Substitute m = 1
y = x + b
Substitute (-5, 0) in y = x + b
0 = 5 + b
Solve for b
b = -5
Substitute b = 5 in y = x + b
y = x + 5
So, we have:
y = x + 5 and y = -x + 3
Substitute x + 5 for y
x + 5 = -x + 3
Solve for x
x = -1
Substitute x = -1 in y = x + 3
y = 2
So, we have the following points
(-1, 2) and (-5, 0)
The distance between the above points is
d = √(x2 - x1)² + (y2 - y1)²
So, we have:
d = √(-1 + 5)² + (2 - 0)²
Evaluate
d = 2√5
Hence, the distance between the line and the point is 2√5 units
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