(5) Find the interval of convergence of the power series 2.". Show your work. (2n)! (6) Find the radius and interval of convergence of the power series niti (7x-5)". Show your n=1 work.

The angle between the two planes is 113.75°.

Firstly, we find the normal vectors of each plane. The normal vector of a plane is the vector perpendicular to the plane.

The first equation can be rewritten as:

6x - 8y + 10z = 12

Note that the coefficients of x, y, and z represent the components of the normal vector.

So the normal vector of the first plane is:

N₁ = <6, -8, 10>

For the second equation, the plane can be extracted:

x + y - z = 2

N₂ = <1, 1, -1>

The angle between the two planes can be found using the dot product of the normal vectors and the formula:

cosθ = (N₁ . N₂) / (|N₁| |N₂|)

where |N| represents the magnitude of vector N.

The dot product of the normal vectors is:

N1 . N2 = (6)(1) + (-8)(1) + (10)(-1) = -12

The magnitudes of the normal vectors are:

|N1| = sqrt(6² + (-8)² + 10²) = sqrt(296) = 17.205

|N2| = sqrt(1² + 1² + (-1)²) = sqrt(3) = 1.732

Substituting these values into the formula gives:

cosθ = (N1 . N2) / (|N1| |N2|)

cosθ = -12 / (17.205 * 1.732)

cosθ = -12/29.799

cosθ = -0.4027

The angle θ can be found using the inverse cosine function:

θ = cos⁻¹(0.4027)

θ ≈ 113.75°

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The value of T(1) by taking cross product r'(t) x r"(t) = [tex](-144(1)^2, 0, 24)[/tex] = (-144, 0, 24).

To find the derivative of r(t), we can differentiate each term separately with respect to t:

r(t) = [tex](4t, 3t^2, 4t^3)[/tex]

r'(t) = [tex](d/dt)(4t, 3t^2, 4t^3) = (4, 6t, 12t^2)[/tex]

To find r"(t), we can differentiate r'(t) with respect to t:

r"(t) = [tex](d/dt)(4, 6t, 12t^2)[/tex] = (0, 6, 24t)

To find r'(1), we can substitute t = 1 into r'(t):

r'(1) = [tex](4, 6(1), 12(1)^2)[/tex] = (4, 6, 12)

To find r′(t) x r″(t), we can take the cross product of r'(t) and r"(t):

r'(t) x r"(t) = [tex](4, 6t, 12t^2) * (0, 6, 24t) = (-144t^2, 0, 24)[/tex]

Finally, we can substitute the values we found into the last equation to find T(1):

T(1) = r'(t) x r"(t) = [tex](-144(1)^2, 0, 24) = (-144, 0, 24)[/tex]

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If the sum of the two digits of a positive integer is 12. when the digits were reversed, the new number was 54 greater than the original number is 66.

Let the two digits of the original number be x and y, where x is the tens digit and y is the units digit. We are given two pieces of information:

1. The sum of the two digits is 12: x + y = 12
2. When the digits are reversed, the new number is 54 greater than the original number: 10y + x = 10x + y + 54

Now we can solve the system of equations:

First, isolate y in the first equation: y = 12 - x
Next, substitute this expression for y into the second equation: 10(12 - x) + x = 10x + (12 - x) + 54
Simplify the equation: 120 - 10x + x = 10x + 12 - x + 54
Combine like terms: 108 - 9x = 9x
Divide by 9: 12 = x + x
Solve for x: x = 6

Now substitute x back into the equation for y: y = 12 - 6 = 6

The original number is 66.

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The correct answer to the multiple-choice question is B) 0.2294. To answer this question, we need to use the properties of the normal distribution.

We know that the distribution of scores is normal with a mean of 560 and a standard deviation of 90. We want to find the percentage of examinees who score between 600 and 700.

To do this, we first need to standardize the scores using the formula z = (x - μ) / σ, where x is the score, μ is the mean, and σ is the standard deviation. For a score of 600, the standardized score is z = (600 - 560) / 90 = 0.44. For a score of 700, the standardized score is z = (700 - 560) / 90 = 1.56.

Next, we look up the percentage of examinees who score between these two standardized scores using a standard normal distribution table or a calculator. The percentage of examinees who score between 0.44 and 1.56 is approximately 0.2294 or 22.94%.

Therefore, the correct answer to the multiple-choice question is B) 0.2294.

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Answer:

see below

Step-by-step explanation:

The net 25% rule states that no more than 25% of your post-tax income should go toward housing costs.

so her post tax income = 60000* (1-27%) = 43800

every month = 43800/12 = 3650

25% of that = 912.5

She can rent a 2BR apt for 880, it's below 25% of her after tax income of 912.5

Therefore, the constant of variation is 0.04.

The equation P = kS represents direct variation, where P and S are two quantities that are directly proportional to each other. This means that as the value of S increases, the value of P also increases proportionally.

In this case, we are given that the price of a package of stickers containing 650 stickers is $26.00. By substituting these values into the equation, we can solve for the constant of variation k.

So, we have:

P = kS

$26.00 = k(650)

Solving for k, we can divide both sides by 650:

k = $26.00 / 650

k = $0.04

Therefore, the constant of variation k is $0.04. This means that for every additional sticker in the package, the price will increase by $0.04.

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The limit is found to  diverge to negative infinity and if we can out the divergence test, we find out that the given series diverges.

The simplest divergence test also known as  the divergence Test, is used to determine whether the sum of a series diverges based on the series's end-behavior.

In the scenario above,  we will compare the given series with the series 1/n^2, which is a known convergent series.

we take  the limit as n approaches infinity of the ratio of the two series, we get:

lim (n^2(6n^3-4))/(1(n^2))

= lim (6n^5 - 4n^2)/(n^2)

= lim 6n^3 - 4 = infinity

We remember that the divergence test states that if the limit of the terms of a series does not approach zero, then the series diverges.

we also go ahead to take the limit as n approaches infinity of the ratio of the given series, we get:

lim (n^2(6n^3-4))/(n^3) = lim 6n - 4/n = infinity

In conclusion, the limit is found to  diverge to negative infinity and if we can out the divergence test, we find out that the given series diverges.

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The solution to the initial value problem dy/dФ + y = sin Ф is: y = (-cos Ф + 2)/e^Ф.

To solve the initial value problem dy/dФ + y = sin Ф, we first need to find the integrating factor, which is given by e^Ф. Multiplying both sides by the integrating factor, we get:

e^Ф(dy/dФ) + e^Фy = e^Фsin Ф

Now, we can use the product rule to simplify the left-hand side:

(d/dФ)(e^Фy) = e^Фsin Ф

Integrating both sides with respect to Ф, we get:

e^Фy = -cos Ф + C

where C is a constant of integration. Solving for y, we get:

y = (-cos Ф + C)/e^Ф

To find the value of C, we use the initial condition y(0) = 1. Substituting this into the equation above, we get:

1 = (-cos 0 + C)/e^0
1 = (-1 + C)/1
C = 2

Therefore, the solution to the initial value problem dy/dФ + y = sin Ф is:

y = (-cos Ф + 2)/e^Ф

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If P is any point inside triangle ABC, then

PA + PB + PC > (AB + BC + CA)/2

It is given that P is any point inside the triangle ABC. So after taking a point P inside the triangle ABC, we will join P with the vertices of the triangle which are A, B, and C. So, now we have formed three sides which are PA, PB, and PC as shown in the figure.

Now, we can see that we have three more triangles formed inside the triangle ABC. These triangles are PAB, PAC, and PBC. As we know the sum of the two sides of a triangle is always greater than the third side. We will apply this property in these three triangles.

In △PBA, AB < PA+PB        (1)

In △PBC, BC < PB+PC       (2)

In △PCA, AC < PC+PA       (3)

Adding (1), (2), and (3), we get

AB + BC + AC  <   PA + PB + PB + PC + PC + PA

AB + BC + AC  <   2PA + 2PB + 2PC

AB + BC + AC  <   2(PA + PB + PC)

(PA + PB + PC)  >   (AB + BC + AC)/2

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The limit of [tex](2x^2-y^2)^{11}/(x^2+2y^2)[/tex] as (x,y) approaches (0,0) is path-dependent and does not exist. The paths y=mx and x=my are used to demonstrate this. The expression approaches a value that depends on the constant m and the chosen path.

To show that the limit does not exist, we need to find two paths to the origin along which the limit has different values. Consider the path y = mx, where m is a constant. As (x,y) approaches (0,0) along this path, we have:

[tex](2x^2 - y^2)^{(11)} / (x^2 + 2y^2)[/tex]

[tex]= (2x^2 - (mx)^2)^{(11)} / (x^2 + 2(mx)^2)[/tex]

[tex]= (2 - m^2)^{11} / (1 + 2m^2)[/tex]

As x approaches 0, this expression approaches [tex](2 - m^2)^{11} / (2m^2)[/tex], which depends on the value of m. Thus, the limit depends on the path chosen, and so the limit does not exist.

Similarly, we can consider the path x = my, where m is a constant, and obtain:

[tex](2x^2 - y^2)^{(11)} / (x^2 + 2y^2)[/tex]

[tex]= (2(my)^2 - y^2)^{(11)} / (m^2y^2 + 2y^2)[/tex]

[tex]= (2m^2 - 1)^{11} / (m^2 + 2)[/tex]

As y approaches 0, this expression approaches[tex](2m^2 - 1)^{11} / 2m^2[/tex], which again depends on the value of m. Therefore, the limit does not exist.

In summary, we showed that the limit of[tex](2x^2-y^2)^{11}/(x^2+2y^2)[/tex] as (x,y) approaches (0,0) does not exist, by considering two different paths to the origin and showing that the limit depends on the value of the parameter in each case.

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Answer:

Step-by-step explanation:      Observational cross-sectional

Answer:

Yes, we can still find the median. You just need to convert the rest to the given data / kilograms and you have to just do the steps of finding the median.

The area of the property, enclosed by the right triangle, is approximately 46.30 acres.

To find the area of the property, we can divide it into two shapes: a right triangle and a rectangle. The stream frontage of 600 feet forms the base of the right triangle, and the property line of 3500 feet forms the hypotenuse.

Using the Pythagorean theorem, we can find the length of the remaining side of the right triangle (the height) as follows:

height = √(3500^2 - 600^2)

height ≈ 3356 feet (rounded to the nearest whole number)

The area of the right triangle is given by:

triangle area = (base * height) / 2

triangle area = (600 * 3356) / 2

triangle area ≈ 1,005,600 square feet (rounded to the nearest whole number)

The area of the rectangle is simply the product of its length and width:

rectangle area = 600 feet * 3356 feet

rectangle area ≈ 2,013,600 square feet (rounded to the nearest whole number)

To convert the area from square feet to acres, we divide by 43,560 (the number of square feet in an acre):

lot area = (triangle area + rectangle area) / 43,560

lot area ≈ (1,005,600 + 2,013,600) / 43,560

lot area ≈ 46.30 acres (rounded to the nearest hundredth)

Therefore, the area of the property, enclosed by the right triangle, is approximately 46.30 acres.

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The height of the can in inches is,

⇒ h = 6.37 inches

Since, We know that;

Volume of the can ground coffee = πr²h

where,

r = radius

h = height of the cylinder

Therefore, We get;

r = 1/2 inches

V = 5 cubic inches

Hence, We get;

Volume of the can ground coffee = 3.14 × (1/2)² × h

5 = 3.14 × 1/4 × h

20/3.14 = h

h = 6.37 inches

Hence, The height of the can in inches is,

⇒ h = 6.37 inches

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The price difference between buying 12 cookies individually and buying them by the dozen is $0.40

Note that from the question, the price of Cookies A is $0.20 for each cookie, so to buy 12 cookies solely, Thus Trisha would need to pay:

12 * $0.20

= $2.40

Since price of Cookies A is $2.00 per dozen, to buy 12 cookies by the dozen, Trisha will pay:

1 * $2.00

= $2.00

Hence the difference in price of buying 12 cookies solely and buying by the dozen is:

$2.40 - $2.00

= $0.40

Therefore, the price is $0.40 cheaper for Trisha to buy 12 cookies by the dozen than to buy them individually.

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The normal component of the acceleration vector (a_n) is a_n = √(|a(t)|^2 - a_t^2).

To find the tangential and normal components of the acceleration vector for the given position vector r(t) = 7e^t*i + 7√2^t*j + 7e^(-t)*k, follow these steps:

1. Differentiate the position vector r(t) to find the velocity vector v(t):

v(t) = dr(t)/dt = (7e^t)*i + (7√2^t * ln(√2))*j - (7e^(-t))*k

2. Differentiate the velocity vector v(t) to find the acceleration vector a(t):

a(t) = dv(t)/dt = (7e^t)*i + (7√2^t * ln^2(√2))*j + (7e^(-t))*k

3. Calculate the magnitude of the velocity vector |v(t)|:

|v(t)| = √((7e^t)^2 + (7√2^t * ln(√2))^2 + (7e^(-t))^2)

4. Find the tangential component of the acceleration vector (a_t):

a_t = (a(t) • v(t)) / |v(t)|

Here, '•' denotes the dot product.

5. Find the normal component of the acceleration vector (a_n):

a_n = √(|a(t)|^2 - a_t^2)

By following these steps, you can find the tangential and normal components of the acceleration vector for the given position vector r(t).

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To calculate the probability that it will take more than X minutes for all the customers currently in line to check out, we would need to know the total number of customers in line. If we have that information, we can use probability theory to calculate the likelihood of the scenario you describe.

To answer your question, we need to know the number of customers currently in line and the average number of minutes each customer takes to check out:

1)Let's represent the number of customers as "N" and the average minutes per customer as "M".

2)We want to calculate the probability that it will take more than "X" minutes for all the customers in line to check out.

3) We can find this by first determining the total time needed for all customers to check out, which is N multiplied by M (N*M). Then, we need to find the probability that the total time taken is greater than X minutes.

Probability = (Total time taken > X minutes) / (All possible time outcomes)

Since we don't have specific values for N, M, or X, we cannot provide an exact probability. Please provide the necessary information, and we'll be happy to help you with the calculation.

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The length of diagonal is 8√6 cm.

We have,

Sides of Square = 8√3 cm

Then, the length of diagonal

= a√2

= 8√3 x √2

= 8√6 cm

Thus, the length of diagonal is 8√6 cm.

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The lengths of the diagonals are approximately 10.6 cm and 31.8 cm.

To solve this problem, we can use the formula for the area of a rhombus, which is A = (d₁ x d₂)/2, where A is the area, and d₁ and d₂ are the lengths of the diagonals.

We are given that the area of the rhombus is 168 square centimeters, so we can substitute this value into the formula:

=> 168 = (d₁ x d₂)/2.

We are also given that one diagonal is three times as long as the other, so we can express the length of one diagonal in terms of the other: d₁ = 3d₂.

Substituting this expression for d₁ into the formula for the area, we get:

168 = (3d₂xd₂)/2 336 = 3d₂²2 d₂² = 112 d₂ = √(112) = 10.6 (to the nearest tenth of a centimeter)

Using the expression for d₁ in terms of d₂, we can find the length of the other diagonal:

d₁ = 3d₂ = 3(10.6) = 31.8 (to the nearest tenth of a centimeter)

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(a) For p(x) = c(ſ)^x, x = 1, 2, 3, ..., the value of the constant c, such that p(x) satisfies the condition of being a probability mass function (pmf) of one random variable X is : (ſ - 1)/ſ.

(b) For p(x) = cm, x = 1, 2, 3, 4, 5, 6, and zero elsewhere, the value of the constant c, such that p(x) satisfies the condition of being a probability mass function (pmf) of one random variable X is :  1/21.

(a) For p(x) = c(ſ)^x, x = 1, 2, 3, ..., and zero elsewhere, we need to ensure that the sum of all probabilities equals 1. Since the function is defined for positive integers, we can use the geometric series formula:

Σ(c(ſ)^x) = 1, where x ranges from 1 to infinity.

c * (ſ/(ſ - 1)) = 1 (geometric series formula)

To find c, we simply rearrange the equation:

c = (ſ - 1)/ſ

So for this pmf, the constant c is (ſ - 1)/ſ.

(b) For p(x) = cm, x = 1, 2, 3, 4, 5, 6, and zero elsewhere, we again need the sum of all probabilities to equal 1:

Σ(cm) = 1, where x ranges from 1 to 6.

c * (1 + 2 + 3 + 4 + 5 + 6) = 1

c * 21 = 1

To find c, we rearrange the equation:

c = 1/21

So for this pmf, the constant c is 1/21.

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To evaluate the derivative of the given function for the given value of x, we will use the power rule of differentiation. The function given is: y = √x(1-x)

Step 1: Rewrite the function using the product rule: y = (√x)(1-x)

Step 2: Apply the power rule of differentiation to the first factor, √x:

y' = [(1/2)x^(-1/2)](1-x) + (√x)(-1)

Step 3: Simplify by combining like terms:

y' = [(1-x)/2√x] - √x

Step 4: Plug in x = 4 to find the derivative at that specific value:

y' = [(1-4)/2√4] - √4

y' = [-3/4] - 2

y' = -2.75

Therefore, the derivative of the given function for the given value of x=4 is -2.75. I believe you meant to ask for the derivative of the function y = √x - x, evaluated at x = 4. Here are the steps to find the derivative and evaluate it:

1. Write down the given function: y = √x - x

2. Rewrite the function using exponents: y = x^(1/2) - x

3. Apply the power rule to find the derivative: dy/dx = (1/2)x^(-1/2) - 1

4. Simplify the derivative: dy/dx = (1/2)(x^(-1/2)) - 1

5. Evaluate the derivative at x = 4: dy/dx = (1/2)(4^(-1/2)) - 1

6. Calculate the values: dy/dx = (1/2)(1/2) - 1

7. Simplify the final answer: dy/dx = 1/4 - 1 = -3/4

So, the derivative of the given function at x = 4 is -3/4.

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The partial derivatives of f with respect to r, s, and t are: ∂f/∂r = y + 0.06tx + 0.02t, ∂f/∂s = y + 0.02s and ∂f/∂t = y + 0.06rx - 0.14x + 0.02r.

To compute the partial derivatives of f(x,y,z) with respect to r, s, and t, we will use the chain rule.

∂f/∂r = ∂f/∂x * ∂x/∂r + ∂f/∂y * ∂y/∂r + ∂f/∂z * ∂z/∂r

∂f/∂s = ∂f/∂x * ∂x/∂s + ∂f/∂y * ∂y/∂s + ∂f/∂z * ∂z/∂s

∂f/∂t = ∂f/∂x * ∂x/∂t + ∂f/∂y * ∂y/∂t + ∂f/∂z * ∂z/∂t

First, we calculate the partial derivatives of the component functions with respect to r, s, and t:

∂x/∂r = 1, ∂x/∂s = 1, ∂x/∂t = -7

∂y/∂r = 3t, ∂y/∂s = 0, ∂y/∂t = 3r

∂z/∂r = t, ∂z/∂s = s, ∂z/∂t = 0

Then, we compute the partial derivatives of f with respect to x, y, and z:

∂f/∂x = y, ∂f/∂y = x, ∂f/∂z = 2%

Finally, we substitute all the partial derivatives into the chain rule formula to obtain:

∂f/∂r = y + 3tx(2%) + 2%(t)

∂f/∂s = y + 2%(s)

∂f/∂t = y + 3rx(2%) - 7x(2%) + 2%(r)

Therefore, the partial derivatives of f with respect to r, s, and t are:

∂f/∂r = y + 0.06tx + 0.02t

∂f/∂s = y + 0.02s

∂f/∂t = y + 0.06rx - 0.14x + 0.02r

where 2% is written as 0.02 for simplicity.

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The expected number of wives who are seated next to their husbands is 1.

To find the expected number of wives who are seated next to their husbands, we can use the linearity of expectation. Let X be a random variable that takes the value 1 if the i-th wife is seated next to her husband, and 0 otherwise. Then the total number of wives seated next to their husbands is [tex]X = X_1 + X_2 + ... + X_{19}.[/tex]

Now, let's consider the probability that a particular wife is seated next to her husband. There are 38 seats at the table (19 couples), and the wife can either sit to the left or right of her husband. So the probability that she is seated next to her husband is 2/38 = 1/19.

Using linearity of expectation, we have:

[tex]E[X] = E[X_1 + X_2 + ... + X_1] = E[X_1] + E[X_2] + ... + E[X_{19}] = 19 * (1/19)=1[/tex]

Therefore, the expected number of wives who are seated next to their husbands is 1.

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If a case of paper contains 16 packages of paper, and each package contains 500 sheets, 8,000 sheets of paper are in a case

In the given question, the number of sheets in one package is given and to calculate the number of sheets in 16 packages of paper we have to find the product of the number of sheets and the number of packages.

Number of sheets in 1 package = 500

Number of sheets in 16 packages = 500 * 16

= 8,000

Thus the number of sheets in a case of paper containing 16 packages of paper is 8,000

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The highest free throw of 82% has an average bowling score of 108

This ordered pair represents the ordered pair of the highest x value in the graph

From the graph, the ordered pair is (82, 108)

It means that the student with the highest free throw of 82% has an average bowling score of 108

This ordered pair represents the ordered pair of the highest y value in the graph

From the graph, the ordered pair is (80, 112)

It means that the student with the highest free throw of 80% has an average bowling score of 112

From the graph, we can see that the association is a positive linear association

This is because as the free throw percents increases, the average bowling score is also expected to increase

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Complete question

The members of a school basketball team went bowling for a season ending party. They made this scatter plot to compare their free throw percents for the season and their average bowling score for 3 games.

Part A:

What ordered pair represents the student with the highest free throw percent? Explain the meaning of each coordinate in the ordered pair.

Part B:

What ordered pair represents the student with the highest bowling average? Explain the meaning of each coordinate in the ordered pair.

Part C:

Is the association between free throw percent and bowling average linear or nonlinear? If it is linear, is the relationship positive, negative, or neither? State the association, if any, in terms of the variables.

To solve this problem, we will use the concept of combinations. Combinations are used to find the number of ways to choose a certain number of items from a larger set without considering the order. In this case, we want to find the number of ways to choose 5 dishes out of 15 available main dishes.

The formula for combinations is:
C(n, k) = n! / (k! * (n-k)!)

Where C(n, k) is the number of combinations, n is the total number of items (15 dishes), and k is the number of items to choose (5 dishes).

Plugging in the values, we get:

C(15, 5) = 15! / (5! * (15-5)!)

Now, let's calculate the factorials:

15! = 1,307,674,368,000
5! = 120
10! = 3,628,800

Now, divide as the formula states:

C(15, 5) = 1,307,674,368,000 / (120 * 3,628,800) = 3,003

So, there are 3,003 different possible meals for the group to share at the restaurant.

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The weight of the heaviest 18% of fruits is 371.7 grams, and we can use deviation and the normal distribution curve to find this answer.

To answer this question, we need to use the concept of deviation and the normal distribution curve. We know that the mean weight of the fruit is 346 grams, and the standard deviation is 30 grams.

Since we want to find out the weight of the heaviest 18% of fruits, we need to look at the right side of the normal distribution curve. We know that 50% of the fruits will be below the mean weight of 346 grams, and 50% will be above it.

We can use a Z-score table to find out the Z-score corresponding to the 82nd percentile (100% - 18%). The Z-score is 0.89.

Now we can use the formula Z = (X - mean) / standard deviation to find out the weight of the heaviest 18% of fruits. Rearranging the formula, we get X = (Z * standard deviation) + mean.

Plugging in the values, we get X = (0.89 * 30) + 346 = 371.7 grams. Rounded to the nearest gram, the heaviest 18% of fruits weigh more than 372 grams.

In conclusion, the weight of the heaviest 18% of fruits is 371.7 grams, and we can use deviation and the normal distribution curve to find this answer.

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1. The solution for the first differential equation is y = -8 + 64x

2.The solution for the second differential equation is y = 7x - 7 + 70e^(-x)

1.For the first differential equation, we have:

x^y' = xy - 8 ln x

Taking the natural logarithm of both sides, we get:

ln(x^y') = ln(xy) - ln(x^8)

Using the properties of logarithms, we can simplify this to:

y' ln(x) = ln(xy) - 8 ln(x)

y' ln(x) = ln(x^y) - ln(x^8)

y' ln(x) = ln(x^(y-8))

y' = (y - 8) / x

This is now in the form y' + P(x)y = Q(x), where P(x) = -1/x and Q(x) = (y-8)/x.

To solve this using an integrating factor, we first find the integrating factor:

μ(x) = e^∫P(x)dx = e^∫(-1/x)dx = e^(-ln(x)) = 1/x

Multiplying both sides of the differential equation by the integrating factor, we get:

1/x * y' - (y-8)/x^2 = 0

Using the product rule, we can rewrite the left-hand side as:

(d/dx)(y/x) = 8/x^2

Integrating both sides with respect to x, we get:

y/x = -8/x + C

Solving for y, we get:

y = -8 + Cx

Using the initial condition y(1) = 56, we can solve for the constant C:

56 = -8 + C(1)

C = 64

Therefore, the solution to the differential equation is:

y = -8 + 64x

2. For the second differential equation, we have:

y' + y = 7x

This is already in the form y' + P(x)y = Q(x), where P(x) = 1 and Q(x) = 7x.

To find the integrating factor, we first find the integrating factor:

μ(x) = e^∫P(x)dx = e^∫dx = e^x

Multiplying both sides of the differential equation by the integrating factor, we get:

e^x y' + e^x y = 7xe^x

Using the product rule, we can rewrite the left-hand side as:

(d/dx)(e^x y) = 7xe^x

Integrating both sides with respect to x, we get:

e^x y = 7 ∫xe^x dx

Using integration by parts, we get:

e^x y = 7(xe^x - e^x) + C

Solving for y, we get:

y = 7x - 7 + Ce^(-x)

Using the initial condition y(0) = 63, we can solve for the constant C:

63 = 7(0) - 7 + Ce^(-0)

C = 70

Therefore, the solution to the differential equation is:

y = 7x - 7 + 70e^(-x)

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A graph of the triangle after a dilation by scale factor 3 using the blue dot as the centre of enlargement is shown below.​

In Mathematics and Geometry, a dilation is a type of transformation which typically changes the size of a geometric object, but not its shape.

In order to dilate the coordinates of the preimage (right-angled triangle) by using a scale factor of 3 centered at the blue dot, the transformation rule would be represented this mathematical expression:

(x, y)  →  (k(x - a) + a, k(y - b) + b)

(x, y)  →  (3(x - a) + a, 3(y - b) + b)

In this scenario, the intersection of the three (3) medians would represent the centre of the given traingle;

AO ≅ 20D

BO ≅ 20E

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The two height functions are h₁(t) = −16t² + 121 is a vertical translation of h₂(t) = −16t² + 225. The y-intercept of h₁ is 104 ft less than that of h₂. The correct answer is option (c)

To understand why this is the correct answer, let's first understand what the given information represents. Two identical baseballs are dropped from different heights, and we are asked to find their respective height functions. The height function gives the height of the baseball at any given time during its descent.

We know that the height function of a ball dropped from a height h₀ is given by h(t) = −16t² + h₀, where t is the time in seconds since the ball was dropped.

Using this formula, we can find the height functions for the two baseballs:

For the first baseball dropped from a height of 121 feet, the height function is h₁(t) = −16t² + 121.

For the second baseball dropped from a height of 225 feet, the height function is h₂(t) = −16t² + 225.

Now, we are given that h₁(t) is a vertical translation of h₂(t) with a difference of 104 ft in the y-intercept. This means that h₁(t) can be obtained from h₂(t) by shifting the graph vertically downward by 104 ft.

Since both functions have the same leading coefficient (-16), they have the same shape but different y-intercepts. Therefore, the correct option is (c).

Comparing their graphs, we can see that h₂(t) starts at a higher point on the y-axis (225 ft) and drops faster than h₁(t) which starts at a lower point (121 ft) and drops at a slower rate. This is because the greater the initial height, the longer it takes for the ball to reach the ground.

The correct answer is option (c)

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