Answer:
[tex]F = \boxed{3.53002 \times 10^{22} \;N}[/tex]
Explanation:
The formula used to calculate the gravitational force between two objects
[tex]F = G \dfrac{m_1m_2}{r^2}[/tex]
where
m₁ and m₂ are the masses of the two objects
G is the universal gravitational constant =6.6743 × 10⁻¹¹ m³/kg·s²
r is the average distance between the two objects
We are given
mass of earth = m₁ = 5.98 X 10²⁴ kg
mass of sun = m₂ = 1.99 x 10³⁰ kg
r = 1.5 x 10¹¹ m
Therefore
[tex]F\:=\:6.6743\:\times \:10^{-11}\times \dfrac{\left(5.98\:\times 10^{24}\times 1.99\:\times 10^{30}\right)}{\left(1.5\:\times \:10^{11}\right)^2}[/tex]
[tex]F = \boxed{3.53002 \times 10^{22} \;N}[/tex]
the earth has a much larger mass than the moon. how many moons would it take to equal the mass of earth?
It would take approximately 81.3 Moons to equal the mass of the Earth.
What is the mass of the earth?Iron and oxygen make up the majority of the Earth's mass. Each of these makes up around 32% of the mass of the planet. Calcium, aluminum, and nickel make up roughly 1.5% of the total, followed by magnesium and silicon, which each contribute another 15%.
The mass of the Earth is approximately 5.97 x 10^24 kilograms, while the mass of the Moon is approximately 7.35 x 10^22 kilograms.
To determine how many Moons would be required to equal the mass of the Earth, we can divide the mass of the Earth by the mass of the Moon:
5.97 x 10^24 kg / 7.35 x 10^22 kg = 81.3
Therefore, it would take approximately 81.3 Moons to equal the mass of the Earth.
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a π bond could be formed from the overlap of which two orbitals?
A π bond is formed from the overlap of two parallel p orbitals that are adjacent to each other. When two such p orbitals overlap, the regions of overlapping electron density create a bonding molecular orbital with a nodal plane between the nuclei of the bonding atoms.
What is P bond and orbitals?Two parallel p orbitals that are near each other combine to form pi bonds. A metallic bond fundamentally consists of two or more atoms sharing the same pair of electrons. In contrast to a sigma bond, which has its electronegativity focused between the atoms, a pi bond has its electron density concentrated both above and below the internuclear axis. A zone of negative electrode is produced by this charge distribution dispersion, which can interact with other molecules' and atoms' positive ions.
Along with s and d orbitals, atomic orbitals are one of the three types of orbitals that an electron can occupy in an atom. P orbitals consist of two prongs that are wedge-shaped in alignment. There are three there. Three are three mutually perpendicular p orbitals that can exist in an atom, each labeled as px, py, and pz.
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Sketch a graphical representation showing the difference of accelerated and non-accelerated uniform motion indicating the magnitude and directions of each segment.
The graph of an accelerating object shows the increase in velocity with time. The object which is not accelerating is having a constant velocity with out any change in direction or magnitude.
What is acceleration ?Acceleration is a physical quantity that, measures the rate of change in velocity. It is a vector quantity thus having both magnitude and direction. It can be defines as the ratio of change in velocity to the change in time.
The change in direction or magnitude or in both of velocity leads to an acceleration on the object. The object moving through a circular curvature is having a change in its direction of velocity. Hence, the object is accelerating.
For an object moving without a change in velocity and no change in direction, the object is not accelerating at all as seen in the graph 2.
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The air around a certain chemical reaction becomes warmer as the reaction progresses. How is energy transferred from the system to the surroundings?
A) Molecules in the system absorb energy when they move to the surroundings.
B) Molecules in the system absorb energy when the collide with molecules from the surroundings.
C) Molecules in the system transfer kinetic energy when they collide which molecules in the surroundings.
D) Molecules in the surroundings transfer kinetic energy when they collide with molecules in the system
The correct answer is D) Molecules in the surroundings transfer kinetic energy when they collide with molecules in the system.
What is exothermic chemical reaction?An exothermic chemical reaction is a type of chemical reaction in which heat energy is released into the surrounding environment. During an exothermic reaction, the products of the reaction have less energy than the reactants, and the difference in energy is released as heat. This means that the temperature of the surroundings increases as the reaction proceeds.
Some common examples of exothermic reactions include combustion, oxidation, and neutralization reactions. In contrast, an endothermic chemical reaction is a reaction that absorbs heat from the surroundings as the reaction proceeds, resulting in a decrease in temperature of the surroundings.
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Answer:
C. Molecules in the system transfer kinetic energy when they collide with molecules in the surroundings.
Explanation:
Could someone type these out for me? (Should be three pages)
They both had the same potential energies. This is because everyone can be found in the same location.
Describe potential energy.
An object or set of things may have potential energy stored in them depending on their size, form, location, or even the material they are constructed of. Find out what potential energy is and the various kinds that an object might have.
There was a difference in the average amount that the box slid after catching the marble when comparing the marbles. The more kinetic energy I have, the greater the impact it has and, as a result, the further the box will slide away. At the end of the ramp, the kinetic energy between them is NOT equal. Because of its greater mass, kinetic energy has larger potential. Distance reveals the outcome.
My data indicate that both of my hypotheses for each experiment are true. My theory for the initial trial was that moving the box by 40 cm would be the most effective. Considering that the average distance was the greatest of all, this was in fact true. The second experiment was conducted similarly. My hypothesis for the second experiment was that the more the marole's mass, the greater the box's distance.
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A 0.112-kg billiard ball moving at 154 cm/s strikes a second billiard ball of the same mass moving in
the opposite direction at 46 cm/s. The second billiard ball rebounds and travels at 72 cm/s after the
head-on collision.
Determine the post-collision velocity of the first billiard ball.
The post-collision velocity of the first billiard ball is 272 cm/s.
Define VelocityVelocity is a vector quantity that describes an object's speed and direction of motion.
We can solve this problem by using the law of conservation of momentum, which states that the total momentum of an isolated system remains constant.
The momentum of an object is defined as the product of its mass and velocity:
p = m * v
The total initial momentum of the system is the sum of the momenta of the two billiard balls before the collision:
p_initial = m * v1 + m * v2
where m is the mass of each billiard ball, v1 is the initial velocity of the first billiard ball, and v2 is the initial velocity of the second billiard ball.
After the collision, the first billiard ball will rebound with a velocity v1', and the second billiard ball will rebound with a velocity v2'. The total final momentum of the system is the sum of the momenta of the two billiard balls after the collision: p_final = m * v1' + m * v2'
Since the law of conservation of momentum applies, we can set the initial momentum equal to the final momentum
p_initial = p_final
Substituting the given values, we get:
m * v1 + m * v2 = m * v1' + m * v2'
Simplifying, we get:
v1' = (m * v1 + m * v2 - m * v2') / m
v1' = v1 + (v2' - v2)
Plugging in the given values, we get:
v1' = 154 cm/s + (72 cm/s - (-46 cm/s))
v1' = 272 cm/s
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Nichrome is used as a heating element in electric iron. give reason
Nichrome is used as a heating element in electric irons
High resistanceCorrosion resistanceGood temperature stabilityWhy Nichrome is used as a heating element?High resistance: Nichrome has a high electrical resistance, which means that it converts electrical energy into heat energy efficiently. This makes it ideal for use in heating elements where heat generation is the primary requirement.
Good temperature stability: Nichrome has a high melting point and a low coefficient of thermal expansion. This means that it can maintain its structural integrity even at high temperatures and does not deform or break easily.
Corrosion resistance: Nichrome is resistant to corrosion, which makes it suitable for use in electrical appliances that are exposed to moisture, such as electric irons.
Long lifespan: Nichrome has a long lifespan and does not degrade easily even with repeated use. This makes it a reliable and durable choice for heating elements.
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how does the speed of sound in sea water compare to the speed of sound in air? a the speed of sound is faster in sea water because the molecules in sea water are closer to each other and more dense. b the speed of sound is slower in sea water because the molecules in sea water are closer to each other and more dense. c the speed of sound is faster in sea water because the molecules in sea water are closer to each other and less dense. d the speed of sound is slower in sea water because the molecules in sea water are closer to each other and less dense.
Seawater has sound travelling at a substantially higher speed than air. The speed of sound in air is roughly 343 metres per second at a temperature of 25 °C.
How quickly does sound travel across sea water?The sound speed in the oceans fluctuates between 1,450 and 1,570 metres per second (or 4,760 and 5,150 feet per second). With every 1 °C increase in temperature and every 1 psu increase in salinity, it grows by around 4.5 metres (about 15 feet) and 1.3 metres (about 4 feet) every second, respectively.
Why does sound travel faster in water than in air?In water, sounds move more quickly than in the air. Because the particles are considerably closer together, They may quickly transfer vibrational energy from one particle to the next because of the water. Sound generally travels through water four times more quickly than through air.
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3. The electric field at a point 27 cm from a charged particle is 105 N
C
toward the particle.
What is the charge on the particle?
The particle has a charge of 2.44 x 10-8 C. when electric field at a point 27 cm from a charged particle is 105 N
What is charge?The electrical properties of particles like electrons and protons are described by charge, a fundamental property of matter. Particles with the same electric charge repel one another while those with the opposite charge attract one another. Electric charge can be positive or negative. The Coulomb (C) is the charge measurement unit, and particles' charges are typically measured in Coulombs.
E is equal to kQ/r₂, where k is the Coulomb constant, r is the distance from the particle to the point where the electric field is being measured, Q is the charge on the particle, and E is the electric field.
The electric field at a distance of 27 cm from the particle is calculated to be 105 N/C in the particle's direction. We now have:
By substituting these values into the equation for the electric field, we obtain: E = 105 N/C r = 27 cm = 0.27 m
105 N/C = (8.99 x 10⁹ N m²/C²) × Q / (0.27 m)²
Solving for Q, we get:
Q = (105 N/C) × (0.27 m)² / (8.99 x 10⁹ N m²/C²)
Q = 2.44 x 10⁻⁸ C
Therefore, the charge on the particle is 2.44 x 10⁻⁸ C.
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a parallel-plate capacitor has 2.00-cm2 plates that are separated by 5.00 mm with air between them. (a) if a 12.0-v battery is connected to this capacitor, how much energy does it store? (b) if a dielectric with a constant of 2.56 were inserted between the plates with the battery attached, what would the energy stored become? (c) repeat (b) for the case where the battery had been disconnected before dielectric insertion.
a) The energy stored in the capacitor is 5.10 × 10⁻¹⁰ J.
b) The energy stored in the capacitor with the dielectric inserted is 1.04 × 10⁻⁹ J.
c) The energy stored in the capacitor with the dielectric inserted and the battery disconnected is 2.14 × 10⁻¹⁰ J.
The energy stored in a parallel-plate capacitor is given by the formula:
U = [tex]\frac{1}{2}CV^2[/tex]
where U is the energy stored, C is the capacitance, and V is the voltage across the capacitor.
(a) The capacitance of a parallel-plate capacitor is given by the formula:
C = [tex]\frac{\epsilon_0A}{d}[/tex]
where [tex]\epsilon_0[/tex] is the permittivity of free space, A is the area of the plates, and d is the distance between them.
Substituting the given values, we have:
C =[tex]\frac{(8.85 \times 10^{-12} \textrm{ F/m})(2.00 \times 10^{-4} \textrm{ m}^2)}{5.00 \times 10^{-3} \textrm{ m}} = 7.08 \times 10^{-12} \textrm{ F}[/tex]
The voltage across the capacitor is given by the battery voltage, which is 12.0 V. Substituting these values into the formula for energy, we have:
U = [tex]\frac{1}{2}(7.08 \times 10^{-12} \textrm{ F})(12.0 \textrm{ V})^2 = 5.10 \times 10^{-10} \textrm{ J}[/tex]
(b) When a dielectric is inserted between the plates, the capacitance increases. The new capacitance is given by the formula:
[tex]C' = \kappa C[/tex]
where [tex]\kappa[/tex] is the dielectric constant of the material.
Substituting the given values, we have:
[tex]C' = (2.56)(7.08 \times 10^{-12} \textrm{ F}) = 1.82 \times 10^{-11} \textrm{ F}[/tex]
The voltage across the capacitor remains the same, so the energy stored in the capacitor becomes:
[tex]U' = \frac{1}{2}(1.82 \times 10^{-11} \textrm{ F})(12.0 \textrm{ V})^2 = 1.04 \times 10^{-9} \textrm{ J}[/tex]
(c) If the battery is disconnected before the dielectric is inserted, the charge on the plates remains the same. However, the voltage across the capacitor decreases due to the increased capacitance. The new voltage is given by the formula:
[tex]V' = \frac{V}{\kappa}[/tex]
Substituting the given values, we have:
[tex]V' = \frac{12.0 \textrm{ V}}{2.56} = 4.69 \textrm{ V}[/tex]
The energy stored in the capacitor becomes:
[tex]U' = \frac{1}{2}(1.82 \times 10^{-11} \textrm{ F})(4.69 \textrm{ V})^2 = 2.14 \times 10^{-10} \textrm{ J}[/tex]
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The stored energy that can be used to do work is called ______ energy, while the energy of motion used to do work is called ________ energy.
The stored energy that can be used to do work is called Potential energy
while the energy of motion used to do work is called kinetic energy.
Potential energy is simply stored energy that, depending on its surroundings or circumstances, a thing may use. Potential energy is the energy that is held inside a system of physically interacting things, to use terminology more closely related to physics.
Kinetic energy, often known as the energy of motion, may be seen in the motion of things and subatomic particles. Kinetic energy may be found in all particles and moving objects. Examples of kinetic energy in action include a person walking, a baseball flying through the air, food tumbling off a table, and a charged particle in an electric field. Everything contains kinetic and potential energy. Kinetic energy is the ability to move anything (KE). Energy is a potential form of energy (PE).
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two children with masses of 22 kg and 38 kg are sitting on a balanced seesaw. if the heavier child is sitting 0.45 m from the center, at what distance from the center is the lighter child sitting?
A seesaw is one type of lever, and it features a long beam attached to a pivot known as the fulcrum. The beam drops to the ground as soon as you sit on one side of it and put weight on one of its ends.
is the distance from the center is the lighter child sitting.
What is the balanced seesaw?The seesaw maintains its balance if the total torques that drive it to revolve in one direction—clockwise—equal the total torques that cause it to rotate in the opposite—counterclockwise. For an object at rest with no net forces acting on it, this is analogous to Newton's First Law.
This is due to the weight of your body being pulled downward by the force of gravity as well as the beam.
Two children with masses of 22 kg and 38 kg are sitting on a balanced seesaw, the heavier child is sitting 0.45 m,
the force by both, as shown below,
the distance as the seesaw is in equilibrium,
Therefore, is the distance from the center is the lighter child sitting.
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the largest object in the asteroid belt is ceres with a radius of 470 km and a mass of 9.384*10^20 kg. what is the weight, in newtons, of a 160. kg astronaut standing on ceres
The largest object in the asteroid belt is ceres with a radius of 470 km and a mass of [tex]9.384*10^2^0 kg[/tex]. The weight of a 160. kg astronaut standing on ceres is 43.2 N.
The weight of the astronaut on Ceres can be calculated using the formula:
w = m * g
here,
w is weight of the astronaut,
m is mass of the astronaut, and
g is gravitational acceleration on Ceres.
The gravitational acceleration on Ceres:-
[tex]F = G * (m1 * m2) / r^2[/tex]
here,
F is gravitational force between two objects,
G is gravitational constant,
m₁ & m₂ are masses of the two objects, and
r is distance between them.
For an object of mass m near the surface of a spherical object of mass M and radius R, the distance r can be approximated as (R + h).
For Ceres, the gravitational acceleration:-
[tex]g = G * M / R^2[/tex]
here,
G is gravitational constant,
M is mass of Ceres, and
R is radius of Ceres.
Reserving values given:-
[tex]g = (6.67430 × 10^-^1^1^ ^m^3/(kg s^2)) * (9.384 × 10^20 kg) / (470000 m)^2[/tex]
[tex]g = 0.27 m/s^2[/tex]
Now, weight of the astronaut as:
w = m * g
[tex]w = 160 kg * 0.27 m/s^2[/tex]
w = 43.2 N
Therefore, the weight of a 160 kg astronaut standing on Ceres is approximately 43.2 newtons.
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if the projectile rises to a maximum height of only 10.7 m, determine the magnitude of the average force due to air resistance.
This can be calculated by the formula - CD=FD12ρAv2Explanation:Air resistance, or drag, is dependent on a number of factors including the density of the air, the area of the object, its velocity, and other properties of the object. The units for the force of air resistance are in Newtons (N).
What projectile rises to a maximum height?The magnitude of the drag force is characterized by the dimensionless drag coefficient CD , given by CD=FD12ρAv2, C D = F D 1 2 ρ A v 2.
Where ρ is the density of the fluid (in this case, air), A=(1/4)πD2 A = ( 1 / 4 ) π D 2 is the cross-sectional area of the object, and v is the object's speed.
Therefore, Air resistance can be calculated by taking air density times the drag coefficient times area all over two, and then multiply by velocity squared.
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is it an inward force or an outward force that is exerted on the clothes during the spin cycle of a washing machine?
when two sources of waves with the same frequency are active, what must the path length difference be at some point in space for the waves to interfere destructively? when two sources of waves with the same frequency are active, what must the path length difference be at some point in space for the waves to interfere destructively? the distance between the two sources. some whole multiple of the wavelength. 0 some whole multiple of the wavelength plus one half the wavelength.
When two sources of waves with the same frequency are active, the path length difference must be equal to some whole multiple of the wavelength plus one half the wavelength for the waves to interfere destructively.
This is because in order for two waves to interfere destructively, they must be exactly out of phase with each other. When waves are out of phase, the crest of one wave lines up with the trough of the other, resulting in a cancellation of the waves. This occurs when the path length difference between the two waves is equal to an odd multiple of half wavelengths. For example, if the distance between the two sources is exactly one wavelength, then the waves will interfere constructively, resulting in a stronger wave. However, if the distance is increased to one and a half wavelengths, then the waves will interfere destructively, resulting in a weaker or canceled wave. This pattern repeats for all odd multiples of half wavelengths.
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A quantity of steam (250 g) at 128°C is condensed, and the resulting water is frozen into ice at 0°C. How much heat was removed?
the heat removed from the steam is 128000 J.
When steam is condensed into water, its temperature decreases from 128°C to 0°C. During this process, heat is removed from the steam and transferred to the surrounding environment. This heat transfer can be calculated using the equation:
q = m * c * ΔT
where q is the heat transferred, m is the mass of the steam, c is the specific heat capacity of water, and ΔT is the change in temperature.
For steam, the specific heat capacity is about 4.184 J/g°C. For water, the specific heat capacity is about 4.184 J/g°C as well.
Plugging in the values, we have:
q = 250 g * 4.184 J/g°C * (128°C - 0°C)
q = 250 * 4.184 * 128
q = 128000 J
a hamster runs at a speed of 13 centimeters per second in a wheel of radius 14 centimeters. a) what is the angular velocity of the wheel? (in radians/sec) incorrect radians/sec correctradians/sec no decimals allowed. b) how fast will the wheel spin in revolutions per minute? incorrect rev/min correctrev/min no decimals allowed.
The angular velocity of the wheel is 0.9286 radians/sec and the number of revolutions per minute is 8.84 rpm
The angular velocity of the wheel in radians per second is given by the formula:
ω = v/r where ω is the angular velocity in radians per second, v is the linear velocity in cm/s, and r is the radius of the wheel in cm.
Therefore, the angular velocity of the wheel is:
ω = 13 cm/s / 14 cm = 0.9286 radians/sec
To calculate the revolutions per minute (rpm), we use the formula:
rpm = ω * 60 / (2π)
where 2π is the number of radians in a full revolution.
Therefore, the wheel will spin at a rate of:
rpm = 0.9286 radians/sec * 60 / (2π) = 8.84 rpm
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. a car, initially travelling at 20.0 m/s, accelerates at a uniform rate of 4.00 m/s2 for a distance of 50.0 m. how much time is required to cover this distance?
It takes 2.07 seconds for the car to cover a distance of 50.0 meters while accelerating at a uniform rate of 4.00 m/s^2.
We can use the kinematic equation to solve for the time required to cover the distance.
Here's the kinematic equation that we'll use:
d = vi * t + 1/2 * a * t^2
where:
d = distance traveled (in meters)
vi = initial velocity (in meters per second)
a = acceleration (in meters per second squared)
t = time (in seconds)
We want to solve for t, so we'll rearrange the equation to isolate t:
d = vi * t + 1/2 * a * t^2
50.0 m = 20.0 m/s * t + 1/2 * 4.00 m/s^2 * t^2
50.0 m = 20.0 m/s * t + 2.00 m/s^2 * t^2
Now we have a quadratic equation in the form of ax^2 + bx + c = 0, where:
a = 2.00 m/s^2
b = 20.0 m/s
c = -50.0 m
We can use the quadratic formula to solve for t:
t = (-b ± sqrt(b^2 - 4ac)) / 2a
Plugging in the values for a, b, and c, we get:
t = (-20.0 ± sqrt(20.0^2 - 4(2.00)(-50.0))) / 2(2.00)
t = (-20.0 ± sqrt(400 + 400)) / 4.00
t = (-20.0 ± 28.28) / 4.00
We have two solutions because of the ± sign. However, we know that time cannot be negative, so we'll take the positive solution:
t = (-20.0 + 28.28) / 4.00
t = 2.07 seconds
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what is the magnitude of a point charge that would create an electric field of 1.20 n/c at points 1.60 m away?
The magnitude of a point charge that would create an electric field of 1.20 n/c at points 1.60 m away is 0.341 * [tex]10^{-9}[/tex] C.
Each location in space where a charge exists in any form can be considered to have an electric field attached to it. The electric force per unit charge is another name for an electric field. Variable magnetic fields or electric charges are frequently the cause of electric fields. Volts per metre (V/m), a unit used in the SI, is used to express electric field strength. The force acting on the positive charge is assumed to be exerted in the direction of the pitch. The electric field is directed radially inwards towards negative point charge and radially outwards from positive charge.
Electric field = 1.20 n/c
r= 1.60 m
[tex]E=\frac{q}{4\pi E_{o}*r^{2} } \\q=4\pi E_{o}*E*r^{2} \\=\frac{(1.20 n/c)((1.60m)^{2} }{8.99*10^{9}N.\frac{m^{2} }{C^{2} } } \\=0.341*10^{-9} C[/tex]
Therefore, the magnitude of a point charge that would create an electric field of 1.20 n/c at points 1.60 m away is 0.341 * [tex]10^{-9}[/tex] C.
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therm is a unit that is generally used to measure the energy contained in natural gas. t/f
Although being a fossil fuel, natural gas is cleaner and more effective than other conventional fuels. According to the Center for Liquefied Natural Gas, natural gas emits fewer greenhouse gases and pollutants than its competitors. Thus, it is true.
What is the energy contained in natural gas?The methane and other hydrocarbon molecules in the decomposing organisms contain chemical energy that was previously obtained by photosynthesis from the sun. Burning natural gas can provide power as well as heat homes.
Methane makes up the majority of natural gas, but it also includes ethane, propane, and heavier hydrocarbons. Moreover, it has trace amounts of water, nitrogen, carbon dioxide, and hydrogen sulphide.
Therefore, it is true that therm is a unit that is generally used to measure the energy contained in natural gas.
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sound waves with frequency 3700 hz and speed 343 m/s diffract through the rectangular opening of a speaker cabinet and into a large auditorium of length 100 m. the opening, which has a horizontal width of 21.0 cm, faces a wall 100 m away. along that wall, how far from the central axis will a listener be at the first diffraction minimum and thus have difficulty hearing the sound? (neglect reflections.)
The central will a listener be at the first minimum and thus have difficulty hearing the sound is 41.2 m.
As with all waves, the relationship between sound speed, frequency, and wavelength can be described by the equation where stands for sound speed, stands for sound frequency, and represents the wavelength.
Perpendicular to the speaker and spaced from the central should make up the initial minimum.
Therefore,
100m/[(0.300m)(3000Hz)/(343m/s)]²-1
= 41.2 m
Therefore, the central will a listener be at the first minimum and thus have difficulty hearing the sound is 41.2 m.
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what two types of forces act on a fluid element? question 5 options: shearing and surface forces body and surface forces gravitational and body forces
The two types of forces that act on a fluid element is body forces and surface forces.
A body force is a force that acts throughout the volume of a body.( 1) Forces due to graveness, electric fields and glamorous fields are exemplifications of body forces. Body forces discrepancy with contact forces or face forces which are wielded to the face of an object.
Normal forces and shear forces between objects are superficial forces as they're wielded to the face of an object. All cohesive face magnet and contact forces between objects are also considered as face forces.
Face force denoted fs is the force that acts across an internal or external face element in a material body. face force can be perished into two vertical factors normal forces and shear forces. A normal force acts typically over an area and a shear force acts parenthetically over an area.
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consider 3 resistors with resistance r1, r2, r3 connected in series with a battery. this means that one end of r1 is connected to the positive terminal of the battery; the other end of r1 is connected to one end of r2; the other end of r2 is connected to one end of r3; the other end of r3 is connected to the negative terminal of the battery. if you replaced the three resistors with a single resistor, what is the resistance req of this resistor?
If we replaced the three resistors with a single resistor, the resistance req of this resistor is R1+R2+R3.For the series combination of resistances, here the second end of each resistance is attached to the first end of the following resistance and the setting goes so on
In a series circuit of resistors, the current that runs through every one of them is identical and is equivalent to the current provided by the battery. Since the resistances are distinct and the same current flows through each one, the potential difference between the different resistors will be different.
let the three resistors R1, R2, and R3 are arranged in a series circuit with a battery providing a potential difference V. The current I supplied by the battery to this combination is then shared between the three resistors.Consider V1, V2 and V3 be the potential difference acrross resistance R1,R2,R3 ends V=V1+V2+V3 ........(1).
Considering the replaced resistance be R, by ohm's law V=IR,V1=IR1,V2=IR2,V3=IR3, so substituing those in equation 1 we get :
I=IR1+IR2+IR3
IR=I(R1+R2+R3)
R=R1+R2+R3
In conclusion, the replaced resistor resistance is the sum of the individual resistances
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Suppose that two objects attract each other with a gravitational force of 18 units. If the mass of one of the objects was tripled, and if the distance between the objects tripled, then what would be the new gravitational force of attraction between the two objects?
Answer:
6 units
Explanation:
You want the gravitational force between two objects after both the mass of one object and the distance between them triples, if it is initially 18 units.
ForceLet F represent the initial force between the objects. Newton's law of gravitational attraction tells us ...
F = GmM/r²
When one mass is tripled, and the distance between the objects is tripled, the new force is ...
F' = G(3m)M/(3r)² = 3/9(GmM/r²) = F/3
Given the initial force is 18 units, the new force of attraction is ...
F' = (18 units)/3 = 6 units
The new gravitational force of attraction between the objects is 6 units.
In the above figure, what is the net electric potential at point P due to the four particles if V=0 at infinity, q=5.00 fC and d=4.00 cm?
The net electric potential at point P due to the four particles would be Vtotal=5.5625×10−4Nm/C.
Among electric potential and electric field which one is a vector quantity?Electric field is a vector quantity, while electric potential is a scalar quantity. So, in order to find the electric potential on a point due to several other point charges, we will make a sum of their individual electric potential with respect to the point charge. So, to find the electric potential on point P due to the other point charges, we can find the electric potential of each point charge on P and add them, V=V1+V2+V3+V4
The electric potential of charges at either side of point P on P will be given by,
V1=V2=k(+q)d
In the same way, the electric potential on point P, due to the third charge,
V3=k(−q)2d
And the electric potential on point P due to fourth charge will be,
V4=k(−q)d
We know that electric potential is a scalar quantity, thus the total electric potential on point P is simply the sum of all the electric potentials on point P, V=V1+V2+V3+V4
Vtotal=k(+q)/d+k(+q)/d+k(−q)/2d+k(−q)/d
Vtotal=kq[(+1)/d+(+1)/d+(−1)/2d+(−1)/d]
Substituting the value of k=1/4πε0
and solving,
Vtotal= [ (2+2−1−2)/2d]
Vtotal= [(1)/2d]
We also know that the q=5.00fC=5×10⁻¹⁵C
, d=4.00cm=4×10⁻²m
and the value of the electrostatic constant, k=1/4πε0=8.996×10⁹Nm2C−2
Vtotal=8.996×10⁹Nm2C−2×5×10⁻¹⁵C[(1)2×4×10⁻²m]
Solving for Vtotal
we get,
Vtotal=5.5625×10⁻⁴Nm/C.
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Where do plants get the energy to make their food?
From the air
From the flower
From the roots
From the sunflower
Plants get the energy to make their food through the flowers and is therefore denoted as option B.
What is Photosynthesis?This is referred to as the process in which green plants manufacture their food in the presence of sunlight and is the reason why they are referred to as primary producers.
Plants have flowers and leaves which help to trap sunlight from the sun through the chlorophyll. The chlorophyll is a green pigment which is present in the chloroplast and they are all found in the flowers of plants which is therefore the reason why it was chosen as the correct choice.
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how much work does juanita do if she uses a force of 40 newtons to pull 2 friends on a wagon for 32 meters?
Juanita does 1280 joules of work to pull her 2 friends on the wagon over a distance of 32 meters with a force of 40 newtons.
To calculate the amount of work Juanita does, we need to use the formula:
Work = Force x Distance x cos(theta)
where:
Force: the amount of force applied (in newtons)
Distance: the distance the object is moved (in meters)
theta: the angle between the direction of the force and the direction of motion (in degrees)
In this case, Juanita applies a force of 40 newtons to pull the wagon with her 2 friends, over a distance of 32 meters.
We don't have information about the angle between the force and the direction of motion, but we can assume that the force is applied in the direction of motion (i.e., theta = 0 degrees).
Using this information, we can calculate the work Juanita does as follows:
Work = Force x Distance x cos(theta)
Work = 40 N x 32 m x cos(0)
Work = 1280 joules
Therefore, Juanita does 1280 joules of work to pull her 2 friends on the wagon over a distance of 32 meters with a force of 40 newtons.
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which structural fragment would give rise to a characteristic triplet-quartet pattern in the 1h nmr spectrum? true or false?
The statement "A structural fragment with three adjacent non equivalent protons would give rise to a characteristic triplet-quartet pattern in the 1H NMR spectrum" is true.
This is because the three protons are magnetically coupled to each other, resulting in a triplet signal, and they are also coupled to a neighboring proton, resulting in a quartet signal.
The relative intensities of the triplet and quartet signals are in a 1:3 ratio, which is characteristic of this type of structural fragment.
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a piece of rope is pulled by two people in a tug-of-war. each pulls with 400 n of force. what is the tension in the rope? 400 n zero 800 n 600 n none of these
If a body puts a 400 N force on a rope, the rope likewise exerts a 400 N force on the body. As a result, the tension in the rope is 400N.
This is determined by whether both persons are tugging in the same direction against a fixed object or against each other. When both forces are applied in the same direction, the total force is 300 N + 300 N = 600 N. If two persons pull on the rope at the same time, the total force in the rope is 300 N, or a net of zero. Newton's third law of motion deals with these two forces, which are known as action and reaction forces. The rope is used to transfer forces in this activity. The action force is the first team to tug, generating the draw on the rope; as the response force, the opposing team's rope end "feels" the pull.
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A piece of rope is pulled by two people in a tug-of-war. each pulls with 400 n of force, the tension in the rope is 400N.
Tension is a force along the length of a medium, especially a force carried by a flexible medium, such as a rope or cable. Tension can be defined as an action-reaction pair of forces acting at each end of the said elements.
If one of the forces exerting an object is a rope, cable or chain, you can call it tension. Cables and Ropes can be used for exerting forces since they can efficiently transfer a force over a specific distance (e.g. the rope length). Please note that tension is the pulling force since ropes cannot push effectively.
This is determined by whether both persons are tugging in the same direction against a fixed object or against each other. When both forces are applied in the same direction, the total force is 300 N + 300 N = 600 N.
The SI unit of Surface Tension is Newton per Meter or N/m.
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