6) Find the speed a spherical raindrop would attain by falling from 4.00 km. Do this:a) In the absence of air dragb) In the presence of air dragc) Assume that the diameter of the drop is 3 mm and the density of the water is 0.98x10^3 kg/m^3

Answers

Answer 1

We are asked to determine the velocity of a rain drop if it falls from 4 km.

To do that we will use the following formula:

[tex]2ah=v_f^2-v_0^2[/tex]

Where:

[tex]\begin{gathered} a=\text{ acceleration} \\ h=\text{ height} \\ v_f,v_0=\text{ final and initial velocity} \end{gathered}[/tex]

If we assume the initial velocity to be 0 we get:

[tex]2ah=v_f^2[/tex]

The acceleration is the acceleration due to gravity:

[tex]2gh=v_f^2[/tex]

Now, we take the square root to both sides:

[tex]\sqrt{2gh}=v_f[/tex]

Now, we substitute the values:

[tex]\sqrt{2(9.8\frac{m}{s^2})(4000m)}=v_f[/tex]

solving the operations:

[tex]280\frac{m}{s}=v[/tex]

Therefore, the velocity without air drag is 280 m/s.

Part B. we are asked to determine the velocity if there is air drag. To do that we will use the following formula:

[tex]F_d=\frac{1}{2}C\rho_{air}Av^2[/tex]

Where:

[tex]\begin{gathered} F_d=drag\text{ force} \\ C=\text{ constant} \\ \rho_{air}=\text{ density of air} \\ A=\text{ area} \\ v=\text{ velocity} \end{gathered}[/tex]

We need to determine the drag force. To do that we will use the following free-body diagram:

Since the velocity that the raindrop reaches is the terminal velocity and its a constant velocity this means that the acceleration is zero and therefore the forces are balanced:

[tex]F_d=mg[/tex]

Now, we determine the mass of the raindrop using the following formula:

[tex]m=\rho_{water}V[/tex]

Where:

[tex]\begin{gathered} \rho_{water}=\text{ density of water} \\ V=\text{ volume} \end{gathered}[/tex]

The volume is the volume of a sphere, therefore:

[tex]m=\rho_{water}(\frac{4}{3}\pi r^3)[/tex]

Since the diameter of the raindrop is 3 millimeters, the radius is 1.5 mm or 0.0015 meters. Substituting we get:

[tex]m=(0.98\times10^3\frac{kg}{m^3})(\frac{4}{3}\pi(0.0015m)^3)[/tex]

Solving the operations:

[tex]m=1.39\times10^{-5}kg[/tex]

Now, we substitute the values in the formula for the drag force:

[tex]F_d=(1.39\times10^{-5}kg)(9.8\frac{m}{s^2})[/tex]

Solving the operations:

[tex]F_d=1.36\times10^{-4}N[/tex]

Now, we substitute in the formula:

[tex]1.36\times10^{-4}N=\frac{1}{2}C\rho_{air}Av^2[/tex]

Now, we solve for the velocity:

[tex]\frac{1.36\times10^{-4}N}{\frac{1}{2}C\rho_{air}A}=v^2[/tex]

Now, we substitute the values. We will use the area of a circle:

[tex]\frac{1.36\times10^{-4}N}{\frac{1}{2}(0.45)(1.21\frac{kg}{m^3})(\pi r^2)}=v^2[/tex]

Substituting the radius:

[tex]\frac{1.36\cdot10^{-4}N}{\frac{1}{2}(0.45)(1.21\frac{kg}{m^{3}})(\pi(0.0015m)^2)}=v^2[/tex]

Solving the operations:

[tex]70.67\frac{m^2}{s^2}=v^2[/tex]

Now, we take the square root to both sides:

[tex]\begin{gathered} \sqrt{70.67\frac{m^2}{s^2}}=v \\ \\ 8.4\frac{m}{s}=v \\ \end{gathered}[/tex]

Therefore, the velocity is 8.4 m/s

6) Find The Speed A Spherical Raindrop Would Attain By Falling From 4.00 Km. Do This:a) In The Absence

Related Questions

Question A student conducts an experiment to determine how the temperature of water affects the time for sugar to dissolve. In each trial, the student uses a different amount of water and a different temperature of water. What is wrong with this experimental design? Responses The student needs to perform more trials. The student needs to perform more trials. The student changed more than one independent variable. The student changed more than one independent variable. The student does not have a dependent variable. The student does not have a dependent variable. The student did not change enough independent variables.

Answers

The student changed more than one independent variable.

A dependent variable is a variable that changes as a result of the manipulation of the independent variable. It's the result you want to measure and it depends on the independent variable. In statistics, the dependent variable is also called the response variable it responds to changes in another variable.

In other words, the two characteristics of the experimental design we've talked about so far are that the experiment must have at least two comparable conditions, and the researcher must match the participants to the conditions, not the participants themselves. That's it. The independent and dependent variables are those when you run the experiment. The independent variable is the one that changes and the dependent variable is the one that changes.

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The principal of a local high school gave all students breakfast for one week. Teachers commented that students were more alert that week in the morning.
Students commented they were more alert and could concentrate in the morning after eating breakfast. What can be concluded based on the observations?
All principals should give free breakfast every morning.
If students eat breakfast they will be able to concentrate in school in the afternoon.
Teachers should serve breakfast to their students.
Students should eat breakfast to be more alert at school during the morning.

Answers

Answer:

D Students should eat breakfast to be more alert at school during the morning.

Explanation:

Because based on the information given they said the principal gave students breakfast and teacher's said the students were more alert and the only common sense answer is D because they are more active in class in the morning not afternoon.

A small sphere with charge q = 5.00 µC and mass 0.500 g is traveling horizontally toward the east at a height of 60.0 cm above the ground. The sphere has a speed of 2.00 m/s as it enters a region of uniform horizontal electric field with magnitude E directed to the east.

What is E if the sphere has a speed of 5.00 m/sm/s just before it strikes the ground?

Answers

If the sphere has a speed of 5.00 m/s just before it strikes the ground the value of E is given as 468.4N

How to solve for the value of E

we have the following values to solve the problem with.

charge q = 5μc,

speed v = 2 m/s

height h = 60 cm

speed of sphere = 5 m/s

The Kinematic equation is given as

[tex]Y = V_{oy} T+\frac{1}{2} a_{y}t^{2}[/tex]

This is the time that it would take the sphere to hit the ground.

we have to insert the values

60 x 10⁻² = 0 + 1/2 (9.8)t²

t = 0.3499 sec

The sphere hits the ground at 0.3499 seconds

Vy = Voy + ayt

= 0 + 9.8 x 0.3499

= 3.429 m/s

Vn = 2 + qE/m (0,.3499)

= 2 + ((5 x 10⁻⁶) E /0.5 x 10⁻³)0.3499

= 2 + 2.499x10⁻³E

V = √Vx² + Vy²

5² = (2 + 3.499 x 10⁻³E)² + (3.429)²

13.241959 = (2 + 3.499 x 10⁻³E)²

3.638 = 2 + 3.499 x 10⁻³E

take like terms

1.6389 = 3.499 x 10⁻³E

to get E

1.6389 /  3.499 x 10⁻³

E = 468.4N

The value of E given the speed is given as 468.4 Newton

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A 3.00-kg object is initially moving northward at 15.0 m/s. Then a force of 15.0 N, toward the east, acts on it for 2.70 s.
A) At the end of the 2.70 s, what is the magnitude of the object’s final velocity?
B) What is the direction of the final velocity? Enter the angle in degrees where positive indicates north of east and negative indicates south of east.
C) What is the change in momentum during the 2.70 s? Take +y to be north and +x to be east. Enter a positive answer if the change in momentum is toward the east and a negative answer if the change in momentum is toward the west.

Answers

The magnitude of the object’s final velocity, the direction of the final velocity and the change in momentum during the 2.70 s

V=0.1 m/s[tex]\theta[/tex]=48.0^0 + from east-4.5kgm/s toward west

This is further explained below.

What is the magnitude of the object’s final velocity?

F_x=m a_x=15N

f is force

m is mass

a is acceleration

[tex]&a_x=\frac{15}{3} \\\\ m s^2=5 m_{s^{-2}} \\[/tex]

v_x=0+5 * 2.7

v_x=13.5

v_y=15

[tex]V=\sqrt{v_x^2+v_{y^2}}\\[/tex]

V=0.1 m/s

b)

[tex]\tan \theta=\frac{V_y}{V_x} \\\\ =\frac{18}{13.5} \\\\[/tex]

=1.11

[tex]\theta[/tex]=48.0^0 + from east

c)

Initial momentum,

p_{i x}=0, p_{i y}=m v_y=45 kgmg

final momentum,

P_{f x}=13.5 *3

=40.5kgm

P_{f y}=45Kgm/s

In conclusion, D P_x=P_{1 \text { In }}-P_{i x}=-4.5kgm/s toward west

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A cat is thrown straight up at 24.9 m/s What is the cat's velocity 4.3 seconds later?

Answers

Answer:

-17.3 m/s

Explanation:

a = -9.81 mm/s^2     vo = 24.9 m/s

vf = vo - at

   = 24.9 - 9.81 ( 4.3) = -17.3 m/s   ( cat is already coming back down)

Find the measure of the indicated angle to the nearest degree.
Sin θ

Answers

The measure of the indicated angle to the nearest degree is Sin 42°.

An angle is formed when two immediate traces or rays meet at a not-unusual endpoint.

The names of primary angles are Acute angle, Obtuse perspective, proper attitude, straight attitude, reflex angle, and full rotation. A perspective is a geometrical form shaped by using joining rays at their endpoints. An angle is normally measured in stages. there are various varieties of angles in geometry.

A right triangle or proper-angled triangle, or greater officially an orthogonal triangle, formerly called a rectangle triangle, is a triangle wherein one angle is a proper angle or facets are perpendicular. The relation among the perimeters and different angles of the proper triangle is the premise for trigonometry.

calculation:-

perpendicular = 43

hypoteneuse = 64.4

Sin θ = perpendicular / hypoteneuse

            = 43 / 64.4

Sin θ   =   0.66770

Sin θ = 41.889

Sin θ = 42° ( nearest degree)

Sin α = 90 - 42

        = 48°

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Inquiry is a process promoted by a Blank

Answers

Answer:

Inquiry is a process prompted by curiosity, observation or question.

Explanation:

Inquiry is driven by curiosity, wonder, interest and/or a need to answer a question. Being able to ask rich questions enables students to construct their knowledge and develop an understanding of concepts and experiences.

A satellite is 100 miles above the earth, it has a mass of 100kg. If the mass of the satellite were doubled the force of gravity of the satellite on the earth would ?

Answers

Given:

Distance of satellite from Earth = 100 miles

Mass of satellite = 100 kg

If the mass of the satellite were doubled, let's find what would happen to the force of gravity of the satellite on earth.

Apply the gravitational force formula:

[tex]F=\frac{Gm_1m_2}{r^2}[/tex]

Where:

F is the force of gravity

m is the mass.

From the formula above, we can see the force of gravity (F), is directly proportional to the mass.

Since they are directly proportional to each other, if the mass is doubled, the force of gravity will also be doubled.

Therefore, if the mass of the satellite is doubled, the force of gravity of the satellite on the earth will also be doubled.

ANSWER:

Force of gravity will be doubled when the mass of the satellite is doubled.

A crate is given a big push, and after it is released, it slides up an inclined plane which makes an angle 0.49 radians with the horizontal. The frictional coefficients between the crate and plane are (s = 0.66, k = 0.21 ). What is the magnitude of the acceleration (in meters/second2) of this crate as it slides up the incline?

Answers

The acceleration of the crate as it slides up the incline is 2.06 m/s².

What is the acceleration of the crate?

The acceleration of the crate as it slides up the inclined plane is calculated as follows;

Apply the principle of Newton's second law of motion to determine the acceleration of the crate.

Ff = ma

kmg = ma

kg = a

where;

k is the coefficient of kinetic frictiong is acceleration due to gravitya is the acceleration of the crate

a = (0.21 x 9.8 m/s²)

a = 2.06 m/s²

Thus, the acceleration of the crate as it slides up the incline depends on the coefficient of kinetic friction since the crate is in motion.

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What is the ratio of the force exerted on the floor by the ground to the persons body weight

Answers

We will have the following:

We are given:

m = 67kg

F = 2300N

Now, we have that the average are of a human foot is approximately 76 cm^2.

So, we will deterine the ratio of force excerted on the floor in terms of pressure, that is:

[tex]P=\frac{2300N}{0.0076m^2}\Rightarrow P=302631.5789Pa[/tex][tex]\Rightarrow P\approx302.632kPa[/tex]

So, the ratio of the force exerted on the floor by the ground is approximately 302.632 Kilopascals.

As the swings ride hits top speed, what applies centripetal force to keep the riders traveling in a circle?

Answers

When the swing moves from the lowest point up to either peak, the main force acting is momentum; and when the swing falls from either peak to its lowest point, the main force acting is gravity. If you do not pump your legs fast enough, air resistance along with gravity will keep you down.

What provides centripetal force?The centripetal force is the resultant force because the swings move in a circle. The centripetal force—the force that keeps the rider in a circle and the horizontal component of the tention force—is produced by the total of the forces acting along the x-axis.Gravity is the centripetal force that drives astronomical orbits according to Newtonian mechanics. A common illustration of centripetal force is when a body moves uniformly fast in a circular motion.A net force that keeps an object moving in a circular motion is known as a centripetal force.

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A toy car of mass 8 kg initially moves with a speed of 5 m/s. How much work must be done on the car to increase its speed to 10 m/s?

Answers

ANSWER:

300 J

STEP-BY-STEP EXPLANATION:

To know the work required, we must calculate the work in both cases, the difference would be the amount of work necessary for the speed to increase. The work done is the same as the amount of energy increase. The formula for kinetic energy is:

[tex]\frac{1}{2}m\cdot v^2[/tex]

We calculate in each case:

[tex]\begin{gathered} \frac{1}{2}\cdot8\cdot10^2=400\text{ J} \\ \frac{1}{2}\cdot8\cdot5^2=100\text{ J} \end{gathered}[/tex]

We calculate the difference between the two to find out the work required:

[tex]400-100=300\text{ J}[/tex]

The work required is 300 J

How much current does a 75-W light bulb draw when connected to 120 V?

Answers

We will determine the current as follows:

First, we recall that:

[tex]I=\frac{P}{V}[/tex]

So:

[tex]I=\frac{75W}{120V}\Rightarrow I=\frac{5}{8}A\Rightarrow I=0.625A[/tex]

So, the current that a 75-W light bulb draws when connected to 120 V is 0.625 Amps.

For a body to be in SHM, the restoring force in the ___________ direction as the displacement from equilibrium.A. OppositeB. PerpendicularC. SameD. Not enough info

Answers

A. Opposite

Explanation

Simple harmonic motion (SHM)is a very important type of periodic oscillation where the acceleration is proportional to the displacement from equilibrium, in the direction of the equilibrium position.

the oscillation of a mass on a spring when it is subject to the linear elastic restoring force given by Hooke's law

The restoring force is the force that brings the object back to its equilibrium position (red); the restoring force acts in the direction opposite to the displacement.

therefore, the answer is

A. Opposite

I hope this helps you

A .5kg book is thrown at a speed of 3m/s. What type of energy does it have and how much?

Answers

Given:

The mass of the book is m = 0.5 kg

The speed of the book is v = 3 m/s.

To find the type of energy and how much.

Explanation:

As the book is in motion, the energy is kinetic energy.

The formula to calculate kinetic energy is

[tex]K.E.\text{ =}\frac{1}{2}mv^2[/tex]

On substituting the values, the kinetic energy will be

[tex]\begin{gathered} K.E.=\frac{1}{2}\times0.5\times(3)^2 \\ =2.25\text{ J} \end{gathered}[/tex]

Thus, the kinetic energy will be 2.25 J

How fast must a 10 kg object be traveling to have the SAME momentum as a 2kg object at 8 m/s?

Answers

Recall that the momentum is given by

[tex]p=m\cdot v[/tex]

Where m is the mass and v is the velocity.

[tex]p=2\cdot8=16\;\;\frac{kg\cdot m}{s}[/tex]

So, the momentum of the object is 16 kg m/s.

Now, we need to equate this momentum to find the velocity of the other object.

[tex]\begin{gathered} p=m\cdot v \\ 16=10\cdot v \\ v=\frac{16}{10} \\ v=1.6\;\frac{m}{s} \end{gathered}[/tex]

Therefore, the object must be traveling at 1.6 m/s to have the same momentum as the other object.

a cylinder of gas is at room temperature (20 °C) the air conditioner breaks down and the temperature rises to 40°C what is the new pressure of gas relative to its initial pressure

Answers

Given,

The initial temperature of the room, T₁=20 °C=293.15 K

The final temperature, T₂=40 °C=313.15 K

Let the initial temperature of the room be P₁, and the final temperature be P₂

From Gay-Lussac's law,

[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]

On substituting the known values in the above equation,

[tex]\frac{P_1}{293.15}=\frac{P_2}{313.15}[/tex]

Therefore P₂ is given by,

[tex]P_2=\frac{P_1\times313.15}{293.15}=1.07P_1[/tex]

Therefore, the new pressure relative to the initial pressure is 1.07 times the initial pressure, i.e., 1.07P₁

I need to find wfg,wnet,the acceleration of the car and how long will it take Tyler to get to the gas station

Answers

The free body diagram representing this scenario is shown below

From the information given.

mass of car = 1200kg

Recall,

weight = mg

where

m = mass

g = acceleration due to gravity = 9.8 m/s^2

Thus,

weight of car = 1200 x 9.8 = 11760 N

Normal reaction, N has same magnitude with the weight but the direction is opposite. thus,

N = 11760 N

Frictional force = N x coefficient of friction

From the information given,

coefficient of friction = 0.67

Thus,

Frictional force = 11760 x 0.67 = 7879.2 N

Net force of the car = applied force - frictional force

applied force = 1.3 x 10^4 N = 13000 N

Thus,

Net force = 13000 - 7879.2 = 5120.8N

Recall,

net force = mass x acceleration

acceleration = net force/mass = 5120.8/1200 = 4.27 m/s^2

We want to calculate the time it will take Tyler to get to the gas station. We would apply one of Newton's equation of motion which is expressed as

s = ut + 1/2at^2

where

s = distance covered

t = time

a = acceleration

u = initial velocity

From the information given,

s = 15

a = 4.27

u = 0 because the car was at rest(Since it was broken down)

By substituting these values into the equation, we have

15 = 0 x t + 1/2 x 4.27 x t^2

15 = 0 + 2.135t^2

15 = 2.135t^2

Dividing both sides of the equation by 2.135, we have

15/2.135 = 2.135t^2

t^2 = 7.026

t = square root of 7.026

t = 2.65

The time required is 2.65 s


When you drop a 0.37 kg apple, Earth exerts
a force on it that accelerates it at 9.8 m/s² to-
ward the earth's surface. According to New-
ton's third law, the apple must exert an equal
but opposite force on Earth.
If the mass of the earth 5.98 x 10²4 kg, what
is the magnitude of the earth's acceleration
toward the apple?
Answer in units of m/s².

Answers

The earth is accelerating toward the apple at a rate of 6.2 × 1025 m/s2.

How is this acceleration determined?

The apple weighs m = 0.37 kg.

The apple's speed when it approaches the earth's surface is 9.8 meters per second.

Earth's mass, M, is 5.98 × 1024 kg.

Using Newton's Second Law of Motion, we may now:

The strength of the force exerted by Earth on the apple is,

F = ma

⇒ F = 0.37 × 9.8

⇒ F = 3.626 N

We are informed that the apple must exert an equal but opposite force on Earth in accordance with Newton's third law of motion.

Therefore, the force exerted by the apple on Earth will be of the following magnitude:

F = 3.626 N

Let "A" be the acceleration of the earth relative to the apple in m/s2.

Thus,

The following will be used to determine how quickly the earth is moving toward the apple:

F = MA

⇒ 3.626 = [5.98 × 10²⁴] × A

⇒ A = 3.626 / [5.98 × 10²⁴]

⇒ A = 0.606 × 10⁻²⁴

A = 6.06 × 10⁻²⁵ m/s²

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2
Carly mentions to her friends that her new scented oils have been helping heal her headaches. With no scientific evidence that this "aromatherapy"
actually works, her friends should caution her and tell her to be careful. What do Carly's friends think she may be diving into?
O A. astrology
OB. phrenology
OC. pseudoscience
O D. astronom

Answers

Carly's friends think she may be diving into pseudoscience .

When presented as pseudoscience, a claim, finding, or explanatory framework lacks the objectivity needed for scientific inquiry. Research that is based on dubious ideas, a defective experimental design, or unreliable data can also lead to pseudoscience.The word "pseudoscience" can be used to describe a single assertion or claim that is allegedly supported by facts or science but falls apart when put to the test of reason. A complicated system, like astrology, that claims to explain how astronomical occurrences cause and effect world events is another example of a pseudoscience. Many pseudosciences, like astrology, are reasonably safe.

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What is the maximum speed of a wave on a cable with length of 50 m, mass of 200 kg, and a tension force of 1000 N apply to it?V= √ Ft/e

Answers

Given:

the length of the cable is

[tex]l=5\text{0 m}[/tex]

the mass of the cable is

[tex]m=200\text{ kg}[/tex]

the tension force on the cable is

[tex]T=1000\text{ N}[/tex]

Required: velocity of the wave.

Explanation:

to find the velocity of the wave on a cable we use the formula that is given by

[tex]v=\sqrt[2]{\frac{T}{\mu}}[/tex]

Where

[tex]T[/tex]

is the tension force and

[tex]\mu[/tex]

is mass per unit length.

first, we calculate the mass per unit length.

[tex]\begin{gathered} \mu=\frac{200\text{ kg}}{50\text{ m}} \\ \mu=4\text{ kg/m} \end{gathered}[/tex]

now put this value in the above relation and solve for velocity, we get

[tex]\begin{gathered} v=\sqrt[2]{\frac{T}{\mu}} \\ v=\sqrt[2]{\frac{1000\text{ N}}{4\text{ kg/m}}} \\ v=15.81\text{ m/s} \end{gathered}[/tex]

Thus, the speed of the wave is 15.81 m/s.

If the tire of a car rotates at a constant speed of 552 times in one minute, how many times will the tire rotate in half-an-hour?

Answers

Given:

The car tire rotates 552 times in a minute.

Required:

The number of times the tire rotates in half an hour.

Explanation:

The tire rotates 552 times in a minute.

There are 30 minutes in half an hour.

The number of times the tire rotates in half an hour will be

[tex]\begin{gathered} 552\times30 \\ =16560 \end{gathered}[/tex]

Final Answer: The tire rotates 16560 times in half an hour.

Draw a supply graph for pizzas. Show what would happen to the supply of pizzas if two more pizzerias open up in town. Identify the determinant of supply that caused the shift.

Answers

The supply curve will move to the correct, demonstrating an increment within the add-up to the amount of pizza as of now on the advertisement, in case two or more pizzerias open within the community.

To encourage data on the important picture, see the subtle elements underneath and the attachment.

The add up to several items and administrations that businesses in a country's economy point to offer inside a particular time outline is known as total supply, too known as residential last supply in economics.

It is the overall number of merchandise and administrations that businesses in an economy are arranged and able to offer for sale at a particular cost point.

A alter in supply is characterized as a move to the cleared out or right within the general price-quantity relationship that shapes a supply shift. A alter in supply is characterized as a move to the cleared out or right within the general price-quantity relationship that shapes a supply bend.

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What is the speed of light in Crown glass? answer:______m/s

Answers

ANSWER

197,368,421.1 m/s ≈ 1.97 x 10⁸ m/s

EXPLANATION

The speed of light in a medium with an index of refraction n is given by,

[tex]v=\frac{c}{n}[/tex]

Where c is the speed of light in a vacuum, which is 3 x 10⁸ m/s.

In this case, we have to find the speed of light in Crown glass, whose index of refraction is 1.52 at 20°C. So, the speed of light in this medium is,

[tex]v=\frac{3\cdot10^8m/s}{1.52}=197,368,421.1m/s\approx1.97\cdot10^8m/s[/tex]

Hence, the speed of light in Crown glass is 197,368,421.1 m/s ≈ 1.97 x 10⁸ m/s.

A 9,900-kg truck runs into the rear of a 1,000-kg car that was stationary. The truck and car are locked together after the collision and move with speed 5 m/s. Compute how much kinetic energy was "lost" in this inelastic collision.
answer in J

Answers

Kinetic energy was "lost" in this inelastic collision is 151 J

The momentum is  given as :

m₁u₁  +  m₂u₂  =  m₁v₁  +   m₂v₂

The truck and car are locked together after the collision. The truck has same final velocity :

u = (( m₁ + m₂ ) v) / m₁

u = ( (9900 + 1000 ) × 3 ) / 9900

u = 3.30 m/s

now, the change in kinetic energy is given by :

ΔK.E = 1/2 (  m₁ + m₂) v² - 1/2 m₁ u²

ΔK.E = 1/2 ( 1211.11 ) - 1/2 ( 909.09)

ΔK.E = 605.55 - 454.54

ΔK.E = 151 J

Thus, A 9,900-kg truck runs into the rear of a 1,000-kg car that was stationary. The truck and car are locked together after the collision and move with speed 5 m/s.  kinetic energy was "lost" in this inelastic collision is 151 J

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which of the following is correct equation for finding the wavelengths of a wave? physics

Answers

Answer:

Option C may be the anawer for it

A train car with a mass of 1 kg is stuck to another train car with a mass of 2 kg. An Explosion pushes the two carts away from each other. After the recoil, the 1 kg train car is now moving at -2 m/s and we need to find the Velocity of the 2 kg train car.

Answers

We know that the momentum is conserved on the system this will mean that:

[tex]p_i=p_f[/tex]

where:

[tex]p=mv[/tex]

At the beginning the cars are stuck together and we can assume they are at rest; we know that after the explosion the velocity of the 1 kg car is -2 m/s; then we have:

[tex]\begin{gathered} (1+2)(0)=(1)(-2)+2v \\ 0=-2+2v \\ 2v=2 \\ v=\frac{2}{2} \\ v=1 \end{gathered}[/tex]

Therefore, the velocity of the 2 kg car is 1 m/s.

velocity differs from speed in that velocity indicates a particle's __________ of motion.

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velocity differs from speed in that velocity indicates a particle's Direction of motion.

For the majority of us, speed and velocity can be a little puzzling. Speed and velocity are different in that speed just gives us an indication of how quickly an object is going, whereas velocity not only tells us an object's speed but also the direction in which it is travelling. In contrast to velocity, which is defined as a function of displacement, speed can be defined as a function of the distance travelled. A body's instantaneous velocity is its speed right now. Average velocity is defined as total displacement divided by total time and is provided by the formula v = x/t, where x is the body's total displacement and t is the time. Average speed is never greater than average velocity, and vice versa.

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What is force equal to?

Answer 1:Mass plus acceleration

Answer 2:Mass minus acceleration

Answer 3:Mass multiplied by acceleration

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Mass multiplied by acceleration

Calculate the x-component and the y-component (in m) of the vector with magnitude 26.0 m and direction 45.0°.x = m y = m

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The components can be found as:

[tex]\begin{gathered} V_x=V\cdot\cos (45)=26\cdot\cos (45) \\ V_x=13\sqrt[]{2} \\ V_x\approx18.38m \\ ----------------------- \\ V_y=V\cdot\sin (45)=26\cdot\sin (45) \\ V_y=13\sqrt[]{2} \\ V_y\approx18.38m \end{gathered}[/tex]

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