60. In the given figure, PTR is tangent of a circle. If AT=PT and ZAPT=20°, what is the value of ZABT? ​

Answer:

  50 miles/1 hour = 50 miles/hour

Step-by-step explanation:

The fraction is reduced by dividing numerator and denominator by their common factor of 2.

  100 miles / (2 hours) = 50 miles/ (1 hour) = 50 miles/hour

I'll focus on part (b) only.

======================================================

Explanation:

Replace the variable b with the commonly used variable x and c with some other constant, let's say the letter m. These replacements will become apparent when we use the quadratic formula shortly later on.

After the replacements are made, we have -3c²-4cb+4b²​ turn into -3m²-4mx+4x²​

This is the same as 4x²​-4mx-3m²

Compare this to the format of ax²​+bx+c

We can see that

Once again, m is constant.

Let's compute the discriminant.

[tex]d = b^2 - 4ac\\\\d = (-4m)^2-4(4)(-3m^2)\\\\d = 16m^2+48m^2\\\\d = 64m^2\\\\[/tex]

This discriminant is under the square root as part of the quadratic formula.

So 4x²​-4mx-3m² would have roots of...

[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-b\pm\sqrt{d}}{2a}\\\\x = \frac{-(-4m)\pm\sqrt{64m^2}}{2(4)}\\\\x = \frac{4m\pm\sqrt{(8m)^2}}{8}\\\\x = \frac{4m\pm 8m}{8}\\\\x = \frac{4(m\pm 2m)}{4*2}\\\\x = \frac{m\pm 2m}{2}\\\\x = \frac{m+ 2m}{2} \ \text{ or } \ x = \frac{m-2m}{2}\\\\x = \frac{3m}{2} \ \text{ or } \ x = \frac{-m}{2}\\\\[/tex]

The whole time, the term "m" is treated as a constant. It is fixed to some unchanging number.

So why did we go through all that trouble to use the quadratic formula in the first place? It turns out that this formula is helpful to factoring quadratics. Recall that the roots of a polynomial tie very closely to its factorization.

For example, x²-4 factors to (x-2)(x+2) to have roots of x = 2 or x = -2. You could use the quadratic formula to solve x²-4 = 0 or x²+0x-4 = 0 and you should get x = 2 or x = -2 as the two solutions.

Anyways, back to the problem at hand.

Let's use the first root we found to form one of the factors needed.

The idea is to do a bit of algebra to get everything to one side. If fractions are present, then multiply both sides by the LCD to clear them out. We need to have 0 isolated on its own side.

[tex]x = \frac{3m}{2} \\\\ 2x = 3m\\\\ 2x-3m = 0[/tex]

So (2x-3m) is one factor

Through similar steps, you would find that the root [tex]x = \frac{-m}{2}[/tex] yields the factor of (2x+m)

Therefore, the factors are (2x-3m) and (2x+m)

------------------------------------

In summary so far, 4x²​-4mx-3m² factors to (2x-3m)(2x+m)

From here we replace x with b and replace m with c, so that we return back to the original variables used.

(2x-3m)(2x+m) becomes (2b-3c)(2b+c)

This can be confirmed using WolframAlpha. You could use the FOIL rule to expand out (2b-3c)(2b+c) and you should get 4b²​-4bc-3c²​ aka -3c²-4cb+4b²​

-------------------------------------

Those previous sections talked about part (i)

Part (ii) is where we plug in b = 4 and c = 3. In other words, we replace every copy of b with 4, and every copy of c with 3.

If you use the original expression, then,

-3c²-4cb+4b²​ = -3(3)²-4(3)(4)+4(4)²​ = -3(9)-4(12)+4(16) = -11

Or you could use the factored expression.

(2b-3c)(2b+c) = (2*4-3*3)(2*4+3) = (8-9)(8+3) = (-1)*(11) = -11

This very partially confirms that -3c²-4cb+4b² = (2b-3c)(2b+c) is indeed the case. Unfortunately you'd have to use infinitely many numeric examples to confirm the answer to part (i); however, something like the FOIL rule is far more efficient.

The computation shows that the time before

they can no longer communicate will be 10 minutes

From the information, it was stated that two hikerd are wandering through heavy woods with walkie talkies and that the walkie talkies have a range c of 100 yards.

It should be noted that after t hours, the distance between the hikers will be:

d² = (0.24t)² + (0.17t)² - 2(0.24t)(0.17t) cos 109.10°

d = 0.0568

Therefore, we will find the time when d = 0.0568. This will give a time of 10 minutes.

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Answer:

A     [tex] \dfrac{2x^3}{3yw} [/tex]

Step-by-step explanation:

[tex] \dfrac{xy(24x^2y^3w)}{36y^5w^2} = [/tex]

[tex] = \dfrac{2 \times 12 x^3y^4w}{3 \times 12y^5w^2} [/tex]

[tex] = \dfrac{2x^3}{3yw} [/tex]

Formula for the circumference of a circle is

[tex]c = \pi \: d[/tex]

where c is the circumference, and d is the diameter.

When diameter is 27-in, then

[tex]c1 = \pi \times 27[/tex]

When diameter is 25-in, then

[tex]c2 = \pi \times 25[/tex]

.: 27π-in – 25π-in is the farther distance.

Finding the difference, we have:

2π ≈ 6.28

.: 6.28-in is our final answer.

The x value or observed value corresponding to  z-score, z = 1.50 is 130.

According to the question.

For a population with µ = 100 and σ = 20.

Since,  we know that

The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.

And it is given by

z = (x - μ) / σ

Where,

x is the observed value.

μ is the mean.

and, σ is the standard deviation.

Therefore, the x value or observed value corresponding to z = 1.50 is given by

[tex]1.50 = \frac{x -100}{20}[/tex]

⇒ 1.50 × 20 = x - 100

⇒ 30 = x - 100

⇒ x = 30 + 100

⇒ x = 130

Hence, the x value or observed value corresponding to  z-score, z = 1.50 is 130.

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D box plot correctly represents the data

A box plot or boxplot is a technique for illustratively displaying the localization, dispersion, and skewness groups of numerical data through their quartiles.

Using a five-number summary (the minimum, first quartile (Q1), median, third quartile (Q3), and "maximum"), a boxplot is a common method of visualizing data distribution.

The median value for the provided data will be the sixth data point's value, or 3.

The median of the data's lower half is now the first quartile. The third data point's value of 1 will therefore be in the lower quartile.

The median of the data's upper half is now referred to as the upper or third quartile. This means that the value of the ninth data point, which is 6, will represent the upper quartile.

Thus, box-plot D effectively displays the data from above.

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Answer:

The answer is D.

Edg 2023.

Answer:

Graph b

Step-by-step explanation:

y = |x| is a "v"at x = 0

y = |x-1| is a "v" shifted to the right by 1 unit

The amount saved in 10 years is = $1,04,461.13

The correct option is B.

An annuity is a series of payments that are distributed evenly over time.

One way to express the future value of an annuity of payment P for n years is,

Total salary is $65000

The interest rate is 5.32%

Trent save 8%  of his salary every year.

Company puts  4.6% of salary every year.

[tex]\text { Future Value }=\mathrm{P} \times \frac{\left(1+\frac{i}{n}\right)^{n t}}{\frac{i}{n}}[/tex]

Given:

Total salary is $65000

The interest rate is 5.32%

Trent save 8% of his salary every year.

Company puts  4.6%of salary every year.

The 8% of salary is calculated as:

[tex]\text { Amount } &=\frac{8}{100} \times 65000\\[/tex]

               [tex]&=\$ 5200[/tex]

The following information is available on the company's put:

[tex]\text { Amount } &=\frac{4.6}{100} \times 65000\\[/tex]

                [tex]&=\$ 2990[/tex]

Total amount as follows:

[tex]\begin{aligned}\text { Amount } &=5200+2990 \\&=\$ 8190\end{aligned}[/tex]

The future value can be obtained as follows

[tex]\begin{aligned}\mathrm{FV} &=8190 \times \frac{(1+0.053)^{10}-1}{0.053} \\&=8190 \times 12.75 \\&=1,04,461.13\ \\\end{aligned}[/tex]

Hence, the amount saved in 10 years is = $1,04,461.13

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The direction of the parabola is determined by the leading coefficient of the polynomial (a > 0 - Upwards, a < 0 - Downwards). The y-intercept of the polynomial is c and the two zeros of the polynomial are x = - b / (2 · a) ± [1 / (2 · a)] · √(b² - 4 · a · c).

Herein we have a quadratic equation of the form f(x) = a · x² + b · x + c. To determine the direction of the parabola, we must transform this expression into its vertex form and looking for the sign of the vertex constant:

f(x) = a · x² + b · x + c

f(x) = a · [x² + (b / a) · x + (c / a)]

f(x) + b² / (4 · a) - c = a · [x² + (b / a) · x + b² / (4 · a²)]

f(x) + b² / (4 · a) - c = a · [x + b / (2 · a)]²

If a > 0, then the direction of the parabola is upwards, but if a < 0, then the direction of the parabola is downwards.

The y-intercept is found by evaluating the quadratic equation at x = 0:

f(0) = a · 0² + b · 0 + c

f(0) = c

And the zeros are determined by the quadratic formula:

x = - b / (2 · a) ± [1 / (2 · a)] · √(b² - 4 · a · c)

The direction of the parabola is determined by the leading coefficient of the polynomial (a > 0 - Upwards, a < 0 - Downwards). The y-intercept of the polynomial is c and the two zeros of the polynomial are x = - b / (2 · a) ± [1 / (2 · a)] · √(b² - 4 · a · c).

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The total surface area of the square pyramid (SA) = 144 yd².

A square pyramid is a solid shape that has a square base and four rectangular lateral faces.

The total surface area of a square pyramid is the sum of the area of its square base and four rectangular lateral faces. To find the total surface area, the following formula is used:

Total surface area of a square pyramid (SA) = A + 1/2(Pl), where:

Given the following:

Area of base (A) = 8² = 64 yd²

Perimeter of base (P) = 4(8) = 32 yds

Slant height of pyramid (l) = 5 yds

Plug in the values

Total surface area of a square pyramid (SA) = 64 + 1/2(32)(5)

Total surface area of a square pyramid (SA) = 64 + 80

Total surface area of a square pyramid (SA) = 144 yd².

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Answer:

false

Step-by-step explanation:

Answer:

False

Step-by-step explanation:

The net of a cylinder has a rectangle for the lateral area and 2 circles for the bases, so it has 3 parts.

Answer: False

The area of the missing slice is 15 inches ²

From the information given, we can see that the pizza takes the form of a circle;

Area of the missing slice takes the shape of a triangle

Area of a triangle = 1/ 2 base × height

base = 10 inches

height = 3 inches

Area of missing slice = 1/ 2 × 10 × 3

Area = 1/ 2 × 30

Area = 15 inches ²

Thus, the area of the missing slice is 15 inches ²

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The solution to 0.5^(x + 2) > 9 is x  > -5.170

The inequality expression is given as:

0.5^(x + 2) > 9

Take the logarithm of both sides of the inequality expression

log(0.5^(x + 2)) > log(9)

Rewrite the inequality expression as

(x + 2)log(0.5) > log(9)

Divide both sides by log(0.5)

x + 2 > -3.170

Subtract 2 from both sides

x  > -5.170

Hence, the solution to 0.5^(x + 2) > 9 is x  > -5.170

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Answer:

1-21>151 and -2>5

I think so.

X is the number of songs and Y the number of pics

our 2 equations will be - X+y=11 & 4x+2y=24

consider x=11-y

Lets replace x in 2:

=4(11-y) +2y=24

=44-4y+2y=24

=44-24= 4y-2y

=20= 2y

=Y=20/2

=Y=10

Lets replace y in 1

=X+10=11

=X=11-10

=X=1

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By using the digits 0 to 9, the boxes are filled with their respective numerical values to make the chart accurate as shown in the image attached below.

A function can be defined as a mathematical expression which is used to define and represent the relationship that exists between two or more variables.

In Mathematics, there are different types of functions and these include the following;

A logarithm function can be defined as a type of function that represents the inverse of an exponential function. Mathematically, a logarithm function is written as follows:

y = logₐₓ

y = log₁₀10

y = log₁₀10 = 1.  

Therefore, if log₁₀x < 1, then, x < 10.  Also, if log₁₀x > 1, then, x > 10.

For this exercise, you should take note of this deductive points:

In conclusion, by using the digits 0 to 9, the boxes are filled with their respective numerical values to make the chart accurate as shown in the image attached below.

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The initial-value is  x(t)=F0/2w^2 (sin wt-wt cos wt)

An initial-value hassle is a differential equation wherein is an open set of, together with a point within the domain called the initial situation. A technique to an initial cost hassle is a function that is a technique to the differential equation and satisfies.

Inside the discipline of differential equations, preliminary cost trouble (additionally called Cauchy trouble by using a few authors) is a normal differential equation collectively with a detailed fee, called the preliminary situation, of the unknown function at a given factor in the domain of the solution.

In multivariable calculus, an initial-value hassle is a normal differential equation collectively with a preliminary circumstance that specifies the fee of the unknown characteristic at a given factor in the area. Modeling a system in physics or different sciences often amounts to fixing an initial cost problem.

Consider a differential equation x+x=F, sin wt, x(0) = 0,X(0) = 0

Apply Laplace transformation on both sides, and we get

(s²L{x(t)}-sy(0)-y'(0)) + w²L {x(t)} =·

Fow

Fow

(s² + w² ) { x(t)} = 3 + w²

L{x(t)}=

Fow

(5²+w²)²

x(t)=FwL

[(s² + w²)²]

Fow

x(t)=(sin wt-wt coswt)

2w

x(t)=

Fo

wtcos

2w (sin wt-wt cos wt),

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Answer:

First number = 33, Second number = -19

Step-by-step explanation:

We can use F to represent the first number and S to represent the second number.

Our two equations then are F + S = 14 and 2F + 3S = 9

We can use substitution:

[tex]F+S = 14\\2F+3S=9\\F=14-S\\2(14-S)+3S=9\\28-2S+3S=9\\28+S=9\\S=-19\\\\F-19=14\\F=33[/tex]

Answer: [tex]\Large\boxed{Total~area=586.17~cm^2}[/tex]

Step-by-step explanation:

Given information

[tex]Height=7~cm[/tex]

[tex]Base=18~cm[/tex]

Given formula

[tex]A=b\times h\times\dfrac{1}{2}[/tex]

[tex]A=Area\\b=base\\h=height\\[/tex]

Substitute values into the formula

[tex]A=(7)\times (18)\times\dfrac{1}{2}[/tex]

Simplify by multiplication

[tex]A=(7)\times 9[/tex]

[tex]A=63~cm^2[/tex]

Given information

[tex]Height = 18~cm[/tex]

[tex]Base=22~cm[/tex]

Given formula

[tex]A=b\times h[/tex]

[tex]A=Area\\b=base\\h=height\\[/tex]

Substitute values into the formula

[tex]A=(22)\times (18)[/tex]

Simplify by multiplication

[tex]A=396~cm^2[/tex]

Given information

Diameter = 18 cm

Given formula

[tex]A=(\dfrac{d}{2} )^2\times \pi \div2[/tex]

[tex]A=Area\\d=diameter[/tex]

Substitute values into the formula

[tex]A=(\dfrac{18}{2} )^2\times (3.14) \div2[/tex]

Simplify the fraction

[tex]A=(9 )^2\times (3.14) \div2[/tex]

Simplify the exponents

[tex]A=81\times (3.14) \div2[/tex]

Simplify by multiplication

[tex]A=254.34\div2[/tex]

Simplify by division

[tex]A=127.17~cm^2[/tex]

Given formula

[tex]Total~area=Triangle+Rectangle+circle~(half)[/tex]

Substitute values into the formula

[tex]Total~area=(63)+(396)+(127.17)[/tex]

Simplify by addition

[tex]Total~area=459+(127.17)[/tex]

[tex]\Large\boxed{Total~area=586.17~cm^2}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

2, x - 2, x + 4

Step-by-step explanation:

The factors of the given quadratic expression, 2x² - 4x - 16, are 2, (x +2), and (x -4)

From the question, we are to determine the each of the factors of the given quadratic expression

The given quadratic expression is

2x² - 4x - 16

Factoring

2x² - 4x - 16

First, factor out 2

That is,

2(x² - 2x - 8)

Now, we will factor x² - 2x - 8
x² - 2x - 8

x² - 4x + 2x - 8

x(x - 4) +2(x -4)

(x +2)(x -4)

Thus,

2x² - 4x - 16  = 2(x +2)(x -4)

Hence, the factors of the given quadratic expression, 2x² - 4x - 16, are 2, (x +2), and (x -4)

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The total amount spent by Elsa and her friends must not exceed RM 475; 475 ≤ x

Elsa + 3(her friends) ≤ Total

145 + 3(110) ≤ x

145 + 330 < x

475 ≤ x

Therefore, the total amount spent by Elsa and her friends must not exceed RM 475; 475 ≤ x

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we can simply take the whole amount of 30 and divide it by (4 + 1), then distribute to each side accordingly, since they're in a 4 to 1 ratio.

[tex]\underset{\hspace{5em}4~\hfill to~\hfill 1\qquad }{\stackrel{\text{\LARGE 30}}{C\rule[0.35em]{18em}{0.25pt}E\rule[0.35em]{10em}{0.25pt}D}} \\\\\\ \stackrel{CE}{4\left( \frac{30}{4+1} \right)} ~~ : ~~ \stackrel{ED}{1\left( \frac{30}{4+1} \right)}\implies \stackrel{CE}{4\left( 6 \right)} ~~ : ~~ \stackrel{ED}{1\left( 6 \right)}\implies \stackrel{CE}{\text{\LARGE 24}} ~~ : ~~ \stackrel{ED}{\text{\LARGE 6}}[/tex]

Answer:

Step-by-step explanation:

Use the distributive property.

Distributive property is a serving to distribute or allot or disperse.

Distributive property:

A(B+C)=AB+AC

A(B-C)=AB-AC

-10(1-9x)+6(x-10)

Expand.

-10(1-9x)

-10*1=-10

-10*9x=90x

[tex]\longrightarrow \sf{=-10+90x+6\left(x-10\right)}}[/tex]

6(x-10)

6*x=6x

6*10=60

6x-60

Rewrite the problem down.

= -10+90x+6x-60

Combine like terms.

90x+6x-10-60

Add the numbers from left to right.

90x+6x=96x

96x-10-60

Finally, subtract the numbers from left to right.

-10-60=-70

[tex]\Longrightarrow \boxed{\sf{96x-70}}[/tex]

Therefore, the final answer is 96x-70.

I hope this helps, let me know if you have any questions.

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Distributive Property :

[tex]-10(1-9x)+6(x - 10)[/tex]

[tex]-10(-9x+1)+6(x - 10)[/tex]

[tex]90x-10+6x-60[/tex]

[tex]90x-70+6x[/tex]

[tex]96x-70[/tex]

[tex]answer : \boxed{\pink\star\tt{96x-70}}[/tex]

━━━━━━━━━━━━━━━━━━━━━━━━

Common factor :

[tex]- 10(1 - 9x) + 6(x - 10)[/tex]

[tex]96x - 70[/tex]

[tex]2(48x - 35)[/tex]

[tex] answer : \boxed{ \pink \star\tt{2(48x - 35)}}[/tex]

Answer: D

Step-by-step explanation:

If the leading coefficient is negative, then as [tex]x \to \infty[/tex], [tex]f(x) \to -\infty[/tex].

If the leading coefficient is negative, then as [tex]x \to -\infty[/tex], [tex]f(x) \to \infty[/tex].

This leaves D as the correct answer.

Answer:

following the (x,y) coordinate system,

(0,4) ; (1,1) ; (2,-2)

Step-by-step explanation:

youre given the value of the x variable in the table, so all you need to do is substitute x and follow pedmas!! hope this helps<3

Answer: 4096.

Step-by-step explanation:

[tex](8^3)^8\div(8^4)^5=\\8^{3*8}\div8^{4*5}=\\8^{24}\div8^{20}=\\8^{24-20}=\\8^4=\\4096.[/tex]

Answer:

5/52

Step-by-step explanation:

There are 52 cards in a deck, with 26 red and 26 black cards. There are 2 red ones, 2 black threes, and 1 six of hearts. The # of favorable outcomes is 2 + 2 + 1 = 5, so the answer is 5/52.

The intervals which represents those in which case the function, f(x) is reducing are as follows; [–2.5, –2], [–2, –1.5], [1.5, 2], [2, 2.5].

It follows from the complete task content that the x-intervals between which the function value of f(x) is reducing are to be identified from the graph as attached.

On this note, by observation on the graph, it follows that from between the interval; [–2.5, –2], the function f(x) is decreasing.

Also, between the interval; [–2, –1.5], the function f(x) is decreasing.

Also, between the interval; [1.5, 2], the function f(x) is decreasing.

Also, between the interval; [2, 2.5], the function f(x) is decreasing.

Remark: The answer choices are as follows; [–2.5, –2] [–2, –1.5] [–1, 1] [1.5, 2] [2, 2.5) [2.5, 3]

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