Answer:
Explanation:
Problem relates to diffraction of light . Location for 2 nd diffraction minima is
[tex]x=2\times\frac{\lambda D}{d}[/tex] where λ is wavelength of light , D is distance of screen , d is slit width .
Puting the values
[tex]x=2\times\frac{620D}{d}[/tex]
for unknown wavelength , position of third diffraction is
[tex]x=3\times\frac{\lambda D}{d}[/tex]
from these two equations
[tex]x=2\times\frac{620D}{d}[/tex][tex]=3\times\frac{\lambda D}{d}[/tex]
λ = 413.33 nm .
Q7:
A 4 kg toy is lifted off the ground and falls at 3 m/s. What is the toy's energy?
Answer:
The toy's energy is 18 J.
Explanation:
We have, a 4 kg toy is lifted off the ground and falls at 3 m/s. It is required to find toy's energy.
The toy will have kinetic energy due to its motion. The energy is given by :
[tex]E=\dfrac{1}{2}mv^2\\\\E=\dfrac{1}{2}\times 4\times 3^2\\\\E=18\ J[/tex]
So, the toy's energy is 18 J.
Two astronomers are discussing supernovas. Dr. Frank says, "Research has established that if a supernova occurs within ten light-years of the Earth, then life on Earth will be destroyed." Dr. Harris says, "Research has also established that either a supernova will not occur within ten light-years of the Earth or life on Earth will not be destroyed." Is it possible that both astronomers are correct? If so, what can we determine about the occurrence of a supernova?
Answer:
Supernovae produce intense flashes of light that can last from several weeks to several months. They are characterized by a rapid increase in light intensity until reaching an absolute magnitude greater than the rest of the galaxy. Subsequently, its brightness decreases more or less smoothly until it disappears completely.
Explanation:
A team of international astronomers discovered that if the supernovae were found at a distance of 50 light years from Earth, they could cause the mass extinction of living things, according to an article published in the Astrophysical Journal.
"Until recently, our colleagues believed that the 'range' of supernovae was about 25 light years. We were of the opinion that they did not take into account a number of factors and that it is actually about 50 light years," Adrian said. Melott, from the University of Kansas at Lawrence (USA).
The unusually high power of cosmic rays in the atmosphere, according to Melott, results in an increase in the "damage radius" of supernovae. According to the researcher, supernova explosions are capable of destroying life within a radius of 50 light years and not 10 or 25 light years, as previously thought.
(20) A rocket is launched vertically. At time t = 0 seconds, the rocket’s engine shuts down. At the time, the rocket has reached an altitude of 500m and is rising at a velocity of 125 m/s. Gravity then takes over. The height of the rocket as a function of time is h(t)=-9.8/2 t^2+125t+500,t>0. Using your function file from HW2A: Generate a plot of height (vertical axis) vs. time (horizontal axis) from 0 to 30 seconds. Include proper axis labels. Find the maximum height and the time at which it occurs: Analytically, showing your steps and equations. This part should be done entirely in the write-up: no coding Using the data cursor on the plot. Using the MAX function on your data from part (a) Using FMINSEARCH on your m file Comment on the differences between the methods. How closely does each method match the "true" (analytical) value? Find the time when the rocket hits the ground: Analytically, showing your equations. This part should be done entirely in the write-up: no coding Using the data cursor on the plot. Using FZERO on your m file Comment on the differences between the methods in each of part (B) and (C). How closely does each method match the "true" (analytical) value? Use a quantitative comparison to make your argument.
Answer:
Explanation:
Given that,
h(t) = -9.8t² / 2 + 125t + 500
for t > 0.
At t = 0, the rocket is at height h = 500m, at a velocity of Vo = 125m/s.
We want to find the maximum height reached by rocket
Using mathematics maxima and minima
let find the turning point when dh/dt = 0
dh/dt = -9.8t + 125
dh / dt = 0 = -9.8t + 125
9.8t = 125
t = 125 / 9.8
t = 12.76s
Let find the turning point to know if this time t = 12.76 is maximum or minimum point
Let find d²h / dt²
d²h / dt² = -9.8
Since, d²h/dt² < 0, then, at t = 12.76s is the maximum points.
Then, the maximum height reached is
h = -9.8t² / 2 + 125t + 500
h = -9.8(12.76)² / 2 + 125(12.76) + 500
h = -797.80 + 1595 + 500
h = 1297.2 m
The maximum height reached is 1297.2 m
From the attachment, the maximum height is 1297.2m at t = 12.76sec.
Comment, the result are the same for both the analysis aspect and the graphical aspect.
In later years, motors improved and could be run directly from a 60 Hz power supply. As a result, 25 Hz power systems shrank and disappeared. However, there were many perfectly-good working 25 Hz motors in factories around the country that owners were not ready to discard. To keep them running, some users created their own 25 Hz power in the plant using motor-generator sets. A motor generator set consists of two machines connected on a common shaft, one acting as a motor and the other acting as a generator. If the two machines have different numbers of poles but exactly the same shaft speed, then the electrical frequency of the two machines will be different due to Equation (3-34). What combination of poles on the two machines could convert 60 Hz power to 25 Hz power?
Answer:
as in motor generaror are connected to same shaft then both machines are working with same speed
but number of poles are different with same speed means both machines are working with different frequencies
we know
frequency F = N*P/120
speed N = 82120F/P
given
motor speed = generator speed
120F1/P1 = 120F2/P2
F1/P1 = F2/P2
output frequency is 25 which is obtained from generator so F2=25
input frequency is 60 which is given to motor soF1=60
60/P1 = 25/P2
60/25 = P!/P2
P1/P2 = 12/5
multiply and divided by 2 becuase poles are even
P1/P2 = 12*2/5*2
=24/10
P1= 24 poles a
P2 =10 poles we get 25 hz frequency from 60 hz frequency
A firearms company is testing a new model of rifle by firing a 7.50-g lead bullet into a block of wood having a mass of 17.5 kg. The bullet embeds into the block and the collision generates heat. As a consequence, the temperature rises by 0.040°C, as measured with a high-precision thermometer. Assuming that all the kinetic energy of the bullet goes into heating the system, what is the bullet’s speed when it enters the block? The initial temperatures of bullet and wooden block can be considered identical and the specific heats of lead and wood are cPb = 130 J/(kg ⋅ C°) and c wood = 1700 J/(kg ⋅ C°), respectively.
Answer:
Explanation:
Let the bullets speed be V .
Kinetic energy = 1/2 mV² where m is mass of bullet
This energy is converted into heat Q which raises the temperature of target by Δ T .
Q = mc Δ T , m is mass , c is specific heat and Δ T is rise in temperature .
heat absobed by bullet
= .0075 x 130 x .040
= .039 J
heat absorbed by block of wood
= 17.5 x 1700 x .04
= 1190 J
Total heat absorbed
= 1190.039 J
So kinetic energy = heat absobed
= 1/2 x .0075 x V² = 1190.039
V² = 317343.73
V = 563.33 m /s
Explain how an electrical current is produced.
Answer:electric current can be generated by moving a metal wire through a magnetic field .electric current can also be produced by batteries
Explanation:
electric current can be generated by moving a metal wire through a magnetic field.this method is applicable in electric generators.
Electric current can also be generated by connecting metal wires to batteries.
Under electrostatic conditions, the electric field just outside the surface of any charged conductor
A. is always zero because the electric field is zero inside conductors
B. can have non zero components perpendicular to and parallel to the surface of the conductor
C. is always perpendicular to the surface of the conductor
D. is always parallel to the surface
E. is perpendicular to the surface of the conductor only if it is a sphere, a cylinder, or a flat sheet.
Answer:
C. is always perpendicular to the surface of the conductor
Explanation:
On a charged conductor , electric charge is uniformly distributed on its surface . The lines of forces are also uniformly distributed on all directions . They repel each other so they emerge perpendicular to the surface so that they do nor cut each other and at the same time they remain at maximum distance from each other.
The spaceship Lilac, based on the Purple Planet, is 721 m long when measured at rest. When the Lilac passes Earth, observers there measure its length to be 661 m. At what speed v is the Lilac moving with respect to Earth? Express your answer as a multiple of the speed of light c.
Answer:
The speed of Lilac is 0.399c.
Explanation:
The size of spaceship Lilac measured at the rest position = 721 m
The length of Lilac when it passes Earth = 661 m
Below is the calculation for speed at which Lilac is moving.
Here, L, is the length of spaceship when it passes the earth.
[tex]L_{0}[/tex] is the length of spaceship measured at rest.
V is the speed.
[tex]L = L_{0}\sqrt{1-\frac{v^{2}}{c^{2}}} \\[/tex]
[tex]1-\frac{v^{2}}{c^{2}} = \left ( \frac{L}{L_{0}} \right )^{2} \\[/tex]
[tex]\frac{v}{c} = \sqrt{1-\left ( \frac{L}{L_{0}} \right )^{2}} \\[/tex]
[tex]\frac{v}{c} = \sqrt{1-\left ( \frac{661}{721} \right )^{2}} \\[/tex]
[tex]v = 0.399c[/tex]
Einstein developed much of his understanding of relativity through the use of gedanken, or thought, experiments. In a gedanken experiment, Einstein would imagine an experiment that could not be performed because of technological limitations, and so he would perform the experiment in his head. By analyzing the results of these experiments, he was led to a deeper understanding of his theory. In each the following gedanken experiments, Albert is in the exact center of a glass-sided freight car speeding to the right at a very high speed vvv relative to you. Albert has a flashlight in each hand and directs them at the front and rear ends of the freight car. Albert switches the flashlights on at the same time.
In Albert's frame of reference, which beam of light travels at a greater speed, the one directed toward the front or the one toward the rear of the train, or do they travel at the same speed? Which beam travels faster in your frame of reference? Enter the answers for Albert's frame of reference and your frame of reference separated by a comma using the terms front, rear, and same. For example, if in Albert's frame of reference the beam of light directed toward the front of the train travels at a greater speed and in your frame of reference the two beams travel at the same speed, then enter front,same.
Answer:
For eintein's frame of reference, both beam travel at the same speed.
For my own frame of reference, both beams travel at the same speed.
Explanation:
According to special relativity, the speed of light is the same in all direction on all reference frame. If not for this law we will assume the from beam will have a relative speed that will be the speed of light plus the speed of the fright car. This is not so and it violates the speed limit of light which according to the first law is the highest speed possible and nothing can go beyond that.
use the formula P=IV to detine how much current is a 120-watt light bulb is connected to a 120-V outlet
Answer:
1 A
Explanation:
P = IV
120 W = I (120 V)
I = 1 A
What is the major difference between herbal and conventional medicines
What happens if you move a magnet near a could of wire
Answer:
The wire would stick to the magnet????????????????????????
Explanation:
Minority group
A shared identity based on
cultural elements such as
heritage, language, and
religion
Ethnicity
A socially constructed
group of people who share
physical characteristics
that are considered
significant by a society
and that are used to
distinguish them from
other groups
Majority group
People who are singled
out for unequal treatment
and who regard
themselves as objects of
collective discrimination
Race
A group's subset that
consists of more than half
of the entire group's
members
Answer:
Minority group - People who are singled out for unequal treatment and who regard themselves as objects of collective discrimination.
Ethnicity - A shared identity based on cultural elements such as heritage, language, and religion.
Majority group - A group's subset that consists of more than half of the entire group's members.
Race - A socially constructed group of people who share physical characteristics that are considered significant by a society and that are used to distinguish them from other groups.
Explanation:
To better understand the above-mentioned definitions we would use some examples:
Elder people can be considered as a minority group in the United States because of their reduced status as a consequence of popular discrimination and prejudice against them. In contrast to them, young men consisting of more than half the population in the age category is an example of the majority group.
Groups of people like Hispanic Americans, Jews, Italian America, Irish are some examples of people belonging to different ethnic backgrounds residing in the U.S.
African Americans who are distinguished based on their skin color is an example of race.
1. When in the past have you pushed your personal limits? Give at least one
example. How did it affect you? (5 points)
Answer:
Umm that's a personal question. All u have to do is say when have u pushed your personal limits....... Ummm one for me is when i had to try out for a select soccer and that is past my comfort zone.
Explanation:
Answer:
You typically push past your personal limits when you are tired or worn out. As an athlete I tend to do this a lot, whether it’s in practice or in a game. One time I pushed past my personal limits is when I came back home to play football (soccer) on break, and ended up playing in a tournament with my team. We had made it to the finals and the other team had their two biggest, most physical guys marking me. They ended up stepping on my foot a few times and getting a bit too physical resulting in fouls, which I typically shrugged off, but one time they got me right in my toe joint. This made it extremely difficult to run and kick the ball due to the severe pain in my strong foot. I was also really tired considering I had been putting a lot of effort into making runs as a winger. To make matters even worse, my team had nobody to sub on for me, considering I’m the only one my coach uses for left wing. I ended up playing through these conditions and winning the tournament with my team, however I ended up being injured for the next 1-2 weeks.
This is more of a personal question but since you asked I'll answer
A fisherman fishing from a pier observes that the float on his line bobs up and down, taking 2.4 s to move from its highest point to its lowest point. He also estimates that the distance between adjacent wave crests is 48 m. What is the speed of the waves going past the pier?Immersive Reader
Answer:
v = 10 m / s
Explanation:
For this exercise we will use the relationship between the speed of a wave and its frequency and wavelength
v = λ f
the wavelength is the distance at which the wave repeats, in this case the distance between the two ridges λ = 48 m.
the frequency is the number of oscillations per unit of time, it is also the inverse of the period which is the time in a complete oscillation, in this case they give us the time of half a period, ½ T = 2.4 s
T = 4.8 s
the frequency is
f = 1 / T
f = 1 / 4.8
f = 0.2083 Hz
let's calculate
v = 0.2083 48
v = 10 m / s
A landscaper is shopping for landscaping materials. She wants to use materials through which water flows easily.
Which materials should she choose? Select three options.
clay
gravel
granite
rocks with cracks
loosely packed soil
Next
Mark this and retum
Save and Exit
Submit
Answer:
He needs clay gravel and rocks with cracks
3. The current in a flashlight powered by 4.5 Volts is 0.5 A. What is the power delivered to the flashlight?
4.If the flashlight in the previous problem is left on for 3 minutes, how much electric energy is delivered to the bulb?
Answer:
Question 3: 2.25 watts
Question 4: 405 joules
Explanation:
question 3:
Current =0.5 amps
Voltage =4.5 volts
Power= current x voltage
Power=0.5 x 4.5
power=2.25 watts
Question 4
Current =0.5 amps
Voltage =4.5v
Time=3 minutes
Time =3x60
Time =180 seconds
Energy=current x voltage x time
Energy =0.5 x 4.5 x 180
Energy =405 joules
plzzz help will mark the brainliest
Geologists have divided rocks into three different categories based on ______
28.18. Consider two conducting spheres with one having a larger radius than the other. Both spheres carry the same amount of excess charge. Which one of the following statements concerning the electric potential of the two spheres is true?a) The electric potential of the larger sphere is greater than that of the smaller sphere.b) The electric potential of the larger sphere is the same as that of the smaller sphere.c) The electric potential of the larger sphere is less than that of the smaller sphere.
Answer:
b) The electric potential of the larger sphere is the same as that of the smaller sphere
Explanation:
An electric potential is the amount of work needed to move a unit of charge from a reference point to a specific point inside the field without producing an acceleration. The reference point is typically the Earth or a point at infinity, although any point can be used.
It is proportional to the charge on a particle and inversely proportional to its relative distance to the electric field.
E = kQ/r
Where k = 1/4¶E°
Where E° is permittivity of free space 8.85x10^-12 F/m
A piston with stops containing water goes through an expansion process through the addition of heat. State 1 the pressure is 200 kPa and the volume is 2 m3. After half of the heat has been delivered the piston hits the stops corresponding to a volume of 5 m3. After all the heat has been delivered, state 2, the pressure is 1000 kPa with the piston resting on the stops. What is the work?
Answer:
The work will be "600 kJ/kg".
Explanation:
(1-a) ⇒ Constant Pressure
(a-2) ⇒ Constant Volume
The given values are:
In state 1,
Pressure, P₁ = 200 kPa
Volume, V₁ = 2m³
In state 2,
Pressure, P₂ = 1000 kPa
Volume, V₁ = 5m³
Now,
In process (1-a), work will be:
⇒ W₁₋ₐ = P₁(Vₐ - V₁)
On putting the values, we get
⇒ W₁₋ₐ = 200(5-2)
⇒ = 200(3)
⇒ = 600 kJ/kg
In process (a-2), work will be:
⇒ Wₐ₋₂ = 0
∴ (The change in the volume will be zero.)
So,
⇒ Total work = (W₁₋ₐ) + (Wₐ₋₂)
⇒ = 600 + 0
⇒ = 600 kJ/kg
The greater the distance between two objects in space, the _______ their gravitational
Answer is Weaker. If it is talking about the objects' gravitational forces.
An object has a mass of 5 kg. What force is needed to accelerate it at 6 m/s?
Answer:30N
Explanation:
Mass=5kg
Acceleration=6m/s^2
Force=mass x acceleration
Force=5 x 6
Force=30N
Answer:
30n
Explanation:
Mass=5kg
Acceleration=6m/s^2
Force=mass x acceleration
Force=5 x 6
Force=30N
19
Which gas is the most abundant greenhouse gas?
A.
ozone
B.
chlorofluorocarbon
C.
carbon dioxide
OD.
methane
E.
water vapor
Reset
Next
Carbon dioxide is the most abundant greenhouse gas in the atmosphere.
Answer:C
Explanation:
Carbon dioxide is the most abundance greenhouse gas in The atmosphere.
In a double-slit interference experiment, which of the following actions (perhaps more than one) would cause the fringe spacing to increase? (a) Increasing the wavelength of the light. (b) Increasing the slit spacing. (c) Increasing the distance to the viewing screen. (d) Submerging the entire experiment in water
Answer:
The correct option is a , c
Explanation:
Generally the fringe spacing is mathematically defined as
[tex]y = \frac{m \lambda D}{d}[/tex]
Where y is the fringe spacing
m is the order of the fringe
[tex]\lambda[/tex] is the wavelength
D is the distance between the slit and the screen
d is the distance between the slit
Now in order to increase the fringe spacing can do the following
Increase the wavelength increase the distance from the slit to the screen Decrease the distance between the slitThe following action would increase the fringe spacing because the from the question these parameters are directly proportional to the fringe spacing
You expend 1000 W of power in moving a piano 5 meters in 5 seconds. How much force did you exert?
Answer:B
Explanation:
Power=1000 watts
Time=5 seconds
Distance=5 meters
Force=(power x time) ➗ distance
Force=(1000 x 5) ➗ 5
Force=5000 ➗ 5
Force=1000
Force=1000N
Answer:1,000
Explanation:
ape.x
Q8.(10 points) a)When you cough,the radius of your trachea (windpipe) decreases,affecting the speed of the air in the trachea. If 0 r is the normal radius of the trachea, the relationship between the speed S of the air and the radius r of the trachea during a cough is given by a function of the form 2 0 S r ar r r ( ) ( ) = − , where a is positive constant. Find the radius r for which the speed of the air is greatest
Answer:
[tex]\bf{r=\frac{2r_o}{3}}[/tex] is greatest
Explanation:
Given:
[tex]S(r)=ar^2(r_{o}-r)[/tex]
[tex]\frac{ds}{dr}=2ar(r_{o}-r)+ar^2(-1)[/tex]
[tex]\frac{ds}{dr}=2ar_{o}-2ar^2-ar^2[/tex]
[tex]\frac{ds}{dr}=2ar_{o}-3ar^2[/tex]
Substitute [tex]\frac{ds}{dr} = 0[/tex], so
[tex]2ar_{o}-3ar^2=0[/tex]
Then, get the common value from the equation.
[tex]ra(2r_{o}-3r) = 0[/tex]
[tex]\bf{r=0}\\r=\frac{2r_{o}}{3}[/tex]
[tex](\frac{d^2s}{dr^2})_{r=0}=2ar_{o}-6ar[/tex]
[tex](\frac{d^2s}{dr^2})_{r=0}=2ar_{o} >0\;and, \\(\frac{d^2s}{dr^2})_{r}=\frac{2r_o}{3} <0[/tex]
So, the speed of the air is greatest.
[tex]\bf{r=\frac{2r_o}{3}}\;is\;greatest[/tex]
A cylindrical specimen of some metal alloy having an elastic modulus of 108 GPa and an original cross-sectional diameter of 3.7 mm will experience only elastic deformation when a tensile load of 1890 N is applied. Calculate the maximum length of the specimen before deformation if the maximum allowable elongation is 0.45 mm.
Answer:
L= 276.4 mm
Explanation:
Given that
E= 180 GPa
d= 3.7 mm
F= 1890 N
ΔL= 0.45 mm
We know that ,elongation due to load F in a cylindrical bar is given as follows
[tex]\Delta L =\dfrac{FL}{AE}[/tex]
[tex]L=\dfrac{\Delta L\times AE}{F}[/tex]
Now by putting the values in the above equation we get
[tex]L=\dfrac{0.45\times 10^{-3}\times \dfrac{\pi}{4}\times (3.7\times 10^{-3})^2\times 108\times 10^9}{1890}\ m[/tex]
L=0.2764 m
L= 276.4 mm
Therefore the length of the specimen will be 276.4 mm
"You throw a small rock straight up from the edge of a highway bridge that crosses a river. The rock passes you on its way down, 9.00 s after it was thrown. What is the speed of the rock just before it reaches the water 21.0 m below the point where the rock left your hand
Answer:
48.54 m/s
Explanation:
If the rock takes 9 seconds to reach your position after being thrown, it reaches its maximum height in 4.5 seconds.
The height the rock reaches above your position is ...
h = (1/2)gt^2 = (4.9 m/s^2)(4.5 s)^2 = 99.225 m
This height is an additional 21 m above the water, so the maximum height above the water is ...
99.225 m +21.0 m = 120.225 m
The velocity (v) achieved when falling from this distance is found from ...
v^2 = 2gh
v = √(2(9.8)(120.225)) = √2356.41 ≈ 48.543 . . . . m/s
The speed of the rock when it hits the water is about 48.54 m/s.
Visible light travels in air, which has an index of refraction of 1.0. It is incident on plastic which is covered by a coating (such that light hits the coating before the plastic). The coating has an index of refraction of 1.6 and is 0.50 microns thick. The ray reflected off the air-coating interface and the ray reflected off the coating-plastic interface experience interference. What frequencies could the light be
Answer:
λ = 0.64 10⁻⁶ m = 640 nm
Explanation:
The two reflected rays experience constructive interference, if we can see them, so we can one condition for interference, but let's see two phenomena that occur
* A ray when it is reflected by a surface of major spare part index has a phase change of 180º, these passes at the air-plastic interface
* A ray when passing a material with a refractive index changes its wavelength
λ= λ₀ / n
taking into account these facts the condition in constructive interference is
2 n t = (m + ½) λ
λ= 2 n t / (m + ½)
if we suppose that we have the first inference m = 0
λ = 2 1.6 0.5 10⁻⁶ (0 + ½)
λ = 3.2 10⁻⁶ m
this wavelength is in the infrared
suppose an interference of m = 1
λ = 1.6 10⁻⁶ / (1 + 1/2)
λ = 1.06 10-6 m
m = 2
λ = 1.6 10⁻⁶ / (2 + 1.5)
λ = 0.64 10⁻⁶ m
this wavelength corresponds to the visible range (640 nm) orange
