7. The graph of f(x) = (1/2)^x was transformedto form the graph of b(x) = -(1/2)^x Whichdescribes the transformation?

7. The Graph Of F(x) = (1/2)^x Was Transformedto Form The Graph Of B(x) = -(1/2)^x Whichdescribes The
7. The Graph Of F(x) = (1/2)^x Was Transformedto Form The Graph Of B(x) = -(1/2)^x Whichdescribes The

Answers

Answer 1

Given:

There are given the function:

[tex]f(x)=(\frac{1}{4})^x[/tex]

And,

The transferred function is:

[tex]f(x)=-(\frac{1}{4})^x[/tex]

Explanation:

According to the question:

We need to describe the transformation:

So,

We can see that in the transfer function, there is given that a negative sign.

So,

The transformation is:

Reflection on the x-axis: reflected:

Final answer:

Hence, the correct option is A.


Related Questions

Please help me solve question 5 on my algebra homework

Answers

Check the answers below, please

1) Since we have this linear function:

[tex]f(x)=-\frac{1}{3}x-4[/tex]

a) We can proceed to state the Domain, the set of inputs for this function as:

[tex]D=(-\infty,\infty)[/tex]

Since this Linear function does not have any restraint or discontinuity.

b) The Range, i.e. the set of outputs for this function will be defined for this function as:

[tex]R=(-\infty,\infty)[/tex]

c) The Zero, can be found algebraically by plugging f(x)=0

[tex]\begin{gathered} f(x)=-\frac{1}{3}x-4 \\ 0=-\frac{1}{3}x-4 \\ \frac{1}{3}x=-4 \\ x=-12 \end{gathered}[/tex]

d) Y-intercept is the point in the y-axis where the line intercepts it. Looking at the rule of the function, we can state the y-intercept as:

[tex]-4[/tex]

e) Slope, the measure of how steep a line of a function is, it's always the coefficient of x, in this case:

[tex]m=-\frac{1}{3}[/tex]

f) Type of slope. Since the slope is -1/3 , i.e. lesser than 0, then we can classify it as decreasing

g) Evaluating f(3):

[tex]\begin{gathered} f(x)=-\frac{1}{3}x-4 \\ f(3)=-\frac{1}{3}(3)-4 \\ f(3)=-1-4 \\ f(3)=-5 \end{gathered}[/tex]

h) The value of x, where f(x)= -4 Similarly to the previous item, we can plug into that f(x)= -4 like this:

[tex]\begin{gathered} f(x)=-\frac{1}{3}x-4 \\ -4=-\frac{1}{3}x-4 \\ -4+4=-\frac{1}{3}x-4+4 \\ -\frac{1}{3}x=0 \\ \mathbf{x=0} \end{gathered}[/tex]

i) The graph can be traced having the zero, the y-intercept the type of the slope we can plot this:

Solve for x and round to the nearest thousandth
4*x=728

Answers

Answer:

182

Step-by-step explanation:

728 divided by 4 is 182.

Look at the equation.

r+ 4 = 32

For which value of r is the equation true?

a. 8
b. 28
C. 36
d. 128

Answers

R+4=32
32-4=28

Answer:
B.28

The result of RREF produced the following matrix. What is the solution of the system? Choose the best answer.

Answers

Using the augmented matrix, we find that:

The first system has no solutions.

The second system has infinite solutions, given by: (-3t, 0, t).

Augmented Matrix:

An augmented matrix for a system of equations is a matrix of numbers in which each row represents the constants from one equation and each column represents all the coefficients for a single variable.

Given:

The matrix is,

[tex]\begin{bmatrix}1 & 0 & 3&| & 0 \\ 0& 1 & 1 & | & 5 \\0 & 0 & 0 & | & 1\end{bmatrix}[/tex]

Here we need to find the solution of the system.

While we looking at the first system, at the third row of the matrix, the relation is written as,

0t=1

This one is not possible, therefore, there are no solutions for the first system.

Now when we looking at the second system, the third line has the value of,

0t=1

This refers that there are infinite solutions, therefore here t is the free parameter.

From the second line, y = 5.

From the first,

=> x + 3t

=> x = -3t

The solutions are: (-3t, 0, t).

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Convert to an algebraic expression and simplify, if y stands for the unknown number: Sixteen more than five times a number.

Answers

Here, we are told y stands for the unknown number: Sixteen more than five times a number.​

Converting to an algebraic expression, we have:

16 + 5y

Here, y is the unknown number.

16 + 5y

ANSWER PLS QUESTION ATTACHED

Answers

A parallelogram is an easy quadrilateral with two pairs of parallel aspects. the other or dealing with facets of a parallelogram are of equal length and the other angles of a parallelogram are of equal measure. Hence, proved  p + q = r.

A parallelogram has four sides overall and two pairs of facets that might be parallel. A square is a parallelogram that has four equal sides. the other facets are parallel and all corners of the rectangular shape the right attitude. A rectangle is a parallelogram that has 4 contrary, parallel, congruent aspects.

proving p + q = r;

q = ∠OCD = ∠BAO   ( alternate angle)

In Δ AOB

∠OAb  + ∠DBA = p + q -------------------(1)

& ∠AOD + ∠BOA = 180° ------------(2)

Also,

∠OAB + ∠OBA + ∠BOA = 180° --------- some of angle in a triangle.

⇒ ( p + q) + (180° - ∠BOA) = 180° --------using 1 & 2

⇒  p + q - r = 0

⇒  p + q = r

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4 (-2,6)
B (4,6)
C(-2,3)
D(4,3)

Answers

Answer:

answer is c-(2,3)

Step-by-step explanation:

......................m

52
base six

Write the normal number

Answers

19770609664 is simple power of 52⁶ .

What is exponent and power?

A base number raised to an exponent is referred to as a power in mathematics, where base number is the factor that is multiplied by itself and exponent is the number of times the same base number is multiplied.Exponents and powers are two techniques for simplification of extremely big or extremely small numbers. As an illustration, we can write 3 x 3 x 3 x 3 as 34, where 4 is the exponent and 3 is the base, if we need to represent it simply. It is claimed that the entire statement 34 has power.

= 52⁶

= 52 × 52 × 52 × 52  × 52 × 52

=  19770609664

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What is the approximate circumference of a circle with a radius of 13 feet?

Answers

ANSWER

81.68 ft

EXPLANATION

The circumference of a circle = 2 * pi * r

[tex]\text{circumference = 2 }\Pi\text{ r = 2}\times\frac{22}{7}\times13\text{ = 81.68 ft}[/tex]

Can someone help me asap

Answers

Answer:

A) 670

B) 192 and 670

C) 670

Answer:

a) 670

b) 192, 670

c) 670

Step-by-step explanation:

670 is divisible by 5 because 670/5=134, also because 670 ends in 0

192 and 670 is divisible by 2 because they both end in even numbers, and also 192/2=96, 670/2=335

670 is divisible by 10 because 670/10=67, and it ends in a 0 as well

John Paul Jones rented a helicopter. There was a one-time charge of $500, plus an hourly rate of $150. His total for the night was $1700. How many hours did he rent the helicopter for?

a. Create an equation that represents the situation

b. Solve the equation
PLEASE I NEED ANSWER FAST

Answers

1. The equation that represents the situation is 500 + 150h = 1700

2. The number of hours used to rent the helicopter is 8 hours.

What is an equation?

It should be noted that an equation is used to show the relationship between the variables.

In this case, John rented a helicopter, there was a one-time charge of $500, plus an hourly rate of $150 and his total for the night was $1700.

Let the number of hours be represented as h.

The equation will be 500 + 150 × h = 1700

500 + 150h = 1700

The number of hours used will be:

500 + 150h = 1700

Collect like terms

150h = 1700 - 500

150h = 1200

Divide

h = 1200/150

h = 8

The helicopter was for 8 hours.

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If angle T = x degrees and angle V = 3x + 60, then angle V = ___ degrees.

Answers

Given data:

The given circle.

The quadrilateral inside the circle is cyclic in nature, the expression for the cyclic quadrilateral is,

[tex]\begin{gathered} \angle V+\angle T=19=180^{\circ} \\ 3x+60+x=180 \\ 4x=120 \\ x=30 \end{gathered}[/tex]

The value of angle V is,

[tex]\begin{gathered} \angle V=3(30^{\circ})+60^{\circ} \\ =150^{\circ} \end{gathered}[/tex]

Thus, the value of angle V is 150 degrees.

The following transactions were completed by Winklevoss Inc., whose fiscal year is the calendar year:
Year 1
July 1 Issued $71,900,000 of 20-year, 6% callable bonds dated July 1, Year 1, at a market (effective) rate of 7%, receiving cash of $64,222,669. Interest is payable semiannually on December 31 and June 30.
Oct. 1 Borrowed $420,000 by issuing a six-year, 5% installment note to Nicks Bank. The note requires annual payments of $82,747, with the first payment occurring on September 30, Year 2.
Dec. 31 Accrued $5,250 of interest on the installment note. The interest is payable on the date of the next installment note payment.
31 Paid the semiannual interest on the bonds. The bond discount amortization of $191,933 is combined with the semiannual interest payment.
Year 2
June 30 Paid the semiannual interest on the bonds. The bond discount amortization of $191,933 is combined with the semiannual interest payment.
Sept. 30 Paid the annual payment on the note, which consisted of interest of $21,000 and principal of $61,747.
Dec. 31 Accrued $4,478 of interest on the installment note. The interest is payable on the date of the next installment note payment.
31 Paid the semiannual interest on the bonds. The bond discount amortization of $191,933 is combined with the semiannual interest payment.
Year 3
June 30 Recorded the redemption of the bonds, which were called at 98. The balance in the bond discount account is $6,909,599 after payment of interest and amortization of discount have been recorded. Record the redemption only.
Sept. 30 Paid the second annual payment on the note, which consisted of interest of $17,913 and principal of $64,834.
Required:
1. Journalize the entries to record the foregoing transactions. Round all amounts to the nearest dollar. Refer to the Chart of Accounts for exact wording of account titles.
2. Indicate the amount of the interest expense in (a) Year 1 and (b) Year 2.
3. Determine the carrying amount of the bonds as of December 31, Year 2.

Answers

1. The journal entries recording the transactions for Winkelvoss Inc. are as follows:

Journal Entries:

Year 1:

July 1: Debit Cash $64,222,669

Debit Bonds Discount $7,677,331

Credit Bonds Payable $71,900,000

Oct. 1: Debit Cash $420,000

Credit Bank Notes Payable $420,000

Dec. 31 Debit Interest Expense $5,250

Credit Installment Note Interest Payable $5,250

Dec. 31 Debit Interest Expense $2,708,433

Credit Cash $2,516,500

Credit Bond Amortization $191,933

Year 2:

June 30 Debit Interest Expense $2,516,500

Credit Cash $2,324,567

Credit Bond Amortization $191,933

Sept. 30 Debit Interest Expense $15,750

Debit Installment Note Interest Payable $5,250

Debit Notes Payable $61,747

Credit Cash $82,747

Dec. 31 Debit Interest Expense $4,478

Credit Installment Note Interest Payable $4,478

Dec. 31 Debit Interest Expense $2,708,433

Credit Cash $2,516,500

Credit Bond Amortization $191,933

Year 3:

June 30 Debit Bonds Payable $64,990,401

Debit Bond Redemption Premium $5,471,599

Credit Cash $70,462,000

Sept. 30 Debit Interest Expense $13,435

Debit Installment Note Interest Payable $4,478

Debit Notes Payable $64,834

Credit Cash $82,747

2. The amounts of the interest expense in Year 1 and Year 2 are as follows:

                                     Year 1             Year 2

Total interest         $2,713,683      $2,72,8661

3. The bond's carrying amount as of December 31, Year 2, is $64,798,468.

Transaction Analysis:

Year 1:

July 1: Cash $64,222,669 Bonds Discount $7,677,331 Bonds Payable $71,900,000

Oct. 1: Cash $420,000 Bank Notes Payable $420,000

Dec. 31 Interest Expense $5,250 Installment Note Interest Payable $5,250

Dec. 31 Interest Expense $2,708,433 Cash $2,516,500 Bond Amortization $191,933

Year 2:

June 30 Interest Expense $2,516,500 Cash $2,324,567 Bond Amortization $191,933

Sept. 30 Interest Expense $15,750 Installment Note Interest Payable $5,250 Notes Payable $61,747 Cash $82,747

Dec. 31 Interest Expense $4,478 Installment Note Interest Payable $4,478

Dec. 31 Interest Expense $2,708,433 Cash $2,516,500 Bond Amortization $191,933

Year 3:

June 30: Bonds Payable $64,990,401 Bond Redemption Premium $5,471,599 Cash $70,462,000

Sept. 30 Interest Expense $13,435 Installment Note Interest Payable $4,478 Notes Payable $64,834 Cash $82,747

Interest Expenses:

                                     Year 1             Year 2

Bonds Payable      $2,708,433     $2,708,433

Notes Payable             $5,250            $15,750

Notes Payable                                      $4,478

Total interest         $2,713,683      $2,72,8661

Carrying amount of the bonds December 31, Year 2:

July 1:                              $64,222,669

Dec. 31 Bond Amortization   $191,933

June 30 Bond Amortization $191,933

Dec. 31 Bond Amortization   $191,933

Dec. 31 Year 2 Carrying Amont = $64,798,468

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In amelies home town the ratio of cars to people is 4,200 to 5,000. Which of the following equals to this ratio? a)0.21, b) 0.42, c) 0.12, d) 0.84?

Answers

The option that is to equal to the ratio,  4,200 to 5,000, is 0.84

What is ratio?

Ratio mean expressing one variable as a fraction of the other variable, in this case, 4,200 is expressed as a fraction of a bigger number which is 5,000, intuitively, the correct answer in this scenario is 0.84 because when viewed in percentage terms, 4000 is 80%,hence, 4,200 is greater than 4000, it would be more 80% which is 84%, without mincing words, the computation can be done as shown below:

ratio 4,200 to 5,000=4,200/5,000

ratio 4,200 to 5,000=0.84

Invariably, as stated earlier, all the options from a-c are incorrect as they are not even up 0.80, which means 0.84 is the most appropriate

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What is the reflection image of X? 0 (3,7) O (73) (5,7) (7,5)

Answers

ANSWER

(7, 5)

EXPLANATION

We want to find the reflection image of X.

The coordinates of X is (-1, 5).

When reflecting over a vertical axis, the x coordinate changes but the y coordinate does not change.

To reflect a point (x, y) (i.e. to find the new x coordinate) across the line x = a, find the distance between a and x, then add that to a.

That is the new x coordinate.

For the question, a = 3.

Therefore, for X(-1, 5):

[tex]\begin{gathered} a-x=3-(-1)=3+1 \\ a=4 \end{gathered}[/tex]

Adding that to a, the new coordinates are:

[tex]\begin{gathered} (4+3,5) \\ (7,5) \end{gathered}[/tex]

That is the reflection image of X.

Simplify this expression 2x² x x³ ​

Answers

[tex]2x^{6}[/tex] is the Simplify of the expression   2x² x x³

[tex]2x^{2} xx^{3} = 2x^{6}[/tex]

what is simplify?

To simplify means to make anything basic or simpler, for example. a: to reduce to the bare minimum. b: to become simpler or broader in scope: It was advised to streamline management processes.

The fundamental guidelines and procedures to simplify any algebraic statement are as follows:

By multiplying factors, remove any grouping symbols like brackets and parenthesis.If the words contain exponents, use the exponent rule to eliminate grouping.Add or subtract like terms to combine them.add the constants together

When you describe a complex mathematical idea to a child in words they can easily understand, you are simplifying. When you eliminate many of the tasks that were keeping you occupied and stressed out, you have simplified.

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Greatest common factor of 5xy+10xy^2+5x

Answers

Greatest Common Factor

To find the GCF of an expression, find the greatest number that every term can divide by. One way we can do this is by factoring the expression.

Solving the Question

[tex]5xy+10xy^2+5x[/tex]

Here, each term has the variable x. Factor this out by dividing each term by x:

[tex]x(5y+10y^2+5)[/tex]

Now, each term has a factor of 5. Divide each term by 5:

[tex]5x(y+2y^2+1)[/tex]

Now, there are no more common factors between each term.

Therefore, the GCF is 5x.

Answer

5x

Which equation represents a line that is perpendicular to the graph of y = 2/5x − 1?

Answers

The equation of the line y=-5/2x-4 is perpendicular to the given equation of the line.

Given that,

The given equation of the line is y=2/5x-1.

We have to find the equation of the line that is perpendicular to the given equation of the line.

We know Equation of the line formula,

y=mx+c

Here,

m denotes the line's slope, and c the y-intercept.

Take the equation of the line y=2/5x-1

m is 2/5

The perpendicular line is m is -5/2

We get the perpendicular line is y=-5/2x-4.

Therefore, The equation of the line y=-5/2x-4 is perpendicular to the given equation of the line.

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Given: 3x + 16 = 4x - 9
Prove: x = 25

Answers

Answer:

x=16

Step-by-step explanation:

Simplifying

3x + 16 = 4x

Reorder the terms:

16 + 3x = 4x

Solving

16 + 3x = 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.

16 + 3x + -4x = 4x + -4x

Combine like terms: 3x + -4x = -1x

16 + -1x = 4x + -4x

Combine like terms: 4x + -4x = 0

16 + -1x = 0

Add '-16' to each side of the equation.

16 + -16 + -1x = 0 + -16

Combine like terms: 16 + -16 = 0

0 + -1x = 0 + -16

-1x = 0 + -16

Combine like terms: 0 + -16 = -16

-1x = -16

Divide each side by '-1'.

x = 16

Simplifying

x = 16

Identify the quadratic function(s). (Select all that apply.) 2b(b - 7) + b = 0 (4a + 2)(2a - 1) + 1 = 0 2y + 2(3y - 5) = 0 8 - 5x = 4(3x - 1)

Answers

The quadratic equations are 2b(b - 7) + b = 0 and (4a + 2)(2a - 1) + 1 = 0 .

what is Quadratic Equation?

An algebraic equation of the second degree in x is a quadratic equation. The quadratic equation is written as ax² + bx + c = 0, where x is the variable, a and b are the coefficients, and c is the constant term. First, there must be a term other than zero in the coefficient of x² (a ≠ 0) for an equation to be a quadratic equation. The x² term is written first when constructing a quadratic equation in standard form, then the x term, and finally the constant term.

Given:

a) 2b(b - 7) + b = 0

2b² - 14b + b = 0

2b² - 13b = 0

b) (4a + 2)(2a - 1) + 1 = 0

8a² - 4a + 4a + 1 =0

8a² 1 =0

c) 2y + 2(3y - 5) = 0

2y+ 6y- 10 = 0

8y -10=0

d) 8 - 5x = 4(3x - 1)

8- 5x= 12x- 4

Hence, the quadratic equations are 2b(b - 7) + b = 0 and (4a + 2)(2a - 1) + 1 = 0 .

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Convert the following complex number into its polar representation: 3i O A. -3(60597 +isin 37 O COS 2 2 O B. -3(cos+ i sin o) O C. 3(cos+ i sin ) O D. 3c052+isin 8

Answers

The correct option is D.

The value of r for the given complex number is calculated below:

[tex]r=\sqrt[]{0^2+3^2}=\sqrt[]{9}=3[/tex]

now,

[tex]\tan \theta=\frac{3}{0}=\text{ not defined}[/tex]

Since the complex number lies on the positive y-axis.

[tex]\theta=\frac{\pi}{2}[/tex]

Therefore, the polar form of the given complex number is

[tex]3(\cos \frac{\pi}{2}+i\sin \frac{\pi}{2})[/tex]

The population of the world in 1987 was 5 billion and the annual growth rate was estimated at 2 percent per year. Assuming that the world population follows an exponential growth model, find the projected world population in 1992.

Answers

Answer:

5.52 billion

Step-by-step explanation:

2% s .02 in decimal    from '87 to '92 is 5 years ( the exponent in the following:

5 (1.02)^5   = 5.52 billion

Answer:

5.52 billion

Step-by-step explanation:

i got this my doing math

Hi, can you help me with that please ‘cause I don’t understand what I have to do .

Answers

This is a simple question.

The run is related to the x-axis and the rise to the y-axis and the slope is the relation between the two and we can calculate in the following form:

[tex]Slope=\frac{Rise}{Run}=\frac{y_2-y_1_{}}{x_2-x_1}[/tex]

To do so, we need to choose 2 different points in the line and calculate. For our explanation, we will choose points (-1,9) and (3,-3). So let's calculate:

[tex]Slope=\frac{Rise}{Run}=\frac{y_2-y_1}{x_2-x_1}=\frac{9-(-3)}{-1-3}=\frac{12}{-4}=-\frac{12}{4}[/tex]

And that is our Slope.

Now we can draw it as follows:

And that is our final answer.

Can you help me with this

Answers

Given:

[tex]\begin{gathered} y=x+4 \\ y=x+2 \\ x=1 \\ x=4 \end{gathered}[/tex]

Required:

To find the volume of the solid by using washer method.

Explanation:

Volume formula of Washer method is,

[tex]V=\int_a^b\pi[(f(x)^2-g(x)^2]dx[/tex]

Therefore,

[tex]\begin{gathered} V=\int_1^4\pi[(x+4)^2-(x+2)^2]dx \\ \\ =\int_1^4\pi[x^2+16+8x-x^2-4-4x]dx \\ \\ =\int_1^4\pi[4x+12]dx \\ \\ =\pi[\frac{4x^2}{2}+12x]_1^4 \\ \\ =\pi[\frac{64}{2}+48-\frac{4}{2}-12] \\ \\ =\pi[32+48-2-12] \\ \\ =66\pi \end{gathered}[/tex]

Final Answer:

Volume is

[tex]66\pi[/tex]

4. What value of c would make the function below have two real solutions? y= -3x^2 – 4x+c

Answers

The quadratic equation is,

[tex]y=-3x^2-4x+c[/tex]

The value of coefficients of square term, x term and constant terms are,

a = -3

b = -4

and c = c.

For two real roots,

[tex]b^2-4ac>0[/tex]

Dubstitute the values in the equation to obtain the value of c.

[tex]\begin{gathered} (-4)^2-4\cdot(-3)\cdot(c)>0 \\ 16+12c-16>0-16 \\ \frac{12c}{12}>\frac{-16}{12} \\ c>-1.333 \end{gathered}[/tex]

So value of c should be greater than -1.333, and from from the options it can be observed that value more than -1.333 is only c = -1.

So answer is c = -1.

Can’t find the correct answer pls help

Answers

a)What is the value of y?   y= 6

b)The value of RS is 57 and ST is 16.

a) How is the value of y calculated?

From the number line,

RS = 9y +3

ST= 2y + 4

RT = 73

Rewriting as equation,

RT = RS + ST

73 = 9y +3 + 2y + 4

73 = 11y  + 7

11 y = 73 - 7

11y = 66

y = 66/11

y = 6

b) What is the value of RS and ST ?

Considering the equation,

RS = 9y + 3

     =9(6) +3

     =54 +3

RS = 57

Considering the equation,

ST = 2y + 4

     =2(6) +4

     = 12 +4

ST = 16

What is an equation?

An equation is a mathematical statement that demonstrates the equality of two mathematical expressions. More than one variable may be present in a linear equation. An equation is said to be linear if the maximum power of the variable is consistently 1. Another name for linear equation is a one-degree equation.

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10. Find the value of k such that the line through (5, 1) and (k, 7) is parallel to the line
y = 3x.

Answers

Answer:

k = 7

Step-by-step explanation:

y = 3x

The slope is 3

Parallel lines have the same slope so a line parallel will have a slope of 3

Using the slope formula

m = (y2-y1)/(x2-x1)

3 = ( 7-1)/(k-5)

3 = 6/(k-5)

Multiply each side by k-5)

3 * (k-5) = 6

Divide each side by 3

k-5 = 6/3

k-5 = 2

Add 5 to each side

k = 7

When 2 triangles are congruent, you can move 1 figure and it fits exactly on the other. Which transformation from Unit 1 would not result in congruent figures?

Answers

The non-rigid transformation will not result in congruent figures because they will change the size or shape.

Hence, the answer is dilation because if we dilate the figures they will not be congruent after the transformation.

Which of the following groups of animals could be found in temperate grasslands?
Answer asap what’s the correct answer

Answers

All groups of animals could be found in temperate grasslands.

Grasslands occupy about a 1/4 of the earth's surface. Grasslands develop in large part as a result of climate. The two main classifications of grasslands are temperate grassland as well as tropical grassland.The American prairies are home to a variety of animals, including prey animals, wild dogs, buffalo, jackrabbits, wolves, and deer. There are many different animals living in the African veldt, such as gazelles, zebra, and rhinos. Rodents, rats, gazelle, beavers, bears, and many other animals are among the fauna of the steppe.

Mammals including wolf, prairie animals, reindeer, mice, coyotes, wolves, and jackrabbits are among the inhabitants of this biome. Starlings, sparrows, owls, raptors, and quails are some of the birds found in this biome. The most common insects are grasshoppers and snakes.

All groups of animals could be found in temperate grasslands.

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PLEASE HELP ME I WAS SICK AND I DONT UNDERSTAND.DUE IN 1 HOUR!!!!

Answers

Answer:

x = 11

Step-by-step explanation:

(3x + 12) + (7x + 15) = 137 (exterior angle: angle KFG = angle g + angle h)

10x + 27 = 137

10x = 110

x = 11

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