The force would have to work on the block till a distance of 15.66m farther to have 56 joules of kinetic energy.
The work done is given by the product of the force applied and the distance covered along the direction of force.
So we can write,
W = F.s
Where w is the work done if is the force and S is the distance covered.
According to work energy theorem, the work done is equal to the change in kinetic energy.
The force applied in this case is 3 Newton and the body has no till a distance of 3m. Let us assume that the block is moved till a distance x in order to achieve a kinetic energy of 56 joules.
So, it can be written,
3(3+x) = 56
Solving,
9+3x = 56
3x = 47
x = 15.66 m.
So, it is required to move the body by a distance of 15.66 m.
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a race car traveling at a constant speed of 50 m/s drives around a circular track that is 500 m in diameter. what is the magnitude of the acceleration of the car
The magnitude of the acceleration of the car was 10m/s^2
what is magnitude?
Magnitude is defined in physics as an object's maximal size and direction. Magnitude is utilised in vector and scalar variables as a common factor. Scalar quantities, by definition, are those with only magnitude. Whereas vector quantities have both magnitude and direction.
Magnitude can be used in a variety of contexts. Some of them include
The magnitude of the earthquake
Charge magnitude on an electron
Force magnitude
The magnitude of the displacement
Gravitational force magnitude
acceleration (a)= v^2/r
v=speed
r=radius
d=diameter=500
r=d/2=500/2=250
a= 50^2/250
=10 m/s^2
Therefore the acceleration was found to be 10m/s^2
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If you know the acceleration and time, how can you calculate the average velocity?.
The average velocity in terms of acceleration and time is 1/2at².
Average velocity:
Velocity is the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.
Assume the acceleration a is uniform then:
v(t) = u + at
u = initial velocity
By average velocity v we mean average over time than strictly speaking:
v = 1/t [tex]\int\limits^t_0 {v(t)} \, dt[/tex]
= 1/t [tex]\int\limits^t_0 {(u + at)} \, dt[/tex]
= 1/t ( ut + 1/2 at²)
v = u + 1/2at²
If u =0, then we have
v = 1/2 at²
Therefore the average velocity is 1/2at².
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How many g are in a pack containing 10 tablets of 500 mg each? *
5g
50g
100g
500g
Answer:
5 g
Explanation:
500 mg x 10 = 5000 mg
5000 x 10^-3 g = 5 g
Hello..!
To solve the problem and calculate the number of pills in the package, we will use the conversion factor.
The conversion factor or unit factor is a conversion method that is based on multiplying by one or more fractions where the numerator and denominator are equal quantities expressed in different units of measure, so that each fraction is equivalent to the unit.
Find out that 1 gram has a total of 1000 mg.
Problem:
How many g are in a carton containing 10 tablets of 500 mg each?
According to the previous text we can say that the conversion factor would be:
[tex] \: \: \: \: \: \qquad \qquad \large \sf\dfrac{1\ g}{1000\ mg}[/tex]
Now we must find out that the box has a total of 10 pills of 500 mg, so to know how many grams the box has we must know how many grams only one pill weighs:
[tex] \sf \qquad\boxed{\boxed{ \sf\large 500\ mg*\dfrac{1\ g}{1000\ mg}= 0.5\ g}}[/tex]
We know that a pill weighs 0.5 grams, now to calculate how many grams the box weighs we must multiply the total pills by the weight of just one pill:
[tex]\qquad \boxed{\boxed{ \sf\large 0.5\ g\times 10= 5\ g}}[/tex]
We conclude that one box contains 5 grams of tablet, option 1.
[tex]\begin{gathered}\rule{7cm}{0.01mm}\\\texttt{Good studies! :D}\\\rule{7cm}{0.01mm}\end{gathered}[/tex]
consider a 20 kg sphere with a 10 cm radius. what weight would a scale read if the sphere was totally submerged in water?
The weight the scale would read if the sphere of mass 20 kg with a 10 cm radius was totally submerged in water is 155.1 N
Fg = m g
Fb = ρ V g
Fg = Force of gravity
Fb = Buoyant force
m = Mass
g = Acceleration due to gravity
ρ = Density of medium
V = Volume of object
m = 20 kg
g = 9.8 m / s²
ρ = 1000 kg / m³
r = 10 cm = 0.1 m
Fg = 20 * 9.81
Fg = 196.2 N
Fb = ρ ( 4 / 3 π r³ ) g
Fb = 1000 * 4 / 3 * 3.14 * 0.1³ * 9.8
Fb = 41.1 N
N = Fg - Fb
N = Scale reading
N = 196.2 - 41.1
N = 155.1 N
Therefore, the scale reading if the sphere was totally submerged in water is 155.1 N
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Compare the use of an electric bicycle with a normal bicycle used
to cycle a 5 km uphill route. The cyclist does not pedal when using
the electric bike to cycle uphill.
Information about the two bikes is given in Table 1.
Table 1
Information
power of the motor
force used to drive the
bicycle forward
weight of bicycle
battery life
time to travel 5 km
Electric bicycle
350 W
50 N
190 N
25 minutes
12 minutes
Ordinary bicycle
no motor
47 N
120 N
no battery
13 minutes
Your answer should contain descriptions of work done, energy
transfers, and power.
The work done by the ordinary and electric bicycle are 235 KJ and 250 KJ respectively and the output power of ordinary and electric bicycle are 0.3 KW and 0.35 KW respectively.
W = F d cos θ
P = W / t
W = Work done
F = Force
d = Distance
P = Power
t = Time
θ = 0
d = 5 km = 5000 m
For Electric bicycle
F = 50 N
t = 12 min = 720 s
W = 50 * 5000 * cos 0
W = 250000 J
W = 250 KJ
P = 250 / 720
P = 0.35 KW
For ordinary bicycle,
F = 47 N
t = 13 min = 780 s
W = 47 * 5000 * cos 0
W = 235000 J
W = 235 KJ
P = 235 / 780
P = 0.3 KW
Therefore, the work done by the ordinary and electric bicycle are 235 KJ and 250 KJ respectively and the output power of ordinary and electric bicycle are 0.3 KW and 0.35 KW respectively.
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an electron and a photon each have a wavelength of 0.200 nm. a. find the momentum and energy of the photon. b. find the momentum and kinetic energy of the electron. ignore relativistic effects for the electron. c. how fast is each one moving?
a. Momentum is 3.315x [tex]10^{-24}[/tex] kg m/s and energy is 6.21KeV.
b. momentum is 3.315x [tex]10^{-24}[/tex] kg m/s and kinetic energy 0.038 KeV.
c. 3.64x [tex]10^{6} m/s[/tex] fast is each one moving.
a. for photon λp = 0.200 nm
Now, λp = [tex]\frac{h}{p_{p} }[/tex]= [tex]p_{p} = \frac{h}{h_{p} }[/tex] = [tex]\frac{6.63\times 10^{-34} }{0.200\times 10^{-9} }[/tex] kgm/s
= 3.315x [tex]10^{-24}[/tex] kg m/s
[tex]E_{P}[/tex] = [tex]P_{p} C[/tex] = 3.315x [tex]10^{-24}[/tex]x 3x [tex]10^{8}[/tex]/ 1.6x [tex]10^{-19}[/tex] eV
= 6.21KeV.
b. λe = 0.200
[tex]P_{e} =[/tex]λ/λe
= 3.315x [tex]10^{-24}[/tex] kg m/s
E = [tex]\frac{P^{2} _{e} }{2m} }[/tex] = [tex]\frac{( 3.315)^{2} }{2\times 9.1\times 10^{-31\times 1.6\times10^{-19} } }[/tex]
= 0.038 KeV
C. [tex]P_{e} = m V_{e}[/tex]
[tex]V_{e} = \frac{P_{e} }{m\\}[/tex]
= [tex]\frac{ 3.315\times 10^{-24} kg m/s}{9.1\times 10^{-31} }[/tex]
= 3.64x [tex]10^{6} m/s[/tex]
What is momentum?Momentum is a quantity used to describe the state of motion of an object with non-zero mass. Thus, an impulse can be applied to any moving object. Since velocity is considered a vector, momentum is also considered a vector. This means that the impulse has a significant magnitude and direction—an impulse indicated by a vector or arrow. For example, if a ball of a certain mass moves with a certain speed, it has momentum. When the ball hits the wall, it stops and thus carries its momentum over the wall. Therefore momentum is always conserved.
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2 balls ball 1 and ball 2 are each thrown horizontally from the same height above the ground. ball 2 has a greater initial velocity after leaving the thrower's hand than ball 1. if air resistance is negligible how do the accelerations of each ball and the time it takes each of them to hit the ground compare?
acceleration on both the balls is same
Time to hit the ground is also equal for both the balls.
Here the acceleration is only acceleration due to gravity in vertically downward direction.
No acceleration in horizontal direction as air resistance is neglected.
Both the balls are projected from same height and downward acceleration is same and there is no initial downward velocity ,hence both the balls take same time to hit the the ground.
Time to hit the ground is also equal for both the balls.
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a mass m is attached to an ideal massless spring. when this system is set in motion with amplitude a, it has a period t. how does the period of the motion change if the amplitude of the motion is increased to 2a? explain.
System is set in motion with an amplitude of a and a period of T. If the amplitude of the motion is increased to 2a, the period of the motion changes.
A straightforward harmonic oscillator's period is independent of its amplitude. with the graphs of acceleration and velocity produced by the time derivatives. These oscillators also show how kinetic and potential energy can be transferred.
The acceleration of the mass increases proportionally with the increase in force, causing the mass to travel farther in the same amount of time. Therefore, increasing the amplitude has no overall impact on the oscillation's period.
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a string is under a tension of 760.0 n. a 1.7 m length of the string has a mass of 4.8 grams. what is the speed of a transverse wave of wavelength 0.50 m in this string? what is the frequency of the wave?
The number of waves that pass by each second is the frequency of a wave, which is expressed in Hertz (Hz). For instance, a sound wave may have a frequency of 450 Hz.
Explain about the frequency of wave?
The wave frequency is the quantity of waves that pass a certain location in a predetermined amount of time. The SI unit for wave frequency is the hertz (Hz), and 1 hertz is equal to 1 wave passing through a fixed point in 1 second. When two waves of equal amplitude and frequency are compared, the higher frequency wave has greater energy.
Divide the wave's velocity by its wavelength to determine its frequency. The unit for frequency is Hertz (Hz), so use that while writing your response. The frequency will be the inverse of the time, or 1 divided by T, if you need to determine it from the amount of time it takes for a wave cycle to complete, or T.
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The rising concern among athletic trainers and health advocates (and parents) regarding concussions and multiple concussions among high school football players has prompted numerous studies of the effectiveness of protective head gear and the forces and accelerations experienced by players. One study suggested that there is a 50% chance of concussions for impacts rated at 75 g's of acceleration (i.e., 75 multiplied by 9.8 m/s/s). The average head impact in football results in 22 to 24 g's of acceleration ... but not all head impacts are equal.
If a player's head mass (with helmet) is 5.41 kg and considered to be a free body, then what net force would be required to produce an acceleration of 75 g's?
Answer:
Explanation:
Given:
m = 5.41 kg
g = 9.8 m/s² - acceleration of gravity
a = 75·g = 75·9.8 ≈ 735 m/s²
__________________
F - ?
Newton's second law:
F = m·a
F = 5.41·735 ≈ 3 980 N
a flight attendant pulls her 2 kg flight bag a distance of 23 m along a level airport floor at a constant velocity. the force she exerts is 8 n at an angle of 30 degrees above the horizontal. find the work she does on the flight bag.
Work done on the flight bag will be 182.20 J.
Work done defined as the product of force and distance covered due to applied force.
The mass of flight bag m = 2 kg
Therefore the weight of the bag will be 2*g = 2*10 = 20 N
(g = acceleration due to gravity = 9.81 m/s2)
The distance covered by the bag is, d = 23 m.
The magnitude of force exerted on bag is, F = 8 N.
The angle of inclination with horizontal = [tex]\alpha[/tex] = 8°
The work done on the flight bag is given by the equation:
W = F * d *Cos [tex]\alpha[/tex]
W = 8 * 23 * Cos8
W = 182.20 J
Thus, the work done by the attendant on the flight bag is 182.20 J.
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four resistors having a value of 100 ohms each are connected in parallel. what is the total resistance of the circuit?
The total resistance of the circuit is 25 ohms.
How can the resistance of a circuit with four resistors in parallel be determined?In the same way, if three or more resistors of the same value are connected in parallel, the equivalent resistance will be equal to R/n, where R is the resistor's value and n is the total number of resistors in the arrangement.
How do you calculate a parallel resistor's total resistance?The total current flowing from the source is the sum of the currents through each of the paths. Using the following formula, you can get the overall resistance in a parallel circuit: 1/Rt = 1/R1 + 1/R2 + 1/R3 +... Even if one of the parallel channels breaks, current will still flow.
[tex]R_{total}[/tex] = 100/4 = 25ohms
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a charged particle, passing through a certain region of space, has a velocity whose magnitude and direction remain constant. if it is known that the external electric field is zero everywhere, then can you conclude that the external magnetic field is also zero? ignore gravity.
YES, if it is known that now the external electric field equals zero everywhere, then you can infer that external magnetic field also is zero.
In plain terms, how is a magnetic field?The region surrounding a magnet that experiences the effects of magnetism is known as the magnetic field. When describing the distribution of the magnetic force within and around a magnetic object in nature, the magnetic field is a useful tool.
What are the workings of the magnetic field?The vicinity of a magnet that exhibits magnetic force is known as the magnetic field. South and north poles are found on every magnet. The opposite poles are drawn to one another, whereas the same poles are drawn away from one another. The atoms in iron have north-seeking poles that line up in the exact direction when it is rubbed against a magnet.
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what would her speed be at 490 m ? (in reality, the air resistance will restrict her speed to perhaps 150 km/h .)
She will pull her ripcord 22.9 s after the dive and her speed at 490 m will be 112.66 m/s.
What is free-fall?Free fall, any motion of a object where gravity is the only force acting upon it. In the context of general relativity, where gravity is reduced to the curvature of spacetime, there are no forces acting on bodies in free fall.
For the given case,
s = ut + 1/2 at²
s = Displacement (3000 - 420 = 2580 m) it is the distance she will free fall
a = Acceleration due to gravity (9.8 m/s²)
u = Initial velocity (0 m/s)
t = Time taken
2580 = 0×t + 1/2 9.8 t²
2580 = 4.9 t²
t = 22.9 s
Now her speed at 490 m will be
v = d/t
v = speed
d = 2580 m
t = 22.9 s
v = 2580/22.9
v = 112.66 m/s
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The given question is incomplete so the complete question is as follows:
"if there were no air resistance, how long would it take a free-falling skydiver to fall from a plane at 3100 m to an altitude of 490 m , where she will pull her ripcord? what would her speed be at 490 m ? (in reality, the air resistance will restrict her speed to perhaps 150 km/h)"
a car has a maximum acceleration of 5.8 m/s2 . what will the maximum acceleration be if the car is towing another car of the same mass? neglect the additional friction force. express your answer using two significant figures.
The maximum acceleration if the car is towing another car of the same mass is 2.8 m/s².
Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.
Case 1:-
acceleration = force/mass
5.8 = F/m
Let each mass of the car is m
mass of two car = 2m
a = F/2m
So new acceleration will become = 5.8/2
= 2.8 m/s²
Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.
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the bucket of the backhoe and its contents have a weight of 1200 lb and a center of gravity at g. the bucket is pinned at e (figure 1).
Answer:
1200
Explanation:
Stan argues that momentum cannot be conserved when a collision is not a head-on collision. Rachel insists it is conserved because each body receives an impulse of equal magnitude. Rachel is correct because.
Rachel is correct because she said that is body receive equal magnitude of impulse which completely satisfy the law of conservation of linear momentum.
According to law Conservation of Linear Momentum, if there is no external force working on the system, then the linear momentum remains conserved before and after the collision.
We know that,
Momentum is nothing but the product of force and the time taken for the contact period of the colliding bodies.
We assume that during the head on collision of the body, the body is remain in contact for such a short period of time that there is no external force all the impulse created due to the external force is neglected.
So, because the impulse imparted on both the bodies are equal to each other.
We know that impulse is nothing but the change in momentum.
So, from here we conclude that bodies received equal magnitude of impulse.
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what is the relation between the current through the resistor and the voltage drop across the resistor
By way of Ohm's Law, the voltage drop is proportional to the cutting-edge flowing thru a resistor. (So in numerous collection resistors with the same resistance, the drop across each one is identical, because the present day throughout each one is equal).
The connection between the current, voltage, and resistance is expressed through Ohm's regulation. This states that the modern-day flowing in a circuit is at once proportional to the implemented voltage and inversely proportional to the resistance of the circuit, provided the temperature stays steady.
Resistors in the collection deliver identical cutting-edge, however, the voltage drop throughout them isn't the same as their man or woman resistance values will create one-of-a-kind voltage drops across every resistor as decided by way of Ohm's regulation ( V = I*R ).
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a group of ten friends, each of mass 50kg, want to test the strength of a trampoline. at their highest jump, each friend is 2m above the trampoline. they all land on the trampoline at the same time and decelerate at a constant rate to a point of zero velocity over a period of 0.5s. the trampoline has a threshold of 5000n, above which it breaks. do the friends succeed in breaking their trampoline? neglect air resistance and the distance the trampoline sags as a result of the friends landing.
Calculate the striking trampoline.
What is zero velocity?
The zero-velocity surface is a notion connected to the N-body gravity problem. It represents a surface that a body with the specified energy cannot traverse because it would have zero velocity there. George William Hill made the initial proclamation about it.
What is resistance?
A circuit's opposition to current flow is measured by its resistance. The Greek letter omega () stands for ohms, which are used to measure resistance. Georg Simon Ohm (1784–1854), a German physicist who examined the connection between voltage, current, and resistance, is the subject of the name "Ohm."
mass of each friends= 50kg
number of friends =10
total mass= 50×10=500kg
now initial velocity before, falling =0
let final velocity be V
v²-μ²= 2as
⇒v²+2as=2as(μ=0)
∴V=[tex]\sqrt{2as}[/tex]=[tex]\sqrt{2*9.8*2}[/tex] ( acceleration due to gravity =9.8m/s²) ( s=2m given)
=6.26ms⁻¹
∴The velocity of the friends, just before striking the trampoline= 6.26ms⁻¹
Now after striking the trampoline, the velocity of the people decelerate to 0, in a time interval 0.5s.
∴deceleration= 6.26/ 0.5= 12.52ms⁻²
∴Force required to decelerate=mass× deacceleration
=500×12.52
=6260.99
=6261N
but that trampoline has a threshold of 500N, which is less than force required to stop, the people.
hence the friends succeed in striking the trampoline.
Therefore, the friends succeed in striking the trampoline.
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a lawn roller is rolled across a lawn by a force of 115 n along the direction of the handle, which is 22 above the horizontal. if george develops 64.6 w of power for 90.0 s, what distance is the roller pushed?
The distance roller pushed is 54.7 meter when a lawn roller is rolled across a lawn by a force of 115 N along the direction of the handle.
What is distance and force and what distance is the roller pushed ?Distance is the quantity representing the product of speed and time of the motion under given time period.Force is a newtonian quantity representing the product of mass and acceleration .Here the lawn roller is rolled across a lawn by force 115 N , the force along the horizontal would be F = 115 cos 22 = 106.60.Power = force x speed, P = 115 x speed, 64.6 = 115 x speed , speed = 64.6/115 = 0.56 m/s.Distance = speed x time = 0.56 x 90 = 54.7 meters, hence the distance roller pushed is 54.7 meters.Therefore when a lawn roller across a lawn by force of 115 N the distance roller pushed will be 54.7 meter.To know more about distance visit:
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3. The average human walks at a speed of 5 km per hour. If your PE teacher asks you to
walk for
40 minutes in
gym class, how far would you walk (km)?
The average human walks at a speed of 5 km per hour. If your PE teacher asks you to walk for 40 minutes in gym class, you would walk for 3 Km.
What is Average speed?
The average speed is the displacement of a particle divided into a time in which the displacement occurs. Instead, instantaneous speed is the limit of the average speed as the time interval approaches zero.
Usually,
Speed = Distance/ Time
Assuming you also walk with the average human walking speed of 5 km/h. We know the above formula of speed and now making distance the subject, distance is a product of speed and time.
Here, time is 40 minutes and if expressed in hours can be converted as,
40/60 = 0.6 hours.
Distance = 5 × 0.6
= 3 km
Thus,the average human walks at a speed of 5 km per hour. If your PE teacher asks you to walk for 40 minutes in gym class, you would walk for 3 Km.
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The kinetic energy of a baseball that with a mass of 0.140kg is 7 J. What is the baseballs velocity?
Answer:
10 m/s
Explanation:
Kinetic energy= [tex]\frac{1}{2}[/tex]mv² where m is mass and v is velocity.
We have to make v the subject so we should rearrange the equation
K=[tex]\frac{1}{2}[/tex]mv²
v²= [tex]\frac{K}{0.5*m}[/tex] (use algebra)
v²= 7/0.5×0.140
v²=100
v=√100
v=10 m/s
We can confirm this by using the kinetic energy formula.
K=[tex]\frac{1}{2}[/tex]×0.140×10²
K= 7 J
Hence it is proved that velocity is 10 m/s
what has more kinetic energy an object of mass 2m moving with speed 3v or an object of mass m moving with speed 4v
Kinetic energy The height of an object of mass m moving at speed 4v will be greater than that of an object of mass 2m moving at speed 3v. Kinetic energy = 0.5 m v2
A mass of 2 m moving at a speed of 3 v has kinetic energy of 9 m, while a mass of m moving at a speed of 4 v has kinetic energy of 8 m. The ability of an object to move another object is known as its kinetic energy. It is effective for a force to move an object. Furthermore, we are aware that an object in motion can cause a stationary object to move if it collides with it. It can therefore perform a function. The ability of an object to perform work as a result of its motion is how we define kinetic energy.
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Highlight (1) calculator
Species
0 0
Harbor seals live off the coast of New England and feed on various fish, squid, shrimp, and other marine life. A sea
approaches a school of fish consisting of mackerel, herring, and harbor pollock. The population of each species is
shown in the table.
mackerel
herring
harbor pollock
What is the probability the seal catches a mackerel?
You may use the calculator.
25%
20%
15%
33%
Elag for Review Normal Color Scheme
Population
15
23
37
There is 20% probability that the seal catches a mackerel.
What is probability?How likely something is to occur is known as its probability.
To determine probability, divide the total number of possible outcomes by the number of possible ways an event could occur. There are differences between probability and odds. Odds are calculated by dividing a situation's likelihood of occurring by its likelihood of not occurring.
Given,
mackerel 15
herring 23
harbor pollock 37
probability = possible event/ no. of event
probability = 15/ 15+23+37
probability = 15/ 75
probability = 0.2
∴ probability is 20%
For numbers less than 1 out of 1,000 (such as 0.20 out of 1,000), it is clearer to recast them as “200 out of 10,000” (“2 out of 10,000,” for instance).
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a 0.13- kg block on a wooden table is given a sharp blow with a hammer. the block then slides across the table to a stop. the coefficient of friction between the block and table is 0.33. the hammer's force on the block as a function of time is well approximated by an isosceles triangle with it's base on the horizontal time axis. the length of the base is 0.0067 s and the maximum force is 37.6 n. how far does the block go? use a graphical technique
The length of the base is 0.0067 s and the maximum force is 37.6 n.1.45 ×10^-1 m far does the block go.
When we use graphical method then we can feel that, here the area of the isosceles triangle will give us the change in the momentum, also as here the initial velocity is zero,
so that let the final velocity is V then,
we have
m*V= area of the triangle
or
0.13* V = area of the triangle = 1/2 * base * height =0.5*0.0067*37.6= 0.1258 kg m/s
so V = 0.968 m/s
the frictional force is = mg(0.33)
let the distance required is X then using conservation of energy here we have
KINETIC ENERGY = FRICTIONAL ENERGY.
1/2mV2 = mg(0.33) *X
X= V^2 / ( 2g*0.33) = 0.1450 m = 1.45 ×10^-1 m
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Which variable is NOT shown on a velocity-time graph?
Acceleration is the variable that is NOT shown on a velocity-time graph
Velocity - time graph, evidently shows two variables, velocity on one axis and time on other . But as we know , that acceleration can be calculated by the formula which is
acceleration = change in velocity / time
hence , the derivative of velocity is acceleration
which mean that the slope of the Velocity - time graph shows the acceleration , which cannot be seen , but is hidden as the slope of that graph
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an art student is designing a large mobile with the dimensions shown below. object c has a mass of 1 kg, and objects b and c are in balance. what does the mass of object a need to be to balance objects b and c?
The mass of object a need to be to balance objects b and c is 12kg
Find man of b
1=[tex]\frac{m_{c}}{m_{b}+m_{c}}[/tex]×4
1=[tex]\frac{1}{1+m_{b} }[/tex]×4
[tex]m_{b}[/tex]=3kg
1=[tex]\frac{(m_{b}+m_{c} )}{m_{a} +(m_{b} +m_{c} )}[/tex] ×4
1=4×4/[tex]m_{a}[/tex]+4
[tex]m_{a}[/tex]=12kg
As a measure of inertia, which is a fundamental characteristic of all matter, mass is used in physics. Effectively, it is the resistance a body of matter offers to a change in its speed or position as a result of the application of a force. The change caused by an applied force is proportional to the mass of the body. The kilogram is the measure of mass in the International System of Units (SI). Its definition is based on the Planck constant, which is set at 6.62607015 1034 joule second. The unit of energy known as a joule is one-kilogram times one square meter per second. The kilogram is determined by precise measurements of Planck's constant, while the second and metre are previously defined in terms of other physical constants.
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A basketball hoop is 3.05 m above the playing surface. A basket is made. The ball reached a maximum height that was 2.00 m above the height of the basket hoop. The basketball was launched from a height of 1.95 m. If the ball traveled a horizontal distance of 5.20 m in 2.00 seconds, what was the initial velocity of the basketball?
Answer:
In this question, we have given a basketball hoop that is 3.05 m above the playing surface and the basket is made. The basketball was launched from a height of 1.95 And if the ball travels the original distance of 5.2 m in two seconds, then we have to find the initial velocity of the basketball. So we can find given data is we have given the horizontal distance traveled, that is d is equals to 5.2 m Per meter. And we have given the time taken to cover this distance, that is T equals to two seconds. So we can find the original velocity. So we can see that horizontal velocity that is three X is equal to, this is 5.2 upon two, and this will come out to be 2.6 meter per second. Now we can see that as we have given That the basketball hoop is 3.05 m above the playing surface. So we can say that the height covered, that is delta edges 3.5 minus 1.95. And this will comes out to be 1.10 m. So, using the equation of motion, we can find the vertical velocity Y. So we can say that that is is, we can apply in and wind direction. So we can say that delta edge is equals to this is initial velocity in y direction into time, T plus half into exhalation in y direction into T square. So we can say this is equals to 1.10, that is we're not y and to time is two seconds blood half into disease. Here, exploration is the gravitational acceleration and it is acting downwards. So this is equal to -3, which is -9.8 into two square. So from here we can find the value of velocity in the Y direction. That is 10.35 m/s. So we have the velocity in X direction and velocity in the Y direction. So we can see that the initial velocity that is we note is equal to this under root of we're not in extraction plus we're not wise square. So we can say this is equal to under root of 2.60 sq Plus 10.35 ft sq. And this will comes out to be 10.67 m/s. But this is the answer of arguing cushion. Thank you.
AP physics 1: Extra points!!
The weight of box 2 and box 3 is 33.72N and 15.32N
According to Lami's Theorem, if three forces acting at a point are in equilibrium, each force is proportional to the sine of the angle between the other two forces. The magnitudes of concurrent, coplanar, and non-collinear forces that keep an object in static equilibrium are all related to Lami's Theorem. This theorem also aids in the analysis of most mechanical and structural systems. For all three forces used in Lami's Theorem, the proportionality constant is the same.
Given box1 weighs 31N
Given two angles 63 and 24
So the third angle will be
180 – 87
= 93
By using Lamis theorem
T_2/(SIN 93)=T_3/(SIN (90+63))=T_1/(SIN (90+24))
Here T1 = 31N
Weight of box 2 = w2 = 31/cos24 x sin 93
= 33.72
Weight of box 3 = w3 = 31/cos24 x cos 63
= 15.32
Therefore the weight of box 2 and box 3 is 33.72N and 15.32N
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If the man pulls the sled with a 10 N
force, what is the horizontal component
of force? Refer to chapter 4, mechanics if
you do not remember how to resolve a
force into its components.
Answer:
Explanation:
The horizontal component of force is Fcosθ if the man pulls the sled with a 10 N force. Force has both a magnitude and a direction since it is a vector quantity.
What is force?A force is an external cause that, when applied, alters or has the potential to alter a body's condition. The body comes to rest while it is moving, and it moves when it is at rest.
The body's orientation, form, size, etc. may also alter as a result. An illustration would be to push or forcefully shove a door. Force has both a magnitude and a direction since it is a vector quantity. If the man pulls the sled with a 10 N force then the horizontal component of force is Fcosθ. Your training at this level should place a major emphasis on the idea that a push or even a pull was referred to as an force.
Therefore, the horizontal component of force is Fcosθ if If the man pulls the sled with a 10 N force.
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