A 12.2 mL sample of liquid was found to have a mass of 10.4 g. Calculate the density of this liquid ( in g/mL).

Answers

Answer 1

Answer:

d=m/

Explanation:

d is density, m is mass, v is volume

Given: m =10.4g, v=12.2mL

substituting in equation,

d=10.4/ 12.2

d=0.8524g/mL

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Answer 2

The density of the liquid is 0.852 g/mL.

To calculate the density of the liquid, we need to use the formula:

Density = Mass / Volume

Given that the mass of the liquid is 10.4 g and the volume is 12.2 mL, we can substitute these values into the formula:

Density = 10.4 g / 12.2 mL

Simplifying this expression, we find:

Density = 0.852 g/mL

Density is a physical property of a substance and is defined as the amount of mass per unit volume. In this case, the density tells us that for every milliliter of the liquid, there is 0.852 grams of mass. The units of grams per milliliter (g/mL) indicate that the density is a ratio of mass to volume.It is important to note that the density of a substance can vary with temperature, so this value is only valid under the conditions at which the measurement was made. Additionally, the density can provide valuable information about the identity of a substance, as different substances have different densities.

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Related Questions

59.6 ml of air is at 20.5 °C. What is its volume at 73.9 °C?

Answers

The volume of air at 73.9 °C would be approximately 70.91 ml.

To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature when pressure and amount of gas are kept constant.

Let's assume that the pressure and amount of air remain constant.

Given:

Initial volume (V1) = 59.6 ml

Initial temperature (T1) = 20.5 °C = 20.5 + 273.15 K = 293.65 K

Final temperature (T2) = 73.9 °C = 73.9 + 273.15 K = 347.05 K

Using Charles's Law, we can set up the following proportion:

V1 / T1 = V2 / T2

Plugging in the values, we have:

59.6 ml / 293.65 K = V2 / 347.05 K

To solve for V2 (the final volume), we can rearrange the equation:

V2 = (59.6 ml * 347.05 K) / 293.65 K

V2 = 70.91 ml

Therefore, the volume of air at 73.9 °C would be approximately 70.91 ml.

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A sample of gas is put into a rigid (fixed volume) container at 3 oC and a pressure of 38.5 kPa. The container is then placed in an oven at 267 oC.

What pressure would you expect to measure for the gas in the container at this higher temperature?

Answers

We would expect to measure a pressure of approximately 75.25 kPa for the gas in the container at the higher temperature of 267 oC.

To determine the expected pressure of the gas in the container at the higher temperature, we can use the combined gas law, which relates the initial and final conditions of temperature and pressure in a fixed volume system. The combined gas law equation is given as:

(P1 * V1) / T1 = (P2 * V2) / T2

Where:

P1 = Initial pressure

V1 = Initial volume (which is fixed in this case)

T1 = Initial temperature

P2 = Final pressure (to be determined)

V2 = Final volume (which is fixed in this case)

T2 = Final temperature

In this scenario, the initial conditions are given as 3 oC (which is equivalent to 276 K) and 38.5 kPa. The final temperature is 267 oC (which is equivalent to 540 K). Since the volume is fixed, we can substitute the given values into the equation:

(38.5 kPa * V1) / 276 K = (P2 * V1) / 540 K

Simplifying the equation, we can cancel out V1:

38.5 / 276 = P2 / 540

Solving for P2:

P2 = (38.5 / 276) * 540 ≈ 75.25 kPa

Therefore, we would expect to measure a pressure of approximately 75.25 kPa for the gas in the container at the higher temperature of 267 oC.

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help, help,help girlll pleasee help​

Answers

From the diagram that is shown;

a. The letter B

b. The letter C

c. It is an exothermic reaction

d. Letter A

e. Letter D

f. Letter D

g. Letter A

What is the reaction coordinate?

The progression of a chemical reaction from the reactants (beginning materials) to the products (end products) is conceptually represented by the reaction coordinate. It offers a means of observing and evaluating the energy shifts and structural modifications that take place throughout a reaction.

The horizontal axis of a reaction coordinate diagram or energy profile shows how the reaction is progressing, usually from left to right. The system's potential or free energy is shown on the vertical axis. The reaction coordinate can be expressed in terms of separation, bond length, or any other appropriate parameter that accurately characterizes the reaction's progress.

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Calculate the volume occupied by the oxygen gas at a pressure of 210 kPa and temperature of 50°C. Use your answer from question 27 to help you solve this problem. Report your answer in liters with 3 significant figures._______L ​

Answers

Answer:

holaholaholaholaholaholaholahola

The volume occupied by the oxygen gas at a pressure of 210 kPa and a temperature of 50°C is 0.126 liters, rounded to three significant figures.

To calculate the volume occupied by the oxygen gas at a pressure of 210 kPa and a temperature of 50°C, we can use the ideal gas law equation:

PV = nRT

where:

P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

First, we need to convert the given temperature from Celsius to Kelvin by adding 273.15:

T = 50°C + 273.15 = 323.15 K

Next, we rearrange the ideal gas law equation to solve for volume:

V = (nRT) / P

To find the number of moles (n), we can use the answer from question 27, which is the mass of oxygen gas:

m = 32 g

Using the molar mass of oxygen (O₂) which is approximately 32 g/mol, we can calculate the number of moles:

n = m / M = 32 g / 32 g/mol = 1 mol

Now we have all the values needed to calculate the volume:

V = (1 mol * 8.314 J/(mol*K) * 323.15 K) / 210,000 Pa

Using the ideal gas constant (R) of 8.314 J/(mol*K) and the pressure of 210 kPa (which is equivalent to 210,000 Pa), we can substitute these values into the equation and solve for volume.

V = 0.126 liters.

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. Convert 6.02 x 105 mol of diethyl ether to molecules of diethyl ether:​

Answers

you have approximately 3.627 x 10^29 molecules of diethyl ether.

To convert from moles to molecules, you can use Avogadro's number, which states that there are approximately 6.022 x 10^23 molecules in one mole of a substance.

Given that you have 6.02 x 10^5 moles of diethyl ether, you can use Avogadro's number to convert it to molecules as follows:

6.02 x 10^5 mol x (6.022 x 10^23 molecules/mol) = 3.627 x 10^29 molecules

It's important to note that diethyl ether (C4H10O) is a compound composed of carbon, hydrogen, and oxygen atoms. Each molecule of diethyl ether consists of 10 atoms (4 carbon atoms, 10 hydrogen atoms, and 1 oxygen atom).

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Why is biodiversity important to people (e.g. in terms of health, agriculture, etc.)?

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Biodiversity is critical to humans because it provides a range of ecosystem services that support life and well-being.

These services include the production of food, medicine, and building materials; regulation of the climate and disease control.

The value of biodiversity to agriculture is demonstrated by the fact that a single crop can depend on hundreds of species of insects, bacteria, and fungi.

Pollination, pest control, soil formation, nutrient cycling, and water filtration are all provided by diverse ecosystems.

Biodiversity also offers several advantages to human health.

The world's pharmacopoeia is made up of a significant percentage of natural products.

This includes more than 50,000 plant-based compounds, many of which are used to create drugs.

Coral reefs and rainforests are two examples of ecosystems that house a wide range of biological diversity.

These ecosystems are also home to a wide range of microorganisms that offer new leads for pharmaceutical development.

Furthermore, biodiversity provides spiritual, cultural, and recreational benefits.

As biodiversity is increasingly threatened, these essential benefits are being lost.

Protecting biodiversity and maintaining a healthy planet is critical to safeguarding human health and well-being.

Humans must work to conserve and manage biodiversity to ensure the continuation of the ecosystem services that are essential for our survival.

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The pressure exerted by a confined gas is the result of

gas particles colliding with each other
gas particles colliding with the walls of the container
nobody knows, it just is
gas particles taking up space in the container

Answers

The pressure exerted by a confined gas is the result of Option b. gas particles colliding with the walls of the container.

The pressure exerted by a confined gas is the result of gas particles colliding with the walls of the container. When a gas is confined within a container, the gas particles are in constant motion, moving in random directions with varying speeds. As these gas particles move, they collide with each other and with the walls of the container.

When a gas particle collides with the walls of the container, it exerts a force on the surface. The collective effect of numerous gas particle collisions leads to a net force being exerted on the walls of the container. This force per unit area is what we call pressure.

The more frequently and vigorously the gas particles collide with the walls, the higher the pressure of the gas. Factors that influence gas pressure include the number of gas particles present, their average speed, and the volume of the container. Therefore, Option b is correct.

The question was incomplete. find the full content below:

The pressure exerted by a confined gas is the result of

a. gas particles colliding with each other

b. gas particles colliding with the walls of the container

c. nobody knows, it just is

d. gas particles taking up space in the container.

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a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!​

Answers

The jumbled word "gzeysktqix" can be unscrambled to form the word "skyzigtext."

Here are possible words that can be made from this jumbled word:

Sky: Referring to the atmosphere above the Earth.

Zig: Describing a series of sharp turns or angles.

Text: Referring to written or printed words.

Six: The number following five and preceding seven.

It seems that the jumbled word has provided a mix of letters that can be rearranged to form these words. This exercise is likely intended to enhance the student's vocabulary skills, spelling ability, and problem-solving skills. By unscrambling the letters, the student is encouraged to explore different word possibilities and apply their knowledge of language. It also promotes critical thinking and creativity as they find valid words from the given set of letters.

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5. The density of water at 4.00°C is 0.967 g/mL. How many molecules of water are present in a 499.8 mL bottle of water? Express your answer to the correct number of significant figures

Answers

There are approximately 1.62 x 10^25 water molecules in the 499.8 mL bottle of water.

To determine the number of water molecules in the given volume of water, we need to use the relationship between mass, volume, and molar mass of water.

First, we need to find the mass of water in the bottle:

Mass = Density * Volume

Mass = 0.967 g/mL * 499.8 mL = 483.9 g

Next, we need to convert the mass of water to moles using the molar mass of water. The molar mass of water (H2O) is approximately 18.015 g/mol.

Moles = Mass / Molar mass

Moles = 483.9 g / 18.015 g/mol = 26.88 mol

Finally, we can calculate the number of water molecules using Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules = Moles * Avogadro's number

Number of molecules = 26.88 mol * (6.022 x 10^23 molecules/mol) = 1.62 x 10^25 molecules

Therefore, there are approximately 1.62 x 10^25 water molecules in the 499.8 mL bottle of water.

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the table shows the percentages of some gases in the exhaust from a petrol engine what is the name of the compound that makes up most of the other gases

Answers

The other compound that makes up most of the other gases in the table is water vapor.

What is water vapor?

Water vapor is not listed in the table because it is not a pollutant. However, it is a significant component of exhaust gas, and it can contribute to smog formation. Water vapor is formed when the fuel in a petrol engine is burned. The combustion process produces water as a byproduct.

The amount of water vapor in the exhaust gas depends on the temperature of the combustion process. At higher temperatures, more water vapor is produced. Water vapor is not a pollutant in itself, but it can contribute to smog formation.

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Complete question:

this table shows the percentages of some gases in the exhaust from a petrol engine

nitrogen 68

carbon dioxide 15

carbon monoxide 1

oxygen 0.75

nitrogen oxides 0.24

hydrocarbons 0.005

sulphur dioxide 0.005

other gases

what is the name of the other compound that makes up most of the other gases in the table?

A reaction requires 22.4 L of gas at STP. You have 45.0 L of gas at 100 kPa and 373 K. Which of the following statements is true? The gas
constant is 8.31 L-kPa/mol-K.

You do not have enough gas for the reaction to occur.
You will have too much gas for the reaction to occur.
You will have an excess of gas and the reaction will occur.
You cannot tell given this information.

Answers

Using the ideal gas law, we can calculate the number of moles of gas present in the given conditions:
```
PV = nRT
n = (PV) / RT
n = ((100 kPa)(45.0 L)) / (8.31 L-kPa/mol-K)(373 K)
n = 1.64 mol
```
The given volume of gas is greater than the required 22.4 L, so we can conclude that the correct statement is:
You will have an excess of gas and the reaction will occur.

Therefore, the correct answer is option C: You will have an excess of gas and the reaction will occur.

Answer:

(c). You will have an excess of gas and the reaction will occur.

Explanation:

We can use the ideal gas law to calculate the number of moles of gas in each case. The ideal gas law is:

PV = nRT

where:

P is the pressure in pascalsV is the volume in litersn is the number of moles of gasR is the gas constant (8.31 L-kPa/mol-K)T is the temperature in Kelvin

At STP, the pressure is 1 atm (101.325 kPa) and the temperature is 273.15 K. So, the number of moles of gas at STP is:

[tex]n =\frac{ PV }{ RT} =\frac{ (101.325 kPa)(22.4 L) }{(8.31 L-kPa/mol-K)(273K)} = 1mol[/tex]

At 100 kPa and 373 K, the number of moles of gas is:

[tex]n =\frac{ PV }{ RT} =\frac{ (100 kPa)(45 L) }{(8.31 L-kPa/mol-K)(373 K)} = 1.45mol[/tex]

So, you have 1.45 moles of gas at 100 kPa and 373 K. The reaction requires 1 mole of gas at STP, so you have an excess of 0.45 moles of gas. The excess gas will not participate in the reaction, but it will not prevent the reaction from occurring.

Therefore, the correct answer is (c). You will have an excess of gas and the reaction will occur.

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An automobile engine has a cylinder with a volume of 500.0 mL that is filled with air (21.00 % oxygen) at a temperature of 55.00 C and a pressure of 101.0 kPa. What is the mass of octane, C8H18 that must be injected to react with all of the oxygen in the cylinder to produce carbon dioxide and water? 2C8H18 + 25O2 -------->. 16CO2 + 18H2O

Answers

The mass of octane, C8H18 that must be injected to react with all of the oxygen in the cylinder to produce carbon dioxide and water is 0.14 g.

The balanced equation for the combustion of octane is:2C8H18 + 25O2 → 16CO2 + 18H2OFrom the above balanced chemical equation, we can see that 25 moles of O2 react with 2 moles of C8H18.

So, 12.5 moles of O2 will react with 1 mole of C8H18. We can use the ideal gas law PV = nRT to calculate the moles of oxygen present in the cylinder.

Here, we need to use the partial pressure of oxygen only since we are interested in the moles of oxygen only.

O2 = 21.00% × 101.0 kPa = 21.21 kPaV = 500.0 mL = 500.0/1000 = 0.5000 L (convert mL to L)R = 8.314 J/mol K (gas constant).

We have,PV = nRTn = PV/RTn = (21.21 × 10^3 Pa) × (0.5000 × 10^-3 m^3) / (8.314 J/mol K × 328.15 K) = 0.01578 moles of O2.

Since 12.5 moles of O2 react with 1 mole of C8H18,0.01578 moles of O2 will react with= (0.01578 moles × 1 mole C8H18)/12.5 moles = 0.001262 moles of C8H18

The molar mass of C8H18 is = 8 × 12.01 + 18 × 1.01 = 114.16 g/mol.

So, the mass of C8H18 required is = 0.001262 × 114.16 = 0.1445 g or 0.14 g (approx.)

Therefore, the mass of octane, C8H18 that must be injected to react with all of the oxygen in the cylinder to produce carbon dioxide and water is 0.14 g.

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Describe the following trends in properties of chlorides across period 3. a) formula. b) state c) their pH of aqueous chlorides solution d) thier structure e) their volatility​

Answers

These trends in properties of chlorides across period 3 reflect the changing nature of the elements and their bonding characteristics within the period.

The trends in chloride characteristics throughout period 3 can be summarised as follows:

a) Formula: The chlorides in period 3 have the general formula MX, where M stands for metal and X stands for chlorine.

b) State: At room temperature, the chlorides in period 3 can exist in a variety of states. Solids include sodium chloride (NaCl) and magnesium chloride (MgCl2), while liquids include aluminium chloride (AlCl3) and silicon tetrachloride (SiCl4). Sulphur dichloride (SCl2) and phosphorus pentachloride (PCl5) are gases.

c) Aqueous chloride solution pH: The pH of aqueous chloride solutions varies according on the chloride. The pH of water is not greatly affected by sodium chloride, magnesium chloride, or aluminium chloride, resulting in a neutral solution. Certain chlorides, such as phosphorus pentachloride, can, however, hydrolyze in water to release acidic hydrogen chloride, resulting in an acidic solution.

d) Structure: The structure of chlorides in period 3 varies. Sodium chloride and magnesium chloride have a crystalline structure, while aluminum chloride exists as a dimer, with two AlCl3 molecules joining together. Silicon tetrachloride forms a tetrahedral structure, and phosphorus pentachloride has a trigonal bipyramidal structure.

e) Volatility: The volatility of chlorides in period 3 increases from sodium chloride to silicon tetrachloride. Sodium chloride has a high melting and boiling point and is relatively non-volatile. Magnesium chloride has a slightly higher volatility. However, aluminum chloride, silicon tetrachloride, phosphorus pentachloride, and sulfur dichloride are more volatile and readily convert from solid or liquid states to gaseous states with increasing temperature.

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A bottle of rubbing alcohol contains both 2-propanol and water.
These liquids can be separated by the process of distillation because the 2-propanol and water
A) have combined chemically and retain their different boiling points
B) have combined physically and have the same boiling point
C) have combined physically and retain their different boiling
DOmIS
D) have combined chemically and have the same boiling point

Answers

These liquids can be separated by the process of distillation because the 2-propanol and water option B) have combined physically and have the same boiling point.

A bottle of rubbing alcohol contains both 2-propanol and water.

These liquids can be separated by the process of distillation because the 2-propanol and water have combined physically and retain their different boiling points.

The process of separating two miscible liquids with different boiling points is called distillation.

The procedure is based on the idea that the liquids have various boiling points.

Thus, during the boiling process, one of the fluids vaporizes faster than the other, and that vapor is then collected and allowed to condense, producing pure liquid.

Alcohol and water are examples of two miscible liquids that can be separated by distillation.

The process of distillation operates on the fact that the liquid with the lowest boiling point is vaporized first.

Alcohol has a lower boiling point than water, so alcohol is vaporized first in distillation, leaving the water behind.

A bottle of rubbing alcohol contains both 2-propanol and water.

These liquids can be separated by the process of distillation because the 2-propanol and water have combined physically and retain their different boiling points.

This means that 2-propanol and water are physically combined; that is, they do not form any new chemical bonds with each other.

Consequently, the molecules of the substances remain separate from each other.

Furthermore, both water and 2-propanol have various boiling points.

The boiling point of 2-propanol is 82.6 °C, while that of water is 100 °C. Thus, they can be separated using distillation.

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The sun is reportedly 92,960,000 miles from Earth. How many significant figures does this number have?

Answers

Answer: The correct answer would be 4

Have a great day!

-Convert 6.02 x 1020 formula units of MgCl₂ to mol of MgCl₂:​

Answers

6.02 x [tex]10^{20[/tex] formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.

Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.

Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:

(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))

The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:

(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol

Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.

Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.

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2PbS + 3O2 ⟶ 2Pb + 2SO3
Using the balanced equation how many grams of lead will be produced if 2.54 grams of PbS is burned with 1.88 g of O2? work the problem with both PbS and O2.

Answers

From the equation 2PbS + 3O2 ⟶ 2Pb + 2SO3 we can produced 8.12 g of lead  if 2.54 g of PbS is burned with 1.88 g of O2.

To find the mass of lead produced, we need to find the limiting reactant (i.e. the reactant that is consumed first).

We can find the limiting reactant by calculating the number of moles of each reactant and then using the mole ratio from the balanced equation.

Number of moles of PbS = mass / molar mass = 2.54 / 239.27 = 0.0106 mol

Number of moles of O2 = mass / molar mass = 1.88 / 32 = 0.0588 mol

From the balanced equation, the mole ratio of PbS to O2 is 2:3.

Therefore, for every 2 moles of PbS, we need 3 moles of O2.

We can use this information to calculate how many moles of O2 are needed for 0.0106 moles of PbS.0.0106 mol PbS × (3 mol O2 / 2 mol PbS) = 0.0159 mol O2.

Since the actual amount of O2 we have is less than what is needed (0.0159 mol), O2 is the limiting reactant.

This means that PbS is in excess and we can calculate the mass of lead produced using the amount of O2 that reacted.

The balanced equation tells us that 3 moles of O2 produce 2 moles of lead.

Therefore,0.0588 mol O2 × (2 mol Pb / 3 mol O2) = 0.0392 mol PbFinally, we can calculate the mass of lead produced using the number of moles and the molar mass of lead.mass of Pb = number of moles × molar mass= 0.0392 mol × 207.2 g/mol= 8.12 g.

Therefore, 8.12 g of lead will be produced if 2.54 g of PbS is burned with 1.88 g of O2.

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Match each reaction to its correct type by dragging it to the appropriate box on the left. Click Done to
check your answers. Drag the items on the left to the correct location on the right.

Answers

From the image attached;

Reaction 1 - Oxidation reduction

Reaction 2 - Precipitation reaction

Reaction 3 - Acid base reaction

Reaction 4 - Reaction with oxygen

What is reaction?

A reaction is a procedure or an occurrence in which a change takes place, frequently leading to the conversion of one or more compounds into other substances. A chemical reaction, which entails the rupturing and creation of chemical bonds between atoms or molecules, is what is meant when the word "reaction" is used in reference to chemistry.

When reactant molecules collide with enough force and in the right orientation, the current chemical bonds are broken, and new bonds are formed, converting the reactants into products.

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Which of the following set of quantum numbers (ordered n, ℓ, mℓ ) are possible for an electron in an atom? Check all that apply
a. 2, 1, 3
b. 5, 3, -3
c. 4, 3, -2
d. -4, 3, 1
e. 2, 1, -2
f. 3, 2, 2
g. 3, 3, 1

Answers

the possible quantum numbers (ordered n, ℓ, mℓ ) are:Option B.5, 3, -3 and Option C. 4, 3, -2

The quantum numbers n, ℓ, mℓ represent respectively the principal quantum number, the orbital angular momentum quantum number and the magnetic quantum number.

These are the three most important quantum numbers. T

here is another quantum number called the spin quantum number, denoted by ms.

Let's see which of the given quantum number sets is possible.2, 1, 3 is not possible because for ℓ = 1, mℓ can only be -1, 0, or 1. 5, 3, -3 is possible.4, 3, -2 is possible. -4, 3, 1 is not possible.

For any value of ℓ, mℓ must be between -ℓ and +ℓ. e. 2, 1, -2 is not possible because for ℓ = 1, mℓ can only be -1, 0, or 1. f. 3, 2, 2 is not possible because for ℓ = 2, mℓ can only be -2, -1, 0, +1, or +2. g. 3, 3, 1 is not possible because for any value of ℓ, mℓ must be between -ℓ and +ℓ.

Therefore, the possible quantum numbers (ordered n, ℓ, mℓ ) are:5, 3, -34, 3, -2

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Other Questions
Subject - Business EthicsOne of the most important characteristics of an effective leader is treating people equitably. This involves fairness and consistency, including regards to applying the rules to everyone equally. What should a coach do when a few superstar players get caught breaking rules that should lead to their suspension from the team immediately before a big game that is very important to the team?If the star players don't play, there is a good chance the team will lose. If the team has to win this game to advance to the championship game, should that affect the coach's decision?If the coach doesn't apply appropriate consequences to the actions of the players who broke the rules, what lesson are those players learning? Will they continue to break rules?What about the other players who do follow the rules. Will they learn that the rules are just suggestions and feel like they don't need to comply in the future?What if one of the players who broke the rules will miss a chance to be seen by professional scouts if he doesn't play in the game?What if the team's school will earn a large amount of money from television coverage of the big game if the team goes to the championship?What if the coach is set to earn a big bonus or significant pay increase if the team advances to the championship game?Coaches are responsible for winning, but they're also responsible for setting an appropriate example of leadership for players and treating all team members fairly. What may seem to be an obvious choice between right and wrong at first glance is really much more complicated.Write two paragraph answer to describe what you would do if you were the coach and what factors influenced your final actions. suppose f has absolute minimum value m and absolute maximum value m. between what two values must 7 5 f(x) dx lie? (enter your answers from smallest to largest.) On March 1, 2021, Yogurt Ltd. issued $300,000, 6%, 10-year bonds at 105. The bonds pay interest semi-annually on September 1 and March 1. The company has a December 31 year end. Assume amortization of $900 and $860 respectively for the first two semi- annual interest periods. On March 2, 2022 the company redeemed the bonds at a price of $312,000. Instructions Prepare the journal entries that Yogurt Ltd. would make related to the bond issue on the dates indicated below: March 1, 2021 September 1, 2021 December 31, 2021 March 1, 2022 March 2, 2022Previous question The American Yawp Article by Matthew Desmond, summarize andexplain the article express 3.765765765... as a rational number, in the form pq where p and q have no common factors. p = and q = not all of the members of everyday categories have all of the same features. most fish have gills, fins, and scales. however, sharks lack the feature of scales, yet they are still categorized as fish. similarly, most birds have wings and can fly, with the exception of penguins, ostriches and emus. this poses a problem for the approach to categorization. what are the coordinates of the midpoint of ab with endpoints a(0, 6) and b(2, 4). Make your own slogan on " Ascendance of Chinese Mestizos." in relation to this module.Briefly explain your slogan in not more than 200 words. Describe how dynamic pricing works including information required to set prices using this strategy. Give at least one example of an industry which typically uses dynamic pricing and explain how this works to maximise the returns to these companies. if the student hears a sound at 15 db, what is the intensity of the sound? Bids were invited under international competitive tender for procurement of equipment valid usd 3m. Bidding documents stated that bidder offering group a bids (domestic) are solely responsible for applying for any deemed export benefits and in case of failure to receive such benefits resulting in imposition of duties and taxes, the said duties and taxes shall not be rembursed by the purchase. Bidders who do not accept this provision will be declared non-responsive and be rejected. Borower received from Group A bids as under.Bidde 1: Two prises, one with and another without deemed export benefitsBidder 2: One price, no conditionBidder 3: One price, subject to deem export benefits onlyBidder 4: One price conditionBorrower proposed to reject the bids submitted by bidder 1 and 3 as non responsive. Is he right? What is your view? Suppose you were implementing a data structure to store information about the paintings on display at an art dealer's Of the following data structures, which one is the right one to use? 1. )Unordered array 2.)Sorted array 3.)Linked list 4.)Binary search tree 5.)It depends [This was a recurring theme in our discussions of data structures. You have to know how the data structure will be used and which operations need to be efficient to make an intelligent choice. List all the steps involved in a typical Bill of Exchange transaction between the 4 main parties involved; Exporter, Importer, Exporter's Bank and Importer's Bank. First step is outlined below. Step 1 - Contract of sale signed by the importer and exporter. why are the processes of mitosis and cytokinesis necessary for cellular health Jean has a capital balance of P480,000 in a local partnership and Storm has a balance of P360,000. These two partners share profit and losses by a ratio of 60:40. ROgue invests P240,000 in cash in the partnership for a 20% ownership. The revaluation method was used. What is the Storm's capital balance after admission? 448,000 O 504,000 398,400 408,000 12. a) The price of blueberries falls from $2.50 to $1.50 per carton and the quantity demanded goes up from 100,000 to 300,000 cartons. Calculate the price elasticity of demand (En). Is demand elastic or inelastic? Say why it is elastic or inelastic. 12. b) At the same time that blueberries fell in price from $2.50 to $1.50 per carton, the demand for another good (Good A) increased from 2000 to 4000. Calculate the cross-price elasticity of demand Exy. What is the relationship between blueberries and good A? Explain why. 13. After Bintou's income increased from $12,000 to $18,000 a year, her purchases of CDs decreased from 30 to 20 CDs a year. Calculate Bintou's income elasticity (E) of demand for CDs. What type of goods are CDs? Explain why. Mr. Onit, age 60, is a retailer who incorporated his business in 2008 under the name of Onit Ltd. The common shares of Onit Ltd., held by Mr. Onit, have a paid-up capital (PUC) value and adjusted cost base (ACB) for tax purposes of $2,500 and were issued to Mr. Onit on incorporation. The present fair market value of the shares is $4,000,000. Mr. Onit wishes to incorporate a holding company, HoldOnitco Ltd., for estate planning purposes. His daughter, age 34, will invest $45,000 of her own money in 500 common shares with a total stated value of $10. His wife will invest $12,500 of her own money in 6% voting preferred shares with a total stated value of $100. He will take back as partial consideration for his shares of Onit Ltd. 3,500 voting, retractable 6% preferred shares with a total retraction value of $3,500,000. In addition, he will take back $500,000 in cash. He will elect with the corporation to transfer his shares of Onit Ltd. at $500,000 to use up the remainder of his capital gains exemption. REQUIRED (A) Outline the tax consequences of Mr. Onit's plan supported by your computations assuming: (i) an ultimate redemption of the 6% preferred shares at their fair market value; and (ii) an arm's length sale of the 6% preferred shares. (B) Indicate briefly your recommendations as to how Mr. Onit might rearrange his plan to avoid any problems arising from the plan presented. Georgia Inc. and Harvard Co. have an exchange with no commercial substance. The asset given up by Georgia Inc. has a book value of $36,000 and a fair value of $45,000. The asset given up by Harvard Co. has a book value of $60,000 and a fair value of $57,000. Boot of $12,000 is received by Harvard Co. What amount should Georgia Inc. record for the asset received? O $45,000 $57,000 $50,000 $48,000 AR TEMERLO SUNTE ITE MENTEN 150.0008.06 2007-1000698 please help me evaluating the 2014 state of the union speech?for example where did it take place? the speakers voice and etc how is workers' compensation insurance funded under a state fund?