A 290 Hz sound wave is directed into one end of a trombone slide seen in the figure. A microphone is placed at the other end to record the intensity of sound waves that are transmitted through the tube. The straight sides of the slide are 80 cm in length and 10 cm apart with a semicircular bend at the end. (Figure 1)

Answers

Answer 1

The length of the extension might be gap of less than 80cm, then the possible length of extension would be  0.83cm, 0.30cm, 0.60cm. A microphone is placed at the other end to record the intensity of sound waves that are transmitted through the tube.

f =290Hz given

The standing wave condition for the given frequency of slide is ,

f=m(v/2L)

L = m.v/2f

r = 10cm/2 = 5cm

The total length of the tube due to extension in the slide is,

L =2(5+80cm)+πr

L= 25 +175.7cm

L = 25+ 1.757m

L = m.V/2f

25+ 1.757m = m.343/2×290

m = 0.5913m

S= (0.5913/2)m - 1.757/2

S = 0.2956m - 0.8785

For m= 1 hence

S =  0.2956(1) - 0.8785 = -0.5829Meter

For m= 2 then,

S =  0.2956(2) - 0.8785 = - 0.2873Meter

For m= 3

S =  0.2956(3) - 0.8785 = - 0.0083Meter

The length of the extension must be gap of less than 80cm. then the possible length of extension are, 0.83cm, 0.30cm, 0.60cm.

The complete question is,

A 290 Hz sound wave is directed into one end of a trombone slide seen in the figure. A microphone is placed at the other end to record the intensity of sound waves that are transmitted through the tube. The straight sides of the slide are 80 cm in length and 10 cm apart with a semicircular bend at the end.(Fiqure 1) For what slide extensions s will the microphone detect a maximum of sound intensity? Express your answer using two significant figures. If there is more than one answer, enter your answers in ascending order separated by commas. 四! ? Submit My Answers Give Up Figure 1 of 1 Provide F Continue 80 cm 10 cm

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A 290 Hz Sound Wave Is Directed Into One End Of A Trombone Slide Seen In The Figure. A Microphone Is

Related Questions

now look at your answers for the current coming out of the same battery when it is put in circuit 7 and then when it is put in circuit 8. are the currents from the battery the same in both cases? what can you say about the current through each bulb in circuit 7 compared with the current through each bulb in circuit 8?

Answers

No, the currents from the battery are not the same in both cases. In circuit 7, the current through each bulb is the same, as the bulbs are in parallel and the same current is passing through each one.

What is current?

Current refers to something that is happening or existing at the present moment in time. It is used to describe an event, a trend, or a state of affairs that is happening now. Current can also refer to the flow of electricity or a current of water.

In circuit 8, the current through each bulb is not the same, as the bulbs are in series and the current is split between them.

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Find the power series expansion of the principal branch of the log function about the point z = i. There are several ways to do this, one of which is really easy

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The power series expansion of the principal branch of the log function about the point z = i is .:

Log(z) = iπ/2 + (z-i)/i - (z-i)²/2i² + (z-i)³/3i³

What is the log function?

The logarithm function is described as  the inverse function to exponentiation which means the logarithm of a number x to the base b is the exponent to which b must be raised to produce x.

We will then apply  the formula for the derivative of the principal branch of the log function:

d/dz Log(z) = 1/z

Log(z) = Log(i) + (z-i)/i - (z-i)²/2i² + (z-i)³/3i³

where Log(i) =  the value of the principal branch of the log function at z = i.

So therefore Since Log(i) = ln(1) + iπ/2 = iπ/2,

Next step is to simplify the power series expansion :

Log(z) = iπ/2 + (z-i)/i - (z-i)²/2i² + (z-i)³/3i³

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Which statements describe the characteristics of a magnet? select four options.

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Magnets have two poles, attract specific materials, can repel and attract each other, and generate a magnetic field. These four characteristics describe the primary features of a magnet.


The characteristics of a magnet are:
1. A magnet has two poles, north and south.
2. A magnet can attract iron, cobalt, and nickel.
3. A magnet can repel another magnet if their poles are the same.
4. A magnet can create a magnetic field around it.
Hi! To answer your question about the characteristics of a magnet, I have selected four key features:

1. Magnets have two poles: One of the primary characteristics of a magnet is that it has two poles - a north pole and a south pole. These poles are responsible for the magnetic field generated by the magnet.

2. Magnets attract certain materials: Magnets are known to attract materials such as iron, nickel, and cobalt. These materials, when in contact with a magnet, experience a force that pulls them towards the magnet.

3. Magnets can repel and attract each other: When two magnets are brought close to each other, they can either attract or repel one another. If the opposite poles (north and south) are facing each other, they will attract, while if the same poles (north-north or south-south) are facing each other, they will repel.

4. Magnets generate a magnetic field: A magnet generates a magnetic field around itself, which is responsible for the attraction or repulsion of other magnets and magnetic materials. This field is invisible and can be represented by magnetic field lines.

In summary, magnets have two poles, attract specific materials, can repel and attract each other, and generate a magnetic field. These four characteristics describe the primary features of a magnet.

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constants a 508 g mass oscillates with an amplitude of 11.0 cm on a spring whose spring constant is 24.0 n/m .A. Determine the period T= ....... s B. Determine the maximum speed Vmax= ...... m/s C. Determine the total energy Wtotal= ........ J

Answers

The period T is 0.738 s, the maximum speed [tex]V_{max[/tex] 0.722 m/s and the total energy [tex]W_{total[/tex] is 0.264 J.

What is energy?

Energy is the capacity of a physical system to do work. It is a fundamental property of the universe that can be transferred and transformed from one form to another. Energy can take many forms, such as kinetic, thermal, electrical, nuclear, chemical, and gravitational energy. It is a measure of how much work can be done by a system.

A. The period of an oscillating system is given by T = 2π√(m/k), where m is the mass and k is the spring constant. Substituting in the given values we have:[tex]T = 2\pi\sqrt{(508 g/24.0 n/m)} = 2\pi\sqrt{(0.508 kg/24.0 N/m)} = 2\pi\sqrt{(0.021 kg/m) = 0.738s}[/tex]

B. The maximum speed of an oscillating system is given by [tex]V_{max[/tex] = √([tex]kx_{max/m[/tex]), where k is the spring constant, xmax is the amplitude of the oscillation, and m is the mass. Substituting in the given values we have:
[tex]V_{max[/tex] = √(24.0 N/m * 0.11 m/508 g) = √(2.64 N/m/0.508 kg) = √(5.23 m/s²/kg) = 0.722 m/s
C. The total energy of an oscillating system is given by Wtotal = ½ [tex]kx^2_{max[/tex], where k is the spring constant and xmax is the amplitude of the oscillation. Substituting in the given values we have:
[tex]W_{total[/tex] = ½ * 24.0 N/m * (0.11 m)² = 0.264 J.

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the theories that the mechanical functions of the body simply decay with age are called the .

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The theories that the mechanical functions of the body simply decay with age are called the "mechanistic theories of aging" or"wear and tear theory."

What is wear and tear theory?

The "wear and tear" theories of ageing suggest that the body's mechanical processes merely deteriorate with time. These ideas contend that throughout time, numerous body systems deteriorate and accumulate damage, which leads to ageing. This viewpoint holds that the body degrades gradually, much like a machine or mechanical item does with use and abuse.

Cellular senescence, DNA damage, oxidative stress, and the gradual loss of organ function are just a few causes of this wear and tear. While the wear and tear hypotheses offer some explanations for age-related changes, they fall short of fully encapsulating the intricate processes and underlying mechanisms that contribute to aging. According to recent studies, complex cellular and molecular mechanisms as well as genetic, environmental, and lifestyle factors all have a role in aging.

Therefore the theories that the mechanical functions of the body simply decay with age are called the "mechanistic theories of aging."

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The relationship between the actual air temperature X (in degrees Fahrenheit) and the temperature Y adjusted for wind chill (in degrees Fahrenheit, given a 10 mph wind) is given by the formula: y= -16 + 1.2x . Estimate the actual air temperature if the temperature adjusted for wind chill is -25 degrees Fahrenheit.a. -15b. -7.5c. -47d. -22.5

Answers

-47 degrees Fahrenheit is the actual air temperature if the temperature adjusted for wind chill is -25 degrees Fahrenheit

Define temperature

How hot or chilly the air is is determined by its temperature. The most typical weather parameter is it. Temperature is a more precise term for the kinetic energy, or energy of motion, of the airborne gases. The air temperature rises when gas molecules travel more swiftly.

Surface temperature is another name for it in meteorology. A thermometer that is placed outside but shielded from the light will read the temperature of the air.

y= -16 + 1.2x

The temperature adjusted for wind chill , Y is -25 degrees Fahrenheit

The actual air temperature is X

-25 = -16 + 1.2x

1.2x = -25+16

x = -9/1.2

x = -47

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12) A gas expands from an initial volume of 30.0 L to a final volume of 65.0 L at a constant pressure of 110 kPa. How much work is done by the gas during this expansion?
A) 3.85 kJ
B) 10.4 kJ
C) 3850 kJ
D) 10.4 MJ
E) 3.85 MJ

Answers

The work done by the gas during expansion is 3.85 kJ (option A).

When a gas expands at a constant pressure, the work done by the gas is given by W = PΔV, where P is the constant pressure and ΔV is the change in volume.

Substituting the given values, we get W = (110 kPa)(65.0 L - 30.0 L) = 3.85 kJ.

Therefore, the correct option is A.

It's important to note that work done by a gas is positive when the gas expands, as in this case, and negative when the gas is compressed.

This is because work is done by the gas on the surroundings during expansion and by the surroundings on the gas during compression.

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How much heat would be required to raise the temperature of a 525 g sample of copper from 20.° C to 100.° C? (Specific
heat of copper = 0.385 J/g-K)
A) -110 000 J
B) 16 000]
C) -16 000]
D 110 000 J

Answers

Answer:

Okay, here are the steps to solve this problem:

   The mass of the copper sample is 525 g

   The specific heat of copper is 0.385 J/kg-K

   The initial temperature is 20°C

   The final temperature is 100°C

   To convert from °C to K: T(K) = T(°C) + 273

   So:

   Initial T (K) = 20°C + 273 = 293 K

   Final T (K) = 100°C + 273 = 373 K

   Temperature change = 373 - 293 = 80 K

Heat Required = (Mass * Specific Heat * Temperature Change)

= (525 g * 0.385 J/kg-K * 80 K)

= 16000 J

So the answer is B: 16000 J

Explanation:

Much like scientists study cause and effect, firefighters and fire investigators observe the effects of a fire and try to find out its cause. Read the following example:
An office building caught fire early one morning, just as people were coming to work. Something caused the fire, and fire investigators need to collect data to determine what did it. Place a checkmark next to the data that could be related to the fire in this office building and could help them determine its cause:
A light switch with worn electrical wiring was found on the third floor.
Gasoline was stored in the basement of the building.
The building is in the downtown area of a big city.
It took firefighters 45 minutes to put out the fire.
The fire started on the third floor of the building.
People coming to work turned on the lights in the building.
People smoking in bed can start fires.
Oily rags were kept in an open container on the first floor.

Answers

The data that could be related to the fire in the office building and help determine its cause are: a light switch with worn electrical wiring found on the third floor, the fire started on the third floor of the building, and oily rags were kept in an open container on the first floor. Option 1, 5 and 8 are correct.

Fire investigators collect data to determine the cause of a fire. In this example, the fire started on the third floor of the building, and a light switch with worn electrical wiring was found on the same floor. This data suggests that the fire could have been caused by an electrical issue. Additionally, oily rags were kept in an open container on the first floor, which could have potentially contributed to the spread of the fire.

The fact that gasoline was stored in the basement or that the building is located in a downtown area may not be directly related to the cause of the fire. The time it took firefighters to put out the fire and people smoking in bed are also not directly relevant to the cause of the fire in this specific building. Option 1, 5 and 8 are correct.

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Answer: Correct answers is 1, 2, 4, 5, 6, and 8

Explanation:  A light switch with worn electrical wiring was found on the third floor. Gasoline was stored in the basement of the building. It took firefighters 45 minutes to put out the fire. The fire started on the third floor of the building. People coming to work turned on the lights in the building. Oily rags were kept in an open container on the first floor. All these choices are a possible cause for the fire, including the time the firefighters took to put the fire out.

hope this helps

When standing waves are produced in an experiment does INCREASING the tension produce a larger or smaller number of antinodes along the string? Please explain and support your answer using relevant equation.

Answers

Increasing the tension on the string will produce a smaller number of antinodes along the string.

What is tension?

Tension is a physical force that is created when two objects or surfaces are pulled in opposite directions. It is characterized by a pulling force that is exerted by one object or surface on another. Tension can also refer to a state of strain or anxiety caused by a difficult situation or problem. In physics, tension is often described as the force per unit area, or the force acting on a particular area. Tension is a vital component of many physics-based systems, such as bridges, cables, trusses, and tensile structures. In these systems, tension is used to resist forces applied to the system and to transmit forces to other components.

This is because the tension in the string affects the wave speed, which is determined by the equation v = √(T/μ),
where T is the tension and μ is the linear mass density of the string.
As the tension increases, the wave speed increases, resulting in a shorter wavelength and fewer antinodes.

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Two parallel wires carrying equal currents of 10 A attract each other with a force of 1 mN. If both currents are doubled, the force of attraction will be: A.1 mN B.4 mN C.0.5 mN D.0.25 mN E.2 mN

Answers

The force of attraction between the wires will be quadrupled, and the correct answer is (B) 4 mN.

What is Current?

Electric current is caused by the movement of charged particles, such as electrons, through a conductor or a circuit. The direction of the current flow is defined as the direction in which positive charges would flow, even though it is actually the negative charges (electrons) that are flowing.

The force between two parallel current-carrying wires is given by the expression:

F = (μ0I1I2L)/(2πd)

where μ0 is the permeability of free space, I1 and I2 are the currents in the wires, L is the length of the wires, and d is the distance between the wires.

Since the wires are identical and carry the same current, we can simplify the expression to:

F = (μ[tex]10^{2}[/tex]L)/(2π*d)

where I is the current in each wire.

Using the given values, we have:

F1 = (μ0[tex]10^{2}[/tex]L)/(2π*d)

where F1 is the force when each wire carries a current of 10 A.

If both currents are doubled, then the new force F2 is given by:

F2 = (μ0[tex]20^{2}[/tex]2L)/(2πd) = 4(μ0[tex]10^{2}[/tex]L)/(2πd) = 4F1

Therefore, the force of attraction between the wires will be quadrupled, and the correct answer is (B) 4 mN.

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The spool of wire having a weight of 300 lb rests on the ground at B and against the wall at A. Determine the normal force acting on the spool at A if P=300 lb. The coefficient of static friction between the spool and the ground is 0.35. The wall at A is smooth.

Answers

According to the question the normal force acting on the spool at A is = 195 lb

What is force?

Force is an invisible push or pull that can act upon objects. It is a fundamental interaction of nature, and is one of the four fundamental interactions of physics, along with gravity, electromagnetism, and the weak nuclear force. Force can cause objects to accelerate, decelerate, change direction, or even stay still. All of these changes are caused by an unbalanced force acting on an object. In physics, a force can be described mathematically as a vector quantity, with direction and magnitude both being important. Force has the ability to cause objects to move, change shape, vibrate, rotate, or accelerate.

The normal force acting on the spool at A is:
Normal force at A = 300 lb - (0.35 * 300 lb)
= 300 lb - 105 lb
= 195 lb

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how much more resistance does a 1cm diameter rod compared to a 2cm diameter rod made of the same material and same length

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The resistance of a conductor depends on its resistivity, length, and cross-sectional area. The 1cm diameter rod will have four times the resistance of the 2cm diameter rod.

The resistivity of a material is a constant that depends on the material's properties, and the length of the conductor is the same for both the 1cm diameter rod and the 2cm diameter rod.

Therefore, we can compare the resistances of the two rods by considering their cross-sectional areas.

The cross-sectional area of a 1cm diameter rod is  [tex]\pi /4 cm^2[/tex] (since the area of a circle is [tex]\pi r^2[/tex] and r = 0.5 cm), and the cross-sectional area of a 2cm diameter rod is  [tex]\pi cm^2[/tex] (since the radius is 1 cm).

Therefore, the cross-sectional area of the 2cm diameter rod is four times greater than the cross-sectional area of the 1cm diameter rod.

Since resistance is inversely proportional to cross-sectional area, the 2cm diameter rod will have one-fourth the resistance of the 1cm diameter rod made of the same material and same length.

In other words, the 1cm diameter rod will have four times the resistance of the 2cm diameter rod.

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a 3.55 l helium ballon at 101 kpa is released at sea level and rises to a height where the pressure is 950 kpa. determine the final volume of the balloon and its gas law

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To solve this problem, we need to use the combined gas law: (P1V1/T1) = (P2V2/T2), where P1, V1, and T1 are the initial pressure, volume, and temperature of the balloon, and P2, V2, and T2 are the final pressure, volume, and temperature of the balloon.

First, we need to convert the initial pressure of 101 kPa to 1 atm (101 kPa = 0.998 atm). We also know that the temperature of the balloon remains constant since it is released at sea level, where the temperature is roughly 15°C or 288 K.

Therefore, we can plug in the given values:

(0.998 atm)(3.55 L)/(288 K) = (950 kPa)(V2)/(288 K)

Simplifying the equation:

V2 = (0.998 atm)(3.55 L)(950 kPa)/(101 kPa)

V2 = 33.3 L

Therefore, the final volume of the balloon is 33.3 L. As for the gas law, since the temperature is constant, the gas law that applies is Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.

To determine the final volume of a 3.55 L helium balloon initially at 101 kPa that rises to a height where the pressure is 950 kPa, we can use Boyle's Law. Boyle's Law states that the product of the initial pressure and volume (P1V1) is equal to the product of the final pressure and volume (P2V2) for an isothermal process (constant temperature).

Step 1: Identify the initial pressure (P1), initial volume (V1), and final pressure (P2).
P1 = 101 kPa
V1 = 3.55 L
P2 = 950 kPa

Step 2: Apply Boyle's Law formula.
P1V1 = P2V2

Step 3: Solve for the final volume (V2).
V2 = P1V1 / P2

Step 4: Plug in the values and calculate V2.
V2 = (101 kPa × 3.55 L) / 950 kPa

Step 5: Calculate the final volume.
V2 ≈ 0.3768 L

The final volume of the helium balloon at 950 kPa is approximately 0.3768 L, and the gas law involved is Boyle's Law.

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two power lines run parallel for a distance of 269 m and are separated by a distance of 40.0 cm. if the current in each of the two lines is 120 a and if they run in opposite directions, determine the magnitude and direction of the force each wire exerts on the other.

Answers

Answer: To determine the magnitude and direction of the force each wire exerts on the other, we can use the formula for the magnetic force between two parallel conductors:

F = μ₀ * I₁ * I₂ * L / (2πd)

where F is the magnitude of the force, μ₀ is the permeability of free space (4π × 10⁻⁷ T·m/A), I₁ and I₂ are the currents in the two conductors, L is the length of the conductors that are parallel to each other, and d is the distance between the two conductors.

In this case, we have:

I₁ = I₂ = 120 A

L = 269 m

d = 0.40 m

Substituting these values into the formula, we get:

F = 4π × 10⁻⁷ T·m/A * 120 A * 120 A * 269 m / (2π * 0.40 m)

= 4π × 10⁻⁷ * 120² * 269 / 0.80

= 1.234 N

Therefore, the magnitude of the force each wire exerts on the other is 1.234 N.

To determine the direction of the force, we can use the right-hand rule. If we point the thumb of our right hand in the direction of the current in the first wire, and the fingers of our right hand in the direction of the current in the second wire, then the direction of the force will be perpendicular to the plane defined by the two currents, and will be given by the direction of our extended palm. If the force on the first wire is F₁, and the force on the second wire is F₂, then we have:

F₁ = -F₂

where the negative sign indicates that the two forces are in opposite directions. Therefore, the force on the first wire is directed towards the second wire, and the force on the second wire is directed towards the first wire.

A magnetic field exists between the plates of a capacitor: A.always B.never C.when the capacitor is fully charged D.while the capacitor is being charged E.only when the capacitor is starting to be charged

Answers

A magnetic field exists between the plates of a capacitor while the capacitor is being charged

Describe the magnetic field.

An electric charge, an electric current, and magnetic materials are all affected magnetically by a magnetic field, which is a vector field. A force perpendicular to the magnetic field and its own velocity acts on a moving charge in a magnetic field.

A magnetic field exists between the capacitor plates when electricity enters or exits the plates. Closed loops have the field direction parallel to the plates. A capacitor generates this field when it is being DC charged or discharged, or when AC current is passing through it.

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A 1-kg ball is hung at the end of a rod 1-m long. If the system balances at a point on the rod 0. 25 m from the end holding the mass, what is the mass of the rod?.

Answers

The mass of the rod must be equal to the mass of the ball, which is 1 kg.

What is mass ?

Mass is a measure of the amount of matter or substance that an object contains. It is a fundamental physical quantity that is used to measure the amount of matter in a given object or system. It is measured in kilograms (kg) or grams (g).

The equation of equilibrium of the system is:
[tex]F_{rod} = F_{ball[/tex]
where [tex]F_{rod[/tex] is the force exerted by the rod and [tex]F_{ball[/tex] is the force exerted by the ball.
The force exerted by the ball is equal to its mass times gravity, so [tex]F_{ball[/tex]= mg, where m is the mass of the ball and g is the acceleration due to gravity.
The force exerted by the rod is equal to its mass times its acceleration. Since the rod is in equilibrium, its acceleration is zero, so [tex]F_{rod[/tex] = 0.
Therefore, we can write the equation of equilibrium as:
0 = mg
Since g is a constant, we can divide both sides by g to get:
0 = m
Since m is the mass of the ball, this equation tells us that the mass of the ball is zero. Therefore, the mass of the rod must be equal to the mass of the ball, which is 1 kg.

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a wire of radius 6 mm and length 400 m is melted into a sphere calculate the radius of the sphere in centimetres​

Answers

Answer:

22.6 cm

Explanation:

The volume of the wire is equal to the volume of the sphere. The volume of a cylinder (the wire) is given by the formula V = πr^2h, where r is the radius and h is the height (length). The volume of a sphere is given by the formula V = 4/3πR^3, where R is the radius of the sphere.

Let’s first convert the radius of the wire from millimeters to meters:

6 mm = 0.006 m.

The volume of the wire is then V = π(0.006 m)^2(400 m) = 0.04524 m^3.

Now we can solve for the radius R of the sphere:
0.04524 m^3 = 4/3πR^3.
Solving for R gives
R = (0.04524 m^3 / (4/3π))^(1/3) ≈ 0.226 m.

Finally, let’s convert the radius from meters to centimeters:
0.226 m = 22.6 cm.

So, the radius of the sphere is approximately 22.6 cm.

light of wavelength 300.0 nm passes through a 0.31-mm wide slit and forms a diffraction pattern on a screen 3.3 m away from the slit. calculate the distance between the first and the third minima on the same side of the central maximum.

Answers

The distance between the first and third minima on the same side of the central maximum is 0.024384 m.

What is distance?

Distance is a numerical measurement of how far apart two objects or points are in space. It is usually measured in linear units such as kilometers, meters, miles, feet, and inches. Distance can also be measured in non-linear units, such as the length of time it takes to get from one point to another.


Angular width of central maximum = λ/(b × d)
Where λ is the wavelength of the light, b is the width of the slit, and d is the distance from the slit to the screen.
In this case, λ = 300.0 nm, b = 0.31 mm, and d = 3.3 m. Plugging these values into the equation gives us:
Angular width of central maximum = 300.0 nm/(0.31 mm × 3.3 m)
= 0.001863 radians
The distance between the first and third minima is equal to the width of the central maximum, which in this case is equal to 2 × 0.001863 radians = 0.003726 radians. To convert this to a distance, we can use the equation:
Distance between first and third minima = d × (2 × 0.003726 radians)
Where d is the distance from the slit to the screen. In this case, d = 3.3 m, so:
Distance between first and third minima = 3.3 m × (2 × 0.003726 radians)
= 0.024384 m
Therefore, the distance between the first and third minima on the same side of the central maximum is 0.024384 m.

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The distance between the first and the third minima on the same side of the central maximum is about 2.02 mm.

How to solve for the distance

mλ = wsin(θ)

y = Ltan(θ) ≈ Lsin(θ)

y = mLλ/w

Δy = y3 - y1

  = (3Lλ/w) - (1Lλ/w)

  = 2Lλ/w

λ = 300.0 nm = 300.0 × 10^-9 m

w = 0.31 mm = 0.31 × 10^-3 m

L = 3.3 m

Δy = 2 * 3.3m * 300.0 × 10^-9 m / (0.31 × 10^-3 m)

  = 2.02 mm

So, the distance between the first and the third minima on the same side of the central maximum is about 2.02 mm.

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a 112 cm long pipe is closed at one end. what is the fundamental frequency of the pipe? the speed of sound in air is 340 m/s.

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The fundamental frequency of the closed pipe is 76.34 Hz. The fundamental frequency of a pipe depends on its length and the speed of sound.

In this case, the length of the pipe is given as 112 cm or 1.12 m, and the speed of sound in air is 340 m/s. The formula for calculating the fundamental frequency of a closed pipe is f = (nv)/(4L), where f is the frequency, n is the harmonic number (1 for the fundamental frequency), v is the speed of sound, and L is the length of the pipe.

Substituting the given values, we get:
f = (1 x 340)/(4 x 1.12) = 76.34 Hz

Therefore, the fundamental frequency of the closed pipe is 76.34 Hz. This means that the pipe will produce a sound with a pitch of 76.34 Hz when it is excited at its fundamental frequency.

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i'm running a skar rp4500 amp with 2 agm batteries and a 120 amp alternator. how can i increase my amperage for cheap

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To increase your amperage for your car audio system,  you can try: Upgrade your alternator, Add a second battery, Upgrade your wiring.

Upgrade your alternator: A higher-output alternator can supply more amperage to your car's electrical system. You can look for a higher-output alternator that is compatible with your car and install it yourself or have a professional install it for you.

Add a second battery: Adding a second battery to your car's electrical system can increase your available amperage, especially if you use a battery isolator to prevent the second battery from draining the primary battery. Make sure the batteries are compatible and have the same voltage rating.

Upgrade your wiring: Upgrading your wiring to a larger gauge can reduce voltage drop and allow more current to flow through your system. Make sure to use wiring that is appropriate for the amount of current you are drawing.

Use a capacitor: Adding a capacitor can help reduce voltage drops in your system by temporarily storing electrical charge and releasing it as needed. However, capacitors are not a replacement for a properly sized power supply, so make sure to use a capacitor that is appropriate for your system's needs.

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a large parallel-plate capacitor is being charged and the magnitude of the electric field between the plates of the capacitor is increasing at the rate d e dt . what is correct about the magnetic field b in the region between the plates of the charging capacitor?

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When a large parallel-plate capacitor is being charged, the electric field between the plates increases at a rate of (dE/dt).

According to Maxwell's equations, particularly the Ampere-Maxwell law, a changing electric field generates a magnetic field (B) in the region between the plates.

For the charging capacitor, the magnetic field (B) will form closed loops around the edges of the plates.

The direction of the magnetic field can be determined using the right-hand rule, with your thumb pointing in the direction of the increasing electric field (from the positive plate to the negative plate), and your curled fingers indicating the direction of the magnetic field.

In summary, during the charging process of a parallel-plate capacitor, the increasing electric field (dE/dt) will induce a magnetic field (B) between the plates.

The magnetic field will form closed loops around the edges of the plates, with the direction determined by the right-hand rule.

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If you see Alice going to your left at exactly 0.99c and Bob going to your right at exactly 0.99, Alice will say that Bob is
a) going away from her at 1.98c
b) going away from her at exactly 0.99c
c) going away from her at exactly c
d) going away from her at about 0.98
e) going away from her faster than 0.99c, but slower than c

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If you see Alice going to your left at exactly 0.99c and Bob going to your right at exactly 0.99, Alice will say that Bob is b) going away from her at exactly 0.99c.

According to special relativity, the laws of physics are the same for all observers in uniform motion relative to one another. This means that both Alice and Bob can consider themselves at rest and the other moving at a speed of 0.99c.

From Alice's point of view, Bob is moving away from her at a speed of 0.99c. This is because she sees Bob's velocity as the difference between his velocity relative to her and the speed of light, which is always constant. Therefore, Alice will say that Bob is going away from her at exactly 0.99c.

On the other hand, from Bob's point of view, Alice is also moving away from him at a speed of 0.99c. However, since the speed of light is constant for both observers, Bob will not see Alice moving away from him at a speed greater than 0.99c. This is because if Alice were to move away from him at a speed faster than this, she would be breaking the laws of physics as we currently understand them.

In summary, Alice will say that Bob is going away from her at exactly 0.99c, but Bob will not see Alice moving away from him at a speed faster than 0.99c. The correct option is b) going away from her at exactly 0.99c.

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To practice Problem-Solving Strategy 30.1: Inductors in Circuits. A circuit has a 5 V battery connected in series with a switch. When the switch is closed, the battery powers two paths in parallel, one of which has a resistor of resistance R1 = 85 Ω in series with an inductor of inductance L = 1.1Ã10â2 H , while the other has a resistor of resistance R2 = 270 Ω . What is the current supplied by the battery at a time t = 0.3 ms after the switch is closed?
What is the current i1 supplied by the battery a time t = 0.3 ms after the switch is closed?

Answers

The current supplied by the battery at a time t = 0.3 ms after the switch is closed is i1 = 0.0058 A.

What is current?

Current is the flow of electric charge through a conductor. It is measured in amperes, which is a unit of electric current equal to one coulomb of charge passing a point in one second.

The current supplied by the battery at a time t = 0.3 ms after the switch is closed can be calculated using the equation i1 = V/R1 + (L/R1)×(di1/dt).

Since the battery is supplying a constant voltage of 5V and the initial current is 0, V = 5V and i1 = 0.

Plugging these values into the equation, we get i1 = 5V/(85 Ω) + (1.1Ã10â2 H / 85 Ω)×(di1/dt).

Differentiating both sides with respect to time, we get di1/dt = (5V/(85 Ω))/(1.1Ã10â2 H).

Substituting the value of di1/dt into the original equation and solving for i1, we get i1 = (5V/(85 Ω))×(1-e^(-t/(L/R1))).

Substituting the value of t = 0.3 ms and L/R1 = 1.1Ã10â2 H / 85 Ω, we get i1 = (5V/(85 Ω))×(1-e^(-0.3 ms/(1.1Ã10â2 H / 85 Ω)) = 0.0058 A.

Therefore, the current supplied by the battery at a time t = 0.3 ms after the switch is closed is i1 = 0.0058 A.

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A 110 g ball moving to the right at 4. 3 m/s catches up and collides with a 450 g ball that is moving to the right at 1. 2 m/s. If the collision is perfectly elastic, what is the speed

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A 110 g ball moving to the right at 4.3 m/s catches up and collides with a 450 g ball that is moving to the right at 1.2 m/s. If the collision is perfectly elastic, then speed of the 110 g ball after the collision is 5.55 m/s to the right.

In an elastic collision, both momentum and kinetic energy are conserved.

Let's define the positive direction to be to the right.

Before the collision, the momentum of the system is

p = m1v1 + m2v2

p = (0.11 kg)(4.3 m/s) + (0.45 kg)(1.2 m/s)

p = 0.473 kg⋅m/s

After the collision, the momentum of the system is still to the right, and is given by

p' = m1v1' + m2v2'

Where v1' and v2' are the final velocities of the two balls.

Since the collision is elastic, kinetic energy is conserved as well, so we can write

(1/2)m1[tex]v1^{2}[/tex] + (1/2)m2[tex]v2^{2}[/tex] = (1/2)m1[tex]v1'^{2}[/tex] + (1/2)m2[tex]v2'^{2}[/tex]

Substituting the given masses and initial velocities, we get and Solving for v1', we get

v1' = 5.55 m/s

Therefore, the speed of the 110 g ball after the collision is 5.55 m/s to the right.

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at 2:10 pm it reads 50 mi/h. show that at some time between 2:00 and 2:10 the acceleration is exactly 120 mi/h2.

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The acceleration is exactly 120 mi/h² at 12.5 seconds past 2:00 pm.

What is acceleration?

Acceleration is the rate at which an object's velocity changes over time. It is a vector quantity, meaning it has both a magnitude and a direction. Acceleration is the rate of change of velocity, or the rate at which an object's speed or velocity changes over time. It can be calculated by dividing the change in velocity by the change in time.

In this case, we have v₂ = 50 mi/h, v1 = 0 mi/h, x = 10 min and we need to find a. We can rearrange the equation to solve for a: a = (v₂ - v₁ / (2x)
Plugging in the values from the problem, we get a = (50 - 0) / (2*10) = 25 mi/h².
Now, to find the exact time at which the acceleration is 120 mi/h2, we need to use the equation for velocity again. This time, we know v₂ = 50 mi/h, a = 120 mi/h² and x = some time t between 2:00 and 2:10. We can rearrange the equation to solve for t: t = (v₂ - v₁) / (2a)
Plugging in the values from the problem, we get t = (50 - 0) / (2*120) = 0.2083333... minutes. This is approximately 12.5 seconds.
Therefore, the acceleration is exactly 120 mi/h² at 12.5 seconds past 2:00 pm.

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What are the three lightest isotopes whose proton and neutron energy levels are both filled, and filled equally?.

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Three of the lightest isotopes with both proton and neutron energy levels filled equally are helium-4, beryllium-8, and Oxygen-16.

Proton and neutron energy levels are filled equally when the nucleus contains an equal number of protons and neutrons, which results in greater nuclear stability.

Helium-4, which is one of the most stable isotopes of helium, has 2 protons and 2 neutrons, both filled equally.

Beryllium-8 has 4 protons and 4 neutrons, which makes the energy levels equally filled, making a stable nucleus.

Oxygen-16 contains eight protons and neutrons, which satisfy the condition for an equally filled and stable nucleus.

The concept of an equally filled nucleus in nuclear physics explains the stability of the isotopes when both protons and neutrons are filled equally. Examples of light isotopes with the above-mentioned characteristics and a stable electronic configuration are helium-4, Beryllium-8, and Oxygen-16.

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If you must do positive work to bring a charged balloon toward a negatively charged sphere, is the charge on the balloon positive or negative?.

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In order to answer your question, we need to understand the concept of electric potential energy. When a charged object is brought closer to another charged object, the electric potential energy of the system changes. If positive work is required to bring the charged balloon toward the negatively charged sphere, it means that the electric potential energy of the system is increasing.

The electric potential energy of a charged object depends on both the charge and the distance between the objects. If the charged balloon has a negative charge, it would be attracted to the negatively charged sphere, and would not require any positive work to bring it closer. Therefore, we can conclude that the charge on the balloon must be positive.

If you must do positive work to bring a charged balloon toward a negatively charged sphere, the charge on the balloon is positive. This is because positive work indicates that you are working against an attractive force between the objects, which occurs when both objects have opposite charges (positive balloon and negative sphere).

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Suppose that you have a mass of 70 kg (equivalent to a 154-pound person). How much mass must another object have in order for your body and the other object to attract each other with a force of 1-Newton when separated by 10 meters? (Circular Motion and Satellite Motion - Lesson 3 - Universal Gravitation: Cavendish and the Value of G)

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214*10^8kg mass must another object have in order for your body and the other object to attract each other with a force of 1-Newton when separated by 10 meters

What is universal gravitational law?

According to Newton, the force of gravity operating between the earth and any other thing is inversely proportional to the square of the distance between the centers of the earth and the object, directly proportional to the mass of the object, and directly proportional to the mass of the earth.

m = 2.14 x 10^10 kg

Use the equation Fgrav = G • m1 • m2 / r^2

where m1 = 70 kg,

r = 10 m and

G = 6.673 x 10-11 N•m2/kg2.

F =  1N

1 =  6.673 x 10-11 * 70 *m2/10*10

m 2 will be 100/6.673 x 10-11 *70 i.e. 214*10^8kg

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A copper ring is attached to a string and allowed to swing as a pendulum between two permanent magnets as shown. The north pole of one magnet faces the south pole of the other magnet. If the magnetic field is directed from the front pole to the back pole, what is the direction of the induced current, if any, as the ring enters the space between the magnetic poles?.

Answers

Therefore, the direction of the induced current will be clockwise as viewed from above.

Based on Faraday's Law of electromagnetic induction, an induced current will be generated in the copper ring as it enters the space between the magnetic poles. The direction of the induced current can be determined using Lenz's Law, which states that the direction of the induced current will be such that it opposes the change in magnetic flux that produced it.

As the copper ring enters the magnetic field, the magnetic flux passing through the ring increases. To oppose this increase in magnetic flux, an induced current will flow in the copper ring in a direction such that it produces a magnetic field that opposes the magnetic field of the permanent magnets. This means that the induced current will flow in a direction that creates a north pole at the front of the copper ring and a south pole at the back of the copper ring.

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