Answer:
23.55 L
Explanation:
USe the following 'identity' of gs laws
P1 V 1 / T1 = P2 V2 / T2 ( T must be in Kelvin)
re arrange to
P1 V 1 T2 / (T1 P2) = V2 NOW SUB IN THE VALUES
752 * 34.2 * ( 34 + 273.15) / [( 229 + 273.15) * 668] = V2 = 23.55 L
1. Calculate the average atomic mass of rubidium. Rubidium has two isotopes, 85Rb and 87Rb. 85Rb has an atomic mass of 84.912 amu and occurs at an abundance of 72.17%. 87Rb has an atomic mass of 86.909 amu and occurs at an abundance of 27.83%. Show your work
What is the oxidation state of oxygen (O) in the reactant O2(g)?
Answer:0
Explanation:
Since oxygen gas i.e., diatomic oxygen exists in the atmosphere in the free state, hence the oxidation state of each atom will be 0
Given the reaction:
Fe3+(yellow) + SCN-(colorless) <--> [FeSCN]2+(dark red)
If Fe3+ is added to the solution:
Group of answer choices
A. No changes in color occur
B. The solution turns darker red
C. The solution becomes colorless
D. The solution becomes more yellow
Fe3+(yellow) + SCN-(colorless) <--> [FeSCN]2+(dark red)
If Fe3+ is added to the solution the solution turns darker red
While precipitating out Fe3+ (as Fe(OH)3) or SCN- (as AgSCN) will push the equilibrium to the left, consuming the complex and reducing color intensity, the addition of Fe3+ or SCN- will push the equilibrium to the right, creating more complex and intensifying the color.
The pace of reaction rises as Fe3+ levels rise. The concentration of SCN reduces as the rate rises.
The FeSCN2+ complex, which is created when iron(III) and thiocyanate ions react, displays an extremely strong blood red color (or orange in diluted solution), making it simple to detect and quantify using spectrophotometry.
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The reaction of charcoal (carbon) and oxygen is sped up by grinding the charcoal into a fine powder. This is an example of:
Group of answer choices
A. All of the above
B. Increasing concentration to increase reaction rate
C. Increasing temperature to increase reaction rate
D. increasing surface area to increase reaction rate
Answer:
D
Explanation:
Grinding to a powder increases the surface area of the charcoal .
The reaction of charcoal (carbon) and oxygen is sped up by grinding the charcoal into a fine powder. This is an example of increasing surface area to increase reaction rate. Option D is the answer.
Reason for the grindingGrinding charcoal into a fine powder enhances its reactivity by increasing surface area. This finer texture promotes more frequent collisions between charcoal particles and oxygen molecules, facilitating faster chemical reactions.
The heightened contact points enable efficient utilization of reactants, optimizing resource consumption. Shorter diffusion paths within smaller particles expedite reactant diffusion, aiding quicker reaction rates.
Additionally, the augmented surface area promotes efficient heat transfer, crucial in reactions involving temperature changes.
Grinding charcoal amplifies the reaction rate by maximizing interaction opportunities, accelerating the conversion of charcoal and oxygen into products.
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help! awarding 20 points
a. The circulatory system in fish is one-directional while it is two-directional in humans.
b. P has a high concentration of carbon dioxide and low oxygen concentration whereas Q has high oxygen concentration and low carbon dioxide concentration.
What is the circulatory system?The circulatory system is the system of organism and tissues which help to transport blood and other fluids through the body of a living organism.
The organs of the circulatory system include:
The heartThe blood vessels - veins, arteries, capillariesa. In the given diagram sowing the circulatory system of man and the fish, it can be seen that the direction of blood flow in the fish is one way through the heart. However, in humans, the direction of blood flow is two-way through the heart.
b. The gas in P has a high concentration of carbon dioxide and low oxygen concentration. However, the gas flowing through Q has high oxygen concentration and low carbon dioxide concentration.
In conclusion, the circulatory system is important in the exchange of gases in the body.
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How many moles of HNO3 will be produced
from the reaction of 46.5 g of NO2 with excess
water in the following chemical reaction?
3 NO₂(g) + H₂O (1)→ 2 HNO3(g) + NO(g)
Answer:
0.674 moles HNO₃
Explanation:
To find the moles of HNO₃, you need to (1) convert grams NO₂ to moles NO₂ (via molar mass) and then (2) convert moles NO₂ to moles HNO₃ (via mole-to-mole ratio from equation coefficients). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value (46.5 g).
Molar Mass (NO₂): 14.007 g/mol + 2(15.998 g/mol)
Molar Mass (NO₂): 46.003 g/mol
3 NO₂(g) + H₂O (l) ------> 2 HNO₃(g) + NO(g)
46.5 g NO₂ 1 mole 2 moles HNO₃
------------------- x ------------------- x -------------------------- = 0.674 moles HNO₃
46.003 g 3 moles NO₂
if .709 j of heat is added to water and cause the temperature to go up by .036 degrees C what mass of water is present
Answer:
0.00471 grams H₂O
Explanation:
To determine the mass, you need to use the following equation:
Q = mcΔT
In this equation,
-----> Q = energy/heat (J)
-----> m = mass (g)
-----> c = specific heat capacity (J/g°C)
-----> ΔT = temperature change (°C)
The specific heat capacity of water is 4182 J/g°C. You can plug the given values into the equation and simplify to isolate "c".
Q = 0.709 J c = 4182 J/g°C
m = ? g ΔT = 0.036 °C
Q = mcΔT <----- Equation
0.709 J = m(4182 J/g°C)(0.036 °C) <----- Insert values
0.709 J = m(150.552) <----- Multiply 4182 and 0.036
0.00471 = m <----- Divide both sides by 150.552
Which of the following is NOT an example of a colligative property?
Group of answer choices
A. Salt is added to ice to make homemade ice cream.
B. Salt is added to roads before a snow storm.
C. Antifreeze is added to a radiator of a car.
D. Salt water dehydrates someone that drinks it.
D. The option that is NOT an example of a colligative property is salt water dehydrates someone that drinks it.
What is colligative property?
Colligative properties are the physical changes that result from adding solute to a solvent.
Colligative Properties depend on how many solute particles are present as well as the solvent amount, but they do NOT depend on the type of solute particles, although do depend on the type of solvent.
One important thing to note is that colligative property is going to change the melting point or the boiling point of a substance.
Thus, the option that is NOT an example of a colligative property is salt water dehydrates someone that drinks it.
The correct option is D.
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Can anyone please give me name of these disaccharides? My professor wrote these on whiteboard and didn't explain anything.
The name of the disaccharide above is sucrose
What are disaccharides?Disaccharides are substances which are composed of two molecules of simple sugars or monosaccharides linked to each other.
Below are some examples of disaccharides:
SucroseMaltoseLactoseCellobioseSo therefore, the name of the disaccharide above is sucrose
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To answer this question, you may need access to the periodic table of elements.
How many bonding electrons are in the Lewis structure of NH₃?
a.) 6
b.) 2
c.) 5
d.) 4
Answer:
6 bonding electrons are needed.
the quantity PV/T must be held constant and both P and V are doubled, the value of T will necessarily have to,
Determine the concentration of a solution (M) made by dissolving 18.8 g of sodium chloride (NaCl) in 750.0 mL of solution.
Answer:
0.429 M
Explanation:
To find the molarity, you need to (1) convert grams to moles (using the molar mass), then (2) convert mL to L, and then (3) calculate the molarity (using the molarity ratio).
(Step 1)
Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol
Molar Mass (NaCl): 58.443 g/mol
18.8 grams NaCl 1 mole
-------------------------- x ------------------------ = 0.322 moles NaCl
58.443 grams
(Step 2)
1,000 mL = L
750.0 mL 1 L
------------------ x ----------------- = 0.7500 L
1,000 mL
(Step 3)
Molarity (M) = moles / volume (L)
Molarity = 0.332 moles / 0.7500 L
Molarity = 0.429 M
Predict and Balance the following reaction:
Na + H2O →
Group of answer choices
A. 2Na + 2H2O → 2NaOH + H2
B. No Reaction Occurs
C. Na + H2O → NaOH2
D. 2Na + H2O → Na2O + H2
A. The balanced chemical reaction of Sodium metal and Water is 2Na + 2H₂O → 2NaOH + H₂.
What is a balanced chemical equation?A balanced equation contains the same number of each type of atoms on both the left and right sides of the reaction arrow.
Reaction of Sodium metal and WaterSodium metal reacts rapidly with water to form a colourless solution of sodium hydroxide (NaOH) and hydrogen gas (H2).
The balanced chemical reaction is written below;
2Na + 2H₂O → 2NaOH + H₂
Thus, the balanced chemical reaction of Sodium metal and Water is 2Na + 2H₂O → 2NaOH + H₂.
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Which of the following elements has the highest electronegativity?
Group of answer choices
A. Boron
B. Nitrogen
C. Oxygen
D. Carbon
Answer:
The answer is Oxygen
The oxygen has the most electronegativity.
H2O Is water. H10O5 Is Monohydrate trihydrate. What Is the chemical compound name for H50O25?
Answer:
THERE IS NO such compound
Explanation:
Burning 2.00 mol of hydrogen releases 483.6 kJ of energy. Determine how much energy, in kilojoules, must be supplied to convert 3.00 mol of water vapor into hydrogen gas and oxygen gas.
Express your answer with the appropriate units.
The amount of heat energy (in KJ) needed to convert 3 moles of water vapor into hydrogen gas and oxygen gas is 1450.8 KJ
Balanced equationWe'll begin by writing the balanced equation. This is illustrated below:
2H₂ + O₂ --> 2H₂O ΔH = 483.6 KJ
From the balanced equation above,
2 moles of water (H₂O) required 483.6 KJ to produce hydrogen gas and oxygen gas
How to determine the heat energy needed to convert 3 moles of water to hydrogen gas and oxygen gasThe heat energy needed to convert 3 moles of water can be obtained as illustrated below:
From the balanced equation above,
2 moles of water (H₂O) required 483.6 KJ to produce hydrogen gas and oxygen gas
Therefore,
3 moles of water (H₂O) will require = 3 × 483.6 = 1450.8 KJ to produce hydrogen gas and oxygen gas
Thus, we can conclude that the energy needed to convert 3 moles of water is 1450.8 KJ
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Mercury-197 has a half-life of 3 days. Starting
with 300 grams, how much remains in 3
weeks? (Round to two places)
Answer:
2.34 gms left
Explanation:
3 weeks = 21 days = 7 half lives
300 * (1/2)^7 = 2.34 gms
Classify H3PO4 as a strong acid or a weak acid.
Answer:
H3PO4 (phosphoric acid) is weak acid
Explanation:
This is because weak acid is an acid that ionizes only slightly in an aqueous solution.
A student investigated the enthalpy of combustion (deltaHc) of methanol under standard conditions using the apparatus shown in the diagram. The measurements the student recorded are shown in the table. Use this information to answer the questions below.
_Clamp stand
_
_ _I__Thermometer
_ I I Beaker
_ I-----I
_ I___I Water
_ I Wick
_ -----
_ I I
_ ----- Alcohol
_ I __I
______________
Alcohol mass before burning: 80.6g
Alcohol mass after burning: 75.9g
Water heated: 100g
Methanol Mr: 32
Initial temperature of water: 21.5 C
Final temperature of water: 32.4 C
Enthalpy of combustion of 1 mole of methanol:
The student wanted to know if the value obtained in part 1 is similar to that calculated using average bond enthalpy data.
a) Using the balanced equation and the data in the table below, calculate the theoretical enthalpy of combustion.
Note: you will need to include the enthalpy of vaporisation for the liquid components which are also given.
CH3OH(l) + 1.5O2(g) → CO2(g) + 2H2O(l)
Average Bond Enthalpies KJmol-1
C-H 412
C-C 348
C-O 358
O=O 496
C=O 743
O-H 463
Enthalpy of vaporisation KJmol-1
Methanol 35
Water 41
b) Suggest some reasons as to why this value is different to the one obtained in the practical. (What are the reasons that the the theoretical and actual enthalpy changes are different)
The Molar enthalpy of combustion of methanol obtained from the practical is -31.02 kJ/mol.
The molar enthalpy of combustion from bond energies, ΔH is -543 kJ/mol
The differences in the values could be due to:
Heat losses from the calorimeter to the surroundingsInaccurate measurements of mass and temperature changesWhat is the enthalpy theoretical and actual enthalpy of combustion of methanol?The actual enthalpy of combustion of methanol is calculated from the data obtained from the laboratory work.
The enthalpy of combustion is equal to the heat energy given off from the combustion of methanol.
Quantity of heat gained by water , q = -mcθ
where:
m = massc = specific heat capacityθ = temperature changemass of water heated = 100 g
specific heat capacity of water = 4.18 J/g/°C
temperature change = 32.4°C - 21.5°C = 10.9°C
q = -(100 * 4.18 * 10.9) J
q = - 4556.2 J
moles of methanol reacted = mass/molar mass
mass of methanol = 80.6 - 75.9 = 4.7 g
molar mass of methanol = 32 g/mol
moles of methanol = 4.7/32 = 0.14687 moles
Molar enthalpy of combustion of methanol = -4556.2 J/0.14687 mole
Molar enthalpy of combustion of methanol = -31.02 kJ/mol
Calculating molar enthalpy of combustion from bond energies:
ΔH = sum of the bond energies of bonds broken - sum of the bond energies of the bonds formedSum of bond energies of bonds broken = (3 * 412) + 358 + 463 + (1.5 * 496) + 35 = 2836 kJ/mol
Sum of bond energies of bonds formed = (2 * 743) + 2(2 * 463) + 41 = 3379 kJ/mol
ΔH = 2836 kJ/mol - 3379 kJ/mol
ΔH = -543 kJ/mol
The value obtained from the practical is less than that from the bond energies
b. The possible reasons for the difference in value obtained from the practical is less than that from the bond energies include:
Heat losses from the calorimeter to the surroundingsInaccurate measurements of mass and temperature changes.In conclusion, the molar enthalpy of combustion of methanol is negative since heat is given off during the reaction.
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Which of these have the highest volume
A. - 1kg of lead
B. - 1kg of iron
C. - 1kg of gold
D. - 1kg of aluminum
Answer:
D. 1kg Aluminium
Explanation:
First of all, you have to know that you were given two quantities, volume and mass.
The relationship between both quantities is given by the formula of density which is:
Density = Mass / Volume
Volume = Mass / Density
Since mass is constant, it means that the volume is inversely proportional to the density.
Volume = k / Density where k is a constant.
This means that the substance with the lowest density would have the highest volume and the one with the highest density would have the highest lowest.
The density of the substances are given as:
Lead = 11.2
Iron = 7.874
Gold = 19.3
Aluminium = 2.7
This means that Aluminium would have the highest volume as its the least dense.
is Sn^2+ + Br2 ---> Sn^4+ + 2Br^- a spontaneous or non-spontaneous redox reaction?
Sn^2+ + Br2 ---> Sn^4+ + 2Br^- is referred to as a non-spontaneous redox reaction.
What is a Non spontaneous reaction?This type of reaction doesn't favor the formation of the product and must be endothermic.
In the reaction above under the given conditions, ΔG is positive and it is intended to form Sn(s) and Br(l) through the reduction of tin cation to make bromine liquid and tin solid. This therefore points to the direction of the reaction being non-spontaneous one.
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Which of the following chemical equations depicts a balanced chemical reaction?
A. 2H₂ +202-> H₂O
B. 2H₂ +202-> 2H₂O
C. H₂ + O2-> H₂O
D. 2H₂ + O₂-> 2H₂O
Answer:
D.) 2 H₂ + O₂ -----> 2 H₂O
Explanation:
An equation is balanced when there is an equal amount of each element on both sides of the reaction. If these amounts are unequal, coefficients can be added to modify the amount of particular molecules.
A.) Not balanced
2 H₂ + 2 O₂ -----> H₂O
Reactants: 4 hydrogen, 4 oxygen
Products: 2 hydrogen, 1 oxygen
B.) Not balanced
2 H₂ + 2 O₂ -----> 2 H₂O
Reactants: 4 hydrogen, 4 oxygen
Products: 4 hydrogen, 2 oxygen
C.) Not balanced
H₂ + O₂ -----> H₂O
Reactants: 2 hydrogen, 2 oxygen
Products: 2 hydrogen, 1 oxygen
D.) Balanced
2 H₂ + O₂ -----> 2 H₂O
Reactants: 4 hydrogen, 2 oxygen
Products: 4 hydrogen, 2 oxygen
A tire has a pressure of 1.8 atm at 20 degrees Celsius. At the end of a long trip, the tire pressure increased to 2.0 atm. What was the temperature of the air inside the tire (in degrees Celsius)?
Answer:
52.57 Celsius
Explanation:
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Gay-Lussac's law
P1/T1 = P2/T2
pressure 1 / temperature1 = pressure2 / temperature2
temperature has to be in kelvin
20 degrees Celsius is 293.15
1.8 / 293.15 = 2.0 / temperature2
1.8 / 293.15 = 2.0 / x
293.15 * 2.0 = 586.3
586.3 divided by 1.8 =
325.722222222 kelvin which is
52.57222222200005 Celsius
chemlibretextsorg
Determine which substance in the following pair has the greater tendency to be oxidized.
Li or K
Potassium (K) has the greater tendency to be oxidized when compared to Lithium (Li).
What is oxidation?Oxidation is a chemical process triggered by the reaction between an compound and an oxidizing agent. The agent is what gains electrons and undergoes reduction, causing what is called oxidation.
With that being said, as you go down the alkali metal group, the ionisation energy decreases. The tendency of an atom to give its electron (or get oxidised) increases. Therefore, potassium oxidises more easily than lithium or in other words, potassium has a lesser tendency to get reduced compared to lithium.
As lithium has a higher tendency to get reduced than potassium, lithium gets deposited instead of potassium.
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What is the element that is located in the 2nd Period and a Halogen?
Group of answer choices
A. Oxygen
B. Nitrogen
C. Flourine
D. Chlorine
Answer:
C.) Fluorine
Explanation:
A period describes a row on the periodic table.
Halogens are located in the 17th column on the periodic table.
As such, the element located in the second row in the 17th column is fluorine.
Given the following reaction: 2 NO(g) + O2(g) <--> 2 NO2(g), what is the equilibrium constant (K), if the concentrations at equilibrium are [NO] = 0.0542 M, [O2] = 0.127 M, and [NO2] = 15.5 M?
Group of answer choices
A. K = 2.35 x 102
B. K = 2.54 x 10-1
C. K = 6.44 x 105
D. K = 3.4 x 103
The equilibrium constant of a reaction, [tex]K_{c}[/tex] = 6.44 * 10⁵; option C.
What is equilibrium constant of a reaction?Equilibrium constant, [tex]K_{c}[/tex] of a reaction is a measure of the ratio of the equilibrium concentration of the products of a reaction, to the equilibrium concentration of the reactants; with each concentration raised to the exponent corresponding to the coefficient in the balanced equation of the reaction.
[tex]K_{c} = \frac{(products)^{a}}{(reactants)^{b}}[/tex]
The balanced equation of the given reaction is as follows:
2 NO (g) + O₂ (g) ⇄ 2 NO₂ (g)The concentrations at equilibrium of the species are as follows:
[NO] = 0.0542 M,
[O₂] = 0.127 M, and
[NO₂] = 15.5 M
Equilibrium constant, [tex]K_{c}[/tex] = (15.5)²/(0.127) * (0.0542)²
[tex]K_{c}[/tex] = 6.44 * 10⁵
In conclusion, the equilibrium constant of a reaction, tells on in which direction, the reaction is favored at equilibrium.
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Consider the following reaction at 298K.
I2 (s) + 2 Cr2+ (aq) 2 I- (aq) + 2 Cr3+ (aq)
Which of the following statements are correct?
Choose all that apply.
n = 4 mol electrons
Eo cell < 0
delta G^o < 0
The reaction is reactant-favored.
K > 1
The true statements are;
ΔG < 0K > 1What are the correct statements?Now we can see that the reaction here is a redox reaction. Thus;
Eocell = cell potential = 0.54 - (-0.41) = 0.95 V
K = equilibrium constant = ?
n = number of moles of electrons = 2
ΔG = change in free energy = ?
Hence;
Eocell = 0.0592/n log K
0.95 = 0.0592/2 log K
K = 0.95 * 2/0.0592
K = 1.2 * 10^32
Now
ΔG = -nFEcell
ΔG = - (2 * 96500 * 0.95)
ΔG = -183.3kJ
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Line p has an equation of y= – 8x+6. Line q, which is perpendicular to line p, includes the point (2, – 2). What is the equation of line q?
The equation of line q is determined as y = ¹/₈x - ⁹/₄.
What is slope?The slope of a line is the change in y axis to change in x axis.
Slope of line Py = – 8x + 6
from general line equation, y = mx + c
where;
m is slopem = - 8
Slope of line qm₂ = -1/m
m₂ = -1/-8
m₂ = 1/8
Equation of line q(y - y₁) / (x - x₁) = m₂
(y + 2)/(x - 2) = 1/8
y + 2 = ¹/₈(x - 2)
y + 2 = ¹/₈x - ¹/₄
y = ¹/₈x - ⁹/₄
Thus, the equation of line q is determined as y = ¹/₈x - ⁹/₄.
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The amount of heat transferred from an object depends on
Group of answer choices
A. The initial temperature of the object
B. All of the above
C. The specific heat of the object
D. The mass of the object
The amount of heat transferred from an object depends on the following;
The initial temperature of the object
The specific heat of the object
The mass of the object
Therefore, the answer is all of the above (option B).
What is heat?
Heat is the internal energy of a system in thermodynamic equilibrium due to its temperature.
The amount of heat absorbed or released by an object can be calculated using the following expression:
Q = m × c × ∆T
Where;
Q = quantity of heat
m = mass of object
c = specific heat capacity of object
∆T = change in temperature
Therefore, this suggests that amount of heat transferred from an object depends on the following;
The initial temperature of the object
The specific heat of the object
The mass of the object
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find the solubility of agcl in a 0.1M solution of cucl2.
ksp = 1.8x10^-10
The solubility of AgCl is 18 × [tex]10^-^1^0[/tex] in a 0.1M solution of CuCl₂.
The amount of a substance that can dissolve completely in a solvent at a specific temperature is known as its solubility. A saturated solution is one such example.
The maximum number of moles per liter of solution can be dissolved before the solution becomes saturated.
The equilibrium in the saturated solution will be as :
[tex]AgCl[/tex] ⇄ [tex]Ag ^+ + Cl ^-[/tex]
[tex]a[/tex] [tex]a[/tex] [tex]a[/tex]
[tex]CuCl_2[/tex] ⇄ [tex]Cu^2^+ + Cl^-[/tex]
[tex]0.1[/tex] [tex]0.1[/tex] [tex]0.1[/tex]
Ksp = [tex]1.8[/tex] × [tex]10^ -^1^0[/tex]
The solubility product constant: Ksp is the equilibrium constant for the dissolving of an ionic compound in water. Ksp is a function of temperature.
[tex]ksp AgCl = [ Ag ^+ ] [ Cl^-]\\[/tex]
[tex]= a[/tex]×[tex][ a + 0.1][/tex]
[tex]= a^2 + 0.1a[/tex]
[tex]a^2[/tex] is very small, so it is neglected.
ksp AgCl = 0.1a
[tex]1.8[/tex] × [tex]10^ -^1^0[/tex] = 0.1a
a = 18 × [tex]10^-^1^0[/tex]
Therefore, the solubility of AgCl is 18 × [tex]10^-^1^0[/tex].
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