A 3D electron microscope magnifies objects 1 000 000 times. A water molecule has a diameter of
[tex]2 \times {10}^{ - 10} [/tex]
m.

How large will it appear in the microscope?
give your answer in milimetres.






​

Answer:

1. BD bisects <CBE, AE || BD (Given)

2. <EBD ~= <CBD (Definition of < Bisectors)

3. <AEB ~= <EBD (Alternate Interior Angles Theorem)

4. <CAE ~= <CBD (Corresponding Angles Postulate)

5. <CAE ~= <AEB (Transitive Property of Congruence)

6. AB ~= BE (Converse of Isosceles Triangles Theorem)

A variable that takes on the values of 0 or 1 and is used to incorporate the effect of categorical variables in a regression model is called the dummy variable.

We know that,

A dummy variable is a binary variable that takes a value of 0 or 1.

In regression analysis, a dummy variable is one that takes only the value 0 or 1 to indicate the absence or presence of some categorical effect that may be expected to shift the outcome.

The number of dummy variables we must create is equal to k - 1, where k is the number of different values that the categorical variable can take on.

It is an artificial variable created to represent an attribute with two or more distinct categories/levels.

These are being used in order to sort out data into mutually exclusive groups.

It is used typically in time series analysis, response modelling, bio-medical studies, economic forecasting and credit scoring.

Therefore, a variable that takes on the values of 0 or 1 and is used to incorporate the effect of categorical variables in a regression model is called the dummy variable.

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The solution for the given equation is -5/8. By using simple algebraic operations, the equation is solved.

A linear equation is represented by ax + b = 0. The solution for this equation is

ax + b = 0

⇒ ax = -b

⇒ x = -b/a

The given equation is

7/8 + x = 1/4

On simplifying,

x = 1/4 - 7/8

⇒ x = -5/8

Therefore, the solution of the given equation is -5/8.

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Answer:

N = 2.1

M = 4.5

Step-by-step explanation:

<p is 25 degrees.  I know this because the exterior angle of p corresponds with 155.  Since this is a straight angle, angle p must be 25 (180-155).  Now I can use the cos and the sin of 25 to find M and N

sin 25 = N/5  multiply both sides by 5 to get

5 sin 25 = N  Use your calculator put in 5 sin 25

2.1 rounded to the nearest tenth.

cos 25 = M/5  Multiply both sides by

5 cos 25 = M Use your calculator

4.5

The radius of cylinder = 6 meter

The height of cylinder = 11 meter

According to the question,

Surface area of the cylinder = 640.56 m²

Let the height of the cylinder = x meters

Let the radius of the cylinder = (x-5)meters

Formula for surface area of cylinder = 2πrh ( where 'r' is the radius of the cylinder and 'h' height of the cylinder)

640.56 = 2 (3.14) (x-5) (x)

640.56/(6.28) = x² - 5x

x² - 5x =102

x² - 5x - 102 =0

using quadratic equation, [-b±√(b² - 4ac)]/2a.

b = -5; a=1; c=102

x =[-(-5) ±√(-5)² - 4(1)(102)]/2

= [5 ± √433]/2

x = 11 and -7

since x=-7 neglect negative value, we get x=11.

The height of the cylinder is 11 meters

The radius of the cylinder is (11 - 5) = 6 meters.

Hence, The radius of cylinder = 6 meter.

The height of cylinder = 11 meter.

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Answer:

Step-by-step explanation:

The radius of cylinder = 6 meter

The height of cylinder = 11 meter

According to the question,

Surface area of the cylinder = 640.56 m²

Let the height of the cylinder = x meters

Let the radius of the cylinder = (x-5)meters

Formula for surface area of cylinder = 2πrh ( where 'r' is the radius of the cylinder and 'h' height of the cylinder)

640.56 = 2 (3.14) (x-5) (x)

640.56/(6.28) = x² - 5x

x² - 5x =102

x² - 5x - 102 =0

using quadratic equation, [-b±√(b² - 4ac)]/2a.

b = -5; a=1; c=102

x =[-(-5) ±√(-5)² - 4(1)(102)]/2

= [5 ± √433]/2

x = 11 and -7

since x=-7 neglect negative value, we get x=11.

The height of the cylinder is 11 meters

The radius of the cylinder is (11 - 5) = 6 meters.

Hence, The radius of cylinder = 6 meter.

The height of cylinder = 11 meter.

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The drop-down menu will be 3 and 2.

The complex number z = 27i.

The radius of the cube root is: [tex]r\sqrt[3]{x}[/tex]

                                                  [tex]r\sqrt[3]{27}[/tex]

                                                  [tex]r=3[/tex]

Cube roots are located in a circle with a center at the origin and a radius of 3 units.

The complex number,z=a+ib is; Θ = tan⁻¹(b/a)

The complex number z=0+27i is:

                                                     Θ = tan⁻¹(27/0)

                                                     Θ = π/2

Cube roots have more than 3 arguments that differ by 2 π.

Therefore, The drop-down menu will be 3 and 2.

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The cube roots exist found on a circle with a center at the origin and a radius of 3. The cube roots contain arguments that vary by 2π over 3.

A complex number is one that has both a real and an imaginary component, both of which are preceded by the letter I which stands for the square root of -1.

The given complex number as;

z = 27i

The radius of the cube root is found as;

r = ∛x

substituting the values in the above equation, we get

r = ∛27

r = 3

The cube roots are located on a circle with a center at the origin and a radius of 3 units.

The argument of a complex number, z = a+ib will be

[tex]\theta[/tex] = tan⁻¹(b/a)

The argument of a complex number z = 0+27i

[tex]\theta[/tex] = tan⁻¹(27/0)

[tex]\theta[/tex] = π/2

The cube roots have arguments that differ by 2π over 3.

Therefore, the correct answer for the drop-down menu exists in 3 and 2.

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[tex] \sqrt{112x {}^{6}y {}^{3} {z}^{5} } \\ \sqrt{(2 {}^{4} \times 7 )x {}^{6}y {}^{2}yz {}^{4} z } \\ 2 {}^{2}x {}^{3} yz {}^{2} \sqrt{7yz} [/tex]

Answer:

5/222

Step-by-step explanation:

you need to add all the cards together first

13 + 10 + 8 + 6 = 37

then you take out 1 card to find the first probability of the blue card (there are 6 blue cards out of 37)

so 6/37

that will be your first probability

then for the 2nd probability, you will have 1 less card grom the deck making it only 36 cards (after taking out the first one, there will be only 5 blue cards left)

making it 5/36

that will be the 2nd probability

then you multiply both these probabilities to find the answer

6/37 × 5/36 = 5/222

1/2

Step-by-step explanation:

All outcomes of a single die= 6

Events less than 4 =3

probability=3/6

=1/2

[tex](x-5)(x+5)-(x+1)^2\\=x^2 -25-(x^2+2x +1)\\=x^2 -25-x^2-2x -1\\=-2x-26[/tex]

ANSWER: -2x -26

Ok done. Thank to me :3

If the speed of the ball after kicking is 48 feet per second then the ball will return on the ground after 3 seconds.

Given that the speed of the ball after kicking is 48 feet per second and the function that represents the height of the ball is [tex]-16t^{2} +48t[/tex].

We are required to find the time that the ball took to travel before returning the ground.

We know that speed is the distance a thing covers in a particular time period.

The height of the ball after t seconds is as follows:

h(t)=[tex]-16t^{2} +48t[/tex]

It is at ground at the instants of t.

Hence,

[tex]-16t^{2} +48t[/tex]=0

-16t(t-3)=0

We want value of t different of 0, hence :

t-3=0

t=3.

Hence if the speed of the ball after kicking is 48 feet per second then the ball will return on the ground after 3 seconds.

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Answer:

B. t=3

Step-by-step explanation:

i took the test and got it right

Using the arrangements formula, it is found that there are 20,160 different groups of players of 2 players that the coach can make.

The number of possible arrangements of n elements is given by the factorial of n, that is:

[tex]A_n = n![/tex]

In this problem, all 8 players will play, hence considering the order, the number of ways is:

[tex]A_8 = 8! = 40320[/tex]

However, the position does not matter, as for example, João and Elisa would form the same pair as Elisa and João, hence the removing the order, the number of groups is:

40,320/2 = 20,160.

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Answer:

The answer is 28!!!

Step-by-step explanation:

Use the combinations formula:

[tex]C = \frac{n!}{r!(n-r)!}[/tex]

n = 8

r = 2

[tex]C = \frac{8!}{2!~*~6! } = 28\\[/tex]

I got it right! Look at the pic for proof.

Hope this helps!! :)

Juan's ball would travel the greatest distance while Barry's ball would travel the shortest.

Juan

Juan's equation is given as:

h = -0.001d^2 + 0.5d + 2.5

h =

Set d to multiples of 50 from 0 to 400.

So, the table of values of Juan's function is:

d (ft)                   h(ft)

0                          2.5

50                        25

100                      42.5

150                        55

200                      62.5

250                        65

300                      62.5

350                        65

400                      42.5

See attachment for the graph of Juan's function

Mark

A quadratic function is represented as:

h = ad^2 + bd + c

Using the values on the table of values, we have:

c = 3 -- the constant value

So, the equation becomes

h = ad^2 + bd + 3

Using the two other values on the table of values, we have:

23 = a(50)^2 + b(50) + 3

38 = a(100)^2 + b(100) + 3

Using a graphing tool, we have:

a = -0.001

b = 0.45

So, Mark's equation is h(d) = -0.001d^2 + 0.45d + 3

See attachment for Mark's graph.

Barry

From the graph, we have the table of values of Barry's function to be:

d (ft)                   h(ft)

0                          2.5

50                        21

100                      35

150                       44

200                      48

250                       46

300                      41

350                       30

400                      14

450                      0

Using a graphing tool, we have the quadratic function to be:

y = -0.001x^2 +0.4x +2.5

From the graphs, equations and tables, the distance travelled by the balls are:

Juan = 505 feet

Mark = 457 feet

Barry = 450 feet

This means that Juan's ball would travel the greatest distance while Barry's ball would travel the shortest.

To do this, we set d = 350

From the graphs, equations and tables, the height at 350 ft by the balls are:

Juan = 65 feet

Mark = 38 feet

Barry = 30 feet

The above represents the height the balls hit the fence

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[tex]\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ V=562\\ r=5 \end{cases}\implies 562=\cfrac{\pi (5)^2 h}{3}\implies 1686=25\pi h \\\\\\ \cfrac{1686}{25\pi }=h\implies 21.47\approx h[/tex]

Answer:$96.98

Step-by-step explanation: all you just do is to add it all up to the total amount.

Answer: $105.47

I hope you get the job!!!!!

The required radius of the cylinder that can be covered by the paint exists at 3.8 feet.

Franco has enough paint to protect an area of about 226 square feet. He must paint a cylinder that exists 5 feet, and the maximum possible radius of the cylinder that can be covered by the paint exists to be determined.

The cylinder exists described as a 3D solid that holds two identical bases joined by a curved surface, at a particular distance.

Here, Franco keeps sufficiently paint to cover an area of about 226 square feet.

Area of the cylinder = 226

Area of the cylinder = πr²h = 226

h = 5 feet and π = 3.14

3.14 [tex]*[/tex] 5 [tex]*[/tex] r² = 226

r² = 226/15.70

[tex]$r = \sqrt{14.70}[/tex]

r = 3.80

Therefore, the required radius of the cylinder that can be covered by the paint exists at 3.8 feet.

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Answer: 4

Step-by-step explanation: I got the answer 4 right on the test

Answer:

Step-by-step explanation:

Answer: Total = $200

Step-by-step explanation:

Given information

Money spent on shoes = $20.00

Percent of Money spent on shoes = 10%

Given formula

The total amount of money spent × Percent = Money spent on shoes

                                                      ⇵    

The total amount of money spent = Money spent on shoes / Percent

Substitute values into the given formula

The total amount of money spent = Money spent on shoes / Percent

Total = (20.00) / (10%)

Convert percentage into decimal

Total = 20.00 / 0.1

Simplify the fraction

[tex]\Large\boxed{Total~=~200~Dollars}[/tex]

Hope this helps!!  :)

Please let me know if you have any questions

[tex]let \: the \: number \: be \: denoted \: by \: p \\ five \: times \: a \: number = 5p \\ square\: of \: a \: number = p {}^{2} [/tex]

[tex] \gamma - p {}^{2} = 5p - p {}^{2} [/tex]

Option C. The mean is less than the median in the distribution of the scores.

The median is given as 79 + 78 / 2

= 78.5

The mode is 79 this is the number that has the highest frequency in the data.

The median is 78.5  this is the middle number in the set of scores of these students.

Hence the mean is less than the mode and the median given that it was  it was brought down by the few scores of 49.

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See attached images for the graph.

Answer:

Find out how much each makes per hour and then compare.

Step-by-step explanation:

Phil: 112.70/14 = 8.05  Phil makes $8.05 per hour

Eva: 113.82/1 =8.13  Eva makes $8.13 per hour

Eva makes $0.08 more an hour.

The average density of the rod is  0.704 kg/m.

For given question,

We have been given the linear density in a rod 5 m long is 10 / x + 4 kg/m, where x is measured in meters from one end of the rod.

We need to find the

The length of rod is, L = 5 m.

The linear density of rod is, ρ = 10/( x + 4) kg/m

To find the average density we need to integrate the linear density from x₁ = 0 to x₂ = 5,  

The expression for the average density is given as,

⇒ ρ'

[tex]=\int\limits^5_0 {\rho} \, dx\\\\=\int\limits^5_0 {\frac{m}{L} } \, dx\\\\=\int\limits^5_0 {\frac{10}{5(x+4)} }\, dx\\\\=\int\limits^5_0 {\frac{2}{x+4} }\, dx[/tex]                        ......................(1)

Using u = x + 4  

du = dx

u₁ = x₁ + 4

u₁ = 0 + 4

u₁ = 4

and

u₂ = x₂ + 4

u₂ = 5 + 4

u₂ = 9

By entering the values above into (1), we have:

⇒ ρ'

[tex]=2\int\limits^9_4 {\frac{1}{u} } \, du\\\\ = 2[(log~u)]_4^{9}\\\\=2[(log~9-log~4)]\\\\=2\times[0.352][/tex]

= 0.704

Thus, we can conclude that the average density of the rod is  0.704 kg/m.

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Answer:

The rope is worth 13.

The shoe is worth 5.

The clock is worth 3.

Step-by-step explanation:

We know that the weights are 8 so we will use 8 for the weights.

Let s = show

Let r = rope

Let c = clock

We have three unknowns so we need three equations.

8 + s = r                      c + s = 8                                 s= c +2

There are a number of ways that we can approach this.  Let's substitute

c + 2 for s in the first 2 equations.

8 + s = r

8 + c + 2 = r

10 + c = r

c + s = 8

c + c + 2 = 8

2c + 2 = 8  

2c = 6

c = 3  we found the value of the clock.

Now, let's substitute 3 in for 3 in the bold equation above.

10 + c = r

10 + 3 = r

13 = r we found the value of the rope.

We can use any of the equations to find the shoe.

s= c + 2

s = 3 + 2

s = 5

This is tricky.  It takes a lot of practice.  Don't give up!

Shoe= 5

Rope= 13

Clock= 3

We can start by giving each item a variable. Shoe= s, rope= r, clock= c. The weight is 8, so we don't need to give it a variable. Our equations are now:

8+s= r

c+s= 8

s= c+2

Now, we can isolate a variable to solve for it using the substitution method. Let's start with s.

c+s=8

-c    -c

s= 8-c

Now, we'll take another equation and plug s in.

8-c=c+2

 +c +c

8= 2c+2

-2      -2

6=2c

c=3

Now we know that the clock is 3. Put 3 into the last equation, and add 3+2 to get 5 for the shoe. 5 in the first equation for the shoe plus 8 as the weight means the rope is 13.

hope this helped!

Answer:

16 square units

Step-by-step explanation:

You find the area by multiplying the base times the height.  The base or horizonal length is 4.  You get this from the ordered point x (4,0).  The x coordinate 4, tells us that the point x is 4 spaces to the right of zero, so the length or base is 4.

The height is also 4.  You get this from the point S (2,4)  The y coordinate of 4 tells you how high up the point is.

4 x 4 = 16

[tex]\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{lllllllll} \log_{\underline{10}}(10)=1&\implies &\underline{10}^1=10 ~~ \checkmark\\\\ \log_{10}(100)=2&\implies &10^2=100~~ \checkmark\\\\ \log_{10}(55)=1.5&\implies &10^{1.5}=55\implies 10^{\frac{3}{2}}=55\implies \sqrt[2]{10^3}=55\\\\ &&\sqrt{1000}\ne 55 ~~ \bigotimes \end{array}[/tex]

increments over the exponent, are not directly proportional to increments on the resulting values, namely the half-way from 10² and 10⁴ is not 10³, because 10⁴ is 100 times 10², and 10³ is simply 10 times 10².

The zeros represent the number of monthly memberships where no profit is made; x = 6, x = 44.

The function we have is: [tex]f(x) = -x^{2} +50x-264[/tex]

That models the profit in dollars, where [tex]x[/tex] is the number of memberships sold.

In order to get the zeros we'll use the quadratic formula:

[tex]x_{1,2} =\frac{-b+-(b^{2}-4ac) }{2a} \\[/tex]

For,

[tex]a=-1,b=50,c=-264: x^{1,2} =\frac{-50+-\sqrt[]{50^{2} -4(-1)(-264)} }{2(-1)} \\x_{1} =\frac{-50+\sqrt[]{50^{2} -4(-1)(-264)} }{2(-1)} =\frac{-50+\sqrt[]{50^{2} -4*1*264} }{2(-1)}=\frac{-50+\sqrt[]{1444} }{-2} =6\\x_{2} =\frac{-50+\sqrt[]{50^{2} -4(-1)(-264)} }{2(-1)} =\frac{-50-\sqrt[]{50^{2} -4*1*264} }{2(-1)}=\frac{-50-\sqrt[]{1444} }{-2} =44\\[/tex]

So, the zeroes are [tex]x=6, x=44[/tex].

Therefore, the zeros represent the number of monthly memberships where no profit is made; x = 6, x = 44.

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The complete question is given below:

A yoga studio sells monthly memberships. The function f(x) = −x2 + 50x − 264 models the profit in dollars, where x is the number of memberships sold.

Determine the zeros, and explain what these values mean in the context of the problem.

x = 6, x = 44; The zeros represent the number of monthly memberships that produce a maximum profit.

x = 6, x = 44; The zeros represent the number of monthly memberships where no profit is made.

x = 25, x = 361; The zeros represent the number of monthly memberships where no profit is made.

x = 25, x = 361; The zeros represent the number of monthly memberships that produce a maximum profit.

Answer:

The answer is: x = 6, x = 44; The zeros represent the number of monthly memberships when no profit is made.

The satellite makes 8 revolutions around the earth, it passes 177272 kilometers.

The orbital velocity of the satellite exists independent of its mass. The radius of the orbit exists as the only variable. If the satellite orbits near the planet at such a low height, its orbital speed must be extremely fast. If the orbital speed exists less than the required value, the satellite will be drawn to the earth's surface by gravity.

The satellite rotates around the earth to form a circle,

diameter of circle = Diameter of earth + 2(Height)

d = 6714 + 2(343)

d = 6714+ 686

d = 7057

Perimeter = πd

Perimeter = 3.14 (7057)

Perimeter = 22158.98

Total Revolution exists 8

Therefore, 8πd = 8(22158.98)

= 177272 kilometers.

Therefore, the satellite makes 8 revolutions around the earth, it passes 177272 kilometers.

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The first series uses a linear function with - 1 as first element and 1 as common difference, then the rule corresponding to the series is y = |- 1 + x|.

The second series uses a linear function with - 3 as second element as 2 as common difference, then the rule corresponding to the series is y = |- 3 + 2 · x|.

In this problem we have two cases of arithmetic series, which are sets of elements generated by a condition in the form of linear function and inside absolute power. Linear functions used in these series are of the form:

y = a + r · x      (1)

Where:

The first series uses a linear function with - 1 as first element and 1 as common difference, then the rule corresponding to the series is y = |- 1 + x|.

The second series uses a linear function with - 3 as second element as 2 as common difference, then the rule corresponding to the series is y = |- 3 + 2 · x|.

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The surface area of all 27 blocks compared to the surface area of the box is 3 times the surface area of the box.

To find the total surface area of the 27 blocks:

A cube's surface area

Given that the box's side length is 15 inches:

Surface Area of 3-inch side length blocks:

Surface Area of 4-inch side length blocks:

Surface Area of 5-inch side length blocks:

Therefore, from the given answer options for the total surface area of the 27 blocks, the side length of the blocks must be 5 inches.

To calculate how many times the total surface area of the 27 blocks is to the surface area of the box:

So,

The side length of the blocks is 5 inches.

The total surface area of the 27 blocks is 4050 square inches.

This is 3 times the surface area of the box.

Therefore, the surface area of all 27 blocks compared to the surface area of the box is 3 times the surface area of the box.

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