A 4.00-kg object is attached by a thread of negligible mass, which passes over a frictionless pulley of negligible mass, to a 5.00-kg object. The objects are positioned so that they are the same height from the floor, and then released from rest. What is the speed of the objects when they are separated vertically by 1.00 m? U= 0.545 m/s

The required time until the coin begins to slide is 1.94 s. Net force = Centripetal force - Frictional force and formula for Centripetal force is = mrω² .

Given that : Radius of turntable, r = 13 cm, Coefficient of static friction between the coin and turntable, µ = 0.11

Angular acceleration, α = 1.2 rad/s²

Net force = Centripetal force - Frictional force

Centripetal force = mrω² where, m = Mass of coin, r = radius of turntable, and ω = Angular velocity, Frictional force, f = µN where, N = Normal force

By equating the above two expressions, we get: mrω² = µN

From the above expression, we get: N = mrω² / µ

Time taken for the coin to begin to slide = Time taken for angular velocity to reach at a value where the above relation holds true

So, we need to find out the value of angular velocity (ω) after which the coin begins to slide.

Substituting the value of N in the equation of frictional force, we get:

f = µmrω² / µ

= mrω²

Now, we have Net force (Fnet) acting on the coin, that is given by: Fnet = mrα

Since the coin will begin to slide when Fnet = fFnet

= fmrα

= µmrω²α

= µω²

From the above expression, we get:ω = √(α / µ)

Putting the given values, we get:

ω = √(1.2 / 0.11)

= 3.24 rad/s

Time taken for the coin to begin to slide is given by:

T = 2π / ω

= 2π / 3.24

≈ 1.94 s

Therefore, the required time is 1.94 s.

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When comparing a CANDU nuclear reactor with a coal-fired electrical generating system, the characteristics that are common to both are i, iv, and v. Both a CANDU nuclear reactor and a coal-fired electrical generating system share the use of non-renewable fuel, conversion of chemical potential energy, and the absence of direct gravitational potential energy conversion.

i. Both systems utilize non-renewable fuel. The CANDU reactor uses uranium as fuel, which is a finite resource, while coal-fired systems rely on the combustion of coal, which is also a non-renewable fossil fuel.

iv. Both systems convert chemical potential energy into electrical energy. In the CANDU reactor, nuclear fission of uranium atoms releases energy that is converted into electricity, whereas in a coal-fired system, the combustion of coal produces heat that is converted into electrical energy.

v. Both systems do not directly convert gravitational potential energy. The CANDU reactor and coal-fired systems do not rely on the gravitational potential energy of water or any other substance as a primary source of energy conversion.

Therefore, the correct answer is option c. i, iv, and v only. Both systems share the use of non-renewable fuel, conversion of chemical potential energy, and absence of direct gravitational potential energy conversion.

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Marisol pushes a  3 kg box 7 m across the floor with a force of 12 N  She lifts the box to a shelf  1 m above the ground. Marisol does a total of 113.4 Joules of work on the box.

To calculate the work done by Marisol on the box, we need to consider two separate components: the work done in pushing the box across the floor and the work done in lifting the box to the shelf.

1. Work done in pushing the box across the floor:

The work done is given by the formula: Work = Force * Distance. In this case, Marisol exerts a force of 12 N and moves the box a distance of 7 m. So,

Work1 = Force * Distance

Work1 = 12 N * 7 m

Work1 = 84 Joules (J)

2. Work done in lifting the box to the shelf:

The work done against gravity is given by the formula: Work = Force * Distance. Marisol lifts the box a vertical distance of 1 m. The force required to lift the box is equal to its weight, which is given by the formula: Weight = mass * gravity. Substituting the values,

Weight = 3 kg * 9.8 m/s^2 (acceleration due to gravity)

Weight = 29.4 N

Work2 = Force * Distance

Work2 = 29.4 N * 1 m

Work2 = 29.4 Joules (J)

To find the total work done, we add the work done in pushing the box across the floor and the work done in lifting it to the shelf:

Total Work = Work1 + Work2

Total Work = 84 J + 29.4 J

Total Work = 113.4 Joules (J)

Therefore, Marisol does a total of 113.4 Joules of work on the box.

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Acceleration is defined as the rate of change of velocity with respect to time. Velocity is defined as the rate of change of displacement with respect to time. The main answer to the question is that an empty shopping cart pushed with a light force will have the least acceleration.

Let us explain why.An object pushed with a hard force will have more acceleration than an object pushed with a light force because of the force applied to the object. A full shopping cart will also have more acceleration than an empty shopping cart, because the mass of the full cart is more than the mass of the empty cart.

We know that acceleration is inversely proportional to mass.Therefore, an empty shopping cart pushed with a light force will have the least acceleration.

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When accelerating upward, T > w. At constant velocity upward, T = w. Upward motion with downward acceleration, w > T. Tension force T can be calculated using T = m * (a + g) in part (a), T = m * g in part (b), and T = m * (a - g) in part (c).

In this scenario, the elevator experiences a net upward force. According to Newton's second law of motion (F = ma), the net force is equal to the mass of the elevator multiplied by its acceleration. Since the elevator is accelerating upward, the tension force in the cable must be greater than the weight force to provide the necessary net upward force.

At a constant velocity, the elevator experiences zero net force. The tension force in the cable and the weight force due to gravity are balanced, resulting in an equilibrium situation. The tension force is equal to the weight force, ensuring the elevator maintains a steady upward motion.

In this case, the elevator is decelerating or slowing down while still moving upward. The net force acting on the elevator is downward, and it is provided by the weight force due to gravity. The tension force in the cable is smaller than the weight force to create this net downward force.

Using Newton's second law of motion (F = ma), we can determine the net force acting on the elevator. The net force is equal to the tension force minus the weight force, which is the product of the mass and acceleration. Setting up the equation, we have T - w = m * a. Substituting the known values and solving for T, we find the tension force to be T = m * (a + g), where g is the acceleration due to gravity. This result is consistent with the answer in part (a) because the elevator is accelerating upward.

At a constant velocity, the elevator experiences zero net force, so the tension force in the cable must be equal to the weight force. Therefore, T = w = m * g. Plugging in the given values, we find that T = 1,500 kg * 9.8 m/s², which confirms the consistency with the answer in part (b).

In this case, the net force acting on the elevator is downward, which is provided by the weight force due to gravity. The tension force in the cable is smaller than the weight force, creating the necessary net downward force. Using Newton's second law of motion, T - w = m * a, we can determine T. Plugging in the given values, we find T = m * (a - g), where g is the acceleration due to gravity. This result is consistent with the answer in part (c) because the elevator is decelerating or slowing down while moving upward.

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Answer:

125 kg

Explanation:

KE = 1/2m * v^2

m = 2KE / v^2

m = 2(4.00x10^3)/8^2

m = 125kg (or whatever units of mass the problem is asking for)

Given parameters:

Displacement = 8km

Velocity  = 3.8km/h

Unknown:

time  = ?

Solution:

Velocity is displacement divided by time.

  Velocity  = [tex]\frac{displacement}{time}[/tex]  

      Displacement  = velocity x time

Input the parameters:

              8  = 3.8  x time

 Time  = [tex]\frac{8}{3.8}[/tex]   = 2.1s

The time taken is 2.1s

The currents I1, I2, and I3 can be determined using Ohm's Law and Kirchhoff's Laws.

First, let's assign some labels to the resistors and batteries in the circuit for easier reference. Let R1 be the resistance of the first resistor, R2 be the resistance of the second resistor, and so on until R5. Let V1 be the voltage of the first battery and V2 be the voltage of the second battery.According to Kirchhoff's Current Law, the sum of currents entering a junction is equal to the sum of currents leaving the junction. Applying this law to the junction between R1 and R2, we have:
I1 + I2 = I3  -------- (Equation 1)
Next, let's apply Ohm's Law to each resistor:
V1 = I1 * R1  -------- (Equation 2)
V2 = I2 * R3  -------- (Equation 3)
V2 = I3 * R4  -------- (Equation 4)
Now, let's substitute the values of V1, V2, R1, R3, and R4 into Equations 2, 3, and 4, respectively:
V1 = I1 * 1.10
V2 = I2 * R3
V2 = I3 * R4

Since the voltage of a battery is equal to the sum of the potential differences across the resistors connected to it, we have:
V1 = V2 + I2 * R2  -------- (Equation 5)
Substituting the value of V2 from Equation 3 into Equation 5, we get:
I2 * R3 = V2 + I2 * R2
Now, let's rearrange Equation 5 to solve for I2:
I2 * (R3 + R2) = V2
I2 = V2 / (R3 + R2)  -------- (Equation 6)
Finally, we can substitute the value of I2 from Equation 6 into Equation 1 to solve for I1: I1 + V2 / (R3 + R2) = I3
Now, we have a system of equations to solve for I1, I2, and I3.

To calculate I1, I2, and I3, we need the values of V1, V2, R1, R2, R3, and R4. Without these values, it is not possible to provide specific numerical values for the currents. However, by applying Kirchhoff's Laws and Ohm's Law as shown above, you can use the given values to solve for the currents I1, I2, and I3.

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The efficiency of a device that takes in 600 J of thermal energy and does 300 J of work is 50%.

Efficiency is a measure of how effectively a device converts input energy into useful work. It is calculated by dividing the useful output energy (work done) by the total input energy.

In this case, the device takes in 600 J of thermal energy and performs 300 J of work. To calculate efficiency, we divide the work done by the input energy and multiply by 100 to express it as a percentage.

Efficiency = (Work output / Input energy) * 100

Substituting the given values:

Efficiency = (300 J / 600 J) * 100

Efficiency = 0.5 * 100

Efficiency = 50%

Therefore, the device in question has an efficiency of 50%. This means that half of the input thermal energy is successfully converted into useful work, while the other half is lost as waste heat or in other non-useful forms.

Improving the efficiency of the device would involve reducing the amount of wasted energy and increasing the amount of useful work accomplished for the given input energy.

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Answer:

The flow of energy through living organisms begins with photoshypothesis. This process stores energy from sunlight in the chemical bonds of glucose. By breaking the chemical bond in glucose, cells release the stored energy and make the ATP they need.

Explanation:

Or humans get energy from other things in the biosphere.

Answer:

I think the answer is 666.7m/s2

Explanation:

30s/3600=0.0083hr

a=(v-v0)/t

a=(65-45)/0.0083=2400/3.6=666.7m/s2

The wavelengths of standing waves on a string fixed at both ends can be determined using the formula:λ = 2L/n. The frequency of the third-longest wavelength is approximately 75.82 Hz.

Given that the length of the string is 230 cm (or 2.30 m), we can calculate the wavelengths for the three longest standing waves as follows:

First-longest wavelength (n = 1):

λ1 = 2L/n = 2(2.30) / 1 = 4.60 m

Second-longest wavelength (n = 2):

λ2 = 2L/n = 2(2.30) / 2 = 2.30 m

Third-longest wavelength (n = 3):

λ3 = 2L/n = 2(2.30) / 3 ≈ 1.53 m

Now, if the frequency of the second-longest wavelength (λ2) is given as 50.0 Hz, we can find the frequency of the third-longest wavelength (λ3) by using the formula for wave speed:

v = fλ

where v is the wave speed, f is the frequency, and λ is the wavelength.

Since the wave speed remains constant for a given medium, we can set up the following equation:

v = f2λ2 = f3λ3

Solving for f3:

f3 = (f2λ2) / λ3 = (50.0 Hz * 2.30 m) / 1.53 m ≈ 75.82 Hz

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Answer:

-1

Explanation:

count 3 spaces in T and go to the object and it should be at -1. I hope this is correct and helps you!

Answer:

Explanation:

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Answer:

The effect of the acceleration on the bus is that the acceleration slows down the bus by 4 m/s, for each second the bus is in motion

Explanation:

The given parameters are;

The velocity of the bus, u = 25 m/s

The direction in which the bus is moving = South

The acceleration acting on the = 4 m/s²

The direction of the acceleration = North

We have;

The acceleration = Rate of change of velocity with time

The acceleration, a = dv/dt

∴ dv = a × dt

The velocity in the direction of the acceleration, v is therefore;

∫dv = v = ∫a × dt = a × t

v = a×t

The direction of the change in velocity due to the acceleration is opposite to the direction of the velocity of the bus, therefore, the effect of the acceleration on the velocity of the bus is given by the following equation for the resultant velocity, s, as follows;

s = u - a × t = 25 - 4×t

s = 25 - 4×t

Therefore, the acceleration slows down the bus by 4 m/s, every second.

Answer:

Explanation:

Gtt

The observed relationship between an applied magnetic field and magnetic induction in a material in which a cyclic magnetic field is applied can be described as a magnetic hysteresis loop.

However, a magnetic hysteresis loop doesn't just appear at the first application of the magnetic field to the material, but also has to be reversed when the magnetic field is removed. When there's an application of an external magnetic field to a ferromagnetic material, the magnetic domains get aligned in the direction of the field.When this alignment of domains is disrupted,

the ferromagnetic material still retains some magnetism even when the applied magnetic field is removed. This remaining magnetism is called the remanence. If the ferromagnetic material is subjected to an opposite magnetic field, it becomes demagnetized. The magnetic induction, at which this complete demagnetization takes place, is called the coercivity.The magnetic hysteresis loop describes how the magnetic induction, magnetizing force and flux density varies with the applied magnetic field. In short, a magnetic hysteresis loop represents how a material responds to a magnetic field.

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The answer is C. Tides becuase plants use tidal energy which is a form of hydropower that works by harnessing the kinetic energy created from the rise and fall of ocean tides, also called tidal flows, and turns it into usable electricity.

The ocean movement that power plants use to produce usable energy is tidal flows, which is  the rise and fall of the ocean tides.

Tidal flow is the movement of water, associated with the rise and fall of the tides.

Plants use tidal energy which is a form of hydro power that works by converting the kinetic energy created from the rise and fall of ocean tides, also called tidal flows, and into usable electricity.

Thus, the ocean movement that power plants use to produce usable energy is tidal flows, which is  the rise and fall of the ocean tides.

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If you move the revolving nosepiece in the wrong direction after viewing under oil immersion, the lens that could get dirty with oil is the 40x lens.

Oil immersion is a technique used in microscopy to increase the resolution and clarity of the image. It involves placing a drop of immersion oil on the slide and using a specially designed lens with a high numerical aperture (NA), such as the 100x objective lens, to maximize the collection of light.

The 40x lens is typically used before oil immersion in the microscopy process. When you move the revolving nosepiece in the wrong direction after viewing under oil immersion, there is a possibility that some oil residue may be left on the 40x lens. This can happen if you accidentally rotate the nosepiece in a counterclockwise direction, causing the lens to come into contact with the oil on the slide.

The other lenses, the 4x and 10x, are used at lower magnifications and are unlikely to come into contact with the oil immersion. They are generally positioned before the oil immersion step in the sequence of lens usage.

It is important to handle the microscope carefully and follow the correct procedure for using oil immersion to avoid damaging the lenses or getting them dirty. If oil does come into contact with the lenses, it should be cleaned off promptly using appropriate cleaning techniques to maintain the optical performance of the microscope.

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When the cathode's work function is larger than the photon energy, the graph of  photoelectric current will not be as pronounced. It will be difficult to detect any current in the circuit, as the energy of the photon is not sufficient to overcome the potential barrier of metal.

A photon's energy must be sufficient to overcome the metal's work function in order for photoemission to occur. When this happens, electrons in the metal's surface absorb the photon and are ejected from the metal, resulting in a current. When the photon's energy is insufficient to overcome the work function, photoemission does not occur and the current is not generated.

On the graph, this is represented by a very low current, or no current at all, when the cathode's work function is larger than the photon energy. The threshold frequency of the metal can be calculated from the photoelectric current graph's x-intercept.

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If the cathode's work function is larger than the photon energy, no photoelectric current will be observed.

1. The photoelectric effect refers to the emission of electrons from a material when it is exposed to light or photons.

2. The photoelectric current is the flow of electrons resulting from the photoelectric effect.

3. The photoelectric current depends on various factors, including the energy of the incident photons and the work function of the material's cathode.

4. The work function is the minimum amount of energy required to remove an electron from the material.

5. If the cathode's work function is larger than the energy of the incident photons, it means that the photons do not possess enough energy to overcome the work function and remove electrons from the material.

6. In this scenario, the electrons will not be emitted, and therefore, no photoelectric current will be observed.

7. The photoelectric current is directly proportional to the intensity of incident light and the number of electrons emitted from the material.

8. However, if the photon energy is larger than the cathode's work function, electrons will be emitted, and a photoelectric current can be observed.

9. Increasing the intensity of the incident light will result in a higher number of emitted electrons and consequently an increased photoelectric current.

10. Overall, if the cathode's work function is larger than the photon energy, no photoelectric current will be observed due to insufficient energy to eject electrons from the material.

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The closest object that can be photographed in cm is 6.25 cm. The focal length of the lens, f = 20.5 mm

Farthest distance of the lens from the film, u = 30.5 mm

Let the distance of the closest object from the lens be v.

Using the lens formula,

1/f = 1/v - 1/u

1/20.5 = 1/v - 1/30.5(30.5 - 20.5)/20.5 × 30.5

= 1/v10/20.5 × 30.5

= 1/vV

= 20.5 × 30.5 / 10V

= 62.525 mm

Therefore, the closest object that can be photographed in cm is 6.25 cm.

Given data:

The focal length of the lens, f = 20.5 mm

Farthest distance of the lens from the film, u = 30.5 mm

Let the distance of the closest object from the lens be v.

Lens formula is given as:

1/f = 1/v - 1/u

Substituting the given values, we get

1/20.5 = 1/v - 1/30.5

Multiplying both sides by 20.5 × 30.5, we get:

(30.5 - 20.5)/20.5 × 30.5 = 1/v

Simplifying, we get:10/20.5 × 30.5 = 1/v

Therefore,

v = 20.5 × 30.5 / 10v = 62.525 mm

Hence, the closest object that can be photographed in cm is 6.25 cm.

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Answer:

The time is 0.65 sec.

The distance from the hill is 2.07 m.

Explanation:

Given that,

Speed = 15 m/s

Distance = 9.8 m

Along horizontal,

We need to calculate the time

Using formula of time

[tex]t=\dfrac{d}{v}[/tex]

Where, d =distance

v = velocity

Put the value into the formula

[tex]t=\dfrac{9.8}{15}[/tex]

[tex]t=0.65\ sec[/tex]

Along vertical,

We need to calculate the height

Using equation of motion

[tex]s=ut+\dfrac{1}{2}gt^2[/tex]

Put the value in the equation

[tex]s=0+\dfrac{1}{2}\times9.8\times(0.65)^2[/tex]

[tex]s=2.07\ m[/tex]

Hence, The time is 0.65 sec.

The distance from the hill is 2.07 m.

Wing divergence is a phenomenon that occurs when the aerodynamic loads acting on an aircraft wing cause it to twist excessively, resulting in potential wing failure. The angle of attack, which is the angle between the wing's chord line and the relative wind, plays a significant role in this process. As the angle of attack increases, the aerodynamic forces acting on the wing also increase, causing a twisting effect known as torsion.

To prevent wing divergence and ensure the safety of the aircraft, wing designs incorporate torsional stiffness. Torsional stiffness refers to the ability of the wing structure to resist twisting under aerodynamic loads. By designing the wing to be torsionally stiff, it can maintain its structural integrity and resist excessive twist even at high angles of attack. This stiffness is achieved through the use of suitable materials, structural reinforcements, and engineering techniques.

By ensuring adequate torsional stiffness, aircraft designers can mitigate the risk of wing divergence and prevent potential wing failures, ensuring the aircraft's structural integrity and flight safety within its designated flight envelope.

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When a turtle crawls along a straight line, its initial velocity is found to be 2.25 cm/s, initial position is 45.0 cm and initial acceleration is -0.127 cm/s². The velocity of the turtle is zero at t = 17.72 s. It takes the turtle approximately 35.37 seconds to return to its starting point.

(a) To find the turtle's initial velocity, we can take the derivative of the position function with respect to time: v(t) = d/dt[x(t)] = 2.25 cm/s - 2(0.0635 cm/s²)t.

The initial velocity can be found by evaluating the velocity function at t = 0:

v(0) = 2.25 cm/s - 2(0.0635 cm/s²)(0) = 2.25 cm/s.

Therefore, the turtle's initial velocity is 2.25 cm/s.

The initial position is given in the equation as x(t) = 45.0 cm.

Therefore, the turtle's initial position is 45.0 cm.

To find the initial acceleration, we can take the second derivative of the position function with respect to time: a(t) = d²/dt²[x(t)] = -2(0.0635 cm/s²) = -0.127 cm/s².

So, the turtle's initial acceleration is -0.127 cm/s².

(b) To find the time at which the velocity of the turtle is zero, we set the velocity function equal to zero and solve for t: 2.25 cm/s - 2(0.0635 cm/s²)t = 0.

2.25 cm/s = 2(0.0635 cm/s²)t.

t = 2.25 cm/s / (2(0.0635 cm/s²)) = 17.72 s.

Therefore, the velocity of the turtle is zero at t = 17.72 s.

(c) To determine the time it takes for the turtle to return to its starting point, we set the position function equal to the initial position and solve for t: x(t) = 45.0 cm.

45.0 cm + (2.25 cm/s)t - (0.0635 cm/s²)t² = 45.0 cm.

(2.25 cm/s)t - (0.0635 cm/s²)t² = 0.

t(2.25 cm/s - (0.0635 cm/s²)t) = 0.

The equation has two solutions: t = 0 and t = 35.37 s.

Since t = 0 corresponds to the initial time when the turtle starts, we consider the positive solution: t = 35.37 s.

Therefore, it takes the turtle approximately 35.37 seconds to return to its starting point.

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Balancing the forces acting on a body is not enough to establish equilibrium because equilibrium also requires the balancing of torques or moments acting on the body.

In physics, equilibrium refers to a state in which an object or system experiences no net force and no net torque. For an object to be in equilibrium, both the forces and the torques acting on it must be balanced.

Balancing the forces means that the vector sum of all the forces acting on the body is equal to zero. This ensures that there is no net force acting on the object, and it will not accelerate in any direction. However, even if the forces are balanced, the object can still rotate or have a tendency to rotate if the torques acting on it are not balanced.

A torque, also known as a moment, is a measure of the tendency of a force to rotate an object about a specific axis. It depends on the magnitude of the force, the distance from the axis of rotation, and the angle between the force and the lever arm. When torques are balanced, the sum of all the torques acting on the object is equal to zero.

To establish equilibrium, both the forces and the torques acting on the body must be balanced. This means that not only should the vector sum of the forces be zero, but also the algebraic sum of the torques should be zero. When both conditions are met, the object will remain at rest or continue to move with a constant rotational motion.

Balancing the forces acting on a body is not enough to establish equilibrium because equilibrium requires the balancing of both forces and torques. Simply balancing the forces ensures that there is no net force acting on the object, but it does not guarantee that the object will be in a state of complete equilibrium. To achieve equilibrium, the torques acting on the object must also be balanced, ensuring that there is no tendency for rotation.

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Gaining speed and changing the direction of force

A third-class lever makes our work easier by both magnifying force and gaining speed.

Hence, the correct option is D.

In a third-class lever, the effort (force) is applied between the fulcrum and the load. The load is closer to the fulcrum than the effort. This mechanical arrangement allows the lever to amplify the force applied at the expense of the distance the effort has to travel.

By applying a smaller force over a greater distance, a third-class lever can magnify the force applied to the load. Additionally, the increased distance covered by the effort compared to the load's displacement results in a greater speed at the load's end. So, both force magnification and speed gain are advantages of a third-class lever, making our work easier.

Therefore, A third-class lever makes our work easier by both magnifying force and gaining speed.

Hence, the correct option is D.

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D) is zero.

The electric field inside a metal sphere that has a net positive charge is zero. This is due to the property of conductors, such as metal, where the excess charge resides on the outer surface and redistributes to eliminate any electric field inside the conductor. As a result, the electric field inside the metal sphere becomes zero. This phenomenon is known as electrostatic shielding or the Faraday cage effect. Therefore, option D is the correct statement. The electric field is present only outside the metal sphere, pointing radially outward from the positively charged surface. Inside the sphere, the electric field is effectively canceled out by the redistribution of charges.

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Answer:

1. The standard metric unit of momentum is the kg•m/s.

2. the units of momentum will be the product of the units of mass and velocity. Mass is measured in kg and velocity in ms-1, therefore, the SI unit of momentum will be kgm/s(-1).

3.Recall that acceleration is rate of change of velocity, so we can rewrite the Second Law: force = mass x rate of change of velocity. Now, the momentum is mv, mass x velocity. ... rate of change of momentum = mass x rate of change of velocity.

Explanation:

i really hope i helped sorry for the paragraphs ;( !

Answer:

The right answer is "The center of mass doesn't move".

Explanation:

The direction of the velocity of the center of mass of the two astronauts does not move after Astronaut Y pulls on the cable.

From the given information, the pulling of the cable by astronaut Y builds and generates tension in the cable.

At the two ends of the cable, this tension will be the same. As such, there exist same force on the two astronauts which occurs in an opposite direction.

Therefore, this gives a net force that is equal to zero thereby making the center of the mass to remian stationary and not to move.

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Answer:

75mph

Explanation:

you multiply 33.528 by 2.237.

The correct answer is 0.798 l. In general, the work done by a system during an expansion or compression process is given by the equation

W = -Pext ΔV

where

W is the work done by the system, Pext is the external pressure, and ΔV is the change in volume. Let's use this equation to solve the problem.

ΔV = -W/Pext

= -(283 J)/(2.80 atm)

= -100.9 L atm

Since the volume increases, ΔV is positive. Therefore, we need to use the absolute value of ΔV to find the final volume.

Vf = Vi + |ΔV| = 0.200 L + 100.9 L = 101.1 L

However, we need to report the answer to the correct number of significant figures, which is three since all the input values in the problem have three significant figures.

Vf = 101 L (to three significant figures). The closest option to this answer is 0.998 l. However, we need to keep in mind that the conversion factor between liters and cubic decimeters is 1 L = 1 dm³, which means that we need to convert L to dm³ to make the units consistent with the input value for the initial volume.

1 L = 1000 cm³ = 1000 dm³

Therefore, the final answer is

Vf = 101 L

= 101 dm³

= 0.101 m³

0.798 L (to three significant figures).

Therefore, the detailed answer to the given problem is 0.798 l.

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Answer:

P = 98100 [N/m2]

Explanation:

To solve this problem we must use the following mathematical expression, which tells us that pressure is the relationship between Force and area.

P = F/A

where:

P = pressure [N/m2]

F = force [N]

A = area [m2]

We must convert the mass from tons to kilograms.

m = 3 [ton] * 1000 [kg/1 *ton] = 3000 [kg]

Force is defined as the product of mass by gravity.

F = 3000*9.81 = 29430 [N]

P = (29430/0.3)

P = 98100 [N/m2]