a 4.3 kg object is suspended by a string from the ceiling of an elevator. the acceleration of gravity is 9.8. determine the tension of the string if it is accelerating upward at a rate of 2.1

In the 1960s, it was proposed that quasars could be compact objects ejected quickly from the cores of adjacent regular galaxies.

Nobody anticipated that an object that resembles a star could have its spectral lines so drastically redshifted.

It's a concept that makes sense when you consider that as light's wavelength is extended, the spectral lines appear to have "shifted" toward the red portion of the spectrum.

Sound waves experience a similar effect when a source moves in relation to an observer.

As a result of the emission lines being "red shifted," astronomers initially had trouble distinguishing them in quasar spectra at optical wavelengths.

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The smallest separation in terms of nm between two slits that will produce a second-order maximum for 652 nm visible light is  1.30 um

Since the relationship between wavelength and angle for  minima and maxima  in Young's double slit experiment is:

For constructive interference

d sinθ = n

for  Destructive interference

d sinθ = (n+1/2)λ, where  λ is the wavelength, n  is the order of maxima and minima, Since here n = 2

So the separation, λ =  652 nm , and  θ = 90

so, d sin90 = 2*652*10⁻⁹

=> d=  2*652*10⁻⁹/ sin90  

     =  1.30 X10⁻⁶

    = 1.30 цm

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Answer:

1875 J

Explanation:

kinetic energy= [tex]\frac{1}{2}[/tex]×mass×velocity²

K.E=[tex]\frac{1}{2}[/tex]mv²

K.E=[tex]\frac{1}{2}[/tex]×150×5.0²

K.E= 1875 J

The kinetic energy of the ball just after it is kicked is 48 J.

Kinetic energy is the force that propels motion, which can be seen in the movement of a particle, an object, or a group of particles. A person walking, a baseball being thrown, a piece of food falling from a table, and a charged particle in an electric field are all instances of objects in motion that use kinetic energy.

Vibrational, rotational, and translational energy are the three subtypes of kinetic energy. Unsurprisingly, vibrating things are the source of vibrational kinetic energy. While objects colliding with one another produce translational kinetic energy, objects moving create rotational kinetic energy.

Given:

Mass- 0.43kg

Velocity- 15

kinetic energy = 1/2 mv²

kinetic energy of the ball = 1/2 (0.43)(15)²

kinetic energy of the ball = 48 J.

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0.80tesla is a strength of a magnetic field.

At a distance r from the wire, a current I flowing through a long, straight wire generates a magnetic field with intensity H=I/2r. In other words, the field's strength is inversely proportional to the distance from the wire.

Newtons per coulomb (N/C) or volts per meter (V/m) are the SI units for measuring electric field strength. E = F/q, where F is the force felt by a very small test charge q placed in a field E in a vacuum, gives the force felt by the charge.

given,

I = 5A , r = 1.0m

H=I/2πr

H = 5 / 2*3.14*1.0

H = 0.80tesla

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The coefficients of static and kinetic friction between crate and floor are

0.25 and 0.176 respectively.

When a body is at rest and if a force is applied to move it, then it would require the force which is equal to the static friction force, if

fs is the static frictional force and the us is the static friction coefficient and Fn is the normal force

[tex]f_{s}[/tex] = us*Fn

Fn = mg

putting the appropriate values, we get

=  71/(29*9.8) = 71/284.2

= 0.2498 = 0.25

Now, similarly when body is in motion, kinetic frictional force is applied, so we can write

[tex]f_{k}[/tex] = uk*Fn

so putting the appropriate values, we get

= 50/mg = 50/284.2 = 0.1759

= 0.176

Hence the value of coefficient of static friction is 0.25 and the value of coefficient of kinetic friction is 0.176.

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The linear speed of the basketball at the bottom in m/s is 37.41 m/s.

The mechanical energy basket ball is conserved and the basket ball starts from rest. and roll down a hill of height 70m.

If mechanical energy is conserved,

Potential energy at top + kinetic energy at top = potential energy at bottom + kinetic energy at bottom.

At bottom, there is no potential energy, and at top, there is no kinetic energy.

Potential energy at top = kinetic energy at bottom.

Mgh = 1/2Mv²

M is the mass of the basketball,

v is the linear speed at the bottom,

h is the height of the ball.

Putting values,

v = √(2gh)

v = √(2x10x70)

v = 37.41m/s.

The speed of the basketball at the bottom is 37.41 /s.

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Using the concepts of motion, we got that Ma is the force exerted on the  passengers inside the car when a  car traveling with a constant velocity quickly comes to rest.

We know very well that according to newton second law of motion,

if a moving object is moving with some velocity v at any particular time t, then there is force acting on that object and that force is given by

F= dp /dt,

where dp is defines as change in momentum of the object. In other words,

dp=M×([tex]v_f_i_n_a_l[/tex] - [tex]v_i_n_i_t_i_a_l[/tex])

where [tex]v_f_i_n_a_l[/tex] and v[tex]_i_n_i_t_i_a_l[/tex] are the velocities of the object in different time.

So suppose car has some mass M kg

It is given that final velocity of the object is =0 as the car comes to rest,

suppose initial velocity is v

Therefore, F=[M×(0-v)]/t

=>              F= -M×(v/t)

=>              F= -Ma because acceleration =velocity/time

Here negative sign shows that force acts on the person in opposite direction of frictional force applied by the road.

Hence, when a car traveling with a constant velocity quickly comes to rest. while slowing down, the passengers inside the car are pushed forward by the force - Ma.

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acceleration of the earth due to jupiter's gravitational attraction at their average separation Is 246590.053 metre/sec²

Acceleration due to gravity is the acceleration gained by an object due to gravitational force. Its SI unit is m/s 2. It has both magnitude and direction, hence, it’s a vector quantity. Acceleration due to gravity is represented by g.

Enter the mass, radius and “x” for the unknown value in the respective input field

Now click the button “Calculate the Unknown” to get the acceleration due to gravity

Finally, the gravitational acceleration will be displayed in the output field.

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0.88m to the left, where the 4.0 kg cat must be to keep the seesaw balanced.

The concept of Torque and the principle of moment are applied here to understand that the 4.0 kg cat and the bowl of tuna fish will balance the seesaw as long as the 4.0 kg cat stays on the left of the pivot.

m (big cat) = 5.4 kg

m (bowl) = 2.4 kg

m (small cat) = 4.0 kg

From the figure,

5.4 kg x (x m) = 2.4kg x (2m)

x = 4.8 / 5.4

=> 0.88m

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By using simple harmonic motion, it can be calculated that The fundamental frequency of the string will be 45Hz.

The wavelength of the standing wave for any given harmonic is related to the length of the string.

Considering the wavelength is equal to the length of the string. It means one wavelength is equal to the length of the string. If more wavelength is made then answer would be different.

so we have wavelength = 1m

wave speed = 45 m/s

as we know that from simple harmonic motion,

frequency = speed/wavelength

frequency = 45/1

frequency = 45 Hz

Hence frequency of the string is 45 Hz.

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The parallel component of the total weight is 320 N.

The perpendicular component of the total weight is 554.3 N.

The components of the total weight of the builder and new roof tiles can be parallel component or perpendicular component.

The parallel component of the total weight of the builder and new roof tiles is calculated as follows;

Fn ( parallel ) =  W sin ( θ )

where;

Fn ( parallel ) =  W sin ( θ )

Fn ( parallel ) =  640 sin ( 30 )

Fn ( parallel ) = 320 N

The perpendicular component of the total weight of the builder and new roof tiles is calculated as follows;

Fn ( parallel ) =  W cos ( θ )

where;

Fn ( perpendicular ) =  W cos ( θ )

Fn ( perpendicular ) =  640 cos ( 30 )

Fn ( perpendicular ) = 554.3 N

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75 lbs/in^2 is the value of pressure. The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure.

In the physical sciences, pressure is defined as the stress at a point within a confined fluid or the perpendicular force per unit area.

The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure. In comparison to the surrounding pressure, gauge pressure is the pressure. Pressure is expressed using a variety of units.

P1V1=P2V2

The amount of force applied to a certain region is referred to as pressure. Absolute pressure, gauge pressure, and differential pressure are the three categories into which pressure is divided.

The distance between that point and the surface, the liquid's density. Gravitational acceleration are the factors of pressure.

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On a wet road, a higher coefficient of friction on the tires is safer as compared to a lower coefficient of friction.

Friction is defined as a force that resists the sliding or rolling of one object over another object. The coefficient of friction refers to a measure of the amount of friction present between two surfaces. When you calculate a coefficient of friction, you're calculating the resistance to motion at the interface of two surfaces of materials.

On dry surfaces, you have a high coefficient of friction of about 0.9, but driving on wet roads would be dangerous because the wet road coefficient is very low about 0.1.

So we can conclude that a higher coefficient of friction is recommended for a safe journey.

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Permanent dipoles are created by the interaction of permanent charges, which are charges that do not lose their charge when they are separated, as opposed to temporary dipoles, which form when two unlike poles come into contact and then separate.

Permanent dipoles are strong; they can be formed even when there is no electrical current present. The strength of a permanent dipole depends on its size and intensity, but it's typically much stronger than a temporary dipole.

Dispersion forces are weaker than both permanent dipoles and temporary dipoles. They can be generated by any two objects whose surfaces have different charges, regardless of whether there is an electrical current present or not.

The strength of dispersion forces depends on the size and intensity of the charged object, but it's typically much weaker than a permanent or temporary dipole.

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A linear track beings at 0 meters and has a total distance of 100 meters, then she will go 55 meters. Hence, option D is correct.

The pace at which the distance a moving item travels changes is measured as speed. Since speed is a scalar, it has quantity but no orientation as a unit of measurement.

Let A represent Juliet's position. O is the starting point with OA = 10, AB = 45, and OP = 100 as its coordinates.

The location of Juliet following running 45 meters will therefore be 55 m, as may be seen from simple math. In the figure, it is OB.

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Your question is not complete, your question probably be :

A linear track begins at 0 meters and has a total distance of 100 meters to the finish line. Juliet starts at the 10-meter mar

while practicing for a race.

After running 45 meters, how far is she from the beginning of the track?

10 meters

35 meters

45 meters

55 meters

With the aid of your spectroscope and E = (h*c)/wavelength, you can determine the energy of the emitted light to be 3.97 x 10-19.

mathematical representation The movement v (in the x direction), frequency f, and wavelength of traveling sinusoidal waves are frequently expressed mathematically as follows: where y is the value of the wave at any place x and time t, and A is the wave's amplitude.

The symbol for the wavelength in the SI is typically m, or one metre. The multiples or fractions of something like a meter are also employed for measuring wavelength. Notably, when wavelengths are a significant attribute, exponential powers of 10 are employed. Shorter wavelengths are given as negative exponentials.

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Answer:

Approximately [tex]0.033\; {\rm m\cdot min^{-1}}[/tex] (meters per minute.)

Explanation:

Let [tex]A[/tex] and [tex]B[/tex] denote the bottom and top width of the trough, respectively. It is given that [tex]A = 30\; {\rm cm} = 0.30\; {\rm m}[/tex] and [tex]B = 80\; {\rm cm} = 0.80\; {\rm m}[/tex]. Let [tex]H[/tex] denote the height of this trough; [tex]H = 50\; {\rm cm} = 0.50\; {\rm m}[/tex].

Let [tex]h[/tex] denote the current depth of the water in this trough.

Let [tex]b[/tex] denote the current width of the surface of the water. As water fills the trough, this width increases from [tex]A = 0.30\; {\rm m}[/tex] (width of bottom of trough) to [tex]B = 0.80\; {\rm m}[/tex] (width of top of trough.)

The relationship between [tex]b[/tex] and [tex]h[/tex] is linear:

[tex]\displaystyle b = \frac{h}{H}\, (B - A) + A[/tex].

Cross-section area of water in this trough:

[tex]\begin{aligned}(\text{area}) &= \frac{1}{2}\, (A + b) \, h \\ &= \frac{1}{2}\, \left(A + \frac{h}{H}\, (B - A) + A\right)\, h \\ &= A\, h + \frac{1}{2\, H} (B - A)\, h^{2}\end{aligned}[/tex].

Let [tex]L[/tex] denote the length of this trough; [tex]L = 10\; {\rm m}[/tex].

Let [tex]v[/tex] denote the volume of water in this trough:

[tex]\begin{aligned}v &= (\text{area})\, L \\ &= \frac{1}{2}\, (A + b) \, h\, L \\ &= \frac{1}{2}\, \left(A + \frac{h}{H}\, (B - A) + A\right)\, h\, L \\ &= A\, L\, h + \frac{L}{2\, H} (B - A)\, h^{2}\end{aligned}[/tex].

Differentiate both sides implicitly with respect to [tex]v[/tex]:

[tex]\displaystyle \frac{d}{dv}[v] = \frac{d}{dv}\left[A\, L\, h + \frac{L}{2\, H}\, (B - A)\, h^{2}\right][/tex].

[tex]\displaystyle \frac{d}{dv}[v] = \frac{d}{dv}[A\, L\, h] + \frac{d}{dv}\left[\frac{L}{2\, H}\, (B - A)\, h^{2}\right][/tex].

[tex]\displaystyle 1 = A\, L\, \frac{dh}{dv} + \frac{L}{2\, H}\, (B - A)\, 2\, h\, \frac{dh}{dv}[/tex].

(Note that [tex]A[/tex], [tex]B[/tex], [tex]L[/tex], and [tex]H[/tex] are constants.)

Rearrange this equation to obtain:

[tex]\displaystyle 1 = A\, L\, \frac{dh}{dv} + \frac{L}{H}\, (B - A)\, h\, \frac{dh}{dv}[/tex].

[tex]\displaystyle 1 = \left(A\, L + \frac{L}{H}\, (B - A)\, h \right)\, \frac{dh}{dv}[/tex].

[tex]\displaystyle \frac{dh}{dv} = \frac{1}{\displaystyle A\, L + \frac{L}{H}\, (B - A)\, h}[/tex].

Let [tex]t[/tex] denote time. It is given that the trough is being filled at a rate of [tex]0.2\; {\rm m^{3}\cdot min^{-1}}[/tex]. In other words:

[tex]\displaystyle \frac{dv}{dt} = 0.2\; {\rm m^{3}\cdot min^{-1}}[/tex].

Apply the chain rule to find the rate at which [tex]h[/tex] is changing with respect to time [tex]t[/tex]:

[tex]\begin{aligned} \frac{dh}{dt} &= \frac{dh}{dv}\cdot \frac{dv}{dt} \\ &= \frac{1}{\displaystyle A\, L + \frac{L}{H}\, (B - A)\, h}\cdot \frac{dv}{dt} \end{aligned}[/tex].

Substitute in [tex]A = 0.30\; {\rm m}[/tex], [tex]L = 10\; {\rm m}[/tex], [tex]H = 0.50\; {\rm m}[/tex], [tex]B = 0.80\; {\rm m}[/tex], [tex]h = 0.30\; {\rm m}[/tex] (converted from [tex]30\; {\rm cm}[/tex]), and that the rate of change in [tex]v[/tex] is [tex]0.2\; {\rm m^{3}\cdot min^{-1}}[/tex]:

[tex]\begin{aligned} \frac{dh}{dt} &= \frac{dh}{dv}\cdot \frac{dv}{dt} \\ &= \frac{1}{\displaystyle A\, L + \frac{L}{H}\, (B - A)\, h}\cdot \frac{dv}{dt} \\ &= \frac{0.2\; {\rm m^{3}\cdot min^{-1}}}{\displaystyle 0.30\; {\rm m} \times 10\; {\rm m} + \frac{10\; {\rm m}}{0.60\; {\rm m}}\, (0.80\; {\rm m} - 0.30\; {\rm m}) \, 0.30\; {\rm m}} \\ &=0.033\; {\rm m\cdot min^{-1}} \end{aligned}[/tex].

In other words, the depth of the water in this trough increases at a rate of approximately [tex]0.033\; {\rm m \cdot min^{-1}}[/tex] (meters per minute.)

It is true that clausius statement of the second law states that energy cannot go spontaneously from a colder to a hotter body.

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If I increases the string length, the frequency will decreases and vise versa.

In physics, frequency is the number of waves that pass a fixed point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time.

For string wave, we know that,

frequency, n = [tex]\frac{1}{lD}[/tex][tex]\sqrt{\frac{T}{\pi \rho} }[/tex]

where, l = length of the string.

D = diameter.

T = tension

ρ = density of the material.

Hence, we can see that, frequency of the wave is inversely proportional to the length of the wire. So, on increasing string length, frequency of the wave will decreases.

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In fast-moving water only coarse material settles out and fine material is carried away. In slow-moving water only fine material, which can settle out.

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Answer:

F = M a        Newton's Second Law

The person is undergoing no acceleration, thus the upwards force of the earth on the person exactly balances the attraction of the earth on the person's center of gravity

(Also, Newton's third law that for every action there is an opposite and equal reaction}

Answer:

To say we have a 12.0-V battery implies that its terminals have a 12.0-V likely contrast. At the point when such a battery moves charge, it puts the charge through an expected distinction of 12.0 V, and the charge is given an adjustment of potential energy equivalent to Δ U = q Δ V .

six cells

There are six cells to a 12 volt lead corrosive battery. A battery cell's greatest capacity to convey current (amps).

A 6 cell lithium particle pack has an ostensible voltage of 21.6V to 22.2V and a most extreme charge voltage of 25.2 volts

Explanation:

The instantaneous magnitude of the poynting vector will be 518.48.

To calculated magnitude of the poynting vector, we require to use the formula of poynting vector

S = E*B/u

since B = E/c

so , S = E^2 /uc

where , E is the electric field and B is the magnetic field ,

S is the poynting vector magnitude and c is the speed of light.

Putting the values, we get

S = (442x442) /uc

S =  195364 / uc

uc = 4πx[tex]10^{-7}[/tex] x 3 x [tex]10^{8}[/tex]

uc = 376.8

Now, S = 195364/376.8

S = 518.48

Hence The instantaneous magnitude of the poynting is 518.48.

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Things which will be attracted to (or repelled by) a magnet are

An iron pipe

A negatively charged piece of silver

An aluminum wire carrying current

According to the "rule of attraction of magnets," magnets will attract one another when their south poles are brought near together. According to the "rule of magnet repulsion," magnets repel one another when their respective north poles are brought close to one another.

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Answer:

the answer should be: An Electromagnet, An Iron Pipe, and An Aluminum Wire Carrying Current

Explanation:

took the test

The quarterback is located 0.3v above ground. The fundamental element of every projectile's body that is moving is its horizontal velocity (vx).

The fundamental element of every projectile's body that is moving is its horizontal velocity (vx). In any projectile motion, it is typically utilized to know the velocity value at which the particle travels along the horizontal direction. It's even thought of as the body's starting point for movement.

Let's say the projectile-moving particle reaches the highest point of its horizontal path. In that case, the horizontal velocity will typically be zero since the force of gravity will cause it to fall vertically downward as soon as it reaches the peak point. Vertical velocity has no impact on this horizontal velocity when it is at its highest point.

Let the horizontal velocity of the object = v

X = vt

X = 0.3v

Thus, The quarterback is located 0.3v above ground.

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Both graphs of energy are attached in the answer.

The ability of a body to do tasks may be referred to as energy. The joule is the SI unit of energy (J). or 1 kJ Equals 1000 J. energy guises: Potential energy, kinetic energy, thermal energy, chemical energy, and light energy are some of the several types.

Potential energy of a man due to gravity can be express as = mass × acceleration due to gravity × height.

Hence, graph, that shows potential energy of a firefighter slides through the vertical pipe with length, will be linearly decreasing type.

As, total energy is conserved, graph, that shows kinetic energy of a firefighter slides through the vertical pipe with length, will be linearly increasing type.

Graphical representation of both linearly increasing and linearly decreasing is attached here.

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Answer:its b

Explanation: i took the test

The given statement is true. A lunar eclipse happens when the Moon passes into the shadow of the Earth. A solar eclipse happens when the Moon passes between Earth and the Sun.

A lunar eclipse happens when the Moon passes into the shadow of the Earth. This is only possible when the Sun, Earth, and Moon are precisely or extremely closely aligned with Earth between the other two, which can happen only on a full moon night when the Moon is close to either lunar node.

A solar eclipse happens when the Moon passes between Earth and the Sun, completely or partially blocking Earth's view of the Sun. A new moon corresponds with such an alignment, showing that the Moon is closest to the plane of the Earth's orbit. The Moon completely obscures the disk of the Sun during a total eclipse.

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The given statement is true. A lunar eclipse happens when the Moon passes into the shadow of the Earth. A solar eclipse happens when the Moon passes between Earth and the Sun.

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Capacitance, charge and electric potential will be greater than the capacitor without the dielectric.

Capacitance is the a property of an electric conductor or set of conductors that is measured by the amount of separate electric charge that can be stored on it per unit change in electric potential.

The value of capacitance for the parallel plate is C = (3∈0AK)/d

Since two identical, parallel-plate capacitors are connected

therefore the value of capacitance for both the plate is C

Ceq. = (C1*C2) / C1 + C2 = C*C / C+C = C2

When the battery remains connected, the potential difference [V] remains constant

Q=CV

∴Cafter>Cbefore [C increased]

∴Qafter>QBefore [Q increased]

Potential difference and charge across the capacitor before the dielectric:

Qbefore = [tex]\frac{CV}{2}[/tex]

Vbefore = Vafter = V

Potential difference and charge on the capacitor after inserting the dielectric:

Qafter = Ceq*V = [tex]\frac{kCV}{k+1}[/tex]

Vafter = Q*After / KC =  [tex]\frac{\frac{kCV}{k+1}}{kc}[/tex]

Vafter=  [tex]\frac{V}{k+1}[/tex]   [K>1]

[Hence V decreases]

Vbefore > Vafter

Also,  E = [tex]\frac{V}{d}[/tex]

therefore [E]before > [E]after [E decreases]

Energy stored in the capacitor:-

U=[tex]\frac{1}{2} CV^{2}[/tex]

As V= constant

Cafter > Cbefore .

Hence Uafter > Ubefore

Thus, the electrostatic potential increases.

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