0.218 m/s speed does he move toward the ship.
use the formula from conservation of Momentum
mu + MV = (m-M)V'
u = o
so
MV = (m-M)V'
V' = (1.5 * 10)/(70-1.5)
V' = 0.218 m/s
What is speed?The most crucial scientific notion is measurement. Base or physical fundamental units are used to quantify a wide range of quantifiable quantities. One such measurable metric is speed, which calculates the ratio between the distance an object travels and the time needed to cover that distance. Let's explore speed in-depth in this session.
The distance traveled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity.
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what is the purpose of the frets on a guitar. in terms of the frequency of the vibration of the strings
To learn frequency to known frequency and frets of guitar.
What is frequency?
The number of waves that pass a fixed point in a unit of time is referred to as frequency in physics. It also describes how many vibrations or cycles a body in periodic motion makes in a given amount of time.
What is the purpose of frets?
Frets, which determine the positions for the proper notes, make it much simpler for a player to achieve an acceptable standard of intonation. Furthermore, playing chords accurately is made simpler by a fretted fingerboard.
Frequency of the vibrations of the strings.
f=2LnmT, where T is the tension in the string, L is the length, and n is the number of harmonics, gives the frequency of vibration of a string.
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a mass m is attached to an ideal massless spring. when this system is set in motion with amplitude a, it has a period t. how does the period of the motion change if the amplitude of the motion is increased to 2a? explain.
System is set in motion with an amplitude of a and a period of T. If the amplitude of the motion is increased to 2a, the period of the motion changes.
A straightforward harmonic oscillator's period is independent of its amplitude. with the graphs of acceleration and velocity produced by the time derivatives. These oscillators also show how kinetic and potential energy can be transferred.
The acceleration of the mass increases proportionally with the increase in force, causing the mass to travel farther in the same amount of time. Therefore, increasing the amplitude has no overall impact on the oscillation's period.
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the hydrogen in a star emits light at 484 nm as observed by an astronomer. which describes the motion of the star if the laboratory value of this spectral line of hydrogen is measured at 486 nm? question 9 options: approaching at 6.17 105 m/s moving away at 6.17 105 m/s approaching at 1.23 106 m/s moving away at 1.23 106 m/s
If the laboratory value of this hydrogen spectral line is detected at 486 nm, the star is moving toward us at a speed of 6.17 105 m/s.
How might Bohr's theory explain the hydrogen spectrum?In less than a year, Niels Bohr had a hydrogen atom model that "explained" the spectral lines. The energy level was a novel idea that Bohr introduced. Sharp spectral lines were released when an electron in hydrogen moved from one of its permitted energy levels, which were defined by the hydrogen atom.The wavelengths, measured from the scale, are 435 nm (purple), 486 nm (blue), and 657 nm (red).Hydrogen has numerous different energy levels while having just one electron. A photon is released when an electron in an object jumps from one energy level to another. Due to the various levels, those photons produce light with various colors and wavelengths.To learn more about Hydrogen atom model refer to:
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Which variable is NOT shown on a velocity-time graph?
Acceleration is the variable that is NOT shown on a velocity-time graph
Velocity - time graph, evidently shows two variables, velocity on one axis and time on other . But as we know , that acceleration can be calculated by the formula which is
acceleration = change in velocity / time
hence , the derivative of velocity is acceleration
which mean that the slope of the Velocity - time graph shows the acceleration , which cannot be seen , but is hidden as the slope of that graph
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four resistors having a value of 100 ohms each are connected in parallel. what is the total resistance of the circuit?
The total resistance of the circuit is 25 ohms.
How can the resistance of a circuit with four resistors in parallel be determined?In the same way, if three or more resistors of the same value are connected in parallel, the equivalent resistance will be equal to R/n, where R is the resistor's value and n is the total number of resistors in the arrangement.
How do you calculate a parallel resistor's total resistance?The total current flowing from the source is the sum of the currents through each of the paths. Using the following formula, you can get the overall resistance in a parallel circuit: 1/Rt = 1/R1 + 1/R2 + 1/R3 +... Even if one of the parallel channels breaks, current will still flow.
[tex]R_{total}[/tex] = 100/4 = 25ohms
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a flight attendant pulls her 2 kg flight bag a distance of 23 m along a level airport floor at a constant velocity. the force she exerts is 8 n at an angle of 30 degrees above the horizontal. find the work she does on the flight bag.
Work done on the flight bag will be 182.20 J.
Work done defined as the product of force and distance covered due to applied force.
The mass of flight bag m = 2 kg
Therefore the weight of the bag will be 2*g = 2*10 = 20 N
(g = acceleration due to gravity = 9.81 m/s2)
The distance covered by the bag is, d = 23 m.
The magnitude of force exerted on bag is, F = 8 N.
The angle of inclination with horizontal = [tex]\alpha[/tex] = 8°
The work done on the flight bag is given by the equation:
W = F * d *Cos [tex]\alpha[/tex]
W = 8 * 23 * Cos8
W = 182.20 J
Thus, the work done by the attendant on the flight bag is 182.20 J.
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a multimeter is used for? select one: a. frequency testing of coaxial cable b. general electrical measurements c. testing the bandwidth of all types of cables d. testing continuity of fiber optic cable
A multimeter is used for general electrical measurements. So, the correct option is (b)
What is a multimeter?A multimeter is an electronic measuring device that combines multiple measurement functions into one device. A typical multimeter include features such as the ability to measure voltage, current, and resistance.
Most multimeters have the ability to test circuit continuity. This makes it easier to find faults such as bad cables. It also helps to see if two points in the circuit are connected.
The typical multimeter can measure voltage, resistance, and current. In this case, the device is also called a Volt-Ohm Milliammeter (VOM), since it has the functions of a voltmeter, an ammeter, and an ohmmeter. Some of them even offer measurements of additional properties such as temperature and capacitance.
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Highlight (1) calculator
Species
0 0
Harbor seals live off the coast of New England and feed on various fish, squid, shrimp, and other marine life. A sea
approaches a school of fish consisting of mackerel, herring, and harbor pollock. The population of each species is
shown in the table.
mackerel
herring
harbor pollock
What is the probability the seal catches a mackerel?
You may use the calculator.
25%
20%
15%
33%
Elag for Review Normal Color Scheme
Population
15
23
37
There is 20% probability that the seal catches a mackerel.
What is probability?How likely something is to occur is known as its probability.
To determine probability, divide the total number of possible outcomes by the number of possible ways an event could occur. There are differences between probability and odds. Odds are calculated by dividing a situation's likelihood of occurring by its likelihood of not occurring.
Given,
mackerel 15
herring 23
harbor pollock 37
probability = possible event/ no. of event
probability = 15/ 15+23+37
probability = 15/ 75
probability = 0.2
∴ probability is 20%
For numbers less than 1 out of 1,000 (such as 0.20 out of 1,000), it is clearer to recast them as “200 out of 10,000” (“2 out of 10,000,” for instance).
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if we could put all the asteroids in the asteroid belt together, their total mass would be .
If we could place all the asteroids collectively, their general mass would be much less than the mass of any terrestrial planet.
The whole mass of the asteroid belt is expected to be 2.39×1021 kg, which is just three% of the mass of the Moon. The 4 biggest items, Ceres, Vesta, Pallas, and Hygiea, account for perhaps 62% of the belt's total mass, with 39% accounted for by way of Ceres on my own. Gravitational tugs from Jupiter avoided fabric from accumulating collectively to shape a planet.
The 4 biggest asteroids inside the belt are known as Ceres, Vesta, Pallas, and Hygiea. these huge asteroids make up about half of the mass of the complete asteroid belt. Scientists like to mention that in case you blended all of those rocky asteroids collectively, it might make a planet a piece smaller than Earth's moon.
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what would her speed be at 490 m ? (in reality, the air resistance will restrict her speed to perhaps 150 km/h .)
She will pull her ripcord 22.9 s after the dive and her speed at 490 m will be 112.66 m/s.
What is free-fall?Free fall, any motion of a object where gravity is the only force acting upon it. In the context of general relativity, where gravity is reduced to the curvature of spacetime, there are no forces acting on bodies in free fall.
For the given case,
s = ut + 1/2 at²
s = Displacement (3000 - 420 = 2580 m) it is the distance she will free fall
a = Acceleration due to gravity (9.8 m/s²)
u = Initial velocity (0 m/s)
t = Time taken
2580 = 0×t + 1/2 9.8 t²
2580 = 4.9 t²
t = 22.9 s
Now her speed at 490 m will be
v = d/t
v = speed
d = 2580 m
t = 22.9 s
v = 2580/22.9
v = 112.66 m/s
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The given question is incomplete so the complete question is as follows:
"if there were no air resistance, how long would it take a free-falling skydiver to fall from a plane at 3100 m to an altitude of 490 m , where she will pull her ripcord? what would her speed be at 490 m ? (in reality, the air resistance will restrict her speed to perhaps 150 km/h)"
a 3 kg block starts from rest at the top of a 30 degree incline and slides a distance of 2 m down the incline in 1.50 seconds. find the magnitude of the acceleration of the block. find the coefficient of kinetic friction between the block and the ramp.
The magnitude of the acceleration of the block is 1.78m/s².
The coefficient of kinetic friction between the block and the ramp is 0.368.
How can I calculate the coefficient of kinetic friction?The resistive force of friction (Fr), which pushes the objects together, is divided by the normal or perpendicular force (N), which pushes them apart, to produce the coefficient of friction (fr), which is a numerical value. The following formula represents it: fr = Fr/N.
Given,
m=3.00kg, θ=30° ,
x= 2.00m, t=1.50s.
constant rate of acceleration,
[tex]X_{f} = v_{i} t[/tex] + 1/2at²
solving,
a = 2([tex]X_{f}[/tex]-[tex]v_{i} t[/tex])/t²
a = 2(2-0)/(1.5)²
a = 1.78m/s².
We have neither a burrowing-in nor a taking-off action when Newton's law is applied in the y direction, which is perpendicular to the inclination. The y component of acceleration is then equal to zero:
∑ [tex]F_{y}[/tex]=n–mgcosθ=0
Thus n=mgcosθ
Because f=[tex]\mu_{k}[/tex]n
[tex]\mu_{k}[/tex] = f/mgcosθ
[tex]\mu_{k}[/tex] = 9.37/3×9.8×cos30°
[tex]\mu_{k}[/tex] = 0.368.
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Compare the use of an electric bicycle with a normal bicycle used
to cycle a 5 km uphill route. The cyclist does not pedal when using
the electric bike to cycle uphill.
Information about the two bikes is given in Table 1.
Table 1
Information
power of the motor
force used to drive the
bicycle forward
weight of bicycle
battery life
time to travel 5 km
Electric bicycle
350 W
50 N
190 N
25 minutes
12 minutes
Ordinary bicycle
no motor
47 N
120 N
no battery
13 minutes
Your answer should contain descriptions of work done, energy
transfers, and power.
The work done by the ordinary and electric bicycle are 235 KJ and 250 KJ respectively and the output power of ordinary and electric bicycle are 0.3 KW and 0.35 KW respectively.
W = F d cos θ
P = W / t
W = Work done
F = Force
d = Distance
P = Power
t = Time
θ = 0
d = 5 km = 5000 m
For Electric bicycle
F = 50 N
t = 12 min = 720 s
W = 50 * 5000 * cos 0
W = 250000 J
W = 250 KJ
P = 250 / 720
P = 0.35 KW
For ordinary bicycle,
F = 47 N
t = 13 min = 780 s
W = 47 * 5000 * cos 0
W = 235000 J
W = 235 KJ
P = 235 / 780
P = 0.3 KW
Therefore, the work done by the ordinary and electric bicycle are 235 KJ and 250 KJ respectively and the output power of ordinary and electric bicycle are 0.3 KW and 0.35 KW respectively.
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a horizontal spring with spring constant 250 nv/m is compressed 12 cm and used to launch a 250 g box across the floor. the coefficient of kinetic friction between the box and the floor is 0.23. what is the box's launch speed?
Therefore, the lunch speed of the box is 3.72m/s
What is kinetic friction ?
Kinetic friction is a force that exists between moving surfaces. A body moving on the surface is subjected to a force that is directed in the opposite direction of its movement. The size of the force is determined by the kinetic friction coefficient of the two materials.
Friction is simply the force that holds a sliding object back. Kinetic friction is present in everything and interferes with the motion of two or more objects. The force acts in the opposite direction of the object's desire to slide.
The integration of force due to spring with respect to spring is equal to the potential energy of the spring.
U=∫-Fdx
Here, U is the potential energy.
U= 1/2k[tex]x^{2}[/tex]
U= 1.8J
The final kinetic energy of the box is,
K= 1/2m[tex]v^{2}[/tex]
v=3.72m/s
The system's total potential energy equals the work done owing to kinetic friction. Using the law of conservation of energy, the sum of the energies obtained before compressing the spring equals the sum of energies obtained after expanding the spring.
Therefore, the lunch speed of the box is 3.72m/s
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a 1500 kg vehicle is traveling on a curved, icy road. the road is banked at an angle of 10.0 degrees and has a radius of curvature of 400 m. the velocity of the car necessary to travel on the icy road without sliding is .
The vehicle speed required to drive on an icy road without sliding is 28.3 m/s.
The weight of the car is m = 1500 kg
The angle at which the road is inclined is θ = 10
The radius of curvature is r = 400m
The expression for the speed of the car required to travel on the road without sliding is V =[tex]\sqrt{rgtan}[/tex]
V =[tex]\sqrt{400*9.8*tan10}[/tex]
V = 28.3 m/s
Velocity is the rate of change in direction of an object in motion measured by a specific time standard and observed from a specific reference point (for example, 60 km/h north). A key idea in kinematics, the branch of classical mechanics that studies the motion of bodies, is velocity.
The definition of velocity requires both its magnitude and its direction, since it is a physical vector quantity. Velocity is a coherently derived unit that is measured in the SI (metric system) as meters per second (m/s or m/s1). Velocity is a scalar absolute value (magnitude) of speed.
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a migrating robin flies due north with a speed of 12 m/s relative to the air. the air moves due east with a speed of 6.3 m/s relative to the ground.what is the robin's speed relative to the ground?
The robin's speed relative to the ground 62.3 degrees north of east, or tan(12/6.3).
How to calculate the speed relative to the ground?Think about the X-east-west axis's direction and the Y-north-south axis's direction.
V ra = 12 j m/s is the speed of a migratory robin relative to the air.
(In which "j" denotes a unit vector in the Y direction)
V ag = air speed in relation to the ground = 6.3 I m/s
(Where I is an X-direction unit vector)
V rg = speed of migratory robin in relation to the ground =
utilizing the formula
V rg = V ra + V ag
= 12 j + 6.3 I
= 6.3 I + 12 j
magnitude: (13.6 m/s = sqrt[tex](6.3)^{2}[/tex] + ([tex](12)^{2}[/tex])
direction: 62.3 degrees north of east, or tan(12/6.3).
The robin's speed relative to the ground 62.3 degrees north of east, or tan(12/6.3).
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If the man pulls the sled with a 10 N
force, what is the horizontal component
of force? Refer to chapter 4, mechanics if
you do not remember how to resolve a
force into its components.
Answer:
Explanation:
The horizontal component of force is Fcosθ if the man pulls the sled with a 10 N force. Force has both a magnitude and a direction since it is a vector quantity.
What is force?A force is an external cause that, when applied, alters or has the potential to alter a body's condition. The body comes to rest while it is moving, and it moves when it is at rest.
The body's orientation, form, size, etc. may also alter as a result. An illustration would be to push or forcefully shove a door. Force has both a magnitude and a direction since it is a vector quantity. If the man pulls the sled with a 10 N force then the horizontal component of force is Fcosθ. Your training at this level should place a major emphasis on the idea that a push or even a pull was referred to as an force.
Therefore, the horizontal component of force is Fcosθ if If the man pulls the sled with a 10 N force.
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consider a 20 kg sphere with a 10 cm radius. what weight would a scale read if the sphere was totally submerged in water?
The weight the scale would read if the sphere of mass 20 kg with a 10 cm radius was totally submerged in water is 155.1 N
Fg = m g
Fb = ρ V g
Fg = Force of gravity
Fb = Buoyant force
m = Mass
g = Acceleration due to gravity
ρ = Density of medium
V = Volume of object
m = 20 kg
g = 9.8 m / s²
ρ = 1000 kg / m³
r = 10 cm = 0.1 m
Fg = 20 * 9.81
Fg = 196.2 N
Fb = ρ ( 4 / 3 π r³ ) g
Fb = 1000 * 4 / 3 * 3.14 * 0.1³ * 9.8
Fb = 41.1 N
N = Fg - Fb
N = Scale reading
N = 196.2 - 41.1
N = 155.1 N
Therefore, the scale reading if the sphere was totally submerged in water is 155.1 N
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Stan argues that momentum cannot be conserved when a collision is not a head-on collision. Rachel insists it is conserved because each body receives an impulse of equal magnitude. Rachel is correct because.
Rachel is correct because she said that is body receive equal magnitude of impulse which completely satisfy the law of conservation of linear momentum.
According to law Conservation of Linear Momentum, if there is no external force working on the system, then the linear momentum remains conserved before and after the collision.
We know that,
Momentum is nothing but the product of force and the time taken for the contact period of the colliding bodies.
We assume that during the head on collision of the body, the body is remain in contact for such a short period of time that there is no external force all the impulse created due to the external force is neglected.
So, because the impulse imparted on both the bodies are equal to each other.
We know that impulse is nothing but the change in momentum.
So, from here we conclude that bodies received equal magnitude of impulse.
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The rising concern among athletic trainers and health advocates (and parents) regarding concussions and multiple concussions among high school football players has prompted numerous studies of the effectiveness of protective head gear and the forces and accelerations experienced by players. One study suggested that there is a 50% chance of concussions for impacts rated at 75 g's of acceleration (i.e., 75 multiplied by 9.8 m/s/s). The average head impact in football results in 22 to 24 g's of acceleration ... but not all head impacts are equal.
If a player's head mass (with helmet) is 5.41 kg and considered to be a free body, then what net force would be required to produce an acceleration of 75 g's?
Answer:
Explanation:
Given:
m = 5.41 kg
g = 9.8 m/s² - acceleration of gravity
a = 75·g = 75·9.8 ≈ 735 m/s²
__________________
F - ?
Newton's second law:
F = m·a
F = 5.41·735 ≈ 3 980 N
If you know the acceleration and time, how can you calculate the average velocity?.
The average velocity in terms of acceleration and time is 1/2at².
Average velocity:
Velocity is the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.
Assume the acceleration a is uniform then:
v(t) = u + at
u = initial velocity
By average velocity v we mean average over time than strictly speaking:
v = 1/t [tex]\int\limits^t_0 {v(t)} \, dt[/tex]
= 1/t [tex]\int\limits^t_0 {(u + at)} \, dt[/tex]
= 1/t ( ut + 1/2 at²)
v = u + 1/2at²
If u =0, then we have
v = 1/2 at²
Therefore the average velocity is 1/2at².
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what is the speed of the 0.100 kg sphere when it has moved 0.400 m to the right from its initial position?
6.01 × 10⁻⁵ m/s is speed of 0.100 kg sphere when it has moved 0.400 m to right from its initial position.
What is conservation of energy?The conservation of energy principle states that in a closed system, the energy of interacting objects or particles remains constant. Kinetic energy, sometimes known as the energy of motion, was the first type of energy to be identified. The sum of the kinetic energy of the particles before collision and the sum of the kinetic energy of the particles after collision are equal in some particle collisions, known as elastic collisions. Progressively, more types of energy were added to the definition of energy.
We have from the conservation of energy,
[tex]E_{i}[/tex] = [tex]E_{f}[/tex]
[tex]E_{i}[/tex] = [tex]\frac{-G(5*0.1)}{0.4}[/tex] - [tex]\frac{G(10*0.1)}{0.6}[/tex]
[tex]E_{i}[/tex] = [tex]\frac{-G(5*0.1)}{0.8}[/tex] - [tex]\frac{G(10*0.1)}{0.2}[/tex] + 1/2 × 0.1v²
∵ [tex]E_{i}[/tex] = [tex]E_{f}[/tex]
= 1/2 × 0.1 × v² = G (5×0.1) (1/0.8 - 1/0.4) + G (10 × 0.1) (1/0.2 - 1/0.6)
∴ v = 6.01 × 10⁻⁵ m/s
Speed of the object moved from its initial position is 6.01 × 10⁻⁵ m/s.
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everyday application: suppose a yo-yo has a center shaft that has a 0.250 cm radius and that its string is being pulled. (a) if the string is stationary and the yo-yo accelerates away from it at a rate of , what is the angular acceleration of the yo-yo? (b) what is the angular velocity after 0.750 s if it starts from rest? (c) the outside radius of the yo-yo is 3.50 cm. what is the tangential acceleration of a point on its edge?
If it starts at rest, the angular velocity after 0.750 is 5.1. The symbol for angular velocity in SI units is s1.
Explain about the angular velocity?When an object rotates or circles around an axis, its angular velocity is the rate at which the angle between the two bodies changes. The angle that is made by a line on one body and a line on the other in the illustration represents this displacement.
Examples of angular velocity include a roulette ball on a wheel, a race car travelling in a circle, and a Ferris wheel. In addition, the object's angular displacement with respect to time is represented by the angular velocity of the object.
Since the radian is a dimensionless quantity and the SI unit of angular velocity is radians per second.
Angular acceleration
a = a /r
= 1.7/0.250
a =6.8
Angular velocity
omega = a*t
= 6.8 *0.75
=5.1
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How many g are in a pack containing 10 tablets of 500 mg each? *
5g
50g
100g
500g
Answer:
5 g
Explanation:
500 mg x 10 = 5000 mg
5000 x 10^-3 g = 5 g
Hello..!
To solve the problem and calculate the number of pills in the package, we will use the conversion factor.
The conversion factor or unit factor is a conversion method that is based on multiplying by one or more fractions where the numerator and denominator are equal quantities expressed in different units of measure, so that each fraction is equivalent to the unit.
Find out that 1 gram has a total of 1000 mg.
Problem:
How many g are in a carton containing 10 tablets of 500 mg each?
According to the previous text we can say that the conversion factor would be:
[tex] \: \: \: \: \: \qquad \qquad \large \sf\dfrac{1\ g}{1000\ mg}[/tex]
Now we must find out that the box has a total of 10 pills of 500 mg, so to know how many grams the box has we must know how many grams only one pill weighs:
[tex] \sf \qquad\boxed{\boxed{ \sf\large 500\ mg*\dfrac{1\ g}{1000\ mg}= 0.5\ g}}[/tex]
We know that a pill weighs 0.5 grams, now to calculate how many grams the box weighs we must multiply the total pills by the weight of just one pill:
[tex]\qquad \boxed{\boxed{ \sf\large 0.5\ g\times 10= 5\ g}}[/tex]
We conclude that one box contains 5 grams of tablet, option 1.
[tex]\begin{gathered}\rule{7cm}{0.01mm}\\\texttt{Good studies! :D}\\\rule{7cm}{0.01mm}\end{gathered}[/tex]
the frequency content of an analog signal to be digitized has a range roughly covering the range of the auditory system of a young child: 200 hz to 20,000 hz. for accurate sampling, what is the minimal sampling rate necessary for an a/d convertor?
For accurate sampling, -44.1khz is minimum sampling rate for an a/d convertor.
What is sampling rate?The number of samples per second (or other unit) taken from a continuous signal to form a discrete or digital signal. The sample rate or sample rate specifies the number of samples per second (or other unit). of a continuous signal to form a discrete or digital signal..
The sampling rate can be thought of as the audio version of frames per second. This is the number of "clips" taken from an analogue sound wave to make a digital file. In addition, the sample rate also controls the highest frequency that can be accurately reproduced by a digital file.
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An 0.8 kg cart rolls down a frictionless hill of height 0.32m. At the bottom of the holl the cart rolls on a flat surface., which exerts a frictional force if 2 n on the cart. How far does the cart roll on the flat surface before it comes to a stop
The distance travelled by the cart on the flat surface before it comes to a stop is 1.25 m.
What is the acceleration of the cart?
The acceleration of the cart is determined by applying Newton's second law of motion as shown below.
F = ma
a = F/m
a = 2 N / 0.8 kg
a = 2.5 m/s²
The velocity of the cart at the bottom of the hill is calculated as;
u = √2gh
u = √(2 x 9.8 x 0.32)
u = 2.5 m/s
The distance travelled by the cart before stopping;
v² = u² - 2as
where;
v is the final velocity of the cart = 0u is the initial velocity = 2.5 m/sa is the accelerations is the distance travelled2as = u²
s = u²/2a
s = (2.5²) / (2 x 2.5)
s = 1.25 m
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you are in bed and wish to shut your bedroom door without getting up. you happen to have some play dough(clay) and a bouncy ball on hand, both with the same mass. the play dough will stick to the door, the ball will bounce off. which one would be more effective to throw at your door to close it?
Using the concepts of momentum, we got that bouncy ball will be more effective as to throw at my door to close it when both with the same mass. the play dough will stick to the door, the ball will bounce off.
The momentum of an object is equal to the product of its mass and its velocity. The momentum of the system is conserved even if the collision is inelastic.
When the bouncy ball or the blob of clay actually hits the door, their momentum changes. Since momentum is conserved, the door would move in the opposite direction so that the total momentum stays at zero.
Let the mass of each object be . Suppose that both of the objects hit the door at a speed of in the same direction.
The bouncy ball will actually bounce back at about the same speed (in the opposite direction, away from the door.) The magnitude of the change in velocity will be at most . The magnitude of the change in momentum will be at most .However, when the blob of clay hits the door, its shape would change (and it would potentially stick to the door.) In other words, its velocity becomes almost after the collision. The magnitude of the change in its momentum will only be around , which is only about the momentum change due to the bouncy ball.By Newton's Second Law, the net force on the door is proportion to the rate of change in its momentum.
Hence, when I am in bed wish to shut my bedroom door without getting up and have some play dough(clay) and a bouncy ball on hand, both with the same mass. the play dough will stick to the door, the ball will bounce off, the more effective ball to throw at my door to close it is the bouncy ball.
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3. The average human walks at a speed of 5 km per hour. If your PE teacher asks you to
walk for
40 minutes in
gym class, how far would you walk (km)?
The average human walks at a speed of 5 km per hour. If your PE teacher asks you to walk for 40 minutes in gym class, you would walk for 3 Km.
What is Average speed?
The average speed is the displacement of a particle divided into a time in which the displacement occurs. Instead, instantaneous speed is the limit of the average speed as the time interval approaches zero.
Usually,
Speed = Distance/ Time
Assuming you also walk with the average human walking speed of 5 km/h. We know the above formula of speed and now making distance the subject, distance is a product of speed and time.
Here, time is 40 minutes and if expressed in hours can be converted as,
40/60 = 0.6 hours.
Distance = 5 × 0.6
= 3 km
Thus,the average human walks at a speed of 5 km per hour. If your PE teacher asks you to walk for 40 minutes in gym class, you would walk for 3 Km.
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The kinetic energy of a baseball that with a mass of 0.140kg is 7 J. What is the baseballs velocity?
Answer:
10 m/s
Explanation:
Kinetic energy= [tex]\frac{1}{2}[/tex]mv² where m is mass and v is velocity.
We have to make v the subject so we should rearrange the equation
K=[tex]\frac{1}{2}[/tex]mv²
v²= [tex]\frac{K}{0.5*m}[/tex] (use algebra)
v²= 7/0.5×0.140
v²=100
v=√100
v=10 m/s
We can confirm this by using the kinetic energy formula.
K=[tex]\frac{1}{2}[/tex]×0.140×10²
K= 7 J
Hence it is proved that velocity is 10 m/s
magnus has reached the finals of a strength competition. in the first round, he has to pull a city bus as far as he can. one end of a rope is attached to the bus and the other is tied around magnus's waist. if a force gauge placed halfway down the rope reads out a constant 1550 newtons while magnus pulls the bus a distance of 2.15 meters, how much work does the tension force do on magnus? the rope is perfectly horizontal during the pull.
The Work done by tension force on Magnus is
- 3225 Joule .
In the given question we have, one end of rope is tied around magnus waist and other attched to bus and he pulls the bus. The direction of tension force is just work done.
constant force = 1550 Newton
displacement = 2.15 meters
The direction of tension force is opposite to work done due to the tension force is reaction force to force of work done for pulling the bus.
work done by tension = W = - W₀
where W₀is horizontal work done by magnus during pulling.
so, W₀ = Fdcosθ
where , F---> force , d--> displacment and θ ---> angle between force and displacement
As we see whole work done in horizontal direction. So, angle between force and displacement is zero.
put all the vales in above formula we get ,
W₀= 1550× 2.15 cos0 = 1550×2.15 = 3225 Joule
W = - W₀ = - 3,225J
Hence, work done by tension force on Magnus is
- 3,225 Joule.
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an art student is designing a large mobile with the dimensions shown below. object c has a mass of 1 kg, and objects b and c are in balance. what does the mass of object a need to be to balance objects b and c?
The mass of object a need to be to balance objects b and c is 12kg
Find man of b
1=[tex]\frac{m_{c}}{m_{b}+m_{c}}[/tex]×4
1=[tex]\frac{1}{1+m_{b} }[/tex]×4
[tex]m_{b}[/tex]=3kg
1=[tex]\frac{(m_{b}+m_{c} )}{m_{a} +(m_{b} +m_{c} )}[/tex] ×4
1=4×4/[tex]m_{a}[/tex]+4
[tex]m_{a}[/tex]=12kg
As a measure of inertia, which is a fundamental characteristic of all matter, mass is used in physics. Effectively, it is the resistance a body of matter offers to a change in its speed or position as a result of the application of a force. The change caused by an applied force is proportional to the mass of the body. The kilogram is the measure of mass in the International System of Units (SI). Its definition is based on the Planck constant, which is set at 6.62607015 1034 joule second. The unit of energy known as a joule is one-kilogram times one square meter per second. The kilogram is determined by precise measurements of Planck's constant, while the second and metre are previously defined in terms of other physical constants.
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