A 7.132 gram sample of an organic compound containing only C, H, and O is analyzed by combustion analysis and 11.88 g CO₂ and
3.891 g H₂0 are produced.
In a separate experiment, the molar mass is found to be 132.1 g/mol. Determine the empirical formula and the molecular formula
of the organic compound.

Answer:  i answerd 34cu i got coreect hopefully you get it corecct!!!!!!!

Explanation:

C5H12 + O2 → H2O + CO2 this reaction is complete combustion reaction. Because carbon dioxide and water are formed as a product.

The Combustion defined as a high-temperature exothermic redox chemical reaction between a fuel and an oxidant, normally atmospheric oxygen, that produces oxidized, often gaseous products, in a mixture termed as smoke.

C5H12 + O2 → H2O + CO2 Pentane undergoes a complete combustion reaction with excess oxygen to give carbon dioxide and water.

Thus, this reaction is complete combustion reaction. Because carbon dioxide and water are formed as a product.

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The CCl4 molecule is larger and has more electrons hence it is more polarizable and has a larger boiling point

A higher molar mass does imply a higher boiling point for a substance, assuming that the other conditions (pressure, temperature, etc.) are constant.

This is because the boiling point is a measure of the temperature at which a substance changes from a liquid to a gas at a given pressure. As the molar mass of a substance increases, the intermolecular forces between the molecules tend to be stronger, which makes it more difficult to separate the molecules and vaporize the substance. As a result, the boiling point generally increases with increasing molar mass.

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Answer:

10 moles of NaClO3 were needed to produce 30 moles of O2

Explanation:

From the equation, we know that 2 moles of NaClO3 produce 3 moles of O2. To find out how many moles of NaClO3 are needed to produce 30 moles of O2, we divide the number of moles of O2 by the mole ratio:

30 moles O2 / 3 moles O2 per 2 moles NaClO3 = 10 moles NaClO3

So, 10 moles of NaClO3 were needed to produce 30 moles of O2.

Answer:

C.

Explanation:

in CO there are 2 capital letters,but in Co there is 1 capital letter because its an element.

Answer: c. Co is an element and CO is not

Explanation:

Co and CO are two different chemical substances. Co is the metal element named cobalt whereas CO is the inorganic compound i.e. carbon monoxide.

Co is a chemical element with atomic no. 27 and CO is an inorganic compound consisting of atoms of carbon and oxygen.

co is a metal whereas CO is a gas.

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The molality and density of an aqueous solution of glucose (mm = 180. 2 g/mol) are 5. 21 and 1. 20 g/ml, respectively. Therefore, the molarity of glucose in the solution is 0.0355 M.

Molality is the number of moles of solute per kilogram of solvent, while molarity is the number of moles of solute per liter of solution.

molarity (M) = molality (m) * (density of solvent in g/mL) / (molar mass of solute in g/mol)

molality (m) = 5.21 m

the density of solvent (g/mL) = 1.20 g/mL

molar mass of solute (g/mol) = 180.2 g/mol

So, molarity (M) = 5.21 m * (1.20 g/mL) / (180.2 g/mol)

molarity (M) = 5.21 m * 0.0067 g/mL/g mol

molarity (M) = 0.0355 M

Therefore, the molarity of glucose in the solution is 0.0355 M.

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the empirical formula of the compound  that contains 1. 04 g k, 0. 70 g cr, and 0. 86 g o. is K0.5Cr1O2.

The empirical formula of a compound is the simplest whole-number ratio of atoms of each element in the compound. To find the empirical formula of a compound, you need to determine the number of moles of each element present in the sample.

First, you need to convert the masses of each element to moles:

For potassium (K), 1.04 g / 39.10 g/mol = 0.0264 moles

For chromium (Cr), 0.70 g / 51.99 g/mol = 0.0134 moles

For oxygen (O), 0.86 g / 16.00 g/mol = 0.0538 moles

Next, divide each number of moles by the smallest number of moles to get the simplest whole-number ratio:For potassium (K), 0.0264 moles / 0.0264 moles = 1

For chromium (Cr), 0.0134 moles / 0.0264 moles = 0.5

For oxygen (O), 0.0538 moles / 0.0264 moles = 2.0

Therefore, the empirical formula of the compound is K0.5Cr1O2. This represents the simplest whole-number ratio of atoms of each element in the compound.

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Answer:

27 moles of sulfuric acid are produced.

Explanation:

The equation for the reaction between nitric acid (HNO3) and sulfuric acid (H2SO4) to form nitration sulfate (HNO3) and water (H2O) is:

2 HNO3 + H2SO4 → H2SO4 + 2 H2O

For every 2 moles of nitric acid that react, 1 mole of sulfuric acid is produced. So, when 54 moles of nitric acid are consumed, 54/2 = 27 moles of sulfuric acid are produced.

Molecular formula S₂F₁₀ for the compound with the empirical formula SF₅ and formula weight 254.1 a.m.u.

Molecular formula for a compound with the empirical formula CH₂O and formula weight 180.156 a.m.u: C₆H₁₂O₆.

Molecular Formula:

Molecular formulas use subscripts that give the actual number of atoms of each type in the molecule of a compound. The molecular formula is related to the molecular weight in grams, which is a simple integer multiple of the mass of the corresponding empirical formula.

Empirical Formula:

The empirical formula of a compound is the formula for a substance written in terms of the smallest integer exponent. The empirical formula provides information about the atomic number ratio of a compound. The percent composition of a compound leads directly to the empirical formula.

Now,

The molecular formula of a compound with a given empirical formula can be calculated as:

molecular formula = (empirical formula)n

The molecular formula for this compound is: n = 254.1

⇒ 127n = 254.1

⇒ n = 2

Formula = (SF5)₂ = S2F10

⇒ (CH2O)n = 180.156amu 44 {41 24424} = 180. 156

⇒ (30)n = 180.156

⇒ n = 6

Molecular formula = (CH2O)₆ = C6H12O₆

Molecular formula of a compound with empirical formula CH2O and formula weight 180.156 amu: C₆H₁₂O₆.

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Answer:

The molecular formula of the compound with the empirical formula SF5 and a formula mass of 254.1 amu is S2F10. This can be determined by dividing the formula mass by the empirical formula mass (254.1/48.3 = 5.26) and then multiplying the elements of the empirical formula by this value (S x 5.26 = S2, F x 5.26 = F10).

It will take approximately 4.39 days until the activity of the Tl-201 in Simone's body is one-fourth of the initial activity.

The time it takes for half of a substance's radioactive nuclei to decay is known as its half-life. It is a radioactive substance is characteristic property that is used to determine a material's rate of decay. A decay curve that plots the number of radioactive atoms remaining over time can be used to determine a substance's half-life. Radiometric dating, nuclear medicine, and radiation safety all make use of half-life.

The decay of Tl-201 follows first-order kinetics. The equation for the decay of a radioactive substance is given by:

                            N = N0 × [tex]1/2^{t/t/2}[/tex]

where N is the amount of the substance at time t, N0 is the initial amount of the substance, t1/2 is the half-life of the substance, and t is the time that has elapsed.

We are given that the half-life of Tl-201 is 3.0 days. This means that if we start with an initial activity of A0, the activity at any time t is given by:

                              A = A0 * [tex]1/2^{t/3}[/tex]

We want to know how many days it will take until the activity of the Tl-201 in Simone's body is one-fourth of the initial activity. Let's call this time t₁ :

                          A = A 0/4

                        = A0 × (1/2)[tex]^{t^{1/3} }[/tex]

Dividing both sides by A0 and taking the logarithm of both sides, we get:

                              ln(1/4)

                         = - [tex]t^{1/3}[/tex] × log(2)

Solving for t₁, we get:

                                t₁ = (3/log(2)) × log(4)

                                = 4.39 days

Therefore, it will take approximately 4.39 days until the activity of the Tl-201 in Simone's body is one-fourth of the initial activity.

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Answer:

50 moles of oxygen

Explanation:

The reaction between octane (C8H18) and oxygen (O2) can be represented by the following equation:

C8H18 + 12.5O2 -> 8CO2 + 9H2O

So, to react fully with 4 mol of octane, we need 4 mol * 12.5 mol O2/1 mol C8H18 = 50 moles of oxygen.


ALLEN

The mathematical representation of Charles's Law is V1/T1 = V2/T2.

What do you mean by Charles's Law?

Charles's Law, also known as the Law of Volume-Temperature, states that the volume of a gas is directly proportional to its temperature when pressure is held constant. In other words, as the temperature of a gas increases, its volume will also increase. It was first established by physicist Jacques Charles in 1787.

The mathematical representation of Charles's Law states that the ratio of the initial volume (V1) to the initial temperature (T1) is equal to the ratio of the final volume (V2) to the final temperature (T2). This means that, as the temperature of a gas increases, its volume will increase proportionally.

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Phenacetin is more polar than aspirin because of its molecular structure. Phenacetin has a polar functional group, the acetamide group (-CONH2), which makes the molecule more polar overall. This group has a positive charge on the nitrogen atom and a negative charge on the oxygen atom, making it a dipole, or a molecule with a positive and negative end.

In contrast, aspirin has a non-polar functional group, the acetyl group (-COCH3), which does not have a dipole moment. This makes aspirin less polar overall.

The polarity of a molecule affects its solubility in different solvents. Polar molecules are soluble in polar solvents, such as water, while non-polar molecules are soluble in non-polar solvents, such as oil. Phenacetin is more soluble in water because of its polar functional group, while aspirin is less soluble in water because of its non-polar functional group.

In summary, phenacetin is more polar than aspirin because it has a polar functional group, the acetamide group, while aspirin has a non-polar functional group, the acetyl group. This difference in polarity affects the solubility of the two molecules in different solvents.

The compound with half life of 17 minute have the rate constant of 0.040 minutes⁻¹ will take  to reach  to 12.5%  of  the initial amount .

Half life of a sample is the time required to consume half of its initial amount in a reaction.

For a first order reaction,

the rate constant k  = 1/t ln W0/Wt

where t is the time of consumption, W0 be the initial amount and Wt be the amount after time t.

The half life of the compound =  17 minutes

rate constant = k = 0.693/17 = 0.040 minutes⁻¹

The time taken to reach the concentration of 12.5 % of its original amount is calculated as follows:

t = 1/k  ln Wo/(Wt )

= ln( 100/12.5)/ 0.040 minutes⁻¹

= 52.49 minutes

Therefore, taken to reach the concentration  12.5%  of  the initial amount is 52.49 minutes.

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When the grain size is reduced to 0.160 pm, the strength of mild steel is 1851 MPa.There are a number of variables that can affect mild steel's strength, including the grain size, which is controllable.

We may use the above information to determine the constants in the Hall-Petch equation: The strength of mild steel at grain size d1 = 17.43 pm is 1 = 232.9 MPa. Mild steel has a strength of 2 = 874.2 MPa when the grain size is d2 = 0.80 um (or 800 nm). This is the formula for the Hall-Petch equation: = o + Kd(-1/2). We can use the following equation to determine K: K = (σ2 - σ1)(d2^(1/2) - d1^(1/2))^(-1) (-1) When the values are plugged in, we get the following result: K = (874.2 - 232.9)(800(1/2) - 17.43(1/2))(-1) = 276.3 MPa um(1/2) We can use the following equation to determine o: σo = σ1 - Kd1^(-1/2) Plugging in the numbers yields the following result: o = 232.9 - 276.3(17.43(-1/2)) = 62.28 MPa. The Hall-Petch equation's constants are K = 276.3 MPa um(1/2) and o = 62.28 MPa. Hence, the power of the  yield strength of mild steel at 0.160 pm grain size is 1851 MPa.

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Answer:

The energy released as the mercury vapor cools from 356°C to 25°C can not be determined from the information provided. The amount of energy released depends on various factors such as the heat capacity of the substance, the mass of the substance, and the specific conditions in which it is cooling.

Explanation:

Answer:

807 cal

Explanation:

To determine the energy released as the mercury vapor cools from 356°C to 25°C, we need to determine the change in its internal energy. The internal energy of a substance is given by the equation ΔU = q + w, where ΔU is the change in internal energy, q is the heat absorbed or released by the substance, and w is the work done by the substance.

In this case, the heat absorbed by the mercury as it is heated from 25°C to 356°C is 110 cal, and the heat absorbed to vaporize the mercury is 697 cal, so the total heat absorbed is 110 + 697 = 807 cal. As the mercury vapor cools from 356°C to 25°C, it releases heat, so the heat released can be calculated as q = -807 cal.

Since no work is done in this process (the substance is not expanding or contracting against an external pressure), the work term can be ignored. Therefore, the change in internal energy of the mercury vapor as it cools from 356°C to 25°C is ΔU = q = -807 cal.

So, the mercury releases 807 cal of energy as it cools from 356°C to 25°C.


Tell me if you still confuse

ALLEN

13.8 kJ [tex]mol-1\\[/tex] is  strain energy for the conformer pictured below, using strain energy increments from the table.

The problem is based on the concept of used strain energy  in the conformers.

When two non bonded groups approach each other, it results in repulsion and causes steric strain in the molecule.

Structure of conformer in eclipsed form in Newman projection is as follows:

4.0 kJ mo is energy of eclipsed H-H bond

Energy of eclipsedН-СH, 3 bond is 5.8 kJ mol

Total strain energy of conformer (S,)

E 2x eclipsed (H-H)+ eclipsed (H-CH,)

Replace eclipsed (H-H) with 4.0 kJ mol and eclipsed (H-CH) with 5.8 kJ mol to get

E 2x4.0 kJ mol +5.8 kJ mol =13.8 kJ mol

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It shows that the number of individuals in the population will decrease until the carrying capacity of the environment is reached.

What is the environment?

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Answer:

0.0456 M

Explanation:

The concentration of glucose can be determined as follows:

Step 1: Concentration of glucose in the original solution = Mass of glucose / Volume of solution = 227.9 g / (500.0 mL x 10^-3 L/mL) = 0.456 M

Step 2: Concentration of glucose in the dilute solution = Mass of glucose / Volume of dilute solution = 0.456 M x (16.8 mL x 10^-3 L/mL) / (250.0 mL x 10^-3 L/mL) = 0.0456 M

So, the concentration of glucose in the dilute solution is 0.0456 M to 4 significant figures.

ALLEN

The molecule D shows an isomer of the molecule given below. Therefore, option D is correct.

The term Isomer is defined as the compounds that contain exactly the same number of atoms, i.e., they have exactly the same empirical formula, but differ from each other by the way in which the atoms are arranged.

Isomerism is the phenomenon in which more than one compounds have the same chemical formula, but they have different chemical structures.

Therefore, given molecule and D molecule are isomers of each other because they have the same number of atoms, but they differ in arrangement of the atoms.

Thus, option D is correct.

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The formulas for the compounds formed between platinum ions and bromide ions are Platinum (II) bromide (PtBr2) and Platinum (IV) bromide (PtBr4)

In both of these compounds, the bonding between the platinum ion and the bromide ions is primarily ionic in nature.

In platinum (II) bromide (PtBr2), each platinum ion is surrounded by two bromide ions, and each bromide ion is bonded to one platinum ion. The platinum ion has a +2 charge, and the two bromide ions have a -1 charge each, so the overall charge of the compound is neutral.

In platinum (IV) bromide (PtBr4), each platinum ion is surrounded by four bromide ions, and each bromide ion is bonded to one platinum ion. The platinum ion has a +4 charge, and the four bromide ions have a -1 charge each, so the overall charge of the compound is neutral.

The bond between the platinum ion and the bromide ions is a result of the attraction between their opposite charges.

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A key advantage of PDF is that it has excellent tools for creating and editing images. It is true.

What is a PDF?

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Every solution should have an x mol/L maximum concentration. Each solution's concentration will be lowered to half, or x/2, after mixing.

∴[FeSO4] = [Na2S] = x/2M

Then, [Fe2+] = [FeSO4] = x/2M

Also, [S2−]=[NasS] = x/2M

Fe(S)(x) ↔ Fe 2 + (aq) + S2−(aq)

Ksp=[Fe2+][S2−]

6.3 × 10−18=(x/2)(x/2)

x2/4=6.3 × 10−18  

⇒ x = 5.02 × 10−9

If the concentrations of both solutions are equal to or less than 5.02 × 10–9M, then there will be no precipitation of iron sulphide.

⇒x =5.02 × 10−9

Na2S and FeSO4 are combined in an equal volume. Maximum concentrations of both solutions are 22, 51109M, and 5. Since Ba(OH)2 is the strongest base of the available alternatives, its pH is highest. BaCl2 is a strong base because it is the salt of Ba (OH)2. BaCl2 hydrolysis produces the most alkaline solutions and raises the PH of all the salts provided in the inquiry.

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According to the stoichiometry of the given balanced chemical equation, 1.85 moles of methane are  required to produce 9.03 g of hydrogen.

It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.

In the given reaction, 16 g that is 1 mole methane gives 6 g that is 3 moles hydrogen ,hence for 9 g hydrogen 16×6/9=24.08 g methane is needed and it is equivalent to number of moles= 24.08/16=1.85 moles.

Thus,1.85 moles of methane are  required to produce 9.03 g of hydrogen.

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Answer:

0.101 M

0.1 mol/kg

0.644

Explanation:

To calculate the molarity, molality, and mole fraction of Na2SO4 in a solution, you need to know the moles of Na2SO4 in the solution and the volume or mass of the solution.

A) Molarity: Molarity (M) is defined as the number of moles of solute per liter of solution. To calculate molarity, we need to divide the number of moles of Na2SO4 by the volume of the solution in liters.

First, calculate the number of moles of Na2SO4:

mass of Na2SO4 = 755 g

molecular weight of Na2SO4 = 142 g/mol

number of moles = mass/molecular weight = 755 g / 142 g/mol = 5.34 moles

Next, calculate the volume of the solution:

mass of water = 53,100 g

density of water = 1 g/mL

volume of water = mass/density = 53,100 g / 1 g/mL = 53,100 mL = 53.1 L

Finally, calculate the molarity:

molarity = number of moles / volume of solution = 5.34 moles / 53.1 L = 0.101 M

B) Molality: Molality (m) is defined as the number of moles of solute per kilogram of solvent. To calculate molality, we need to divide the number of moles of Na2SO4 by the mass of the solvent in kilograms.

mass of water = 53,100 g

mass of solvent in kilograms = mass in grams / 1000 g/kg = 53,100 g / 1000 g/kg = 53.1 kg

Finally, calculate the molality:

molality = number of moles / mass of solvent = 5.34 moles / 53.1 kg = 0.1 mol/kg

C) Mole fraction: The mole fraction (X) is defined as the ratio of the number of moles of solute to the total number of moles of solute and solvent in a solution. To calculate the mole fraction of Na2SO4, we need to divide the number of moles of Na2SO4 by the total number of moles of Na2SO4 and water.

number of moles of Na2SO4 = 5.34 moles

number of moles of water = 53.1 kg * 1000 g/kg / 18.015 g/mol = 2.96 moles

total number of moles = number of moles of Na2SO4 + number of moles of water = 5.34 moles + 2.96 moles = 8.30 moles

Finally, calculate the mole fraction:

mole fraction of Na2SO4 = number of moles of Na2SO4 / total number of moles = 5.34 moles / 8.30 moles = 0.644

The molarity of Na2SO4 in the solution is 0.101 M, the molality is 0.1 mol/kg, and the mole fraction of Na2SO4 is 0.644.

The coefficients that correctly balance the given equation is 1. 6, 3,2

The correct option is C

A balanced equation of a reaction is an equation in which the moles of atoms of elements of the reactants are equal to the moles of atoms of the product.

According to the law of conservation of matter, matter is neither created nor destroyed, hence, the mass of the reactants must be equal to the mass of products at the end of any given chemical reaction.

The balanced equation of the given reaction is as follows:

Ba₃N₂+ 6 HOH - -> 3 Ba(OH)₂ + 2 NH₃

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46.2648

Atomic mass describes the number of protons and neutrons in an atom.

Percent Abundance

Percent abundance is the percentage of atoms within a sample that have a specific mass number. The reason that different atoms within a sample would have different mass numbers is that they are different isotopes. For example, if the isotope Cl-35 has a percent abundance of 75%, then 75% of all Chlorine atoms within a sample will have a mass number of 35. Percent abundance refers to the likelihood of an isotope occurring in a natural sample. Percent abundance does not take into account artificial samples of elements.

Finding Atomic Mass

The atomic mass of an element is found through the mass of isotopes and their percent abundances. The formula for atomic mass is:

In this formula, the m is the mass of the isotope and p is the percent abundance. The percent abundance should be expressed as a decimal for all calculations. Now, plug in the values and solve.

Rounded to 4 decimal places, this equals 46.2648. This means that the atomic mass of element "X" is 46.2648 amu.

According to the recipe, to make 4 moles of lemonade, you use 2 moles of water, one mole of sugar and one mole of lemon juice, expressed in grams:

2 water  + sugar + lemon juice = 4 lemonade

2*(236.59) + 225g + 257.83g  = 4*(719.42)g

   473.18g + 225g + 257.83g = 2877.68g

So for every 2877.68g of lemonade made, they use 473.18g of water, 225g of sugar, and 257.83g of lemon juice.

You know that they made a batch of 2050.25g, so to detect the limiting reactant, first, you have to calculate, in theory, how much of each ingredient you need to make the given amount of lemonade:

Use cross multiplication

Water:

2877.68g lemonade → 473.18g water

2050.25g lemonade → X= (2050.25*473.18)/2877.68= 337.12g water

Following the recipe, to elaborate 2050.25g of lemonade, you need to use 337.12g of water.

Sugar:

2877.68g lemonade → 225g sugar

2050.25g lemonade → X= (2050.25*225)/2877.68= 160.30g sugar.

To elaborate 2050.25f of lemonade you need to use 160.30g of sugar.

Lemon juice:

2877.68g lemonade → 257.83g lemon juice

2050.25g lemonade → X= (2050.25*257.83)/2877.68= 183.69g lemon juice.

To elaborate 2050.25f of lemonade you need to use 183.69g lemon juice.

Available ingredients vs. theoretical yields for 2050.25g of lemonade:

Water 946.36 g → 337.12g

Sugar 196.86 g → 160.30g

Lemon Juice 193.37 g → 183.69g

The lemon juice will be the first ingredient to be used up, there will be a surplus of water and sugar.

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