A: "The ball has changing velocity & changing acceleration" is true in regard to inertial reference frame.
The ball has changing acceleration and changing velocity in an inertial reference frame. As it moves in a circular path, it experiences a centripetal acceleration directed towards the center of the circle, which changes its velocity direction. This means the velocity of the ball is not constant in an inertial reference frame and is constantly changing, which is why the acceleration is also changing.
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Complete question
A ball is tied to a string and swung so that the ball follows a circular path that lies in a horizontal the following statements is true in an inertial reference frame, i.e. a reference frame that is at rest with respect to the earth?
A: The ball has changing velocity & changing acceleration
B: The ball has changing velocity & constant acceleration
C: The ball has constant velocity & changing acceleration
D: The ball has constant velocity & constant acceleration
"
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An object at the surface of Earth (at a distance R from the centerof Earth) weighs 90 N. Its weight at a distance 3R from thecenter of Earth is:a. 10 Nb. 30 Nc. 90 Nd. 270 Ne. 810 N
The weight of the object at distance 3R from the Earth is 10 N if the weight at center of the Earth is 90N.
According to Newton's law of gravitation,
Weight W = m × g; where m is the mass of the object and
g is the acceleration due to gravity.
Also,
[tex]g = \dfrac{GM}{R^{2}}[/tex]
where G=gravitational constant, M=mass of earth, R=radius of earth.
Hence,
[tex]W = m \times \dfrac{GM}{R^{2}}[/tex]
Weight is inversely proportional to the square of radius R.
Weight of objects at the surface of the earth is 90 N.
Let W be the weight at a distance of 3 R from the center.
[tex]\dfrac{W}{90} = \dfrac{R^{2}}{(3R)^{2}}\\\dfrac{W}{90} = \dfrac{1}{9}\\W = 10[/tex]
Weight at a distance 3 R is 10 N.
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A particle undergoes three consecutive displacements given by vectors D1 = (2.5î − 3.5ĵ − 3.0 k) mm, D2 = (2.5î − 2.0ĵ + 3.0 k) mm, and D3 = (−8.5î + 9.0ĵ + 8.0 k) mm. a-Find the resultant displacement vector of the particle (in mm).
D = mm (b) What is the magnitude of the resultant displacement (in mm)? mm
(c) If all displacements were along one line and in the same direction, how far would the particle travel (in mm)? mm
a) The resultant displacement vector of the particle is given by the vector sum of all three displacement vectors, which is D = D1 + D2 + D3 = (-5î + 3.5ĵ + 8.0k) mm.
What is resultant displacement?Resultant displacement is a vector which describes the total change in position from the starting point to the ending point. It is calculated by adding the individual displacements of the same body in different directions. Resultant displacement is the magnitude of the displacement vector which is the shortest distance between the two points.
b) The magnitude of the resultant displacement is given by the magnitude of the resultant vector, which is
|D| = √(-5)² + 3.5² + 8.0² = 8.9 mm
c) If all displacements were along one line and in the same direction, then the particle would travel the distance of the magnitude of the resultant vector, which is 8.9 mm.
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Henry’s first history exam score is +1 standard deviation from the mean in a normal distribution. The test has a mean of 65 and a standard deviation of 5. Henry’s percentile rank would be approximately: Group of answer choices None of these choices. 55%. 84%. 70%.
Answer:
84
Explanation:
+1 S.D z-score corresponds to .8413 .... from z-score table
this is 84 percentile
Which of the following velocity versus time graphs best represents the motion of a ball that was thrown upward, from just after it was thrown until just before it is caught on the way down?
Based on the provided information, the velocity versus time graph that best represents the motion of a ball is option D.
Velocity versus time graph refers to a graph that depicts the change in velocity over a period of time. It is used to understand both the velocity of an object, its direction, its acceleration, and the displacement of the object. The velocity in a constant acceleration motion is a linear function of time and is given by:
v = u + at
where v is the velocity at time t, u is the initial velocity, a is the acceleration, and t is the time.
As the ball is influence by gravitational acceleration, a = -g, hence
v = u – gt
Velocity will decrease initially based on the equation v = u – gt, hence the graph does not start from origin because u is not zero and is thrown with some velocity and v is final velocity. The velocity will be positive initially when the ball is moving upward and is decreasing until it goes to zero.
Then, it reverses its sign when moving downward until it is caught having the same initial speed (negative velocity). When v = 0, then t = u/g the v will become zero then it will start increasing in opposite direction, If the upward direction is taken as positive then the downward velocity will be negative. The graph is a straight line consistent with the constant acceleration motion under the action of gravity.
At a certain point, velocity becomes negative and get increasing. Hence option D is correct.
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A racing car starts from rest and reaches a final speed v in a time t. If the acceleration of the car is constant during this time, which of the following statements must be true?
(a) The car travels a distance vt.
(b) The average speed of the car is v/2.
(c) The acceleration of the car is v/t.
(d) The velocity of the car remains constant.
(e) None of these.
Option - B : The average speed of the car is [tex]\frac{v}{2}[/tex] , If the acceleration of the car is constant from rest and reaches a final speed v in a time t .
The average velocity of the car is
[tex]\frac{v+v_{0} }{2}[/tex] = [tex]\frac{v + 0}{2}[/tex]
= [tex]\frac{v}{2}[/tex]
Acceleration refers to the speed at which velocity varies. Acceleration frequently, but not always, denotes a shift in speed. The direction of motion is changing, therefore an object travelling at a constant speed along a circular path is still going ahead. the rate of time-dependent velocity variation. Acceleration is a vector quantity because it has a both magnitude and a direction. The second derivative of position with respect to time or the first derivative of velocity with respect to time are also included. Acceleration is the rate at which an object's velocity varies in relation to time in physics. Newton's Second Law states that an object accelerates as a result of the total of all the forces acting on it.
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Besides kinetic energy, the engine of a car also uses and gives off other types of energy. Name all that apply below: 1: Mechanical 2: Light 3:thermal 4:sound Helpp plis!!!
Other types of energy that the engine of a car also uses and gives off are radiant, thermal, sound, electrical, and mechanical.
What kind of energy are there in a car’s engine?Inside the engine, kinetic energy is converted from chemical energy (fuel, air, and spark plugs) to mechanical energy.
Kinetic energy is classified into five types: radiant, thermal, acoustic, electrical, and mechanical. Radiant energy refers to the constant movement of ultraviolet light and gamma rays across the universe. Sound energy is kinetic energy that manifests itself as vibrations and noise, for as when someone bangs on a drum set. Battery: The battery delivers power to the engine and vehicle electronics/accessories.
When a force, such as sound or pressure, causes an item or substance to vibrate, sound energy is produced. Waves of energy pass through the material. These sound waves are referred to as kinetic mechanical energy.
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Technician A says that when replacing a rear hatch window with defroster grids, the
wiring connection may have a locking tab that will need to be released before
removal.
Technician B says that when replacing a rear hatch window with hydraulic lift struts,
the struts should be completely compressed before removal.
Who is right?
A only
B only
Both A and B
Neither A nor B
Technician A only is tight as hen replacing a rear hatch window with defroster grids, the wiring connection may have a locking tab that will need to be released before removal.
Who is a Technician?A technician is someone with expertise and training in a technical procedure. You might need to contact a network technician if your computer network is giving you problems.
A technician is familiar with all of the technical details (ins and outs) of a particular process. A computer technician is an expert in both operating and repairing computers. Similar to a mechanic, an automotive technician is well-versed in cars and how to repair them. Technology and technicians are not always synonymous. A painter or musician may also be referred to as a technician if they have received training in a variety of artistic or musical techniques.
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A freight company uses a compressed spring to shoot 1.90 kg packages up a 1.00 m-high frictionless ramp into a truck. The spring constant is 391 N/m and the spring is compressed 32.0cm.
1. What is the speed of the package when it reaches the truck?
2. A careless worker spills his soda on the ramp. This creates a 50.0 cm-long sticky spot with a coefficient of kinetic friction 0.300. Will the next package make it into the truck?
a. The speed of the package when it reaches the truck is 1.7 m/sec.
b. No, the next package will not make it into the truck.
a. The speed of the package when it reaches the truck is calculated using the equation for potential energy, PE = 1/2kx², where k is the spring constant and x is the amount of compression (30 cm).
PE = 1/2(500N/m)(0.30m)²
PE = 4.5 J
The kinetic energy, KE, of the package when it reaches the truck is equal to the potential energy, so:
KE = 4.5 J
Using the equation KE = 1/2mv², where m is the mass of the package (2.0 kg) and v is the velocity, we can calculate the velocity.
4.5 J = 1/2(2.0 kg)(v²)
v = 1.7 m/sec
b. The package will not make it into the truck due to the increased friction from the sticky spot. The energy dissipated due to friction will be greater than the kinetic energy of the package, resulting in the package not having enough energy to make it up the ramp.
Complete Question:
A freight company uses a compressed spring to shoot 2.0kg packages up a -high frictionless ramp into a truck, as FIGURE P10.51 shows. The spring constant is 500N/m and the spring is compressed 30cm.
a. What is the speed of the package when it reaches the truck?
b. A careless worker spills his soda on the ramp. This creates a 50-cm-long sticky spot with a coefficient of kinetic friction 0.30. Will the next package make it into the truck?
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Question is in the order of the images.
Need this by midnight!!! Will give brainliest if correct
(please provide the explanation to the answer also)
Answer:
The charge has to move "parallel to the field lines because the field lines are equal and there will be no sidewise force exerted on the charge.
Also, since the field lines are somewhat converging the charge will be entering a stronger electric field and will experience an acceleration due to the increase in the accelerating field.
This explanation assumes that the charge and field lines have the same signs so that the charge is accelerated in the direction of the field.
Field lines start on positive charge and end on negative charge. A positive charge will experience a force in the same direction as the field lines.
ball falls from height of 19.5 m hits the floor, and rebounds vertically upward height of 15.5 m. Assume that mball What is the impulse (in kg M/s) delivered to the ball by the floor? magnitude mls direction Select '400 kg: If the ball Is In contact wlth the floor for 0400 seconds; what the average farce (In N) the floor exerts on the ball? magnltude direction
The average force exerted on the ball by the floor is equal to the impulse divided by the duration of contact, or 1000 N.
Assuming the ball has a mass of 400 kg and that it is in contact with the floor for 0.4 seconds, the impulse delivered to the ball by the floor is 400 kg m/s.
The average force exerted on the ball by the floor is equal to the impulse divided by the duration of contact, or 1000 N. The direction of the force is opposite to the direction of the ball's motion, which is in the downward direction.
The impulse delivered to the ball by the floor is calculated by multiplying the mass of the ball (400 kg) by the change in velocity of the ball, which is the difference between its initial velocity (zero) and its final velocity (after striking the floor). This gives us an impulse of 400 kg m/s.
The average force exerted on the ball by the floor is then calculated by dividing the impulse by the duration of contact (0.4 seconds). This gives us an average force of 1000 N, directed in the opposite direction of the ball's motion.
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Two points in a rectangular coordinate system have the coordinates (5.0, 2.7) and (−3.1, 5.5), where the units are centimeters. Determine the distance between these points.
Answer:
V2 = 5.0 i + 2.7 j
V1 = -3.1 i + 5.5 j vector description of points in question
Or (X2 - X1) = 5.0 - (-3.1) = 8.1 distance between x-coordinates
(Y2 - Y1) = 2.7 - 5.5 = -2.8 distance between y-coordinates
S = [(X2 - X1)^2 + (Y2 - Y1)^2]^1/2
S =[(8.1^2 + (-2.8)^2)]^1/2 = (8.1^2 + 2.8^2)^1/2
S = 73.45^1/2 = 8.57
(d) for steady-level cruise, the engine thrust must equal drag and lift must equal weight. at 35,000 ft altitude, if the aircraft climbs at a rate of 500 ft/min, find the angle of climb and the proportional increment in net thrust needed to achieve this climb rate. assume l/d of 21.6.
The angle of climb is 3.2° and incremental thrust is 500 * W - (21.6) * T.
The lift-to-drag ratio (L/D) for an aircraft is equal to the ratio of lift to drag at constant velocity. For a steady-level cruise, lift must equal weight and engine thrust must equal drag. At 35,000 ft altitude, the aircraft needs an additional net thrust to climb at a rate of 500 ft/min.
To find the angle of climb
tanθ = V/g
θ = angle of climb
V = the climb rate (500 ft/min)
g = 32.2 ft/s2
tanθ = (500 ft/min)/(32.2 ft/s2)
θ = 3.2°
The lift force, L, must equal the weight of the aircraft, W. The drag force, D, must equal the thrust force, T.
L = W
D = T
The lift-to-drag ratio, L/D, is given as 21.6.
L/D = 21.6
The rate of climb is 500 ft/min.
R = 500 ft/min
Using the equation for rate of climb:
R = (T - D) / W
to get extra thrust ΔT:
ΔT = R * W - D
ΔT = 500 * W - D
= 500 * W - (L/D) * T
= 500 * W - (21.6) * T
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10. How much potential energy does 1 m³ of Angel
Falls (the highest waterfall in the world, located
in Venezuela) have at an altitude of 979 m?
The tallest waterfall on the planet is called Angel Falls, located in Venezuela. It is 3,212 feet (979 m) tall, or about a kilometer tall.
Angel Falls in Venezuela has the distinction of being the highest waterfall ever measured?At Venezuela's Angel Falls, the highest waterfall ever measured, you can find. Having a height of 807 m, it boasts the longest single waterfall. The tallest waterfall on the planet is called Angel Falls, located in Venezuela. The tallest waterfall on the planet is called Angel Falls, located in Venezuela. It is 3,212 feet (979 m) tall, or about a kilometer tall! Other intriguing waterfalls in Latin America are Three Sisters Waterfalls (Cataratas las three hermanas in Per), which rise to a height of 2,998 feet (914 m).It is 3,212 feet (979 m) tall, or about a kilometer tall! Other intriguing waterfalls in Latin America are Three Sisters Waterfalls (Cataratas las three hermanas in Per), which rise to a height of 2,998 feet (914 m).To learn more about Angel Falls refer to:
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Which of the following mechanisms is most important quantitatively for the exchange of electrolytes across capillaries?
Bulk flow is the most important mechanism for the exchange of electrolytes across capillaries.
This is because the capillary walls are permeable to electrolytes, allowing them to move freely through the capillary wall to be exchanged between the interstitial fluid and the blood. This is known as bulk flow, and it is responsible for the majority of electrolyte exchanges between the two fluids.
In addition to bulk flow, other mechanisms are involved in the exchange of electrolytes across capillaries. These include:
Diffusion is the process of molecules moving from an area of higher concentration to an area of lower concentration. Osmosis is a special kind of diffusion, where a solvent (usually water) is moved from an area of lower solute concentration to an area of higher solute concentration. Active transport is the movement of molecules against a concentration gradient, and is powered by energy from ATP.Learn more about capillaries:
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4. A 400 kg car is traveling north at 15 m/s. It collides
with and sticks to a truck of mass 700 kg which was
traveling east at an unknown speed. The two stick
together and move initially in a direction 30 degrees
east of North. Determine the speed of the truck.
The speed of the truck is 20m/s
What is speed?
The speed of an object is described as the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time.
After the collision, the momentum of the car and the truck is given by:
p(total) = m(car) * v(total) + m(truck) * v(total)
where v(total) is the velocity of the two vehicles after the collision.
We can use the angle to find the velocity of the truck.
velocity of truck = velocity total * cos(30)
We then substitute the given values into the equation and solve for v(truck).
p(car) + p(truck) = p(total)
m(car) * v(car) + m(truck) * v(truck) = (m(car) + m(truck)) * v(total)
400*15 + m(truck) * v(truck) = (400 + 700) * v(total)
Therefore,
v(truck) = (40015 + 400v(total)) / 700
and
v(total) = v(truck) * cos(30)
v(truck) = (6000 + 400* v(truck)*cos(30)) / 700
Solving for v(truck) we get v(truck) = 20 m/s
In conclusion, the truck was traveling at 20 m/s before the collision.
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The beam is constructed from four pieces of wood, glued together as shown. If M = 10 kip ft, determine the maximum bending stress in the beam. Sketch a three-dimensional view of the stress distribution acting over the cross section.
The maximum bending stress in the beam is 1.46 ksi.
What is bending stress?All of the sections of a beam will experience a bending moment when it is loaded externally.
The internal stresses in the beam fight against the bending that the bending moment at a section tends to cause in the beam.
Bending stress is the term used to describe the resistance provided by internal stresses to bending.
In other words, bending stresses are the internal resistance to an external force that bends a member.
The symbol for it is.
N/mm2 will serve as its unit.
[tex]$ I =\frac{1}{12}^{b'h'3} - \frac{1}{12}^{bh3}[/tex]
[tex]$ I = \frac{1}{12} \times 8 \times 10^3 - \frac{1}{12} \times 6 \times 8^3[/tex]
I = 410.667 inch
Depth of neutral axis
d = 10/2 = 5 inch
Maximum bending stress (σmax) = md/I
σmax = md/I
[tex]$ =\frac{ (10 \times 12)\times 5}{410.667}[/tex]
= 1.46 ksi
Thus, the maximum bending stress in the beam is 1.46 ksi.
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Which of the following Gaussian surfaces would be the simplest to use to determine the electric field intensity near a long, straight, charged wire? A cylinder whose axis coincides with the wire A cylinder whose axis is perpendicular to the wire and passes through the wire A sphere with the wire through its center A cube with the wire passing through the centers of opposite faces
Gaussian surfaces would be the simplest to use to determine the electric field intensity near a long, straight, charged wire, is a cylinder whose axis coincides with the wire.
The Gaussian surface is known as a closed surface in three-dimensional space such that the flux of a vector field is calculated.
Take a uniformly charged straight wire that has a linear charge density λ and Length (L). Make an assumption of a cylindrical Gaussian surface to calculate the electric field. The electric flux across the end of the cylindrical surface would be zero because of the electric field E s circular in direction.
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Click on a few different locations on the Earth globe, and watch how the part of the celestial sphere that is visible from different locations changes. What fraction of the celestial sphere is visible from any location on Earth?
It depends on the location, but typically a person can see approximately 50% of the celestial sphere from any one location.
What fraction of the celestial sphere is visible from any location on Earth?When clicking on different locations on the Earth globe, the part of the celestial sphere that is visible from those locations changes significantly.This is because the orientation of the stars in the sky changes as the observer changes their location on Earth.The fraction of the celestial sphere that is visible from any location on Earth is roughly half, as the Earth blocks the view of the stars in the southern hemisphere from the northern hemisphere and vice versa.However, due to the tilt of the Earth's axis, some stars in the southern hemisphere are still able to be seen from the northern hemisphere, and vice versa.Additionally, the fraction of the celestial sphere that is visible from any location on Earth can also vary depending on the time of year and time of day.For example, during the winter months in the northern hemisphere, the stars in the southern hemisphere are visible in the night sky, and during the summer months in the northern hemisphere, the stars in the northern hemisphere are visible in the night sky.The fraction of the celestial sphere that is visible from any location on Earth is ultimately dependent on the observer's location and the time of day.To learn more about the fraction of the celestial sphere refer to:
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Determine the algebraic sign of alex's x velocity and y velocity at the instant he leaves the ground at the edge of the crevasse.
Alex's velocity as he leaves the ground is +,0 after it leaves the player's hand at the instant before he leaves the ground is +,-.
at the highest point of the ball,
A group of terms combined using addition, subtraction, multiplication, and division constitute an algebraic expression.
Expressions made from constants and variables are known as algebraic expressions. Any value is possible for a variable. For instance, the formula 6 x + 5 comprises two terms. The variable, its coefficient, and the constant term are represented by the numbers 7 x, 5 y.
Consequently, the algebraic expression just before he rises off the ground is positive and negative.
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An object of mass M 1 moving with a speed v on a straight, level, frictionless track when it collides with another mass, M 2 that is at rest on the track. After the collision, M 1 and M 2 stick together and move with a speed of ____
a. V
b. M1v
c. (M1 + M2)/M1
d. M1v/(M1 + M2)
After the collision, the object of mass M1 and the other mass M2 stick together and move with a speed of M1v/(M1 + M2), option D.
What is collision?In physics, a collision, also known as an impact, is the sudden, forceful coming together of two bodies in direct contact. This is known as the law of conservation of momentum, which states that the total momentum of a system remains constant if no external forces are acting on it.
In this scenario, the combined mass of M1 and M2 is moving with a velocity equal to the initial velocity of M1 divided by the sum of the two masses.
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Exercise 20: Olga, the 50.0-kg gymnast, swings her 1.6-m-long body around a bar by her
outstretched arms. a) What is Olga's moment of inertia? b) If Olga were to
pull in her legs, thereby cutting her body length in half, how would this
change her moment of inertia? (Assume her mass is evenly distributed all
along her body.)
Olga's inertia moment approximately 42.7kgm². If Olga was ever to tuck her legs in, she would have a 10.6kgm² moment of inertia and overall body length would be cut in half.
Describe inertia.A feature of substance known as inertia is the ability to maintain either a situation of rest or homogeneous motion in a straight line without the assistance of an external entity. A body's inertia is a quality that makes it resist any effort to move it by any force.
A force as well as inertia?The unifying force of the earth is inertia. Literally. Without it, everything would not possess the magnetic forces required to create its current configuration. The heat and dynamic energy created by moving particles work to resist inertia.
(a) moment of inertia,
I = 1/3 mL²
m = 50.0 kg
L = 1.6 m
I = 1/3 (50.0kg) (1.6m)²
= 42.7kgm²
(b) Olga's body is just half the length
L = 1.6m / 2
= 0.8m
I = 1/3(50.0kg) (0.8m)²
= 10.6kgm²
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Two speakers are arranged 1 m apart directly on the y-axis. They emit 0.5 m wavelength sound in phase. If you walk in a circle around the speakers with a radius of 2 m as shown, why are there 8 points of constructive interference that you will encounter?
The points of constructive interference will be at 4π/0.5 = 8 points around the circle.
What is constructive?Constructive is an adjective that describes something that is useful and productive. It is often associated with problem-solving and constructive criticism. Constructive actions are those that are aimed at achieving a desired result, such as improving an existing situation or creating something new.
Constructive interference occurs when two waves of the same frequency are in phase and move through the same point in space at the same time. As you walk in a circle around the speakers with a radius of 2 m, the distance from the speaker to any given point on the circle is equal, and therefore the two waves will reach each point at the same time.
Since the wavelength of the sound is 0.5 m, the two waves will be in phase at any point on the circle that is an integer multiple of 0.5 m away from the speakers.
Since the circumference of the circle is 4π m, the points of constructive interference will be at 4π/0.5 = 8 points around the circle.
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A positively charged rubber rod is moved close to a neutral copper ball that is resting on a nonconducting sheet of plastic.
With the rod still close to the ball, a metal wire is briefly connected from the ball to the earth and then removed. After the rubber rod is also removed, describe the distribution of charges (if any) on the copper ball.
Match the words to the appropriate blanks.
1. __________ from the earth are _______ by the region of _________ charge on the ball and flow onto the ball, giving it a net ______ charge.
2. When the rod is removed, this net charge distributes _______ over the ______of the ball.
- attracted
- uniformly
- positive
- electrons
- unevenly
- negative
- repelled
- surface
- interior
- protons
1. Electrons from the earth are attracted by the region of positive charge on the ball and flow onto the ball, giving it a net negative charge.
2. When the rod is removed, this net charge distributes uniformly over the surface of the ball.
The planet serves as a ground with little promise. Therefore, positive charge flows into the ground when a positively charged conductor is linked to it, and as a result, electrons move from the earth to the conductor.
The sphere receives electrons from the ground until it reaches electrical neutrality. As the sphere fills with electrons from the earth, it becomes negatively charged.
The item will have a balanced charge and become neutral by absorbing electrons from the ground. A positively charged item is grounded by transferring electrons from the earth into it, a process known as grounding. Electrons from the ground are drawn to the object's surplus positive charge.
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when a jumbo egg was dropped from 5 meters onto a 1-inch foam surface, it fractured. which of the following changes in conditions would lead to a safe landing? select all that would. A.Change the egg size to a large egg.
B.Change the drop height to 1 meter.
C.Change the landing surface to a box of foam.
When a jumbo egg was dropped from 5 meters and fractured upon landing on a 1-inch foam surface, there were two changes in conditions that would have likely led to a safe landing. Option B and C are correct.
The first change is to lower the drop height. The force of the impact is proportional to the height from which the egg is dropped, so reducing the height would reduce the force of the impact and make a safe landing more likely. For example, if the height was reduced to 1 meter, the force of the impact would be one fifth of what it was when dropped from 5 meters.
The second change is to provide more cushioning upon impact. The 1-inch foam surface did not provide enough cushioning to absorb the force of the impact and protect the egg, but using a box of foam as the landing surface would increase the amount of cushioning and reduce the force of the impact. The more cushioning there is, the less the force of the impact will be and the more likely it is that the egg will have a safe landing.
In conclusion, reducing the drop height and providing more cushioning upon impact are two changes in conditions that would have led to a safe landing for the jumbo egg when dropped. It is important to keep in mind that the specifics of each situation will affect the outcome, and it is necessary to consider various factors, such as the size and type of egg, the height and surface upon landing, and the speed and angle of impact, to determine the best way to ensure a safe landing.
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1 What point defects are possible for MgO as an impurity in Al2O3? How many Mg2 ions must be added to form each of these defects?
Point defects are possible for the compound Al₂O₃ as an impurity in MgO. Then, two Al³⁺ must be added to form bond with one Mg²⁺ must be added to form each of these defects in the lattice.
What are Point defects?Point defects are the defects in zero-dimensional lattice, meaning that they may lack a specific lattice structure in any possible dimension. Impurities in the atoms in a pure metal, vacancies, and the self-interstitials are some examples of the common point defects.
Point defects lack include, however are not limited to, the atoms of impurity in a pure metal, vacancies, and the self-interstitials.
The term point defect refers to the flaw or the imperfection in the lattice which results from the placement of a point-like constituent particle in the lattice, such as an atom, an ion, or a molecule, in a crystalline structure.
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A control volume is a special type of closed system that does not interact in any way with its surroundings. FALSE
The given statement is false
What is closed system?
A system can be either closed or open: A closed system is a system that is completely isolated from its environment.A closed system is that in which only the exchange of energy is allowed but the exchange of matter is not allowed. Example-When we boil water with a closed lid, the heat can exchange but matter cannot.There are two types of systems: open and closed. An open system is one in which energy can be transferred between the system and its surroundings. The stovetop system is open because heat can be lost into the air. A closed system is one that cannot transfer energy to its surroundings.An open system can exchange both energy and matter with its surroundings. The stovetop example would be an open system, because heat and water vapor can be lost to the air. A closed system, on the other hand, can exchange only energy with its surroundings, not matter.To learn more about closed refers to:
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q1. at which point or points (marked a-e) is the object moving the slowest without being at rest? explain your reasoning.
In the given position-versus-time graph, the object moving the slowest without being at rest is at point B.
A position-versus-time graph illustrates how far an object has traveled from its starting position at any given time since it started moving. The vertical axis represents the position of the object, and the horizontal axis represents the time.
The slope of the graph indicates the speed of the moving object. Hence, the value of the slope at a particular time indicates the speed of the object at that instant. Hence, the steeper the line is, the greater the slope of the line and the faster the object's motion is changing.
In the given graph, at point A, C and E the slope is zero the object is not moving, hence at rest. At point D slope is steeper as compared to slope at point B. Hence, object is moving slower at point B compared to point D.
Note: The question is incomplete. The complete question probably is: The figure shows the position-versus-time graph for a moving object. At which point or points is the object moving the slowest without being at rest?
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DRAW the lines of convergence and area of convergence in this picture
PLEASE HELPPP
It is possible to identify the line of convergence by drawing straight lines down the blood spatter's long axis and noting where the lines intersect.
Where do these two things converge?Area of Convergence,the region where lines connect the long axes of distinct stains to produce intersections, which in two dimensions shows where the blood source is.An area of origin is the point in space where a bloodstain first appeared.If the blood spatter contains at least two drops, the source of the blood can be located. It is possible to identify the line of convergence by drawing straight lines down the blood spatter's long axis and noting where the lines intersect.It is possible to identify the line of convergence by drawing straight lines down the blood spatter's long axis and noting where the lines intersect.The complete question is,
What is forensics along the line of convergence?
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The SST’s initial operating temperature was 5.5 K. At what wavelength (in micrometers) does the telescope’s own blackbody emission peak? How does this wavelength compare with the wavelength range in which the telescope is designed to operate?
We can calculate the wavelength of the peak as follows:
λmax = 2.898 x 10^-3 μm K / 5.5 K = 0.526 μm
So, the wavelength of the peak is 0.526 μm.
What type of wavelength is this?The above wavelength is in the far-infrared range, which is different from the wavelength range in which the SST is designed to operate. The SST operates in the submillimeter range, which is significantly longer than the wavelength of the blackbody emission peak.
How does this wavelength compare with the wavelength range in which the telescope is prepared to work?The wavelength of the blackbody emission peak does not compare favourably with the wavelength range in which the telescope is designed to operate. The telescope must be cooled to reduce its blackbody emission to operate effectively in the submillimeter range.
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Determine the stiffness kt of the single spring such that the force f will stretch it by the same amount s as the force f stretches the two springs. express kt in terms of stiffness k1 and k2 of the two springs.
The stiffness of the single spring kt is k1 + k2, if the force f stretches it by the same amount s as the force stretches the two springs.
The force f will stretch the single spring and the two springs by the same amount s if the following equation is satisfied:
f / kt = s
f / (k1 + k2) = s
where kt is the stiffness of the single spring, k1 and k2 are the stiffnesses of the two springs, f is the force, and s is the stretch.
Solving for kt, we get:
kt = f / s = k1 + k2
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