Answer:
ac = ω²R = 3.5²(1.5) = 18.375 ≈ 18 m/s²
1.Convert 8.1 kilograms into grams.
2.Convert 376 centimeters into meters.
3 Convert 68 centimeters into feet.
Answer:
See below.
Explanation:
1. 8.1 kg = 8100 g
2. 376 cm = 3.76 m
3. 68 cm ≈ 2.23 ft
9. A vehicle accelerates from rest to a final velocity of 12 m/s. Its acceleration is 3 m/s2. How far does the vehicle
travel?
Answer:
not enough info i need to know what the time is
Explanation:
The force of attraction between things that have mass called_____. Someone please help
A machine has mechanical advantage 2, what does it mean
Answer:
Mechanical advantage MA is the ratio of output (generated by the machine) force to input (applied to the machine) force. So MA = 2 means that for example if you apply 100 N then your machine will multiply that force and generate 200 N.
Source = Wikipedia
I Hope IT WILL HELP YOU A LOT.
Suppose you throw a baseball (mass of 145 g) in the air with a force of 300 N.
What is its acceleration?
Answer:
A = 43.5 m/sec^2
Explanation:
A = F x m
Must turn g into kg
A = 300 N x 0.145 kg
A = 43.5
Hope this helps :)
Which correctly describes electric potential, electric field, and electric (or electrostatic) force?
a. The potential, the field, and the force are vector quantities.
b. The potential, the field, and the force are scalar quantities.
c. The potential and the field are scalar quantities, and the force is a vector quantity.
d. The potential and the force are vector quantities and the field is a scalar quantity.
e. The potential is a scalar quantity, and the field and the force are vector quantities.
f. The potential and the force are scalar quantities, and the field is a vector quantity
Answer:
E
Explanation:
A vector is a physical quantity that has magnitude and direction while a scalar is a physical quantity that has magnitude only
*electric potential is a scalar quantity because it only has magnitude
*electric field and electric force are vector quantities because they have magnitude and direction
Select the correct answer.
Calculate the force of gravity on a 1–kilogram box located at a point 1.3 × 107 meters from the center of Earth. (The value of G is 6.673 × 10-11 newton meter2/kilogram2. The mass of Earth is 5.98 × 1024 kilograms.)
A.
2.36 newtons
B.
3.58 newtons
C.
4.87 newtons
D.
8.95 newtons
Answer:
A. 2.36 Newtons
Explanation:
F = GmM/d²
F = 6.673 x 10⁻¹¹(1)(5.98 x 10²⁴) / (1.3 x 10⁷)²
F = 2.36121...
Very poor question design.
mass of box... 1 significant digit
distance... 2 significant digits
mass of earth... 3 significant digits
value of G... 4 significant digits
Answer precision to 3 significant digits is not justifiable
Bobo, the clown, wants to set the world record for the furthest range traveled by a clown shot out of a cannon. Write a sentence describing the cannon that Bobo would need to use to accomplish this feat. Be sure to include the necessary initial velocity and the required angle of the cannon. Score: 0 / 1
In the human cannonball act makes use of of a special type of "cannon" that more safely ejects a person who acts as the "cannonball"
The world record for the longest flight by a human cannonball is approximately 194 feet and therefore the human cannon catapult that Bobo would need is one that would be able to propel him with an initial velocity of more than 120 kilometer per hour (more than the speed of the current record holder) with the cannon directed at an angle 45 degrees above the horizonal
The reason the values given above are correct is as follows:
The world record of the furthest range of the human cannonball is 193 ft. 8.8 inches. The maximum claim for the furthest range of a human cannonball is 200 ft. 4 in. Therefore, to safely set the world record would be to reach a range of 194 feet
The speed with which the world record was accomplished (120 km/jhr) should be expected to be exceeded given, horizontal speed in free fall motion is constant (decreasing in the presence of drag), and the conditions are likely to be more or less similar
In order to reach the furthest range, R, at the possible speed, the angle of inclination of the "cannon" required is 45°, according to the range formula, which is given as follows;
[tex]Range, \ R = \dfrac{v^2 \times sin(2\cdot \theta)}{g}[/tex]
The maximum range is given where θ = 45, such that sin(2·θ) = sin(90°) = 1
A further range than the world record van be obtained using the above values
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A horse track is a loop where the starting point and the finish line are at the same point. A horse gallops around a 400 m track in 20 s. Calculate the velocity of the horse
A.20 m/s
B.0.05 m/s
C.0 m/s
D.40 m/s
The velocity of the horse is 0 m/s, so the correct option is C.
The velocity is a vector that is given by the rate of change of the displacement.
[tex] v = \frac{d}{t} [/tex]
Where:
d: is the displacement
t: is the time
Since in the horse track the starting point and the finish line are at the same point, the velocity of the horse is zero because the velocity depends on the direction of the displacement, and here the displacement is zero (the horse returns to the starting point).
Therefore, the correct option is C: 0 m/s.
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Answer:
The velocity of the horse is 0 m/s:
Correct answer is C.
what is the difference between the pressure exerted by a solid and that by liquid?
Answer:
• Pressure inside liquids are due to the random movement of the liquid molecules and the weight of the liquid. The pressure inside solids occurs only due to the weight of the solid.
• The liquid pressure acts on the sides of the liquid as well as the bottom. The pressure due to solids only appears at the bottom of the solid.
A person takes a trip, driving with a constant speed of 90.5 km/h, except for a 28.0-min rest stop. The person's average speed is 73.2 km/h.
(a) how much time is spent on the trip?
(b) how far does the person travel?
We have a segment AC and B is in the middle. So AB + BC = AC because the segment is in pieces. Because B is a midpoint, AB = BC. We now have
AB + BC = AC sum of a segment is sum of its pieces
AB + AB = AC B is the midpoint, so AB = BC
2x + 2x = 3x + 20 putting in for AB (twice!) and AC
4x = 3x + 20 collect like terms
x = 20 subtract 3x on both sides.
So x=20
If the solar system were the size of your campus, how far away would the nearest star be?
About a mile away.
About 100 miles away.
About 2,000 miles away.
An infinite distance away.
The solar system is very large with the boundaries located around the Orth cloud 100,000 Astronomical Units away
The correct option for, the distance to the nearest star if the solar system were the size of a campus is the option;
About a mile away
The reason the above selection is correct is as follows:
The nearest star to the solar system is Proxima CentauriThe distance of the nearest star to the solar system from Earth is 40,208,000,000,000 kilometers awayThe area of the solar system is about (π × (10⁵ × 149.6 × 10⁶)²) km²The size of one of the largest campus can be taken as 27,000 acres = 109.2651 km²The ratio of the area of the solar system to the area of a campus = (π × (10⁵ × 149.6 × 10⁶)²)/(109.2651) = 6.4347487 × 10²⁴
Therefore, the linear scale factor ≈ √(6.4347487 × 10²⁴) ≈ 2.5366807 × 10¹²
Therefore, the corresponding distance to the distance of the nearest star to the solar system, X is given as follows;
X = (40,208,000,000,000 km)/(2.5366807 × 10¹²) ≈ 15.85 km ≈ 9.85 miles
Given that compared with the largest campus the distance is at most approximately 9.85 mile, if the solar system is taken to be a much smaller campus, the distance of the closest star Proxima Centauri will be about a mile away
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moment of inertia of uniform rod
define it.
Explanation:
Hopefully the picture is clear and understandable
:)
Answer:
a quantity expressing a body's tendency to resist angular acceleration, which is the sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation.
Which of the following materials can be charged: plastic, glass, metal? 
• This question comes from the study of electrostatics.
Materials that can be charged from the options are; plastic and glass.
• Now, among the 3 listed materials, plastic and glass are insulators whereas metal is a conductor because it can conduct electricity.
• With respect to insulators and conductors as regards charging by electrostatics, we can say that in conductors if you charge a portion of them, the charges inside will have the freedom of movement. However, inside of the material, If a charge is added in another portion of the conductor, the previously introduced charges will combine to neutralize this new charge.
• With respect to insulators, the charges that are put at the surface of the object will remain there because unlike conductors, these insulators do not allow for freedom of movement of charges inside the material that could neutralize.
• Thus, the materials that can be charged by rubbing are plastic and glass.
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If an object is moving with a constant velocity then according to Newton's first law:
A- it will continue with this velocity only if a net external unbalanced force acts.
B- it will change its velocity if a net unbalanced external force is applied.
С- it will continue with its velocity as external unbalanced force acts.
D- it will continue with its velocity as friction only acts if an external unbalanced force is applied.
An artist creates a solid sculpture made from 7.10 kg of tin. She wishes to create an identical sculpture, using the same mold used to make the original, out of solid lead. What is the mass (in kg) of the lead sculpture? (The density of tin is 7.26 ✕ 103 kg/m3, and that of lead is 11.30 ✕ 103 kg/m3.)
Answer:
7.10(11.30/7.26) = 11.05 kg
Explanation:
dividing by the density of tin gives the volume of the sculpture
multiplying that volume by the density of lead gives the lead mass required.
What does it mean to maintain balance or
homeostasis?
The controlling and maintaining of the
internal environment of an organism.
Controlling what happens in the world around
you.
Standing on one foot with your eyes shut.
ube
Not watering your plant for four days.
What is the force on a 1,000 kg elevator that is falling freely at
25 m/s?
Explanation:
Force=mass*acceleration
Mass=1000kg
Acceleration=25m/s
F=1000*25
F=25000N
2. Determine the units of the quantity described by each of the following
combinations of units:
a. kg (m/s) (1/s) b. (kg/s) (m/s)
c. (kg/s) (m/s) d. (kg/s) (m/s)
Explanation:
a.) kg(m/s)(1/s) = force (N)
b.) (kg/s)(m/s) = force (N)
c.) (kg/s)(m/s) = force (N)
d.) (kg/s)(m/s) = force (N)
The units of the quantity described by each of the following
combinations of units are the Newton
Force is defined as the product of mass and acceleration of the body. The unit of force is Newton or kgm/s². Mathematically,
Force = mass* acceleration
Unit of mass = kg
Unit of acceleration = m/s²
Unit of Force = kg * m/s²
Unit of force is therefore also expressed as kgm/s²
According to the option given:
kg (m/s) (1/s) = kgm/s² (Thisis also equivalent to Newton)
We can also see that the other option when multiplied together will give kgm/s² which is also expressed in Newton (N)
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If a river is flowing south at 4 m/s and you swim straight across (i.e. east) at 2 m/s; admittedly, you're going to drift a bit south. That said, calculate that distance that you drifted south from your starting point. The river is 16 m wide.
We have that the distance that you drifted south from your starting point is
[tex]\triangle y=32m[/tex]
From the question we are told that
a river is flowing south at 4 m/s
you swim straight across (i.e. east) at 2 m/s; admittedly
The river is 16 m wide
Generally the equation for the change in direction is mathematically given as
[tex]\triangle x = v_x t\\\\16=2*t\\\\t=8s[/tex]
Therefore
[tex]\triangle y = v_y t\\\\\triangle y=4*8\\\\\triangle y=32m[/tex]
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Finally , what is this kinematics ??
xD
Answer:
study of force and motion
A rocket blasts off and accelerates upward from rest with a rate of 15.4 m/s2. Calculate the
distance it will rise in 22 seconds.
NEED HELP!!
From question we have,
Inital velocity(u) = 0Accleration(a) = 15.4 m/s²Time taken(t) = 22 secNow, from the second equation of motion;
s = ut + ½at² { where s = distance covered }Just put all the values provided in the question, in this equation;
s = ut + ½at²s = (0 × 22) + ½ × 15.4 × 22 × 22s = 15.4 × 11 × 22s = 15.4 × 242s = 3726.8 mTherefore, distance it will rise in 22 seconds will be 3726.8m
A robot used in a pharmacy picks up a medicine bottle at t=0. It accelerates at 0.25 m/s2 for 6.5 s , then travels without acceleration for 57 s and finally decelerates at -0.60 m/s2 for 2.7 s to reach the counter where the pharmacist will take the medicine from the robot.
The acceleration-time graph is used to show the relationship between the acceleration of a body and time.
Let:
[tex]a \to[/tex] acceleration
[tex]t \to[/tex] time
From the question, we have the following parameters:
[tex](a_1,t_1) = (0,0)[/tex]
[tex](a_2,t_2) = (0.25,6.5)[/tex] ---- when the robot accelerates
[tex](a_3,t_3) = (0,57)[/tex] ----- when the robot travels without acceleration
[tex](a_4,t_4) = (-0.60,2.7)[/tex] ---- when the robot decelerates
To represent this on an acceleration time graph, we consider the following:
When the robot accelerates, the line on the graph increases in a right upward directionWhen the robot travels without acceleration, the acceleration is represented with a horizontal line. This simply means that acceleration is 0When the robot decelerates, the line on the graph decreases in a right downward directionThe total time (t) spent by the robot is 66.2 seconds
This is calculated as follows:
[tex]t = 6.5 + 57 + 2.7[/tex]
[tex]t = 66.2[/tex]
See attachment for the acceleration time graph (not drawn to scale)
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When a driver hits the brakes, his car decelerates from 50m/s at a uniform rate of 2.0m/s^2. His car stops after covering some distance. How long does it take him to stop?
Please find attached photograph for your answer. Please do comment whether it is useful or not.
the minute arm of the clock rotates in one complete Revolution in 60 seconds calculate the angular velocity?
Answer:
w (angular velocity = theta / t where 2 pi = 360 deg
For clock w = 1 rev / 60 sec = 2 * pi / 60 = pi / (30 sec)
A particle at t1= -2 seconds is at x1=4.8cm and at t2=4 seconds is at x2=9cm. Why can’t you calculate the average speed from this data?
Answer:
A particle at t1= -2 seconds is at x1=4.8cm and at t2=4 seconds is at x2=9cm. Why can’t you calculate the average speed from this data?
Explanation:
the average speed of the distance travelled is needed to be know and we were only given displacement.
Convert the following in to SI units without changing its values
a. 4000 g.
b. 2.4 km
#A
[tex]\boxed{\sf 1kg=1000g}[/tex]
[tex]\\ \sf\longmapsto 4000[/tex]
[tex]\\ \sf\longmapsto \dfrac{4000}{1000}[/tex]
[tex]\\ \sf\longmapsto 4kg[/tex]
#B
[tex]\boxed{\sf 1km=1000m}[/tex]
[tex]\\ \sf\longmapsto 2.4km=2.4(1000)[/tex]
[tex]\\ \sf\longmapsto 2400m[/tex]
If it takes Tanya 9.4 hours to get to her cousin's house while driving an average of 40 mph, how far away does her
cousin live?
Answer:
376 miles
Explanation:
speed = distance / time
therefore distance = speed * time
distance = 40 miles/hr * 9.4 hr
then
distance = 375 miles
When are theories constructed?
A. after data is collected from an experiment
B. after there is numerous data collected during the experiment
Hi, This is the answer...
Theories are constructed after there is numerous data collected during the experiment.
Hope it helps you...Pls mark brainliest if it helps you....(by Benjemin)
The correct answer is B.
Theories are constructed after there is numerous data collected during the experiment.
Theory construction is simply a process of formulating and bringing together different components of theories into a single form that is more meaningful.
These theories are usually supported by evidence (data) gathered from many experiments.
In addition, these theories may answer the basic questions of our universe such as;
how does nature work? and,why it exhibits certain characteristicsThus, from the given options, only option B matches the above explanations.
"theories are constructed after there is numerous data collected during the experiment"
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Identify the parts of the body based on the medical terminology given:
1. mr. heart describes pain that is midline, superior to the chest but inferior to the chin.
2. miss triangle says that she has a ‘tweak’ that is superior to the waist, inferior to the breast bone, lateral to the umbilicus on the left side of the body on the anterior surface.
3. mr. square states that he has pulled a muscle, inferior to the buttocks, superior to the knee, medial to the right side of the body on the posterior surface.
4. miss circle complains of a sharp pain inferior to her ears, superior to the scapula at midline on the posterior side of her body.
5. mr. x says that he has numbness and tingling on the anterior side of his left arm, distal to the wrist.
6. mrs. diamond describes a throbbing pain on the posterior side of her body, inferior to her shoulder blades and superior to her waist.
7. miss arrow states that she has had a pain on the left side of her body, superior to her neck and inferior to her forehead, lateral to her nose.
8. mr. teardrop says that he has been bitten by a spider lateral to his umbilicus on the anterior aspect of his body, superior to his hip on the right side of his body.
9. miss eight describes a burning sensation on the posterior side of her body, lateral to the spine on the left side of the body inferior to the shoulder blade, inferior to the waist but anterior to the knee.
10. mr. four shows you a deep wound on the anterior side of his body, medial to the left hip, lateral to the umbilicus, inferior to the collarbone and anterior to the waist.
Answer:
1. Right hypochondriac region (upper, right).
2. Epigastric region (upper, middle).
3. Left hypochondriac region (upper, left).
4. Right lumbar region (middle, right).
5. Umbilical region (centre).
6. Left lumbar region (middle, left).
7. Right iliac region (lower, right).
8. Hypogastric region (lower, middle).
9. Left iliac region (lower, left).
Explanation:
1. Right hypochondriac region (upper, right)- Liver, gallbladder, right kidney, small intestine.
2. Epigastric region (upper, middle)- stomach, liver, pancreas, duodenum, spleen, adrenal glands
3. Left hypochondriac region (upper, left)- Spleen, colon, left kidney, pancreas
4. Right lumbar region (middle, right)- Gallbladder, liver, right colon
5. Umbilical region (centre)- Umbilicus, parts of the small intestine, duodenum
6. Left lumbar region (middle, left)- Descending colon and left kidney
7. Right iliac region (lower, right)- Appendix and cecum
8. Hypogastric region (lower, middle)- Bladder, reproductive organs, sigmoid colon
9. Left iliac region (lower, left)- Descending and sigmoid colon.
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