The intensity of the sound waves to a listener 93.52 m from the band is approximately [tex]6.75 *10^{-7} W/m^2[/tex].
The formula for sound intensity is:
[tex]I = P/(4\pi r^2)[/tex]
where I is the intensity of the sound, P is the power of the sound source, and r is the distance from the sound source.
In this case, the power of the banjo band is 67.05 W, and the distance from the listener to the band is 93.52 m. Substituting these values into the formula, we get:
[tex]I = 67.05 W/(4\pi(93.52 m)^2)[/tex]
Simplifying this expression, we get:
[tex]I = 6.75 *10^{-7} W/m^2[/tex]
Therefore, the intensity of the sound waves to a listener 93.52 m from the band is approximately [tex]6.75 *10^{-7} W/m^2[/tex]. This is a relatively low value, as the threshold of hearing for most humans is around [tex]1 * 10^{-12} W/m^2[/tex]. However, the actual loudness of the sound heard by the listener will also depend on the sensitivity of the human ear and other factors.
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what is the magnitude of a point charge that would create an electric field of 1.20 n/c at points 1.60 m away?
The magnitude of a point charge that would create an electric field of 1.20 n/c at points 1.60 m away is 0.341 * [tex]10^{-9}[/tex] C.
Each location in space where a charge exists in any form can be considered to have an electric field attached to it. The electric force per unit charge is another name for an electric field. Variable magnetic fields or electric charges are frequently the cause of electric fields. Volts per metre (V/m), a unit used in the SI, is used to express electric field strength. The force acting on the positive charge is assumed to be exerted in the direction of the pitch. The electric field is directed radially inwards towards negative point charge and radially outwards from positive charge.
Electric field = 1.20 n/c
r= 1.60 m
[tex]E=\frac{q}{4\pi E_{o}*r^{2} } \\q=4\pi E_{o}*E*r^{2} \\=\frac{(1.20 n/c)((1.60m)^{2} }{8.99*10^{9}N.\frac{m^{2} }{C^{2} } } \\=0.341*10^{-9} C[/tex]
Therefore, the magnitude of a point charge that would create an electric field of 1.20 n/c at points 1.60 m away is 0.341 * [tex]10^{-9}[/tex] C.
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sound waves with frequency 3700 hz and speed 343 m/s diffract through the rectangular opening of a speaker cabinet and into a large auditorium of length 100 m. the opening, which has a horizontal width of 21.0 cm, faces a wall 100 m away. along that wall, how far from the central axis will a listener be at the first diffraction minimum and thus have difficulty hearing the sound? (neglect reflections.)
The central will a listener be at the first minimum and thus have difficulty hearing the sound is 41.2 m.
As with all waves, the relationship between sound speed, frequency, and wavelength can be described by the equation where stands for sound speed, stands for sound frequency, and represents the wavelength.
Perpendicular to the speaker and spaced from the central should make up the initial minimum.
Therefore,
100m/[(0.300m)(3000Hz)/(343m/s)]²-1
= 41.2 m
Therefore, the central will a listener be at the first minimum and thus have difficulty hearing the sound is 41.2 m.
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light is traveling from plastic into air. at the interface some of the light is reflected. how does the reflected wave compare to the incident wave?
When light travels from plastic into the air, some of the light is reflected at the interface between the two media. The reflected wave is characterized by a few key differences compared to the incident wave.
Firstly, the reflected wave is inverted with respect to the incident wave, meaning that it is flipped upside down.
Furthermore, the abundance of the reflected wave is by and large more modest than that of the occurrence wave.
This is because some of the energy of the wave is absorbed or scattered as it interacts with the interface between the plastic and air.
Lastly, the reflected wave is shifted in phase compared to the incident wave. The amount of phase shift depends on the angle of incidence and the refractive indices of the two media.
In summary, the reflected wave that occurs when light travels from plastic into the air is inverted, has a smaller amplitude, and is shifted in phase compared to the incident wave.
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3. The electric field at a point 27 cm from a charged particle is 105 N
C
toward the particle.
What is the charge on the particle?
The particle has a charge of 2.44 x 10-8 C. when electric field at a point 27 cm from a charged particle is 105 N
What is charge?The electrical properties of particles like electrons and protons are described by charge, a fundamental property of matter. Particles with the same electric charge repel one another while those with the opposite charge attract one another. Electric charge can be positive or negative. The Coulomb (C) is the charge measurement unit, and particles' charges are typically measured in Coulombs.
E is equal to kQ/r₂, where k is the Coulomb constant, r is the distance from the particle to the point where the electric field is being measured, Q is the charge on the particle, and E is the electric field.
The electric field at a distance of 27 cm from the particle is calculated to be 105 N/C in the particle's direction. We now have:
By substituting these values into the equation for the electric field, we obtain: E = 105 N/C r = 27 cm = 0.27 m
105 N/C = (8.99 x 10⁹ N m²/C²) × Q / (0.27 m)²
Solving for Q, we get:
Q = (105 N/C) × (0.27 m)² / (8.99 x 10⁹ N m²/C²)
Q = 2.44 x 10⁻⁸ C
Therefore, the charge on the particle is 2.44 x 10⁻⁸ C.
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how does the speed of sound in sea water compare to the speed of sound in air? a the speed of sound is faster in sea water because the molecules in sea water are closer to each other and more dense. b the speed of sound is slower in sea water because the molecules in sea water are closer to each other and more dense. c the speed of sound is faster in sea water because the molecules in sea water are closer to each other and less dense. d the speed of sound is slower in sea water because the molecules in sea water are closer to each other and less dense.
Seawater has sound travelling at a substantially higher speed than air. The speed of sound in air is roughly 343 metres per second at a temperature of 25 °C.
How quickly does sound travel across sea water?The sound speed in the oceans fluctuates between 1,450 and 1,570 metres per second (or 4,760 and 5,150 feet per second). With every 1 °C increase in temperature and every 1 psu increase in salinity, it grows by around 4.5 metres (about 15 feet) and 1.3 metres (about 4 feet) every second, respectively.
Why does sound travel faster in water than in air?In water, sounds move more quickly than in the air. Because the particles are considerably closer together, They may quickly transfer vibrational energy from one particle to the next because of the water. Sound generally travels through water four times more quickly than through air.
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Could someone type these out for me? (Should be three pages)
They both had the same potential energies. This is because everyone can be found in the same location.
Describe potential energy.
An object or set of things may have potential energy stored in them depending on their size, form, location, or even the material they are constructed of. Find out what potential energy is and the various kinds that an object might have.
There was a difference in the average amount that the box slid after catching the marble when comparing the marbles. The more kinetic energy I have, the greater the impact it has and, as a result, the further the box will slide away. At the end of the ramp, the kinetic energy between them is NOT equal. Because of its greater mass, kinetic energy has larger potential. Distance reveals the outcome.
My data indicate that both of my hypotheses for each experiment are true. My theory for the initial trial was that moving the box by 40 cm would be the most effective. Considering that the average distance was the greatest of all, this was in fact true. The second experiment was conducted similarly. My hypothesis for the second experiment was that the more the marole's mass, the greater the box's distance.
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if the projectile rises to a maximum height of only 10.7 m, determine the magnitude of the average force due to air resistance.
This can be calculated by the formula - CD=FD12ρAv2Explanation:Air resistance, or drag, is dependent on a number of factors including the density of the air, the area of the object, its velocity, and other properties of the object. The units for the force of air resistance are in Newtons (N).
What projectile rises to a maximum height?The magnitude of the drag force is characterized by the dimensionless drag coefficient CD , given by CD=FD12ρAv2, C D = F D 1 2 ρ A v 2.
Where ρ is the density of the fluid (in this case, air), A=(1/4)πD2 A = ( 1 / 4 ) π D 2 is the cross-sectional area of the object, and v is the object's speed.
Therefore, Air resistance can be calculated by taking air density times the drag coefficient times area all over two, and then multiply by velocity squared.
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the earth has a much larger mass than the moon. how many moons would it take to equal the mass of earth?
It would take approximately 81.3 Moons to equal the mass of the Earth.
What is the mass of the earth?Iron and oxygen make up the majority of the Earth's mass. Each of these makes up around 32% of the mass of the planet. Calcium, aluminum, and nickel make up roughly 1.5% of the total, followed by magnesium and silicon, which each contribute another 15%.
The mass of the Earth is approximately 5.97 x 10^24 kilograms, while the mass of the Moon is approximately 7.35 x 10^22 kilograms.
To determine how many Moons would be required to equal the mass of the Earth, we can divide the mass of the Earth by the mass of the Moon:
5.97 x 10^24 kg / 7.35 x 10^22 kg = 81.3
Therefore, it would take approximately 81.3 Moons to equal the mass of the Earth.
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therm is a unit that is generally used to measure the energy contained in natural gas. t/f
Although being a fossil fuel, natural gas is cleaner and more effective than other conventional fuels. According to the Center for Liquefied Natural Gas, natural gas emits fewer greenhouse gases and pollutants than its competitors. Thus, it is true.
What is the energy contained in natural gas?The methane and other hydrocarbon molecules in the decomposing organisms contain chemical energy that was previously obtained by photosynthesis from the sun. Burning natural gas can provide power as well as heat homes.
Methane makes up the majority of natural gas, but it also includes ethane, propane, and heavier hydrocarbons. Moreover, it has trace amounts of water, nitrogen, carbon dioxide, and hydrogen sulphide.
Therefore, it is true that therm is a unit that is generally used to measure the energy contained in natural gas.
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you measured the length, diameter and mass of two different cylinders. in both cases, you found that the length had 3 significant figures and that length was the measurement with the fewest number of significant digits. if you found the weight densities to be 38123 n/m3 and 38091 n/m3 and you round these values to the correct number of significant figures, can you conclude the two cylinders are made of the same material (do they have the same weight density)?
Weight Density 1 = 38107 N/m³
Weight Density 2 = 38107 N/m³
The formula for volume of cylinder is:
V = πr²l
where,
V = Volume
r = radius
l = length of cylinder
So, if length has the 3 significant figures which is least in all values, Then the volume must also be in 3 significant figures. The formula for weight density is:
Weight Density = Weight/Volume
Here, the volume has the least significant figures of 3, therefore, the weight densities must also have 3 significant figures:
Weight Density 1 = 38123 N/m³
Weight Density 1 = 38124 N/m³
Weight Density 1 = 38107 N/m³
Weight Density 2 = 38123 N/m³
Weight Density 2 = 38124 N/m³
Weight Density 2 = 38107 N/m³
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two children with masses of 22 kg and 38 kg are sitting on a balanced seesaw. if the heavier child is sitting 0.45 m from the center, at what distance from the center is the lighter child sitting?
A seesaw is one type of lever, and it features a long beam attached to a pivot known as the fulcrum. The beam drops to the ground as soon as you sit on one side of it and put weight on one of its ends.
is the distance from the center is the lighter child sitting.
What is the balanced seesaw?The seesaw maintains its balance if the total torques that drive it to revolve in one direction—clockwise—equal the total torques that cause it to rotate in the opposite—counterclockwise. For an object at rest with no net forces acting on it, this is analogous to Newton's First Law.
This is due to the weight of your body being pulled downward by the force of gravity as well as the beam.
Two children with masses of 22 kg and 38 kg are sitting on a balanced seesaw, the heavier child is sitting 0.45 m,
the force by both, as shown below,
the distance as the seesaw is in equilibrium,
Therefore, is the distance from the center is the lighter child sitting.
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what is the minimum possible diameter of the spot on the wall, defined as the diameter of the circle where the intensity is zero? (a) 2.03e-03 m
The minimum possible diameter of the spot on the wall is approximately 3.05e-4 mm or 2.03e-3 m.
The minimum possible diameter of the spot on the wall, also known as the diffraction spot or Airy disk, can be calculated using the formula:
d = 2.44 * λ * L / D
where λ is the wavelength of the light, L is the distance between the aperture and the wall, and D is the diameter of the aperture.
In this case, we are not given the wavelength or distance L, but we are given the diameter of the aperture, which is 0.4 mm or 4e-4 m. We can assume a typical visible light wavelength of 500 nm or 5e-7 m and a distance L of 1 m for this calculation.
d = 2.44 * 5e-7 m * 1 m / 4e-4 m
d = 3.05e-7 m or 3.05e-4 mm
Therefore, the minimum possible diameter of the spot on the wall is approximately 3.05e-4 mm or 2.03e-3 m.
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PLS ANSWERRR What are the main differences between the carbon flows 300 years ago and today?
The main differences between the carbon flow 300 years ago and today are the amount of carbon dioxide released into the atmosphere and the sources of those emissions.
300 years ago, the majority of carbon emissions came from natural sources, such as volcanic eruptions and forest fires. However, today, the majority of carbon emissions come from human activities, such as burning fossil fuels for energy and deforestation for agriculture and urbanization. Additionally, the amount of carbon dioxide released into the atmosphere has greatly increased in the past 300 years due to the industrialization of society and the increase in the human population. This has led to an increase in greenhouse gases in the atmosphere and has contributed to climate change.
In summary, the main differences between the carbon flow 300 years ago and today are the sources of emissions and the amount of carbon dioxide released into the atmosphere.
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a π bond could be formed from the overlap of which two orbitals?
A π bond is formed from the overlap of two parallel p orbitals that are adjacent to each other. When two such p orbitals overlap, the regions of overlapping electron density create a bonding molecular orbital with a nodal plane between the nuclei of the bonding atoms.
What is P bond and orbitals?Two parallel p orbitals that are near each other combine to form pi bonds. A metallic bond fundamentally consists of two or more atoms sharing the same pair of electrons. In contrast to a sigma bond, which has its electronegativity focused between the atoms, a pi bond has its electron density concentrated both above and below the internuclear axis. A zone of negative electrode is produced by this charge distribution dispersion, which can interact with other molecules' and atoms' positive ions.
Along with s and d orbitals, atomic orbitals are one of the three types of orbitals that an electron can occupy in an atom. P orbitals consist of two prongs that are wedge-shaped in alignment. There are three there. Three are three mutually perpendicular p orbitals that can exist in an atom, each labeled as px, py, and pz.
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The probability of fusion occurring is greatly enhanced when appropriate nuclei are brought close together, but mutual Coulomb repulsion must be overcome. This can be done using the kinetic energy of hightemperature gas ions or by accelerating the nuclei toward one another. (a) Calculate the potential energy of two singly charged nuclei separated by 1.00 x 10^-12. (b) At what temperature will atoms of a gas have an average kinetic energy equal to this needed electrical potential energy?
Electric potential energy = 8.99 x 10^-3 J and the temperature T = 2.01 x 10^7 K
What is the potential energy between two singly charged nuclei separated by a distance of 1.00 x 10^-12 m? Use Coulomb's constant (k= 8.99 x 10^9 N m^2/C^2) and assume the charges of the nuclei are +1. ?
where k is Coulomb's constant (k = 8.99 x 10^9 N m^2/C^2), q1 and q2 are the charges of the two nuclei (each with a charge of +1 since they are singly charged), and r is the separation distance between the nuclei (1.00 x 10^-12 m).
(a) The potential energy of two singly charged nuclei separated by a distance of 1.00 x 10^-12 m can be calculated using the Coulomb potential energy equation:
Electric potential energy = (k * q1 * q2) / r
where k is Coulomb's constant (k = 8.99 x 10^9 N m^2/C^2), q1 and q2 are the charges of the two nuclei (each with a charge of +1 since they are singly charged), and r is the separation distance between the nuclei (1.00 x 10^-12 m).
Plugging in the values, we get:
Electric potential energy = (8.99 x 10^9 N m^2/C^2) * (+1 C) * (+1 C) / (1.00 x 10^-12 m)
Electric potential energy = 8.99 x 10^-3 J
Therefore, the potential energy of two singly charged nuclei separated by a distance of 1.00 x 10^-12 m is 8.99 x 10^-3 J.
(b) We can use the average kinetic energy equation to find the temperature at which atoms of a gas will have an average kinetic energy equal to the electrical potential energy calculated in part (a):
(1/2)mv^2 = (3/2)kT
where m is the mass of a gas atom, v is the root-mean-square velocity of the atoms, k is Boltzmann's constant (k = 1.38 x 10^-23 J/K), and T is the temperature.
To solve for T, we can rearrange the equation:
T = (1/3)mv^2 / k
The mass of a gas atom can be approximated using the molar mass of the gas and Avogadro's number. Let's assume we are considering helium gas, which has a molar mass of approximately 4.00 g/mol. This is equivalent to approximately 6.64 x 10^-27 kg per helium atom.
The root-mean-square velocity of gas atoms can be found using the equation:
v = sqrt((3kT) / m)
We want to find the temperature at which the average kinetic energy of helium gas atoms is equal to the electrical potential energy calculated in part (a), so we can set (1/2)mv^2 equal to 8.99 x 10^-3 J:
(1/2)mv^2 = 8.99 x 10^-3 J
Substituting in the values for m and v, we get:
(1/2) * (6.64 x 10^-27 kg) * [(sqrt((3kT) / m))^2] = 8.99 x 10^-3 J
Simplifying, we get:
sqrt(3kT / m) = sqrt(2 * 8.99 x 10^-3 J / 6.64 x 10^-27 kg)
sqrt(3kT / m) = 2427.5 m/s
Squaring both sides, we get:
3kT / m = (2427.5 m/s)^2
Solving for T, we get:
T = (m / 3k) * (2427.5 m/s)^2
Substituting in the values for m and k, we get:
T = (6.64 x 10^-27 kg / (3 * 1.38 x 10^-23 J/K)) * (2427.5 m/s)^2
T = 2.01 x 10^7 K
therefore the temperature was found to be about T = 2.01 x 10^7 K
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the largest object in the asteroid belt is ceres with a radius of 470 km and a mass of 9.384*10^20 kg. what is the weight, in newtons, of a 160. kg astronaut standing on ceres
The largest object in the asteroid belt is ceres with a radius of 470 km and a mass of [tex]9.384*10^2^0 kg[/tex]. The weight of a 160. kg astronaut standing on ceres is 43.2 N.
The weight of the astronaut on Ceres can be calculated using the formula:
w = m * g
here,
w is weight of the astronaut,
m is mass of the astronaut, and
g is gravitational acceleration on Ceres.
The gravitational acceleration on Ceres:-
[tex]F = G * (m1 * m2) / r^2[/tex]
here,
F is gravitational force between two objects,
G is gravitational constant,
m₁ & m₂ are masses of the two objects, and
r is distance between them.
For an object of mass m near the surface of a spherical object of mass M and radius R, the distance r can be approximated as (R + h).
For Ceres, the gravitational acceleration:-
[tex]g = G * M / R^2[/tex]
here,
G is gravitational constant,
M is mass of Ceres, and
R is radius of Ceres.
Reserving values given:-
[tex]g = (6.67430 × 10^-^1^1^ ^m^3/(kg s^2)) * (9.384 × 10^20 kg) / (470000 m)^2[/tex]
[tex]g = 0.27 m/s^2[/tex]
Now, weight of the astronaut as:
w = m * g
[tex]w = 160 kg * 0.27 m/s^2[/tex]
w = 43.2 N
Therefore, the weight of a 160 kg astronaut standing on Ceres is approximately 43.2 newtons.
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what two types of forces act on a fluid element? question 5 options: shearing and surface forces body and surface forces gravitational and body forces
The two types of forces that act on a fluid element is body forces and surface forces.
A body force is a force that acts throughout the volume of a body.( 1) Forces due to graveness, electric fields and glamorous fields are exemplifications of body forces. Body forces discrepancy with contact forces or face forces which are wielded to the face of an object.
Normal forces and shear forces between objects are superficial forces as they're wielded to the face of an object. All cohesive face magnet and contact forces between objects are also considered as face forces.
Face force denoted fs is the force that acts across an internal or external face element in a material body. face force can be perished into two vertical factors normal forces and shear forces. A normal force acts typically over an area and a shear force acts parenthetically over an area.
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. a car, initially travelling at 20.0 m/s, accelerates at a uniform rate of 4.00 m/s2 for a distance of 50.0 m. how much time is required to cover this distance?
It takes 2.07 seconds for the car to cover a distance of 50.0 meters while accelerating at a uniform rate of 4.00 m/s^2.
We can use the kinematic equation to solve for the time required to cover the distance.
Here's the kinematic equation that we'll use:
d = vi * t + 1/2 * a * t^2
where:
d = distance traveled (in meters)
vi = initial velocity (in meters per second)
a = acceleration (in meters per second squared)
t = time (in seconds)
We want to solve for t, so we'll rearrange the equation to isolate t:
d = vi * t + 1/2 * a * t^2
50.0 m = 20.0 m/s * t + 1/2 * 4.00 m/s^2 * t^2
50.0 m = 20.0 m/s * t + 2.00 m/s^2 * t^2
Now we have a quadratic equation in the form of ax^2 + bx + c = 0, where:
a = 2.00 m/s^2
b = 20.0 m/s
c = -50.0 m
We can use the quadratic formula to solve for t:
t = (-b ± sqrt(b^2 - 4ac)) / 2a
Plugging in the values for a, b, and c, we get:
t = (-20.0 ± sqrt(20.0^2 - 4(2.00)(-50.0))) / 2(2.00)
t = (-20.0 ± sqrt(400 + 400)) / 4.00
t = (-20.0 ± 28.28) / 4.00
We have two solutions because of the ± sign. However, we know that time cannot be negative, so we'll take the positive solution:
t = (-20.0 + 28.28) / 4.00
t = 2.07 seconds
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a parallel-plate capacitor has 2.00-cm2 plates that are separated by 5.00 mm with air between them. (a) if a 12.0-v battery is connected to this capacitor, how much energy does it store? (b) if a dielectric with a constant of 2.56 were inserted between the plates with the battery attached, what would the energy stored become? (c) repeat (b) for the case where the battery had been disconnected before dielectric insertion.
a) The energy stored in the capacitor is 5.10 × 10⁻¹⁰ J.
b) The energy stored in the capacitor with the dielectric inserted is 1.04 × 10⁻⁹ J.
c) The energy stored in the capacitor with the dielectric inserted and the battery disconnected is 2.14 × 10⁻¹⁰ J.
The energy stored in a parallel-plate capacitor is given by the formula:
U = [tex]\frac{1}{2}CV^2[/tex]
where U is the energy stored, C is the capacitance, and V is the voltage across the capacitor.
(a) The capacitance of a parallel-plate capacitor is given by the formula:
C = [tex]\frac{\epsilon_0A}{d}[/tex]
where [tex]\epsilon_0[/tex] is the permittivity of free space, A is the area of the plates, and d is the distance between them.
Substituting the given values, we have:
C =[tex]\frac{(8.85 \times 10^{-12} \textrm{ F/m})(2.00 \times 10^{-4} \textrm{ m}^2)}{5.00 \times 10^{-3} \textrm{ m}} = 7.08 \times 10^{-12} \textrm{ F}[/tex]
The voltage across the capacitor is given by the battery voltage, which is 12.0 V. Substituting these values into the formula for energy, we have:
U = [tex]\frac{1}{2}(7.08 \times 10^{-12} \textrm{ F})(12.0 \textrm{ V})^2 = 5.10 \times 10^{-10} \textrm{ J}[/tex]
(b) When a dielectric is inserted between the plates, the capacitance increases. The new capacitance is given by the formula:
[tex]C' = \kappa C[/tex]
where [tex]\kappa[/tex] is the dielectric constant of the material.
Substituting the given values, we have:
[tex]C' = (2.56)(7.08 \times 10^{-12} \textrm{ F}) = 1.82 \times 10^{-11} \textrm{ F}[/tex]
The voltage across the capacitor remains the same, so the energy stored in the capacitor becomes:
[tex]U' = \frac{1}{2}(1.82 \times 10^{-11} \textrm{ F})(12.0 \textrm{ V})^2 = 1.04 \times 10^{-9} \textrm{ J}[/tex]
(c) If the battery is disconnected before the dielectric is inserted, the charge on the plates remains the same. However, the voltage across the capacitor decreases due to the increased capacitance. The new voltage is given by the formula:
[tex]V' = \frac{V}{\kappa}[/tex]
Substituting the given values, we have:
[tex]V' = \frac{12.0 \textrm{ V}}{2.56} = 4.69 \textrm{ V}[/tex]
The energy stored in the capacitor becomes:
[tex]U' = \frac{1}{2}(1.82 \times 10^{-11} \textrm{ F})(4.69 \textrm{ V})^2 = 2.14 \times 10^{-10} \textrm{ J}[/tex]
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Nichrome is used as a heating element in electric iron. give reason
Nichrome is used as a heating element in electric irons
High resistanceCorrosion resistanceGood temperature stabilityWhy Nichrome is used as a heating element?High resistance: Nichrome has a high electrical resistance, which means that it converts electrical energy into heat energy efficiently. This makes it ideal for use in heating elements where heat generation is the primary requirement.
Good temperature stability: Nichrome has a high melting point and a low coefficient of thermal expansion. This means that it can maintain its structural integrity even at high temperatures and does not deform or break easily.
Corrosion resistance: Nichrome is resistant to corrosion, which makes it suitable for use in electrical appliances that are exposed to moisture, such as electric irons.
Long lifespan: Nichrome has a long lifespan and does not degrade easily even with repeated use. This makes it a reliable and durable choice for heating elements.
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Suppose that two objects attract each other with a gravitational force of 18 units. If the mass of one of the objects was tripled, and if the distance between the objects tripled, then what would be the new gravitational force of attraction between the two objects?
Answer:
6 units
Explanation:
You want the gravitational force between two objects after both the mass of one object and the distance between them triples, if it is initially 18 units.
ForceLet F represent the initial force between the objects. Newton's law of gravitational attraction tells us ...
F = GmM/r²
When one mass is tripled, and the distance between the objects is tripled, the new force is ...
F' = G(3m)M/(3r)² = 3/9(GmM/r²) = F/3
Given the initial force is 18 units, the new force of attraction is ...
F' = (18 units)/3 = 6 units
The new gravitational force of attraction between the objects is 6 units.
a 70.0 kg person rides in an elevator while standing on a scale. the elevator is traveling downward and speeding up at a rate of 2.50 m/s2 . the reading on the scale is closest to
Reading on the scale will be closest to 861.7 N which can be calculated using Newton's 2nd Law of Motion.
The reading on the scale will depend on the force acting on the person in the elevator. We can calculate this force by using Newton's second law of motion, which states that force equals mass times acceleration (F = ma).
In this case, the force acting on the person is the sum of their weight (mg) and the force due to the acceleration of the elevator (ma). The direction of the acceleration is downward, so we can take it as negative. Net force:
Fnet = mg - ma
where m is the mass of the person, g is the acceleration due to gravity (9.81 m/s^2), and a is the acceleration of the elevator (-2.50 m/s^2).
Substituting the given values, we have:
Fnet = (70.0 kg)(9.81 m/s^2) - (70.0 kg)(-2.50 m/s^2)
Fnet = 686.7 N + 175 N
Fnet = 861.7 N
Therefore, the reading on the scale will be closest to 861.7 N. Note that this is greater than the person's weight (686.7 N) because the elevator is accelerating downward, creating an additional force on the person.
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consider 3 resistors with resistance r1, r2, r3 connected in series with a battery. this means that one end of r1 is connected to the positive terminal of the battery; the other end of r1 is connected to one end of r2; the other end of r2 is connected to one end of r3; the other end of r3 is connected to the negative terminal of the battery. if you replaced the three resistors with a single resistor, what is the resistance req of this resistor?
If we replaced the three resistors with a single resistor, the resistance req of this resistor is R1+R2+R3.For the series combination of resistances, here the second end of each resistance is attached to the first end of the following resistance and the setting goes so on
In a series circuit of resistors, the current that runs through every one of them is identical and is equivalent to the current provided by the battery. Since the resistances are distinct and the same current flows through each one, the potential difference between the different resistors will be different.
let the three resistors R1, R2, and R3 are arranged in a series circuit with a battery providing a potential difference V. The current I supplied by the battery to this combination is then shared between the three resistors.Consider V1, V2 and V3 be the potential difference acrross resistance R1,R2,R3 ends V=V1+V2+V3 ........(1).
Considering the replaced resistance be R, by ohm's law V=IR,V1=IR1,V2=IR2,V3=IR3, so substituing those in equation 1 we get :
I=IR1+IR2+IR3
IR=I(R1+R2+R3)
R=R1+R2+R3
In conclusion, the replaced resistor resistance is the sum of the individual resistances
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a hamster runs at a speed of 13 centimeters per second in a wheel of radius 14 centimeters. a) what is the angular velocity of the wheel? (in radians/sec) incorrect radians/sec correctradians/sec no decimals allowed. b) how fast will the wheel spin in revolutions per minute? incorrect rev/min correctrev/min no decimals allowed.
The angular velocity of the wheel is 0.9286 radians/sec and the number of revolutions per minute is 8.84 rpm
The angular velocity of the wheel in radians per second is given by the formula:
ω = v/r where ω is the angular velocity in radians per second, v is the linear velocity in cm/s, and r is the radius of the wheel in cm.
Therefore, the angular velocity of the wheel is:
ω = 13 cm/s / 14 cm = 0.9286 radians/sec
To calculate the revolutions per minute (rpm), we use the formula:
rpm = ω * 60 / (2π)
where 2π is the number of radians in a full revolution.
Therefore, the wheel will spin at a rate of:
rpm = 0.9286 radians/sec * 60 / (2π) = 8.84 rpm
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which structural fragment would give rise to a characteristic triplet-quartet pattern in the 1h nmr spectrum? true or false?
The statement "A structural fragment with three adjacent non equivalent protons would give rise to a characteristic triplet-quartet pattern in the 1H NMR spectrum" is true.
This is because the three protons are magnetically coupled to each other, resulting in a triplet signal, and they are also coupled to a neighboring proton, resulting in a quartet signal.
The relative intensities of the triplet and quartet signals are in a 1:3 ratio, which is characteristic of this type of structural fragment.
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suppose that the cable from a to b must exert a 8500 n horizontal force on the car to hold it in place. determine the car's weight and also mass in kg
The car's weight and mass in kg if cable from a to b must exert a 8500 n horizontal force on the car to hold it in place is 14722N and 1502.24 kg.
Believe or not, weight is the force that the earth Earth is acting on you. The gravitational acceleration which is multiplied to the mass is deduced by using the equation of Newton's law of solemnity similar that one mass is the mass of the earth Earth.
The free body diagram is shown to the right
Applying the equilibrium equation
[tex]\sum F_s = T- Nsin30\degree = 0\\\\\sumF = Ncos30 - mg = 0\\[/tex]
Setting T = 8500N and solving the equation we get,
N = 17000N
mg = 14722 N
So weight = 14722 N
and mass = 14722/g = 14722/9.8 = 1502.24 kg
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Where do plants get the energy to make their food?
From the air
From the flower
From the roots
From the sunflower
Plants get the energy to make their food through the flowers and is therefore denoted as option B.
What is Photosynthesis?This is referred to as the process in which green plants manufacture their food in the presence of sunlight and is the reason why they are referred to as primary producers.
Plants have flowers and leaves which help to trap sunlight from the sun through the chlorophyll. The chlorophyll is a green pigment which is present in the chloroplast and they are all found in the flowers of plants which is therefore the reason why it was chosen as the correct choice.
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A 0.112-kg billiard ball moving at 154 cm/s strikes a second billiard ball of the same mass moving in
the opposite direction at 46 cm/s. The second billiard ball rebounds and travels at 72 cm/s after the
head-on collision.
Determine the post-collision velocity of the first billiard ball.
The post-collision velocity of the first billiard ball is 272 cm/s.
Define VelocityVelocity is a vector quantity that describes an object's speed and direction of motion.
We can solve this problem by using the law of conservation of momentum, which states that the total momentum of an isolated system remains constant.
The momentum of an object is defined as the product of its mass and velocity:
p = m * v
The total initial momentum of the system is the sum of the momenta of the two billiard balls before the collision:
p_initial = m * v1 + m * v2
where m is the mass of each billiard ball, v1 is the initial velocity of the first billiard ball, and v2 is the initial velocity of the second billiard ball.
After the collision, the first billiard ball will rebound with a velocity v1', and the second billiard ball will rebound with a velocity v2'. The total final momentum of the system is the sum of the momenta of the two billiard balls after the collision: p_final = m * v1' + m * v2'
Since the law of conservation of momentum applies, we can set the initial momentum equal to the final momentum
p_initial = p_final
Substituting the given values, we get:
m * v1 + m * v2 = m * v1' + m * v2'
Simplifying, we get:
v1' = (m * v1 + m * v2 - m * v2') / m
v1' = v1 + (v2' - v2)
Plugging in the given values, we get:
v1' = 154 cm/s + (72 cm/s - (-46 cm/s))
v1' = 272 cm/s
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The stored energy that can be used to do work is called ______ energy, while the energy of motion used to do work is called ________ energy.
The stored energy that can be used to do work is called Potential energy
while the energy of motion used to do work is called kinetic energy.
Potential energy is simply stored energy that, depending on its surroundings or circumstances, a thing may use. Potential energy is the energy that is held inside a system of physically interacting things, to use terminology more closely related to physics.
Kinetic energy, often known as the energy of motion, may be seen in the motion of things and subatomic particles. Kinetic energy may be found in all particles and moving objects. Examples of kinetic energy in action include a person walking, a baseball flying through the air, food tumbling off a table, and a charged particle in an electric field. Everything contains kinetic and potential energy. Kinetic energy is the ability to move anything (KE). Energy is a potential form of energy (PE).
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1. find the distance between a 0.300 kg billiard ball and a 0.400 kg billiard ball if the magnitude of the gravitational force between them is 8.92 x 10-11 n.
The distance between two pool balls are separated by 0.0424 m.
By gravitational force, what do you mean?The gravitational pull draws any two mass-containing things together. It mentions the gravitational force. The force will always be applied along the line joining the two masses in the direction of the other mass, according to the formula F=Gm1m2r2.
The following formula can be used to determine the gravitational force between two objects:
F = G * (m1 * m2) / r²
where F is the gravitational force's strength, G is the gravitational constant (6.67 x 10-11 N×m2/kg), m1 and m2 are the objects' masses, and r is the separation between them.
To determine the separation between the two pool cues To account for r, we can rearrange this expression as follows:
Represents the objects' masses, while r denotes the separation between their mass centres.
Rearranging this formula to solve for r will allow us to get the distance between the two pool balls:
r = √(G × m1 × m2 / F)
Substituting the given values, we get:
r = √(6.67 x 10⁻¹¹ N*m²/kg² × 0.300 kg × 0.400 kg / 8.92 x 10⁻¹¹ N)
r = 0.0424 m
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